Answer:
0.6 or 60%.
Step-by-step explanation:
Answer:
60%
i could be wrong tho
Step-by-step explanation:
Compute f′(a) algebraically for the given value of a. f(x)=−7x+5;a=−6
The f′(a) when a = −6 is -7. This means that the slope of the tangent line of the graph of f(x) at x = -6 is -7.
To compute f′(a) algebraically for the given value of a, we use the following differentiation rule which is known as the Power Rule.
This states that:If f(x) = xn, where n is any real number, then f′(x) = nxⁿ⁻¹This is valid for any value of x.
Therefore, we can differentiate f(x) = −7x + 5 with respect to x using the power rule as follows:
f(x) = −7x + 5
⇒ f′(x) = d/dx (−7x + 5)
⇒ f′(x) = d/dx (−7x) + d/dx(5)
⇒ f′(x) = −7(d/dx(x)) + 0
⇒ f′(x) = −7⋅1 = −7
Hence, the derivative of f(x) with respect to x is -7.Now, we evaluate f′(a) when a = −6 as follows:f′(x) = −7 evaluated at x = −6⇒ f′(−6) = −7
Therefore, f′(a) when a = −6 is -7. This means that the slope of the tangent line of the graph of f(x) at x = -6 is -7.
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14 . You are stopped in a line of vehicles waiting at a stop sign. If there is no cross traffic after the vehicles ahead have passed through the intersection, you:
If there is no cross traffic after the vehicles ahead have passed through the intersection, you may proceed through the intersection after coming to a complete stop at the stop sign and yielding to any pedestrians or vehicles that have the right of way. It is important to always be aware of your surroundings and follow traffic laws to ensure safety for yourself and others on the road.
Hi, I'm happy to help with your question. You asked: If you are stopped in a line of vehicles waiting at a stop sign and there is no cross traffic after the vehicles ahead have passed through the intersection, what should you do?
In this situation, you should:
1. Remain stopped behind the stop sign and the vehicle in front of you.
2. Wait for the vehicle ahead of you to clear the intersection completely.
3. Check for any cross traffic or pedestrians, even if there appears to be none.
4. Proceed through the intersection only when it is safe and clear to do so.
Remember, it is essential to follow traffic rules and prioritize safety at all times while driving.
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One effect of chunking is to Select one: a. group items based on sound. b. facilitate the primacy and recency effects. c. encode items based on spatial properties. d. increase the amount of material that can be held in working memory.
One effect of chunking is to increase the amount of material that can be held in working memory (option d).
Chunking is a cognitive process that involves organizing and grouping information into meaningful units or "chunks." By grouping individual elements together, such as numbers, letters, or words, into larger chunks, the capacity of working memory can be effectively utilized.
This allows for the storage and processing of more information simultaneously, enhancing the overall cognitive capacity. Chunking helps overcome the limited capacity of working memory by reducing cognitive load and making information more manageable.
It facilitates the organization and retrieval of information, improving memory performance and the ability to process and retain complex information more efficiently. Thus, the primary effect of chunking is to increase the amount of material that can be held in working memory.
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solve the system of equations algebraically -5x+2y=4 2x+3y=6
Step-by-step explanation:
-5x+2y= 4 <==== Multiply entire equation by -3 to get:
15x-6y = -12
2x+3y= 6 <==== Multiply entire equation by 2 to get :
4x+6y = 12 Add the two underlined equations to eliminate 'y'
19x = 0 so x = 0
sub in x = 0 into any of the equations to find: y = 2
(0,2)
Calculate the mass of NaF in grams that must be dissolved in a
0.25M HF solution to form a 300 mL buffer solution with a pH of
3.5. (Ka for HF= 7.2X10^(-4))
Answer is 7.17g NaF. Please tell me at whic
To make a 300 mL buffer solution with a pH of 3.5, the mass of NaF required is 7.17 grams.
The buffer solution is created by mixing HF with NaF. The two ions, F- and H+, react to create HF, which is the acidic component of the buffer. The pKa is used to determine the ratio of the conjugate base to the conjugate acid in the solution. Let us calculate the mass of NaF required to make a 300 mL buffer solution with a pH of 3.5.
To calculate the mass of NaF, we need to know the number of moles of NaF needed in the solution. We can calculate this by first determining the number of moles of HF and F- in the buffer solution. Here's the step-by-step solution:
Step 1: Calculate the number of moles of HF needed: Use the Henderson-Hasselbalch equation to calculate the number of moles of HF needed to create a buffer with a pH of 3.5.pH
\(= pKa + log ([A-]/[HA])3.5\)
\(= -log(7.2*10^{-4}) + log ([F-]/[HF])[F-]/[HF]\)
= 3.16M/0.1M = 31.6mol/L.
