Answer: 211.75m
Explanation:
Listing everything the question gives you:
Vi = 5.5
a = 2.5
t = 11
ΔX = ?
Then pick a kinematic equation to solve for the missing variable
I used this one: Δx = Vit + \(\frac{1}{2} at^2\)
When you plug in all ur variables you get Δx = 211.75m
The object has travelled a distance of 211.75 meters.
We have an object moving with an initial velocity of 5.5 m/s.
We have to determine how far will it have traveled during the time of its acceleration.
What is Acceleration ?The rate of change of velocity with respect to time is called Acceleration.
a = dv/dt
According to the question -
initial velocity = u = 5.5 m/s
acceleration = a = 2.5 m/s²
time = t = 11 seconds
Therefore -
S = ut + \(\frac{1}{2} at^{2}\)
S = 5.5 x 11 + 0.5 x 2.5 x 11 x 11
S = 211.75 meters
Therefore, the object has travelled a distance of 211.75 meters.
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John has a utility function of the following: UL, C) = L ^BC ^(1-ẞ), where L is leisure and C is consumption. If he works, he receives a real wage w. Outside of the labor market, he has nonlabor market income V. And his endowment of time T is normalized to 1. And the price of goods p is also normalized to 1.
(a) Please write down his budget constraint.
(b) Assuming ẞ = 1/2, V = 100, w = 200, what is his optimal supply of labor?
(c) How much total income does he have?
(d) How much consumption will he make?
(e) Now, consider the case where John is subject to a 10% income tax on labor income only. What is his new optimal supply of labor?
(a) The budget constraint can be written as: C = wL + V, where C is consumption, w is the real wage, L is leisure, and V is non-labor market income.
(b) With ẞ = 1/2, V = 100, and w = 200, John's optimal supply of labor cannot be determined without information about his preferences for leisure and consumption. The utility function only represents his preferences, but we need additional information to determine the specific amount of labor he would choose to supply.
(c) John's total income is the sum of his labor income and non-labor market income: Total income = Labor income + Non-labor income = wL + V. Without knowing the specific value of L, we cannot calculate the total income.
(d) Similarly, without knowing John's preferences for leisure and consumption, we cannot determine the specific level of consumption he would choose.
(e) In the case where John is subject to a 10% income tax on labor income only, his new optimal supply of labor would depend on the tax rate's impact on his preferences and the trade-off between leisure and consumption. Without further information on his preferences and the specific tax structure, we cannot determine the new optimal supply of labor.
Additional information about John's preferences for leisure and consumption, as well as the specific tax structure, is necessary to calculate his optimal labor supply, total income, consumption, and the impact of the income tax on his labor supply.
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6. Robin pushes a wheelbarrow by exerting a 145-N force horizontally. Robin moves it 60.0 m at constant velocity in 25.0s
If Robin moves the wheelbarrow twice as fast, how much power is developed?
If Robin moves the wheelbarrow twice as fast, the power developed is 696 J/s.
What is the power is developed?
If Robin moves the wheelbarrow twice as fast, the power developed will be determined as follows;
Power = Energy / time
when moved twice as fast, new power developed is given as;
new power = Energy / time/2
new power developed = ( Fd ) / ( t/2)
where;
F is the applied forced is the displacementt is the timenew power developed = ( 145 N x 60 m ) / ( 25 s / 2 )
new power developed = 696 J/s
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dentify the following as open- or closed-loop control. a. controlling the water height in a toilet tank b. actuation of street lights at 6 p.m. c. stopping a clothes dryer when the clothes are dry d. actuation of an ice maker when the supply of cubes is low
Controlling the water height in a toilet tank, stopping a clothes dryer when the clothes are dry, actuation of an ice maker when the supply of cubes is low are closed loops. actuation of street lights at 6 p.m. is a open loop. Option a, c and d are closed loops. Option b is a open loop.
a. is an example of closed-loop control. This is because there is a feedback mechanism in place that continuously monitors the water level and adjusts the valve to maintain a constant level.
b. is an example of open-loop control. This is because the lights are turned on at a fixed time, regardless of the actual lighting conditions.
c. is an example of closed-loop control.
d. is an example of closed-loop control.
