An element is lustrous, brittle, and silver colored. What type of element is it
Metal
Metalloid
Non Metal
Other
Will give brainlist

Answer:

Volume = 3.4 L

Explanation:

In order to calculate the volume of CO₂ produced when 15.2 g of CaCO₃ is heated, we need to first write out the balanced equation of the thermal decomposition of CaCO₃:

CaCO₃ (s) + [Heat] ⇒ CaO (s) + CO₂ (g)

Now, let's calculate the number of moles in 15.2 g CaCO₃:

mole no. = \(\mathrm{\frac{mass}{molar \ mass}}\)

                 = \(\frac{15.2}{40.1 + 12 + (16 \times 3)}\)

                 = 0.1518 moles

From the balanced equation above, we can see that the stoichiometric molar ratios of CaCO₃ and CO₂ are equal. Therefore, the number of moles of CO₂ produced is also 0.1518 moles.

Hence, from the formula for the number of moles of a gas, we can calculate the volume of  CO₂:

mole no. = \(\mathrm{\frac{Volume \ in \ L}{22.4}}\)

⇒ \(0.1518 = \mathrm{\frac{Volume}{22.4}}\)

⇒ Volume = 0.1518 × 22.4

                 = 3.4 L

Therefore, if 15.2 g of CaCO₃ is heated, 3.4 L of CO₂ is produced at STP.

The volume of argon gas will be, 79.68L .

Mass of argon (Ar) gas = 2.71 g

Molar mass of argon = 39.95 g/mole

Volume of argon gas = 4.21 L

Moles of neon (Ne) gas = 1.29 mole

First we have to calculate the moles of argon gas.

\(Moles of argon = \frac{mass\ of \ar}{molar \mass\ of \ ar}\\ \\Moles of argon = \frac{2.71}{39.95} \\\\Moles of argon = 0.0678 moles\)

Now we have to calculate the volume of neon gas.

According to the Avogadro's law, the volume of gas is directly proportional to the number of moles of gas at same pressure and temperature. That means,

\(\frac{v_1}{v_2} =\frac{n_1}{n_2}\)

where,

\(v_1\) = volume of argon gas

\(v_2\) = volume of argon gas

\(n_1\) = number of moles of argon gas

\(n_2\) = number of moles of argon gas

Now we put all the given values in this formula, we get

\(\frac{4.21}{v_2} = \frac{0.068}{1.29} \\\\v_2 = 79.86 L\)

Therefore, the volume of argon gas will be, 79.68L .

The molar mass of a chemical compound is defined as the mass of a sample of the compound divided by the amount of the substance, which is the number of moles of the sample measured in moles. Molar mass is the volume of a substance, not a molecular property. Molar mass is the average of several occurrences of a compound, whose mass often varies  due to the presence of isotopes. In most cases, molar mass is calculated from  standard atomic masses and is thus a function of the Earth's average and  the relative abundance of the Earth's atomic isotopes. Molar mass is suitable for converting between the mass of a substance and the amount of  substance in bulk.

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Moving a gas to a smaller container and holding the container over a Bunsen burner are two modifications that might raise a gas's pressure.

Gas pressure rises as container volume decreases. As a gas's temperature rises inside a rigid container, pressure also rises. The temperature, volume, and particle count of an enclosed gas are all variables that determine its pressure.

We can modify the pressure in two ways. First, we can make the air denser by either decreasing the volume of the container or adding additional air molecules to it.

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Given,

\(V = 5.2 L\\\\M = 1.1 KOH\\\\V_2 = 2.3 L\\\\M_2 = 0.2 Sc(OH)_3\)

moles of each substance,

moles of base = \(M*V = 5.2L * 1.1M = 5.72 moles of KOH\)

mole of \(Sc(OH)_3 = M*V = 2.3*0.2 = 0.46 moles of Sc(OH)_3\)

Assume

\(Sc(OH)3 ---> Sc+3 and 3OH-\)

therefore,

there is 3x the amount of moles of \(Sc(OH)_3\) per mol of \(OH-\)

\(0.46 * 3 = 1.38 mol of OH-\)

Adding all OH- moles

\(1.38+5.72 = 7.1 mol of OH- present\)

The total volume:

\(V_T = V_1+V_2 = 5.2+2.3 = 7.5 L\)

The concentration of  ions

\([OH-] = \frac{mol OH}{V}= \frac{7.1}{7.5} = 0.94667\)

\(pOH = -log(OH-) = -log(0.94667) = 0.0238\)

Therefore,

\(pH = 14 - pOH\\\\pH = 14 - 0.0238 = 13.97\)

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To solve this we must be knowing each and every concept related to mole and  and its calculations. Therefore, 83.17g is the grams of  CaCl\(_2\) would it take to make 1.5 moles of KCl. The correct option is option B.

