an object is released from rest and falls a distance h during the first second of time. how far will it fall during the next second of time?

Answer:

2.05 Ω

Explanation:

We are here given that the

We need to find out the resistance of the given wire . As we know that,

\(\implies R = \rho \dfrac{l}{A} \\\)

\(\implies R =\rho \dfrac{ l}{\pi r^2} \\\)

\(\implies R =\rho \dfrac{l}{\pi \dfrac{d^2}{4}} \\\)

\(\implies R =\rho \dfrac{4l}{\pi d^2}\\\)

substitute the respective values,

\(\implies R = 1.720 \times 10^{-8}\times \dfrac{4\times 5000m}{3.14\times (0.74\times 10^{-2}} \\\)

\(\implies\underline{\underline{ R = 2.05 \Omega }} \\\)

and we are done!

Answer:

What are your answer choices?

Explanation:

Work is like if you are a police officer you take down enemies. Force is like if you use a negatively charged balloon next to an uncharged piece of paper, they balloon would attract each other.

Hope this helps :D

The largest object in the asteroid belt is ceres with a radius of 470 km and a mass of \(9.384*10^2^0 kg\). The weight of a 160. kg astronaut standing on ceres is 43.2 N.

The weight of the astronaut on Ceres can be calculated using the formula:

w = m * g

here,

w is weight of the astronaut,

m is mass of the astronaut, and

g is gravitational acceleration on Ceres.

The gravitational acceleration on Ceres:-

\(F = G * (m1 * m2) / r^2\)

here,

F is gravitational force between two objects,

G is gravitational constant,

m₁ & m₂ are masses of the two objects, and

r is distance between them.

For an object of mass m near the surface of a spherical object of mass M and radius R, the distance r can be approximated as (R + h).

For Ceres, the gravitational acceleration:-

\(g = G * M / R^2\)

here,

G is gravitational constant,

M is mass of Ceres, and

R is radius of Ceres.

Reserving values given:-

\(g = (6.67430 × 10^-^1^1^ ^m^3/(kg s^2)) * (9.384 × 10^20 kg) / (470000 m)^2\)

\(g = 0.27 m/s^2\)

Now, weight of the astronaut as:

w = m * g

\(w = 160 kg * 0.27 m/s^2\)

w = 43.2 N

Therefore, the weight of a 160 kg astronaut standing on Ceres is approximately 43.2 newtons.

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answer = 33.4 net force.

Answer:

Answer:

2 in front of water and 1 in front of oxygen

Explanation:

This question is describing balancing a chemical reaction. A balanced chemical reaction has the same number of atoms of each elements on both the reactant and product side. According to the question, the reactants contains 4 atoms of oxygen. The reactants give rise to water (H20) and O2 in the products side.

This reaction is most likely the decomposition of hydrogen peroxide (H2O2) as follows:

H2O2 (l) ----> H2O (l) + O2(g)

Based on the description, H2O2 will be 2H2O2 as it is said to contain four atoms of oxygen. This means that, in order to have a balanced equation, we must place coefficient 2 in front of water and coefficient 1 in front of oxygen. That is;

2H2O2 (l) ----> 2H2O (l) + O2(g)

Explanation:

Answer:

2 in front of water and 1 in front of oxygen

Explanation:

i took the test and got 100 so it has to be right ;)

Answer:

d

Explanation:

The accepted conclusion is that a frictional force exactly opposes your pull and the first law applies. The correct option is C.

According to the laws of motion, an object at rest or moving with a constant velocity will continue to do so unless acted upon by an external force (Newton's first law of motion). In the given scenario, when a steady pull is required to keep an object moving on a level surface with friction present, the following explanation applies:

1. Frictional Force: Friction is a force that opposes the relative motion between two surfaces in contact. When you pull an object on a level surface, a frictional force arises that acts in the opposite direction to your pull. This frictional force is equal in magnitude and opposite in direction to your applied force.