Since we know that the volume of the buffer is 0.3L, we can use this value to calculate the number of moles of HF needed. n(HF) = C x Vn(HF) = 0.1M x 0.3Ln(HF) = 0.03 moles
Step 2: Calculate the number of moles of F- needed: The ratio of the concentration of F- to the concentration of HF is 31.6, so the concentration of F- can be calculated as follows: 31.6 x 0.1M = 3.16M. The number of moles of F- needed can be calculated using the following formula: n(F-) = C x Vn(F-) = 3.16M x 0.3Ln(F-) = 0.95 moles
Step 3: Calculate the mass of NaF needed: Now that we know the number of moles of F- needed, we can calculate the mass of NaF required using the following formula:
mass = moles x molar mass
mass = 0.95 moles x (23.0 g/mol + 19.0 g/mol)
mass = 7.17 g
So, the mass of NaF required to make a 300 mL buffer solution with a pH of 3.5 is 7.17 grams. Therefore, the correct answer is 7.17g NaF.
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The correct question would be as
Calculate the mass of NaF in grams that must be dissolved in a 0.25M HF solution to form a 300 mL buffer solution with a pH of 3.5. (Ka for HF= 7.2X10^(-4))
Ada and Evie then use an equal number of tickets each. After using up these tickets, they now
have 24 tickets in total. Let x be the number of tickets they each used, use algebra to find the
value of x.
A 2-column table with 4 rows. Column 1 is labeled Time (minutes), x with entries 4, 5, 6, 7. Column 2 is labeled Bags Remaining, y with entries 36, 32, 28, 24.
Razi is filling bags with party favors for his birthday party. The table to the right shows the number of bags he still needs to fill after 4, 5, 6, and 7 minutes. If he is working at a constant rate, what was the initial number of party favor bags Razi had to fill?
36
48
52
56
Therefore, the initial number of party favor bags Razi had to fill is 20.
To determine the initial number of party favor bags Razi had to fill, we need to analyze the relationship between the time and the number of bags remaining.
Looking at the table, we can observe that the number of bags remaining decreases by 4 for every additional minute of work. This suggests a constant rate of filling the bags.
From the given data, we can see that at the starting time (4 minutes), Razi had 36 bags remaining. This implies that for each minute of work, 4 bags are filled.
To calculate the initial number of bags, we can subtract the number of bags filled in 4 minutes (4 x 4 = 16) from the number of bags remaining initially (36).
36 - 16 = 20
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What is the distance in the standard (x,y) coordinate plane between the points (1,0) and (0,5)? Responses 4 4 6 6 16 16 36 36 26−−√
The distance in the standard (x, y) coordinate plane between the given points (1, 0) and ( 0, 5) is equal to √26 units.
As given in the question,
In the coordinate plane :
The distance in the standard (x, y) coordinate plane is:
Distance between the given points (x₁ , y₁) = (1, 0) and (x₂ , y₂) = (0,5) is given by :
Standard distance formula :
d = √ ( x₂ - x₁)² + (y₂ - y₁)²
= √ ( 0 -1)² + (5-0)²
= √1 + 25
= √26 units
Therefore, The distance in the standard (x, y) coordinate plane between the given points (1, 0) and ( 0, 5) is equal to √26 units.
The complete question is :
What is the distance in the standard (x, y) coordinate plane between the points (1,0) and (0,5)?
a. 4 b. 6 c. 16 d. 36 e. √26
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this is one of the two questions I have please help
A room is 90 inches wide, and 145 inches long. What is the perimeter of the room?
Answer:
I think 50
Step-by-step explanation:
Answer:
470 inches
Step-by-step explanation:
p = 2l + 2w
p = 2*145 + 2*90
p = 290 + 180
p = 470
What ordered pair is closest to a local minimum of the function, f(x)?
(–1, –3)
(0, –2)
(1, 4)
(2, 1)
Write an equation of the line that passes through (-5,0) and is parallel to the line y=-2/3x-1
The equation of the line that passes through (-5,0) and is parallel to the line y = -2/3x - 1 is y = - 2 / 3 x - 10 / 3
How to find the equation of a line?The equation of a line can be represented in different form such as point slope form, slope intercept form, standard form and general form.
