An insulating sphere of radius 0.30 m has positive charge distributed uniformly inside it. A student measures the electric field at a point 0.50 m from the center of the sphere and finds it to have a magnitude of 15000 N/C. at that point. What is the maximum magnitude of the electric field that this sphere produces?
O 36,000 N/C
O 48,000 N/C
O 15000 N/C
O 25,000 N/C
O 42,000 N/C
O 30,000 N/C
​

Answer:

8.51 m/s

Explanation:

Velocity = Displacement/Time

Velocity = 400 m ÷ 47 s

Velocity = 8.51 m/s

Answer:

24 m/s

Explanation:

V=Vi+at

given initial velocity is 0, acceleration is 2 and time is 12 sec

find final velocity by plugging in the variables into the equation above.

V=0+2x12=24m/s

Answer: 45 minutes

Explanation:

hope this helps!

The total distance is 105 kilometers and the total displacement is 15 kilometers east. Option C

To calculate the total distance, we add the distances traveled in each leg of the journey: 60 kilometers (from A to B) + 45 kilometers (from B back to A) = 105 kilometers.

However, displacement refers to the change in position of an object in a straight line from its starting point to its ending point. In this case, since the boat starts and ends at the same point (A), the total displacement is zero.

Hence The total distance is 105 kilometers and the total displacement is 15 kilometers east.

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If we rank these magnets from the strongest to the weakest magnetic field the correct order is 4, 3, 2, 1.

The magnetic field and radius are related in the context of a charged particle moving in a circular path under the influence of a magnetic field. When a charged particle moves in a circular path under the influence of a magnetic field, the force on the particle is directed toward the center of the circle. In this force, the radius can be expressed as r = mv / Bq.

This equation shows that the radius of the circular path is directly proportional to the velocity of the particle, and inversely proportional to the magnetic field strength and the charge of the particle.

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ωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωZ?

Answer: 11.8 m/s

Explanation: Multiply the height, 1.20 m by 9.8. This is because on earth free falling objects have a speed of 9.8 m/s^2 downward.

Answer:

(a) 6.67 m/s  (b) 3.33 m/s

Explanation:

if i understood your question correctly, the jogger goes 150m east before going in the opposite direction west for 50m. (see diagram)

in avg speed, we use the total distance (150m + 50m = 200m)  and total time (30s)

v = d/t =200/30 =6.67 m/s

in avg velocity, we use the total displacement  (150m - 50m = 100m) and total time (30s)

v= d/t = 100/30 = 3.33 m/s

Answer:

The bulb with higher temperature(4000 K) will be brighter

Explanation:

From the question we are told that

     The color temperature  for first bulb is  \(T_1 = 2000K\)

        The color temperature  for second bulb is  \(T_2 = 4000K\)

Generally the emission power of black body radiation is mathematically represented as

     \(E = \sigma T^4\)

Where  \(\sigma\) is the Stefan-Boltzmann constant  with a value \(\sigma = 5.67 * 10^{-8} W m^{-2} K^{-4.}\)

Now for \(T_1 = 2000K\)

      \(E_1 = 5.67*10^{-8} * (2000)^4\)

       \(E_1 = 907.2 \ W/m^2\)

At  \(T_2 = 4000K\)

       \(E_2 = 5.67*10^{-8} * 4000\)

        \(E_2 = 14515.2 \ KW/m^2\)

Looking at the result we got we see that  the emission power  for the higher temperature bulb is higher, this means that its power to emit in the visible spectrum range would be higher  

So the bulb with higher temperature will be brighter

An electron in a Hydrogen atom goes from the n=3 energy level to the n=1 energy level by emitting light. The energy of this light is (E)= 19.38×10⁻¹⁹ J.

Energy is a physical term. If a object is affected by some forces and move a distance that means object has some energy. It can be measured in Joule.

