An impure sample of table salt that weighed 0. 8421 g when dissolved in water and treated with excess agno3 formed 2. 044 g of agcl. What percentage of nacl is in the impure sample?.

Answer:

14660.75 kJ.

Explanation:

We are given from the question above that the pressure inside is represented by this equation:

P = Po + C(1-(D1/D))(D1/D).

Thus, P = 100 + C (1 - 1/4) (1/4). Therefore, P  which is = 400 is;

400 = 100 + C (1 - 1/4) (1/4).

Hence, C = 1600. And the equation can be written as P = 100 + 1600 (1 - (D1/D))(D1/D).

The work done during the entire process, w = (work done during the process 1 to 2) + (work done duringbthe process 2 to 3 ).

Therefore, work done during the process 1 to 2 = P(V2 + V1) = 100( π/6 - 0).

{NB: V2 is gotten from π/6 × D^3. Where D^3 = 1. }

Hence, work done during the process 1 to 2 = 52.36 kJ.

So, the work done duringbthe process 2 to 3 ) is going to be the integration of PdV. Where P = 100 + 1600 (1 - (D1/D))(D1/D) and dV = π/2 D^2 dD. Taking the upper and the lower limit as 4 and 1 respectively.

After the integration (kindly check attached picture for the process) the work done duringbthe process 2 to 3  = 14.61 × 10^3 kJ.  

Therefore, The work done during the entire process, w = (work done during the process 1 to 2) + (work done duringbthe process 2 to 3 ).

The work done during the entire process, w = 52.36 kJ + 14.61 × 10^3 kJ.   = 14660.75 kJ.

The answer is :

3.02 X 10–19 J

Answer:

-400.3 kJ/mol

Explanation:

Answer:

0.67 atm

Explanation:

From the question,

Applying Boyles law

PV = P'V'......................... Equation 1

Where P = Initial Pressure of the sample of gas, P' = Final pressure of the sample of gas, V = Initial volume of the sample of gas, V' = Final volume of the sample of gas.

make P' the subject of the equation above

P' = PV/V'.................... Equation 2

Given: P = 10.0 L, V = 1.0 atm, V' = 15.0 L

Substitute these values into equation 2

P' = (10.0×1.0)/15.0

P' = 0.67 atm

Answer:

have one delocalised electron

Explanation:

The elements which are  present of left side of periodic table have similar chemical properties.

Periodic table is a tabular arrangement of elements wherein elements are arranged according to their atomic numbers. It consists of seven horizontal rows called periods  and eighteen vertical columns called groups .

Elements in the same group have similar chemical properties as they have same number of valence electrons. While, electrons in the same period have different valence electrons as electrons are added to same shell and hence have  a little variation in chemical properties.

It is called periodic as properties repeat after an interval of certain electronic configuration. Elements are divided in four blocks depending on their properties.

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Answer:

ffff

Explanation:

Answer: The pH is 9.09.

Explanation:

This question involves the hydrolysis of a salt into a weak acid and strong base.

The fastest solution is found by using the equation:

\(\text{pH} = \frac12 \ \text{pK}_w + \frac12 \ \text{pK}_a + \frac12 \log C\)

where C represents the concentration of the solution.

We have:

Ka = 1.34 x 10^-5, so pKa = -log(1.34 x 10^-5) = 4.873

Kw = 1.0 x 10^-14, so pKw = -log(1.0 x 10^-14) = 14.00

C = 0.20, so log(C) = log(0.20) = -0.70

Then,

\(\text{pH} = \frac12 (4.873) + \frac12 (14.00) + \frac12 (-0.70) = 9.09\)

A solution that uses only fundamental chemistry techniques can be found by considering the chemical reactions involved.

