An equation is given. Part A. x2 = 49 What are the values of x? Part B. Solve for b in the equation -64 = b³​

All values of b that prove Stella's claim is not correct by making the rate of change of function B greater than the rate of change of function A are:

D. 15

E. 17

In Mathematics and Geometry, the rate of change (slope) of any straight line can be determined by using this mathematical equation;

Rate of change = (Change in y-axis, Δy)/(Change in x-axis, Δx)

Rate of change = rise/run

Rate of change = (y₂ - y₁)/(x₂ - x₁)

When b = 6, the rate of change of function B is given by:

Rate of change = (6 - 3)/(4 - 1)

Rate of change = 3/3

Rate of change = 1 (not greater than 3).

When b = 12, the rate of change of function B is given by:

Rate of change = (12 - 3)/(4 - 1)

Rate of change = 9/3

Rate of change = 3 (not greater than 3).

When b = 15, the rate of change of function B is given by:

Rate of change = (15 - 3)/(4 - 1)

Rate of change = 12/3

Rate of change = 4 (greater than 3).

When b = 15, the rate of change of function B is given by:

Rate of change = (17 - 3)/(4 - 1)

Rate of change = 14/3

Rate of change = 4.7 (greater than 3).

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Missing information:

Select all values of b that prove Stella's claim is not correct by making the rate of change of function B greater than the rate of change of function A.

6

8

12

15

17

Answer:

Step-by-step explanation:

This is the answer

Answer:X=12/7

Step-by-step explanation:

Y \(\alpha\) X

⇒Y=KX

Where K is the constant

From the question,k=7

⇒ When Y=12,

y=KX

12=7X

X=12/7

Answer:

Screenshot and post it please

Step-by-step explanation:

Answer:

Rectangle

Step-by-step explanation:

The one on the bottom right corner.

Hope it helps.

;)

<3

A method to swap two array elements works correctly because it is designed to swap the entire elements at two different indexes in an array.

The method receives two integer values representing the indexes of the elements to be swapped and then proceeds to swap the elements themselves.
On the other hand, a method to swap two integer values does not work correctly because integers are passed by value, which means that the method receives a copy of the integer values rather than the original values themselves. Thus, the method only swaps the copies and not the original values, and as a result, the original values remain unchanged.
To overcome this issue, one can use a workaround such as passing the integer values as references instead of values. This way, the method receives a reference to the original value, and any changes made to the reference will affect the original value as well. However, this approach can be more complex and less efficient than simply swapping array elements.

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The probability that the sum of two fair dice is not 7 is \(31/36\).When two fair dice are rolled, the probability of the sum not being 7 is \(5/6\).

When two fair dice are rolled, there are a total of 36 possible outcomes (6 outcomes for the first die multiplied by 6 outcomes for the second die). Out of these 36 outcomes, there are 6 outcomes where the sum is 7 (1+6, 2+5, 3+4, 4+3, 5+2, and 6+1).

To find the probability of the sum not being 7, we subtract the number of outcomes where the sum is 7 from the total number of outcomes and divide by the total number of outcomes:

\(1 - (6/36) = 30/36 = 5/6\)

Therefore, the probability that the sum is not 7 is \(5/6\).

When two fair dice are rolled, the probability of the sum not being 7 is \(5/6\).

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Answer:

Selection D

Step-by-step explanation:

Based on the equation f(x) = 3(.5)^x, we can see that this function is an exponential function.

This eliminates selection B

We can also see that the A value (3) is positive, and therefore will slope upwards.

This eliminates selection C

Now you are left with selections A and D

The difference between the two is their y-intercepts and the origin points.

So let's start by trying out a y-intercept point

In selection A, the y-intercept is (0,1)

Let's plug this into the equation y = 3(.5)^x

\(1 = 3(.5)^0\\\)

Anything to the power of 0 is equal to 1

3 x 1 does not equal 1

Therefore, this eliminates selection A

The only one left is  . . . . . Answer D!

Hope this helps!

