An object has a gravitational potential energy of 72250 J and a mass of 425kg. How high is it above the ground?

Grouping data refers to the process of categorizing or organizing data based on specific criteria or attributes.

It involves grouping similar data points together to gain a better understanding of patterns, relationships, and trends within the dataset. By grouping data, you can simplify complex information and derive meaningful insights from large amounts of data. The purpose of grouping data is to create subsets or clusters that share common characteristics.

This enables easier analysis, summarization, and comparison of data within each group. Grouping can be performed on various types of data, such as numerical, categorical, or time-based data. Grouping data allows for the exploration of data at different levels of granularity.

For example, you can group sales data by region to analyze regional performance, or group customer data by demographics to identify specific customer segments. This process helps in identifying outliers, detecting patterns, and making data-driven decisions.

Common techniques for grouping data include using functions like GROUP BY in SQL or utilizing data visualization tools to create charts or graphs that illustrate the grouped data. Grouping can be applied in various fields, such as marketing, finance, healthcare, and research, to uncover insights and support decision-making processes.

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Answer:

0.73m/s2

Explanation:

The speed at which the passengers move is the final speed of the plane

Hence acceleration = V-U/t; change in velocity and t is time taken. U is the initial velocity which is 0m/s

a = 73-0/100= 0.73m/s2

Answer:

the answer is weight

Explanation:

Answer:

Weight

Explanation: Just took the quiz

The height that will illustrate the distance will be d = 6.36m

Based on the information given, the length of the vine will be:

L = ✓(16² + 27.7)²

L = 32m

The velocity of Jane when she reaches position B will be:

V = ✓2gh

V = ✓(2 × 9.8 × 4.3)

V = 9.18m/s

We will apply the conversation of momentum. This will be:

50 × 9.18 = (50 + 80)V1

V1 = 3.53m/s

Therefore, the height that will illustrate the distance will be:

31.36² + d² = 32²

d² = 32² - 31.36²

d = 6.36m

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The three basic rules for the electric charge are like charges repel each other, unlike charges attract each other and the charges in the system are constant. The unit of charge is coulomb (C).

Electric charge is of two types and they are positive and negative charges. The negative charge is free electrons and the positive charges are the holes in the conductors. The basic rules are, two positive charges repel each other and two negative charges repel each other and they are called like charges.

One positive and one negative charge attract each other and hence they are unlike charges. The attractional force and repulsion force increase with a decrease in the distance of separation. The charges remain constant in the system and it is called as law of conservation of charges in the system.

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position in a gravitation field (c)

Answer:

The answer is C. position in a gravity field

Answer:

B.) 0.3s

Explanation:

The period of a wave that has a frequency of 3 Hz is 0.3s. Hence option B is correct.

Wave is is a disturbance in a medium that carries energy as well as momentum . wave is characterized by amplitude, wavelength and phase. Amplitude is the greatest distance that the particles are vibrating. especially a sound or radio wave, moves up and down. Amplitude is a measure of loudness of a sound wave. More amplitude means more loud is the sound wave.

Wavelength is the distance between two points on the wave which are in same phase. Phase is the position of a wave at a point at time t on a waveform.

There are two types of the wave longitudinal wave and transverse wave.

Longitudinal wave : in which, vibration of the medium (particle) is parallel to propagation of the wave. Sound wave is a longitudinal wave. Transverse wave : in which, vibration of the medium (particle) is perpendicular to propagation of the wave. Light wave is a transverse wave.

Time period of the wave is inverse to the frequency of the wave.  

T = 1/f

T = 1/3

T = 0.333 s

Hence option B is correct.

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Answer:

The smallest value is n= 2

Explanation:

The balmer equation is given below

1/λ = R(1/4 - 1/n₂²).

R= 1.0973731568508 × 10^7 m^-1

λ= 400*10^-9 m

(400*10^-9)= 1.0973731568508 × 10^7 (1/4-1/n²)

(400*10^-9)/1.0973731568508 × 10^7

= 1/4 - 1/n²

364.51 *10^-16= 1/4 - 1/n²

1/n²= 1/4 -364.51 *10^-16

1/n² = 0.25-3.6451*10^-14

1/0.25= n²

4= n²

√4= n

2= n

The smallest value is N= 2

According to Dalton,

Water molecules are made of two different kinds of atoms, which are considered hydrogen and Oxygen

Water molecules have twice as many hydrogen atoms as Oxygen atoms

Water molecules have one oxygen atom for every two hydrogen atom

Answer:

Tension

Explanation:

Answer:

a body which was thrown in space ,moves under the influence of gravity only is defined as projectile.

Answer:

hope it is you

Answer:

74.0 meters

Explanation:

We can use the kinematic equation for displacement with constant acceleration to solve this problem:

Δy = v0t + 1/2at^2

where Δy is the displacement (i.e., the change in height), v0 is the initial velocity (which is 0), a is the constant acceleration, and t is the time taken.

Plugging in the given values, we get:

Δy = 0 + 1/2(71.0 m/s^2)(1.45 s)^2

Δy = 74.0 m

Therefore, the maximum altitude achieved by the rocket is 74.0 meters above the ground.

