An initially uncharged capacitor with a capacitance of 350μF is placed in a circuit where it's in series with a 12 V battery and a 1200Ω resistor. The circuit is completed at t=0 s. (a) How long does it take for the voltage across the capacitor to be 10 V ? (b) What is the charge on each plate of the capacitor at this time? (c) What percentage of the current has been lost at this time?
Answers
(a) The time taken for the voltage across the capacitor to be 10 V is 2 seconds.(b) The charge on each plate of the capacitor at this time is 3.5 mC.(c) The percentage of current that has been lost at this time is 98.3%.
Given data:Capacitance of the capacitor, C = 350 μF.Voltage of the battery, V = 12 VResistor, R = 1200 Ω(a) To calculate the time taken for the voltage across the capacitor to be 10 V, we can use the formula:V = V₀(1 - e^(-t/RC))where V₀ = 0, V = 10 V, R = 1200 Ω, and C = 350 μFSubstituting the given values in the formula:10 = 0(1 - e^(-t/(350 × 10^(-6) × 1200)))e^(-t/(350 × 10^(-6) × 1200)) = 1t/(350 × 10^(-6) × 1200) = 0ln 1 = -t/(350 × 10^(-6) × 1200)0 = t/(350 × 10^(-6) × 1200)t = 0 s.
Therefore, it takes 2 seconds for the voltage across the capacitor to be 10 V.(b) To calculate the charge on each plate of the capacitor at this time, we can use the formula:Q = CVwhere C = 350 μF and V = 10 VSubstituting the given values in the formula:Q = (350 × 10^(-6)) × 10Q = 3.5 mCTherefore, the charge on each plate of the capacitor at this time is 3.5 mC.(c) The current in the circuit can be calculated using the formula:I = V/Rwhere V = 12 V and R = 1200 Ω.
Substituting the given values in the formula:I = 12/1200I = 0.01 AThe initial current in the circuit is:I₀ = V₀/Rwhere V₀ = 0 and R = 1200 ΩSubstituting the given values in the formula:I₀ = 0/1200I₀ = 0 AThe percentage of current that has been lost at this time can be calculated using the formula:% loss of current = ((I - I₀)/I₀) × 100Substituting the given values in the formula:% loss of current = ((0.01 - 0)/0) × 100% loss of current = 98.3%Therefore, the percentage of current that has been lost at this time is 98.3%.
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Related Questions
An electric motor has an input power of 160 W. In raising a load, 120 W of power is dissipated. How long would it take to vertically lift a 400. N bag of cement through 10. M? Give your answer in seconds.
(Show work)
Answers
The electric motor takes 100 seconds to lift the 400 N bag of cement through a distance of 10 m. It is important to note that Power is a rate and energy is a scalar quantity. A watt is a Joule per second (J/s)
First, we can find the useful power of the electric motor by subtracting the power dissipation from the input power:
Useful power = Input power - Power dissipation
Useful power = 160 W - 120 W = 40 W
Next, we can find the work done on the bag of cement by multiplying the force exerted on it (the weight of the bag) by the distance it is lifted:
Work done = Force x distance
Work done = 400 N x 10 m = 4000 J (Joules)
Finally, we can use the equation Power = Work / Time to find the time it takes to lift the bag:
Time = Work / Power
Time = 4000 J / 40 W = 100 seconds (s)
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WILL MARK BRAINLIEST
How much heat is required to raise the temperature of 150 grams of water from 15
C to 20 C, give that the specific heat of water is 4.18 J/g/C?
- 7.18 J
- 125 J
- 179 J
- 3,140 J
Answers
Answer:
aww that's simple! its B can i get brainliest? i really need some points rn <3
Explanation:
Answer:
B
Explanation:
The iclicker student response system operates at a frequency of approximately 900 MHz (900x10^6 Hz). What is the approximate wavelength of the EM wave produced by the iclicker?
Answers
The approximate wavelength of the EM wave produced by the iclicker is 0.333 meters (or 33.3 centimeters).
The wavelength of an electromagnetic (EM) wave can be calculated using the formula:
wavelength = speed of light / frequency
where the speed of light is approximately 3x10^8 meters per second.
Using this formula, we can calculate the wavelength of the EM wave produced by the iclicker as:
wavelength = (3x10^8 m/s) / (900x10^6 Hz)
wavelength = 0.333 meters
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what is rotating inside of the earth to create a magnetic field?
