An invasive species is a species that disrupts the ecosystem into which it is introduced by displacing species.

GIVEN

• Mass of Al2O3 =, 408g

• Molecular mass Al2O3 =,101,96 g/mol

• Molecular Mass Oxygen =,15,999 g/mol

We will consider the following balanced chemical equation that takes place :

3 moles Oxygen reacts and produce 2 moles Al2O3

So, x moles Oxygen willreact and produce 4 moles Al2O3

Therefore,

X moles O2 = (4Moles Al2O3 *3 moles Oxygen ) / 2 moles Oxygen

= 6 moles of O2

(iii) Determine Mass of Oxygen :

Therefore, 95.99 grams of O2 are needed to produce 408g of Al2O3

Explanation:

For dissolving dry mortar on floor tiles, you can use concrete and mortar dissolver. You can find this product at your local hardware store or online12.

For removing KMnO stains, you can use vinegar. Mix vinegar with water and spray or pour it on the tile surface. Let the vinegar water set in for a few minutes, then sponge the entire area to get it as clean as possible. Next, use a razor blade or scraper to peel up the mortar. Be careful not to gouge or scratch the tiles3.

KMnO is potassium permanganate. it makes water drinkable if it's polluted

For drying acid anhydrides, you can use calcium chloride. Calcium chloride is a hygroscopic substance that absorbs moisture from the air and can be used as a desiccant.

desiccants keeps things dry so they last longer like food & clothes

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The reaction order and specific reaction rate constant can be determined by performing the kinetics experiment on irreversible polymerization A. Kinetic experiments can be used to investigate the rate and mechanism of chemical reactions. Chemical kinetics is the study of chemical reactions' speed and pathway.

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Answer:

1

Explanation:

One particle is observed in solution

Molecular substances do not dissociate into ions in solution.

A molecular substance is any substance that is formed by a covalent bond. These covalent substances do not dissociate into ions because they are not composed of ions. Only electrovalent or ionic substances are composed of ions.

CH3OH is a molecular substance. It is soluble in water because the polar O-H bond interacts with water via hydrogen bonding. However, it does not dissociate in solution hence only one particle is observed in solution.

The properties that depend on the number of particles in solution are known as colligative properties. For more about colligative properties, see:

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The amount of heat energy absorbed when 200 grams of water are heated from 20 C to 60 C is 33,440 Joules.

To find the amount of heat energy absorbed when 200 grams of water are heated from 20 C to 60 C, we can use the equation Q = mcAT.
First, we need to find the value of m, which is the mass of the water in grams. In this case, it is given as 200 grams.
Next, we need to find the value of AT, which is the change in temperature in degrees Celsius.

This can be calculated by subtracting the initial temperature from the final temperature, which gives us 60 C - 20 C = 40 C.
The specific heat capacity of water, C, is given as 4.18 Joules per gram per degree Celsius.
Now we can plug in the values into the equation:
Q = mcAT
Q = (200 g) x (4.18 J/g°C) x (40°C)
Q = 33,440 J
Therefore, the amount of heat energy absorbed when 200 grams of water are heated from 20 C to 60 C is 33,440 Joules.

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Answer:

The periodic law states “When elements are arranged in order of increasing atomic number, there is a periodic repetition of their chemical and physical properties

As per the given data, 1.6 grams of oxygen reacted in this experiment.

To calculate the amount of oxygen that reacted in the experiment, we need to determine the difference in the mass of X oxide (X,O) formed and the mass of X initially used.

Given:

Mass of X = 4.6 g

Mass of X oxide (X,O) = 6.2 g

To find the amount of oxygen that reacted:

Mass of oxygen = Mass of X oxide - Mass of X

= 6.2 g - 4.6 g

= 1.6 g

Therefore, 1.6 grams of oxygen reacted in this experiment.

Calculate the mass of 1 mole of X:

Given that the mass of X is 4.6 g, we can calculate the molar mass of X by dividing the mass by the number of moles:

Molar mass of X = Mass of X / Number of moles of X

Molar mass of X = 4.6 g / 0.1 mol

Molar mass of X = 46 g/mol

Therefore, the mass of 1 mole of X is 46 grams.

Thus, the answer is 46 grams.

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Answer:

Attached picture.

Explanation:

(1) Ksp equals the product of [Co 2+][CO3 2-]. CoCO3 is excluded from the equilibrium expression because it is a pure solid. The mole ratio of Co 2+ and CO3 2- is 1:1 so their molar solubilities are the same.

(2) There is an initial concentration of 0.10 M Co 2+ so write that in the "I" row for Co 2+ on the ICE table. When you find the zeros of the quadratic when solving for "s", take the positive value rather than the negative value because concentration cannot be negative.