Answer:

   R = ½ R₀

Explanation:

This is an exercise in Ohm's law,

           V = IR

in the initial case

           V₀ = I₀ R₀               (1)

indicates that the voltage remains constant and the current is doubled

             I = 2 I₀

           V₀ = I R

we substitute

           V₀ = 2 I₀ R

            R = ½ V₀ / I₀

we replace by equation 1

            R = ½ R₀

The distance traveled by the person to come to a complete stop in 38 ms at a constant acceleration of 60 g is approximately 273.42 meters.

The distance that a person covers to come to a complete stop in 38 ms at a constant acceleration of 60 g can be calculated using the kinematic equation.

The formula is given by, d = (v^2 - u^2) / 2a, where d is the distance traveled, v is the final velocity, u is the initial velocity, and a is the acceleration given in g units.

To solve the problem, we need to first convert the acceleration given in g units to meters per second squared (m/s²). We know that 1 g is equivalent to 9.8 m/s².

Hence, 60 g is equivalent to 60 × 9.8 m/s² = 588 m/s².

Substituting the values in the above formula, we get,d = (0 - u^2) / 2a= u^2 / 2a, since the final velocity is 0 when the person comes to a complete stop= u^2 / 2 × 588= u^2 / 1176 m

The time taken, t = 38 ms = 0.038 s.

Now, we know that acceleration, a = (v - u) / t.

We can rearrange the above equation to find the final velocity, v. We get,v = u + at

Substituting the values, we get,588 = u + (588 × 0.038)u = 588 - (588 × 0.038)u = 567.816 m/s

Using the value of u, we can now find the distance traveled using the kinematic equation as, d = u^2 / 1176= (567.816)^2 / 1176≈ 273.42 m.

Therefore, the distance traveled by the person to come to a complete stop in 38 ms at a constant acceleration of 60 g is approximately 273.42 meters.

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The average distance from mars to the sun if Mars had an orbital period of 1.88 years is 2.27 * \(10^{8}\) km

P² = a³

P = Orbital period

a = Average distance

P = 1.88 years

a³ = 1.88²

a³ = 3.53

a = 1.52 AU

a = 1.52 * 1.496 * \(10^{8}\) km

a = 2.27 * \(10^{8}\) km

The formula used to solve the given problem is derived from Kepler's third law of planetary motion. AU is the abbreviated from of Astronomical unit. 1 AU = 1.496 * \(10^{8}\) km

Therefore, the average distance from mars to the sun is 2.27 * \(10^{8}\) km

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The owner's velocity is in the opposite direction of the combined velocity of the dog and the cat, and its magnitude is approximately 0.916 m/s.

To solve the given problem, we can use the principle of conservation of momentum to find the direction and magnitude of the owner's velocity.

Let's denote the velocity of the dog as v1 (northward), the velocity of the cat as v2 (eastward), and the velocity of the owner as v (unknown).

According to the conservation of momentum, the total momentum before the interaction is equal to the total momentum after the interaction.

The total momentum before the interaction is given by:

Total momentum before = (mass of the dog * velocity of the dog) + (mass of the cat * velocity of the cat) + (mass of the owner * velocity of the owner)

Mass of the dog (m1) = 24.4 kg

Velocity of the dog (v1) = 2.14 m/s

Mass of the cat (m2) = 5.53 kg

Velocity of the cat (v2) = 3.56 m/s

Mass of the owner (m3) = 78.5 kg

Velocity of the owner (v) = unknown

Total momentum before = (24.4 kg * 2.14 m/s) + (5.53 kg * 3.56 m/s) + (78.5 kg * v)

The total momentum after the interaction is zero since the owner has the same momentum as the pets taken together.

Total momentum after = 0

Equating the two expressions:

(24.4 kg * 2.14 m/s) + (5.53 kg * 3.56 m/s) + (78.5 kg * v) = 0

Simplifying the equation:

(52.216 kg·m/s) + (19.6488 kg·m/s) + (78.5 kg * v) = 0

71.8648 kg·m/s + (78.5 kg * v) = 0

Solving for v:

78.5 kg * v = -71.8648 kg·m/s

v = -71.8648 kg·m/s / 78.5 kg

v ≈ -0.916 m/s

Therefore, the direction of the owner's velocity is opposite to the combined velocity of the dog and the cat, and the magnitude of the owner's velocity is approximately 0.916 m/s.

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Based on the given diagram, we can only reasonably conclude statement c, that the upper plate is positive and the lower plate is negative

What is Electric Field?

Electric field is a concept used in physics to describe the influence that an electric charge exerts on other charges in its vicinity. It is defined as the force experienced by a positive test charge placed in the vicinity of an electric charge, divided by the magnitude of the test charge

The upper plate is positive and the lower plate is negative: This statement is a common convention for charged parallel metal plates in a capacitor. The positive plate is usually considered as the plate with electric field lines originating from it (in this case, the upper plate), and the negative plate is usually considered as the plate with electric field lines terminating on it (in this case, the lower plate). So, this statement is likely to be true based on convention.