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what is the density rhoh of hot air inside the balloon? assume that this density is uniform throughout the balloon. express the density in terms of th , tc , and rhoc .
The density (ρh) of hot air inside the balloon, assuming it is uniform throughout, can be expressed in terms of Th, Tc and ρc (density of surrounding air) using the ideal gas law as follows: ρh = (ρc * Tc) / Th
The ideal gas law states that for a given amount of gas, the product of its pressure (P) and volume (V) is proportional to the product of its temperature (T) and the number of moles (n). Mathematically, it can be expressed as:
PV = nRT
Where R is the ideal gas constant.
Since we are considering a balloon filled with hot air, the pressure and volume inside the balloon remain constant. Therefore, we can modify the ideal gas law to relate the densities of hot air (ρh) and surrounding air (ρc) to their respective temperatures:
(ρh * V) / Th = (ρc * V) / Tc
Here, V represents the volume of the balloon, which cancels out on both sides of the equation.
Simplifying the equation:
ρh / Th = ρc / Tc
Rearranging the equation to solve for ρh:
ρh = (ρc * Tc) / Th
The density (ρh) of hot air inside the balloon, assuming it is uniform throughout, can be calculated using the ideal gas law. The expression for ρh in terms of Th (temperature of hot air), Tc (temperature of surrounding air), and ρc (density of surrounding air) is given as: ρh = (ρc * Tc) / Th.
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A perfectly inelastic demand curve Multiple Choice graphs as a line parallel to the vertical axis. has a price elasticity coefficient greater than unity. has a price elasticity coefficient of unity throughout. graphs as a line parallel to the horizontal axis.
A perfectly inelastic demand curve graphs as a line parallel to the vertical axis.
How does a perfectly inelastic demand curve graph?A perfectly inelastic demand curve is a type of demand curve where the quantity demanded remains constant regardless of changes in price. In other words, the demand is completely unresponsive to price changes. When graphed, a perfectly inelastic demand curve appears as a vertical line parallel to the vertical axis.
This means that no matter how much the price of a product or service changes, the quantity demanded by consumers remains the same. The price elasticity of demand coefficient for a perfectly inelastic demand curve is zero because there is no change in quantity demanded relative to price changes.
A perfectly inelastic demand curve is often seen in the case of essential goods or products with no close substitutes, where consumers are willing to pay any price to obtain the item. Examples may include life-saving medications or specific medical treatments.
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How much gravitational energy does a 65 kg skydiver have 650 m up in the sky?
Answer:
G.P.E = 414050 Joules or 414.05 Kilojoules
Explanation:
Given the following data;
Mass = 65 kg
Height = 650 m
We know that acceleration due to gravity is equal to 9.8m/s²
To find the gravitational potential energy;
Gravitational potential energy (GPE) is an energy possessed by an object or body due to its position above the earth.
Mathematically, gravitational potential energy is given by the formula;
\( G.P.E = mgh\)
Where;
G.P.E represents potential energy measured in Joules.m represents the mass of an object. g represents acceleration due to gravity measured in meters per seconds square. h represents the height measured in meters.Substituting into the equation, we have;
\( G.P.E = 65 * 9.8 * 650 \)
\( G.P.E = 414050 \)
G.P.E = 414050 Joules or 414.05 Kilojoules.
URGENT! Why are vectors important to the concept of relative velocity?
Answer:
Explanation:
In physics, vectors are useful because they can visually represent position, displacement, velocity and acceleration. When drawing vectors, you often do not have enough space to draw them to the scale they are representing, so it is important to denote somewhere what scale they are being drawn at.
After being assaulted by flying cannonballs, the knights on the castle walls (12.0 m above the ground) respond by propelling flaming pitch balls at their assailants. One ball lands on the ground at a distance of 81.1 m from the castle walls. If it was launched at an angle of 53.0° above the horizontal, what was its initial speed?