(3) Extra products will cause the equilibrium to consume products and form reactants. So the reverse reaction will occur faster than the forward reaction. More products mean an increased Q value compared to K, since the numerator of \(K = \frac{[products]}{[reactants]}\) increases.

Answer:

When a copper is drawn into wire the only change that occurs is change in its shape and size no change will take place into its composition that is the wires are still possessing the properties of copper metal. Thus, a physical change takes place when copper is drawn into wire.

Answer:

CH3F is a polar molecule due to the presence of a very electronegative fluorine (3.98) as one of the outer atoms which pulls electrons towards it inducing a partial negative charge

Explanation:

The sample with the largest number of oxygen atoms will be calcium perchlorate.

Since we are not looking at the number of moles, the mass of the compounds has no bearing on the number of atoms of oxygen.

Therefore, the compound with the largest number of oxygen atoms is calcium perchlorate.

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Answer:

Using atomic spectra selection rules for electronic excitations, determine the electron configurations and their associated term symbols for the two lowest-lying electronic excited states for a hydrogen atom. (Starting from the ground electronic state, determine what the two lowest energy electronic excitations are possible.) Indicate which will have the lower energy.

Explanation:

Using atomic spectra selection rules for electronic excitations, determine the electron configurations and their associated term symbols for the two lowest-lying electronic excited states for a hydrogen atom. (Starting from the ground electronic state, determine what the two lowest energy electronic excitations are possible.) Indicate which will have the lower energy.

Answer: -100 kJ

Explanation:

Heat of reaction or enthalpy of the reaction is the energy released or absorbed during the course of the reaction.

Heat of reaction is represented by the symbol \(\Delta H\).

\(\Delta H=H_{products}-H_{reactants}\)

\(\Delta H\) = enthalpy of reaction = ?

\(H_{products}\) = enthalpy of products = 0 kJ

\(H_{reactants}\) = enthalpy of reactants = 100 kJ

\(\Delta H=0kJ-100kJ\)

\(\Delta H=-100kJ\)

Thus the ΔH for the reaction is -100kJ

The limiting reactant is iron ore, the theoretical yield of iron metal is 701.344 kg, and the theoretical yield of carbon dioxide is 413.292 kg.

From the equation of the reaction:

\(2 Fe_2O_3(s) + 3 C(s) --- > 4 Fe(s) + 3 CO_2(g)\)

The mole ratio of iron ore to carbon is 2:3.

Mole of 1000 kg of iron ore = 1000000/159.69

                                          = 6,262 moles

Mole of 120 kg carbon = 120000/12

                                 = 10,000 moles

Thus, it appears that the carbon is in excess while the iron ore is limited in availability.

The mole ratio of the iron ore and the iron produced is 1:2. Thus, the equivalent number of moles of iron produced will be:

              6,262 x 2 = 12,524 moles

Mass of 12,524 moles of iron = 12,524 x 56

                                                = 701,344 g or 701.344 kg

Thus, the theoretical yield of iron is 701.344 kg.

The mole ratio of the iron ore and the carbon dioxide produced is 2:3. The equivalent mole of carbon dioxide produced will be:

         6,262 x 3/2 = 9,393 moles

Mass of 9,393 moles carbon dioxide = 9,393 x 44

                                                         = 413,292 or 413.292 kg

The theoretical yield of carbon dioxide is, therefore, 413.292 kg.

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Answer:

To resolve this, we need to place the coefficient “2” in front of the sodium in the reactant, to give the equation shown below. 2 Na (s) + Cl 2 (g) → 2 NaCl (s) In this equation, there are two sodiums in the reactants, two sodiums in the products, two chlorines in the reactants and two chlorines in the products; the equation is now balanced.

Explanation:

Moles of Li₂S will be required to completely react with 45.0 mL of 0.100 M Fe(NO₃)₃ is 0.00675 moles.

The reaction is as follows :

3 Li₂S(aq) + 2 Fe(NO₃)₃(aq) → Fe₂S₃(s)  + 6 LiNO₃(aq)

Molarity = mol / V in L

Molarity = 0.100 M

Volume = 45.0 mL = 0.045 L

now , putting the values in formula :

M = mol / V

mol = M × V

moles = 0.100 × 0.045

moles = 0.0045 moles of Fe(NO₃)₃

from the equation it is clear that :

2 moles of Fe(NO₃)₃ react with 3 moles of  Li₂S

therefore, 0.0045 moles of Fe(NO₃)₃ react with = (3 × 0.0045 ) / 2

                                                                               = 0.00675 moles of Li₂S

Thus, Moles of Li₂S will be required to completely react with 45.0 mL of 0.100 M Fe(NO₃)₃ is 0.00675 moles.