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Answer:

hope you can understand

Answer:

answer is C

-they could be shown to be false by evidence

The acceleration of the dish washer is obtained as 5.1 m/s^2.

A free body diagram is a type of image that physicists use to illustrate the forces operating on an item in a certain circumstance.

By dissecting the motion of the object into its component forces and displaying the direction and amount of each force acting on the object, the diagram may be used to study the motion of the object.

We know that;

Net force =Applied force - Frictional force

35a = 225 - 45

a = 225 - 45/35

a = 5.1 m/s^2

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Answer:

\(\huge\boxed{\sf v = 2.7\ m/s}\)

Explanation:

Radius = r = 1.14 m

Angular velocity = ω = 2.38 rad/s

Linear velocity = v = ?

v = rω

v = (1.14)(2.38)

\(\rule[225]{225}{2}\)

Answer:

Answer is "two tectonic plates slide past eachother" ( for a pe x)

Explanation:

Answer:

the wind carries abrasive materials

Explanation:

such as sand and salt over time theses small particles slowly strip way at the land form sculpting it by eroding the softer layers first

Answer:

She applies 75N of force

Explanation:

F=ma

50=20(2.5)

F=30(2.5)

F=75 N

The magnitude of the applied force is 3369.57 N.

Force can be defined as the product of mass and acceleration.

To calculate the magnitude of the applied force, we use the formula below.

Formula:

Where:

Make F the subject of the equation

From the question.

Given:

Substitute these values into equation 2

Hence, the magnitude of the applied force is 3369.57 N.

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The time taken for the bicycle to come to a complete stop with an initial velocity of 13.5 m/s is 27 seconds.

Time can be defined as the calculable measure of motion with respect to before and afterness.

To calculate the time it takes the cyclist to bring the bicycle to complete stop, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence the time taken for the bicycle to stop completely is 27 seconds.

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Explanation:

Given:

Diameter = 200 m

Radius, r = 200/2 = 100 m

Time taken, t = 30 seconds

Formula to be used:

Distance traveled, = circumference of circle = 2πr

Answer:

Putting all the values, we get

Distance traveled = 2πr

So, the distance traveled by Raju is 628.57 m.

Now, magnitude of the displacement,

At the end of 30 seconds, Raju will come to starting position or initial position, so displacement is zero.

The resultant force that water exerts on the overhang sea wall along abc is 179 kN.

Force is a physical quantity that describes the interaction between two objects, such as a push or a pull. It is defined as any influence that causes an object to undergo a change in motion or deformation. Force is a vector quantity, meaning that it has both magnitude (size or strength) and direction.

Component that is horizontal. Because AB is horizontal, there is no horizontal component. The horizontal component of BC's force is.

(Fbc)h =γwhˉA=(1000kg/m3)(9.81m/s2)(1.5m+21(2m))(2m(2m))=98.1(103)N.

Component that is vertical. The weight of the water contained in blocks Abefa and Bcdeb (shown shaded in Fig. a) is equal to the force on AB and the vertical component of the force on BC. Here,

Aabefa=1.5m(2.5m)=3.75m2and

2Abcdeb=(3.5m)(2m)–4π(2m)2=(7–p)m2. Then,

Fab=γwVabefa=(1000kg/m3)(9.81m/s2)[(3.75m2)(2m)] =73.575(103)N=73.6N (FBC)v=γwVbcdeb=(1000kg/m3)(9.81m/s2)[(7–π)m2(2m)] =75.702(103)N

Therefore,

Fbc=(Fbc)²h2+(Fbc)²v2=√[98.1(10³)N]²+[75.702(10³)N]²=123.91(10³)N=124KN

FR²   =(Fbc)²H2+[Fab+(Fbc)v]²

==[98.1(10³)N]² + [(73.6(10³)N)²+75.702(10³)N²]

=178.6(10³)N = 179 kN.

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The hammer must be moving at a speed of 12.0 m/s in order to just barely ring the bell.

When the hammer strikes the target, it transfers its kinetic energy to the metal piece, causing it to move upwards. This means that the kinetic energy of the hammer is converted into potential energy (PE) of the metal piece, given by:

PE = mgh

where m is the mass of the metal piece, g is the acceleration due to gravity, and h is the height of the bell above the metal piece. Substituting the given values, we get:

PE = (0.400 kg)(9.81 m/s²)(5.00 m) = 19.62 J

Since 25.0% of the hammer's kinetic energy is used to do this work, we can write:

0.25KE_hammer = PE

where KE_hammer is the kinetic energy of the hammer before the collision. Solving for KE_hammer, we get:

KE_hammer = 4PE = 4(19.62 J) = 78.48 J

Finally, we can use the formula for kinetic energy to find the velocity (v) of the hammer:

KE_hammer = (1/2)mv²

where m is the mass of the hammer. Rearranging and substituting the given values, we get:

v = sqrt(2KE_hammer/m) = sqrt(2(78.48 J)/(9.00 kg)) = 12.0 m/s

The hammer must be moving at a speed of 12.0 m/s in order to just barely ring the bell.

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