An ideal heat engine absorbs 94.5 kj of heat and exhausts 78.8 kj of heat in each cycle. what is the efficiency of the engine?

Answers

Answer 1

The efficiency of the engine is 17%

The answers to this exercise do not depend on the engine being of the Carnot design. Any heat engine that intakes energy as heat (from, say, consuming fuel) equal to

\(|Q_{H} |=\)=94.5kJ and exhausts (or discards) energy as

heat equal to \(|Q_{L} |=\)78.8KJ

will have these values of efficiency ε and network W

(a) Equation 20-12 gives ε=1- \(|\frac{Q_{L} }{Q_{H} }|\) =1-0.8338624339 =0.17 =17%

What exactly does a Carnot engine do?

Leonard Carnot proposed the Carnot engine, a theoretical thermodynamic cycle. It calculates the maximum possible efficiency of a heat engine during the process of converting heat into work and, conversely, working between two reservoirs.

Carnot cycle definition

An ideal reversible closed thermodynamic cycle in which the working substance undergoes four successive operations: isothermal expansion to a desired point, adiabatic expansion to a desired point, isothermal compression, and adiabatic compression back to its initial state.If we define the Carnot factor more broadly as the ratio of an active volume to total volume, the condition = 1/2 means that half of the volume is "active."

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Related Questions

much like a battery these generate electricity from chemical events

Answers

The term you are looking for is "chemical battery". Chemical batteries work by converting chemical energy into electrical energy through a series of chemical reactions. These reactions take place within the battery's cells, which are composed of two electrodes and an electrolyte.

When the battery is connected to a circuit, the chemical reactions produce an electrical current that can be used to power devices. Chemical batteries are widely used in many applications, including consumer electronics, electric vehicles, and renewable energy systems. They are a crucial component of our modern technological society, and ongoing research is focused on developing more efficient and sustainable battery technologies to meet growing energy demands.

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I am stationary in a reference system but if my reference system is not an inertial reference system, then, relative to me, a system that is an inertial reference system must:.

Answers

I am stationary in a reference system but if my reference system is not an inertial reference system, then, relative to me, a system that is an inertial reference system must:

Option (b). move with constant velocity.

In an inertial reference system, objects either remain at rest or move with a constant velocity in a straight line. Since you are stationary in your non-inertial reference system, a system that is inertial would appear to move with a constant velocity relative to you.

An inertial reference system is a frame of reference in which a body remains at rest or moves with constant velocity unless acted upon by a force. In contrast, a non-inertial reference system is a frame of reference in which a body may appear to move even when no external forces are acting upon it due to the presence of fictitious forces.

Therefore, relative to an observer in a non-inertial reference system, an inertial reference system must move with constant velocity to be free from fictitious force.

Therefore Option (b) is correct.

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--The given question is incomplete, the complete question is:

"I am stationary in a reference system but if my reference system is not an inertial reference system, then, relative to me, a system that is an inertial reference system must:

a. remain at rest.

b. move with constant velocity.

c. be accelerating.

d. be none of the above."--

The 12-ft boom ab has a fixed end a. a steel cable is stretched from the free end b of the boom to a point c located on the vertical wall. if the tension in the cable is 406 lb, determine the moment about a of the force exerted by the cable at b.

Answers

The moment about a of the force exerted by the cable at b if the tension in the cable is 406 Ib is (2400j + 1440k) Ib -ft.

Write the coordinates of each point as follows:

A = (0i,0j,0k)

B= (12i,0j, 0k)

C = (0i, 4.8j,-8k)

Calculate the position vector of B with respect to A.

rAB= B - A

rAB =(12i,0j, 0k ) - ( 0i,0j,0k)

=(12i)ft

Calculate the position vector of cable C with respect to B.

rBC=C - B

rBC = (0i, 4.8j,-8k) - (12i,0j, 0k)

= (-12i+4.8j -8k) ft

Calculate the magnitude of BC.

IBCl = √(-12)^2 + (4.8)^2 +(-8)^2

=15.2 ft

Calculate the unit vector of C with respect to C.

unit vector of C with respect to C (Ucc) = rBC / IBCl

=(-12i+4.8j -8k) / 15.2

Represent the force BC in vector from.

