The required magnetic field strength is 1.54×10^-3 T and it must be perpendicular to the plane of the paper and into the paper.
When a charged particle moves through a magnetic field, it experiences a force given by the equation F = qvBsinθ, where F is the force, q is the charge of the particle, v is the velocity of the particle, B is the magnetic field strength, and θ is the angle between the velocity vector and the magnetic field vector.
In this problem, the electron is moving horizontally between the plates, and we want it to pass through the plates without being deflected. This means that the force on the electron due to the electric field between the plates must be equal and opposite to the force on the electron due to the magnetic field.
The force on the electron due to the electric field is given by F = Eq, where E is the electric field strength and q is the charge of the electron. The electric field strength is given by E = V/d, where V is the voltage of the battery and d is the distance between the plates. Substituting the values given in the problem, we get E = 200 V/0.01 m = 2.0×10^4 V/m.
The force on the electron due to the magnetic field is given by F = qvB, where q is the charge of the electron, v is the velocity of the electron, and B is the magnetic field strength. Substituting the values given in the problem, we get F = 1.6×10^-19 C × 1.3×10^7 m/s × B = 2.08×10^-12 B N.
Since the electron is not deflected by the magnetic field, we know that the magnetic force is equal and opposite to the electric force. Therefore, we can equate the two forces and solve for B:
F = Eq
1.6×10^-19 C × 1.3×10^7 m/s × B = 2.0×10^4 V/m × 1.6×10^-19 C
B = (2.0×10^4 V/m × 1.6×10^-19 C)/(1.3×10^7 m/s)
B ≈ 1.54×10^-3 T
The direction of the magnetic field can be found using the right-hand rule. If you point your right thumb in the direction of the electron's velocity (to the right in this case), and your fingers in the direction of the electric field (from positive to negative), then the magnetic field must be directed into the paper (towards you) in order to produce a force that opposes the electric force and allows the electron to pass through the plates without being deflected.
The required magnetic field strength is 1.54×10^-3 T, and it must be perpendicular to the plane of the paper and into the paper.
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Can someone explains questions 4 and 5 and tell me which of my ans are wrong? please.
The values and the description of the motion of the objects under gravity are as follows;
1. The same
2. A smaller
3. A greater
4. 40 m/s
a. 5 m/s directed down
b. 45 m/s
5. a. Upwards
b. B
c. B
d. 10 m/s²
e. 10 m/s²
f. C
What is gravitational acceleration?Gravitational acceleration is the acceleration due to the force of the Earth's attraction or pull on an object.
1. Compared with X, Y has the same acceleration as they fall
2. Compared with X, Y hits the ground with a smaller speed
3. Compared with X, Y has a greater time of descent
4. Assume g = 10 m/s², and that there is no air resistance. A stone is dropped from rest. What is its speed after 4 seconds.
The speed is given by the equation;
v = u + g•t
The velocity of the stone is therefore;
v = 0 + 10 × 4 = 40
The speed of the stone = 40 m/s
a. The initial speed of the stone u = 25 m/s
Therefore;
v = 25 - 10 × 3 = -5
The speed of the stone after 3 seconds is 5 m/s directed down
b. The initial speed of the stone = 15 m/s
Direction of the stone = Downwards
The speed after 3 seconds is therefore;
v = 15 + 10 × 3 = 45
The speed after 3 seconds is 45 m/s
5. a. The speed of the ball at point A is -30 m/s which is upwards, given that the speed is measured in the downward direction
b. The ball is stationary when the speed is 0, which is at point B.
c. The motion is a projectile motion, of an object moving upwards under gravity. The ball reaches its maximum height when its speed is 0, which is at point B.
d. The acceleration of the ball is due to gravity and it is constant. The acceleration at point C is therefore, 10 m/s²
e. The acceleration at point A is 10 m/s²
f. The point where the ball has the same speed as it did at point A is given by the point that is equidistant as point A from the point B where the speed is 0, which is point C.
