.An object has a mass of 10 kg and an acceleration of 20 m/s2. What is the force on the object?

For a beam of length 20.0 m and mass 40.0 kg resting on two supports placed at 5.0 m from each end with a person of mass 50.0kg on the beam between the supports, the value of N₁ + N₂ is 882.9 N.

The weight of the beam and the person is equal to the sum of the reaction forces at the supports:

W + P = N₁ + N₂

where W = weight of the beam and

P = weight of the person.

W = mg = 40.0 kg × 9.81 m/s² = 392.4 N

P = mg = 50.0 kg × 9.81 m/s² = 490.5 N

So, N₁ + N₂ = W + P = 882.9 N.

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Answer:

Hi

Explanation:

A H20

The initial acceleration of the steel shuttle is approximately 16.97 m/s².

To find the initial acceleration of the 750 g steel shuttle, we will use the following terms: tension, angle, mass, force, and acceleration. Here are the steps to calculate the acceleration:

1. Convert the mass of the shuttle to kilograms: 750 g = 0.75 kg.

2. Determine the horizontal component of the tension force, which is the force acting on the shuttle. Since the tension is at a 45° angle, we will use the cosine function to find the horizontal component: F_horizontal = Tension * cos(angle) = 18.0 N * cos(45°) = 18.0 N * 0.7071 ≈ 12.73 N.

3. Use Newton's second law of motion, which states that Force = mass * acceleration, to find the acceleration of the shuttle: F_horizontal = m * a.

4. Solve for the acceleration (a): a = F_horizontal / m = 12.73 N / 0.75 kg ≈ 16.97 m/s².

So, the initial acceleration of the steel shuttle is approximately 16.97 m/s².

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The initial acceleration of the steel shuttle is approximately 16.97 m/s².

To find the initial acceleration of the 750 g steel shuttle, we will use the following terms: tension, angle, mass, force, and acceleration. Here are the steps to calculate the acceleration:

1. Convert the mass of the shuttle to kilograms: 750 g = 0.75 kg.

2. Determine the horizontal component of the tension force, which is the force acting on the shuttle. Since the tension is at a 45° angle, we will use the cosine function to find the horizontal component: F_horizontal = Tension * cos(angle) = 18.0 N * cos(45°) = 18.0 N * 0.7071 ≈ 12.73 N.

3. Use Newton's second law of motion, which states that Force = mass * acceleration, to find the acceleration of the shuttle: F_horizontal = m * a.

4. Solve for the acceleration (a): a = F_horizontal / m = 12.73 N / 0.75 kg ≈ 16.97 m/s².

So, the initial acceleration of the steel shuttle is approximately 16.97 m/s².

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The correct answer choice for the explanatory and response variables of a scatterplot depends on the context and the variables being studied.

The correct answer choice for the explanatory and response variables of a scatterplot depends on the context and the variables being studied.

In general, the explanatory variable is the independent variable, which is the variable being manipulated or controlled in the study.

The response variable is the dependent variable, which is the variable being measured or observed in response to changes in the explanatory variable.

For example, if we are studying the relationship between voltage and the rotation of an electric motor, then the explanatory variable would be voltage, and the response variable would be rotation.

As voltage is being manipulated, the resulting changes in the rotation of the motor are being observed and measured.

Conversely, if we are studying the relationship between rotation and the voltage required to achieve that rotation, then the explanatory variable would be rotation, and the response variable would be voltage.

As rotation is being manipulated, the resulting changes in the required voltage are being observed and measured.

It is important to carefully consider the variables and their relationships when interpreting a scatterplot.

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A small rocket is propelled forward by expelling gas at a rate of 3.63 kg/s and the magnitude of the thrust force of the rocket is 198.198 N.

In order to find the magnitude of the thrust force of a small rocket that is propelled forward by expelling gas at a rate of 3.63 kg/s and an exhaust speed of 54.6 m/s, we can use the formula for thrust force:

Thrust force = mass flow rate x exhaust velocity

Thrust force = 3.63 kg/s x 54.6 m/s

Thrust force = 198.198 N

Therefore, the magnitude of the thrust force of the rocket is 198.198 N.

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Answer:

True

Explanation:

Because with more force the car will move faster than it did before!!!

The weight of a sheet of aluminum that is 36" long, 24" wide, and thick would be 7.776 lbs.

We need to first find the volume of the aluminum sheet in cubic inches, and then use its density to calculate its weight.