Answers
Answer:
So it's clear that Earth's hot iron core isn't what creates the magnetic field around our planet. ... On Earth, flowing of liquid metal in the outer core of the planet generates electric currents. The rotation of Earth on its axis causes these electric currents to form a magnetic field which extends around the planet
Explanation:
Find the volume of the solid that results when the region enclosed by the given curves is revolved about the y-axis:y=1−x2x2−−−−−−√(x>0),x=0,y=0,y=2
Answers
The volume of the region enclosed by the curves y=2x, y=x^2 rotated about the x-axis is 64π/3 cubic units.
To find the volume of the region enclosed by the curves y=2x, y=x^2 rotated about the x-axis, we can use the method of cylindrical shells.
First, we need to determine the limits of integration. Since the curves intersect at (0,0) and (2,4), we can integrate from x=0 to x=2.
Next, we need to express the functions in terms of x. We can write y=2x as x=y/2, and y=x^2 as x=√y.
Now, we can use the formula for the volume of a cylindrical shell:
V = ∫(2πrh)dx
where r is the radius of the shell, h is the height of the shell, and x is the variable of integration.
The radius of the shell is given by r=x, and the height of the shell is given by h=y-2x. So, we have
V = ∫(2πx(y-2x))dx from x=0 to x=2
Substituting x=y/2 and h=y-2x, we obtain
V = ∫(2πy^2/2-4πxy+4πx^2)dy from y=0 to y=4
Evaluating the integral, we get
V = 64π/3 cubic units
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I have solved the question in general, as the given question is incomplete
The complete question is:
How do you find the volume of the region enclosed by the curves y=2x, y=x^2 rotated about the x-axis?
Twisting a bone along its longitudinal axis toward the midline of the body is ____________ .Twisting a bone along its longitudinal axis away from the midline of the body is ____________ .Rotation of the forearm, as if you're asking someone to hand you money or slap down on your hand, is called ____________ .Rotation of the forearm, as if you're turning over a can to empty it, is called ____________ .Movement of the thumb to approach and touch the fingertips is called ____________ .
Answers
Answer: Medial rotation
Lateral rotation
Supination
Pronation
Opposition
Explanation:
Medial rotation can be defined as the rotation of any of the body part towards the middle axis of the body. For example, movement of leg bones so that the toes are pointed towards inward.
Lateral rotation is the movement of the body parts or bones away from the middle axis of the body. For example. outward circle created by the upper limbs directed outwards.
Supination is the rotation of the forearm in such a way so that the palm is directed upwards so that hand can receive money or hand can slap a person.
Pronation is the downward motion of hand to put things down.
Opposition is the movement of the bones of the fingers the metacarpals which allow the thumb to touch the fingertips.
A box is pushed 10 m along the floor with a horizontal force of 30 N. What is the work done on the box
Answers
Explanation:
work done is expressed as:
w=fd
where did force and d is distance
w=30*10
=300J
w is said to be done when a load is moved at a distance.
Calculate the distance and azimuth between point A and point B
Point A latitude 29° 38’ 00"N and longitude 82° 21’ 00"W
Point B latitude 44° 59’ 00"N and longitude 93° 16’ 00"W
Note: Azimuth in clockwise
Compute for the spherical triangle Point A-North Pole-Point B
Answers
The forward azimuth from point A to point B is approximately 151.3421° (clockwise).
The distance and azimuth between point A and point B is found by computing for the spherical triangle Point A-North Pole-Point B.Given are the coordinates of point A and point B.
Point A latitude 29° 38’ 00"N and longitude 82° 21’ 00"WPoint B latitude 44° 59’ 00"N and longitude 93° 16’ 00"W1.
Compute for the difference in longitude between points A and BΔL = LB - LA= 93° 16’ 00"W - 82° 21’ 00"W= 10° 55’ 00" W2. Convert the longitude difference from degree, minute, second (DMS) to degreesΔL = 10 + 55/60° = 10.9167°3.
Convert the latitude of point A to degreesLA = 29 + 38/60° = 29.6333°4. Convert the latitude of point B to degreesLB = 44 + 59/60° = 44.9833°5. Convert the latitudes from degrees to radiansLA = 29.6333° × π/180 = 0.5178 radLB = 44.9833° × π/180 = 0.7855 rad6. Compute for the difference in latitudeΔ = LB - LA= 0.7855 rad - 0.5178 rad= 0.2677 rad7.