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Most commonly effective spin recovery for a straight-wing aircraft
a. Stop spin rotation with opposite aileron and lower AOA with Aft Stick
b. Stop spin rotation with aileron into the spin and lower AOA with Aft stick
c. Hold what you got
d. Stop spin rotation with opposite rudder and lower AOA with Forward stick
The most commonly effective spin recovery technique for a straight-wing aircraft is option (d) Stop spin rotation with opposite rudder and lower AOA with Forward stick.
In a spin, an aircraft experiences an uncontrolled and sustained rotating motion around its vertical axis. To recover from a spin, it is crucial to stop the rotation and reduce the angle of attack (AOA) to regain control.
Using the opposite rudder (opposite to the direction of the spin) helps counteract the yawing motion and can help stop the rotation. By applying rudder in the opposite direction, the adverse yaw can be minimized, aiding in spin recovery.
Additionally, lowering the AOA is essential to break the stall and regain control. By pushing the control stick forward (forward stick), the pilot can reduce the AOA, which helps in recovering from the spin.
Combining the use of opposite rudder to stop the spin rotation and lowering the AOA with a forward stick provides a commonly effective spin recovery technique for straight-wing aircraft.
Therefore, the correct answer is d) Stop spin rotation with opposite rudder and lower AOA with Forward stick.
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What is a bond between a positive and a negative ion charge?
Answer:
Ionic Bond
Explanation:
Answer:
An ionic bond
A young student drops a stone off the side of a cliff that is 41 meters high. How long does it take the stone to hit the ground below?
A)
2.89 s
B)
8.36 s
C)
3.20 s
D)
2.04 s
If a police car is travelling towards you what effect does this have on the police
siren?
Answer:
well they make the siren go beacaus eyou are doing somthing wrong so what were you thinking
Explanation:
A truck accelerating at 0.0083 meters/second2 covers a distance of 5.8 × 104 meters. If the truck's mass is 7,000 kilograms, what is the work done to reach this distance?
A. 1.7 × 106 joules
B. 3.4 × 106 joules
C. 5.6 × 106 joules
D. 6.8 × 106 joules
A truck accelerating at 0.0083 meters/second2 covers a distance of 5.8 ×\(10^4\) meters. If the truck's mass is 7,000 kilograms, the work done to reach this distance is 3.3× \(10^6\) joules.
The correct answer is option E.
To calculate the work done by the truck to cover a distance of 5.8 × \(10^4\)meters, we need to use the equation for work:
Work = Force × Distance
In this case, the force can be calculated using Newton's second law:
Force = mass × acceleration
Where:
Acceleration (a) = \(0.0083 meters/second^2\)
Distance (d) = 5.8 ×\(10^4\) meters
Mass (m) = 7,000 kilograms
First, let's calculate the force exerted by the truck:
Force = mass × acceleration = (7,000 kg) ×\((0.0083 meters/second^2)\)= 57.1 Newtons
Next, we can calculate the work done:
Work = Force × Distance = (57.1 N) × (5.8 × 10^4 meters) = 3.3158 × \(10^6\)joules
Rounded to the nearest significant figure, the work done by the truck is approximately 3.3 × \(10^6\) joules.
Therefore, the correct answer is E.
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The question probable may be:
A truck accelerating at 0.0083 meters/second2 covers a distance of 5.8 ×\(10^4\)meters. If the truck's mass is 7,000 kilograms, what is the work done to reach this distance?
A. 1.7 × \(10^6\) joules
B. 3.4 ×\(10^6\) joules
C. 5.6 × \(10^6\)joules
D. 6.8 × \(10^6\)joules
E. 3,3 ×\(10^6\) joules
- A periodic composite signal with a bandwidth of 2000 Hz is composed of two sine waves. The first one has a frequency of 100 Hz with a maximum amplitude of 20 V; the second one has a maximum amplitude of 5 V. Draw the bandwidth. - A TV channel has a bandwidth of 6MHz. If we send a digital signal using one channel, what are the data rates if we use one harmonic, three harmonics, and five harmonics?