TBC= TBC (Ucc)

TBC= (380 (-12i+4.8j -8k) )/ 15.2 lb

Calculate the moment about A.

MA = rAB x TBC

MA = (12i) x (380 (-12i+4.8j -8k) / 15.2

= (300i) x (-12i + 4.8j - 8k )

= 1440k - (-2400j)

MA= (2400j + 1440k ) lb -ft

Therefore, The moment about a of the force exerted by the cable at b = (2400j + 1440k) Ib -ft.

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calculate the time taken to raise the temperature of 1.5 kg of water in a kettle from 15°C to 100°C given that specific heat capacity of water is 4200 J/kg/K and the heater is rated 250V , 2kW​

Answers

Answer:

270 s or 4.5 min

Explanation:

First find the amount of heat needed:

q = mCΔT

q = (1.5 kg) (4200 J/kg/K) (100 − 15) K

q = 535,500 J

q = 535.5 kJ

Power is energy per time.

P = E / t

2 kW = 535.5 kJ / t

t = 270 s

Use the drop-down menu to choose the type of thermal energy transfer shown at each point in the image. A: B:

Answers

Answer:

ANSWER IS A CONVECTION

B CONDUCTION

Point A heat transfer as steam is type of a convection heat transfer

Point B a source is the type of conduction heat transfer

What is conduction and convection heat transfer ?

Conduction = It is a process of heat transfer in which energy is transferred between successive molecules For example If we put the one end of the spoon to the boiling water then other end also become hot due to conduction.

Convection = It is type of heat transfer in which the heat flows due to movement of molecules or convection currents. convection heat transfer takes place in water and gases.

Just like this at point B the heat is transferred from one molecule to other which is conduction.

And point A heat transferred from steam which is convection as explained in above definition.

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Alejandro has collected over 35 studies focusing on the impact of vitamin C on a person's cold duration. He hopes to combine these findings and draw a general conclusion regarding the usefulness of the vitamin. Alejandro is using the statistical tool of:

Answers

Since Alejandro hopes to combine the findings from the collected studies and draw a general conclusion regarding the subject, he is using statistical tool of inference.

There are basically 2 types of statistical tools:

Descriptive statistical toolsInferential statistical tools

Descriptive tools are used to describe data. They include the use of tables, graphs, measures of dispersion, measures of central tendencies, etc.

Inferential tools are used to deduce conclusions from data. They include measures of significant differences, probability, correlation and regression, etc.

In this case, Alejandro would need to subject the data collected from the 35 studies to inferential statistical analysis tools in order to be able to make relevant conclusions.

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Please help ASAP !!

Explain how genetic variation is an important part of natural selection.

Please help ASAP !!Explain how genetic variation is an important part of natural selection.

Answers

Genetic variation can be bad or good to an organism . If it affects positively then, the organism can have more adaptable features to survive in the environment. For those in which worse genetic variations are happens cannot survive and will given out the way to the fittest to live.

What  are genetic variations?

Genes are the basic hereditary material in living things. Genes from the parent are inherited to their offsprings. Genes undergo variations or mutations by some internal factors. These can produce both good and bad results.

The given passage can be completed as follows:

Natural selection is defined as a process in which organisms that do will in an environment pass their genes on next generation. Over time, these genes can become more common in a population.

However, natural selection doesn't work in all situations. It works only when there are variations within the population. Some individual are more suited to the environment. This means that they are  better able to survive or reproduce. There must be variations in the genes.

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Iron
4 Fe
+ Oxygen → Rust
302
2Fe2O3
*
If 100g iron reacts with 33g of oxygen, what is the mass of the products?

Answers

Answer:

110 grams

Explanation:

The given chemical equation is

\(4Fe+3O_2\rightarrow 2Fe_2O_3\)

\(\Rightarrow 2Fe+1.5O_2\rightarrow Fe_2O_3\)

2 moles of Iron, Fe, react with 1.5 moles of oxygen, \(O_2\), to produce 1 mole of rust.

Or, 2x56=112 grams of Iron, Fe, reacts with 1.5x32=48 grams of oxygen, \(O_2\), to produce 112+48=160 grams of rust.

[As the mass of 1 mole of Fe is 56g and the mass of 1 mole of \(O_2\) is 32g]

The given mass of Iron, Fe, is 100 g.