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The sample containing 1.00 mg of iodine-129 would have an activity of 1900 disintegrations per second.

The first step in solving this problem is to determine the number of iodine-129 atoms present in 1.00 mg of the sample. We can use the Avogadro's number (6.022 × 10^23 atoms per mole) and the molar mass of iodine-129 (129 g/mol) to calculate this:

Number of iodine-129 atoms = (1.00 mg / 129 g/mol) x (6.022 × 10^23 atoms/mol)

= 4.66 × 10^16 atoms

Next, we can use the half-life of iodine-129 (1.7 × 10^7 years) to calculate the decay constant (λ) using the following equation:

λ = ln(2) / half-life

λ = ln(2) / 1.7 × 10^7 years

= 4.09 × 10^-8 per year

Now, we can use the decay constant and the number of iodine-129 atoms to calculate the activity (A) in disintegrations per second (Bq):

A = λ x N

A = (4.09 × 10^-8 per year) x (4.66 × 10^16 atoms)

= 1900 Bq

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The incorrect part of the chemical equation is the coefficient for the oxygen gas reactant.

        2 C2H6 + 7 O2 → 4 CO2 + 6 H2O

        2 C2H10 (should be C2H6) + 10 O2 → 8 CO2 + 10 H2O

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The amount of copper in moles in the 27.5 g pure copper sheet is approximately 0.433 moles.

To calculate the amount of copper in moles in a pure copper sheet, we need to use the molar mass of copper and the given mass of the sheet.

The molar mass of copper (Cu) is approximately 63.55 g/mol. This value represents the mass of one mole of copper atoms.

Given that the mass of the pure copper sheet is 27.5 g, we can calculate the number of moles using the following formula:

moles = mass / molar mass

Substituting the values:

moles = 27.5 g / 63.55 g/mol

moles ≈ 0.433 mol

Therefore, the amount of copper in moles in the 27.5 g pure copper sheet is approximately 0.433 moles.

To arrive at this result, we divided the given mass of the sheet (27.5 g) by the molar mass of copper (63.55 g/mol). This calculation allows us to convert the mass of the sheet into the corresponding number of moles of copper.

The result tells us that the 27.5 g pure copper sheet contains approximately 0.433 moles of copper atoms. This conversion to moles is useful in various chemical calculations and allows for easier comparison and analysis of quantities on a molecular scale.

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Explanation:

since diferentes colours of light través at diferentes speeds, the refractiva index is diferentes for each color. The result? that whenthe White light países thought the prism it cover into a red light

Explanation:

carbohydrate,fat,protein, vitamin, mineral, water

Answer:

There are six major nutrients: Carbohydrates (CHO), Lipids (fats), Proteins, Vitamins, Minerals, Water.

According to the 2 trials, we observe that the concentration of HCl is higher in 2. We can assume that we have more particles in the solution so, we will have more collisions, and then the time will be lower.

Concentration HCl 1 < Concentration HCl 2

I think the answer is less than 48 seconds because there are more effective particle collisions per second.

Answer:

Earth covers a greater area in position A than in position B in the same amount of time.

Explanation:

Based on the diagram that shows different positions of Earth and Mars around the sun, it seems that this statement is correct:

Earth covers a greater area in position A than in position B in the same amount of time. (Covers as I understood it means "overshadowing" Mars)

At equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

1: Write the balanced chemical equation:

\(C_O\)(g) + \(Cl_2\)(g) ⟶ \(C_OCl_2\)(g)

2: Set up an ICE table to track the changes in moles of the substances involved in the reaction.

Initial:

\(C_O\)(g) = 0.3500 mol

\(Cl_2\)(g) = 0.05500 mol

\(C_OCl_2\)(g) = 0 mol

Change:

\(C_O\)(g) = -x

\(Cl_2\)(g) = -x

\(C_OCl_2\)(g) = +x

Equilibrium:

\(C_O\)(g) = 0.3500 - x mol

\(Cl_2\)(g) = 0.05500 - x mol

\(C_OCl_2\)(g) = x mol

3: Write the expression for the equilibrium constant (Kc) using the concentrations of the species involved:

Kc = [\(C_OCl_2\)(g)] / [\(C_O\)(g)] * [\(Cl_2\)(g)]

4: Substitute the given equilibrium constant (Kc) value into the expression:

1.2 x \(10^3\) = x / (0.3500 - x) * (0.05500 - x)

5: Solve the equation for x. Rearrange the equation to obtain a quadratic equation:

1.2 x \(10^3\) * (0.3500 - x) * (0.05500 - x) = x

6: Simplify and solve the quadratic equation. This can be done by multiplying out the terms, rearranging the equation to standard quadratic form, and then using the quadratic formula.

