An electron travels 3.31 m in 5.83 x 10 to the -8 s. How fast is it traveling?

Answer:

The acceleration of the sled is "0.49 m/s²". A further explanation is given below.

Explanation:

The given values are,

Speed,

V = 4.0 m/s

Coefficient of kinetic friction,

μ = 0.05

As we know,

⇒  \(F \mu=\mu mg\)

and,

⇒  \(a = \mu g\)

On substituting the given values, we get

⇒     \(=0.0 5\times 9.8\)

⇒     \(=0.49 \ m/s^2\)

As a general rule, water pipes should be separated from sewer pipes by a horizontal distance of 10 ft.

Water mains shall be laid at least 10 feet horizontally from any sanitary sewer, or sewer manhole, whenever possible; the distance shall be measured edge-to-edge (pipe wall to pipe wall). The minimum fall for a waste pipe is 1 in 40. The maximum fall is 1 in 110 (apart from vertical pipes but that's a different story). So pipes with a gradient between 1 in 40 and 1 in 110 should have adequate flow to prevent blockages from occurring.In other words, for every 100 feet the pipe travels horizontally, it should drop about half a foot vertically. .

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Answer:

a) t = 14.2 s ,  v = -92 m / s , b) v = - 59.16 m / s ,   t = 0.916 s

c)  t = 7.75 s ,   x = 387.5 m

d) t = 10.64 s , x = 463.9 m ,   v = 92.2 m / s

Explanation:

This is an exercise in kinematics, suppose we take the upward direction as positive

a) is thrown up vertically.

Let's use the equation

          y = y₀ + v₀ t - ½ g t²

When reaching the ground y = 0, the initial height is y₀ = 300 m and the initial velocity is v₀ = + 50m / s, to simplify we use g = 10 m /s² as the value of the acceleration of gravity, for a more exact calculation we can must use 9.80 m /s²

         0 = y₀ + v₀t - ½ g t²

         ½ 10 t² - 50 t - 300 = 0

Let's solve the quadratic equation

         t² - 10 t - 60 = 0

         t = [10 ±√ (10² + 4 60)] / 2

         t = [10 ± 18.4] / 2

         t₁ = 14.2 s

         t₂ = -4.2 s

since time must be a positive quantity, the correctors result t = 14.2 s

the speed at this point is

         v = v₀ - g t

         v = 50 - 10 14.2

         v = -92 m / s

the sign indicates that the body is going down

b) in this case the initial velocity is vo = -50 m / s

let's calculate the velocity on the ground

    v² = v₀² - 2g (y-y₀)

    v² = 50 2 - 2 10 ((0- 300)

    v² = 3500

    v = + - 59.16 m / s

as the body is going down the correct sign is the negative

    v = - 59.16 m / s

the time it takes to arrive is

        v = v₀ - g t

        t = (v₀ - v) / g

        t = (-50 + 59.16) / 10

        t = 0.916 s

c) the velocity is horizontal (vox = 50 m / s), this implies that the vertical velocity is zero voy = 0

         y = y₀ + v₀ t - ½ g t²

         0 = 300 + 0 - ½ 10 t²

         t = √ (2 300/10)

         t = 7.75 s

the horizontal displacement at this time is

        x = v₀ₓ t

        x = 50 7.75

        x = 387.5 m

d) as it is thrown with an angle let's find each component of the velocities

      v₀ₓ = v₀ cos 30

      \(v_{oy}\) = v₀ sin 30

       v₀ₓ = 50 cos 30 = 43.3 m / s

       v_{oy} = 50 sin 30 = 25 m / s

we look for the time of descent

     y = y₀ + v_{oy} t - ½ g t²

     0 = y₀ + v_{oy} t - ½ g t²

     0 = 300 + 25 t - ½ 10 t²

     t² - 5t - 60 = 0

   we solve the second degree equation

     t = [5 ±√ (5² + 4 60)] / 2

     t = [5 ± 16.28] / 2

     t₁ = 10.64 s

     t₂ = -5.64 s

since the time must be positive the result is t = 10.64 s

the range on the x axis is

       x = v₀ₓ t

       x = 43.6 10.64

       x = 463.9 m

the ground speed is

      v_{y} = \(v_{oy}\) - g t

      v_{y} = 25 - 10 10.64

      v_{y} = -81.4 m / s

speed is

       v = √ (v₀ₓ² + v_{y}²)

       v = √ (43.3² + 81.4²)

       v = 92.2 m / s

Answer:Answer:

They are inhaled or eaten

Explanation:

Radioactivity can be defined as the process in which an unstable atomic nucleus spontaneously emits ionizing radiation and charge particles. This eventually results in the formation of an energetically stable atomic nucleus.