The bandwidth of the periodic composite signal is drawn as a range between 100 Hz and 2100 Hz , The data rates for sending a digital signal using one harmonic, three harmonics, and five harmonics on a TV channel with a 6 MHz bandwidth would be 6 MHz, 18 MHz, and 30 MHz .
For the first question
Draw the bandwidth of a periodic composite signal, we need to consider the highest frequency component present in the signal.
We have two sine waves one with a frequency of 100 Hz and the other unspecified. Since the bandwidth is given as 2000 Hz, we can assume that the second sine wave has a frequency of 2100 Hz (2000 Hz above the first sine wave frequency).
Draw the bandwidth, we can create a graph with frequency on the x-axis and amplitude on the y-axis.
We plot the amplitude values for the two sine waves at their respective frequencies (100 Hz and 2100 Hz). The bandwidth will be the range between these two frequencies on the x-axis.
For the second question
The data rate for a digital signal transmitted using one harmonic, three harmonics, and five harmonics can be calculated by multiplying the channel bandwidth by the number of harmonics used. Since the bandwidth is given as 6 MHz, the data rates would be as follows:
One harmonic: 6 MHz
Three harmonics: 18 MHz
Five harmonics: 30 MHz
The data rate increases with the number of harmonics used because each harmonic contributes additional information to the signal, allowing for a higher data transmission rate.
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a sled and rider (combined mass of 79 kg) finish a downhill run with a speed of 31 m/s, then enter a flat (horizontal) area where the sled slows down at a constant rate of -1.82 m/s2 until it stops. what distance did the sled move while slowing down?
The sled moved a distance of 293.9 meters while slowing down.
To solve this problem, we can use the kinematic equation:
\(v^{2} = u^{2} +2as\)
where v is the final velocity, u is the initial velocity, a is the acceleration, and s is the distance.
Before the sled starts slowing down, its velocity is 31 m/s. When it comes to a stop, its velocity is 0 m/s. Therefore, the initial velocity u is 31 m/s and the final velocity v is 0 m/s.
The acceleration of the sled while it is slowing down is -1.82 m/s^2 (negative because it is in the opposite direction of the sled's initial velocity).
Substituting these values into the kinematic equation, we get:
\(0^{2} = 31^{2} +2(-1.82)s\)
Solving for s, we get:
\(s = (0-31^{2})/2(2(-1.82)) = 293.9 meters\)
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A bus is travelling at 10m/s. It accelerates at 2m/s^2 over a distance of 20m. Calculate it's final velocity
Answer:
13.4 m/s
Explanation:
Given:
Δx = 20 m
v₀ = 10 m/s
a = 2 m/s²
Find: v
v² = v₀² + 2aΔx
v² = (10 m/s)² + 2 (2 m/s²) (20 m)
v = 13.4 m/s
1. Se tienen 10 moles de gas nitrógeno molecular: N2 en un recipiente a 400 K. Manteniendo la temperatura a 400 K y las 10 moles en el recipiente se disminuye la presión desde 10 atm a 1 atm para obtener un volumen final del gas de 20 litros. El volumen inicial del gas a. 0,5 litros b. 2 litros c. 100 litros d. 200 litros
Answer:
B. 2 litros.
Explanation:
De acuerdo con el enunciado, el gas experimenta un proceso isotérmico y se conserva su masa. Asumiendo que el gas se comporta idealmente, tenemos la siguiente relación entre los estados final e inicial:
\(P_{1}\cdot V_{1} = P_{2}\cdot V_{2}\) (1)
Donde:
\(P_{1}, P_{2}\) - Presiones inicial y final, medidos en atmósferas.
\(V_{1}, V_{2}\) - Volúmenes inicial y final, medidos en litros.