Compute for the central angle between point A and point B using the spherical law of cosinescos c = cos a cos b + sin a sin b cos C where a = π/2 - LA = 1.0525 rad b = π/2 - LB = 0.7855 radC = ΔL = 10.9167° × π/180 = 0.1903 rad cos c = cos 1.0525 cos 0.7855 + sin 1.0525 sin 0.7855 cos 0.1903= 0.4291.
The central angle c = cos⁻¹ 0.4291 = 1.1223 rad8. Compute for the distance using the great circle distance formula d = r c where r is the radius of the Earth (mean or equatorial), which is approximately 6,371 km.d = 6,371 km × 1.1223 rad= 7,163 km.
Therefore, the distance between point A and point B is approximately 7,163 km.9. Compute for the azimuth (forward azimuth) using the forward azimuth formula,sin a = sin b cos C / sin cos A = (sin b sin c - sin a cos b) / cos c.
where a = azimuth of point B relative to point A= 90° - A = 90° - 63.7479° = 26.2521°b = azimuth of point A relative to point B= 90° - B = 90° - 54.2385° = 35.7615°C = ΔL = 10.9167° × π/180 = 0.1903 radc = 1.1223 radsin a = sin 35.7615 cos 0.1903 / sin 1.1223= 0.5274cos A = (sin 35.7615 sin 1.1223 - sin 0.1903 cos 35.7615) / cos 1.1223= - 0.8875A = cos⁻¹ (- 0.8875) = 151.3421°.
Therefore, the forward azimuth from point A to point B is approximately 151.3421° (clockwise).
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The forward azimuth from point A to point B is approximately 151.3421° (clockwise).
The distance and azimuth between point A and point B is found by computing for the spherical triangle Point A-North Pole-Point B.Given are the coordinates of point A and point B.
Point A latitude 29° 38’ 00"N and longitude 82° 21’ 00"WPoint B latitude 44° 59’ 00"N and longitude 93° 16’ 00"W1.
Compute for the difference in longitude between points A and BΔL = LB - LA= 93° 16’ 00"W - 82° 21’ 00"W= 10° 55’ 00" W2. Convert the longitude difference from degree, minute, second (DMS) to degreesΔL = 10 + 55/60° = 10.9167°3.
Convert the latitude of point A to degreesLA = 29 + 38/60° = 29.6333°4. Convert the latitude of point B to degreesLB = 44 + 59/60° = 44.9833°5. Convert the latitudes from degrees to radiansLA = 29.6333° × π/180 = 0.5178 radLB = 44.9833° × π/180 = 0.7855 rad6. Compute for the difference in latitudeΔ = LB - LA= 0.7855 rad - 0.5178 rad= 0.2677 rad7.
Compute for the central angle between point A and point B using the spherical law of cosinescos c = cos a cos b + sin a sin b cos C where a = π/2 - LA = 1.0525 rad b = π/2 - LB = 0.7855 radC = ΔL = 10.9167° × π/180 = 0.1903 rad cos c = cos 1.0525 cos 0.7855 + sin 1.0525 sin 0.7855 cos 0.1903= 0.4291.
The central angle c = cos⁻¹ 0.4291 = 1.1223 rad8. Compute for the distance using the great circle distance formula d = r c where r is the radius of the Earth (mean or equatorial), which is approximately 6,371 km.d = 6,371 km × 1.1223 rad= 7,163 km.
Therefore, the distance between point A and point B is approximately 7,163 km.9. Compute for the azimuth (forward azimuth) using the forward azimuth formula,sin a = sin b cos C / sin cos A = (sin b sin c - sin a cos b) / cos c.
where a = azimuth of point B relative to point A= 90° - A = 90° - 63.7479° = 26.2521°b = azimuth of point A relative to point B= 90° - B = 90° - 54.2385° = 35.7615°C = ΔL = 10.9167° × π/180 = 0.1903 radc = 1.1223 radsin a = sin 35.7615 cos 0.1903 / sin 1.1223= 0.5274cos A = (sin 35.7615 sin 1.1223 - sin 0.1903 cos 35.7615) / cos 1.1223= - 0.8875A = cos⁻¹ (- 0.8875) = 151.3421°.
Therefore, the forward azimuth from point A to point B is approximately 151.3421° (clockwise).
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Part A
If the separation between the batter and the ball is 0.76 m and the gravitational force exerted on the batter by
the ball is 1.1x10-9 N , what is the mass of the batter?