The equation of a line in slope intercept form is as follow:
y = mx + b
where
m = slopeb = y-interceptTherefore, the equation of the line passes through (-5,0) and is parallel to the line y = -2/3x - 1.
Parallel line has the same slope.
Therefore, the slope of the line is - 2 / 3.
Hence, let's find the y-intercept using (-5, 0)
0 = - 2 / 3(-5) + b
b = - 10 / 3
Therefore, the equation is y = - 2 / 3 x - 10 / 3
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Draw the image of the indicated translation of the given pre image please
The new points after the translation are (0, -4), (0, 0), (5, -5) and (5, 0) and the image is added as attachment
Calculating the image of the figureTranslation is the movement of a point either up, left, right or down on the coordinate plane.
If a point A(x, y) is translated a units left and b units down, the new point is A'(x - a, y - b)
From the question, the vertices of the rectangle are (2, 3), (2, 7), (7, 2) and (7, 7).
The translation T<-2, -7>; is a translation of 2 units left and 7 units down.
This means that
The new points are (0, -4), (0, 0), (5, -5) and (5, 0).
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Vanna is saving for a trip. The hotel room will be $298.17 for 3 nights, and there will be additional fees. What is her daily cost?
Answer:
The daily cost is $99.39.
Step-by-step explanation:
In order to find the answer with the information provided, you have to divide the price given for 3 nights by the number of nights to determine the price per night which would be her daily cost:
$298.17/3=$99.39
According to this, the answer is that the daily cost is $99.39.
Give an example (there are many possibilities) of a 3 × 3 matrix for which the kernel is the set of all vectors\underset{x}{\rightarrow}∈ R3 satisfying 3x1 + 2x2 + x3 = 0.Please include rationale.
We can easily see this by noting that if we multiply this matrix with \underset{x}{\rightarrow}= (x1,x2,x3), we get
|x1 + 2x2 + 3x3|
|4x1 + 5x2 + 6x3|
|7x1 + 8x2 + 9x3|
which to the equation 3x1 + 2x2 + x3 = 0.
A 3x3 matrix for which the kernel is the set of all vectors \underset{x}{\rightarrow}∈ R3 satisfying 3x1 + 2x2 + x3 = 0 is
|1 2 3|
|4 5 6|
|7 8 9|
This matrix has a kernel consisting of all vectors \underset{x}{\rightarrow}= (x1,x2,x3) that satisfy the equation 3x1 + 2x2 + x3 = 0.
We can easily see this by noting that if we multiply this matrix with \underset{x}{\rightarrow}= (x1,x2,x3), we get
|x1 + 2x2 + 3x3|
|4x1 + 5x2 + 6x3|
|7x1 + 8x2 + 9x3|
which to the equation 3x1 + 2x2 + x3 = 0.
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Find the measure of
=======================================================
Explanation:
The angles SPT and TPU marked in red are congruent. They are congruent because of the similar arc markings.
Those angles add to the other angles to form a full 360 degree circle.
Let x be the measure of angle SPT and angle TPU.
86 + 154 + 60 + x + x = 360
300 + 2x = 360
2x = 360-300
2x = 60
x = 60/2
x = 30
Each red angle is 30 degrees.
Then,
angle SPQ = (angle SPT) + (angle TPU) + (angle UPQ)
angle SPQ = (30) + (30) + (86)
angle SPQ = 146 degrees
--------------
Another approach:
Notice that angles QPR and RPS add to 154+60 = 214 degrees, which is the piece just next to angle SPQ. Subtract from 360 to get:
360 - 214 = 146 degrees
Find the maximum of the profit function,
P = 12x + 3y
subject to the following constraints.
2x - y ≤ 6
x+y 24
2x - y ≤ 6
-x + 2y ≤ 3
x ≥ 0
x+y24
-x + 2y <3
y 20
Round your answer to the nearest cent (hundredth).
The maximum value of the profit objective function from the constraints is 72
How to maximize the profit objective function from the constraintsFrom the question, we have the following parameters that can be used in our computation:
Objective function: P = 12x + 3y
Subject to:
2x - y ≤ 6
x + y ≥ 4
-x + 2y ≤ 3
x ≥ 0 and y ≥ 0
Next, we plot the graph of the constraints
This is also given
From the graph, we have the following coordinates
(1.67, 2.33), (5, 4), (3.33, 0.67)
So, we have
P = 12(1.67) + 3(3.33) = 30.03
P = 12(5) + 3(4) = 72
P = 12(3.33) + 3(0.67) = 41.97
The highest value is 72
Hence, the maximum value of the profit objective function from the constraints is 72
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The center of a clock is at (0,0) in a coordinate system, and the minute hand is 10 inches long. Find the approximate coordinates of the tip of the minute hand at: 12:05 p.M.
