An engineer is designing the runway for an airport. Of the planes that will use the airport, the lowest acceleration rate is likely to be 3 m/s2. The takeoff speed for this plane will be 65 m/s. All airplanes will start from rest(0m/s). Assuming this minimum acceleration, what is the minimum allowed length for the runway for take off?

The distance walked by the woman at the given speed an time, is 15 miles.

The speed of an object is defined as the rate of change of the distance travelled by the object.

Here,

Speed with which the woman is walking,

v = 5 miles/hour

Time taken by the woman for walking,

t = 3 hours

We know speed is the rate of change of distance,

v = d/t  where d is the distance travelled by the woman

So, d = v x t

 d = 5 x 3

 d = 15 miles

Hence,

The distance walked by the woman at the given speed an time, is 15 miles.

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Answer:

the position of the wood below the interface of the two liquids is 2.39 cm.

Explanation:

Given;

density of oil, \(\rho _o\) = 926 kg/m³

density of the wood, \(\rho _{wood}\) = 974 kg/m³

density of water, \(\rho _w\) = 1000 kg/m³

height of the wood, h = 3.69 cm

Based on the density of the wood, it will position across the two liquids.

let the position of the wood below the interface of the two liquids = x

Let the wood be in equilibrium position;

\(F_{wood} - F_{oil} - F_{water} = 0\\\\\rho _{wood} .gh - \rho _o .g(h-x) - \rho_w .gx = 0\\\\\rho _{wood} .h - \rho _o (h-x) - \rho_w .x = 0\\\\\rho _{wood} .h -\rho _o h + \rho _o x - \rho_w .x =0\\\\h (\rho _{wood} -\rho _o ) = x( \rho_w - \rho _o)\\\\x =h[\frac{ \rho _{wood} -\rho _o }{\rho_w - \rho _o} ]\\\\x = 3.69\ cm \times [\frac{974 - 926}{1000-926} ]\\\\x = 2.39 \ cm\)

Therefore, the position of the wood below the interface of the two liquids is 2.39 cm.

Answer:

500

p=w/t

w=force *displacement

w=750*20=15000j

p=15000/20=500watt

Explanation:

500

p=w/t

w =force displacement

w=750*20=15000j

p=15000/20=500 watt

Answer:

4300N

Explanation:

Based on the free body diagram, the friction (fFr in the attached diagram) is dependent on the reaction force (Rn in the attached diagram) acting on the object, in this case a car. The frictional force will always act against the direction of movement (DOM in the attached diagram.)

Given the condition is dry,

Summation of forces in the vertical direction (Positive for upward forces) = 0

Reaction Force - Weight of car = 0

Reaction Force = Weight of car = 14000N

Since the friction is dependent on the reaction force with the formula: Coefficient of friction X Reaction Force,

Friction (Dry Condition) = 0.7 * 14000N = 9800N

Now given the condition is wet,

We will use the same formula but with a change to the coefficient of friction.

Friction (Wet Condition) = 0.4 * 14000N = 5600N

Difference between them = 9800N - 5600N = 4300N.

The accurate statements that describe mechanical waves are: Mechanical waves require a medium , Mechanical waves transfer energy, Mechanical waves can be longitudinal or transverse, Mechanical waves can be categorized as compressional or shear waves, Mechanical waves obey the principles of reflection, refraction, and interference, Mechanical waves have measurable properties such as wavelength, frequency, and amplitude.

Mechanical waves are a type of wave that require a medium, such as a solid, liquid, or gas, to propagate. They are characterized by the transfer of energy through the oscillation or vibration of particles in the medium. Here are the accurate statements that describe mechanical waves:

1. Mechanical waves require a medium: This statement is true. Mechanical waves cannot propagate in a vacuum because they rely on the interaction of particles in a medium to transfer energy.

2. Mechanical waves transfer energy: This statement is true. Mechanical waves transport energy from one location to another as the particles of the medium vibrate or oscillate.

3. Mechanical waves can be longitudinal or transverse: This statement is true. Mechanical waves can exhibit different types of motion. In longitudinal waves, the particles of the medium oscillate parallel to the direction of wave propagation. In transverse waves, the particles oscillate perpendicular to the direction of wave propagation.

4. Mechanical waves can be categorized as compressional or shear waves: This statement is true. In a compressional wave, the particles of the medium undergo compression and rarefaction as the wave passes through. In shear waves, the particles move perpendicular to the direction of wave propagation, resulting in a sideways displacement.

5. Mechanical waves obey the principles of reflection, refraction, and interference: This statement is true. Mechanical waves can reflect off surfaces, change direction when passing through different media (refraction), and exhibit interference patterns when two or more waves interact.

