An infusion pump is a medical device that delivers fluids, such as nutrients and medications, into a patient's body in controlled amounts. Summarize the operation of infusion pump with its control system block diagram.

Answer:

True

Explanation:

Tensile testing which is also referred to as tension testing is a process which materials are subjected to so as to know how well it can be stretched before it reaches breaking point. Hence, the statement in the question is true

very big question aa having i can't answer it

Answer:

Shallow foundations, often called footings, are usually embedded about a metre or so into soil. ... Another common type of shallow foundation is the slab-on-grade foundation where the weight of the structure is transferred to the soil through a concrete slab placed at the surface.

Explanation:

Because I said so.

Answer:

If a tube having oval cross section is subjected to pressure its cross section tends to change from oval to circular.

Bourdon tube gauges consist of a circular tube.

One end of the tube is fixed while the other end is free to undergo elastic deformation under the effect of pressure.

Fixed end is open and pressure which is to be measured is applied at the fixed end.

Free end is closed and undergoes deformation under the effect of pressure.

Due to applied pressure the circular tube tends to uncoil and become straight along the dotted line.

Working of Bourdon Gauge

As the pressure is applied at the fixed end free end undergoes deformation.

The free end is attached with sector which further meshes with the pinion on which pointer is mounted.

Deformation of the pointer is transferred to pointer via this mechanism.

As a result point undergoes deflection and shows the pressure reading on calibrated dial.

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Answer:

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Explanation:

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Answer: This spark energy trigger ignition and combustion in the compressed air-fuel mixture. This discharge is of extremely brief duration (about 1/1000 of a second) and is extraordinarily complex!

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Answer:

This spark energy trigger ignition and combustion in the compressed air-fuel mixture. This discharge is of extremely brief duration (about 1/1000 of a second) and is extraordinarily complex.

Answer:

a) In turbulent flow, the tubes with rough surfaces have much higher friction factors than the tubes with smooth surfaces.

Explanation:

Turbulent flow is a type of fluid flow in which fluid will undergo irregular fluctuations. The tubes with rough surfaces have higher friction factors than the tubes with smooth surfaces. In laminar flow the effect of effect of surface roughness is negligible on friction factors.

Answer:

with what

Explanation:

Answer:

Efficiency is defined as any performance that uses the fewest number of inputs to produce the greatest number of outputs. Simply put, you're efficient if you get more out of less.

Explanation:

Note that if a manufacturer decides to use a push policy to promote its products, it is most likely to focus its efforts on wholesalers (Option B)

Push policy refers to the creation of processes that originate in the firm and travel to the market, whereas pull policy refers to processes that originate in the market and travel to the company.

The primary goal of PUSH's marketing tactics is to acquire product exposure, which applies to both new and old items. This is especially important for freshly introduced products when visibility is a high priority.

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Answer:

Explanation:

research how your company offers promotions show professional behavior at all times set both short and long-term personal goals make sure some goals are only for personal growth

Both Technician A and Technician B can be correct, as both methods are commonly used to check crankshaft endplay or end clearance.

Technician A uses a feeler gauge to measure the gap between the end of the crankshaft and the thrust surface of the engine block. This method involves inserting a calibrated feeler gauge between the two surfaces and measuring the thickness of the gauge required to fill the gap. This measurement gives an accurate indication of the amount of endplay or end clearance present.Technician B uses a dial indicator to measure the movement of the crankshaft as it is pushed back and forth in its axial direction. The indicator is mounted to the engine block or some other fixed point, and the measuring tip is placed against the end of the crankshaft.

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Answer:

The answer is below

Explanation:

Case hardening is a form of steel hardening that is applied on mild steel with a high temperature of heat.

It results in material forming a hard surface membrane, while the inner layer is soft.

It is mostly used for universal joints, construction cranes, machine tools, etc.

On the other hand, Through hardening is a form of steel hardening in engineering that involves heat treatment of carbon steel.

It increases the hardness and brittleness of the material.

It is often used for axles, blades, nuts and bolts, nails, etc.

Answer:

True

Explanation:

The Depreciation charge for year 2 is $177,200 and the book value at the end of year 2 if straight-line depreciation is used is $694,200.

