Answers
The electron gains more kinetic energy than the proton when accelerated through a potential difference of 1 V.
The relationship between the kinetic energies of the electron and proton can be determined using the formula for the kinetic energy of a particle:
\(KE = (1/2)mv^2\)
\(V = (q/m)d\)
where V is the potential difference, q is the charge, m is its mass, and d is the distance .
For the electron, \(V = 1 V\)and\(q/m = -1.6 x 10^-19 C/kg\), so its final velocity is:
\(v_e = sqrt((2qV)/m) = sqrt((2*(-1.6 x 10^-19)*1)/9.11 x 10^-31) = 5.93 x 10^6 m/s\)
For the proton, \(V = -1 V and q/m = 1.6 x 10^-19 C/kg,\) so its final velocity is:
\(v_p = sqrt((2qV)/m) = sqrt((2*(1.6 x 10^-19)*(-1))/1.67 x 10^-27) = 7.16 x 10^5 m/s\)
Substituting these values into the formula for kinetic energy, we get:
\(KE_e = (1/2)9.11 x 10^-31(5.93 x 10^6)^2 = 1.63 x 10^-17 J\)\(KE_p = (1/2)1.67 x 10^-27(7.16 x 10^5)^2 = 0.84 x 10^-17 J\)
Therefore, we have:
\(KE_e > KE_p\) , This is because the electron has a much smaller mass than the proton, so it experiences a much larger acceleration and gains more velocity and kinetic energy.
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Related Questions
Planets A and B have the same size, but planet A is half the mass of planet B.
Which statement correctly explains the weight you would experience on each
planet?
O A. You would weigh the same on both planets because the planets
are the same size.
B. You would weigh less on planet A because it has less mass than
planet B.
C. You would weigh more on planet A because it has less mass than
planet B.
D. You would weigh the same on both planets because your mass
would be the same on both.
SUBMIT
Answers
Answer: Choice B) You would weigh less on planet A because it has less mass than planet B.
=====================================================
Explanation:
Weight is due to the force of gravity. The higher the force of gravity, the more pull and therefore the larger weight.
Imagine that gravity was basically a rope pulling a person down. The higher the force of gravity, the stronger the pull on the rope.
Due to planet A having less mass compared to planet B, this means the force of gravity on planet A is smaller, and therefore a person on planet A will weigh less compared to planet B.
-------------
As a more real world example, the moon's mass is less than the Earth's mass. It turns out that weights on the moon are roughly 1/6 of what they would be on Earth. This means that if a person weighed 180 pounds on Earth, then they would weigh about 180*(1/6) = 180/6 = 30 pounds on the moon. This is why astronauts on the moon are able to jump higher and have a bigger bounce in their step, even if they aren't even trying to jump so high.
6. In the diagram below, A is a vector of magnitude 35 cm; B is a vector of magnitude 13 cm. If tan a = 4/3 and tan ß = 5/12, a. write A and B in terms of î and ĵ b. Show that A + B makes an angle of 45° to the x-axis.
Answers
Answer:
A = 21 î + 28 ĵ
B = 12 î + 5 ĵ
Explanation:
a.
To write A and B in terms of î and ĵ, we need to use the trigonometric ratios and the vector notation
According to the diagram, we have:
tan a = 4/3 tan ß = 5/12
Using the identity tan θ = opposite/adjacent, we can find the x and y components of A and B.
For A, we have:
x component = 35 cos a y component = 35 sin a
Using tan a = 4/3, we can find cos a and sin a by using Pythagoras’ theorem:
cos a = 3/5 sin a = 4/5
Therefore, the x and y components of A are:
x component = 35 cos a = 35 (3/5) = 21 y component = 35 sin a = 35 (4/5) = 28
Using the vector notation, we can write A as:
A = 21 î + 28 ĵ
Similarly, for B, we have:
x component = 13 cos ß y component = 13 sin ß
Using tan ß = 5/12, we can find cos ß and sin ß by using Pythagoras’ theorem:
cos ß = 12/13 sin ß = 5/13
Therefore, the x and y components of B are:
x component = 13 cos ß = 13 (12/13) = 12 y component = 13 sin ß = 13 (5/13) = 5
Using the vector notation, we can write B as:
B = 12 î + 5 ĵ
b.