6. Mechanical waves have measurable properties such as wavelength, frequency, and amplitude: This statement is true. Mechanical waves can be described by various properties. Wavelength represents the distance between two consecutive points in the wave, frequency is the number of wave cycles per unit of time, and amplitude is the maximum displacement of particles from their equilibrium position.

These statements accurately describe mechanical waves and their properties, highlighting the key characteristics of this type of wave propagation.

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Answer:

can u send pictures again it's unclear.

The number of moles of gas added to the container is -3.56 mol, and the negative sign means that the number of moles of gas decreased, or in other words, the gas was compressed.

The number of moles of gas can be calculated using the Ideal Gas Law:

PV = nRT

where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant, and T is temperature.

Since the pressure and temperature remain constant, we can equate the initial and final state of the gas:

n1 × (8.15 L) × (T) = n2 × (13.7 L) × (T)

Dividing both sides by T, we get:

n1 × 8.15 L = n2 × 13.7 L

Solving for n2:

n2 = (n1 × 8.15 L) / (13.7 L)

n2 = (8.51 mol) × (8.15 L) / (13.7 L)

n2 = 4.95 mol

So, the number of moles of gas added to the container is:

n2 - n1 = 4.95 mol - 8.51 mol = -3.56 mol.

Note that the answer is negative, which means that the number of moles of gas decreased, or in other words, the gas was compressed.

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Answer: They are only taken when a player from the other team does something wrong. And they are only worth 1 point

Explanation:

Answer: You don't jump on your free throws, since they are not a jumpshot or layup and since u were fouled, they're only worth 1pt each.

Explanation:

Answer: 520 nm; 5.77 × 1014 Hz; 3.82 × 10−19 J

Answer:

240 meter

Explanation:

d= s*d=60m/s * 4sec=240 meter

Answer:

The difference between them is that the velocity-time graph reveals the speed of an object (and whether it is slowing down or speeding up), while the position-time graph describes the motion of an object over a period of time.

Explanation:

Answer:

0.6 m/s 2

Explanation:

Answer:

HEY PLS LISTEN THERE IS A GUY GOING AROUND TELLING GIRLS TO JOIN HIS ZOOM ON BRAINLY AND MAKING ACCS AND STUFF TO MAKE PEOPLE JOIN HIS ZOOM.THE CODE IS 387 187 6280 HES A PEDXO AND TELLING GIRLS TO SHOW THERE BODIES TO HIM. SO PLEASE BE AWARE! COPY AND PASTE THIS TO SPREAD THE WORD!

Explanation:

HEY PLS LISTEN THERE IS A GUY GOING AROUND TELLING GIRLS TO JOIN HIS ZOOM ON BRAINLY AND MAKING ACCS AND STUFF TO MAKE PEOPLE JOIN HIS ZOOM.THE CODE IS 387 187 6280 HES A PEDXO AND TELLING GIRLS TO SHOW THERE BODIES TO HIM. SO PLEASE BE AWARE! COPY AND PASTE THIS TO SPREAD THE WORD!

Icecaps and Glaciers

Explanation:

Icecaps and Glaciers hold 68 percent of fresh water on earth :)

Explanation:

Given:

Diameter = 200 m

Radius, r = 200/2 = 100 m

Time taken, t = 30 seconds

Formula to be used:

Distance traveled, = circumference of circle = 2πr

Answer:

Putting all the values, we get

Distance traveled = 2πr

So, the distance traveled by Raju is 628.57 m.

Now, magnitude of the displacement,

At the end of 30 seconds, Raju will come to starting position or initial position, so displacement is zero.

( a) The acceleration of the box in the absence of friction is 8.49 m/s².

(b) The acceleration of the box in the presence of friction is 1.7 m/s².

(c) The speed of the box at the bottom of the incline is 18.44 m/s.

The acceleration of the box if no friction is present is calculated by applying Newton's second law of motion.

mg cosθ = ma

g cosθ = a

where;

The acceleration of the box in the absence of friction is calculated as;

a = ( 9.8 ) x ( cos 30 )

a = 8.49 m/s²

The acceleration of the box in the presence of friction is calculated as;

Ff = ma

where;

μmg cosθ = ma

μg cosθ = a

( 0.2 x 9.8 x cos 30 ) = a

1.7 m/s² = a

The speed of the box at the bottom of the incline is calculated as follows;

v² = u² + 2ah

where;

v² = 0 + 2ah

v = √ ( 2ah )

h = L sinθ

v = √ ( 2 x a x L sinθ )

v = √ ( 2 x 1.7 x 200 x sin 30 )

v = 18.44 m/s

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The linear speed will be the insect be 0.5759 meter/second carried collision with the near stationary photograph.

Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.

Given that an insect lands 0.1m from the center of the turn table.

Rotational speed of the turn table = 55 rev/min

= (55×2π/60) rad/second

= 5.759 rad/second.