The given mass of the oxygen, \(O_2\) is 33 g.

Since 48 grams of oxygen required 112 grams of iron to react completely.

So, 1 gram of oxygen required 112/48 grams of iron to react completely.

So, 33 grams of oxygen required (112/48)x33=77 grams of iron to react completely.

Here, the availability of oxygen is less, so, the oxygen in the limiting agent.

So, the 33g of oxygen (reactant) will react with 77 g of iron (reactant) to produce 33+77=110 g of rust (product) as by the law of conservation of mass the mass of the product is the sum of masses of all the reactant. The remaining iron will remains be unreacted.

3.26 a football is kicked at an angle of 30 degrees with a speed of 20 m/s. To the nearest 5m, how far will the ball travel?
A 15m
b 25 m
C 35 m
D 45 m

Answers

The ball will travel 40 m, which is an option (D).

We can use the range formula to determine how far the football will travel:

\(R = (v^2 / g) * sin(2 \theta)\)

where R is the range, v is the initial velocity, g is the acceleration due to gravity, and θ is the angle of launch.

Substituting the given values, we get:

\(R = (20 m/s)^2 / (2 * 9.81 m/s^2) * sin(2*30^o)\)

R = 40 m / (2 * 0.5)

R = 40 m / 1

R = 40 m

Rounded to the nearest 5m, the ball will travel 40 m, which is an option (D).

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12 A car travels in a straight line at speed v along a horizontal road. The car moves
against a resistive force F given by the equation
F = 400+kv²
where F is in newtons, v in ms-1 and k is a constant.
At speed v = 15ms-1, the resistive force F is 1100 N.
a
Calculate, for this car:
i the power necessary to maintain the speed of 15ms-¹,
ii the total resistive force at a speed of 30 ms-¹,
iii the power required to maintain the speed of 30ms-¹.

Answers

Answer:

i) Power = Force * Velocity = 1100 * 15 = 16500 W = 16.5 kW(ii)  Find the value of k first: F = 400 + k(15^2)                                              k = 28/9    F = 400 +(28/9)(30^2) = 320

Explanation:

a. The power necessary to maintain the speed of 15ms^-1 can be found using the equation for power, P = Force * velocity, where P is in watts, force is in newtons and velocity is in meters per second. Substituting the values given in the question, we get:

P = (400 + k * 15²) * 15
P = (400 + 11250) * 15
P = 11650 Watts

Therefore, the power necessary to maintain the speed of 15ms^-1 is approximately 11650 Watts.

b. The total resistive force at a speed of 30ms^-1 can be found by substituting 30 for v in the force equation:

F = 400 + k * 30^2

F = 12000 N

Therefore, the total resistive force at a speed of 30ms^-1 is approximately 12000 N.

c. The power required to maintain the speed of 30ms^-1 can be found using the same equation as in part a:

P = (400 + k * 30^2) * 30
P = (1500 + 600000) * 30
P = 625000000 Watts

Therefore, the power required to maintain the speed of 30ms^-1 is approximately 625000000 Watts. This is a very large amount of power and would require a significant amount of energy to maintain.


please help and seriously answer all questions :)) your help will be highly appreciated:)

1. What force is necessary to stretch an ideal spring with a spring constant of 125 N/m by
35 cm?

2. A spring with a spring constant of 650. N/m is used for a scale to weigh fish. What is the mass of a fish that would stretch the spring by 7.55 cm from its normal length?

3. A spring in a pogo-stick is compressed 16cm when a 43kg girl stands on it. What is the spring constant for the pogo-stick spring?

4. A spring is connected to a wall and a horizontal force of 80.0 N is applied. It stretches 28cm, what is its spring constant?

5. A spring stretches 8.0 cm when a 16 N force is applied. How far does it stretch when a 23 N is applied?

6. A 7.3 kg mass is placed on a spring with a spring constant of 36 N/cm. How much does this stretch the spring?

7. An elastic cord is 80cm long when it is supporting a mass of 15. kg hanging from it at rest. When an additional 5.0 kg is added, the cord is 82.5 cm long. What is the spring
constant?

8. What is the original length of the cord (with no mass) in question 7?

9. A spring with a spring constant of 50. N/m is hanging from a stand. A second spring with a spring constant of 100. N/m is hanging from the first spring. How far do they stretch if a 0.58 kg is hung from the bottom spring?

