an increase in sound level from 30 db to 50 db requires an increase in sound intensity by a factor of:

When looking at the viewing screen with a dark screen and a 2-mm-diameter hole, you would see a small, bright spot of light.

On the viewing screen, you would see a small, bright spot of light. Since the screen is dark and there is a 2-mm-diameter hole, only the light from the bulb passing through the hole will be visible. This creates a focused beam of light that appears as a spot on the screen.
To explain this further, when light passes through a small hole, it undergoes a process called diffraction. Diffraction causes the light to spread out and interfere with itself, creating a pattern of bright and dark regions. However, in this case, since the screen is dark and there are no other sources of light, only the light passing through the hole will be visible on the screen.
The size of the spot on the screen will depend on the size of the hole. In this case, with a 2-mm-diameter hole, the spot will be relatively small. The brightness of the spot will depend on the intensity of the light emitted by the bulb.
In summary, when looking at the viewing screen with a dark screen and a 2-mm-diameter hole, you would see a small, bright spot of light.

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Answer:

The bigger one. Ignoring air resistance, they will fall at the same speed, but the bigger one will hit first because it sticks out lower.

Explanation:

Rotational speed and tangential speed are related because tangential speed is directly proportional to the rotational speed and the radial distance from the axis of rotation.

The degree to which a metric reproduces the same performance under the same measurement conditions consistently is known as reliability.

Reliability is an important characteristic of any measurement or assessment tool, and it refers to the consistency and stability of the results obtained from that tool. A reliable metric should produce consistent results each time it is used to measure the same thing under the same conditions.

There are various methods to assess reliability, such as test-retest reliability, inter-rater reliability, and internal consistency reliability. These methods help to determine whether the same results are obtained consistently over time, across different raters or observers, or within a single assessment tool.

So, reliability is a critical aspect of any metric or assessment tool, as it ensures that the results obtained are accurate and consistent, which is necessary for making informed decisions and drawing valid conclusions.

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It took Steven 2 hours time to drive back home at an average speed of 66 mph. To solve this problem, we can use the formula: distance = speed x time

We know that Steven drove to the airport at an average speed of 44 mph for 3 hours, so we can calculate the distance he traveled: distance to airport = 44 mph x 3 hours = 132 miles
Now, to find out how long it took him to drive back home at an average speed of 66 mph, we can use the same formula: distance = speed x time

But this time, we know the distance (132 miles) and the speed (66 mph), and we want to find the time it took him to drive back home (let's call it "t").
distance from airport to home = 132 miles
speed = 66 mph
time = t

Plugging these values into the formula, we get: 132 miles = 66 mph x t
To solve for "t", we can divide both sides of the equation by 66 mph:
t = 132 miles ÷ 66 mph
t = 2 hours

Therefore, it took Steven 2 hours to drive back home at an average speed of 66 mph.

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The time taken for Marissa's car to accelerate is 0.86s.

Tme is the measure of the duration of an event. The S.I unit of time is seconds (s)

To calculate the time it takes Marissa's car to accelerete, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the time taken for Marissa's car to accelerate is 0.86s.

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To set up a good experiment to test whether hypothesis H is true or not, try to get evidence E such that there is as big a difference between P(E | H) and P(E | ~H) as possible. This means the correct option is d.

For a good experiment to test whether hypothesis H is true or not, it is necessary to gather the right evidence. This evidence should be such that there is as big a difference between P(E | H) and P(E | ~H) as possible.

P(E | H) and P(E | ~H) are the conditional probabilities of evidence E given hypothesis H and evidence E given not-H respectively. The difference between these two probabilities measures how well evidence E supports hypothesis H versus not H.

For example, suppose we want to test the hypothesis H: All dogs bark. To get evidence that there is as big a difference between P(E | H) and P(E | ~H) as possible, we can test this hypothesis by taking two groups of dogs. One group is the dogs that bark (group A) and the other group is the dogs that don't bark (group B).