If you wanted to check the answer, plug in the y-intercept into the equation

The y-intercept for D is (0,3)

\(3= 3(.5)^0\)

Again, anything to the 0 power is equal to 1, leaving us with:

3 = 3 x 1

This statement is true, and therefore Answer D is correct

Answer:

\(3x^3 - 5x + 1 - \frac{10}{x + 3}\)

or

3x^3 - 5x + 1

Remainder: -10

Step-by-step explanation:

Please see attached image for full explanation!

1.) Write the coefficient of each term.

2.) Beginning with 3, multiply by -3, or x + 3 = 0 (the divisor.)

3.) Add the product to the next coefficient and repeat until you get to the last number, -7.

4.) You should have the numbers 3, 0, -5, 1, and -10.

5.) Rewrite this quotient as an equation:

3x^3 - 5x + 1

Note that the highest power is 3, one less than that of the highest power in the original equation.

6.) Don't forget the remainder!

You can include this in the equation or not, depending on the instructions.

Therefore, the final answer is 3x^3 - 5x + 1 - 10/x+3 or 3x^3 - 5x + 1 R: -10.

2x-3=7

The answer would be 5.

Answer:

x=5

Step-by-step explanation:

2x−3=7

Add 3 to both sides.

2x=7+3

Add 7 and 3 to get 10.

2x=10

Divide both sides by 2.

x=10/2

Divide 10 by 2 to get 5.

x=5

True. The r command "qt(0.95, 7)" calculates the critical value of the distribution with 7 degrees of freedom at a significance level of 0.05 and a two-tailed test. The "qt" function in R is used to find the critical value of a t-distribution for a given probability and degrees of freedom.

In this case, the command returns the critical value of the t-distribution with 7 degrees of freedom at a significance level of 0.05, which can be used to perform hypothesis testing or confidence interval calculations. It is important to note that the critical values of the t-distribution change as the degrees of freedom change, and different significance levels require different critical values. Answering in more than 100 words, it is necessary to understand the concept of degrees of freedom in statistics. Degrees of freedom represent the number of independent observations that are available for estimation in a statistical model. The number of degrees of freedom depends on the sample size, the number of parameters being estimated, and any constraints on the model. In general, more degrees of freedom lead to greater precision in estimates and narrower confidence intervals.

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Answer:

jacki did not subtract 8 minus 12 properly.8 minus 12 equals -4

Answer:

its c

Step-by-step explanation:

on edunuity

The component form of the vector that translates A to A' is (11, -17)

A translation is a type of transformation that takes each point in a figure and slides it the same distance in the same direction.

In translation, the shape of the figure does not change but its size may change.

Other transformation processes are reflection and rotation.

The component form of the vector is governed by the rule; A' - A

so we subtract corresponding x- coordinates and corresponding y- coordinates

A' - A = (7, -9) - (-4, 8)

       = ( 7 - - 4, -9 - 8)

       -= ( 11, -17)

In conclusion, the vector that translates A to A' is ( 11, -17 )

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The cone is a three dimensional shape, and the value of the height of the cone is 27 inches

The given parameters are:

The volume of the cone is calculated using:

\(V = \frac13 Bh\)

So, we have:

\(45 = \frac13 * 5 * h\)

Divide both sides by 5

\(9 = \frac13 * h\)

Multiply both sides by 3

h = 27

Hence, the value of the height of the cone is 27 inches

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Answer:

0

Step-by-step explanation:

Jordan hasn't got enough money to buy any books, as $11.40<$280.

Answer:

|-11 |

Step-by-step explanation:

Answer:

Step-by-step explanation:

your right there wrong

In order to get the value of n, which is what we are trying to find, it is important to know how to isolate the variable.

When something is added to n, you subtract to isolate n. Going with this logic, you would multiply by a number if you wanted to isolate n with a fraction.

\(\frac{n}{5}+4=-4\)

The first step would be to get rid of the 4 on the left side so we can work on the variable. We can do this by subtracting both sides by 4, so the left side cancels out to 0.