Answer:
28.6 m/s
Explanation:
Using the equation for the range of a projectile,
R = U²sin2θ/g where U = initial speed of flaming pitch balls, θ = launch angle = 53° and g = acceleration due to gravity = 9.8 m/s²
Making U subject of the formula, we have
U = √(gR/sin2θ)
substituting the values of the variables into the equation given that R = 81.1 m, we have
U = √(9.8 m/s² × 81.1 m/sin2(53°))
U = √(794.78 m²/s²/sin106°)
U = √(794.78 m²/s²/0.9613)
U = √(826.78 m²/s²)
U = 28.75 m/s
U ≅ 28.6 m/s
SPEAR is a storage ring at the Stanford Linear Accelerator which has a circulating beam of electrons that are moving at nearly the speed of light (2.998 108 m/s). If a similar ring is about 80.0 m in diameter and has a 0.59 A beam, how many electrons are in the beam
Answer:
n = 3.1x10¹²
Explanation:
To find the number of electrons we need to find first the charge (q):
\( I = \frac{q}{\Delta t} \rightarrow q = I*\Delta t \) (1)
Where:
I: is the electric current = 0.59 A
t: is the time
The time t is equal to:
\(v = \frac{\Delta x}{\Delta t} \rightarrow \Delta t = \frac{\Delta x}{v}\) (2)
Where:
x: is the displacement
v: is the average speed = 2.998x10⁸ m/s
The displacement is equal to the perimeter of the circumference:
\( \Delta x = 2\pi*r = \pi*d \) (3)
Where d is the diameter = 80.0 m
By entering equations (2) and (3) into (1) we have:
\(q = I*\Delta t = I*\frac{\Delta x}{v} = \frac{I\pi d}{v} = \frac{0.59 A*\pi*80.0 m}{2.99 \cdot 10^{8} m/s} = 4.96 \cdot 10^{-7} C\)
Now, the number of electrons (n) is given by:
\( n = \frac{q}{e} \)
Where e is the electron's charge = 1.6x10⁻¹⁹ C
\( n = \frac{q}{e} = \frac{4.96 \cdot 10^{-7} C}{1.6 \cdot 10^{-19} C} = 3.1 \cdot 10^{12} \)
Therefore, the number of electrons in the beam is 3.1x10¹².
I hope it helps you!
A boiler is being used to heat water. The graph shows the temperature of
the water every 5 minutes.
a. What state is the water in between points Q and R?
b. At which point does the water begin to boil?
c. What state is the water in at 110°c?
Answer:
a. Liquid state
b. At point R. The physical state of water at its boiling point temperature of 100 degree Celsius will be both liquid state as well as gaseous state.
c. at 110 degrees it is in gaseous state
Which of the following objects have gravitational potential energy?
A) a diver standing on a diving platform.
B) A hockey puck gliding across the ice.
C) an archers bow that is drawn back.
D) A runner waiting on the starting blocks.
Answer:
An archers bow that is drawn back
Answer:
A)a diver standing on a diving platform.
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A rock thrown to the right with an initial horizontal velocity of 4 m/s lands after 5
seconds. What horizontal distance has the rock traveled?
Answer:
20m
Explanation:
Using the equation s=d/t and re arranging it to solve for distance, d=St, where d=distance, s=speed, ant t=time, we can plug in known variables.
d=4*5
d=20m
there is a distance of 20m traveled
The horizontal distance traveled by the rock is 20 m
For horizontal motion, we use the formula below
⇒ Formula
s = vt.................... equation 1
⇒ Where
S = horizontal distance traveled by the rockv = velocity of the rockt = timeFrom the question,
⇒ Given:
v = 4 m/st = 5 seconds⇒ Substitute these values into equation 1
s = 4×5s = 20 mHence, The horizontal distance traveled by the rock is 20 m
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A ladder is balanced against a wall without moving. What
must be true about this ladder?
Answer:a no net force
Explanation: google lol
Multiple-Concept Example 7 deals with some of the concepts that are used to solve this problem. A cue ball (mass
=0.165 kg
) is at rest on a frictionless pool table. The ball is hit dead center by a pool stick, which applies an impulse of
+2.50 Nâ‹…
s to the ball. The ball then slides along the table and makes an elastic head-on collision with a second ball of equal mass that is initially at rest. Find the velocity of the second ball just after it is struck. Number Units
The velocity of the second ball just after it is struck is 15.15 m/s.