10. What is the spring constant of the system of springs in question 9?


please help and seriously answer all questions :)) your help will be highly appreciated:)

Answers

1. Force  necessary to stretch an ideal spring with a spring constant of 125 N/m by 35 cm is 437.5 N.

2. The mass of a fish that would stretch the spring by 7.55 cm from its normal length is 5.10 kg.

3. Spring constant is 267.94 N/m.

4. Spring constant is 285.71 N/m.

5. Distance will be 0.115 m.

6. Distance will be 1.986 m.

7. Spring constant is calculated to be 183.38 N/m.

8. Original length becomes 80 cm.

9. Distance covers to be 0.1924 m.

10. Equivalent spring constant becomes 150 N/m

1. The force necessary to stretch the spring can be calculated using Hooke's law, which states that F = kx, where F is the force applied, k is the spring constant, and x is the displacement from the equilibrium position.

Thus, F = kx

F = (125 N/m)(0.35 m)

F = 43.75 N.

2. Using Hooke's law again, we have

F = kx

F = (650 N/m)(0.0755 m)

F = 49.98 N.

This force is equal to the weight of the fish, so we can find its mass by dividing by the acceleration due to gravity:

m = F/g

m = 5.10 kg.

3. We can use Hooke's law once more to find the spring constant:

k = F/x

k = (43 kg)(9.81 m/s²)/(0.16 m)

k = 267.94 N/m.

4. Hooke's law gives us k = F/x

k = (80 N)/(0.28 m)

k = 285.71 N/m.

5. We can use Hooke's law to set up a proportion: F1/x1 = F2/x2, where F1 and x1 are the initial force and displacement, and F2 and x2 are the new force and displacement. Solving for x2, we get

x2 = (F2/F1)x1

x2 = (23 N/16 N)(0.08 m)

x2 = 0.115 m.

6. Hooke's law gives us F = kx = (36 N/cm)(0.073 m) = 2.628 N. This is the force required to stretch the spring by 1 cm, so the total displacement is

x = (7.3 kg)(9.81 m/s²)/(36 N/cm)

= 1.986 m.

7. We can use Hooke's law to set up an equation: mg = kx, where m is the mass, g is the acceleration due to gravity, and x is the displacement from the equilibrium position. Solving for k, we get

k = mg/x

k = (15 kg)(9.81 m/s²)/(0.80 m)

k = 183.38 N/m.

8. The original length of the cord is simply the length when no mass is attached, so it is 80 cm.

9. The total force on the bottom spring is the sum of the weights of the two springs and the mass, so

F = (0.58 kg)(9.81 m/s²) + (50 N/m + 100 N/m)(x), where x is the displacement of the two springs together. Using Hooke's law, we can write this as F = 19.24 N + 150 x.

Setting this equal to kx and solving for x, we get

x = F/(k1 + k2)

x = (19.24 N)/(50 N/m + 100 N/m)

x = 0.1924 m.

10. The spring constant of the system of springs is simply the sum of the individual spring constants, so

k = k1 + k2

k = 50 N/m + 100 N/m

k = 150 N/m.

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The cornering performance of an automobile is evaluated on a skid pad, where the maximum speed a car can maintain around a circular path on a dry, flat surface is measured. Then the magnitude of the centripetal acceleration, also called the lateral acceleration, is calculated as a multiple of the free-fall acceleration g. Along with the height and width of the car, factors affecting its performance are the tire characteristics and the suspension system. A Dodge Viper GTS-R can negotiate a skid pad of radius 156 m at 139 km/h. Calculate its maximum lateral acceleration from these data to verify the corresponding entry in Table 3.1.

Answers

The cornering performance of an automobile is evaluated on a skid pad, where the maximum speed a car can maintain around a circular path on a dry, flat surface is measured. the maximum lateral acceleration of the Dodge Viper GTS-R on the skid pad is approximately 9.54 m/s^2.