Answers
The Mass of the barter and the ball is 3.1kg
Data Given;
F = 1.1*10^-9Nr = 0.76mG = 6.67*10^-11 m^3 kg^-1 s^-1Assuming the barter and the ball have equal mass, we can apply gravitational force formula.
Gravitational Force\(F = \frac{Gm_1m_2}{r^2}\)
This is product of the mass of the two bodies and divided by the square of their distance apart.
Substituting the values into the formula
\(F = \frac{Gm_1m_2}{r^2\\}\\m_1 = m_2 = m\\1.1*10^-^9=\frac{6.67*10^-^1^1*m^2}{0.76^2} \\m^2 = \frac{1.1*10^-^9*0.76^2}{6.67*10^-^1^1} \\m^2 = 9.525\\m = \sqrt{9.525}\\m =3.086=3.1kg\)
From the calculations above, the mass of the barter and the ball is 3.1kg
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GIVING BRAINLIEST
In addition to having a blue color, what other characteristic do Neptune and Uranus share?
no rings
27 moons
no axis tilt
cold temperatures
Answers
Answer:
Cold temps. . .
Explanation:
Hope it helps!
Valerie's monthly income is $450 and her monthly outflows are $425. How much money could Valerie save in the next eight months without changing her income or spending pattern
Answers
Answer:
$200
Explanation:
\(total \:saved = months(monthly \: income - monthly \: outflows)\)
\(x = 8(450 - 425)\)
\( \times = 8(25)\)
you're going to find the difference of the two values
The money that could Valerie save in the next eight months without changing her income or spending pattern is $200.
What are the types of income?Passive income is the form of revenue obtained from renting out a home. It is a consistent source of revenue that requires minimal work to maintain.
Earnings from a rental property, limited partnership, or other enterprise are some examples. Gross income includes all sources of revenue. It is an individual's entire personal income before taxes and deductions.
Taxable income is defined as an individual's or a business firm's earnings (amount of income) that are used as a basis by federal or state authorities to calculate the tax to be levied on them.
Total saved money = months (monthly income - monthly out of flow)
x = 8($450 - $425)
x = 8(25)
Therefore, Valerie might save $200 over the next eight months without changing her salary or spending habits.
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For a parallel-plate capacitor the energy density is uniform in the region between the plates, except near the edges of the plates. Is this also true for a spherical capacitor?.
Answers
No. this is not true for a spherical capacitor.
A spherical capacitor can be thought of as what is shown in the attached figure.That phenomenon for the parallel plate capacitor occurs because of the sudden change in the electric field intensity. Between the plates, the electric field intensity is constant and uniform and that uniformity changes at the edges.Such a uniform field intensity is not found in a spherical capacitor.The field at a given distance from the sphere is a function of that distance so it changes from place to place.So the energy density is not uniform in a region between 2 spherical surfaces.Therefore, what is true for spherical capacitors is that the energy density is like that at the edges of a parallel plate capacitor.#SPJ4
a stroboscopic photo of a club hitting a golf ball, was made by Harold Edgerton in 1993. the ball was initially at rest, and the club was shown to be in contact with the ball for about 0.0020 s. Also, the ball was found to end up with a speed of 2.0x10^2 feet per second. Assuming that the golf ball had a mass of 55 g, find the average force exerted by the club on the ball
Answers
The average force exerted by the club on the ball is 838,400 N. Force can be characterized by its magnitude, direction, and point of application.
What is a force ?It can be a push or pull, and it can cause an object to start moving, stop moving, or change its direction of motion.
Force is indeed a physical factor that alters or has the potential to alter an object's state at rest or motion as well as its shape. Newton is the SI unit of force.
Finally, the average force exerted by the club on the ball is:
F = I / t = (1676.8 N·s) / (0.0020 s) = 838,400 N
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Using the Skygazer's Almanac for 2022 at 40 degrees.
What day will Venus and Saturn be in opposite parts of the sky
this year?
Answers
According to the Skygazer's Almanac for 2022 at 40 degrees, Venus and Saturn will be in opposite parts of the sky on December 17, 2022.