To solve this problem, follow these steps:
1. Calculate the initial velocity of the cue ball using the impulse-momentum theorem:
Impulse = Change in Momentum
Impulse = m * (v_f - v_i)
+2.50 N⋅s = 0.165 kg * (v_f - 0 m/s)
2. Solve for v_f (initial velocity of the cue ball):
v_f = Impulse / m
v_f = 2.50 N⋅s / 0.165 kg
v_f = 15.15 m/s
3. Since the collision is elastic and the masses are equal, the first ball comes to a stop and transfers all its velocity to the second ball. Therefore, the final velocity of the second ball is equal to the initial velocity of the cue ball.
So, the velocity of the second ball just after it is struck is 15.15 m/s.
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Numa determinada escala X, arbitrária, um termômetro marca 0°X para o ponto de fusão do gelo e 50°X para o ponto de ebulição da água, ao nível do mar. Que temperatura esse termômetro marcaria se fosse mergulhado em um líquido cuja temperatura é de 50°C?
Answer:
the temperature measured by the thermometer is 25 ° X
Explanation:
The computation of the temperature measured by the thermometer is shown below:
Here is the thermometric scale list
(X - 0) ÷ C - 0 = (50 - 0) ÷ (100 - 0)
X ÷ C = 50 ÷100
X = C ÷ 2
Now if there is 50 degrees celcius
So, the x would be
= 50 ÷ 2
= 25 ° X
Hence, the temperature measured by the thermometer is 25 ° X
The same is to be considere d
Como puedo saber la carga de una partícula en un campo magnético
The charge of a particle in a magnetic field can be determined by measuring the force, velocity, and strength of the magnetic field using the Lorentz force equation. There are various methods to measure the charge, such as using a particle accelerator or mass spectrometer.
In a magnetic field, charged particles experience a force that can be used to determine their charge. This force, known as the Lorentz force, is given by the equation F = q(v x B), where F is the force, q is the charge of the particle, v is the velocity of the particle, and B is the strength of the magnetic field.
To determine the charge of a particle in a magnetic field, you can measure the velocity of the particle and the strength of the magnetic field, and then measure the force experienced by the particle. By rearranging the equation F = q(v x B), you can solve for the charge q.
It is important to note that the Lorentz force only applies to charged particles that are in motion. If the particle is stationary, it will not experience any force in a magnetic field.
In practice, there are many ways to measure the charge of a particle in a magnetic field, such as using a particle accelerator or a mass spectrometer. These techniques involve manipulating the motion of the particle in a controlled way and measuring the resulting forces and velocities to determine its charge.
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Complete question:
How can I know the charge of a particle in a magnetic field?
A 954-kg satellite orbits the Earth at a constant altitude of 99-km.
(a) How much energy must be added to the system to move the satellite into a circular orbit with altitude 193 km?
(. )MJ
(b) What is the change in the system's kinetic energy?
(. )MJ
(c) What is the change in the system's potential energy?
(. )MJ
(a) Energy needed to move the satellite to an orbit with a height of 193 km: 8.44 x 10⁹ J
(b) Change in the system's kinetic energy: 1.62 x 10⁹ J(c) Change in the system's potential energy: 6.82 x 10⁹ J.
(a) To move the satellite into a circular orbit with altitude 193 km, energy must be added to the system. The energy required can be calculated using the formula:
ΔE = GMm * [(2/r₁) - (1/r₂)]
Where ΔE is the change in energy, G is the gravitational constant (6.67430 × 10^-11 m^3 kg^-1 s^-2), M is the mass of the Earth (5.972 × 10^24 kg), m is the mass of the satellite (954 kg), r₁ is the initial distance from the center of the Earth (altitude 99 km + radius of the Earth), and r₂ is the final distance from the center of the Earth (altitude 193 km + radius of the Earth).
