An FM radio station broadcasts at a frequency of 100 MHz. The period of this wave is closest to 10 ns 1 ns 10 us 100 ns
Answers
The period of the FM radio wave with a frequency of 100 MHz is closest to 10 ns.
The period of a wave is the time it takes for one complete cycle to occur. It is the reciprocal of the frequency. In this case, the FM radio station broadcasts at a frequency of 100 MHz, which means it undergoes 100 million cycles per second. To calculate the period, we divide 1 second by the frequency. In this case, the period is approximately 1/100 million seconds, which is equal to 10 ns (nanoseconds).
A nanosecond is one billionth of a second, and it represents a very short period of time. This short period is necessary for the FM radio wave to oscillate at such a high frequency. The wave completes one cycle every 10 ns, meaning it repeats its pattern 100 million times in one second. This rapid oscillation allows the transmission and reception of audio signals with high fidelity. Therefore, the period of the FM radio wave with a frequency of 100 MHz is closest to 10 ns.
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Related Questions
A baby elephant trots in a straight line along river. The horizontal position of the elephant in meters over time is shown below. Questions: 1. What is the displacement of the elephant between 8 s and 24 s ?2. What is the distance traveled by the elephant between 8s and 24s?
Answers
looking at the graph,
1) Displacement includes direction
Displacement from 8s to 16s = 15 - 6 = 9
Displacement fbetween 16s and 24s = 0 - 15 = - 15
Displacemet between 8s and 24s = 9 - 15
Displacemet between 8s and 24s = - 6m
2)
Distance does not include direction
from 8s to 16s,
distance travelled = 15 - 6 = 9 m
From 16s to 24s,
distance travelled = 15 - 0 = 15
Total distance between 8s and 24s = 9 + 15
Total distance between 8s and 24s = 24 m
In the drawing above, what is vector r?
Write the algebraic equation for the vector addition shown above.
Answers
(a Vector r represents the sum of the two vectors x and y.
(b) The algebraic equation for the vector addition shown is r² = x² + y²
What is the resultant of the vectors?(a) The resultant of the vectors is the sum of the two vectors x and y which is given by vector r.
So vector r represents the sum of the two vectors x and y.
(b) The algebraic equation for the vector addition shown is determined by applying Pythagorean theorem as follows;
r² = x² + y²
where;
r is the resultant of the vectorsx represents one of the vectorsy represents one of the vectorsLearn more about resultant of vectors here: https://brainly.com/question/28047791
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Why we need football?
Answers
Answer:
bc we play when we are bored and some people use it as a tradition to play on thanksgiving
When you ride your bike around a corner at 10 m/s, you are accelerating?
Answers
When you ride your bike around a corner at 10 m/s, you are accelerating. Acceleration is caused by any forces. Sliding friction keeps you in the seat when a car goes around a corner. If you throw a ball into the air, Earth exerts a force on the ball.
Answer:
yes because acceleration is a vector quantity and as u turn around a corner you are changing direction.
Explanation:
which of the following statements about stars is true?; if the sun is white-yellow, which of the following is a reasonable approximation of its temperature?; immediately above the sun's photosphere is the _______, which is the sun's lower atmosphere.; which of the following statements about the sun is true?; which of the following lists stars in order of increasing size?; betelgeuse star
Answers
From around 6500 K at the bottom to 4000 K at the top, the photosphere's temperature changes (11,000 and 6700 degrees F, 6200 and 3700 degrees C). Granulation covers a large portion of the photosphere.
The results of these many techniques indicate that the Sun's surface actually has a temperature of about 5,800 kelvin (9,980 degrees Fahrenheit [5,520 degrees Celsius]). The photosphere contains areas of darkness known as sunspots, where the temperature is comparatively lower—about 3800K. The photosphere is therefore the layer that is the coldest. It is 15 million K inside the sun (27 million degrees Fahrenheit). It is 5780 K at the surface (9900 degrees Fahrenheit).
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in the 1920s, the development of practical radio communication was furthered by select one: a. the theory of modulation. b. the use of vacuum tubes. c. its ability to receive more than just simple pulses. d. both the theory of modulation and the use of vacuum tubes. e. all these answers are correct.
Answers
The correct answer is d. both the theory of modulation and the use of vacuum tubes.
In the 1920s, the development of practical radio communication was furthered by both the theory of modulation and the use of vacuum tubes. Modulation is the process of varying one or more characteristics of a periodic waveform, called the carrier signal, with a modulating signal that typically contains information to be transmitted.