Then, we can get evidence E, which is the number of dogs in group A that bark and the number of dogs in group B that bark. Using this evidence, we can calculate the conditional probabilities of evidence E given hypothesis H (P(E | H)) and evidence E given not-H (P(E | ~H)).

Finally, we can calculate the difference between P(E | H) and P(E | ~H). If this difference is large, then the evidence supports hypothesis H more than not H.

To set up a good experiment to test whether hypothesis H is true or not, it is necessary to gather the right evidence. This evidence should be such that there is as big a difference between P(E | H) and P(E | ~H) as possible.

For example, suppose we want to test the hypothesis H: All dogs bark. To get evidence that there is as big a difference between P(E | H) and P(E | ~H) as possible, we can test this hypothesis by taking two groups of dogs. One group is the dogs that bark (group A) and the other group is the dogs that don't bark (group B).

Then, we can get evidence E, which is the number of dogs in group A that bark and the number of dogs in group B that bark. Using this evidence, we can calculate the conditional probabilities of evidence E given hypothesis H (P(E | H)) and evidence E given not-H (P(E | ~H)).

Finally, we can calculate the difference between P(E | H) and P(E | ~H). If this difference is large, then the evidence supports hypothesis H more than not H.

Hence, it is important to get evidence that has a significant difference between P(E | H) and P(E | ~H) to set up a good experiment to test whether hypothesis H is true or not.

It is necessary to gather the right evidence to set up a good experiment to test whether hypothesis H is true or not.

Evidence E should be such that there is as big a difference between P(E | H) and P(E | ~H) as possible. The difference between these two probabilities measures how well evidence E supports hypothesis H versus not H. Therefore, option d is the correct answer.

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The maximum number of 6 AWG THW copper conductors permitted in a 1 1/4-inch RMC conduit nipple, 20 inches long, would be 7 conductors.

To determine the maximum number of 6 AWG THW copper conductors permitted in a 1 1/4-inch RMC (rigid metal conduit) conduit nipple, you need to consider the fill capacity of the conduit as per the National Electrical Code (NEC) guidelines. The fill capacity depends on the size of the conduit and the size of the conductors being used.

According to NEC Table C.9, the maximum fill capacity for a 1 1/4-inch RMC conduit is 0.40 square inches. This measurement represents the total cross-sectional area of the conductors that can be inside the conduit.

For 6 AWG THW copper conductors, you can refer to NEC Table 8, which provides the area per conductor. In this case, a 6 AWG conductor has an area of 0.0507 square inches.

To determine the maximum number of 6 AWG THW copper conductors, you divide the fill capacity of the conduit by the area per conductor. In this case:

Maximum fill capacity of 1 1/4-inch RMC conduit = 0.40 square inches

Area per conductor for 6 AWG THW copper = 0.0507 square inches

Maximum number of conductors = Fill capacity / Area per conductor

Maximum number of conductors = 0.40 / 0.0507

Maximum number of conductors = 7.89

Therefore, the maximum number of 6 AWG THW copper conductors permitted in a 1 1/4-inch RMC conduit nipple, 20 inches long, would be 7 conductors. However, it's important to note that local codes and regulations may impose additional requirements or limitations, so it's always best to consult the relevant electrical codes or a licensed electrician for precise calculations in a specific installation.

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Given:

The current density is,

a is a constant, and the radius of the wire is R.

To find:

The current in the wire

Explanation:

The current in the wire is,

We know,

So,

Hence, the required current is,

The focal length (in meters) of a lens  = 18.4 m

When a lens is focused at infinity, the focal length of the lens is discovered. We can determine the angle of view, or how much of the scene will be captured, and the magnification, or how big the individual elements will be, by measuring the focal length of the lens. A narrower field of view and a higher magnification result from a longer focal length.

Radius of curvature is 9.2 m.

A refractive index 1.2.