2. First Law of Motion: Despite your continuous pull, the object remains in motion with a constant velocity due to the frictional force exactly opposing your pull. This aligns with the first law of motion, which states that an object will continue to move with a constant velocity (including zero velocity) if the net force acting on it is zero.

Therefore, the accepted conclusion is that a frictional force exactly opposes your pull, allowing the object to continue moving with a constant velocity, and the first law of motion applies. Option C is the correct answer.

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Answer:

Yes, greater power is necessary to lift a car with your own body in a dire emergency situation than it would be to lift the same car using a jack.

Explanation:

This is because lifting the car with your body requires a combination of strength, power, and speed, all of which must be generated by your muscles. In contrast, a jack is a tool that uses hydraulic pressure to lift the car, which requires much less effort on your part.

When lifting a car with your body, you are essentially performing a squat or deadlift with an extremely heavy weight. This requires your muscles to produce a tremendous amount of force to overcome the weight of the car and gravity, as well as to generate the speed and power necessary to lift the car quickly and effectively.

In addition, lifting a car with your body requires you to use multiple muscle groups simultaneously, including your legs, back, arms, and core. This makes it a very taxing exercise that can quickly fatigue your muscles and potentially lead to injury if not performed correctly.

In contrast, using a jack to lift a car requires minimal effort on your part, as the hydraulic pressure does the majority of the work. This means that you do not need to generate as much force, speed, or power with your muscles, and can avoid the risk of injury or fatigue associated with lifting the car with your body.

Overall, lifting a car with your body is a remarkable feat that requires a tremendous amount of strength, power, and speed. While it can be done in dire emergency situations, it should not be attempted unless absolutely necessary, and only by individuals who are properly trained and physically capable of performing the lift safely.

Answer:

The star's luminosity rises above its previous level. Because it is so cool, the surface will be red, and it will be much farther away from the center than it was during the earlier stages of star evolution. Despite its lower surface temperature, the red giant has a large surface area, which makes it very luminous.

Answer:

Explanation:

from t = .3 to t = .33 , velocity appears to be uniform .

uniform velocity = .22 m /s

displacement will be area of the v-t graph which is a rectangle .

= .22 x ( .33 - .3 )

= .22 x .03

= 66 x 10⁻⁴ m

= 6.6 mm .

(a) The truck's speed at the end of the braking period is 4.0 m/s.

During the first phase, the truck undergoes uniform acceleration with a rate of +2.0 m/s for 9.0 seconds. We can calculate the final velocity using the formula:

v=u+at

Where:

v = final velocity

u = initial velocity (which is 0 m/s as the truck starts from rest)

a = acceleration

t = time

Plugging in the values, we have:

v=0+(2.0m/s^2)(9.0s)=18.0 m/s

During the second phase, the truck undergoes uniform acceleration in the opposite direction (-2.0 m/s) for 3.0 seconds. We can calculate the change in velocity using the same formula:

v=u+at

Where:

v = final velocity

u = initial velocity (which is 18.0 m/s from the first phase)

a = acceleration

t = time

Plugging in the values, we have:

v=18.0+(−2.0m/s^2 )(3.0s)=12.0m/s

Therefore, the truck's speed at the end of the braking period is 12.0 m/s.

(b) The total distance traveled by the truck from the point where it started at rest to the end of the braking period is 144.0 meters.

To calculate the distance traveled during each phase, we can use the formula:

s=ut+ 1/2at^2

Where:

s = distance

u = initial velocity

t = time

a = acceleration

For the first phase (acceleration), we have:

s1 =0×9.0+ 1/2 (2.0m/s^2 )(9.0s)^2 =81.0m

For the second phase (deceleration), we have:

s2 =18.0×3.0+ 1/2 (−2.0m/s^2 )(3.0s)^2 =63.0m

Adding the distances from both phases, we get:

s total =s1 +s2 =81.0+63.0=144.0m

Therefore, the total distance traveled by the truck is 144.0 meters.