The volume of the aluminum sheet can be calculated as:

V = l x w x h = 36 in x 24 in x 0.1 in = 86.4 cubic inches

where l is the length, w is the width, and h is the thickness of the sheet.

The density of aluminum is 0.090 lb/in^3, as given in the problem.

Therefore, the weight of the aluminum sheet can be calculated as:

W = V x density = 86.4 cubic inches x 0.090 lb/in^3 = 7.776 lbs

Therefore, the weight of the aluminum sheet is 7.776 lbs.

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Answer:

Models are used to study atoms because we can never really see an atom up close, and a model is like a super magnified version of the atom. Plus, its easier to study from them because we can pin point the different characteristics of the atom (Protons, Neutrons, etc.)

Explanation:

Hope this helps! :>

Answer:

I believe its because the molecules are to small to see with the human eye and because the process would be very dangerous and somebody could get hurt.

The force on the string with a mass of 1 kg attached it is 250 N.

Force is the product of mass and acceleration. The S.I unit of force is Newton (N). Force is a vector quantity because it can be measured in terms of magnitude and direction.

To calculate the force, we use the formula below

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

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The equation for the path of a comet that follows a hyperbolic trajectory around the sun can be derived based on certain conditions. Assuming that the closest distance of the comet to the sun is 2 × 10⁹ miles and the path before and after approaching the solar system is at a right angle, we can determine the equation for the comet's path.

A hyperbolic path can be described by the equation:

r(θ) = a / (1 + e * cos(θ))

Where: r is the distance from the focus (the sun) to the comet at a given angle θ, a is a constant that represents the semi-major axis of the hyperbola, e is the eccentricity of the hyperbola.

In this case, since the comet's path approaches the sun at a closest distance of 2 × 10⁹ miles, we can set this value as the value of a. The eccentricity (e) can be determined based on the right angle condition.

The equation for the path of the comet would then be: r(θ) = 2 × 10⁹ / (1 + e * cos(θ))

By determining the value of e and plugging it into the equation, we can obtain the specific equation for the path of the comet.

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The average speed of the particles in terms of the speed of light is 0.976c. Given that, The particle-X has a lifetime of 256.2.A particle track detector is used to measure the speed of particles. On average, the particles leave 10.6 cm long tracks before they decay into other particles that are not observable by the detector.

The formula to calculate the average speed of the particles is given as;v = d / t Where,v = velocity of the particles, d = distance traveled by the particles, and t = time taken by the particles. The distance traveled by the particles before they decay is 10.6 cm = 0.106 m. The lifetime of the particle is given as 256.2 s. Therefore, time taken by the particle to decay, t = 256.2 s.

The speed of the particles can be calculated as follows; v = d / tv = 0.106 / 256.2v = 4.135 × 10^-4 m/s The speed of the particles in terms of the speed of light can be calculated as follows; Speed of light = 3 × 10^8 m/s Average speed of the particles in terms of the speed of light, v/c= (4.135 × 10^-4) / (3 × 10^8)= 0.976 × 10^-8= 0.976cTherefore, the average speed of the particles in terms of the speed of light is 0.976c.

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Answer:

a) velocity - time realation

that graph's gradient gives the uniform acceleration

The experiment that provides the most direct evidence of the de Broglie hypothesis that particles can display wavelike behavior is the double-slit experiment with electrons.

In this experiment, a beam of electrons is fired at a screen with two parallel slits.

The electrons pass through the slits and create an interference pattern on a detection screen behind the slits.

The interference pattern is similar to the pattern created by waves, such as light waves, passing through the same slits.

This observation supports the idea that the electrons have wave-like properties, as predicted by the de Broglie hypothesis.

The experiment demonstrates the wave-particle duality of matter, where particles can behave as both waves and particles depending on the experimental conditions.

The wave-like behavior of particles is described by their de Broglie wavelength, which is related to their momentum and can be calculated using the de Broglie relation.

The double-slit experiment with electrons provides direct evidence of this wave-like behavior and supports the fundamental principles of quantum mechanics.

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How hard you must push down on the handle is by applying a force of 215.63 N

The moment of a force about a point is the turning effect of the force about that point.