The salt \(\text{C}_2\text{H}_5\text{COONa}\) will completely dissolve in solution into its ions:

\(\text{C}_2\text{H}_5\text{COONa} \text{ (aq)} \rightarrow \text{C}_2\text{H}_5\text{COO}^- \text{ (aq)} + \text{Na}^+ \text{ (aq)}\)

This shows that \([\text{C}_2\text{H}_5\text{COO}^-] = [\text{C}_2\text{H}_5\text{COONa}] = 0.20 \text{ M}\).

When water is added, an acid-base reaction occurs:

\(\text{C}_2\text{H}_5\text{COO}^- \text{ (aq)} + \text{H}_2\text{O} \text{ (l)} \rightleftharpoons \text{C}_2\text{H}_5\text{COOH} \text{ (aq)} + \text{OH}^- \text{ (aq)}\)

Using a RICE (Reaction-Initial-Change-Equilibrium) table, we can write the following analysis:

0.20                       N/A                0                        0       (initial conc.)
- x                           N/A                + x                      + x    (change)
-------------------------------------------------------------------------
(0.20 - x)                N/A                 x                        x       (equilibrium)

Then, we can write the forward base-reaction constant:

\(\text{K}_b = \frac{[\text{C}_2\text{H}_5\text{COOH}][\text{OH}^-]}{[\text{C}_2\text{H}_5\text{COO}^-]} = \frac{(x)(x)}{0.20-x} = \frac{x^2}{0.20-x}\)

We have \(\text{K}_a = 1.34 \times 10^{-5}\) and we also know that \(\text{K}_w = \text{K}_a \times \text{K}_b\). It follows that:

\(\text{K}_b = \frac{\text{K}_w}{\text{K}_a} = \frac{1.0 \times 10^{-14}}{1.34 \times 10^{-5}} = 7.46 \times 10^{-10}\)

Since Kb is very small, we may assume that \((0.20 - x) \approx 0.20\). Then,

\(7.46 \times 10^{-10} = \frac{x^2}{0.20} \quad \rightarrow \quad x \approx \sqrt{0.20(7.46 \times 10^{-10})} = 1.22 \times 10^{-5}\)

Then,

\([\text{OH}^-] = x = 1.22 \times 10^{-5}\)

\(\text{pOH} = -\log(1.22 \times 10^{-5}) = 4.91\)

Finally,

\(\text{pH} = \text{pK}_w - \text{pH} = 14.00 - 4.91 = 9.09\)

\({ \qquad\qquad\huge\underline{{\sf Answer}}} \)

Here we go ~

Mass of 1 mole C - 12 atom = 12 g

So, mass of 1 carbon - 12 atom = ( 12 / 1 mole ) g

that is :

\(\qquad \sf  \dashrightarrow \: \cfrac{12}{6.022 \times 10 {}^{23} } \: \: g\)

[ since 1 mole = 6.022 × 10²³ ]

\( \qquad \sf  \approx2 \times 10 {}^{ - 23} \: \: g\)

Molarity :

Molarity is defined as " The number of moles of solute present in per litre of solution "

Molality :

Molality is defined as " Number of moles of solute present per kg mass of solvent "

As per the given reaction ~

\(\qquad \sf  \dashrightarrow \: Zn + 2\:H Cl \rightarrow ZnCl_2 + H_2\)

32.65 g of zinc reacted,

[ Number of moles of zinc reacted = mass of zinc reacted divided by its formula Weight ]

\(\qquad \sf  \dashrightarrow \: number \: \: of \: \: moles = \cfrac{32.65}{65.3} \: \: mol\)

\(\qquad \sf  \dashrightarrow \: number \: \: of \: \: moles = \cfrac{1}{2} \: \: mol\)

so, we can say that " half mole Zinc reacted with 1 mole of HCl to form half mole of Zinc chloride and half mole of Hydrogen gas "

And we already know that 1 mole of any gas occupies 22.7 litre volume at STP.