Si sabemos que \(P_{1} = 10\,atm\), \(P_{2} = 1\,atm\) y \(V_{2} = 20\,L\), entonces el volumen inicial del gas es:
\(V_{1} = \frac{P_{2}\cdot V_{2}}{P_{1}}\)
\(V_{1} = 2\,L\)
Por lo tanto, la respuesta correcta es B.
he first right-hand rule relates which two quantities?
A.
current (thumb) to magnetic field (fingers)
B.
magnetic field (thumb) to current (fingers)
C.
current (thumb) to force (fingers)
D.
force (thumb) to current (fingers)
Reset Next
Answer: A.
current (thumb) to magnetic field (fingers)
Answer:
A. current (thumb) to magnetic field (fingers)
Explanation:
According to the Right-Hand Thumb rule, if we are holding a current- carrying straight conductor in our right hand such that the thumb points toward the direction of current, then the fingers will wrap around the conductor in the direction of the field lines of the magnetic field.
Hope it helps.
If you have any query, feel free to ask.
a girl is riding her bike and coasting down a hill. When she gets to the bottom of the hill, her bike continues to move without her pedaling. What type of energy is her bike using ?
a. potential
b. kinetic
c. solar
d. thermal
y’all, i have so many more questions
Answer:
Her bike is using kinetic energy
B
Explanation:
Why is Pizza so good?
Answer:
its the cheese
Explanation:
answer fast , is si unit newton/meter square or pascal or both
Answer:
Both
Explanation:
The S.I. unit of pressure is newton/meter square or pascal as both represent the same dimensional value.
a 4.50-v battery is connected across the primary coil of a transformer having 20 turns. if the secondary coil of the transformer has 40 turns, what voltage appears across the secondary?
A constant flux travels through the secondary coil as a result of the battery's production of a constant current in the first coil. There is no induced voltage across the secondary coil if the flux through the secondary coil remains unchanged.
The value of induced current depends on the change in the flux which is produced due to the change in current in the primary coil, since the voltage is constant the current across the coil is also constant which results in 0 change in flux across the secondary coil which will result in no voltage.
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what is the work done when a 400.n force is use to lift a 400.n object 3.5 meters strait up
Answer:
i think it's 1400
Explanation:
w = Force x displacement
w = 400 x 3.5
Two solid spheres, both of radius 5cm, carry identical total charges of 2μC. Sphere A is a good conductor.Sphere B is an insulator, and its charge is distributed uniformly throughout its volume.
How do the magnitudes of the electric fields they separately create at radius 4 cm compare?
The magnitudes of the electric fields they are separately create at the radius 4 cm is the correct option is C. EA = EB > 0.
Two solid spheres, both of the radius 5cm, they carry the identical total charges of the 2μC. Sphere A is the good conductor. Sphere B is an insulator, and the charge are distributed uniformly throughout the volume. Both the spheres are produce the identical fields at the outer locations, the like particles will do at the cores, because of the spherically symmetric charge distributions.
The magnitudes of the electric fields they are separately create at the radius 4 cm is EA = EB > 0.
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LED lights will only work if the current is flowing in one direction. Which type of current would be best for powering an LED light bulb?
A.
Alternating current (AC) because with AC, the current flows steadily in one direction.
B.
Direct current (DC) because with DC, the current flows steadily in one direction.
C.
Direct current (DC) because DC provides more power but over shorter distances.
D.
Alternating current (AC) because with AC, the current periodically reverses.
Answer:
c
Explanation: i took the same text and got a 90
Direct current (DC) would be best because with DC, the current flows steadily in one direction. correct answer be Option (B).
What are direct current and alternating current?There are two main methods for creating electric current. Direct current (DC) and alternating current (AC) are these (AC).
Direct current is a technique in which electricity consistently flows in the same direction, like the flow of a river. It discusses how electricity generated by solar panels, batteries, and other sources flows.
On the other hand, alternating current (AC) is a method in which the positive and negative sides are alternately switched at regular intervals, thereby altering the direction of the energy flow. This is the electricity that is provided by a plug-in or a generator. Both the electricity generated at power plants and the electricity delivered to homes are transmitted using alternating current.
