An example of one of the ways a ph buffer helps to maintain homeostasis is to.

1. Which of the following is not homogeneous? (A) Brass

(B) Calamine lotion

(C) Dilute hydrochloric acid

(D) Air​

All of them are homogeneous, I looked them up individually, And it says they are all homogeneous.

Hope this helps and let me know if I'm wrong!

Explanation:

moles=mass÷molar mass

n=m÷Mr

6.0=14.6÷Mr

Mr=14.6÷6.0

Molar mass= 2.433

The balanced molecular equation for the reaction between aqueous solutions of lithium fluoride (LiF) and potassium chloride (KCl) is:

LiF(aq) + 2KCl(aq) → 2KF(aq) + LiCl(aq)

To balance the equation, we need to ensure that the number of each type of atom is the same on both sides of the equation.

For lithium fluoride (LiF), we have one lithium (Li) atom and one fluorine (F) atom. For potassium chloride (KCl), we have one potassium (K) atom and one chlorine (Cl) atom.

Therefore, to balance the equation, we need to have two potassium atoms and two fluoride atoms on the product side. This can be achieved by placing a coefficient of 2 in front of KF:

LiF(aq) + 2KCl(aq) → 2KF(aq) + LiCl(aq)

Now, the number of atoms is balanced on both sides of the equation.

The balanced molecular equation for the reaction between aqueous solutions of lithium fluoride and potassium chloride is LiF(aq) + 2KCl(aq) → 2KF(aq) + LiCl(aq). This equation shows the exchange of ions, where lithium ions (Li+) from LiF combine with chloride ions (Cl-) from KCl to form lithium chloride (LiCl), and potassium ions (K+) from KCl combine with fluoride ions (F-) from LiF to form potassium fluoride (KF). The coefficients in front of the compounds ensure that the number of each type of atom is balanced on both sides of the equation. The equation does not indicate the formation of a precipitate since all the products are aqueous solutions.

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The number of moles of N2 produced in the reaction is 3.69 moles. To calculate the number of moles of N2 produced in a reaction, we need to use the ideal gas law equation, PV = nRT.

In this equation, P represents pressure, V represents volume, n represents the number of moles, R represents the gas constant, and T represents temperature.
First, we need to convert the temperature to Kelvin by adding 273.15 to 21.5, which gives us 294.65 K.
Next, we need to convert the volume to litres by dividing 110.0 mL by 1000, which gives us 0.110 L.
Now we can plug in the values we have into the ideal gas law equation:
(2.75 atm)(0.110 L) = n(0.0821 L atm/K mol)(294.65 K)
Simplifying this equation, we get:
0.3025 = 0.0821n
To solve for n, we divide both sides by 0.0821:
n = 3.69 moles of N2

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Answer:

It's D, it is the horizon that contains the least humus.

Explanation:

I just did the test

The  statement which correctly describes the soil horizon is option B. The horizon B contains the the smallest rock pieces. It is also called the subsoil layer.

Soil horizon contains different layers of soil which are classified based on the composition of the soil and the presence of rocks within the soil. The primary level of the soil is rich in humus. The decomposed of matter of plants and animals are called humus. On which the plants are growing.

The secondary level of soil horizon or the subsoil level contains some small rocks also onto which the roots of plants does not adhere so much. The third level of soil horizon contains bigger rocks with small gaps between them.

The last layer of the soil horizon is called bedrock layer containing bigger rocks with no significant gaps between them It is called the bedrock layer.

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10g water is removed from every Kilogram of Commercial Sea Salt

Answer:

900 g

Explanation:

90% of 1000 g is 900g

The atomic or hybrid orbitals that make up the sigma bond between C1 and O1 in acetic acid, and CH3COOH are the hybrid sp3 orbitals. The approximate C2-C1-O1 bond angle is about 120 degrees.

Hybrid orbitals are orbitals produced from the hybridization of atomic orbitals. Hybridization occurs when valence electrons of an atom mix into new atomic orbitals. The new orbitals have shapes and properties that are distinct from the original atomic orbitals.Hybrid orbitals arise in the process of chemical bonding. Hybrid orbitals are used to create bonds that are stronger than those created by the use of atomic orbitals. Hybrid orbitals come in different types including sp3, sp2, and sp orbitals. A sigma bond is a type of covalent bond in which two atoms come together and share a pair of electrons. A sigma bond is a strong bond that is formed through the overlap of atomic or hybrid orbitals. A sigma bond is represented using the symbol σ. It is a type of single bond. The approximate C2-C1-O1 bond angle is about 120 degrees. The C2-C1-O1 bond angle is a measure of the degree of deviation from the linear arrangement of the three atoms in the molecule. The bond angle depends on the types of atoms, the number of electron pairs, and the repulsion between electron pairs in the molecule.