So, volume of Hydrogen gas Liberated :

\(\qquad \sf  \dashrightarrow \: \cfrac{1}{2} \times 22.7\)

\(\qquad \sf  \dashrightarrow \: 11.35 \: \: litres\)

The relationship between Molarity and molality can be expressed as :

\(\qquad \sf  \dashrightarrow \: M =\cfrac{ 1000(m \times d)}{1000+(m \times F)}\)

Terms :

\(\qquad \sf  \dashrightarrow \: M =\cfrac{ 1000(3 \times 1.110)}{1000+(3 \times 40)}\)

\(\qquad \sf  \dashrightarrow \: M =\cfrac{ 1000( 3.330)}{1000+120}\)

\(\qquad \sf  \dashrightarrow \: M =\cfrac{ 3330}{1120}\)

\(\qquad \sf  \dashrightarrow \: M =2.973 \: mol \: l {}^{ - 1} \)

The structure of Ester:

\(CH_3CH_2CH_2CH_2CH_2-C-O-CH_2CH_3\)

I

\(CH_3\)

An alcohol and a carboxylic acid react to form an ester, a type of chemical molecule. Esters are often used in a variety of common items including plastics, flavorings and fragrances. They often have a pleasant fruity or floral scent, which is what gives many fruits their distinctive aroma.

An alkyl group (R) is attached to one oxygen atom and a carbonyl group (C = O) is attached to another oxygen atom to form an ester structure. Alkyl or aryl groups can form alkyl groups.

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Answer:

The answer to your question is probably false

Answer:

I think the answer is false

False. The two's complement of an integer is not produced using the XOR (exclusive OR) opcode.

An integer's two's complement is created by flipping all of its bits, then adding one to the result. This can be done by adding 1 and the bitwise NOT operator ().

The XOR instruction performs the exclusive OR operation on each pair of corresponding bits of two operands. It is a bitwise logical operation. It is frequently used in programming for things like testing if two values are different or toggling a bit.

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The Coase theorem is an economic concept that suggests that, under certain conditions, private parties can efficiently resolve externalities through bargaining without the need for government intervention. It was developed by economist Ronald Coase.

First, property rights must be well defined, allowing individuals to negotiate and make agreements.

Second, transaction costs, such as the costs of gathering information and enforcing agreements, should be low.

Overall, the Coase theorem highlights the potential for private bargaining to efficiently resolve externalities when certain conditions are met.

It emphasizes the importance of well-defined property rights and low transaction costs in facilitating voluntary agreements between parties.

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Answer:

Charles's law, or the law of volumes, was found in 1787 by Jacques Charles.

Answer:

A solid's particles fit closely together. The forces between the particles are so strong that the particles can not move freely; they can only vibrate. This causes a solid to be a stable, non-compressible shape with a definite volume.

Explanation:

I honestly don't know if that's right...

Ethanolic fermentation, which is the process of converting sugars into ethanol and carbon dioxide by yeast, is primarily carried out by the yeast species known as zymogens. The correct answer is (B).

Zymomonas species are well-known for their ability to ferment sugars and produce ethanol. They are commonly used in the production of various alcoholic beverages, including beer, wine, and pulque. Option (A) clostridium, (C) leuconostoc, (D) lactobacillus, and (E) propionibacterium are not typically associated with ethanolic fermentation. Each of these microorganisms has different metabolic pathways and roles in various other fermentation processes, but they are not the main agents involved in ethanolic fermentation for beverage production. Hence the correct answer is (B).

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Answer:

C

Explanation:

The order of increasing size are electron, neutron, nucleus and atom.

The size of electron is the smallest among the given particles which followed by neutron that is bigger in size from electron but smaller than nucleus. Proton and neutron are located in the nucleus of an atom so it is bigger in size than neutron.

Atom is the largest among the given substances in which nucleus is present at the center and electrons are revolving around the nucleus in fixed orbits so we can conclude that electron is the smallest and atom is the largest particle.