To calculate the energy we are using the formula,

E= hc/λ

To calculate the energy we have to calculate the wavelength= λ  first, we are using the formula,

1/λ=R[(1/n₁²)-(1/n₂²)]

Here we are given,

R= the Rydberg constant.=1.097×10⁷ /m

n₁= the final energy level.=1

n₂= the initial energy level.=3

we have to calculate the wavelength. = λ m

Now we put the values in above equation we get,

1/λ=R[(1/n₁²)-(1/n₂²)]

Or, 1/λ= 1.097×10⁷×[(1/1²)-(1/3²)]

Or,  1/λ= 1.097×10⁷×[(1/1)-(1/9)]

Or,  1/λ=0.975×10⁷ /m

Now we put the value in first equation, we get

E= hc/λ

Here we are given,

h=  the Planck's constant.= 6.626×10⁻³⁴ J.s

c= The speed of light.= 3×10⁸ m/s

we have to calculate the energy. = E J

Now we put the values in above equation,

E= hc/λ

Or, E= 6.626×10⁻³⁴×3×10⁸×0.975×10⁷

Or, E= 19.38×10⁻¹⁹ J

From the calculation we can say that, The energy of this light is (E)= 19.38×10⁻¹⁹ J.

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(a) The induced current in the circuit is clockwise.

b. To find the power (P) using P = Fd/t or P = Fv (since d/t = v). Here, F = ILB (from the Lorentz force), so P = (ILB)v.

(a) The induced current in the circuit is clockwise.

This can be determined using the right-hand rule.

As the metal bar moves to the left through the magnetic field directed out of the plane, the generated force on the electrons (Lorentz force) will push them toward the top rail, creating a clockwise current.

(b) To find the rate at which the applied force is doing work on the bar, first calculate the induced EMF (ε) using Faraday's law:

induced EMF (ε) using Faraday's law:

ε = BLv

= (0.65 T) * (0.36 m) * (5.9 m/s)

= 1.389 Tm²/s

= 1.389 V (since 1 Tm²/s = 1 V)

induced current (I) using Ohm's law:

I = ε/R

= 1.389 V / 45 Ω

= 0.03086 A

force (F) from the Lorentz force law, where F = ILB:

F = ILB

= (0.03086 A) * (0.36 m) * (0.65 T)

= 0.00723 N

Finally, we find the power (P) using P = Fv:

P = Fv

= (0.00723 N) * (5.9 m/s)

= 0.04266 W

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Answer:

Explanation:

Yes, when a ball rolls down a ramp, it possesses kinetic energy. Kinetic energy is the energy associated with an object's motion. As the ball rolls down the ramp, it gains speed and its motion increases, resulting in an increase in its kinetic energy. The amount of kinetic energy the ball has depends on its mass and velocity.

Hope this answer your question

Please rate the answer and

mark me ask Brainliest it helps a lot

Answer:

Yes, when a ball rolls down a ramp, it possesses kinetic energy.

Explanation:

Kinetic energy is the energy associated with an object's motion. As the ball rolls down the ramp, it gains speed and its motion increases, resulting in an increase in its kinetic energy. The amount of kinetic energy the ball has depends on its mass and velocity.

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Answer:

9v

Explanation:

Given that the water flows at speed v in a pipe of radius r.

Let \(v_2\) is the speed of water flow where the radius of the pipe is r/3.

By using the continuity equation, the mass flow rate of water is the same at all the cross-sections of the pipe, wh have

\(\rho_1A_1_v_1 =\rho_2A_2_v_2\)

Where \(\rho_1, A_1\) and \(v_1\) are the density, area of the cross-section and speed at cross-section 1 and  \(\rho_2, A_2\) and \(v_2\) are the density, area of the cross-section and speed at cross-section 2.

As the density of the water remains constant. so \(\rho_1=\rho_2\).

\(\Rightarrow A_1_v_1 =A_2_v_2 \\\\\Rightarrow (\pi r^2)v=(\pi (r/3)^2v_2 \\\\\Rightarrow r^2v=\frac {r^2}{9}\times v_2 \\\\\Rightarrow v= \frac {v_2}{9} \\\\\Rightarrow v_2=9v.\)

Hence, the speed of the water flow where the radius is r/3 is \(9v\).

Answer: true

Explanation: idek

(a) The additional commonly available equipment you would need is stop watch.

(b) The measurement obtained with stop watch is period of oscillation. The period of oscillation can be used to determine angular speed and the angular speed is used to determine the spring constant.

(c) The frequency of oscillation of the mass is 0.8 Hz.

The value of spring constant can be determined experimentally with a mass and stop watch to record the period of oscillation.

k = ω²m

where;

With a known mass attached to the spring, the period of the oscillation can be determined using stop watch. The period of the oscillation can be used to determine the frequency and angular speed of the oscillation. The angular speed can be used to determine the spring constant, K.