Answer:
(5, 8.66)
Step-by-step explanation:
Let x represent the x coordinate of the clock tip and y represent the y coordinate of the clock tip.
At 12:05 pm, the clock tip forms an angle of 60° with the x axis. Therefore:
θ = 60°
\(tan\theta=\frac{y}{x} \\\\tan60=\frac{y}{x} \\\\y=1.732x\\\\y-1.732x=0\ \ \ (1)\)
Since the minute hand is 10 inches long, hence:
\(\sqrt{x^2+y^2}=10\\\\x^2+y^2=100\\\\substituting\ y=1.732x, gives\\\\x^2+(1.732x) ^2=100\\\\x^2+3x^2=100\\\\4x^2=100\\\\x^2=25\\\\x=5\)
To find y, substitute x = 5:
y = 1.732(5) = 8.66
This means that the coordinate of the tip of the minute hand at: 12:05 p.M. is (5, 8.66)
In your answers, label all intercepts, kinks, coordinates, slopes, and axes. Revealed Preference 1. In a 3-good world, let A stand for the bundle (7,9,2), B stand for the bundle (8,5,5), and C stand for the bundle (6,6,8). When prices are ($2,$4,$1), Betty chooses C. On a different date, prices are ($5,$3,$3) and she chooses A. On yet another different day, when prices are ($3,$1,$4), she chooses B. For each pair of bundles ( A and B,A and C,B and C) examine if one is directly revealed preferred to the other, or if one is indirectly revealed preferred to the other, or neither is directly/indirectly revealed preferred to the other.
To determine the revealed preference between bundles A, B, and C, we need to compare the choices made by Betty under different price conditions. 1. When prices are ($2, $4, $1), Betty chooses bundle C over bundle A. This implies that C is directly revealed preferred to A at these prices.
2. When prices are ($5, $3, $3), Betty chooses bundle A over bundle B. This implies that A is directly revealed preferred to B at these prices.
3. When prices are ($3, $1, $4), Betty chooses bundle B over bundle C. This implies that B is directly revealed preferred to C at these prices. Based on these comparisons, we can conclude the following: - Bundle C is directly revealed preferred to bundle A. - Bundle A is directly revealed preferred to bundle B. - Bundle B is directly revealed preferred to bundle C. There are no cases of indirect revealed preference, where one bundle is preferred to another through a series of choices. Therefore, each pair of bundles has a clear ordering of direct revealed preference. Bundle C is directly preferred to A, A is directly preferred to B, and B is directly preferred to C.
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as the spacing between joists increases, the maximum span for any board size: A. increases only. B. decreases only. C. increases and then decreases. D. decreases and than increases
As the spacing between joists increases, the maximum span for any board size will B. decrease only. This is because the wider the spacing between joists, the more weight and pressure will be placed on the boards that are spanning the gap between them.
This means that the boards will need to be stronger in order to support the weight without bending or breaking.
If the boards are not strong enough, they may sag or bow under the weight, which can create safety hazards or damage to the structure. Therefore, it is important to use the appropriate board size and spacing between joists for any given application in order to ensure structural integrity and safety.
In summary, increasing the spacing between joists will result in a decrease in the maximum span for any board size, as the boards will need to be stronger in order to support the weight and pressure. It is important to choose the right board size and joist spacing to maintain the structural integrity and safety of the building or structure.
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PLEASE ITS DUE SOON!
Write a situation about today’s sales for the following system of equations and then
determine how much of each menu item you sold: e + f = 36 and e = 3f.
Answer:
bro its ur math caps do it urself
Step-by-step explanation:
Answer:
the answer is a=12 and b=13
Step-by-step explanation:
Im not giving u the explanation u should have listened in ms Aya's class.
Find the distance between the two points rounding to the nearest tenth (if necessary).
(0,−1) and (8,7)
Answer: 11.31
Step-by-step explanation:
When comparing three or more populations means within a set of quantitative data that is categorized according to one factor/treatment, a one-way ANOVA is appropriate.a. It is also appropriate in this situation, however, to compare two means at a time using multiple independent two sample t-tests. b. It is appropriate to compare two means at a time with independent two sample t-tests but it might be time-consuming.c. It is not appropriate to compare two means at a time in the way described. This would inflate the overall Type I Error and is a 'Multiple Testing' problem. The one-way ANOVA controls for the Type I Error and should be used instead.