Hence, the speed of the insect be = Rotational speed × length

= 5.759 rad/second × 0.1 M.

= 0.5759 meter/second.

Therefore, the speed of the insect be 0.5759 meter/second.

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Answer:

the reading of the balance must decrease

Explanation:

The balance of the span is within a fluid the air, for which it is subjected to the pressure of the same, if we write the equilibrium equation we have

          F_net = B -W - F_armosphere

in this case F_net = 540 N

where the thrust is given by Archimedes' principle which states that the thrust is equal to the weight of the fluid dislodged

          B = ρ g V

in this case the density of the air is

           ρ = 1.1 kg / m³

therefore the value of the thrust is small

the force of the air is

            P = F / A

            F = P A

the air pressure is approximately P = 1 10⁵ Pa

Thus

      B <F_atmosphere

Now we can analyze what happens when we remove the air from the room, the pressure at atmospheric pressure decreases therefore the force of the air decreases, while there is some air the thrust is maintained even when it also decreases since the density of the air decreases when decreasing the Pressure.

Consequently, the reading of the balance changes depending on how the thrust and the air force decreases, in general the air force decreases much faster than the thrust, therefore the reading of the balance must decrease

Explanation:

Volume ( L X W X D)   * density = mass

(5 * 4 * 10) m^3      *     2000 kg/m^3   = 400 000 kg

    ( see how the ' m^3'  cancels out and you are left with kg as your answer units?)

I don't know about it your answer will give another people

Answer: Let the final velocity be v.

Given,

Initial velocity(u)=8m/s

Acceleration(a)=7m/s2

Time(t)=3 sec

Then,

v=u+at

  =8+7*3 m/s

  =29m/s

Therefore, the final velocity is 29m/s.

The minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

To maintain equilibrium, the torques acting on the meter stick must balance each other. The torque is given by the formula:

τ = r * F * sin(θ)

where τ is the torque, r is the distance from the pivot point to the point where the force is applied, F is the force applied, and θ is the angle between the force vector and the lever arm.

In this case, the meter stick is in equilibrium when the torques on both sides of the pivot point cancel each other out. The torque due to the weight of the meter stick itself is acting at the center of mass of the meter stick, which is at the 50.0 cm mark.

Let's denote the mass to be placed on the 0.00 cm mark as M. The torque due to the weight of M can be calculated as:

τ_M = r_M * F_M * sin(θ)

where r_M is the distance from the pivot point to the 0.00 cm mark (which is 30.0 cm), F_M is the weight of M, and θ is the angle between the weight vector and the lever arm.

Since the system is in equilibrium, the torques on both sides of the pivot point must be equal:

τ_M = τ_stick

r_M * F_M * sin(θ) = r_stick * F_stick * sin(θ)

Substituting the given values:

30.0 cm * F_M = 20.0 cm * (0.0400 kg * 9.8 m/s^2)

Solving for F_M:

F_M = (20.0 cm / 30.0 cm) * (0.0400 kg * 9.8 m/s^2)

F_M = 0.0264 kg * 9.8 m/s^2

F_M = 0.25872 N

Finally, we can convert the force into mass using the formula:

F = m * g

0.25872 N = M * 9.8 m/s^2

M = 0.0264 kg

Therefore, the minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

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The number of photons per second emitted by the laser is \(7.64 \times 10^{-19} \ photons /s\).

The given parameters:

The number of photons per second emitted by the laser is calculated as follows;

\(n(P \times t ) = E\)

where;

\(n = \frac{E}{P\times t} \\\\n = \frac{3.1 \times 1.602 \times 10^{-19}}{0.65 \times t} \\\\n = 7.64 \times 10^{-19} \ photons/s\)

Thus, the number of photons per second emitted by the laser is \(7.64 \times 10^{-19} \ photons /s\).

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Answer:

whats the question?

Explanation:

maybe sphere if its a shape though

Answer:

everything will float up and go up to space and die

Explanation:

gravity keeps us down and once it stops everything will float up. And if it were to stop everywhere everything and everyone will die and everything will be destroyed.

Answer:

The torque exerted on the merry-go-round is 766.95 Nm

Explanation:

Given;

mass of the merry-go-round, m = 416 kg

radius of the disk, r = 1.7 m

angular speed of the merry-go-round, ω = 3.7 rad/s

time of motion, t = 2.9 s

The torque exerted on the merry-go-round is calculated as;

\(\tau = Fr= I\alpha\\\\\tau = (\frac{1}{2} m r^2)(\frac{\omega }{t} )\\\\\tau = (\frac{1}{2} \times 416 \times 1.7^2)( \frac{3.7}{2.9} )\\\\\tau = 766.95 \ Nm\)

Therefore, the torque exerted on the merry-go-round is 766.95 Nm