The focal length (in meters) of a lens  =

We know that the formula for  focal length:

focal length = 2 * radius of curvature

So,

Putting the value in the formula :

we get

focal length = 2 * 9.2

                    =  18.4 m

The focal length (in meters) of a lens  = 18.4 m

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Answer:

there is an option for uploading the pic of a diagram while posing any question on brainly. hope you use that feature of the app to upload graph of your question so that it can be well answered

Answer: It’s A!

Explanation: I took the test

To determine the radial acceleration of a point on the rim of the disk, we can use the formula: radial acceleration = radius × angular velocity squared. After simplifying this equation, we get the radial acceleration in the appropriate units.

Given that the radius of the disk is 8.00 cm and the disk rotates at a constant rate of 1200 rev/min, we need to convert the angular velocity from rev/min to rad/s.

1 revolution = 2π radians.

1 minute = 60 seconds.

angular velocity = (1200 rev/min) × (2π rad/rev) / (60 s/min).

Now, we can calculate the angular velocity in rad/s.

angular velocity = (1200 × 2π) / 60 rad/s.

radial acceleration = (8.00 cm) × [(1200 × 2π) / 60 rad/s]².

Simplifying this equation will give us the radial acceleration in the appropriate units.

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A 0.41 kg spike is hammered into a railroad tie with 1.4 m/s initial speed. They absorb 40.4% of its initial kinetic energy as internal energy, resulting in an increase of 0.164 J in their internal energy.

To solve this problem, we need to use the conservation of energy principle, which states that the total energy in a closed system remains constant. In this case, the initial kinetic energy of the spike is converted into internal energy of the spike and tie.

The initial kinetic energy of the spike is given by:

\(KEi = (1/2) \times m \times v^2\)

\(KEi = (1/2) \times 0.41 kg \times (1.4 m/s)^2\)

KEi = 0.4054 J

The internal energy gained by the spike and tie is given by:

\(\Delta E = KEi \times 40.4\%\)

\(\Delta E = 0.4054 J \times 0.404\)

ΔE = 0.164 J

Therefore, the increase in internal energy of the spike and tie is 0.164 J.

In summary, a 0.41 kg spike is hammered into a railroad tie with an initial speed of 1.4 m/s. The tie and spike absorb 40.4% of the spike's initial kinetic energy as internal energy. Using the conservation of energy principle, we calculate that the increase in internal energy of the tie and spike is 0.164 J.

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For moving an object from one side of a room to the other side of the room a force is needed to be applied to the object and the position of the object must be known. Thus, A and D are the correct options.

Motion is a phenomenon in which an object changes its position with respect to time. It is the distance or displacement covered by an object in a particular time period.

Newton's first Law states that a body at rest will stay at rest and a body in motion will remain in motion unless and until an external force is applied on it. Force is responsible for the displacement of an object from one place to another.

Direction is equally important in motion as force applied in the direction opposite to the motion can stop the motion while the force in the direction of motion can accelerate the motion.

Therefore, correct options are A and D. The force and position are important factors for the motion of an object.  

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The image is approximately 9.33 cm away from the mirror, on the object's side.

To determine the image location formed by a converging mirror, we can use the mirror equation:

1/f = 1/d_o + 1/d_i

where:

f is the focal length of the mirror,

d_o is the object distance (distance of the object from the mirror), and

d_i is the image distance (distance of the image from the mirror).

In this case, the focal length (f) is given as 7 cm, and the object distance (d_o) is 4 cm.

Plugging in the values into the mirror equation:

1/7 = 1/4 + 1/d_i

To find the image distance (d_i), we can solve for it:

1/d_i = 1/7 - 1/4

1/d_i = (4 - 7) / (4 * 7)

1/d_i = -3 / 28

Taking the reciprocal of both sides:

d_i = 28 / -3

d_i ≈ -9.33 cm

The negative sign indicates that the image formed by the converging mirror is virtual and located on the same side as the object.

Therefore, the image is approximately 9.33 cm away from the mirror, on the object's side.