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The Option a and e represent excited states because they have electrons in higher energy levels than the ground state configuration.

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Answer:

b

b

Explanation:

The molar mass of element M can be calculated based on the given mass of the compound \(M_{3}N_{2}\) formed from the reaction. In this case, the molar mass of element M is 12.01 g/mol.

To calculate the molar mass of element M, we need to use the law of conservation of mass. The mass of the compound M_{3}N_{2} (43.5 g) is equal to the sum of the masses of three atoms of M and two atoms of nitrogen. We can calculate the mass of M in the compound by subtracting the mass of nitrogen from the total mass.

The molar mass of nitrogen (N) is 14.01 g/mol. Therefore, the total mass of nitrogen in the compound is 14.01 g/mol × 2 = 28.02 g/mol.

Now, subtracting the mass of nitrogen from the total mass of the compound, we get the mass of M: 43.5 g - 28.02 g = 15.48 g.

Since the mass of 35.3 g of element M reacted to form 15.48 g of M in the compound, we can conclude that the molar mass of element M is 15.48 g/mol / 35.3 g/mol = 12.01 g/mol, which is the molar mass of carbon (C).

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Answer:

The mean value theorem tells us the average velocity must be between the minimum velocity and the maximum velocity. The only way it can be either the minimum or the maximum is if velocity is constant. So of course instantaneous velocity can be greater and can be less.

Explanation:

The pressure exerted by the gas mixture in the 10.0 L tank is approximately 46.6 atm (Option E).

To find the pressure exerted by a gas mixture in a 10.0 L tank, we can use the Ideal Gas Law: PV = nRT,

where P is pressure, V is volume, n is the number of moles, R is the Ideal Gas Constant (0.0821 L atm/mol K), and T is temperature in Kelvin.

Step 1: Calculate the number of moles (n) for each gas.
He: n = mass / molar mass = 48.5 g / (4.00 g/mol) = 12.125 mol
CO₂: n = mass / molar mass = 94.6 g / (44.01 g/mol) = 2.149 mol

Step 2: Add the moles of each gas to find the total number of moles (n_total) in the mixture.
n_total = 12.125 mol + 2.149 mol = 14.274 mol

Step 3: Plug the values into the Ideal Gas Law equation.
P = nRT / V = (14.274 mol)(0.0821 L atm/mol K)(398 K) / (10.0 L)

Step 4: Calculate the pressure.
P ≈ 46.6 atm

Therefore, the pressure exerted by the gas mixture in the 10.0 L tank is approximately 46.6 atm .

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Answer:

The water cycle shows the continuous movement of water within the Earth and atmosphere. It is a complex system that includes many different processes. Liquid water evaporates into water vapor, condenses to form clouds, and precipitates back to earth in the form of rain and snow.

Explanation:

Explanation:

It is understood that water cycle is also a continuous cycle because it is the continuous movement of water from the earth’s surface to the atmosphere and then back to the ground. It is a continuous process. Hence, it does not have a starting or an ending point.

Answer:

Chemical bonds are forces that hold atoms together to make compounds or molecules. Chemical bonds include covalent, polar covalent, and ionic bonds.

Explanation:

Answer:

it's either a or b not c or d. there you go hope I helped

Explanation:

salt grains are very small, just like water molecule. so yea, hope I helped you out whoever you are.

The theoretical yield of copper nitrate Cu(NO3)2 is 10.83 g.

The given reaction is as follows:

Cu (s) + 4HNO₃ (aq) -----------> Cu(NO₃)₂+ 2NO₂ (g) + 2H₂O (l)

The molar mass of copper Cu is 63.53 g / mol.

The molar mass of copper nitrate solution Cu(NO₃)₂ can be calculated as:

Cu(NO₃)₂ = mass of Cu + 2 * mass of N + 6 * mass of O

                 = 63.53 + 14 + 3 * 16

                 = 125.53 g / mol

From the reaction, we can say one mole of copper gives one mole of copper nitrate.