To calculate the maximum lateral acceleration of the Dodge Viper GTS-R, we need to convert the speed from km/h to m/s and then use the formula for centripetal acceleration:

a = v^2 / r

where:

a = centripetal acceleration

v = velocity (in m/s)

r = radius of the circular path

First, let's convert the speed from km/h to m/s:

139 km/h = (139 * 1000) / 3600 = 38.61 m/s

Now we can calculate the centripetal acceleration:

a = (38.61)^2 / 156

Calculating this value gives:

a ≈ 9.54 m/s^2

Therefore, the maximum lateral acceleration of the Dodge Viper GTS-R on the skid pad is approximately 9.54 m/s^2.

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A car traveling initially at 7.35 m/s acceler-
ates at the rate of 0.824 m/s² for 2.09 s.
What is its velocity at the end of the accel-
eration?
Answer in units of m/s.

Answers

Answer:

\(v_f=9,07~m/s\)

Explanation:

Constant Acceleration Motion

It's a type of motion in which the velocity of an object changes uniformly in time.

Being a the constant acceleration, vo the initial speed, vf the final speed, and t the time, the following relation applies:

\(v_f=v_o+at\)

The car initially travels at vo=7.35 m/s and accelerates at a rate of \(a=0.824~m/s^2\) during t=2.09 s.

The final velocity is:

\(v_f=7.35+0.824*2.09\)

\(\mathbf{v_f=9,07~m/s}\)

Ou have not yet been cleared for the approach, but you are being vectored to the ils approach course. it is clear that you will pass through the localizer course unless you take action. you should a. continue as assigned and query atc. b. turn outbound and complete the procedure turn. c. turn inbound and join the final approach course.

Answers

let us break down the options given.

Option A suggests continuing with the assigned course and querying ATC. This is a good option, especially if there is uncertainty about whether or not clearance will be given. It is important to always follow ATC instructions and remain in communication with them.

Option B suggests turning outbound and completing the procedure turn. This may be a viable option if there is enough distance to complete the turn and return to the localizer course before crossing it. However, it is important to consider the timing of this turn and to ensure that it will not interfere with other aircraft in the vicinity.

Option C suggests turning inbound and joining the final approach course. This may be the best option if clearance for the approach is imminent. However, it is important to ensure that the aircraft is properly configured for the approach and that the necessary approach procedures are followed.

In conclusion, the best course of action may depend on the specific situation and factors such as timing and proximity to other aircraft. It is important to stay alert and communicate with ATC to ensure a safe and successful approach.

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3. The pressure at the bottom of the ocean is great enough to crush submarines with steel walls that are 10 centimeters thick. Suppose a submarine is at a depth of 1,000 meters. The weight of water above each square meter of the submarine is 9,800,000 newtons.

Answers

Answer:

just awnsered this one your awnser is the the second option

Answer:

answer one

Explanation:

Nuclei decay from a more stable form to a less stable form.Question 9 options:TrueFalse

Answers

ANSWER

False.

EXPLANATION

In radioactive decay (or nuclei decay), an unstable nucleus emits radiation into a nucleus that is table and has less energy and a lower mass.

Therefore, nuclei decay from a less stable form to a more stable form.

The answer is false.

Mr. Rosa’s student has a backpack with a density of 30g/mL. How much mass does the backpack have if it takes up 12.3 cm cubed of space?
Known:
Unknown:
Plug it in:
Answer:

Answers

Answer:

m = 369 grams

Explanation:

Given that,

The density of backpack, d = 30 g/mL

The volume of the backpack, V = 12.3 cm³

We need to find the mass of the backpack. The density of an object is given by :

\(d=\dfrac{m}{V}\\\\m=d\times V\\\\m=30\times 12.3\\\\m=369\ g\)

So, the mass of the backpack is 369 grams.

Identify the primary effect of each situation on capillary forces. Choose one for each of the following.
a. Increasing the surface tension of the liquid
b. Decreasing the contact angle between the liquid and solid surface
c. Increasing the viscosity of the liquid
d. Decreasing the temperature of the liquid

Answers

The primary effect of increasing the surface tension of the liquid is to increase the capillary force. Capillary forces arise due to the combined effects of adhesion and cohesion

When the surface tension of the liquid increases, the capillary rise will increase. It is because the increase in surface tension leads to an increase in the force that pulls the liquid upwards in a tube. is as follows;If you place a capillary tube in a beaker filled with water, the water surface inside the tube rises slightly higher than the level outside the tube.

