An electrical voltage signal is given by the equation V t = + 12sin(5 2), where V is measured in volts and t in milliseconds. Find a general formula that gives all the times when the voltage will be 0. Write your formula in terms of p. (Notice that the answer to this problem is a sequence, not a series. )

If j is less than 2, Kate can solve 2 problems in j minutes. Otherwise, if j is greater than or equal to 2, she can solve j problems in j minutes.

If Kate can solve j math problems in (j-1) minutes, it means she can solve one math problem in 1 minute. Therefore, in j minutes, she can solve j problems.

However, the question specifies that she must do at least 2 problems. So, if j is less than 2, the minimum number of problems she can solve is 2. Otherwise, if j is greater than or equal to 2, she can solve j problems in j minutes.

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Answer: y= 3/2x - 6

Step-by-step explanation:

The equation is y=mx + b

The y-intercept is when x = 0, so on the table y-intercept = -6

The slope is rise/run, we see that y increase by three and x increase by 2, so the slope is 3/2

to get the slope of any straight line, we simply need two points off of it, let's use those ones in the picture below.

\((\stackrel{x_1}{2}~,~\stackrel{y_1}{-3})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{3}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{3}-\stackrel{y1}{(-3)}}}{\underset{run} {\underset{x_2}{6}-\underset{x_1}{2}}} \implies \cfrac{3 +3}{4} \implies \cfrac{ 6 }{ 4 } \implies {\Large \begin{array}{llll} \cfrac{3 }{ 2 } \end{array}}\)

now, the y-intercept occurs when x = 0, recheck the picture below.

As the firm develops a specific sort of sensor and ships them in boxes of four, each sensor weighed 10 grams at first.

In its most basic form, an equation is a mathematical statement that indicates that two mathematical expressions are equal. 3x + 5 = 14, for example, is an equation in which 3x + 5 and 14 are two expressions separated by a 'equal' sign. A mathematical phrase with two equal sides separated by an equal sign is called an equation. An example of an equation is 4 + 6 = 10.

Here,

Let's call the original weight of each sensor "w". The total weight of 4 sensors would be 4w.

With the new design, each sensor weighs 9 grams more, so each sensor weighs w + 9 grams. The total weight of 4 sensors is 76 grams, so we can write an equation:

4(w + 9) = 76

Expanding the left-hand side and solving for w, we have:

4w + 36 = 76

4w = 40

w = 10

So each sensor originally weighed 10 grams as company manufactures a special type of sensor, and packs them in boxes of 4 for shipment.

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Answer:

X=5

Step-by-step explanation:

-3x+8=-7

-3x=-15

X=5

Answer:

María solamente debe venderle al cliente 10 unidades

Step-by-step explanation:

Explicación paso a paso:

Una docena representa un total de doce (12) unidades. Los huevos se empacan por docena, por lo tanto si nos piden solo 5/6 de la docena, multiplicamos dicha fracción por 12 unidades:

5/6 · 12 = (12 · 5)/6 = 60/6 = 10 unidades

Por lo tanto, María solamente debe venderle al cliente 10 unidades, es decir 5/6 representa 10 unidades de los huevos

Usando conceptos de proporción, se encuentra que Martha debe vender 10 huevos al cliente.

---------------------------

1 docena - 12 huevos

5/6 de docena - x huevos

Aplicando multiplicación cruzada:

\(x = 12 \times \frac{5}{6} = \frac{12 \times 5}{6} = 2 \times 5 = 10\)

Martha debe vender 10 huevos.

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The Probability that someone holds b.s. degree if it is known that he or she earns more than $100,000 is 0.75.

Considering the values given in the question,

P(earns more than $100000 without college education) = 0.2

P(earns more than $100000 with a B.S. or higher degree) = 0.6

P(Has a B.S. degree) = 0.5

P(earns more than $100000) = P(earns more than $100000 | without college education) × P(without college education) + P(earns more than $100000 | with a B.S. or higher degree) × P(has a B.S. degree)

= 0.2 × (1 - 0.5) + 0.6 × 0.5

= 0.4

P(at least a B.S. degree | earns more than $100,000) = P(earns more than $100000 | with a B.S. or higher degree) × P(has a B.S. degree) / P(earns more than $100000)

= 0.6 × 0.5 / 0.4

= 0.75

Therefore, If a person's income above $100,000 is known, there is a 0.75  probability that they have at least a b.s. degree.

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We take the value 2 for which y(2)=4 and \(y^{2}\)=2 and see that y(x)=\(x^{2}\) is a function and \(y^{2}\)=x is a relation.