It enables the transmission of audio and other forms of information, such as speech and music, over radio waves. Vacuum tubes were used to amplify weak radio signals, making it possible to transmit messages over greater distances and with more clarity. The development of the vacuum tube was a crucial step in the development of radio communication because it allowed for amplification of radio signals, which was necessary for long-distance communication.
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For Each Of The Following Scenarios Described Where A Molecule Or Ion Is Moving From One Side Of A Membrane To The Other, Select The Method By Which The Molecule Or Ion Is Moving. Each Answer Can Be Used More Than Once, Or Not At All. A. Simple Diffusion B. Facilitated Diffusion By A Channel Protein C. Facilitated Diffusion By A Carrier/Transport Protein
Answers
For Each Of The Following Scenarios Described Where A Molecule Or Ion Is Moving From One Side Of A Membrane To The Other, Option A is correct answer.
Scenario A: Oxygen moving across a plasma membrane Answer: A. Simple Diffusion Scenario B: Glucose moving across a plasma membrane Answer: C. Facilitated Diffusion By A Carrier/Transport Protein Scenario C: Sodium moving across a plasma membrane Answer: B. Facilitated Diffusion By A Channel Protein Scenario D: Water moving across a plasma membrane Answer: A. Simple Diffusion : Simple diffusion allows the nonpolar and small molecules to pass through the plasma membrane without any assistance of proteins. In facilitated diffusion, larger polar molecules or ions move across the membrane through the help of transport proteins. Transport proteins are of two types, channel and carrier proteins. Channel proteins provide an open path for the molecules to move whereas carrier proteins hold the molecules to move across the membrane and change their shape.
Option A is correct answer.
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What are the proportions between current and voltage and current and resistance according to Ohm’s law?
Answers
Ohm's law states that the current flowing through a conductor is directly proportional to the voltage applied across it, and inversely proportional to its resistance. This can be expressed mathematically as I = V/R, where I is the current, V is the voltage, and R is the resistance.
In practical terms, this means that if the voltage applied across a circuit remains constant, increasing the resistance will result in a decrease in current flow. Conversely, if the resistance remains constant, increasing the voltage will result in an increase in current flow.
It's important to note that Ohm's law only applies to materials that exhibit a linear relationship between current and voltage, known as Ohmic materials. Non-Ohmic materials, such as diodes and transistors, do not follow this relationship and require more complex equations to describe their behavior.
In summary, Ohm's law provides a fundamental understanding of the relationship between current, voltage, and resistance in electrical circuits and allows engineers and technicians to design and troubleshoot electrical systems.
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An object dropped from a cliff falls with a constant acceleration of 10 m/s2.Find its speed 5 s after it was dropped.
Answers
Answer:
50m/s2
Explanation:
u=0m/s
a=10m/s
v=?
t=5s
v=u+at
=0+(10×5)
=0+50
=50m/s
A box of mass 6.0 kg is accelerated from rest
across a floor at a rate of 6.0 m/s² for 9.0 s.
Find the network done on the box
Answers
\(\text{Given that },\\\text{Mass, m = 6 kg}\\\\\text{Acceleration, a = 6 } \text{m} \text{s}^{-2}\\\\\text{Time, t=9 sec}\\\\\text{Displacement, }s=ut + \dfrac 12 at^2 = \dfrac 12 at^2 = \dfrac 12 \times 6 \times 9^2 = 243 ~m}\\\\\ \text{Work,} ~W = Fs = mas = 6 \times 6 \times 243 = 8748 ~ J}\)
Hi there!
We know that:
\(W = \Delta KE = \frac{1}{2}m(\Delta v)^2\)
We can begin by solving for the final velocity using the equation:
\(v_f = v_i + at\)
The box starts from rest, so:
\(v_f = at\\\\v_f = 6(9) = 54 m/s\)
Now, we can find the kinetic energy:
\(KE = \frac{1}{2}mv^2\\\\KE = \frac{1}{2}(6)(54^2) = 8748 J\)
Thus:
\(W = \Delta KE\\\boxed{W = 8748 J}\)
4. Can an object's displacement be negative? What does the sign indicate about the
displacement?
Answers
Answer:
1. Displacement can be positive OR negative. The sign implies the direction of the displacement. 2. In one dimension the direction is indicated by the sign: negative if to the left and positive if to the right.
Explanation:
A. It Implies That M Is Finitely Generated. B. It Implies That M Has Nonzero Elements Of Nonzero Order. C. When Every Non-Null Element Has Null . D. In The Case That The Ring R Is A Body. E. None Of The Above Alternatives Gives A
Which of the following alternatives give a true statement. Justify your answer.