To show that A + B makes an angle of 45° to the x-axis, we need to find the resultant vector R and its angle θ with the x-axis.
To find R, we can use the vector addition rule :
R = A + B R = (21 î + 28 ĵ) + (12 î + 5 ĵ) R = (21 + 12) î + (28 + 5) ĵ R = 33 î + 33 ĵ
To find θ, we can use the inverse tangent function :
tan θ = y component / x component tan θ = 33 / 33 tan θ = 1
θ = tan^-1(1) θ = 45°
Therefore, A + B makes an angle of 45° to the x-axis.
I NEED HELP Quick PLEASE AND THANK YOU !!!
Answers
What is the relationship between the quantity of matter and mass?
Answers
Explanation:
The substance with less quantity of matter has less mass and that with more quantity has more mass..
\(...\)
A liquid x at 25 degree Celsius is poured to a height of 40cm in a capillary tube of length 70cm and the diameter is 1cm .Assume that volume does not change with temperature. A find the initial volume of the liquid in cm^3. B. The temperature is reduced by 10°C causing the liquid to reduce in height to 37cm.Find the volume coefficient of the thermal expansion of the liquid. C. At the initial height of 40cm and temperature of 25°C , what change in temperature is needed for liquid to rise to a height of 49cm.
Answers
The initial volume of the liquid is 31.4 cm³. The volume coefficient of thermal expansion of the liquid is 0.002 per degree Celsius. A temperature increase of 109.5°C is needed for the liquid to rise to a height of 49cm.
The initial volume of the liquid can be found using the formula for the volume of a cylinder:
V = πr²h
where r is the radius (half the diameter), h is the height, and π is approximately 3.14. Plugging in the given values, we get:
V = π(0.5 cm)²(40 cm)
V = 31.4 cm³
The volume coefficient of thermal expansion (β) is defined as the fractional change in volume per degree Celsius change in temperature. It can be calculated using the formula:
β = ΔV/(VΔT)
where ΔV is the change in volume, V is the initial volume, and ΔT is the change in temperature. We can rearrange this formula to solve for ΔV:
ΔV = βVΔT
We know that ΔT = -10°C (a decrease of 10°C) and that the height decreased from 40cm to 37cm, or by 3cm. The change in volume can be found using the formula for the volume of a cylinder again, with the new height of 37cm:
ΔV = π(0.5 cm)²(40 cm - 37 cm)
ΔV = 0.59 cm³
Plugging in all the values, we get:
0.59 cm³ = β(31.4 cm³)(-10°C)
β = 0.002
To find the change in temperature needed for the liquid to rise to a height of 49cm, we can use the same formula as before, but solve for ΔT:
ΔT = ΔV/(βV)
We know that ΔV is the difference between the initial volume and the volume at the new height, which is:
ΔV = π(0.5 cm)²(49 cm - 40 cm)
ΔV = 6.86 cm³
Plugging in all the values, we get:
ΔT = 6.86 cm³/(0.002)(31.4 cm³)
ΔT = 109.5°C
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A soap bubble was slowly enlarged from a radius of 4cm to 6cm. The amount of work necessary for enlargement was 1.5 x 10^-4 joules. Calculate the surface tension of the soap bubble.
Answers
Answer:
\(T=3*10^-3 N/m\)
Explanation:
From the question we are told that:
Radius :
\(R_1=4=>0.04\\\\R_2=6=>0.06\)
Work \(W=1.5 * 10^{-4}\)
Generally the equation for Work done is mathematically given by
\(W=TdA\)
Where
\(dA=A_2-A_1\\\\dA=(2 \pi r_2^2)(2 \pi r_1^2)\)
\(dA=8 \pi*(r_2^2-r_1^2)\\\\dA=8*3.142*(0.06^2-0.04^2)\)
\(dA=0.050m^2\)
Therefore
\(W=TdA\)
\(T=\frac{1.5 * 10^{-4}}{0.05m^2}\)
\(T=3*10^-3 N/m\)
What do you need to know to analyze the forces in a situation?