Examples of radioactive elements are Uranium, Polonium, Thorium, Radon, etc. The radiation emitted during this process is classified as;

1. Alpha radiation (α).

2. Beta radiation (β).

3. Gamma radiation (G).

Alpha-emitting substances, such as radon gas, can be a serious health hazard only if they are inhaled or eaten. Alpha-emitting substances compared to other radiation has very short-range particle and as such cannot penetrate the human skin or body.

Answer:· Relationship between Energy Transferred, Current, Voltage and Time. The potential difference or voltage, V across two points is defined as the energy, E dissipated or transferred by a coulomb of charge, Q that moves through the two points. Therefore, potential difference, Current is the rate of charge flow.

Explanation:

Relationship between Time, Current, Voltage, and Transferred Energy The energy, E, dissipated or transferred by a coulomb of charge, Q, which passes through the two places, is described as the potential difference or voltage, V across two points.

An electric circuit, also known as an electrical circuit, is a conductor used to move current or electricity. To connect the source of power to the load, a conductive wire is utilized. Between the supply and the load, an ON/OFF switch and a fuse are also employed.

The rate of charge flow is therefore determined by potential difference and current.

A circuit is said to be open when an electrical line, electronic device, or switch is malfunctioning or when the switch is off. You can see in the diagram below that the bulb is not lighting because either the switch is turned off or an electrical line is faulty.

Therefore, Relationship between Time, Current, Voltage, and Transferred Energy The energy, E, dissipated or transferred by a coulomb of charge, Q, which passes through the two places, is described as the potential difference or voltage, V across two points.

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The orbital period for Exoplanet A is estimated to be 18.4 days based on the time between two transit events observed on the graph. This calculation assumes a regular and consistent orbital pattern, but the actual period may vary slightly due to factors like orbital eccentricity.

The first transit event occurs at day 10.5 on the graph. The second transit event occurs at day 28.9 on the graph. The time between these two events is 28.9 - 10.5 = 18.4 days.

It is important to note that this is just an estimate of the orbital period. The actual orbital period may be slightly different due to factors such as the eccentricity of the orbit.

Here are the steps I took to calculate the orbital period:

The orbital period for Exoplanet A is 18.4 days.

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The time constant (in ms) of the RC circuit is 3.75 ms. Hence, the correct option is  (d) 3.75 ms.

The rate of decay of the current in a charging capacitor is proportional to the current in the circuit at that time. Therefore, it takes longer for a larger current to decay than for a smaller current to decay in a charging capacitor.A capacitor is discharged through a 20.0 Ω resistor.

The discharge current decreases to 22.0% of its initial value in 1.50 ms. We can obtain the time constant of the RC circuit using the following formula:$$I=I_{o} e^{-t / \tau}$$Where, I = instantaneous current Io = initial current t = time constant R = resistance of the circuit C = capacitance of the circuit

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The time constant of the RC circuit is approximately 0.674 m s.

To determine the time constant (τ) of an RC circuit, we can use the formula:

τ = RC

Given that the discharge current decreases to 22.0% of its initial value in 1.50 m s, we can calculate the time constant as follows:

The percentage of the initial current remaining after time t is given by the equation:

I(t) =\(I_oe^{(-t/\tau)\)

Where:

I(t) = current at time t

I₀ = initial current

e = Euler's number (approximately 2.71828)

t = time

τ = time constant

We are given that the discharge current decreases to 22.0% of its initial value. Therefore, we can set up the following equation:

0.22 =\(e^{(-1.50/\tau)\)

To solve for τ, we can take the natural logarithm (ln) of both sides:

ln(0.22) = \(\frac{-1.50}{\tau}\)

Rearranging the equation to solve for τ:

τ = \(\frac{-1.50 }{ ln(0.22)}\)

Calculating this expression:

τ ≈ 0.674 m s

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If a company assigns factory Labour to production at a cost of $84,000 when the standard cost is $80,000, it will have a Labour Price Variance. The Labour Price Variance measures the difference between the standard labour rate and the actual labour rate.