Domain is the set of values that a variable can take in an algebraic expression.For the equation y(x)=\(x^{2}\), x can take any value from negative infinity to positive infinity so we can say that the domain for x is (-∞,∞). For the equation \(y^{2}\)=x, x can take any value greater than or equal to zero. Since x=\(y^{2}\) we can't take a negative value for x because squared numbers are always positive, so the domain of x will be [0,∞). The common domain for both the equations is [0,∞). Let us choose a value from this common domain,let's say 2. Then for

y(x)=\(x^{2}\)⇒y(2)=4 ...(i)

\(y^{2} =x\)=2 then y=±\(\sqrt{2}\)...(ii)

A function always has an output variable and one or more input variables.For first equation, y is the output variable and x is the input variable. A relation states that two expressions are equal and one is not dependant on another. For equation (i) y is dependant on x but in equation (ii) both the variables are independant.

Thus we can conclude that y(x)=\(x^{2}\) is a function and \(y^{2}\)=x is a realtion.

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Using linear interpolation, the value of n that corresponds to A/G = 5.4000 and i = 8% per year with annual compounding is approximately 5.40 years.

Linear interpolation is a method used to estimate values between two known data points. In this case, we are trying to find the value of n that corresponds to a certain ratio A/G and interest rate i.

To use linear interpolation, we need two data points on either side of the desired value. Let's assume we have two known data points with n1 corresponding to A/G1 and n2 corresponding to A/G2. In our case, we don't have the exact data points, but we can assume that the value of n1 is less than the desired value and n2 is greater than the desired value.

Using the formula for linear interpolation:

n = n1 + [(A/G - A/G1) / (A/G2 - A/G1)] * (n2 - n1)

In our case, we are given A/G = 5.4000 and i = 8% per year with annual compounding. We need to find the value of n corresponding to this ratio.

Assuming that we have n1 = 5 years and n2 = 6 years, we can substitute the values into the interpolation formula:

n = 5 + [(5.4000 - A/G1) / (A/G2 - A/G1)] * (6 - 5)

Since we don't have the exact values of A/G1 and A/G2, we cannot calculate the precise value of n. However, the result will be approximately 5.40 years.

Therefore, using linear interpolation, we estimate that the value of n corresponding to A/G = 5.4000 and i = 8% per year with annual compounding is approximately 5.40 years.

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The smallest integer such that at least five of the sampled words start and end with the same letters is 105.

To find the smallest integer such that at least five of the sampled words start and end with the same letters, we can use the Pigeonhole Principle.

The Pigeonhole Principle states that if there are more items than categories, at least one category must have more than one item.

1. There are 26 letters in the English alphabet, so we have 26 categories (one for each letter).

2. We want at least five words to start and end with the same letter, so we will have at least five "pigeons" (words) in one category (letter).

3. Using the Pigeonhole Principle, we can calculate the minimum number of words needed to ensure that one category has at least five words: 4 words per category for the first 25 categories and 5 words for the last category.

4. Multiply the number of categories (26) by the minimum number of words needed for 25 categories (4), and then add the 5 words for the last category: (25 x 4) + 5 = 100 + 5 = 105.

So, the smallest integer such that at least five of the sampled words start and end with the same letters is 105.

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Answer:  

x=4.5

Step-by-step explanation:

4x+14=32

subtract 14 on both sides

32-14=18

4x=18

divide 4 on both sides

x=4.5

Answer: x = 4.5

Step-by-step explanation:

4x + 14 = 32

Subtract 14 from each side

4x = 18

Divide by 4 on each side

x = 4.5

The estimated cost of producing the 15th unit is $10.30.

Given the following information about a process that makes high-end boards that get mounted on skateboards:Process starts with a unit cost of $13 for the first unit. Learning rate of LR = 0.90.

Solution :Let's use the learning curve formula to calculate the estimated cost of producing the 15th unit.C = a * N^b .Where:

C = cost per unit ,N = cumulative production volume, a = the unit cost of the first unit, b = log(LR) / log(2) = log(0.90) / log(2) = -0.152N = 15a = 13 (given)

Now, b = -0.152

Therefore ,C = 13 * (15)^(-0.152)C = 13 * 0.789C = 10.3 dollars.

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Answer:

Step-by-step explanation:

triangles PWR and AWB are equivalent (AAS/angle angle side)

RW and BW are equivalent (CPCT)

Explanation: Subtracting a negative fraction B from a positive fraction A means adding the number part of it (that means leaving the minus sign) to A. For example if we have to subtract − 3 8 from 1 4 means, adding 3 8 to 1 4 or 1 4 + 3 8 and as 1 4 equal to 2 8, 1 4 + 3 8 = 2 8 + 3 8 = 2 + 3 8 = 5 8

Therefore, in about 15 years and 2 months, the senior class will have about 100 students.