A modulus M over a ring R has a finite basis:
a. It implies that M is finitely generated.
b. It implies that M has nonzero elements of nonzero order.
C. When every non-null element has null .
d. in the case that the ring R is a body.
e. None of the above alternatives gives a true statement.
Which of the following statements are true?
a. If a subset of a module generates that whole module, then the subset cannot be
empty.
b. Every submodule S of a module M verifies the inequality C. Two different subsets of M have to generate two different submodules of M.
d. If S generates a submodule N of the module M, then contains S.
e. Neither statement is true.
Answers
The correct answer is e. None of the above alternatives gives a true statement. None of the statements in options a, b, c, and d are true when it comes to a modulus M over a ring R having a finite basis.
When a modulus M can be formed entirely from a finite set of elements, the modulus M is said to be finitely generated. M's finite basis does not, however, automatically imply that M is finitely generated. A basis is a set of linearly independent elements, and it might not be enough to produce all of the components of the modulus.
According to the assertion in option b, M must include nonzero items of nonzero order if it has a finite basis. This is untrue, though. The smallest positive number k, such that the element raised to the power of k equals the identity element, is referred to as the order of an element.
According to option c, every non-null element in a modulus with a finite basis has a null. Nevertheless, this claim is likewise untrue. It is possible for a modulus with a finite basis to have non-null elements without a null element.
According to option d, a ring R is a body, or a field, and only then can a modulus have a finite basis. However, this assertion is also untrue. Even though the ring R is not a field, a modulus can nonetheless have a finite basis. None of the given alternatives provides a true statement about a modulus M over a ring R having a finite basis.
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How does newton’s third law of motion relate to a catapult?
PLEASE ANSWER ASAP. WILL GIVE BRAINLIEST
Answers
Answer: the force when the catapult swings has the same force as it does when coming down
Explanation:
for every reaction there is an equal opposite reaction
What combination of ester and bromo-grignard reagent could you use to prepare the following tertiary alcohol?.
Answers
Combination to prepare tertiary alcohol:
A Grignard reagent interacts first with an ester to produce a ketone, which then undergoes further reactions to produce tertiary alcohol.
Process to form tertiary alcohol:
Methyl esters react with two moles of a Bromo-Grignard reagent to give tertiary alcohol.A ketone is produced when one mole of Grignard reagent is added to the carbon-oxygen double bond, creating an unstable intermediate. Then, a second mole of the reagent is added to the ketone, resulting in tertiary alcohol with at least two identical groups linked to the hydroxyl-bearing carbon. With acid halides and anhydrides, an identical series of reactions take place.Learn more about Grignard reagent here,
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the driver of a car hears the siren of an ambulance which is moving away from her. if the actual frequency of the siren si 2,000 hertz, the frequency heard by the driver may be
Answers
Frequency heard by the driver = 1864.96 Hz
The Doppler effect is a phenomenon that occurs when there is a change in the frequency of a wave as the source of the wave moves relative to an observer. This effect can be observed with any type of wave, but it is most commonly associated with sound waves.
The Doppler effect causes a shift in the pitch of sound waves, which is why it is often described as a change in the "sound" of a moving object. When an object emitting sound waves moves toward an observer, the frequency of the sound waves appears to increase, causing the pitch to sound higher. Conversely, when an object emitting sound waves moves away from an observer, the frequency of the sound waves appears to decrease, causing the pitch to sound lower.
The frequency heard by the driver of the car will be lower than the actual frequency of the siren because the ambulance is moving away from her. This is known as the Doppler Effect. The formula to calculate the frequency heard by the driver is:
frequency heard = actual frequency / (1 ± (velocity of the ambulance / speed of sound))
Assuming the ambulance is moving away from the driver at a speed of 30 m/s, and the speed of sound is 343 m/s, the frequency heard by the driver will be:
frequency heard = 2000 / (1 + (30 / 343)) = 1864.96 Hz
Therefore, the frequency heard by the driver may be around 1864.96 Hz.
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Find the acceleration of an object when the force is 850 N and the mass is 85 kg.
A. 0 m/s2
B. 7.3 x 104 m/s2
C. 0.1 m/s2
D.10 m/s2
Answers
Air pressure decreases with height more rapidly in a warm air column than in a cold air column. True False Question 2 In the Northern Hemisphere, the average height of contour lines on an upper-level
Answers
True. Warm air expands faster, leading to a more rapid decrease in air pressure with height than in cold air.