A mole is merely a measuring unit. In reality, it is one of International System of Units' seven foundation units (SI). When basically determines are insufficient, new units are created.

Chemical reactions frequently occur at levels that use grams would be inappropriate, but using actual figures of atoms/molecules/ions would also be misleading.

It's much easier to write' mole' than '6.02x10²³' whenever you wish to refer to a huge number of things. That is essentially why and how this particular component was created.

2K\(_3\)N + 3CaCl\(_2\) → 6KCl + Ca\(_3\)N\(_2\)

mole ratio between CaCl\(_2\) and KCl is 1:2

2 mole of KCl requires 1 mole of CaCl\(_2\)

1 mole of KCl requires 1/2 moles of CaCl\(_2\)

1.5 moles of KCl requires (1/2)×1.5= 0.75 moles of CaCl\(_2\)

mass of CaCl\(_2\) =  0.75 moles ×110.9g/mol

                        = 83.17g

Therefore, 83.17g is the grams of  CaCl\(_2\) would it take to make 1.5 moles of KCl.

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Answer:

0.0238 moles NaOH

Explanation:

To find the amount of moles, you need to

(1) convert the volume from mL to L (1,000 mL = 1 L)

(2) calculate the amount of moles (using the molarity equation)

It is important to arrange the conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs.

 125.0 mL NaOH                  1 L
---------------------------  x  ---------------------  =  0.1250 L NaOH
                                         1,000 mL

Molarity = moles / volume (L)                    <----- Molarity equation

0.190 M = moles / 0.1250 L                       <----- Insert values

0.0238 = moles                                         <----- Multiply both sides by 0.1250

The percent composition of CuBr₂ is approximately 28.46% of Cu and 71.54% of Br.

To determine the percent composition of CuBr₂ (copper(II) bromide), we need to calculate the mass of each element in the compound and then divide it by the molar mass of the entire compound.

The molar mass of CuBr₂ can be calculated by adding up the atomic masses of copper (Cu) and bromine (Br) in the compound. The atomic masses of Cu and Br are approximately 63.55 g/mol and 79.90 g/mol, respectively.

Molar mass of CuBr₂ = (63.55 g/mol) + 2(79.90 g/mol) = 223.35 g/mol

Now, let's calculate the percent composition of each element in CuBr₂:

Percent composition of copper (Cu):

Mass of Cu = (63.55 g/mol) / 223.35 g/mol × 100% ≈ 28.46%

Percent composition of bromine (Br):

Mass of Br = 2(79.90 g/mol) / 223.35 g/mol × 100% ≈ 71.54%

Therefore, the percent composition of CuBr₂ is approximately:

- Copper (Cu): 28.46%

- Bromine (Br): 71.54%

These values represent the relative mass percentages of copper and bromine in the compound CuBr₂.

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The value of h in the right triangle is 7.7 cm.

Trigonometric ratio is used to show the relationship between the sides and angles of a right angled triangle.

In the right triangle, using trigonometric ratio:

a) sin(31) = h/15

⇒ 0.515 = h/15

Making H the subject of the formula we have:

0.515 x 15 = h/15  x 15

h = 7.725

h \(\approx\) 7,7

Hence, is is correct to state that the value of h in the diagram is 7.7 cm approximately. See the attached image.

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Full Question:

Although part of your question is missing, you might be referring to this full question:

the diagram shows a right-angled triangle. what is the value of h? give your answer correct to 1 decimal place.

The mass percentage of C in morphine would be 4.21%.

The mass percentage of a composition in a compound is the mass of the composition relative to the mass of the entire compound. This can be mathematically expressed as:

Mass percentage = mass of component/mass of substance x 100%

In this case, we are looking for the mass percentage of C in \(C_{17}H_{19}NO_3\).

Molar weight of C = 12 g/mol

Molar mass of  \(C_{17}H_{19}NO_3\) = (12x17) + (1x19) + (14x1) + (16x3)

                                             = 285 g/mol

Mass percentage of C = 12/285

                                     = 4.21% to 2 decimal places.

In other words, the mass percentage of C in morphine is 4.21%.

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If there had been five exons and four introns, the result would have been. The four introns will be forced to loop in order to bring out the adjacent exons together.