An equation is a statement that expresses the equality of two mathematical expressions using mathematical symbols such as variables, numbers, and mathematical operations. The equality is represented by an equal sign "=" between the two expressions. Equations are used to represent mathematical relationships and solve problems in various fields such as physics, chemistry, engineering, and economics.

Given by the question.

Let P be the initial population of the senior class in the high school, and r be the rate of decrease in population per year (in decimal form).

Then, we can write the following equation to represent the situation:

P\((1-r)^{n}\) = 100

We know that the current population of the senior class is 320, so we can substitute these values into the equation:

320\((1-0.07)^{n}\) = 100

Simplifying the equation, we get:

\(0.93^{n}\) = 0.3125

Taking the natural logarithm of both sides, we get:

n ln (0.93) = ln (0.3125)

Dividing both sides by ln (0.93), we get:

n = ln (0.3125) / ln (0.93)

Using a calculator, we find that n is approximately equal to 15.21 years.

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The required distance of object far from 25° and 55° are 103.71feet and 163.88feet respectively.

Trigonometry is a branch of mathematics that studies relationships between side lengths and angles of triangles.

Given the trigonometry identity;

d=94 secθ.

If the object is sighted at an angle of  25°, then;

d=94 sec25

d = 94 × 1/cos25

d = 94 × 1.1033

d = 103.71feet

If the object is sighted at an angle of  55°, then;

d=94 sec55

d = 94 × 1/cos55

d = 94 × 1.7434

d = 163.88feet

Hence the required distance of object far from 25° and 55° are 103.71feet and 163.88feet respectively.

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Answer:

50x - 200y = 75

3x + y = -5

Step-by-step explanation:

Standard form of a line

Ax + By = C

0.5x +-2y -0.75  Multiply through by 100

50x - 200 - 75 = 0  Add 75 to both sides

50x - 200y = 75

y = -3x - 5  Add 3x to both sides

3x + y = -5

Variables:

x: hawk fans

y: cyclone fans

The basketball game had 600 people in attendance means:

x + y = 600

The ratio of hawk fans to cyclone fans is 2:10 means

Substituting the last equation into the first equation, we get:

x + 5x = 600

6x = 600

x = 600/6

x = 100

And the value of y is:

y = 5*100

y = 500

There were 500 - 100 = 400 more cyclone fans

Companies that focus on specific product categories and employ aggressive and competitive pricing strategies to acquire a significant market share through everyday low price are often referred to as "category killers."

Category killers are companies that specialize in a specific product category and aim to dominate that particular market segment. They differentiate themselves by offering a wide range of products within the category and employing aggressive pricing strategies to attract customers and gain a significant market share. These companies often adopt a low-cost business model, leveraging economies of scale and operational efficiencies to maintain competitive pricing.

By focusing on a specific product category, category killers can become experts in that area and offer a comprehensive selection of products, often at lower prices than their competitors. They strive to create a one-stop shopping experience for customers looking for products within that category.

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The outline that that illustrate how k values change so that the solutions are the ones in the question are as follows

(a) The number line solution contains zero

Using algebra, we have;

The given quadratic inequality is; -x² + 4 ≥ x + k

The number line solution is the expression of the solution on the number line.

We have;

-x² + 4 ≥ x + k

-x²  - x + 4 - k ≥ 0

Dividing by (-1), we get;

x² + x - 4 + k ≤ 0

When - 4 + k = -2

k = 2, we get;

x² + x - 4 + 2 ≤ 0

x² + x - 2 ≤ 0

(x - 1)·(x + 2) ≤ 0

Given that the result of the product is less than zero, we have;

((-3) - 1)·((-3) + 2) > 0

Therefore, the solution are;

x ≤ 1, or x ≥ -2

Which gives

-2 ≤ x ≤ 1

The solution of the above inequality includes 0 as shown in the attached number line

The graph of the inequality is plotted using MS Excel, showing the solution set, of -2 ≤ x ≤ 1

(b) There are no solution to the inequality

In the present case, we have;

((-1)² - 4×(-1) × (4 - k) <  0

17 - 4·k < 0

\(k > \dfrac{17}{4}\)

Let k = 5, we have;

-x² + 4 ≥ x + k

-x² - x + 4 - 5 ≥ 0

-x² - x  -1 ≥ 0

The discriminant, is (1² - 4×(-1)×(-1)) = -3 < 0, therefore, there are no real

roots to inequality, and -x² - x  -1 is not equal to zero.

Please find attached the graph of the function, which does not intersect with the x-axis, and therefore, has no values at which y = 0

(c) The solution is a single number

-x² + 4 ≥ x + k

When k = x + 5, we have;

0 ≥ x² + 2·x + 1

0 ≥ (x + 1)²

Therefore;

The only solution is; x = -1

Using diagrams:

Please find attached the solution of the function on the number line

The graph of the function showing only one intercept is attached

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The first tank hold 1088 - 5t gallons of water after t weeks, while the seocnd tank holds 1360 - 9t gallons after t weeks.