The formula for Labour Price Variance is:

Labour Price Variance = (Standard Labour Rate - Actual Labour Rate) * Actual Labour Hours

In this case, the Labour Quantity Variance is given as $4,000. The labour Quantity Variance measures the difference between the standard labour hours allowed for the actual production and the actual labour hours used.

Since the Labour Quantity Variance is provided.

Actual Labour Hours = Standard Labour Hours Allowed - labour Quantity Variance

Here, the Labour Quantity Variance is $4,000. Assuming the standard Labour hours allowed are equal to the actual Labour hours used, we can determine the Actual Labour Hours.

Actual Labour Hours = Standard Labour  Hours Allowed - Labour Quantity Variance

Actual Labour Hours = Standard Labour Hours Allowed - $4,000

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Answer:

The x - component of vector B is determined as -18.3 m.

What is x-component of  a vector?

The x-component  or horizontal component of a vector is the value of the vector acting or pointing x direction  or in a horizontal direction.

The x-component or horizontal component of a vector on a given plane calculated as follows;

Bx = B cos(θ)

where;

The given parameters include the following;

Substitute the given parameters into the above equation and for the x-component of vector b.

Bx = 18.6 x cos(170)

Bx = -18.3 m

Thus, from the magnitude of vector B in the image, the value of vector B in x - direction is -18.3 m.

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Answer:

Part A

The power to turn on the lamp, ∑P = 3.36 W

Part B

The Resistor required is approximately 8.04 Ohms

Part C

The time for all the lights to go out is approximately 21.43 hours

Explanation:

The input voltage of the motor battery , V = 12 V

The capacity of the battery, Q = 6 Ah

The number of lamps in parallel = 8 lamps

The maximum voltage of each lamp,  = 3 V

The electric current in each lamp = 140 mA

The energy available in a battery, E = Q × V

For the battery, we have;

E = 6 Ah × 12 V = 72 Wh

The energy available in a battery, E = 72 Wh

Part A

The power used by the lamps, \(P_i\) = \(I_i\) × \(V_i\)

∴ The total power used by the lamp, ∑P = 8 × 0.14 A × 3 V = 3.36 W

The power to turn on the lamp, ∑P = 3.36 W

Part B

The resistance required, is given as follows;

Resistor required = (Battery voltage - Lamp voltage)/(The sum of bulb current)

∴ Resistor required = (12 V - 3 V)/(8 × 0.14 A)

The Resistor required = 8.03571429 Ohms

The Resistor required ≈ 8.04 Ohms

Part C

The time for all the lights to go out = The time for the lamps to use all the power available in the battery

The time for all the lights to go out, t = E/∑P

∴ t = 72 Wh/(3.36 W) = 21.4285714 h

∴ The time for all the lights to go out, t ≈ 21.43 h

The time for all the lights to go out = The time for the lamps to use all the power available in the battery = t ≈ 21.43 h

∴ The time for all the lights to go out ≈ 21.43 hours.

Answer:

B 2m/s2

Explanation:

Givens: m=10kg F=20N

Solution:

\(F=m\cdot a\)

\(a=\frac{F}{m}\)

\(a=\frac{20}{10}\)

\(a=2\ \frac{m}{s^{2}}\)

Therefore, the answer is B

On planets like Venus, Earth, and Mars do not see as many craters because most of them have been eroded away by wind, rain or volcanic activity. We do not see any craters Jupiter, Saturn, Uranus, and Neptune because there is no visible solid surface for the meteors to hit.

Craters heavily dominate the surfaces of Mercury and the Earth's Moon because both the bodies lack water on their surfaces that would erode impact craters with time. They also lack an atmosphere which could disintegrate meteoroids before they impact the surface.

As smaller planets have less gravitational pull as compared to large planets therefore impactors will strike at lower speeds. Greater is the mass of the impactor, greater is the size of crater. Craters are often circular.

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The leaf goes back to the vertical position due to grounding, caused by the excess charge flowing through Alan's body to the ground.

The human body is a good conductor of electricity and can easily transfer excess charge to the ground. Therefore, when Alan touched the electroscope, his body provided a path for the excess charge to flow from the electroscope to the ground, causing the leaf to lose its charge and return to its neutral position. This process of grounding occurs when excess charge flows from the charged object to the ground through a conductor.