7: After solving the quadratic equation, you will find two possible values for x. However, since the number of moles cannot be negative, we discard the negative solution.

8: The positive value of x represents the number of moles of \(Cl_2\)(g) at equilibrium. Substitute the value of x into the expression for \(Cl_2\)(g):

\(Cl_2\)(g) = 0.05500 - x

9: Calculate the value of \(Cl_2\)(g) at equilibrium:

\(Cl_2\)(g) = 0.05500 - x

\(Cl_2\)(g) = 0.05500 - (positive value of x)

10: Calculate the final value of \(Cl_2\) (g) at equilibrium to get the answer.

Therefore, at equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

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Covalent bonds between purines and pyrimidine bases  is NOT a type of molecular interaction that determines the tertiary structure of a protein. The correct answer is A.

A polypeptide's overall three-dimensional structure is referred to as its tertiary structure. The interactions between the R groups of the amino acids that make up the protein are principally responsible for the tertiary structure.

The entire spectrum of non-covalent bonds, including hydrogen bonds, ionic bonds, dipole-dipole interactions, and London dispersion forces, all contribute to tertiary structure.

For instance, R groups with opposite charges can form an ionic bond, while those with like charges repel one another. Similar to other dipole-dipole interactions, polar R groups can create hydrogen bonds

Hydrophobic interactions are crucial to tertiary structure because they allow hydrophilic amino acids to connect with nearby water molecules on the outside of the protein while forming clusters of nonpolar, hydrophobic R groups on the inside of the protein.

The disulfide link is a unique sort of covalent bond that can contribute to tertiary structure. Disulfide bonds, covalent connections between the side chains of cysteines that contain sulfur, are substantially more powerful than the other kinds of bonds that make up tertiary structure.

They serve as molecular "safety pins," firmly connecting various polypeptide components to one another.

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The molar mass is 3230.8 g/mol

First, we need to know that the formula for the general gas law  is represented as;

PV = nRT

such that the parameters are;

Substitute the values

1 × 2.33 = n × 8.314 × 433.15

Multiply the values, we get;

n = 2.33/ 8.314 × 433.15

Divide the values

n = 6.5 × 10⁻⁴ moles

But, number of moles = mass/molar mass

Molar mass = 2.10/ 6.5 × 10⁻⁴

Molar mass = 3230.8 g/mol

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To name Type 2 ionic compounds such as AuCl₃, you need to use the Stock system or Roman numeral system to indicate the oxidation state of the cation. Some steps are; Identify the cation, Determine the charge, Write the name, and combine two names.

Here are the steps to name AuCl₃; Identify the cation and anion. In this case, the cation is Au³⁺ and the anion is Cl⁻.

Determine the charge on the cation by using the anion's charge and balancing the charges to zero. Since Cl⁻ has a charge of -1 and there are three Cl⁻ ions in the compound, the total negative charge is -3. Therefore, the Au³⁺ ion has a charge of +3.

Write the name of the cation first, followed by the name of the anion with an -ide ending. Since the cation is Au³⁺, we use the name "gold(III)" to indicate the oxidation state of +3. The anion is Cl⁻, so we add the -ide ending to get "chloride".

Combine the two names to get the compound's name: "gold(III) chloride".

Therefore, the name of the Type 2 ionic compound AuCl₃ is "gold(III) chloride".

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Answer:

When a system is at equilibrium, the process is not spontaneous at either direction.

Explanation:

The process is not spontaneous at either direction , when a system is at equilibrium  ΔG = 0, because -

We know that a negative ΔG indicates a forward-moving phase that is random.

We already know that a positive ΔG implies a non-spontaneous phase going forward.

Thus , here ΔG = 0, so the process is not spontaneous in either direction.

Answer:

The inside of the Earth is too hot to hold a solid magnet therefore, there is liquid metals within the mantle and deeper. These metals flow around causing volcanic eruptions, earthquakes, and Earth's magnetic field.

Explanation:

The density of a substance (in g/dL) of a sample with a mass of 8.3 x 10-¹ dag and a volume of 4.10 mL is 202.44g/dL.

The density of a substance is the measure of the mass of matter contained by a unit volume.

The density of a substance can be calculated by dividing the mass of the substance by its volume.

According to this question, a substance with a mass of 8.3 x 10-¹ dag has a volume of 4.10 mL. The density can be calculated as follows:

Density = 8.3g ÷ 0.041dL

Density = 202.44g/dL

Therefore, the density of a substance (in g/dL) of a sample with a mass of 8.3 x 10-¹ dag and a volume of 4.10 mL is 202.44g/dL.

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