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If λ occurs as an eigenvalue of A with multiplicity r, then there are r linearly independent eigenvectors associated with λ, and the geometric multiplicity of λ is equal to r.

Let A be an n × n matrix. An eigenvalue of A is a scalar λ such that there is a nonzero vector x satisfying the equation Ax = λx. This equation can be rewritten as the linear system (A − λI)x = 0, where I is the identity matrix. Nontrivial solutions to this equation exist if and only if the matrix A − λI is singular, which means that its determinant is zero. Thus, the eigenvalues of A are the roots of the polynomial equation det(A − λI) = 0, which is called the characteristic equation of A. The algebraic multiplicity of an eigenvalue is the number of times it appears as a root of the characteristic equation. The geometric multiplicity of an eigenvalue is the dimension of the eigenspace associated with that eigenvalue. The eigenspace of an eigenvalue λ is the set of all eigenvectors of A associated with λ, along with the zero vector.

The rank of A is the dimension of its column space, which is the span of its column vectors. The rank of A is equal to the dimension of the row space of A, which is the span of its row vectors. The rank of A is also equal to the number of nonzero singular values of A. If the rank of A is r, then the dimension of the nullspace of A is n − r. If A has r linearly independent eigenvectors associated with a particular eigenvalue λ, then the geometric multiplicity of λ is r. If the algebraic multiplicity of λ is greater than its geometric multiplicity, then there are not enough eigenvectors to form a basis of the eigenspace associated with λ, which means that A is not diagonalizable. If the algebraic multiplicity of λ is equal to its geometric multiplicity, then A is diagonalizable. If λ occurs as an eigenvalue of A with multiplicity r, then there are r linearly independent eigenvectors associated with λ, and the geometric multiplicity of λ is equal to r.

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Both the initial amount and the kind of gas play a role.  However, the pressure and the quantity of gas present also have a role in this relationship.

Charles' Law states that a gas's volume is directly proportionate to its temperature. However, the pressure and the quantity of gas present also have a role in this relationship. Hence, we would need to know the starting volume, pressure, and number of moles of a gas sample in order to calculate its volume at 50.0 °C. The type of gas would also be a role in deciding its final volume at 50.0 °C because different gases behave differently at various temperatures.  Ideal gas perfectly obeys the gas law. Thus, the correct answer to the question is Ideal gas.

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The magnitude of the force on the wire is 1.9 × 10⁻⁴ N. The direction of the current is 50° south of the west. 1.9×10 N⁻⁴, out of the Earth's surface is the correct option.

Length of the horizontal wire, L = 3.0 m

Current flowing through the wire, I = 6.0 A

Earth's magnetic field, B = 0.14 × 10⁻⁴ T

Angle made by the current direction with due west = 50° south of westForce on a current-carrying wire due to the Earth's magnetic field is given by the formula:

F = BILsinθ, where

L is the length of the wire, I is the current flowing through it, B is the magnetic field strength at that location and θ is the angle between the current direction and the magnetic field direction

Magnitude of the force on the wire is

F = BILsinθF = (0.14 × 10⁻⁴ T) × (6.0 A) × (3.0 m) × sin 50°F = 1.9 × 10⁻⁴ N

Earth's magnetic field is due north, the direction of the force on the wire is out of the Earth's surface. Therefore, the correct option is 1.9×10 N⁻⁴, out of the Earth's surface.

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Answer:

get help with your work

try understand your work

ask your teacher for assistance or class

or maybe cheat but understand the work first if you wanna

The angular speed of the disk is 16.95 radians/s.

The angular speed of a uniform density 9 kg disk of radius 0.20 m is mounted on a nearly frictionless axle is to be determined.

Mass of disk, m = 9 kg

Radius of disk, r = 0.20 m

Force applied, F = 37 N

Distance, s = 0.7 m

The moment of inertia of the disk is given byI = 1/2 mr²

Where,

m = mass of the disk

r = radius of the disk

I = 1/2 x 9 x (0.20)²

I = 0.18 kg m²

The work done on the disk by the applied force is given by W = FsW = 37 x 0.7W = 25.9 J

The work done is equal to the change in kinetic energy of the disk.