An exon is any part of a gene that will be included in the final mature RNA produced by that gene after introns are removed via RNA splicing. Exons refer to both the DNA sequence within a gene and the corresponding RNA transcript sequence. In RNA splicing, introns are removed and exons are covalently joined to form mature RNA. The genome is made up of the entire set of genes for a species, and the exome is made up of the entire set of exons."The concept of the cistron must be replaced by that of a transcription unit," wrote American biochemist Walter Gilbert in 1978.

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Answer:

3000mg

Explanation:

So,

Remember the following:

Let's first find the molality of solution:

Our solute here is C12H22O11. So let's first find the moles of solute dividing the amount in grams provided by the problem by the molar mass:

Answer:

32.52×10¹⁹ atoms

Explanation:

Given data:

Mass of gold = 0.106 g

Number of atoms of gold = ?

Solution:

We will calculate the number of moles first.

Number of moles = mass/molar mass

Number of moles = 0.106 g/ 197 g/mol

Number of moles = 5.4×10⁻⁴ mol

Number of atoms:

1 mole contain 6.022×10²³ atoms

5.4×10⁻⁴ mol ×  6.022×10²³ atoms /1 mol

32.52×10¹⁹ atoms

Answer:

The hydronium ion concentration is 1.0 x 10−6

Answer:

C

Explanation:

Isotopes are versions of the same element but with a different number of neutrons.

The pair that represents isotopes is 28Si and 29Si. Option C is the correct answer.

Isotopes are atoms of the same element that have different numbers of neutrons but the same number of protons. Option C is the correct answer.

A) 28Si and 28S14+: In this pair, the element symbol changes from Si (silicon) to S (sulfur), so they are not isotopes.

B) 28Si and 28A1: In this pair, the element symbol changes from Si (silicon) to Al (aluminum), so they are not isotopes.

C) 28Si and 29Si: In this pair, the element symbol remains the same (Si), but the number of neutrons changes (28 vs. 29), so they are isotopes.

D) 28Si and 28Si4-: In this pair, the charge changes from neutral (Si) to a negative ion (Si4-), so they are not isotopes.

E) 28Si4+ and 28A13+: In this pair, the element symbol changes from Si (silicon) to Al (aluminum), so they are not isotopes.

Based on this analysis, the pair that represents isotopes is C) 28Si and 29Si.

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Answer:

Composition: All hydrocarbons are made up of only two types of atoms: carbon and hydrogen. They are like building blocks that contain carbon and hydrogen stuck together.

Organic Nature: Hydrocarbons are special because they are part of a group of compounds that come from living things or things that were once alive. They have carbon and hydrogen in them, which is what makes them different from other types of compounds.

Explanation:

The reaction order and specific reaction rate constant can be determined by performing the kinetics experiment on irreversible polymerization A. Kinetic experiments can be used to investigate the rate and mechanism of chemical reactions. Chemical kinetics is the study of chemical reactions' speed and pathway.

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Answer:

which property is least helpful in identifying a sample of matter is (B) VOLUME

Explanation:

volume depend on the amount of substance present and are not useful in the identification of a sample of matter. volume is an extensive property so it is not useful identifying the sample of matter.

Explanation:

petrol or bitumen and at least one use of petrol and at least one use of bitumen eg petrol has a lower boiling point and is used as a fuel in cars, bitumen is more viscous and is used to surface roads.Aug 19, 2015

Petrol and bitumen fractions differ in their properties and uses in a number of ways with regard to melting point, viscosity, ignition ,combustion .

Petrol has less number of carbon chains while bitumen has large number of carbon chains.Bitumen has higher melting and boiling point as compared to petrol.

Petrol has higher viscosity as compared to bitumen.It combusts easily while bitumen does not combust completely ,it produces large number of carbon monoxide or soot.

Petrol fractions are used in cars,motorbikes,etc. while bitumen fractions are used in road surfaces and roofing. Boiling point of petrol is 35-70°C while that of bitumen is 700°C.Bitumen is more viscous as compared to petrol.

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Based on the provided steps, we are conducting an experiment involving copper(II) sulfate solution and zinc powder. We are measuring the temperature change that occurs when zinc reacts with copper(II) sulfate.

Measurement:

Initial temperature (°C): This is the temperature of the copper(II) sulfate solution before adding zinc powder. Use a thermometer to measure and record this temperature.