Answers
Answer:
An analysis yielding the respective forces acting at any point of any member, or part of a member, of a mechanism, obtained by using relationships for dynamic equilibrium in a plane rigid body subject to external forces within this plane and to internal forces due to its motion in this plane.
A 5kg block rests on a 30° incline. The coefficient of static friction between the block and the incline is 0.20. How large a horizontal force must push on the block if the block is to be on the verge of sliding. a) up the incline, b) down the incline ?
Answers
Answer:
Hope It Help
Explanation:
That's all I know
Weight is best defined as _____. A the amount of space an object takes up B the speed of an object C the force of gravity on an object D the amount of energy in an object
Answers
Weight is best defined as C) the force of gravity on an object.
you are working in an optical research laboratory. One of the pieces of experimental apparatus involves a beam of light entering a transparent rod (see the figure below) of diameter d = 3.50 pm and index of refraction n = 1.39, surrounded by air. d Your supervisor has given you the task of determining the cone of acceptance for the rod, which is the maximum angle max (in degrees) for which the light rays incident on the end of the rod are subject to total internal reflection along the walls of the rod.
Answers
The greatest angle, when light rays incident on the rod's end are subject to total internal reflection along the rod's walls, is 57.8 degrees. while performing work in an optical research lab.
The optical phenomena known as total internal reflection (TIR) occurs when waves crossing a boundary from one medium to another, such as water crossing into air, are entirely reflected back into the first ("internal") medium rather than being refracted into the second ("external"). An incident ray is a light beam that strikes any surface. A polished surface causes the incident ray to reflect back to the surroundings. It is known as a reflected ray.
tetha = sin^-1(1/1.31)
Tetha = 49.79 degrees
tetha(r) = tetha - tetha(c) = 40.24
tetha = sin^-1(1.31*(sin40.24)) = 57.8 degrees
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The more mass an object has,the less inertia the object has. True or False
Answers
Answer:
This is true. objects that have a greater mass has greater interia. which also means objects that have a less mass has also less interia.
Explanation:
i hope this helps!!!
The photograph shows a mixture of beach sand. A student
wants to separate the shell bits, rocks, and sea animals
from the sand.
Which method is the best way for the student to separate the mixture?
A. Flisering
B. Settling
C. Exaporation
D. Magnetism
Answers
Sand and salt and water will be separated by decanting. The student's best option for separating the mixture is to leave the sand in the original container.
How can you divide the components of saltwater using the best technique?The salt will be left behind as a solid even if you boil or evaporate the water. Distillation is an option if you wish to collect the water. Salt has a far greater boiling point than water, which explains why this is effective.
How can components be separated with the least amount of effort?Filtration. Filtration is among the most straightforward techniques for separating mixtures. Filtration is simple if one component is a liquid and the other is a solid. In this case, the mixture can simply be poured through filter paper.
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A. The probabilities are decimals, which can never represent a probability. B. Two possible outcomes have an identical probability, which is not possible. C. The sum of all possible moves is greater than 1, which is not possible. D. The probability of two possible outcomes sums to the probability of another outcome, which is not possible.
Answers
Answer:
Explanation:
wo possible outcomes have an identical probability, which is not possible. C. The sum of all possible moves is greater than 1, which is not possible. D. The probability of two possible outcomes sums to the probability of another outcome, which is not possible.
For the simple harmonic oscillation where k = 19.6
N/m, A = 0.100 m, x = -(0.100 m) cos 8.08t, and v =
(0.808 m/s) sin 8.08t, determine (a) the total energy, (b)
the kinetic and potential energies as a function of time,
(c) the velocity when the mass is 0.050 m from
equilibrium, (d) the kinetic and potential energies at
half amplitude (x = A/2).