Similarly, 63.53 g of copper will give 125.53 g of copper nitrate

Then 5.48 g of copper will give x g of copper nitrate.

for calculating x :

x = 5.48 * 125.53 / 63.53

x = 10.83 g

We have assumed x as the mass of copper nitrate Cu(NO₃)₂ which is the theoretical yield of Cu(NO₃)₂.

Hence, the theoretical yield of copper nitrate Cu(NO₃)₂ is 10.83 g.

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Answer:

i think 1:3

Explanation:

The mole fraction of methanol in the mixture is the ratio of the number of moles of methanol to the sum of number of moles of all the components in the mixture.The mole fraction of methanol in the mixture is 0.375.

Mole fraction of a component in a mixture is the ratio of the number of moles of that component to the total number of moles of all the components in the mixture.

Let nA be the number of moles of component A in the mixture and nB that of the component B. Then, mole fraction of A and B is written as:

xA = nA/ (nA + nB)

xB = nB/ (nA + nB)

Given that, number of moles of methanol = 3

number of moles of ethanol = 5 moles

total number of moles in the mixture  =  5 + 3= 8 moles.

Then mole fraction of methanol = 3 /8 = 0.375.

Therefore, the mole fraction of methanol in the mixture is 0.375.

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Answer:

the amount of reactants as well as the difference in the potential energy of the reactants and products

Answer:

1) harm life forms that rely on carbonate-based shells and skeletons, 2) harm organisms sensitive to acidity

Explanation:

Answer:

Ocean acidification can negatively affect marine life, causing organisms' shells and skeletons made from calcium carbonate to dissolve.

Explanation:the more acidic the ocean, the faster the shells dissolve.

The bond energy of B2 is approximately -1421 kJ/mol.

To determine the bond energy of A2 in the reaction A2 + B2 → 2AB, we can use the concept of bond energy and the given information.

The enthalpy change (∆H) of the reaction is given as -377 kJ, which represents the energy released during the formation of two AB molecules.

We know that the bond energy represents the energy required to break one mole of a particular bond in a compound. In this reaction, two AB molecules are formed, so the energy released (∆H) must be equal to twice the bond energy of AB.

Since the bond energy of AB is given as 522 kJ/mol, twice that value will be 2 * 522 kJ/mol = 1044 kJ/mol.

Now, to determine the bond energy of B2, we subtract the energy released from the bond energy of AB:

Bond energy of B2 = ∆H - 2 * bond energy of AB

                \(= -377 kJ - 2 * 522 kJ/mol\)

               \(= -377 kJ - 1044 kJ/mol\)

                \(= -1421 kJ/mol\)

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INFORMATION:

We know that:

- pure water boils at 99.8 degrees celcius

And we must calculate the expected elevated boiling point of a solution of 2.50g of CaCl2, in 50.0mL (i.e., 50.0g) of H2O

STEP BY STEP EXPLANATION:

To calculate it, we need to use that:

Boiling point of solution = boiling point of pure solvent + boiling point elevation (ΔTb)

The elevation in boiling point (ΔTb) is proportional to the concentration of the solute in the solution. It can be calculated via the following equation.

Where,

- i is the Van’t Hoff factor

- Kb is the ebullioscopic constant

- m is the molality of the solute

From given information, we know that:

- i = 3

Now, the ebullioscopic constant (Kb) is often expressed in terms of °C * kg * mol^-1. The value of Kb for water is 0.512.

So, kb = 0.512 °C * kg * mol^-1

Then, we must calculate the molality

So, m = 0.45 mol/kg

Replacing the values in the formula for ΔTb

Finally, the expected elevated boiling point of the solution would be

ANSWER:

The expected elevated boiling point of the solution is 100.49 °C

Answer:

Students will know that scientists find answers to questions about the natural world in different ways. ... Students will be able to explain that some science investigations are not experiments because they DON'T involve testing a hypothesis by changing one variable while keeping the other factors constant.

Explanation:

It  really all depends on the levels of suspicion.