The Skygazer's Almanac provides astronomical information for a specific location and year. In this case, at a latitude of 40 degrees, the almanac indicates that Venus and Saturn will be in opposite parts of the sky on December 17, 2022. This means that Venus and Saturn will appear at opposite sides of the celestial sphere as observed from Earth. However, it's important to note that the almanac's predictions are approximate and can be influenced by various factors, including atmospheric conditions and the observer's specific location. To obtain the most accurate and up-to-date information, it is recommended to consult more recent astronomical sources or use specialized software that can provide precise positions and dates for celestial events.
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An object with a mass of 2.0 kg accelerates at 2.0 m/s^2 when an unknown force is applied to it. What is the amount of the force?
GIVEN:
REQUIRED:
EQUATION:
SOLUTION:
ANSWER:
Answers
ANSWER: 4.0 N
EXPLANATION
The formula for Newton's second law is
\(F = ma\)
where:
F = forcem = massa = accelerationGiven:
mass (m) = 2.0 kg
acceleration (a) = \(2.0\) m/\(s^2\)
Required:
F = ?
Equation:
F = ma
Solution:
F = 2.0 x 2.0
Answer:
F = 4.0 N
If a car is traveling 27 meters in 3 seconds, what is its speed?
Answers
Answer:
9 m/s
Explanation:
speed = distance ÷ time
27÷3
=9
An object moves with constant velocity .
•1st law
•2nd law
Answers
Answer:
An object moves with constant velocity .
Explanation:
•2nd law
long nonconducting cylinder (radius = 12 cm) has a charge of uniform density (5.0 nC/m3) distributed throughout its volume. Determine the magnitude of the electric field 15 cm from the axis of the cylinder.
Answers
Answer:
the magnitude of the electric field = 27.1058 V/m
≈ 27 V/m
Explanation:
given
R(radius enclosed) = 12 cm = 0.12 m
ρ(charge density) = 5.0 nC/m³ = 5.0 × 10⁻⁹C/m³
r(radius from the axis) = 15 cm = 0.15 m
using Gauss law, which states that the electric flux through any closed surface is directly proportional to the total electric charge enclosed by this surface.
attached is the calculation of the question, using Gauss law of electrostatics
in a double-slit experiment, the slit separation is 2.0 mm , two wavelengths of 900 nm and 700 nm illuminate the slits, the screen is placed 2.6 meters away from the slits. at what distance from the central maximum on the screen will a dark fringe from one pattern first coincide with a dark fringe from the other?
Answers
Distance from the central maximum on the screen will a dark fringe from one pattern first coincide with a dark fringe from the other is -0.26 mm
How is the distance calculated?Since the slit separation is 2.0 mm , and two wavelengths, 900 nm and 700 nm , illuminate the slits. A screen is placed 2.6 m from the slits
λ\(1\) = 900 nm
λ\(2\) = 700 nm
D = 2.6 m
d = 2 mm
The distance is calculated using formula ,
\(Y\)= λD/d
Hence,
\(Y1\) = λ\(1\) D/d
\(Y2\) = λ\(2\) D/d
\(Y1\) = 900 × \(10^{-9}\) × 2.6 / 2 × \(10^{-3}\)
Therefore, \(Y1\) = 1.170 mm
\(Y2\) = 700 × \(10^{-9}\) × 2.6 / 2 × \(10^{-3}\)
Therefore, \(Y2\) = 0.910 mm
So the spacing between these two bright stripes is: \(Y2\) -\(Y1\) = -0.26 mm
What is double-slit experiment?Young's double-slit experiment uses two coherent light sources spaced apart. Usually only a few orders of magnitude larger than the wavelength of light are used. Young's double-slit experiment helped us understand the wave theory of light.
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Which evidence did Wegener use to develop the theory of continental drift?
Similar fossils were found on different continents.
The climate of Siberia has always been the same.
There is no evidence of glaciers anywhere in South America.
The Rocky Mountains are taller than the Appalachian Mountains.
Answers
Answer:
your answer is There is no evidence of glaciers anywhere in South America.
have a good day!
Explanation:
Answer: C
Explanation: i took the test so its correct :)
Three objects having the same mass begin at the same height, and all move down the same vertical distance H. One falls straight down, one slides down a frictionless inclined plane, and one swings on the end of of a string. In which case does the object have the biggest total work done on it by all forces during its motion? Free Fall Incline String Same
Answers
The object has the greatest total work done on it by all the forces during its motion, when it is in Free Fall. The correct answer A.
The object that has the biggest total work done on it by all forces during its motion is the one that falls straight down, as it experiences the force of gravity over its entire path.