Answers
a. Total energy is 0.098 J
b. Potential and Kinetic Energies is 0.032 sin^2(8.08t) J
c. Velocity at x is -0.808 sin(8.08t) m/s
d. Potential and Kinetic Energies at x is 0.016 sin^2(8.08t) J
Step by step explanationWe can use the following formulas for the energy, velocity, and potential and kinetic energies of a simple harmonic oscillator:
Total Energy: E = 1/2 k A^2Velocity: v = -ωA sin(ωt)Potential Energy: U = 1/2 k x^2Kinetic Energy: K = 1/2 m v^2where ω = √(k/m) is the angular frequency.
Given that k = 19.6 N/m, A = 0.100 m, x = -(0.100 m) cos 8.08t, and v = (0.808 m/s) sin 8.08t, we can find the values of E, U, and K as follows:
(a) Total Energy:
E = 1/2 k A^2 = 1/2 * 19.6 * 0.1^2 = 0.098 J
(b) Potential and Kinetic Energies:
U = 1/2 k x^2 = 1/2 * 19.6 * (-0.1 cos(8.08t))^2 = 0.098 cos^2(8.08t) J
K = 1/2 m v^2 = 1/2 * (0.1) * (0.808 sin(8.08t))^2 = 0.032 sin^2(8.08t) J
(c) Velocity at x = 0.050 m:
When x = 0.050 m, cos(8.08t) = -0.5, so we have:
v = -ωA sin(ωt) = -ω(0.1) sin(8.08t) = -0.808 sin(8.08t) m/s
(d) Potential and Kinetic Energies at x = A/2:
When x = A/2 = 0.050 m, cos(8.08t) = -0.5, so we have:
U = 1/2 k x^2 = 1/2 * 19.6 * (0.050)^2 = 0.0245 J
K = 1/2 m v^2 = 1/2 * (0.1) * (0.808 sin(8.08t))^2 = 0.016 sin^2(8.08t) J
Note that the sum of potential and kinetic energies at any point in time is equal to the total energy, which is constant.
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A motorcycle stoop is at a traffic light, when the light turns green, the motorcycle accelerates to a speed of 78 km/h over a distance of 50 m. What is the average acceleration of the motorcycle over this distance?
Answers
The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².
To calculate the average acceleration of the motorcycle, we can use the formula:
Average acceleration = (final velocity - initial velocity) / time
First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.
Converting the final velocity:
Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s
Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:
Average acceleration = (21.67 m/s - 0 m/s) / time
To find the time taken to reach this velocity, we need to use the formula for average speed:
Average speed = total distance/time
Rearranging the formula:
time = total distance / average speed
Plugging in the values:
time = 50 m / 21.67 m/s ≈ 2.31 seconds
Now we can calculate the average acceleration:
Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²
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if you sit on the edge of a very light table, it is likely the table will topple over. explain?
Answers
Answer:
This question heavily relies on the weight of the table and the weight of the person sitting on it, if a 90 pound person sits on the side of a 40 pound table, it will topple over.
Explanation: Tables are generally have a 50/50 weight distribution ratio so that they are even on the ground and can stay upright, but if a table is too light and the person or object sitting on it is heavier than the side they/it is placed on, it will fall.
What is sound waves
Answers
Sound waves are a type of mechanical wave that propagate through a medium, typically air but also other materials such as water or solids.
Characteristics of sound wavesFrequency: the frequency of a sound wave refers to the number of cycles or vibrations it completes per second and is measured in Hertz (Hz).
Amplitude: the amplitude of a sound wave refers to the maximum displacement or intensity of the wave from its equilibrium position. It represents the loudness or volume of the sound, with larger amplitudes corresponding to louder sounds and smaller amplitudes corresponding to softer sounds.
Wavelength: the wavelength of a sound wave is the distance between two consecutive points in the wave that are in phase, such as from one peak to the next or one trough to the next. It is inversely related to the frequency of the wave.
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A car travels a distance of 200 miles in 3.5 hours in a given trip. What is the average speed of the car in that
trip? Write the data given, equation, substitution and the answer with correct units for full credit.