This rise in water level is called capillary rise. The capillary rise is caused by the attraction between the molecules of the water and the molecules of the glass tube.This attraction is called capillary force or capillary action. The capillary force is due to the combined effect of adhesive and cohesive forces. The adhesive force is the attraction between the molecules of the liquid and the molecules of the solid surface, while the cohesive force is the attraction between the molecules of the liquid.

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What describes the motion of atoms in a gas?
O Atoms in a gas are locked in place.
O Atoms in a gas can move slightly.
O Atoms in a gas move about freely.
O Atoms in a gas cannot be described.

Answers

Answer:

O Atoms in gas can move freely

Explanation:

Depends on where it is going please follow me

Answer:

its option C

Explanation:

just took it

Please help ASAP!!
The velocity-time graph of a particle moving in a straight line is shown in a figure. Find the distance travelled by the particle in the time interval t = 0 and t= 10 s.

Please help ASAP!!The velocity-time graph of a particle moving in a straight line is shown in a figure.

Answers

Answer:

40 m

Explanation:

The area under v-t graph gives the distance travelled by the particle.

Distance = area of ΔOBC + area of ΔCDE + area of ΔEFG

\(=\dfrac{1}{2}\times 4\times 10+\dfrac{1}{2}\times 2\times 10+\dfrac{1}{2}\times 4\times 5\\\\=40\ m\)

So, the distance travelled by the particle in the time interval t = 0 and t= 10 s is equal to 40 m.

During photosynthesis, ___________ energy is converted into ____________ energy.

Answers

Answer:

Answer is radiant and chemical.

Hope this help:)

Sry if wrong

Consider the polynomial

() = −0. 14 − 0. 153 − 0. 52 − 0. 25 + 1. 2

The true value of its derivative at x=0. 5 is ′

(0. 5) = −0. 9125. Use backward, forward, and centered

first finite differences to estimate the derivative numerically if the step size ∆ = 0. 25, and determine

the percent error between the true value and each of the estimated values (percent error is given by

= −


converted to a percentage. ) What value of ∆ would you have to use for the backward and forward

finite differences to get the same percent error as the centered finite difference (hint: it should be less

than 0. 25. )

Answers

The backward finite difference method for estimating the derivative at x=0.5 is:

(f(0.5) - f(0.25)) / (0.5 - 0.25) = (-0.14 - (-0.4025)) / (0.5 - 0.25) = 0.2625 / 0.25 = 10.5

The percent error between this estimate and the true value is:

|(10.5 - (-0.9125)) / (-0.9125)| * 100% = |11.4125 / (-0.9125)| * 100% = 12.48%

The forward finite difference method for estimating the derivative at x=0.5 is:

(f(0.75) - f(0.5)) / (0.75 - 0.5) = (-0.6275 - (-0.14)) / (0.75 - 0.5) = -0.4875 / 0.25 = -1.95

The percent error between this estimate and the true value is:

|(-1.95 - (-0.9125)) / (-0.9125)| * 100% = |-1.0375 / (-0.9125)| * 100% = 1.14%

The centred finite difference method for estimating the derivative at x=0.5 is:

(f(0.75) - f(0.25)) / (0.75 - 0.25) = (-0.6275 - (-0.4025)) / (0.75 - 0.25) = -0.225 / 0.5 = -0.45

The percent error between this estimate and the true value is:

|(-0.45 - (-0.9125)) / (-0.9125)| * 100% = |0.4625 / (-0.9125)| * 100% = 0.51%

To get the same percent error as the centred finite difference, we would have to use a step size of ∆ = 0.125.

This is because a smaller step size means a smaller difference between the estimates and the true value, and therefore a smaller percent error.

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the standard hydrogen peroxide volume used with permanent haircolor is

Answers

The standard volume of hydrogen peroxide used with permanent hair color is typically 20 volume (6%).

The standard volume of hydrogen peroxide used with permanent hair color is typically 20 volume (6%). It is important to note that different hair color brands or formulations may offer different volumes of hydrogen peroxide options, so it is always advisable to refer to the specific instructions and recommendations provided by the hair color manufacturer.

The percentage value, in this case, 6%, indicates the weight of hydrogen peroxide present in the formulation. In a 20 volume hydrogen peroxide solution, 6% of the total weight is hydrogen peroxide, while the remaining 94% consists of other components, such as water, stabilizers, and conditioners.