True. In a warm air column, the air molecules have higher kinetic energy and move more vigorously. This increased motion leads to greater expansion of the air column and a more rapid decrease in air pressure with height. As the warm air rises, it expands and becomes less dense, causing the pressure to decrease at a faster rate. In contrast, in a cold air column, the air molecules have lower kinetic energy and move more slowly.
The reduced motion results in less expansion of the air column and a slower decrease in air pressure with height. Therefore, air pressure decreases more rapidly with height in a warm air column compared to a cold air column.
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Which factor will not affect the speed of sound?
(size of the medium) or (elasticity of the medium)
Answers
Answer:
size of the medium
Explanation:
Q.5 Louisa rolls a ball with 31N of force. She observes that it has a acceleration
of 2.1m/s2. What is the mass of the ball?
Answers
Answer:
F = M a Newton's Second Law
M = F / a = 31 N / 2.1 m/s^2 = 14.8 kg
Rather heavy since 1 kg mass weighs about 2.2 lbs force
a.) Review the graphical data above and create a data table that reflects the graph (10
pts.)
Answers
A sports car travelling at uniform speed of 30 m s-¹ passes a police van which is cruising at 15 m s-¹. The van, accelerating at the rate of 1.2 m s-2, immediately begins to chase the car. (i) Write down expressions for the distance, s, travelled by each vehicle in t second, and hence (ii) calculate the time required for the van to overtake the car.
Answers
Answer:
Are you looking for a personal tutor??
where does a roller coaster have the most potential energy
Answers
Answer: the motor ......................................................................
Answer:
The top
Explanation:
Potential energy is the product of height, acceleration due to gravity, and mass, so the higher the height is, the higher the potential energy.
This means that at the very top point of the rollercoaster, you will have the most potential energy.
013
A car of mass 1,000 kg begins stationary on a road at the top of a
mountain, at a height h = 3,000 m. The car then rolls freely down a
winding road, travelling a total distance of 5 km, to reach the height h
= 2,000 m. Assume g = 9.8 ms 2.
1
How much energy did the car lose on descent? Give you answer to 3 significant figures,
with units.
Energy lost =
Answers
The energy lost by the car on descent is 980×10⁴ J
We'll begin by calculating the energy of car at various heights.
At height 3000 m:Mass (m) = 1000 Kg
Acceleration due to gravity (g) = 9.8 m/s²
Height (h) = 3000 m
Energy (E) =?E = mgh
E = 1000 × 9.8 × 3000
E = 29400000 JAt height 2000 m:Mass (m) = 1000 Kg
Acceleration due to gravity (g) = 9.8 m/s²
Height (h) = 2000 m
Energy (E) =?
E = mgh
E = 1000 × 9.8 × 2000
E = 19600000 JFinally, we shall determine the the energy lost
Energy at 3000 m = 29400000 J
Energy at 2000 m = 19600000 J
Energy lost =?Energy lost = Energy at 3000 m – Energy at 2000 m
Energy lost = 29400000 – 19600000
Energy lost = 980×10⁴ JLearn more on potential energy: https://brainly.com/question/8664733
Calculate the mass Marvin the Martian if his weight on Mars is 340 N. Acceleration due to gravity on Mars is approximately 3.80 m/s2 (Make sure to show all your work for full credit.)
Answers
Using Newtons law
\(\\ \sf\longmapsto Force=Mass\times Acceleration\)
\(\\ \sf\longmapsto Mass=\dfrac{Force}{Acceleration}\)
\(\\ \sf\longmapsto Mass=\dfrac{340}{3.8}\)
\(\\ \sf\longmapsto Mass=89.4kg\)
A patient brings in a new prescription for tetracycline 500 mg, what is the best practice at data entry?
Answers
When a patient brings in a new prescription for tetracycline 500 mg
The best practice at data entry would be
Ask for her date of birth and phone numberAsk if she has any allergiesCheck if you have the medication in stockUses of tetracycline
Tetracycline is used to treat a wide variety of infections, including acne. It is an antibiotic that works by stopping the growth of bacteria. This antibiotic treats only bacterial infections. It will not work for viral infections (such as common cold, flu).
Using any antibiotic when it is not needed can cause it to not work for future infections. Tetracycline can also be used in combination with anti-ulcer medications to treat certain types of stomach ulcers.
Tetracycline works best when taken on an empty stomach 1 hour before or 2 hours after meals. If stomach upset occurs, ask your doctor if you can take this medication with food. Take each dose with a full glass of water (8 ounces or 240 millilitres) unless your doctor directs you otherwise. Do not lie down for at least 10 minutes after taking this medication. For this reason, do not take it right before bedtime.