Plugging in the values:
ΔE = (6.67430 × 10^-11) * (5.972 × 10^24) * (954) * [(2/(99,000 + 6,371,000)) - (1/(193,000 + 6,371,000))]
Calculating this expression will give the change in energy required in joules (J).
(b) The change in the system's kinetic energy can be found by subtracting the initial kinetic energy from the final kinetic energy. The initial kinetic energy can be calculated using the formula:
KE₁ = (1/2) * m * v₁^2
Where KE₁ is the initial kinetic energy, m is the mass of the satellite (954 kg), and v₁ is the initial velocity of the satellite.
The final kinetic energy can be calculated using the formula:
KE₂ = (1/2) * m * v₂^2
Where KE₂ is the final kinetic energy, m is the mass of the satellite (954 kg), and v₂ is the final velocity of the satellite in the circular orbit.
The change in kinetic energy is then given by:
ΔKE = KE₂ - KE₁
Plugging in the values and calculating the expressions will give the change in kinetic energy in joules (J).
(c) The change in the system's potential energy can be found by subtracting the initial potential energy from the final potential energy. The initial potential energy can be calculated using the formula:
PE₁ = -G * M * m / r₁
Where PE₁ is the initial potential energy, G is the gravitational constant (6.67430 × 10^-11 m^3 kg^-1 s^-2), M is the mass of the Earth (5.972 × 10^24 kg), m is the mass of the satellite (954 kg), and r₁ is the initial distance from the center of the Earth (altitude 99 km + radius of the Earth).
The final potential energy can be calculated using the formula:
PE₂ = -G * M * m / r₂
Where PE₂ is the final potential energy, G is the gravitational constant (6.67430 × 10^-11 m^3 kg^-1 s^-2), M is the mass of the Earth (5.972 × 10^24 kg), m is the mass of the satellite (954 kg), and r₂ is the final distance from the center of the Earth (altitude 193 km + radius of the Earth).
The change in potential energy is then given by:
ΔPE = PE₂ - PE₁
Plugging in the values and calculating the expressions will give the change in potential energy in joules (J).
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What is Newton's gravitational constant G write down its numerical value and SI unit?.
The S.I value of Newton's gravitational constant G will be 6.674×10⁻¹¹ (Newton.meter².kg⁻²) .
The gravitational constant, denoted by the capital letter G and also known as the universal gravitational constant, Newtonian constant of gravitation, or Cavendish gravitational constant, is an empirical physical constant that is used to calculate the gravitational effects in both Albert Einstein's theory of general relativity and Sir Isaac Newton's law of universal gravitation.
It is the proportionality constant in Newton's law that links the gravitational force between two bodies to the sum of their respective masses and the square root of their distance. It quantifies the relationship between the energy-momentum tensor and the spacetime geometry in the Einstein field equations (also referred to as the stress–energy tensor).
We can reasonably say that we know the measured value of the constant to four significant digits. SI units is 6.674 ×10⁻¹¹(Newton.meter².kg⁻²) .
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What's the free body diagram for:
Mr. Seifert needs to push a cardboard box down the hallway for Ms. Wang. The box has a mass of 40 kg and he is pushing it with an acceleration of 2 m/s/s. Because the cardboard does not slide easily, there is a friction force of 25 Newtons acting on the box to the LEFT. How much force is Mr. Seifert applying to the box to move it forward to the RIGHT?
(a) The free body diagram for representing all the forces acting on an object.
(b) The force Mr. Seifert is applying to the box to move it forward to the RIGHT is 105 N.
What is free body diagram?
A free body diagram is a graphical illustration of all the forces acting on an object.
The force applied by Mr Seifert is calculated by applying Newton's second law of motion as follows;
F - Ff = ma
where;
F is the applied forceFf is the force of frictionm is the mass of the cardboarda is the acceleration of the cardboardThe given parameters include;
mass of the cardboard = 40 kg
force of friction = 25 N
acceleration of the cardboard = 2 m/s²
The force applied by Mr Seifert is calculated as follows;
F = Ff + ma
F = 25 N + (40 kg x 2 m/s²)
F = 105 N
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A spring has a spring constant of 300 N/m. How much force is in thespring if it is stretched 0.25 m?32
Force applied is directly proportional to displacement.