Answers
Taking into account the definition of speed, the average speed of the car in the trip is 57.14 \(\frac{miles}{hour}\).
Definition of speedSpeed is a physical magnitude that relates the displacement of an object and the time it takes to make this change in position.
So, the speed can be defined as the amount of space traveled per unit of time with which a body moves and can be calculated using the expression:
\(speed=\frac{displacement}{time}\)
Speed has units of \(\frac{distance}{time}\), such as \(\frac{meters}{second}\) or \(\frac{miles}{hour}\).
Average speed of the carIn this case, you know that:
displacement= 200 milestime= 3.5 hoursReplacing in the definition of speed:
\(speed=\frac{200 miles}{3.5 hours}\)
speed= 57.14 \(\frac{miles}{hour}\)
Finally, the average speed of the car in the trip is 57.14 \(\frac{miles}{hour}\).
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When resistors are connected in series they are?
Answers
Answer:
c
Explanation:
Dr. John Paul Stapp was a U.S. Air Force officer who studied the effects of extreme deceleration on the human body. On December 10, 1954, Stapp rode a rocket sled, accelerating from rest to a top speed of 282 m/s (1015 km/h) in 5.00 s, and was brought jarringly back to rest in only 1.40 s!Calculate the magnitude of the average acceleration during the first part of his motion and the magnitude of the average acceleration during the second part of his motion?
Answers
ANSWER:
a. 5.75g
b. -20.55g
STEP-BY-STEP EXPLANATION:
We have the following information from the statement:
\(\begin{gathered} v_i=0\text{ m/s} \\ v_{f1}=282\text{ m/s} \\ v_{f2}=0\text{ m/s} \\ t_1=5\text{ s} \\ t_2=1.4\text{ s} \end{gathered}\)To calculate the acceleration during the first part of the motion it would be:
\(\begin{gathered} a_1=\frac{v_f-v_i}{t_1} \\ \text{ replacing} \\ a_1=\frac{282-0}{5}=56.4\frac{m}{s^2} \\ \text{ in terms of g would be:} \\ a_1=\frac{56.4}{9.8}=5.75g \end{gathered}\)To calculate the acceleration during the second part of the movement it would be:
\(\begin{gathered} a_2=\frac{v_{f2}-v_{f1}}{t_2} \\ \text{ replacing} \\ a_2=\frac{0-282}{1.4}=-201.43\frac{m}{s^2} \\ \text{ in terms of g would be:} \\ a_1=\frac{-201.43}{9.8}=-20.55g \end{gathered}\)which of the following are true about S waves
1. they begin at an earthquakes focus
2. they can travel through liquids
3. they can travel through solids
4. they move rock at right angles to the direction of wave travel
Answers
Answer:
3. they can travel through solids
4. they move rock at right angles to the direction of wave travel
Explanation:
S waves are called transverse waves they have the ability to move past the solids. They cannot move through the liquids, these waves are perpendicular to the direction of travel. They are also called longitudinal waves, the ad is second to record on the seismograph as they slowly pass through the rocks. They have a speed of 3.4 to 7.2 km as per the boundary.Answer:
1, 3, 4
Explanation:
S waves are transverse waves, so they move rock at right angles to the direction of wave travel. Also, S waves can only travel through solids. S waves and P waves both begin at an earthquake's focus.
Plane-polarized light is incident on a single polarizing disk, withthe direction of E0 parallel to thedirection of the transmission axis. Through what angle should thedisk be rotated so that the intensity in the transmitted beam isreduced by a factor of each of the following?
(a) 2.20
(b) 5.20
(c) 12.0
Answers
Answer;
Cos²စ= I/Io
So
A. Cos²စ = 1/2.2
Cosစ= √1/2.2
စ = cos^-1 0.68
= 47.2°
B.
Cosစ = √1/5.2
စ = ,cos^-1 0.4385
= 64°
C.