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4.
A tennis ball that is released falls vertically
from a building of height 50 m. Calculate:
(a) the time taken for the ball to reach the
base of the building
(b)
the velocity of the ball just before hitting
the base of the building
(c) the vertical distance passed at the third
second
Ignore air resistance. [g = 9.81 m s-²]
Answers
Answer:
(a) The time taken for the ball to reach the base of the building can be calculated using the kinematic equation:
h = 1/2 gt^2
where h is the height of the building, g is the acceleration due to gravity, and t is the time taken for the ball to reach the base of the building.
Substituting the given values, we get:
50 = 1/2 × 9.81 × t^2
Solving for t, we get:
t = √(50/4.905) = 3.19 seconds
Therefore, the time taken for the ball to reach the base of the building is 3.19 seconds.
(b) The velocity of the ball just before hitting the base of the building can be calculated using the kinematic equation:
v = gt
where v is the final velocity of the ball, g is the acceleration due to gravity, and t is the time taken for the ball to reach the base of the building.
Substituting the given values, we get:
v = 9.81 × 3.19
v = 31.3 m/s
Therefore, the velocity of the ball just before hitting the base of the building is 31.3 m/s.
(c) The vertical distance passed at the third second can be calculated using the kinematic equation:
h = ut + 1/2 at^2
where h is the distance traveled by the ball, u is the initial velocity, a is the acceleration due to gravity, and t is the time elapsed.
At the end of the second second, the ball has fallen a distance of:
h = 1/2 × 9.81 × (2^2) = 19.62 m
At the end of the third second, the ball has fallen a distance of:
h = 1/2 × 9.81 × (3^2) = 44.145 m
Therefore, the vertical distance passed at the third second is 44.145 - 19.62 = 24.525 m.
questionwhich statement is the most correct statement about a gas?responsesa gas has very little thermal energy.a gas has very little thermal energy.a gas takes the shape of its container.a gas takes the shape of its container.a gas holds its shape.a gas holds its shape.a gas is not affected by changes in pressure.a gas is not affected by changes in pressure.
Answers
The most correct statement about gas among the given options is "a gas takes the shape of its container."
This is because gases do not have a fixed shape or volume and can fill any container they are placed in, taking on its shape.
The other statements are not accurate. Gases do have thermal energy and are affected by changes in pressure.
Gases do not hold their shape, as they can expand and contract to fill the space available to them.
Gases are highly compressible and can be compressed to occupy a much smaller volume than their original state.
Additionally, the behavior of gases can be explained by the kinetic theory of gases, which states that gases are made up of tiny particles in constant random motion.
This motion results in the transfer of energy, which is responsible for the pressure, temperature, and other properties of gases.
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6. Suppose the resistance of your body between your right and left hands is 500,000 N. What
would be the current flowing through your body if you touched the plus and minus terminals of
a 120 V battery? The threshold of sensation for electric current through your body is about
300 PA. Would you feel the current?
HELP PLS
Answers
find the magnitude and angle of a vector given the components: Bx=7, By=-5
Answers
Answer:
Magnitude = 8.6
Angle = 324.5 degree from + X axis in counter clock wise direction.
Explanation:
X component of B, Bx = 7
Y component of B, By = - 5
The magnitude of the resultant is
\(B =\sqrt{7^{2}+(-5)^2}\\\\B =\sqrt{49+ 25}\\\\B = 8.6\)
The angle is given by
\(tan\theta=\frac{By}{Bx}\\\\tan\theta = \frac {-5}{7}\\\\\theta = 324.5^{o}\)
Animals often use more than one type of clue to help them to navigate. These clues include a sense of smell ('olfaction'') and remembering landmarks as well as using the Sun or the Earth's magnetic field. Suggest why an animal might use more than one type of clue to find its way.
Pls answer, will give 50 points.
Answers
An animal might use more than one type of clue to find its way due to change in the way one mechanism used to work.
Different animals have different senses heightened, that lets them use different mechanisms to navigate. Some of the mechanism include remembering landmarks, solar navigation, star navigation, magnetoreception, olfaction, gravity receptors etc.
For example, a bird using landmark to navigate will find it hard to navigate in the same way again if the landmark has been changed. So it has to depend on other senses such as olfaction or magnetoreception to navigate.
Therefore, an animal might use more than one type of clue to find its way due to change in the way one mechanism used to work.
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