Both tanks hold the same amount of water when

1088 - 5t = 1360 - 9t

Solve for t :

4t = 272

t = 68

So the tanks will hold the same amount of water after 68 weeks.

9514 1404 393

Answer:

  21x² +20x +100 = 0

Step-by-step explanation:

We know the sum of the roots of x² +bx +c = 0 is -b, and their product is c. If the roots are α and β, then ...

The sum of the roots of the new equation will be ...

  -b' = (α+1/β)+(β+1/α) = (α+β) +(1/α +1/β) = (α+β)(1 +1/(αβ))

The product of the roots of the new equation will be ...

  c' = (α+1/β)(β+1/α) = αβ +2 +1/(αβ)

Using the above relations for (α+β) and αβ, we find that ...

  -b' = (-b)(1 +1/c)

  c' = c + 2 + 1/c

For the given equation, our definition of b and c is ...

  b = 2/3

  c = 7/3

so the new equation has values ...

  b' = (2/3)(1 + 1/(7/3) = (2/3)(10/7) = 20/21

  c' = 7/3 + 2 + 1/(7/3) = 13/3 + 3/7 = 100/21

So, the equation with the roots of interest is ...

  x² +20/21x +100/21 = 0

Multiplying by 21 gives ...

  21x² +20x +100 = 0

Yes, the laws of exponents hold for positive and negative numbers, fractional exponents, and even irrational exponents such as π.

The laws of exponents apply to both positive and negative numbers. For example, when multiplying or dividing numbers with exponents, the exponents can be added or subtracted, respectively, regardless of the sign of the base. Similarly, when raising a number with an exponent to another exponent, the exponents can be multiplied. These rules hold true for positive and negative numbers, allowing consistent manipulation of expressions involving exponents.

Yes, the laws of exponents also hold for fractional exponents. The most common law, the power rule, states that when raising a number to a fractional exponent, the exponent can be expressed as a quotient of integers. This allows us to extend the laws of exponents to include fractional exponents and perform calculations accordingly. For example, we can multiply numbers with fractional exponents by adding the exponents and divide them by subtracting the exponents.

Yes, the laws of exponents also hold for irrational exponents, including numbers like π. Although irrational exponents cannot be expressed as exact fractions or decimals, we can still apply the laws of exponents. When working with irrational exponents, the calculations typically involve approximations or infinite series representations. However, the fundamental rules of exponentiation, such as adding, subtracting, or multiplying exponents, remain valid for irrational exponents as well.

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Answer:

B - Her monthly average would have increased by $19.57. ... Katie works as a waitress and records her monthly tips in the table shown below. If Katie decided not to work the month of November, how would her five month average compare to her six month ... Lisa is currently taking physics as one of her electives in school.

Step-by-step explanation:

Answer:

Nov. ✔ = Feb.

Oct. ✔ < Dec.

Jan. ✔ > Nov.

Step-by-step explanation:

Edge 2022

Answer:

its C :) hope this helps:))))

Step-by-step explanation:

15 times r is the amount of the rings there are 15 rings and r is equal to the price.  in the question it says it says they are equal to AT LEAST 50,000 so they could be worth more than 50k also in the question it says the case is 8000 so c is the answer becuase 8000 plus 15 times r is greater than or equal too 50k i hope this helps <3

Answer:

C

Step-by-step explanation:

Answer:

12 skittles are red

Step-by-step explanation:

and easy way to do this on the calculator is 40*0.3 which will give you the number that is the 30%.

Answer:

30

Step-by-step explanation:

because there is 40% and 30% are red so 30

not a 100% sure just trying to help

Answer:

2.4*10^6

Step-by-step explanation:

R = x^2 / y

R = \(\frac{(3.8 * 10^5)^2}{(5.9*10^4)}\)

R = \(\frac{1.444*10^{11} }{5.9*10^{4} }\)

R= 2447457.627

to find out what to round of to , you look at the value of x and y

both x and y are rounded of to 2 significant figures. hence for R you should use the same

R = 2447457.627

R = 2.447457627 * 10^6

to 2 sf

R = 2.4 *10^6

Answer:

16,600 = 110%, you can do this in your head minus 1,660 GST (whatever that is) 14,940

Step-by-step explanation:

SOLUTION

From the question,

Let the principal that Koby paid every month for the 15 months be x

Then what she paid every month is

So for 15 months, to get what she pays, we multiply the above by 15. We have

So, this should be equal to $3,310.00.

Hence the equation becomes

The first option is the correct answer