The moment of a force M = Fd where

Now, for you to lift up the car, the moment due to your force about the fulcrum, M equals the moment due to the force on back of car. M'

M = M'

FD = F'd where

Making F subject of the formula,we have

F = F'd/D

Substituting the values of the variables into the equation,we have

F = F'd/D

F = 6900 N × 0.050 m/1.6 m

F = 345 Nm/1.6 m

F = 215.625 N

F ≅ 215.63 N

So, how hard you must push down on the handle is by applying a force of 215.63 N

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Answer:

A

Explanation:

Answer:

How do static and sliding friction affect the speed of a paperback book, a flat eraser and a key?

Prediction: Which item (paperback book, flat eraser, or key) will have the most static friction and which item will have the most sliding friction?  Make sure your prediction gives an explanation of your reasoning.

Explanation:

Answer:

Yes, in case of uniform velocity

Explanation:

This is the case of uniform velocity. If a body covers equal displacement in equal intervals of time, then the velocity of a body is said to be ‘Uniform Velocity’. It meas that the velocity of a body remains constant during the motion and it does not change.

Since, acceleration is defined as the rate of change of velocity.

Therefore, if there is no change in velocity or in other words the change in velocity is zero, then the acceleration is also zero.

a = ΔV/t = 0/t

a = 0 m/s²

So, the acceleration of the body is 0 m/s², but it has a uniform velocity

Hence, it is possible for an object that, object with zero acceleration have velocity, which is the case case of uniform velocity.

Answer: 4 miles.

Explanation:

Let's use the rectangular coordinates (x,y)

And define:

East as the positive x-axis.

North as the positive y-axis.

We know that, if the jogger starts at the point (0mi, 0mi):

"Runs 3 miles East"

Then the new position is (3mi, 0mi)

"Then 7 miles west"

The new position is (3mi - 7mi, 0mi) = (-4mi, 0mi)

Now, the displacement is calculated as the difference between the initial position and the final position, and this can be written as:

D = I (-4mi, 0mi) - (0mi, 0mi)I = √( (-4mi - 0mi)^2 + (0mi - 0mi)^2) = 4mi

The total displacement is 4 miles.

A planet whose mass is half of the mass of Earth and radius equal to the radius of the Earth, the acceleration due to gravity on the surface of the planet would be  19.6m/s².

Large, circular celestial objects that are neither stars nor their remnants are known as planets. The nebular hypothesis, which states that an interstellar cloud collapses out of a nebula to create a young protostar orbited by a protoplanetary disc, is currently the best theory for planet formation. The formula for the acceleration caused by gravity on earth's surface is,

g = GM/R

Now, Mp = M/2

Rp = R/2

The planet's gravitational acceleration is,

gp =  GMp/Rp

gp = (GM/2)/(R²/4) = 2g

gp = 2 × 9.8 = 19.6m/s²

Therefore, the acceleration due to gravity on the surface of the planet will be 19.6m/s².

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Answer: is  13

Explanation:

Given data,

Mass,

Acceleration,

Spring constant,

Acceleration due to gravity,

Accelerating upward,

Comsider the formula for force.

Thus, the spring compression is 25.68 cm.

J. J. Thomson used a cathode-ray tube to calculate the charge-to-mass ratio of the electron. The deflection of cathode rays towards the positively charged surface and emission of green light at the far end of the tube confirmed that they are negatively charged particles.

In 1897, J.J Thomson performed a cathode ray tube experiment to determine the charge-to-mass ratio of electrons.

Due to high voltage, a beam of particles was allowed to flow from the negatively charged end to the positively charged end of the tube.

One end of the tube was painted with phosphorous. When electrons struck the wall a green spark was observed which confirmed the presence of negatively charged particles i.e. electrons.

To put it simply, cathode rays came from the cathode tube and deflected towards a positively charged plate showing that they are negatively charged particles.

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A ball is thrown vertically into the air. Because of air resistance it's speed when it returns to Its starting starting level compared with its initial speed is lower.

Air resistance, also known as drag, is a force that opposes the motion of an object through the air. As the ball travels upwards, air resistance slows it down, reducing its speed. As the ball falls back to its starting level, air resistance continues to oppose its motion, further reducing its speed.

Therefore, the speed of the ball when it returns to its starting level will be lower than its initial speed due to the effects of air resistance.

In mathematical terms, the speed of the ball at any given time can be calculated using the equation v = v0 - gt, where v0 is the initial speed, g is the acceleration due to gravity, and t is the time elapsed. Air resistance adds an additional force that opposes the motion of the ball, reducing its speed even further.

So, the correct answer is that the ball's speed when it returns to its starting level compared with its initial speed is lower because of air resistance.

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Answer: C

Explanation: i hoped that helped!