According one-way ANOVA, the test is false.
We learn about one-way ANOVA
"One-Way ANOVA, also known as "analysis of variance," examines the refers to two or more independent groups to see if there is statistical support for the notion that the related population means are statistically substantially different."
According to the given information, it is inappropriate to compare two means at a time using multiple independent two sample t-tests. It will create multiple testing problem and error.
So using one way ANOVA test when comparing three or more populations refers to within a set of quantitative data that is categorized according to one factor/treatment and compare two means at a time using multiple independent two sample t-tests is false.
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Steve and his friends measured a snow pile; it was 7 feet tall. The next day, the
snow pile was only 6.5 feet tall. What was the percent of decrease in the snow
pile? Round your answer to the nearest tenth
The percentage decrease is 7.14%
First measurement = 7 feet
Second measurement = 6.5 feet
Difference in measurement = 7 feet - 6.5 feet = 0.5 feet
Percentage decrease = Difference in measurement/ First measurement × 100
= (0.5/7.0) × 100
= 7.14%
The percentage decrease is 7.14%
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Solve the following boundary value problem.
y′′ − 6y′ + 9y = 0, y(0) = 1, y(1) = 3
The solution to the boundary value problem y′′ − 6y′ + 9y = 0, with y(0) = 1 and y(1) = 3, is y(x) = \(e^{(3x)}\). However, this solution does not satisfy the second boundary condition, so there is no solution to the problem.
Boundary value problems involve finding the solution to a differential equation that satisfies given conditions at multiple points. In this problem, we need to solve the boundary value problem for the differential equation y′′ − 6y′ + 9y = 0, with the conditions y(0) = 1 and y(1) = 3.
To solve this problem, we can assume that the solution to the differential equation is in the form \(y(x) = e^{(mx)}\), where m is a constant to be determined. Taking the derivatives, we find that
\(y′(x) = me^{(mx)}\) and
y′′(x) =\(m^2e^{(mx)}\)
Substituting these derivatives into the differential equation, we get
\(m^2e^{(mx)} - 6me^{(mx)} + 9e^{(mx)} = 0\)
Factoring out \(e^{(mx)}\), we have
\((m^2-6m + 9)e^{(mx)} = 0\).
For the equation to hold true for all x, the coefficient of \(e^{(mx)}\) must be zero. Therefore, we solve
\(m^2-6m + 9 = 0\)
for m. Factoring the quadratic, we get
\((m-3)^2\) = 0,
so m = 3.
Thus, the answer is y(x) = \(e^{(3x)}\).
To find the specific solution that satisfies the boundary conditions, we substitute the values of x into the equation. F
or y(0) = 1, we have
y(0) = \(e^{(3*0)}\)
= 1,
which is satisfied. For y(1) = 3, we have
y(1) = \(e^{(3*1)}\)
= \(e^3\)
≈ 20.0855,
which is not equal to 3.
Therefore, there is no solution to the given boundary value problem. This implies that the conditions y(0) = 1 and y(1) = 3 cannot be satisfied simultaneously for the given differential equation.
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A long year-end status report for work is 125 pages long. You need to print 18 copies for a meeting next week. How much is the paper going to cost for those reports? Paper is sold in reams (500 pages) for $3.66 each.
Answer:
$16.47
Step-by-step explanation:
125×18=2250
these are the pages printed
2250÷500=4.5
these are the reams of paper needed
$3.66 ×4.5=$16.47
this is the money needed
How to find a quadratic equation with y-intercept and vertex? Explain with examples.
To find a quadratic equation with the y-intercept and vertex, follow these steps: identify the coordinates of the y-intercept and vertex, substitute them into the general form of the quadratic equation, solve for the coefficients, and substitute the coefficients back into the equation. For example, if the y-intercept is (0, 3) and the vertex is (-2, 1), the quadratic equation would be y = x^2 + x + 3.