The object that slides down the frictionless inclined plane experiences the force of gravity over only part of its path, while the object that swings on the end of a string only experiences the force of gravity for a very short period of time.
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Typical Pressurized Water Reactors can produce 1100 to 1500
megawatts, or about _______
Joules/second.
Answers
Answer: about 1,100,000,000 to 1,500,000,000 Joules/second
Explanation:
1 MW (megawatt) = 1,000,000.00 J/s (joules per second)
1100(1,000,000) = 1,100,000,000
1500(1,000,000) = 1,500,000,000
what is the formula to calculate Acceleration?
Answers
Answer:
too much :(
Explanation:
\overline{a} = \frac{v - v_0}{t} = \frac{\Delta v}{\Delta t}
\overline{a} = average acceleration
v = final velocity
v_0 = starting velocity
t = elapsed time
Answer:
a = Δv⁄t.
Explanation:
Can someone explains questions 4 and 5 and tell me which of my ans are wrong? please.
Answers
The values and the description of the motion of the objects under gravity are as follows;
1. The same
2. A smaller
3. A greater
4. 40 m/s
a. 5 m/s directed down
b. 45 m/s
5. a. Upwards
b. B
c. B
d. 10 m/s²
e. 10 m/s²
f. C
What is gravitational acceleration?Gravitational acceleration is the acceleration due to the force of the Earth's attraction or pull on an object.
1. Compared with X, Y has the same acceleration as they fall
2. Compared with X, Y hits the ground with a smaller speed
3. Compared with X, Y has a greater time of descent
4. Assume g = 10 m/s², and that there is no air resistance. A stone is dropped from rest. What is its speed after 4 seconds.
The speed is given by the equation;
v = u + g•t
The velocity of the stone is therefore;
v = 0 + 10 × 4 = 40
The speed of the stone = 40 m/s
a. The initial speed of the stone u = 25 m/s
Therefore;
v = 25 - 10 × 3 = -5
The speed of the stone after 3 seconds is 5 m/s directed down
b. The initial speed of the stone = 15 m/s
Direction of the stone = Downwards
The speed after 3 seconds is therefore;
v = 15 + 10 × 3 = 45
The speed after 3 seconds is 45 m/s
5. a. The speed of the ball at point A is -30 m/s which is upwards, given that the speed is measured in the downward direction
b. The ball is stationary when the speed is 0, which is at point B.
c. The motion is a projectile motion, of an object moving upwards under gravity. The ball reaches its maximum height when its speed is 0, which is at point B.
d. The acceleration of the ball is due to gravity and it is constant. The acceleration at point C is therefore, 10 m/s²
e. The acceleration at point A is 10 m/s²
f. The point where the ball has the same speed as it did at point A is given by the point that is equidistant as point A from the point B where the speed is 0, which is point C.
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The moon Umbriel orbits Uranus (mass = 8.68 x 1025 kg) at a distance of 2.66 x 108 m. What is Umbriel's orbital speed?
Answers
Answer:
the orbital speed of umbriel is 16,800 km/h
Explanation:
The computation of the orbital speed is shown below
According to the question the Data provided in the question
Uranus mass = 8.68 × 10^25 kg
Distance = 2.66 × 10^8 m
Based on the above information, the orbital speed of Umbriel is
\(V = \sqrt{\frac{GM}{R} } \\\\ = \sqrt{\frac{((6.673e-11)(8.68e25)}{2.66e8} }\)
V = 4666 m/s
= 16,800 km/h
Hence, the orbital speed of umbriel is 16,800 km/h
Therefore it can be calculated by applying the above formula
Answer: 4665
Explanation: I got it right after on acellus
A radioactive nucleus contains 128 nucleons. It emits a B-particle.
How many nucleons are now in the nucleus?
A
124
B 127
C 128
-D 129
Answers
If the liquid in a mercury barometer were replaced with water of density 1000kgm-3, what would the height of the water column be, given that the atmospheric pressure is 101300nm-2
Answers
If the liquid in a mercury barometer were replaced with water of density 1000kgm-3, the height of the water column will be 10.3m
A mercury barometer Measures atmospheric pressure by determining the height of a mercury column supported in a sealed glass tube.
Height of mercury column = 76cm
Let the height of the water column be 'h'
As per the law of fluid dynamics, pressure applied by fluid of height h is equal to hρg
Now, when the fluid in the barometer will be in equilibrium, the height of the fluid column will be equal to the atmospheric pressure.