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The bicycle wheel will rotate at a rotational velocity of 6 revolutions per second after 4 seconds. The wheel will turn 12 revolutions during this time.

a) If a bicycle wheel is rotationally accelerated at a constant rate of 1.5 rev/s², and it starts from rest, then its rotational velocity after 4 seconds is 6 revolutions per second.  

Angular acceleration is calculated by the formula

α = Δω/Δt = (ωf - ωi)/t

where α is angular acceleration, Δω is the change in angular velocity, and Δt is the change in time.

ωi = initial angular velocity

    = 0

ωf = final angular velocity

α = 1.5 rev/s²

t = 4 s

ωf = αt + ωi

    = 1.5 rev/s² x 4 s + 0

    = 6 rev/s

b) Through how many revolutions does it turn in this time

Angular displacement is calculated by the formula

θ = ωit + ½αt²

Where θ is angular displacement, ωi is the initial angular velocity, t is time, and α is angular acceleration.

ωi = 0

α = 1.5 rev/s²

t = 4 s

θ = ωit + ½αt²

θ = 0 + ½ x 1.5 rev/s² x (4 s)²

  = 12 revolutions.

Hence, the bicycle wheel will rotate at a rotational velocity of 6 revolutions per second after 4 seconds. The wheel will turn 12 revolutions during this time.

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Answer:

whichever teacher gave you this question is a legend

Explanation:

Answer: D

Explanation:

When current suddenly begins to flow through the long, straight wire, a magnetic field is generated around it. This magnetic field induces an electric current in the small circular loop of wire, as the loop cuts through the magnetic field lines.

The direction of the induced current in the loop is determined by Lenz's law, which states that the direction of the induced current will oppose the change that produced it. Therefore, the induced current in the loop will flow in a direction opposite to the flow of the current in the long, straight wire.

When the current in the long, straight wire suddenly stops flowing, the magnetic field around it also disappears. As a result, there is no longer a changing magnetic field to induce an electric current in the small circular loop of wire. Therefore, no current will be detected in the loop once the current in the long, straight wire stops flowing.

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The amount of lateral strain in a tension member can be calculated using Poisson's ratio.

To calculate the lateral strain, we can use the equation: ε_lateral = -ν * ε_longitudinal

Where:

ε_lateral = Lateral strain

ν = Poisson's ratio

ε_longitudinal = Longitudinal strain

Poisson's ratio (ν) is a material property that describes the ratio of lateral strain to longitudinal strain when a material is subjected to an axial load. It is defined as the negative ratio of the transverse strain to the longitudinal strain.

Calculating the lateral strain involves determining the longitudinal strain, which can be calculated using the equation:ε_longitudinal = ΔL / L

Where:

ε_longitudinal = Longitudinal strain

ΔL = Change in length of the tension member

L = Original length of the tension member

Once the longitudinal strain is calculated, we can use Poisson's ratio to determine the lateral strain by multiplying the longitudinal strain by the negative value of Poisson's ratio.

It is important to note that the lateral strain is typically very small compared to the longitudinal strain in a tension member, especially for materials with a low Poisson's ratio.

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William Herschel thought he had found a comet when he spotted the green disk of Uranus.

Uranus is the seventh planet located far away from the Sun. It is a gaseous planet which was discovered in 1781, mistaken by a comet but after two years it was accepted as a planet. After decades of observations and only one close visit by a spacecraft, which shows us that Uranus has unique atmosphere.

Atmosphere of Uranus is mostly made up of hydrogen and helium as well as a small amount of methane and traces of water and ammonia. The presence of methane gas gives blue colour to Uranus so we can conclude that Uranus is the planet which was thought first a comet by William Herschel.

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Answer:

Explanation:

0 m/s^2 is the answer

Answer:

Zero

Explanation:

Constant speed involves zero acceleration  ( which is a change in speed)

Answer:

(a) Parallel to the incedent ray

The timing experiments with a partially-charged capacitor result in shorter charging and discharging times, and the voltage across the capacitor starts at a certain level determined by the initial charge.