Cost of a draw bench for precision forming and strengthening of carbon steel tubing= $960,000.Salvage value after a useful life of 10 years= $74,000.The useful life of the draw bench= 10 years.Let's calculate the Depreciation charge for year 2:Depreciation charge for a year using the straight-line method:Depreciation charge for a year=(Cost of an asset-Salvage value)/Useful life of an asset Depreciation charge for a year=($960,000-$74,000)/10 yearsDepreciation charge for a year=$88,600Now, we need to calculate the Depreciation charge for year 2:Depreciation charge for year 2=2×Depreciation charge for a yearDepreciation charge for year 2=2×$88,600Depreciation charge for year 2=$177,200Let's calculate the Book value at the end of year 2:Book value at the end of year 2=Cost of an asset-(Depreciation charge for year 1 + Depreciation charge for year 2 + Depreciation charge for year 3 + … + Depreciation charge for year 10)Book value at the end of year 2=$960,000-(Depreciation charge for year 1 + Depreciation charge for year 2)We know,Depreciation charge for year 1=Depreciation charge for a year=$88,600Depreciation charge for year 2=$177,200Therefore,Book value at the end of year 2=$960,000-($88,600+$177,200)=$694,200Hence, the Depreciation charge for year 2 is $177,200 and the book value at the end of year 2 if straight-line depreciation is used is $694,200.

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Answer:

\(N_a=\frac{45.04}{2}=22.52lb,N_b=\frac{67.48}{2} =33.74lb\)

Explanation:

Na and Nb are the vertical reactions on each of the two legs at A and at B

For the horizontal forces:

\(Fcos(30)-0.5N_a-0.5N_b=0\\0.5N_a+0.5N_b= Fcos(30)\\N_a+N_b= 2Fcos(30)\)

For the vertical forces:

\(N_a+N_b-Fsin(30)-75=0\\N_a+N_b=Fsin(30)+80\)

Therefore equating both equations:

\(2Fcos(30)=Fsin(30)+80\\F(2cos(30)-sin(30))=80\\F=\frac{80}{2cos(30)-sin(30)} =64.93N\)

After the desk star to slide:

sum of all vertical force = ma , therefore:

\(N_a+N_b-64.93sin(30)-80=0\\N_a+N_b=64.93sin(30)+80\)

sum of all horizontal force = ma

\(64.93cos(30)-0.2N_a-0.2N_b=\frac{80lb}{32.2ft/s^2}a\\ 0.2(N_a+N_b)=64.93cos(30)-\frac{80lb}{32.2ft/s^2}a\\N_a+N_b=\frac{64.93cos(30)-\frac{80lb}{32.2ft/s^2}a}{0.2}=324.65-12.42a\)

equating both equations:

\(324.65-12.42a=64.93sin(30)+80\\12.42a=324.65-64.93sin(30)-80\\12.42a=212.185\\a=17.08ft/s^2\)

From the moment equation:

\(4N_b-80(2)-64.93(3)=\frac{-80}{32.2} (17.08)(2)\\N_b=67.48lb\)

\(N_a=\frac{64.93cos(30)-\frac{80lb}{32.2ft/s^2}(17.08)}{0.2}-67.48 = 45.04lb\)

For each leg: \(N_a=\frac{45.04}{2}=22.52lb,N_b=\frac{67.48}{2} =33.74lb\)

Answer:

B....................

Answer:

The answer is "$10.12 million"

Explanation:

To find the price of the 36 dock doors only at the current rate, just use the cost index.  

\(C_n=C_k \times (\frac{I_n}{I_k})\\\\\)

     \(= 6 \times \frac{195}{140} \\\\= \$ \ 8 \ million\)

Its current cost of 36 dock doors is, thus,\(\$ \ 8 \ million\). To calculate the price for 48 dock doors, just use the second formula now:

\(\to (\frac{C_A}{C_B})=(\frac{S_A}{S_B})^{X}\\\\\to C_A=C_B \times (\frac{S_A}{S_B})^{X}\\\\\)

         \(=8 \times (\frac{48}{36})^{0.82}\\\\= \$ 10.12 \ million\)

Explanation:

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Answer:

456.2 days

Explanation:

Cv = tv x d²/t

For v>69%

We have tv = -0.933log(1-0.65)-0.0851

= 0.4254-0.0851

= 0.340

d² = (19/2)²

= 90.25

Cv = 0.340x90.25/10

= 3.0685mm²/min

At 40% consolidation

Tv = pi/4 x 0.4²

= 0.126

t = Tv x d²/cv

= 0.126x(4000)²/3.0685

t = 656998/60*24

= 456.2days

So it is going to take 456.2 days for a 4-m thick clay layer in the field to undergo 40% consolidation under the same pressure increment.