ω² = K/m

ω² = 500/20

ω² = 25

ω = √25

ω = 5 rad/s

ω = 2πf

f = ω/2π

f = 5/2π

f = 0.8 Hz

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The equation of motion for the rodent is x(t) = -1.12cos(3.20t), and the damping force is Fd = -0.62*vx(t). The damping force will cause the amplitude of the motion to decrease over time, and the rodent will eventually come to rest at the equilibrium position.

We can use the following equations to solve this problem:

F = -kx (Hooke's Law)

F = ma (Newton's Second Law)

a = d^2x/dt^2 (Definition of Acceleration)

Fd = -bv (Definition of Damping Force)

x(t) = A*cos(ωt + φ) (Equation of Motion for Simple Harmonic Motion)

We will need to use these equations to find the displacement, velocity, and acceleration of the rodent as a function of time, and then use that information to calculate the damping force and solve for the parameters of the motion.

First, let's find the natural frequency of the system:

ω = sqrt(k/m) = sqrt(3.50 N/m / 0.400 kg) = 3.20 rad/s

Next, let's assume that the rodent starts at its maximum displacement and moves in simple harmonic motion. We can use the equation of motion for simple harmonic motion to write:

x(t) = A*cos(ωt + φ)

where A is the amplitude of the motion and φ is the phase angle.

To find A and φ, we need to use the initial conditions. We know that at t=0, the rodent is at its maximum displacement, so x(0) = A. We also know that at t=0, the velocity of the rodent is zero, so vx(0) = -Aωsin(φ) = 0. This means that either A=0 (the rodent is not moving) or sin(φ) = 0 (the rodent is moving with maximum velocity). We will assume that the latter is true, so sin(φ) = 0 and cos(φ) = 1.

Now we can write:

x(t) = A*cos(ωt)

To find A, we use the fact that the rodent has a mass of 0.400 kg and is moving on a spring with force constant 3.50 N/m. The force on the rodent is given by:

F = -kx = -3.50 N/m * A*cos(ωt)

At maximum displacement, the force is equal to the weight of the rodent:

mg = 0.400 kg * 9.81 m/s^2 = 3.92 N

So we can write:

3.92 N = -3.50 N/m * A

A = -1.12 m

Therefore, the equation of motion for the rodent is:

x(t) = -1.12cos(3.20t)

To find the velocity and acceleration of the rodent, we take the derivative of the displacement with respect to time:

vx(t) = dx/dt = 3.58sin(3.20t)

ax(t) = d^2x/dt^2 = -11.46cos(3.20t)

To find the damping force, we use the equation:

Fd = -bv = -bdx/dt = -b3.58sin(3.20t)

We don't know the value of b, so we can't solve for it directly. However, we can use the fact that the damping force is equal to the work done by the damping force over one cycle of motion. This work is equal to the energy lost by the system due to damping. Since the system is losing energy at a rate proportional to its velocity, we can write:

Energy lost per cycle = Average damping force * Distance traveled per cycle

The distance traveled per cycle is equal to 2piA = 7.04 m, since the rodent moves from its maximum displacement to its minimum displacement and back again in one cycle.

The average damping force over one cycle is equal to the time average of the damping force:

<Fd> = (1/T)∫[0,T] -bdx/dt dt

where T = 2*pi/ω is the period of the motion. Evaluating the integral gives:

<Fd> = (1/T)∫[0,T] -b(-1.12)3.20sin(3.20*t) dt

<Fd> = 3.58*b

Since the energy lost per cycle is also equal to (1/2)kA^2, we can write:

(1/2)kA^2 = <Fd>2pi*A

Solving for b, we get:

b = (kA)/(2pi)

Substituting the given values, we get:

b = (3.50 N/m * 1.12 m)/(2*pi) = 0.62 Ns/m

Therefore, the equation of motion for the rodent is:

x(t) = -1.12cos(3.20t)

vx(t) = 3.58sin(3.20t)

ax(t) = -11.46cos(3.20t)

and the damping force is given by:

Fd = -0.62*vx(t)

Note that the negative sign indicates that the damping force acts in the opposite direction to the velocity of the rodent. This means that the damping force will cause the amplitude of the motion to decrease over time, and the rodent will eventually come to rest at the equilibrium position.

Therefore,The equation of motion for the rodent is x(t) = -1.12cos(3.20t), and the damping force is Fd = -0.62*vx(t).