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Answer:

.

Fusion powers the Sun and stars as hydrogen atoms fuse together to form helium, and matter is converted into energy.

nuclear fission reactors include the possibility of radiation-releasing nuclear accidents, the problems of radioactive waste disposal, and the possibility of contributing to nuclear weapon proliferation

Therefore, the minimum thickness of the soap film that will produce cancellation in the reflected light is approximately 96.2 nanometers.

When light reflects from a thin film, interference can occur between the reflected wave and the wave that travels directly back through the air. If the difference in the path lengths of these two waves is an integer multiple of the wavelength, destructive interference occurs and the reflected light is canceled out.

The condition for destructive interference in a thin film is:

2nt = (m + 1/2)λ

where n is the refractive index of the film, t is the thickness of the film, λ is the wavelength of the incident light in air, and m is an integer that represents the order of interference.

In this case, we want to find the minimum thickness of the soap film that will produce cancellation in the reflected light, so we can set m = 0:

2nt = (0 + 1/2)λ

t = λ/4n

Substituting the given values, we get:

t = (500 nm) / (4 × 1.3)

= 96.2 nm

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A collision that is fully elastic is one where there is no kinetic energy lost during the contact. In an inelastic collision, a proportion of the energy is converted into another kind of energy during the contact.

In elastic collisions, kinetic energy and momentum are both conserved. Consider two similar trolleys that are moving in the same direction at the same pace. With no loss of speed, they collide and bounce off one another. Since no power has been lost, this collision is fully elastic.

photo of A description of completely elastic collision

When a system's maximal quantity of kinetic energy is equal to zero, a relatively inelastic collision takes place.

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A collision that is fully elastic is one where there is no kinetic energy lost during the contact. In an inelastic collision, a proportion of the energy is converted into another kind of energy during the contact.

In elastic collisions, kinetic energy and momentum are both conserved. Consider two similar trolleys that are moving in the same direction at the same pace. With no loss of speed, they collide and bounce off one another. Since no power has been lost, this collision is fully elastic.

photo of A description of completely elastic collision

When a system's maximal quantity of kinetic energy is equal to zero, a relatively inelastic collision takes place.

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Answer:

An atom with a closed shell of valence electrons (corresponding to an electron configuration s2p6) tends to be chemically inert. An atom with one or two valence electrons more than a closed shell is highly reactive, because the extra valence electrons are easily removed to form a positive ion.Explanation:

Answer:

C. 7.3 kg

Explanation:

The weight of the shelf can be calculated using the equation:

W = mg

where m is the mass of the shelf and g is the acceleration due to gravity (10 m/s^2).

Since the tension in each wire is equal and equal to 80 N, the total tension in the two wires is 80 N + 80 N = 160 N.

The horizontal component of the tension in each wire can be calculated using the equation:

T_horizontal = T * cos(25)

where T is the tension in each wire and 25 is the angle between the wire and the horizontal.

The horizontal component of the tension in each wire is equal to the weight of the shelf, so we can set the two equal:

T_horizontal = W

80 * cos(25) = W

W = 80 * cos(25) = 74.17 N

Finally, we can calculate the mass of the shelf using the equation for weight:

m = W / g

m = 74.17 / 10

m = 7.417 kg

Therefore, the mass of the shelf is approximately 7.417 kg, which is closest to option C, 7.3 kg.

Answer :

C

Explanation:

When tensional stresses pull crust apart, it breaks into blocks that slide up and drop down along normal faults. The result is alternating mountains and valleys, known as a basin-and-range.

Answer:

by finding melting and boiling points

Explanation:

Answer:

Simple chemical tests can be used to identify the presence of various elements or classes of molecules (Tollen's test). ... Electron spin resonance (ESR): Also referred to as electron paramagnetic resonance (EPR), this method uses the spins of unpaired electrons in molecules to determine structure

The ball was thrown from a height of 15.82 meters above the ground.

To find the height from which the ball was thrown, we can use the equations of motion for vertical and horizontal motion individually.