So, Direct current (DC) would be best for LED lights will only work if the current is flowing in one direction.
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What is the period of a wave that has a frequency of 30 Hz?
A. 0.3s
B. 0.03 s
C. 30 s
D. 35
Answer:
0.03s
Explanation:
Period of wave and its frequency are closely related. Period is the inverse of frequency.
The period of a wave is the time taken for a number of waves to pass through a particular point.
The frequency of a wave is the number of waves that passes through a point at a particular time.
So;
f = \(\frac{1}{T}\)
f is the frequency
T is the period
Period of the wave = \(\frac{1}{30}\) = 0.03s
Answer:
a
Explanation:
Tom is sitting facing forward in the train as it is getting ready to leave the station. He puts a smooth ball on the train floor. The train jolts into motion, accelerating rapidly up to speed. According to Newton's first law of motion, what happens to the ball?
According to Newton's first law of motion, the ball also moves with train .
According to Newton's first law of motion "An object at rest remains at rest, or if in motion, remains in motion at a constant velocity unless acted on by a net external force".
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A current was sent through a helical coil spring. the spring contracted, as though it had been compressed. why?
The helical coil spring contracts as if compressed when the current flows through it. This is because of the magnetic force generated by the magnetic field and the current flowing through the coil.
An electromagnet is the type of magnet that generates a magnetic field by using an electric current. The magnetic field is created when a current is passed through a wire wrapped around an iron core, which produces a magnetic field around the wire. A helical coil spring is a mechanical spring that is made by winding a wire around a cylinder or a cone-shaped object. The shape of the spring is a helix or a spiral, which is why it is called a helical spring.
The reason why the spring contracts when a current is passed through it is due to the magnetic force produced by the magnetic field and the current flowing through the coil. When the current flows through the wire, it creates a magnetic field around the wire. The magnetic field exerts a force on the spring, causing it to contract or expand depending on the direction of the current flow.
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what is the separation in meters between two slits for which 604 nm orange light has its first maximum at an angle of 29.2°?
The separation between two slits for which 604 nm orange light has its first maximum at an angle of 29.2° is approximately 1.63 x 10^(-6) meters.
To calculate the separation between the slits, we can use the equation for the position of the first maximum in a double-slit interference pattern:
sin(θ) = mλ / d
where θ is the angle of the maximum, m is the order of the maximum (which is 1 for the first maximum), λ is the wavelength of light, and d is the separation between the slits.
Rearranging the equation, we can solve for d:
d = mλ / sin(θ)
Substituting the given values:
d = (1)(604 nm) / sin(29.2°)
Converting the wavelength to meters (1 nm = 1 x 10^(-9) meters) and performing the calculation, we get:
d ≈ (1)(604 x 10^(-9) meters) / sin(29.2°)
d ≈ 1.63 x 10^(-6) meters
Therefore, the separation between the two slits is approximately 1.63 x 10^(-6) meters.
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HURRRY PLEASSSSEEE
Energy required for cellular respiration can be processed from ____.
A) Carbohydrates
B) Fats/ Lipids
C) Proteins
D) All of the above
Answer:
fats / liquids or proteins one of them
Explanation:
..........
Answer:
D) All of the above
Explanation:
I googled it :)
The picture shows a bicycle’s pedals. Look at the shaft that the pedals are attached to. Do you think the shaft is a lever? Why or why not?
Answer:
yes
Explanation:
A shaft instead of a chain to transmit power from the pedals to the wheel.
Yes, the shaft that the pedals are attached to in a bicycle can be considered a lever.
A lever is a simple machine that consists of a rigid object that rotates around a fixed point called the fulcrum. In the case of the bicycle pedals, the shaft acts as the lever arm, and the fulcrum is the point where the shaft is attached to the bicycle frame.
The characteristics of a lever apply to the shaft in the bicycle pedals:
1. Fulcrum: The fixed point of rotation in the lever system is provided by the bearing or axle that holds the shaft in place on the bicycle frame. This allows the shaft to rotate freely.