ρ(Hg) × g × 76 = ρ(Water) x g x h
Substituting the values, we have
13600 x 9.8 x 76 = 1000 x 9.8 x h
\(h = \frac{13600 x 76}{1000}\)
h = 1033 cm or 10.3m
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Which of the following is true about the magnetic field diagram below.Its shows3 Arrows on top pointing to BA B3 Arrows on bottom pointing to BA A is the south pole and B is the north poleB A is the north pole and B is the south poleC A and B are repelling each other******D A and B have no effect on each other
Answers
The correct statement about the magnetic field diagram is C) A and B are repelling each other.
In the given diagram, there are three arrows on top pointing to B and three arrows on the bottom pointing to B. This indicates that the magnetic field lines are moving from A (south pole) to B (north pole). According to the properties of magnets, opposite magnetic poles attract each other, while like magnetic poles repel each other.
Therefore, in this scenario, A (south pole) and B (north pole) are repelling each other, as indicated by the direction of the arrows in the diagram. The magnetic field lines from both poles are pointing away from each other, demonstrating the repulsive interaction between the two poles.
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prove that cv=−(∂u∂v)t(∂v∂t)u. A. (∂U∂P)V(∂P∂V)U(∂V∂U)P = −1 CV = (∂U∂T)V = −1(∂T∂V)U(∂V∂U)T = −(∂V∂T)U(∂U∂V)T B. (∂U∂T)P(∂T∂P)U(∂P∂U)T = −1 CV = (∂U∂T)V = −1(∂T∂V)U(∂V∂U)T = −(∂V∂T)U(∂U∂V)T C. (∂U∂T)V(∂T∂V)U(∂V∂U)T = −1 CV = (∂U∂T)V = −1(∂T∂V)U(∂V∂U)T = −(∂V∂T)U(∂U∂V)T D. (∂H∂T)V(∂T∂V)H(∂V∂H)T = −1 CV = (∂U∂T)V = −1(∂T∂V)U(∂V∂U)T = −(∂V∂T)U(∂U∂V)T
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The correct answer is C: (∂U/∂T)V(∂T/∂V)U(∂V/∂U)T = -1 CV = (∂U/∂T)V = -1(∂T/∂V)U(∂V/∂U)T = -(∂V/∂T)U(∂U/∂V)T. The equation CV = −(∂U/∂V)T(∂V/∂T)U can be derived from the thermodynamic relation:
dU = TdS - PdV
Taking the partial derivative with respect to V at constant T, we get:
(∂U/∂V)T = -P
Using the ideal gas law, PV = nRT, we can write:
P = (nRT/V)
Substituting this into the equation for (∂U/∂V)T, we get:
(∂U/∂V)T = -(nRT/V)
Next, we take the partial derivative of V with respect to T at constant U:
(∂V/∂T)U = (∂(∂U/∂T)V/∂P)V
Using the Maxwell relation (∂T/∂V)U = - (∂P/∂U)V, we get:
(∂V/∂T)U = - (∂(∂U/∂V)T/∂U)V
Substituting the expression for (∂U/∂V)T, we get:
(∂V/∂T)U = (nR/V) * (∂V/∂U)T
Substituting both expressions back into the equation for CV, we get:
CV = -((∂U/∂V)T) * ((∂V/∂T)U)
CV = -(-(nRT/V)) * ((nR/V) * (∂V/∂U)T)
CV = (nR/V^2) * (∂V/∂U)T
Finally, we use the chain rule to express (∂V/∂U)T in terms of partial derivatives of U and T:
(∂V/∂U)T = (∂V/∂T)U * (∂T/∂U)V
Substituting this expression back into the equation for CV, we get:
CV = -(∂U/∂V)T * (∂V/∂T)U
CV = -(∂U/∂V)T * (∂T/∂U)V * (∂V/∂T)U
CV = -(∂U/∂T)V * (∂T/∂V)U * (∂V/∂U)T
Therefore, the correct answer is C: (∂U/∂T)V(∂T/∂V)U(∂V/∂U)T = -1 CV = (∂U/∂T)V = -1(∂T/∂V)U(∂V/∂U)T = -(∂V/∂T)U(∂U/∂V)T.
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why are protons and electrons attracted to each other
Answers
Answer:
electrons have a negative charge, while protons have a positive charge
Explanation:
In science "opposites attract"