First, we know that the horizontal velocity of the ball is constant, so we can use the equation:

distance = velocity * time

We know the distance (58 m) and the velocity (26 m/s) of the ball, so we can find the time it takes for the ball to travel 58 m:

time = distance/velocity

time = 58 m / 26 m/s

Now we can use this time to find the height from which the ball was thrown. Since the vertical motion of the ball is affected by gravity, we can use the equation:

vertical distance = initial vertical velocity * time + (1/2) * acceleration due to gravity * time^2

Since the ball was thrown horizontally, its initial vertical velocity is 0 m/s. The acceleration due to gravity is 9.8 m/s^2 (going down).

We can substitute the values into the equation:

\(height = 0 m/s * time + (1/2) * 9.8 m/s^2 * time^2\)

\(h = (1/2) * 9.8 m/s^2 * time^2\)

\(h = (1/2) * 9.8 m/s^2 * (58 m / 26 m/s)^2\)

height = 15.82 m

Therefore, the ball was thrown from a height of 15.82 meters above the ground.

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Answer:

Explanation:

The Law of reflection states that angle of incidence equals angle of reflection.

So Angle of reflection is 14° also.

In this process, the volume of the gas is held constant. This is because when a gas is heated, it expands. If the volume of the gas is held constant, then the pressure of the gas must also be held constant.

What is gas?
One of the four basic states of matter is gas. Individual atoms may make up a pure gas (such as a noble gas such as neon), elemental molecules made of a single type of atom (such as oxygen), as well as compound molecules made of a number of different atoms (e.g. carbon dioxide). A variety of pure gases can be found in a gas mixture like air. The vast distance between each individual gas particle is what separates gases from liquids and solids. A colourless gas is typically rendered invisible to a human observer by this separation. Between the liquid as well as plasma states, where the latter sets the upper temperature limit for gases, is where matter is in its gaseous state. Degenerative quantum gases, which encircle the lower end of a temperature scale, are receiving more and more attention.

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To find the angle between the wire and the 1.3 T magnetic field, we can use the formula for magnetic force on a current-carrying wire: F = I * L * B * sinθ

Where F is the magnetic force, I is the current, L is the length of the wire, B is the magnetic field strength, and θ is the angle between the wire and the magnetic field. We can rearrange this formula to solve for the angle:
sinθ = F / (I * L * B)
Substituting the given values, we get:
sinθ = 0.65 N / (2.5 A * 0.475 m * 1.3 T)
sinθ ≈ 0.275
θ ≈ arcsin(0.275) ≈ 16.2°
For part (b), if the wire is rotated to make an angle of 90° with the field, the magnetic force becomes:
F' = I * L * B * sin(90°)
Since sin(90°) = 1, the force becomes:
F' = 2.5 A * 0.475 m * 1.3 T ≈ 1.54 N

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Answer:

Yo dude, if you had a beaker of liquid in outer space, it wouldn't push down on the bottom or the sides of the beaker like it would on Earth. In space, there's no gravity to make the liquid settle down, so it forms a round shape because of surface tension. So basically, the liquid would just float around in a ball inside the beaker. If you moved the beaker around, the liquid would just roll around with it like a bouncy ball.

Answer:

(1) Pull

(2) Bend

Those two are Non-Locomotor movements while others are Locomotor movements.

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Formula for force:

\(F=ma\)

force(measured in newtons) = mass(measured in kg) * acceleration(measured in m/s^2)

Formula for work:

\(w=Fd\)

work(measured in joules) = force(measured in newtons) * distance(measured in meters)

__________________________________________________________

Given:

\(m=3.4kg\)

\(d=1613m\)

\(a=9.8m/s\) (due to gravity)

\(w=?\)

__________________________________________________________

Finding force:

\(F=ma\)

\(F=3.4\times9.8\)

\(F=33.32N\)

__________________________________________________________

Finding work:

\(W=Fd\)

\(W=33.32\times1613\)

__________________________________________________________

Answer:

\(\fbox{w = 53745.16 Joules}\)

Answer:

C. the production of new machines as a result of processes using science and knowledge.

Explanation:

Technology is the application of scientific research and knowledge .

After completion of the trip described in the question, it would be the year 2320 on Earth.

This has to do with the way light-years are described. A light-year is in fact not a measurement of time, but of distance. It is how far you would travel in one year if traveling at the speed of light. So since the star is 100 light-years away, it would take 100 Earth years to get there and then 100 more to get back, making the current Earth year 2320.

Therefore, we can confirm that after completion of the trip described in the question, it would be the year 2320 on Earth.

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there is nothing there