Therefore, the final kinetic energy of the disk can be given by1/2 I ω²

Where, ω = angular speed of the diskThe final kinetic energy of the disk is equal to the work done on the disk.

Therefore,1/2 I ω² = 25.9ω²

= 51.8/0.18ω²

= 287.8ω

= √287.8ω

= 16.95 rad/s

Therefore, the angular speed of the disk is 16.95 radians/s.

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Answer:

Oblique

Explanation:

I think that's the answer I was told this but forgot if this is the right answer if not then sorry

Answer:

1476 J

Explanation:

From the question,

Net Work done = Net force× distance moved by net force.

W' = (F-F')×d................... Equation 1

Where W' = Net work done, F = force applied, F' = Frictional force, d = distance moved.

Given: F = 150 N, F' = 37 N, d = 12 m

Substitute these values into equation 1

W' = (150-37)×12

W' = 123×12

W' = 1476 J.

hence the Net Work done by the object is 1476 J

The relative ability of a bonded atom to attract shared electron pairs is called its electronegativity. This ability increases as the size of the atom decreases because for a smaller atom the shared electrons will be closer to the nucleus.

A covalent bond consists of the mutual sharing of one or more pairs of electrons between two atoms. These electrons are simultaneously attracted by the two atomic nuclei.

Electronegativity is defined as the ability of an atom in a molecule to attract electrons to itself. The concept of an electronegativity scale for the elements was proposed by Pauling.

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Strength training increases muscular strength. It involves lifting weights, performing bodyweight exercises, or using resistance bands.

To develop muscular endurance, it is necessary to train the muscles for an extended period of time using a low load. This involves working with lighter weights and performing a high number of reps. Below is an example of a muscular strength and endurance routine:

Warm-up: Start with a 5-minute warm-up. This can be jogging, cycling, or any other form of light exercise.

Cool-down: End the workout with a 5-minute cool-down. This can be stretching or light jogging. A muscular strength and endurance routine requires dedication, consistency, and proper form. It is essential to follow a well-structured program, allowing time for rest and recovery.

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Answer:

I guess the answer is c the f am not wrong

Answer:

Osteologists are trained to read and translate a bone's story.

Explanation:

This rare skill provides information that helps us better understand ancient cultures, solve mysteries, and learn about animals. Being an Osteologist means you have a variety of job opportunities.

Answer:

A 1.5 metres per second squared B 0 C 6 0.5

b) 9m

Explanation:

a= v-a/t

a= acceleration measured in metres per second squared

v= final speed measured in metres per second

u= initial speed measured in metres per second

t= time measured in second

A

a=v-a/t

a= 3-0/2

a= 1.5 metres per second squared

Distance in a velocity time graph = area under

To calculate the distance in the first 4 seconds

You divide the graph into triangles and rectangles

Area A (triangle )= 1/2 × base × height

=1÷2 ×2×3

= 3m

Area B (rectangle)= L×B

=2×3

=6m

Area A + Area B= 3+6

= 9m

The correct answer of the question is P (type B is the 2nd hottest) , R (F is 4th in hottest) and Q (type K is second coolest).

Answer: i think its a bullfrog forgive me if im wrong i dont exactly know

Explanation:

Answer:

that is an African bullfrog

Answer:

770.1 m

Explanation:

From the question given above, the following data were obtained:

Velocity (v) = 45.3 m/s

Time (t) = 17 s

Displacement (d) =?

Velocity is defined according to the following formula:

Velocity = Displacement /Time

With the above formula, we can obtain the displacement of the ball as follow:

Velocity = Displacement /Time

45.3 = Displacement / 17

Cross multiply

Displacement = 45.3 × 17

Displacement = 770.1 m

Therefore the displacement of the ball is 770.1 m

Answer: 770.1     gravity multiplied by time