The empirical formula of the compound containing 15.66% A and 84.34% Z as given from the question is AZ₂

Divide by their molar mass

A = 15.66 / 15.45 = 1.014

Z = 84.34 / 41.62 = 2.026

Divide by the smallest

A = 1.014 / 1.014 = 1

Z = 2.026 / 1.014 = 2

Thus, the empirical formula of the compound is AZ₂

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The main answer is that the compound with a six carbon chain and a ketone on carbon 4 will not form a yellow precipitate when treated with excess iodine in the presence of NaOH.

that the yellow precipitate formed in this reaction is due to the presence of an alpha-beta unsaturated carbonyl compound, which can undergo a reaction with iodine and NaOH to form iodoform. However, the compound with a ketone on carbon 4 does not have an alpha-beta unsaturated carbonyl group, so it will not react with iodine and NaOH to form a yellow precipitate.

out of the given options, only the compound with a six carbon chain and a ketone on carbon 4 will not form a yellow precipitate when treated with excess iodine in the presence of NaOH.

The compound(s) that will not form a yellow precipitate when treated with excess iodine in the presence of NaOH are: a five carbon chain with a ketone on carbon 3 and a six carbon chain with a ketone on carbon 4.
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: When treated with excess iodine in the presence of NaOH, compounds that contain methyl ketones (RC(O)CH3) will undergo the iodoform reaction, which produces a yellow precipitate of iodoform (CHI3). In this case, the compounds with ketones on carbon 2 (both five and six carbon chains) contain methyl ketones, so they will form a yellow precipitate. However, the five carbon chain with a ketone on carbon 3 and the six carbon chain with a ketone on carbon 4 do not contain methyl ketones and will not form a yellow precipitate.

Based on the structures provided, the compounds that will not form a yellow precipitate in the reaction with excess iodine and NaOH are those with a ketone on carbon 3 in a five carbon chain and a ketone on carbon 4 in a six carbon chain.

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5 micrograms then 5 milligrams than 5 g then 5 kg

The density of the liquid is 1.05 g/ml. To find the volume of 1.05 g of the liquid, we can use the formula:

Density = Mass / Volume

Solving for Volume, we get:

Volume = Mass / Density

Substituting the given values, we get:

Volume = 1.05 g / 1.05 g/ml

Volume = 1 ml

To convert ml to liters, we divide by 1000:

Volume = 1 ml / 1000

Volume = 0.001 L

Therefore, the volume of 1.05 g of this liquid is 0.001 liters.

To find the volume of 1.05 g of a liquid with a density of 1.05 g/mL, you can use the formula:

Volume = Mass / Density

Given:
Mass = 1.05 g
Density = 1.05 g/mL

Now, plug the values into the formula:

Volume = 1.05 g / 1.05 g/mL = 1 mL

Since 1 L equals 1000 mL, you'll need to convert the volume from mL to L:

Volume = 1 mL * (1 L / 1000 mL) = 0.001 L

So, the volume of 1.05 g of this liquid is 0.001 liters.

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Answer:

Explanation:

It is a 3s electron

Answer:

5 moles of Fe(II) are required to react completely with the 5 moles of Sulphur

Explanation:

The balanced equation in this question is

Iron + Sulfur = Iron(II) Sulfide

Fe (II) + S --> Fe(II)S

Thus one mole of sulfur reacts with one mole of Fe(II)

Hence, 5 moles of Fe(II) are required to react completely with the 5 moles of Sulphur

The balanced equation for the reaction of hydrogen gas (H2) with iodine gas (I2) is:

H2(g) + I2(g) → 2HI(g)

In this reaction, hydrogen gas reacts with iodine gas to produce hydrogen iodide gas. The reaction is a combination or synthesis reaction, where two elements combine to form a compound.

The equation is balanced with coefficients of 1 in front of H2 and I2, and a coefficient of 2 in front of HI to ensure equal numbers of atoms on both sides of the equation.

The phase labels in the equation represent the states of the substances involved: (g) indicates a gaseous state. In the reaction, both hydrogen gas and iodine gas are in the gaseous state, and hydrogen iodide gas is also in the gaseous state.

It's important to note that the reaction between hydrogen gas and iodine gas is an exothermic reaction, meaning it releases energy in the form of heat. This reaction is often used to illustrate the concept of a redox reaction, as hydrogen undergoes oxidation from an oxidation state of 0 to +1, while iodine undergoes reduction from an oxidation state of 0 to -1.

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Explanation:

agreed with above answer