2. Effort and Load: The rider applies an effort or force on the pedals by pushing down with their feet. This effort is transmitted to the shaft, which in turn rotates the bicycle's crankset.
3. Mechanical Advantage: The shaft in the bicycle pedals can provide mechanical advantage by amplifying the force applied by the rider. By having longer pedals or using different gear ratios, the effective lever arm length can be modified, allowing the rider to exert more force with less effort or cover a greater distance with each pedal stroke.
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2. John starts up his hoverboard, and glides down a track for 10 seconds. He reaches a top
velocity of 36m/s. What is Bader's average acceleration?
The average acceleration of John is 3.6 m/s.
As we know the acceleration of an object is the rate of change of its velocity concerning the time, it is a vector quantity which means it both has direction and magnitude, the orientation of the object depends on the orientation of the total force acting on the object.
As we are given that the initial velocity, u= 0 ms/s( as it started with rest) and the time taken, t= 10 seconds, the final velocity , v= 36 m/s.
As the formula, we can prefer the calculation of the acceleration of an object, which is one of the equations of the motion
v = u+at
Here a= v-u/t
= 36-0/10
= 3.6 m/s
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a u-tube is rotated as 50 rev/min about one leg. the fluid at the bottom of the u-tube has a specific gravity of 4.0. a 6in height of another fluid is in the outer leg of the u-tube. both legs are open to the atmosphere. calculate the specific gravity of the other fluid
The specific gravity of the other fluid is 2.0.
We know that the specific gravity of the fluid at the bottom of the u-tube is 4.0, which means its density is 4 times the density of water. Since the density of water is 62.4 lb/ft^3, the density of the fluid is:
ρ_1 = 4 * 62.4 lb/ft^3 = 249.6 lb/ft^3
We also know that the height of the fluid in the outer leg is 6 inches, or 0.5 feet. Substituting these values into the equation, we get:
P_atm + 249.6 lb/ft^3 * g * 0.5 ft = P_atm + ρ_2 * g * 0.5 ft
Simplifying and canceling out P_atm and g, we get:
124.8 lb/ft^3 = ρ_2
Therefore, the specific gravity of the other fluid is,
SG = ρ_2 / ρ_water = 124.8 lb/ft^3 / 62.4 lb/ft^3 = 2.0
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2. what happened to the diffraction pattern as you increased the width of the slit?
As the width of the slit in a single-slit diffraction experiment is increased, the diffraction pattern becomes narrower and less intense.
Single-slit diffraction is a phenomenon that occurs when a beam of light passes through a narrow slit, causing the light waves to diffract, or spread out, into a pattern of bright and dark fringes on a screen located behind the slit. This effect can be observed when monochromatic light, such as from a laser or a narrowband filter, is shone through a thin slit that is narrower than the wavelength of the light.This is because a wider slit allows more light to pass through, resulting in a wider central maximum. However, the wider slit also allows more diffraction of light around the edges of the slit, resulting in additional interference patterns, or secondary maxima, on either side of the central maximum. As the width of the slit is increased, the interference from these secondary maxima becomes weaker, resulting in a narrower and less intense diffraction pattern.
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How far can a person run in 13.22 minutes if he or she runs at an average speed of 12.33 km/hr?
Answer:
2.72 km
Explanation:
(12.33 km)/ 1 hr * (1 hr)/ 60 min
0.2055 km/ min
distance=rate * time (assuming v is constant,
a=0)
(0.2055 km/ min)*(13.22 min)
2.72 km OR 2716.71 m
which is a dopant for a p-type semiconductor?
a. arsenic
b. indium
c. phosphorus
d. antimony
A website is having a sale, and all items are 25% off the original price, p
Which expressions can be used to find the price of an item after the discount?
Select all that apply
Α.
0.75
B
1.25
CP_25
DP - 0.25
E 001P x 75