\(\frac{n}{5}+4-4=-4-4\)

\(\frac{n}{5} =-8\)

Next, we can multiply both sides by 5, so we can isolate the variable, because it is being divided by 5.

\(\frac{n}{5} *5=-8*5\)

n=-40

a) The probability of failing to meet the specification limit of 45-pounds tensile strength 15.87%.

b) The number of parts that would not meet the specification is 7,935.

a) Given that the tensile strength of a metal part is normally distributed with mean 40 pounds and standard deviation 5 pounds.

We have to find the probability of failing to meet the specification limit of 45-pounds tensile strength.

Using the standard normal distribution, we can find the probability of failing to meet the specification limit of 45 pounds as follows:

z = {45 - 40}/{5}

= 1

The probability of failing to meet the specification limit of 45 pounds is the probability that the standardized variable Z is greater than 1, which is given by:

P(Z > 1) = 0.1587

Therefore, the probability of failing to meet the specification limit of 45-pounds tensile strength is 0.1587 or 15.87%.

b) If the probability of failing to meet the specification is 0.1587, the probability of meeting the specification limit is

1 - 0.1587 = 0.8413

.If 50,000 parts are produced, then the expected number of parts that meet the specification limit is:

0.8413* 50,000 =  42,065.

Therefore, the number of parts that would not meet the specification is: 50,000 - 42,065 = 7,935.

Hence, about 7,935 parts would not meet the specification.

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Answer:

Sin X=Cos Y

Step-by-step explanation:

Objective: Understand trigonometric relations such that

Cosine and Sine are similar to complementary angles that if X+Y are complementary angles,

Cos X= Sin Y and Cos Y= Sin X

Emma needed to budget an extra $87.00 - $24.00 = $63.00 for eating at restaurants instead of eating at home.

What is the equivalent expression?

Equivalent expressions are expressions that perform the same function despite their appearance. If two algebraic expressions are equivalent, they have the same value when we use the same variable value.

Emma spent a total of $29.00 x 3 = $87.00 on eating at restaurants.

If Emma had eaten at home, she would have spent $8.00 x 3 = $24.00.

Therefore, Emma needed to budget an extra $87.00 - $24.00 = $63.00 for eating at restaurants instead of eating at home.

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The union of two sets is to avoid counting the same elements twice.

The mathematical logic subfield of set theory investigates sets, which can be loosely defined as collections of objects. Although any object can be combined into a set, set theory, as a mathematical discipline, focuses primarily on those that are relevant to mathematics as a whole.

Given union of set

(A ∪ B),

The set of all objects that are members of either A or B, or both, is the union of the sets A ∪ B.

let us take example,

A = { 1, 2, 3, 4}

B = {3, 4, 5, 6, 7}

(A ∪ B) = { 1, 2, 3, 4} ∪  {3, 4, 5, 6, 7}

we can simply write all of A and B's elements in a single set to avoid duplicates to find A U B.

(A ∪ B) = {1, 2, 3, 4, 5, 6, 7}

Hence the  union of two sets is a set that contains all the elements of both set and avoid duplicates.

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If the confidence coefficient reduces to 0.90, the confidence interval for μ becomes narrower.

What is an Interval estimation?

Interval estimation in statistics refers to the use of sample data to calculate an interval of likely values for an interesting parameter.

What is Mean?

It's obtained by simply dividing the sum of all values in a data set by the number of values. The calculation can be done from raw data or for data aggregated in a frequency table.

In interval estimation, as the sample size becomes larger, the interval estimate becomes narrower.

A 95% confidence interval for population mean is determined to be 100 to 120.

If the confidence coefficient reduces to 0.90, the confidence interval for μ becomes narrower.

Hence the answer is If the confidence coefficient reduces to 0.90, the confidence interval for μ becomes narrower.

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Relation and Function both are same except for one thing.

Relation can have repetitive domain while Function cannot. We can say that Function is a relation without repetitive domain.

Example of Relation

{(1,1),(1,3),(2,5),(2,6),(3,46),(3,90)}

This is a relation because there are same and repetitive domain.