It is given by the formula
\(F=-kx\)Here F is the force , k is the spring constant , x is the displacement.
Substituting the values,
\(F=-300\text{ }\ast0.25\)\(F=-75\text{ N}\)A boat driver travelling west at 5km/hr finds that the wind appears to blow from the south. On doubling it's speed, the wind appears to blow from the southwest. Find the magnitude and direction of the winds velocity
The wind velocity can be determined by analyzing the boat's motion and the apparent wind direction.
1. The boat is traveling west at a speed of 5 km/hr.
2. The apparent wind direction is from the south.
3. When the boat's speed is doubled, the apparent wind direction is from the southwest.
To find the magnitude and direction of the wind's velocity, we can consider the boat's velocity as well as the apparent wind direction in both scenarios.
Let's denote the magnitude of the wind's velocity as "v" and the direction as "θ."
1. When the boat is traveling at 5 km/hr:
- The boat's velocity is 5 km/hr to the west.
- The apparent wind direction is from the south.
- Therefore, the wind's velocity can be represented as the vector sum of the boat's velocity and the apparent wind direction. This vector sum forms a right angle triangle.
- Using trigonometry, we can find the magnitude and direction of the wind's velocity in this scenario.
2. When the boat's speed is doubled to 10 km/hr:
- The boat's velocity is 10 km/hr to the west.
- The apparent wind direction is from the southwest.
- Again, the wind's velocity can be represented as the vector sum of the boat's velocity and the apparent wind direction, forming a right angle triangle.
- By using trigonometry, we can determine the magnitude and direction of the wind's velocity in this case.
By comparing the two scenarios, we can find the change in the wind's velocity magnitude and direction when the boat's speed is doubled. This information will help us determine the actual magnitude and direction of the wind's velocity.
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A 15 N force and a 45 N force act on in object in opposite directions. What is the net force on the object?
Answer:
30N in the direction the 45N acts.
Explanation:
Fnet = F1 + F2 (the vector sum of the forces)
Assigning a positive direction to the 45N force and a negative direction to the 15N force gives:
Fnet = 45 - 15
Fnet = 30N
Since the answer is positive, it is in the direction the 45N force acts.
PLEASE HELP (multiple choice)
What is the space between to items
Answer:
A Gap is the space between
Answer: distance, a gap
Explanation:
In the graph, the dotted line represents potential energy and the solid line represents kinetic energy.
Determine which senario bests fits the graph.
A. a car accelerating on the highway.
B. a rollercoaster at the end of the ride.
C. a car coming to a red light on a highway.
D. a roller coaster on a low-friction track.
Answer: D
Explanation: The roller coaster gains and loses kinetic energy throughout the ride.
A pleasure filled Excursion into the realm of Physics: 1. Before applying the Super Teflon Anti-friction spray Clark Griswold reviews the trial run stats. His 85.0 kg mass took 5.00 sec to stop with an applied force of 15.0 N. The titanium disc sled had a mass of 5.20 kg. What is Clark's velocity before the stopping force is applied?
Answer:
/
Explanation:
Efficiency of a machine is always less than 100% why?
The reason the efficiency is always less than 100% is because there is always some sort of friction in the machine.
Answer: because of friction
how does 3rd class lever make our work easier
Answer:
the third class lever makes our work easier as effort is located at the middle, load at first and fore is applied at the buttom. which helps in accelerating work.
hope it is helpful to you
Why should a person warm up before exercising?
To gradually increase blood flow to the body
To spend extra time thinking about exercise
To keep from getting too tired after the activity
To help increase muscle strength
Answer:
To gradually increase blood flow to the body
Compare the physical sciences to the life sciences.
1.Life science involves fields of discipline catering to living organisms such as we humans while physical science caters to non-living organisms.
2.Life science has more fields of discipline than physical science.
3.Physical science relies on laws and theories to explain concepts while life science relies on biological explanations and can also rely on theories.
Physical science is concerned with the study of natural but non-living objects, while life science is the scientific study of living organisms. There is also a field called biophysics, which is where physics theories and methods are used to study biological systems.