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Answer: ≈ 67.4 g

Explanation:

A(t) = amount remaining in t years        = A0ekt, where A0 is the initial amount and k is a constant to                     be determined.   Since A(1690) = (1/2)A0 and A0 = 80,                   we have 40 = 80e1690k                  1/2 = e1690k                  ln(1/2) = 1690k                  k = -0.0004 So, A(t) = 80e-0.0004t  Therefore, A(430) = 80e-0.0004(430)                             = 80e-0.172                             ≈ 67.4 g

Answer:

Final temperature = 152.57K,

Pressure = 0.6907 bar.

dT/dt = - 1,151 K/s.

Explanation:

The first thing to do here is to write out the equation for mass balance as given below:

dN/dt = N -------------------------------------------------------------------------------------------(1).

N = P/T, then, substitute the values given in the question into:

d[p/T]/ dt = [- 4.5/28 × 8.314]/0.15 = - 8.9 × 10⁻⁵ bar/K.s.

Thus, there is the need to integrate, Integrate [p/T]f = 10/320 - 8.9 × 10⁻⁵ bar/K.s. ------------------------------------(2).

NB; fT = final temperature, fP = final pressure and iT = initial temperature.

Also, [ fT]³⁰/₈.₃₁₄/ [fP] = [iT]³⁰/₈.₃₁₄/ Pi] = [ 320]³⁰/₈.₃₁₄/ 10.

Therefore, [fT]³⁰/₈.₃₁₄ = 109.52 × 10⁶.

Final temperature=  [fP]³⁰/₈.₃₁₄ × 169.05.

Note that fP/ [fP]³⁰/₈.₃₁₄ × 169.05 = 10/320 - 8.9 × 10⁻⁵.

Therefore, [fP]¹ ⁻ ³⁰/₈.₃₁₄ = 0.7651.

Hence, Final temperature = 152.57K,

Pressure = 0.6907 bar

dT/ dt = N[RT]² / Cv . PV.

R = 30 - 8.314 = 21.86 J/mol K.

Then, the rate of change of the gas temperature at this time = dT/dt = - 1,151 K/s.

Answer:

Molar mass = 105 g/mol

Explanation:

Given data:

Mass of gas = 3.15 g

Pressure = 785 mmHg

Temperature = 20°C

Volume of gas = 750 mL

Molar mass of gas = ?

Solution:

Pressure = 785 mmHg (785/760 = 1 atm)

Temperature = 20°C (20+273 = 293 K)

Volume of gas = 750 mL (750 mL× 1 L/1000 mL = 0.75 L)

PV = nRT

R = general gas constant (0.0821 atm.L/mol.K)

1 atm× 0.75 L =  n×0.0821 atm.L/mol.K × 293 K)

0.75 atm.L = n× 24.06 atm.L/mol

n = 0.75 atm.L / 24.06 atm.L/mol

n = 0.03 mol

Molar mass of gas:

Molar mass = Mass / number of moles

Molar mass = 3.15 g/ 0.03 mol

Molar mass = 105 g/mol

Answer:

:)

Explanation:

Water (chemical formula: H2O) is a transparent fluid which forms the world's streams, lakes, oceans and rain, and is the major constituent of the fluids of organisms. As a chemical compound, a water molecule contains one oxygen and two hydrogen atoms that are connected by covalent bonds.

Answer:

H2O

Explanation:

Thats the formula :P

Explanation:

21. The given molecule for cracking is tetradecane.

On cracking it forms one mole of decane (C10H22) and two moles of ethene gas.

The chemical equation is shown below:

\(C_1_4H_3_0->C_1_0H_2_2+2C_2H_4\)

22. The essential condition for the formation of an ester is the reaction of alcohol and acid in presence of concentrated sulfuric acid.

Thus among the given options, the first option is the correct one.

23. Isomers of butanol are shown below:

It is 2-butanol.

The position of -OH group changes to the second carbon.

Answer:

\(H _{3}O {}^{ + } \)

Hydroxonium ion

In the context of atomic orbital (AO) wavefunctions, the terms "radial node" and "nodal plane" refer to different aspects of the wavefunction's behavior.