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Highlight the correct answer.

A.) An object with more mass has more/less gravitational force than an object with a smaller mass.

B.) Objects that are closer together have more/less of a gravitational force between them than objects that are further apart.

Answers

The correct answer is B. According to Newton's law of universal gravitation, the gravitational force between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

In simpler terms, as objects get closer together, the gravitational force between them increases.

When the distance between two objects decreases, the denominator of the equation (distance squared) becomes smaller, resulting in a larger force. Conversely, when the distance increases, the denominator becomes larger, resulting in a smaller force.

It is important to note that the mass of an object does not directly affect the strength of the gravitational force between two objects. However, a higher mass will lead to a greater gravitational force when compared to a lower mass, but only because the force is being exerted on a more massive object. The mass of an individual object doesn't directly affect the gravitational force it experiences from another object. option B

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What is angular momentum called?.

Answers

The rotational equivalent of linear momentum, angular momentum, is also known as Rotational Momentum or Moment of Momentum.

What is angular momentum?

Angular momentum is the rotational equivalent of linear momentum in physics. It is an important physical quantity because it is a conserved quantity—in a closed system, the total angular momentum remains constant. Both the direction and magnitude of angular momentum are conserved. The property of any rotating object given by moment of inertia times angular velocity is defined as angular momentum. It is the property of a rotating body determined by the product of the rotating object's moment of inertia and angular velocity. Angular Momentum is defined as the property of any rotating object given by the product of the rotating object's moment of inertia and angular velocity. It is a vector with both magnitude and direction.

Here,

Angular momentum, which is the rotational equivalent of linear momentum, is also known as Rotational Momentum or Moment of Momentum.

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What is thermodynamics?
a) the way energy changes
b) the classification of energy
c) the movement of energy
d) the movement of heat

Answers

Answer:

I think it is D

Explanation:

Answer:

D :D lol

Explanation:

A ball in a simple pendulum is tied to a string and pulled up to the side 15 cm above its lowest position and then starts with an initial speed of 0.5 m/s. What will be its speed when it reaches the bottom? (2.5 point)

Answers

Answer:

1.786m/s

Explanation:

We are given the following the following

Initial speed u = 0.5m/s

initial distance S1 = 15cm = 0.15m

Final distance = 0m

Required

Final speed v

Using the equation of motion;

v² = u²+2gS

v² = 0.5²+2(9.8)(0.15)

v² = 0.25+2.94

v² = 3.19

v = √3.19

v = 1.786m/s

Hence  its speed when it reaches the bottom is 1.786m/s

While rolling on the pool table, ball X has 16.00 J of kinetic energy. It collides with identical ball Y and ball X stops, but ball Y moves on with 15.75 J of kinetic energy. What causes the loss of energy?

Answers

Inelastic collision and a host of other factors causes the loss of energy.

What is kinetic energy?

Kinetic energy of an object is the energy that it possesses due to motion.

It can be defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. When it has gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes.

In an inelastic collision which is the case of ball X and Y, the kinetic energy of the system is not conserved. The energy that you find lost has been dissipated as other forms of energy. This can be heat, friction, vibrational energy transferred to atoms of the colliding particles, energy lost to deform the atomic structure etc.

In conclusion, the inelastic collision nature of the two balls results in the loss of energy through different forms.

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Select the false statement. Scientific models are:

A. Designed to assist in developing intuition about the physical process being represented.

B. Allow for logical and objective representations of physical processes.

C. Tend to be simplified representations of reality.

D. Must be implemented using a computer.

Answers

D. Must be implemented using a computer.

It is possible to make scientific models without computers and/or other technology.

Answer:

D.

Explanation:

thnks mark me brainliest

in what direction must you pull on the third rope to keep the knot from moving? pearson

Answers

In order to keep the knot from moving, you must pull on the third rope in the direction of the loop closest to the end of the rope.

Here, correct answer will be

This will tighten the knot and secure the rope in place. As the rope is pulled, the loop that is closest to the end of the rope should be gradually tightened.

This is because the tension on the rope will ensure the knot remains in place, preventing any unwanted movement.

Pulling on the third rope in the direction of the loop closest to the end of the rope will ensure the knot remains secure and does not move.

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