When repeating the timing experiments with a partially-charged capacitor, the differences can be summarized in the following points:

Charging Time:

Voltage Rise:

Discharging Time:

Timing Dependency:

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Answer: 1.0

Explanation:

not sure why but that is the correct answer

Answer:

1.0

Explanation:

Correct answer on Khan Academy

The work done by the external force on the child is positive.

When a force is applied to an object, work is done on that object. Work is defined as the product of the force applied on an object and the distance over which the force acts. In this case, the external force acted on the child on a skateboard, causing her speed to increase from 2 m/s to 3 m/s.

To calculate the work done, we can use the formula for work:

\[ \text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta) \]

Since the child's speed increased, we know that the force and displacement acted in the same direction. Therefore, the angle between the force and displacement vectors, denoted by theta (θ), is 0 degrees, and the cosine of 0 degrees is 1.

Considering the child's speed increased, we can conclude that the force applied in the direction of motion did positive work on the child. The positive work done by the external force resulted in an increase in the child's kinetic energy, causing her speed to change.

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Answer:

4

Explanation:

Volume =Mass / density

V= 12/3

V=4dm³

Answer:

4ml^3

Explanation:

Density = Mass/ Volume

From this,

Volume = Mass/ Density

V = 12g / 3g/ml

Volume = 4ml^3

The star is moving away from Earth at a velocity of 1.8 x 106 m/s.

The Doppler Effect describes the shift in wavelength of a wave when the source is moving in relation to the observer. The shift can be observed in sound waves, light waves, and other waves.

The Doppler Effect can be used to determine the velocity of objects moving away from an observer, as in the case of stars moving away from Earth.

The velocity of a star moving away from Earth can be determined using the equation:

v = Δλ/λ x c, Where v is the velocity of the star, Δλ is the shift in wavelength of the spectral line, λ is the wavelength of the spectral line measured in the lab on Earth, and c is the speed of light (3.00 x 108 m/s).

In this case, the shift in wavelength of the spectral line is Δλ = 500.3 nm - 500 nm = 0.3 nm.

The wavelength of the spectral line measured in the lab on Earth is λ = 500 nm.

Plugging in these values to the equation above: v = Δλ/λ x cv = (0.3 nm / 500 nm) x (3.00 x 108 m/s) = 1.8 x 106 m/s.

Therefore, velocity of star 1.8 x 106 m/s.

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Answer:

0.125 J

Explanation:

E = ½ kx²

E = ½ (25 N/m) (0.10 m)²

E = 0.125 J

The stored elastic potential energy from the given equation is equal to 0.5 J.

When an elastic object, such a spring or a stretched rubber band, is displaced from its equilibrium state, it stores energy called elastic potential energy.

Given:

Spring constant, k = 25 Nm⁻¹

Distance, s = 10 cm

From the given equation

E = (0.5) × k × e²

Substitute values:

Ee = (0.5) ×  k × e²

Ee = (0.5) ×  25 ×  (0.1)²

Ee = 0.5 J

Hence, the stored elastic potential energy from the given equation is equal to 0.5 J.

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Answer:

1. L=mgh= 0.1x4x9.8=4.0J

2. L= 2x3x9.8=59J

A metal is in the shape of a box the length of its sides are 3.0 yd, 2.0 yd, and 0.50 yd, the volume of the metal box is 81 ft³.

To calculate the volume of the metal box in ft³:

Here, it is given that:

Length = 3.0 yd

Width = 2.0 yd

Height = 0.50 yd

Converting the dimensions to feet:

Length = 3.0 yd × 3 ft/yd = 9 ft

Width = 2.0 yd × 3 ft/yd = 6 ft

Height = 0.50 yd × 3 ft/yd = 1.50 ft

Now we can calculate the volume of the box:

Volume = Length × Width × Height

Volume = 9 ft × 6 ft × 1.50 ft

Volume = 81 ft³

Therefore, the volume of the metal box is 81 ft³.

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