Example of Function

{(1,1),(2,4),(3,9),(4,16),(5,25),(6,36),(7,49)}

This can be classified as relation as well but relation that is function. We can say that function is a subset of relation. Remember that functions are relations that don't have repetitive domain while relations that are not function (or just relations) can have repetitive or same domain.

Graph of Relation and Function

Relations can have graphs along with Functions. The problem is you might not see set of ordered pairs but graph instead.

How can we tell if the graph is a function or just only relation? The answer is to do line test.

If the graph intercepts only one point then it is a function. Otherwise, no.

The value of angle S is 53°

Exterior angle theorem states that the measure of an exterior angle of a triangle is equal to the sum of two remote interior angles.

With this theorem we can say that

7x+2 = 4x+13+19

collecting like terms

7x -4x = 13+19-2

3x = 30

divide both sides by 3

x = 30/3

x = 10

Since x = 10

angle S = 4x+13

angle S = 4(10) +13

= 40+13

= 53°

Therefore the measure of angle S is 53°

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When Steven combines the sacks into one large bag, the probability of drawing a "1" and a "B" without replacement reduces since the full number of balls increments, resulting in a little probability.

To decide on the off chance that the probability would alter when Steven combines the table tennis balls into one large bag, we ought to compare the probabilities sometime recently and after the combination.

In address 17, the probability of drawing a "1" and a "B" without substitution can be calculated utilizing the concept of conditional likelihood.

Let's expect the two-person sacks to be signified as Sack 1 and Pack 2, and they contain a add up to n balls each.

Sometime recently combining the packs:

The probability of drawing a "1" from Sack 1 is p(1) = 2/n (since there are 2 "1" balls in Pack 1).

The probability of drawing a "B" from Sack 2 is p(B) = 3/n (since there are 3 "B" balls in Sack 2).

Expecting the occasions of drawing a "1" and a "B" to be free, the likelihood of both occasions happening without replacement is given by the item of the person probabilities:

P(1 and B) = p(1) * p(B) = (2/n) * (3/n) = 6/n^2

After combining the bags:

When Steven combines the sacks into one expansive sack, the entire number of balls gets to be 2n (since each sack initially contained n balls).

The probability of drawing a "1" from the combined sack is presently p(1) = 2/(2n) = 1/n (since there are still 2 "1" balls).

The likelihood of drawing a "B" from the large bag is presently p(B) = 3/(2n) = 3/(2n) (since there are still 3 "B" balls).

Once more, accepting autonomy, the likelihood of both occasions happening without replacing the combined pack is given by:

P(1 and B) = p(1) * p(B) = (1/n) * (3/(2n)) = 3/(2n^2)

Comparing the probabilities:

P(1 and B) sometime recently combining packs: \(6/n^{2}\)

P(1 and B) after combining packs: \(3/(2n^{2})\)

Hence, the probability does alter when Steven combines the bags into one expansive pack. The probability of drawing a "1" and a "B" without substitution diminishes from \(6/n^{2} to 3/(2n^{2}).\)

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Since the distance between the centers is 10 and the radius of both circles is 7, the two circles are externally tangent.Therefore, Chante is right.

To prove that two circles are externally tangent, we need to show that their radii are equal and the distance between their centers is equal to the sum of their radii.

We can find the equation of the first circle to be (x+2)^2+(y−4)^2=49, which has a radius of 7.

For the second circle, we can rewrite the equation as x^2+y^2−6x+16y−37=0, which has a radius of sqrt(37).

Since the radius of both circles is 7, they are equal.

To find the distance between their centers, we can use the Pythagorean theorem. The distance between the centers is the square root of (6^2 + 16^2) = sqrt(100) = 10.

Since the distance between the centers is 10 and the radius of both circles is 7, the two circles are externally tangent.

Therefore, Chante is right.

the correct question is: Chante claims that two circles given by (x+2)^2+(y−4)2=49 and x^2+y^2−6x+16y+37=0 are externally tangent. She is right. Show that she is right.

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