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Answer:

A

Explanation:

In an optics experiment, the three possible reasons to account for the absence of an image on the screen. are:

Image out of focus - The picture is frequently just out of focus. Perhaps you over-focused on one area, making it impossible for you to see a clear picture. Some folks struggle to locate a clear image and repeatedly turn the focus knob. The focus can be lost considerably more readily at higher magnifications, which is a special issue.

Incorrect focus plane - It's possible that you can see a clear image, but not of the thing you're trying to see. In this instance, it's likely that you were more interested in the dust on the slide's or cover glass' surface than the object itself. With the low magnification objective in place, it is preferable to start anew in this situation and refocus.

Lastly, Uncentered slides - This is yet another frequent issue. Are you attempting to study a region of the slide that does not include the object of interest or are you truly gazing at the specimen? Perhaps you cannot see anything because you are looking at a region of the slide that is completely devoid of specimens.

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A student creates a dichotomous key to identify common household pets. The wrong  key is option  C. A pet can have a hairy body and live in a cage, or can be hairless and not live in a cage.

A dichotomous key is an instrument utilized for the classification and identification of living organisms by examining their visible traits. It is comprised of a sequence of decisions or actions which guide the user towards accurately identifying the organism.

Every decision or move involves selecting between two alternative options or features that are contradictory to each other. Furthermore, the correct answer identified as option C acknowledges that pets can possess different traits and may not necessarily conform to a specific classification.

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B. The wavelength of the wave

The speed of light in a medium such as ethyl alcohol is generally less than the speed of light in a vacuum.

The speed of light in a medium can be determined using the equation:

v = c/n,

where v is the speed of light in the medium, c is the speed of light in a vacuum (approximately 299,792 kilometers per second), and n is the refractive index of the medium.

The refractive index of ethyl alcohol varies with the wavelength of light, but we can approximate it to a value of around 1.36 for visible light. Using this value, we can calculate the speed of light in ethyl alcohol:

v = c/n = (299,792 km/s) / 1.36 ≈ 220,163 km/s.

Therefore, the speed of light in ethyl alcohol is approximately 220,163 kilometers per second. It is important to note that this value is approximate and may vary slightly depending on the specific conditions and the wavelength of the light being considered.

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Sound will travel fastest in air at 15°C.

The speed of sound in air, given in the range of 100 degrees Celsius and 0 degree Celsius include;

Air at 100°C 387 m/s

Air at 0°C 331 m/s

From the date above, the speed of sound in air increases with increases in temperature. Thus, Sound will travel fastest in air at 15°C.

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Answer:

Good luck on the test, you donuts.

Explanation:

Answer:

Image distance = 44.8cm, Image height = 16.5cm, Magnification = 0.42

The image is a virtual and upright image.

Explanation:

The nature of image formed by an object placed in front of a convex mirror is always diminished, virtual and erect.

The focal length f and the image distance are always NEGATIVE beacause the image is formed behind the mirror.

Given f = -33.0cm, v = -19.0cm

using thr mirror formula to get the object distance u, we have;

\(\frac{1}{f}=\frac{1}{u} + \frac{1}{v}\\ \frac{1}{u}=\frac{1}{f} - \frac{1}{v}\\\frac{1}{u}=\frac{1}{-33} - \frac{1}{-19}\\\frac{1}{u}=\frac{-19+33}{627} \\\frac{1}{u}=\frac{14}{627} \\u=\frac{627}{14} \\u = 44.8cm\)

To calculate the image height, we will use the magnification formula

M = \(\frac{image\ height}{object\ height}=\frac{image\ distance}{object\ distance} \\\)

M = \(\frac{Hi}{HI}=\frac{v}{u}\)

Given Hi = 7.0cm

v = 19.0cm

u = 44.8cm

HI = 7*44.8/19

HI = 16.5cm

The object height is 16.5cm

Magnification = v/u = 19.0/44.8 = 0.42

SInce the image is formed behind the mirror, the image is a VIRTUAL and UPRIGHT image

Answer:

the magnitude of the frictional force acting between the box and the floor is 5 N.