A warning sign is a sort of sign that signals a potential threat, barrier, or circumstance that calls for extra care. Some are road dangers that are indicated by traffic signs but may not be immediately obvious to a vehicle.

Although warning traffic signs come in a variety of styles, they often have an equilateral triangle shape with a white background and a heavy red border. They appear with a black border and a yellow background in the People's Republic of China (apart from Macau and Hong Kong). They have a crimson border with an amber backdrop in Poland, North Macedonia, Serbia, Bosnia and Herzegovina, Greece, Finland, and Sweden. The Svalbard polar bear warning sign has switched from showing a black bear on a white background to one that is white.

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Answer:

A

Explanation:

the type of work they do

Explanation:

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Answer:

I think it's the no 3rd

Explanation:

hope this helps

Answer:

a) The amount by which this specimen will elongate in the direction of the applied stress is 0.466 mm

b) The change in diameter of the specimen is  - 0.015 mm

Explanation:

Given the data  in the question;

(a) The amount by which this specimen will elongate in the direction of the applied stress.

First we find the area of the cross section of the specimen

A = \(\frac{\pi }{4}\) d²

our given diameter is 20.5 mm so we substitute

A = \(\frac{\pi }{4}\) ( 20.5 mm )²

A = 330.06 mm²

Next, we find the change in length of the specimen using young's modulus formula

E = σ/∈

E = P/A × L/ΔL

ΔL = PL/AE

P is force ( 46300 N), L is length ( 201 mm ), A is area ( 330.06 mm² ) and E is  elastic modulus (60.5 GPa) = 60.5 × 10⁹ N/m² = 60500 N/mm²

so we substitute

ΔL = (46300 N × 201 mm) / ( 330.06 mm² × 60500 N/mm² )

ΔL =  0.466 mm

Therefore, The amount by which this specimen will elongate in the direction of the applied stress is 0.466 mm

(b) The change in diameter of the specimen. Indicate an increase in diameter with a positive number and a decrease with a negative number.

Using the following relation for Poisson ratio

μ = -  Δd/d / ΔL/L

given that Poisson's ratio of the metal is 0.33

so we substitute

0.33 = -  Δd/20.5 / 0.466/201

0.33 = -  Δd201 / 20.5 × 0.466

0.33 = - Δd201  / 9.143

0.33 × 9.143 =  - Δd201

3.01719 = -Δd201

Δd = 3.01719 / - 201

Δd  = - 0.015 mm

Therefore, The change in diameter of the specimen is  - 0.015 mm

Answer:

Explanation:

sorry i dont know

ShopKey Pro presents repair information in a customized email template as well as auto repair software format or layout.

In regards to auto repair information tools, the solution that is known to be made available is the use of ShopKey® Pro with 1Search.

This is know  to be a kind of an exclusive auto repair software that helps to streamlines the search acts to bring closer a special  combination of OEM data as well as experience-based Real Fixes.

Therefore, based on the above, one can say that ShopKey Pro presents repair information in a customized email template as well as auto repair software format or layout.

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Inadequate nutrition, pollution-associated health disorders and communicable illnesses, poor sanitation and housing conditions, and linked health conditions are some of the primary health concerns caused by urbanization. Hence, a properly planned topography will prevent these negative concerns.

The drafting of plans for, as well as the control and management of, towns, cities, and metropolitan regions falls within the purview of urban planning. It tries to arrange sociospatial linkages at many levels of government and governance.

Urban planning can help to create more livable and desirable communities by designing for walkability, accessibility, and green spaces.

It can help to create more efficient and sustainable communities by promoting the use of public transportation, promoting mixed-use development, and designing for energy efficiency. This can help to reduce greenhouse gas emissions, reduce traffic congestion, and save energy.

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