A radial node is a region in the AO wavefunction where the probability of finding an electron is zero along the radial direction. In other words, it represents a spherical shell where the electron is unlikely to be found. The number of radial nodes is determined by the principal quantum number (n) of the orbital. For example, the 2s orbital has one radial node, while the 2p orbital has no radial nodes.

On the other hand, a nodal plane is a flat plane within the AO wavefunction where the probability of finding an electron is zero along a particular direction. It represents a surface that divides the orbital into two regions of opposite phases. The number of nodal planes is determined by the angular quantum numbers (l and m) of the orbital. For example, the 2s orbital has no nodal planes, while the 2p orbital has one nodal plane (the xz or yz plane).

Radial nodes arise from the radial part of the wavefunction because they depend on the distance from the nucleus. The radial part determines the distribution of the electron density as a function of distance, and the nodes correspond to regions where the density drops to zero.

On the other hand, nodal planes arise from the angular part of the wavefunction because they depend on the orientation and shape of the orbital. The angular part describes the angular distribution of the electron density around the nucleus, and the nodal planes correspond to regions where the phase of the wavefunction changes sign.

In summary, radial nodes are related to the distance from the nucleus and arise from the radial part of the wavefunction, while nodal planes are related to the orientation and shape of the orbital and arise from the angular part of the wavefunction. The 2s orbital has one radial node and no nodal planes, while the 2p orbital has no radial nodes and one nodal plane.

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The present value of the given scenario can be determined by using the formula, PV = FV * e^(-rt), where PV is the present value, FV is the future value, r is the interest rate and t is the time in years.

Given that a large farm with a known reservoir of gas beneath the ground sells the gas rights to a company for a guaranteed payment at a rate of 1, 300e ^ (0.03t) dollars per year and an interest rate of 8% compounded continuously.

PV = FV * e^(-rt)PV = (1300/0.03) * e^(-0.08 * t)PV = 43333.33 * e^(-0.08 * t)The present value is represented by PV. The present value of the given scenario can be determined by using the formula, PV = FV * e^(-rt), where PV is the present value, FV is the future value, r is the interest rate and t is the time in years.

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To Find :

The STP moles of 67.2 L CO.

Solution :

We know, molar volume at STP is used to converted into moles by :

1 moles = 22.4 L STP

So, number of moles in 67.2 L CO is :

\(n=\dfrac{67.2}{22.4}\\\\n = 3 \ moles\)

Therefore, number of STP moles are 3.

Hence, this is the required solution.

A reducing chemical reaction adds an electron to the substrate.

Reduction is a term used to describe the yield of electrons, the accumulation of hydrogen, or the reduction of oxygen from the substrate.

When a reactant accumulates electrons during a reaction, it is called reduction. Reduction reactions include the addition of electrons to a substrate and the donor of the electrons is a reducing agent that itself brings oxidization. Therefore a reducing chemical reaction retains the addition of electrons to a substrate.

Oxidation-reduction (redox) reactions consist of the transfer of electrons between compounds while catabolic reactions are the type of reactions in which complex substances are split down into simpler units with the discharge of energy. Therefore these options are incorrect

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The belt of maximum solar energy input to earth swings back and forth through the tropics.

Solar energy is the energy derived from the sun, or rather, from the heat produced by sun. This heat/radiation is propagated in the form of electromagnetic radiations. The amount of solar radiation that reaches any given area on the Earth's surface is not constant - it fluctuates. Although, every location receives some sunshine during the course of a year. This radiation is captured using solar technology, which transforms it into useful energy for different purposes. Photovoltaics (PV) and concentrating solar-thermal power (CSP) are the two main solar technologies used. If we observe the movement of earth around the sun, we know that the tropics (around the equator) receive maximum sunlight throughout the year, wheres, the poles receive the minimum. Hence, The belt of maximum solar energy input to earth swings back and forth through the tropics.

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