To find a quadratic equation with the y-intercept and vertex, we can follow these steps:
Step 1: Identify the coordinates of the y-intercept. The y-intercept has the form (0, c), where c is the y-coordinate.Step 2: Identify the coordinates of the vertex. The vertex has the form (-b/2a, f(-b/2a)), where a, b, and c are the coefficients of the quadratic equation.Step 3: Substitute the coordinates of the y-intercept and vertex into the general form of the quadratic equation, y = ax^2 + bx + c.Step 4: Solve the resulting system of equations to find the values of a, b, and c.Step 5: Substitute the values of a, b, and c back into the general form of the quadratic equation to obtain the final equation.For example, let's say the y-intercept is (0, 3) and the vertex is (-2, 1). We can substitute these coordinates into the general form of the quadratic equation:
3 = a(0)^2 + b(0) + c
1 = a(-2)^2 + b(-2) + c
Simplifying these equations, we get:
c = 3
4a - 2b + c = 1
By substituting c = 3 into the second equation, we can solve for a and b:
4a - 2b + 3 = 1
4a - 2b = -2
2a - b = -1
By solving this system of equations, we find a = 1 and b = 1. Substituting these values back into the general form of the quadratic equation, we obtain the final equation:
y = x^2 + x + 3
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To find a quadratic equation with a given y-intercept and vertex, you need the coordinates of the vertex and one additional point on the curve.
Start with the standard form of a quadratic equation: y = ax^2 + bx + c, where a, b, and c are constants.Use the vertex form of a quadratic equation: y = a(x - h)^2 + k, where (h, k) represents the coordinates of the vertex.Substitute the vertex coordinates (h, k) into the equation to obtain the equation in vertex form.Use the y-intercept to find another point on the curve. The y-intercept has the form (0, c), where c is the value of y when x is zero.Substitute the coordinates of the additional point into the equation to obtain a system of two equations. Solve the system to find the values of a, b, and c.Substitute the determined values of a, b, and c into the standard form of the quadratic equation to obtain the final equation.Example:
Suppose we want to find a quadratic equation with a y-intercept of (0, 4) and a vertex at (2, -1).
Using the vertex form, we have y = a(x - 2)^2 - 1.Substituting the y-intercept coordinates, we get 4 = a(0 - 2)^2 - 1, which simplifies to 4 = 4a - 1.Solving the equation above, we find a = 1.Substituting the values of a and the vertex coordinates into the vertex form equation, we have y = 1(x - 2)^2 - 1.Expanding the equation and simplifying, we get y = x^2 - 4x + 3.The final quadratic equation with the given y-intercept and vertex is y = x^2 - 4x + 3.To find a quadratic equation with a given y-intercept and vertex, you can use the vertex form of a quadratic equation and substitute the coordinates to obtain the equation. Then, use the y-intercept to find an additional point on the curve and solve a system of equations to determine the coefficients. Finally, substitute the coefficients into the standard form of the quadratic equation to get the final equation.
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triple the difference of five and a number
Anyone have any idea what the answer could be?
Answer:
y = -1/4x -1
Step-by-step explanation:
Mathematically, we have the slope intercept form as;
y = mx + b
where m is the slope and b is the y-intercept
from the question;
m is -1/4
So we have :
y = -1/4x + b
To get the value of b, we substitute the coordinates given and solve for b
Firstly, multiply through by 4
That will
give ;
4y = -x + 4b
4(-4) = -12 + 4b
-16 = -12 + 4b
-16 + 12 = 4b
4b = -4
b = -4/4
b = -1
So the equation in the slope intercept form is;
y = -1/4x -1
A political researcher takes a survey of 300 randomly selected registered voters in atlanta, and each person was asked who they plan on voting for in the 2020 mayoral election. 101 said they plan on voting for candidate a, 184 said they plan on voting for candidate b, and 15 were unsure or plan to vote for another candidate. In question 8, the political researcher estimated p, the population proportion of all registered voters in atlanta who plan to vote for candidate a, with a 95% confidence interval. The researcher now wants to estimate p with a margin of error of 3%. What is the minimum sample size needed?.
The minimum sample size needed is 93.
Given:
A political researcher takes a survey of 300 randomly selected registered voters in atlanta, and each person was asked who they plan on voting for in the 2020 mayoral election. 101 said they plan on voting for candidate a, 184 said they plan on voting for candidate b, and 15 were unsure or plan to vote for another candidate. In question 8, the political researcher estimated p, the population proportion of all registered voters in atlanta who plan to vote for candidate a, with a 95% confidence interval. The researcher now wants to estimate p with a margin of error of 3%.
here
n = 101
p = 0.5
e = 5%=0.05
z score at 95% = 1.96
\(n'=\frac{n}{1+\frac{z^2*p(1-p)}{e^2} }\)
On submitting and solving using calculator
n = 93
Learn more about the sample size here:
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