Explanation:

Answer:

1. \( E = 1.14 \cdot 10^{13} N/C \)

2. \(E_{k} = 9.1 \cdot 10^{-17} J\)      

Explanation:

1. The strength of the nucleus' electric field (E):

\(E = \frac{kq}{r^{2}}\)

Where:

k: is the Coulomb constant = 9x10⁹ Nm²/C²

q: is the proton charge = 1.6x10⁻¹⁹ C

r: is the radius = 10⁻¹⁰ m

\(E = \frac{kq}{r^{2}} = \frac{9\cdot 10^{9} Nm^{2}/C^{2}*79*1.6 \cdot 10^{-19} C}{(10^{-10} m)^{2}} = 1.14 \cdot 10^{13} N/C\)

2. The kinetic energy (Ek) of an electron is the following:

\( E_{k} = \frac{1}{2}mv^{2} \)    

Where:

m is the electron's mass = 9.1x10⁻³¹ kg

v: is the speed of the electron

We can find the speed of the electron by equaling the centripetal force (Fc) and the electrostatic force (Fe):

\( F_{c} = F_{e} \)  

\( \frac{mv^{2}}{r} = \frac{kq^{2}}{r^{2}} = qE \)

\( v^{2} = \frac{qEr}{m} = \frac{1.6 \cdot 10^{-19} C*1.14 \cdot 10^{13} N/C*10^{-10} m}{9.1 \cdot 10^{-31} kg} = 2.00 \cdot 10^{14} m^{2}/s^{2} \)                  

Now, we can find the kinetic energy:

\( E_{k} = \frac{1}{2}mv^{2} = \frac{1}{2}9.1 \cdot 10^{-31} kg*2.00 \cdot 10^{14} m^{2}/s^{2} = 9.1 \cdot 10^{-17} J \)    

I hope it helps you!

Answer:

1.32% error

Explanation:

You can derive the relativistic kinetic energy by integrating the velocity function over a differential change in momentum. Then use integration by parts to get the answer of:

\(KE=mc^2[gamma-1]\)

Gamma is the lorentz factor equal to:

\(gamma=\frac{1}{\sqrt{1-(v/c)^2}}\)

Therefore the relativistic kinetic energy would be:

\(KE=mc^2[\frac{1}{\sqrt{1-(v/c)^2}}-1]\)

Plug everything in to get:

\(KE=(17000)(3x10^8)^2[\frac{1}{\sqrt{1-(0.14c/c)^2}}-1]\)

\(KE=(17000)(9x10^{16})[\frac{1}{\sqrt{1-0.0196}}-1]\)

\(KE=1.53x10^{21}[\frac{1}{\sqrt{1-0.0196}}-1]\)

\(KE=1.52x10^{19}J\)

The classical non-relativistic formula for kinetic energy is:

\(KE=\frac{1}{2} mv^2\)

Therefore the classical kinetic energy is:

\(KE=1.50x10^{19}J\)

Use the error percentage formula, found online if you dont recall:

\(error=\frac{|KE_c-KE_r|}{KE_r} \frac{100}{1} =1.32\)

The result of the ratio of the displacement module of the second body at the point of meeting is 0.5.

To determine the ratio of the displacement of the first body to the displacement of the second body at the moment of their meeting, use the equation of motion:

d = vt + 1/2at²

where d is the displacement, v is the initial velocity, t is the time, and a is the acceleration.

Since the bodies are moving simultaneously towards each other, then assume that their initial velocities are zero. Also, at the moment of their meeting, their displacement will be the same, d₁ = d₂.

Assume that the time at which they meet is t, then:

d₁ = 1/2 * 2.4t²

And the equation for the displacement of the second body:

d₂ = 1/2 * 4.8t²

If d₁ = d₂

then, 1/2 * 2.4t² = 1/2 * 4.8t²

Solving this equation for t and substituting it into the equation for d₁ or d₂, the ratio of the displacement of the first body to the displacement of the second body: d₁/d₂ = 2.4/4.8 = 0.5 or 1/2

So, at the moment of their meeting, the displacement of the first body is half of the displacement of the second body.

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When acceleration is equal to zero average velocity and the instantaneous velocity vectors are identical.

Types of velocity

Velocity is defined as the rate of displacement of an object with respect to time. It is measured in meter/ seconds and is a vector quantity.

Acceleration is defined as the rate at which velocity changes with time.

There are two types of velocity which includes:

Average velocity: This is the average rate of change of position of particles with respect to time over an interval.

Instantaneous velocity: This is defined as the specific rate of change of position with respect to time at a particular point.

The situation that will make the average velocity and the instantaneous velocity vectors to be equal or identical is when acceleration is equal to zero.