Cosစ = √1/12
စ = cos^-1 0.2886
= 73.2°
A shaft carries five masses A, B, C, D and E which revolve at the same radius in planes
which are equidistant from one another. The magnitude of the masses in planes A, C and
D are 50 kg, 40 kg and 80 kg respectively. The angle between A and C is 90° and that
between C and D is 135°. Determine the magnitude of the masses in planes B and E and
their positions to put the shaft in complete rotating balance.
Answers
The magnitude of the masses in planes B and E is 40 kg, and their positions are 120° and 240°, respectively, from the reference point on the shaft to achieve complete rotating balance.
To achieve complete rotating balance, the sum of the moments of the masses in planes A, C, D, B, and E should be equal to zero. Let's determine the magnitude of the masses in planes B and E and their positions.
Consider the moments of the masses in planes A, C, and D. The moment of a mass is given by the product of its magnitude and the sine of the angle between the mass and a reference line. The moments of masses A, C, and D are:
Moment of A = 50 kg * sin(0°) = 0 kg·m,
Moment of C = 40 kg * sin(90°) = 40 kg·m,
Moment of D = 80 kg * sin(135°) = -80 kg·m.
Since the moments of A, C, and D are known, we can use the principle of complete rotating balance to determine the magnitude and position of the masses in planes B and E.
Let's assume the magnitude of the masses in planes B and E as M. The moments of masses B and E can be represented as:
Moment of B = M * sin(120°) = M * √(3)/2,
Moment of E = M * sin(240°) = -M * √(3)/2.
Using the principle of complete rotating balance, the sum of the moments should be zero. Thus, we have:
Moment of A + Moment of C + Moment of D + Moment of B + Moment of E = 0.
0 + 40 kg·m + (-80 kg·m) + M * √(3)/2 + (-M * √(3)/2) = 0.
Simplifying the equation:
40 kg·m - 80 kg·m + M * √(3)/2 - M * √(3)/2 = 0,
-40 kg·m = 0.
From the equation, we can deduce that M must be equal to 40 kg to satisfy the condition of complete rotating balance.
Finally, we determine the positions of masses B and E. Since planes A, C, D, B, and E are equidistant from one another, and the angle between A and C is 90°, we divide the circle into 360°/5 = 72° sections. Thus, the positions of masses B and E are:
Position of B = 0° + 2 * 72° = 144°,
Position of E = 0° + 4 * 72° = 288°.
Therefore, the magnitude of the masses in planes B and E is 40 kg, and their positions to put the shaft in complete rotating balance are 144° and 288°, respectively, from the reference point on the shaft.
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LICATION
1. A bar of iron can occasionally be magnetized
by laying it on the ground, pointing it parallel
to the earth's magnetic field, and striking it
repeatedly with a hammer. Use the domain
theory to explain what causes the bar to
become magnetized.
Answers
The domain theory of magnetism explains that ferromagnetic materials such as iron are composed of tiny magnetic domains that are randomly oriented in the absence of a magnetic field.
The Domain theoryThese domains have their own magnetic fields that cancel each other out. When an external magnetic field is applied to the material, the domains align themselves with the field, resulting in a net magnetic field and the material becoming magnetized.
In the case of the bar of iron being magnetized by striking it repeatedly with a hammer while pointing it parallel to the earth's magnetic field, the mechanical energy from the hammer blows causes the domains to align themselves in the same direction as the earth's magnetic field. This alignment becomes "locked in" as the domains resist changing their orientation once aligned. Therefore, the bar of iron becomes magnetized and will remain so until it is demagnetized or its magnetic domains are realigned in a different direction by another magnetic field.
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Describe one common critique or criticism of Utilitarianism. To what extent do you agree or disagree with this criticism?
Answers
1.
The momentum of a 5-kilogram object moving at
6 meters per second is
A. 1 kg • m/sec
B. 5 kg • m/sec
C. 11 kg • m/sec
D. 30 kg. m/sec
Answers
Answer:
D
Explanation:
Momentum= mass x speed (P=MV)
Momentum= 5x6=30
Momentum= 30kg m/s
The momentum of the 5-kilogram object moving at 6 meters per second is 30 kg•m/s. Thus the correct answer is (D) 30 kg•m/sec.