Final temperature (°C): This is the highest temperature reached by the solution after adding the zinc powder and allowing the reaction to occur. Watch the thermometer for a couple of minutes and record the highest temperature observed.

Temperature change (°C): Calculate the difference between the initial and final temperatures. Subtract the initial temperature from the final temperature and record the result as the temperature change.

Follow the steps provided to carry out the experiment and record the corresponding measurements in the table. Make sure to use the pipette to transfer 10 milliliters of copper(II) sulfate solution to test tube 3, then add 0.25 grams of zinc powder to the test tube.

Monitor the temperature using a thermometer and record the initial and final temperatures accurately. Finally, calculate the temperature change by subtracting the initial temperature from the final temperature and record the value in the table.

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The sample that uses the substance that Jacob and Natalie should use to make a cold pack that will do the best job of keeping food cool is sample 2, because it absorbs the most energy (option B).

Endothermic refers to a chemical reaction that absorbs heat energy from its surroundings. This ensures that the temperature of the surroundings is cool or has a lower temperature.

According to this question, Jacob and Natalie are asked by their science teacher to design a warming or cooling device. They make use of certain substances, however, sample 2 has the lowest final temperature of -4°C.

This shows that sample 2 absorbs the most energy, hence, would be the best for keeping the food cool.

The incomplete question is as follows:

Jacob and Natalie are asked by their science teacher to design a warming or cooling device. They decide to design a cold pack that can be used to help keep food cool. Jacob and Natalie read about different substances that can be used inside cold packs and learn that most cold packs use endothermic reactions to cool objects.

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The second time David build a neutron gun he used radium and thorium instead of aluminum.

David was a young boy who decided to build a neutron gun. His story is described in the text "The Radioactive Boy Scout".

David had in mind the idea of building a neutron gun for this he needed radioactive elements such as radium and thorium, which he obtained by deceiving the officials of the Nuclear Regulatory Commission. This was a very dangerous experiment as radioactive elements are a great danger for health.

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1. The constituent gases of air are:

2. The surrounding air is not seen with the eyes because it is transparent. Air molecules are not visible to the na-ked eye, and they do not scatter or absorb visible light significantly. Therefore, air appears colorless and transparent.

3. To prove that air supports burning, you can perform an experiment with a burning candle. Place a glass jar or bell jar over a lit candle, ensuring that the jar is airtight. As the candle burns, it consumes oxygen from the air inside the jar. Eventually, the candle flame will go out due to the lack of oxygen, proving that air (specifically oxygen) is necessary for burning.

4. To show that air occupies space, you can perform a simple experiment using a plastic bottle or syringe. Fill the bottle or syringe with water, ensuring there are no air bubbles. Then, cover the opening tightly and try to compress the air inside. You will find that it is not possible to compress the air significantly, indicating that air occupies space.

5. To prove that air has weight, you can use a sensitive balance or scale. Weigh an airtight container or balloon, and then fill it with air. The weight of the container or balloon with the added air will be greater than its initial weight, demonstrating that air has weight.

6. Air is useful to us in various ways. Three points highlighting the importance of air are:

7. Three properties of air include:

Air exerts force in various ways. For example, air pressure allows objects like airplanes to fly by providing lift. Air resistance or drag opposes the motion of objects moving through the air, creating a force that can affect their speed and trajectory.

8. Four effects of air pollution include:

9. Causes of pollution:

10. Two control measures for air pollution include:

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Answer:

12.6 g O2 or

12.60 g O2 (if needed two decimal places)

Explanation:

First convert grams into moles:

17.4 g KCl × 1

74.55

= 0.233 moles of KCl

Next solve for the mole of O2:

= 0.233 × 3 moles of O2

2 moles of KCl

= 0.3495 or

= 0.350 moles of O2

Finally convert the mole to grams:

= 0.350 moles of O2 × 36g

1 mole

= 12.6 g O2 or 12.60 g O2

Answer:

a car traveled 20m &400k/g

Answer:

Explanation:

Assumptions

Note

The concentrations would merely add. All things change if the assumptions I've made are not true.

Ethyl propanoate is an organic compound that is a member of a family of organic compounds known as esters.

a. The Lewis electron dot diagram for ethyl propanoate is as follows:

H  H    H

|    |     |

C-C-C-O-C

|    |     |

H  CH3-CH2-

b. Each oxygen atom in ethyl propanoate has a hybridization of sp3. The lone pairs of electrons on each oxygen atom occupy two of the hybridized orbitals, while the other two hybridized orbitals form sigma bonds with the carbon and hydrogen atoms.

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