What is the momentum of an object?It is an attribute of a moving body that exists due to its mass and motion and is equal to the product of the body's mass and velocity.
Mathematically, momentum (p) can be expressed as:
p = m × v
Where:
p = momentum
m = mass
v = velocity
As per the question, the mass of the object is 5 kg and its velocity is 6 m/s.
Therefore, the momentum of the object can be calculated as:
p = m × v
p = 5 kg × 6 m/s
Apply the multiplication operation, then we get
p = 30 kg•m/s
Therefore, the momentum of the 5-kilogram object moving at 6 meters per second is 30 kg•m/s.
So, the correct answer is (D) 30 kg•m/sec.
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Explain/Describe how atoms in domains determine whether a material is magnetic or not. (Please help this is due today)
Answers
Answer:
In a material, the magnetic behavior depends on the alignment of magnetic moments of the atoms. Magnetic moments are generated by the motion of the electrons in the atoms. When the magnetic moments of atoms in a material are aligned in a specific pattern, it creates a magnetic field which results in the material being magnetic.
In many materials, the magnetic behavior arises due to the alignment of magnetic domains, which are regions of atoms with magnetic moments aligned in the same direction. When many domains with aligned magnetic moments are present in a material, the material becomes magnetic.
The magnetic behavior of a material depends on the number of electrons and the arrangement of those electrons in the atoms. In particular, for an atom to have a magnetic moment, it must have unpaired electrons, meaning electrons that are not paired with another electron with the opposite spin. When these unpaired electrons in the atoms are aligned, they generate a magnetic moment. If all electrons are paired, there will not be a net magnetic moment, so the material will not be magnetic.
So, in summary, the magnetic behavior of a material is determined by the alignment of magnetic moments of atoms. When the magnetic moments of many atoms in a material align in the same direction, it creates a magnetic field, leading to a material being magnetic. This alignment is usually present in magnetic domains consisting of atoms with unpaired electrons.
give 3 example of right quantities that have no unit
Answers
Answer:
velocity ratio
mechanical advantage
Relative density
A rock is thrown straight down from a cliff with an initial velocity of 10.0 m/s. Its final velocity when it strikes the water below is 115 m/s. How long is the rock in flight?
Answers
The time of the rock in flight is 10.71 s.
What is time of flight?This is the total time taken for an object or a projectile to return back to the same plane at which it was projected.
To calculate the time of the rock in flight, we use the formula below.
Formula:
v = u+gt............. Equation 1Where:
v = Final final velocityu = Initial velocityt = time of the rock in flight. g = acceleration due to gravitymake t the subject of the equation
t = (v-u)/g.................... Equation 2
From the question,
Given:
u = 10 m/sv = 115 m/sg = 9.8 m/s².Substitute these values into equation 2
t = (115-10)/9.8t = 105/9.8t = 10.71 sHence, the time of the rock in flight is 10.71 s.
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The rock was in the flight for 11.7 s
Time of flightThis is defined as the total time spent by an object in air.
Determination of the height of the cliffFrom the question given above, the following data were obtained:
Initial velocity (u) = 10 m/sFinal velocity (v) = 115 m/sAcceleration due to gravity (g) = 9.8 m/s²Height of cliff (h) =?v² = u² + 2gh
115² = 10² + (2 × 9.8 × h)
13225 = 100 + 19.6h
Collect like terms
13225 – 100 = 19.6h
13125 = 19.6h
Divide both side by 19.6
h = 13125 / 19.6
h = 669.64 m
How to determine the time of flight Acceleration due to gravity (g) = 9.8 m/s²Height of cliff (h) = 669.64 mTime of flight (t) =?h = ½gt²
669.64 = ½ × 9.8 × t²
669.64 = 4.9 × t²
Divide both side by 4.9
t² = 669.64 / 4.9
Take the square root of both side
t = √(669.64 / 4.9)
t = 11.7 s
Thus, the rock was in the flight for 11.7 s
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