An astronaut standing on the Mars drops a brick. If the brick falls 12m vertically in 3.1s,what is its acceleration?

An athlete would need to apply a force of 1000 N to move the punching bag 1.5 m if 1500 J of work were done.

Energy transferred to or from an object by the application of force along a displacement is known as work.

The work done by the athlete is equal to the force applied multiplied by the distance moved in the direction of the force. Therefore, we can use the formula:

As Work = Force x Distance

So, Force = Work / Distance

Substituting the given values, we can have:

Force = 1500 J / 1.5 m = 1000 N

Therefore, the athlete would need to apply a force of 1000 N to move the punching bag 1.5 m if 1500 J of work were done.

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Answer:

At least \(2\; \rm m\).

Explanation:

The torque \(\tau\) that a force exerts on a lever is equal the product of the following:

\(\tau = F\cdot r \cdot \sin\theta\).

The force in this question is (at most) \(50\; \rm N\). That is: \(F = 50\; \rm N\).

\(\sin \theta\) is maximized when \(\theta = 90^\circ\). In other words, the force on the door gives the largest-possible torque when that force is applied perpendicular to the door. When \(\theta = 90^\circ\!\), \(\sin \theta =1\).

If the force here is applied at a distance of \(r\) meters away from the hinge (the fulcrum of this door,) the torque generated would be:

\(\begin{aligned}\tau &= F \cdot r \cdot \sin \theta \\ &= (50\, r)\; \rm N \cdot m\end{aligned}\).

That torque is supposed to be at least \(100\; \rm N\cdot m\). That is:

\(50\, r \ge 100\).

\(r \ge 2\).

In other words, the force needs to be applied at a point a minimum distance of \(2\; \rm m\) away from the hinge of this door.

Answer:

True

Explanation:

hope this helps everyone! :D

When a positively charged object is brought near an uncharged electroscope, the vanes will move apart due to the separation of charge within the electroscope.

As the positive charges in the disk are repelled by the positively charged object and move towards the vanes, the negative charges in the disk are attracted to the positively charged object and move towards it. This creates a separation of charge within the electroscope, with the disk becoming positively charged and the vanes becoming negatively charged. As a result, the vanes will repel each other and move apart. This movement of the vanes is an indication of the presence of charge in the electroscope.

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Answer:

0.01 s

Explanation:

When the capacitor voltage is maximum, the inductor voltage is at a minimum, and when the capacitor voltage is minimum, the inductor voltage is at a maximum.

The time difference between minimum voltage and maximum voltage for the capacitor or inductor is the same as that for maximum voltage of capacitor to maximum voltage of inductor and this is t = T/4 where T = period.

Since T = 0.04 s, t = T/4

= 0.04 s/4

= 0.01 s

So, the amount of time is there between when the capacitor voltage maximizes and the inductor voltage maximizes is 0.01 s

Answer: The resistance of the 0.75 km length of the copper wire is 6.47 Ω (ohms).

Explanation:

The resistance R of a wire of length L and cross-sectional area A with resistivity ρ can be calculated using the formula:

R = (ρ x L) / A

We are given the diameter of the copper wire, but we need to calculate its cross-sectional area first. The cross-sectional area A of a wire with diameter d can be calculated using the formula:

A = (π / 4) x d^2

Substituting the given values:

A = (π / 4) x (5.034 mm)^2

A = 19.977 mm^2 (square millimeters)

Now we can calculate the resistance R of the 0.75 km length of wire:

L = 0.75 km = 750 m

ρ = 1.72 × 10^-8 Ω⋅m

R = (ρ x L) / A

R = (1.72 × 10^-8 Ω⋅m x 750 m) / 19.977 mm^2

R = 6.47 Ω (ohms)

Therefore, the resistance of the 0.75 km length of the copper wire is 6.47 Ω (ohms).

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With 20 windings, the generator will produce a higher EMF and, consequently, a larger current. This increased current will provide more power to the light bulb, resulting in a brighter illumination compared to the dim illumination observed with only 5 windings.

When you increase the number of wire windings in the generator from 5 to 20, the effect on the light bulb will be a brighter illumination. The brightness of the light bulb is directly proportional to the number of windings in the generator.

By increasing the number of windings, you are increasing the amount of wire wrapped around the magnet. This results in a higher number of turns per unit length, leading to an increased magnetic flux passing through the wire coils.

According to Faraday's law of electromagnetic induction, a change in magnetic flux induces an electromotive force (EMF) in a conductor, which in this case is the copper wire. The induced EMF causes electric current to flow through the wire, creating a flow of electrons.

The 30-W light bulb requires a certain amount of electrical power to produce its specified brightness. With 20 windings, the generator will produce a higher EMF and, consequently, a larger current. This increased current will provide more power to the light bulb, resulting in a brighter illumination compared to the dim illumination observed with only 5 windings.

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Hi there!

A)
Since the ball's velocity is initially only in the HORIZONTAL direction, there is NO vertical component of its velocity. Therefore, we can treat this like a free-fall scenario. (Dropped from rest).

We can rearrange the following kinematic equation to make solving for the time taken for the balls to hit the ground easier.

\(d_y = v_yt + \frac{1}{2}at^2\)

dy = vertical displacement (height of table, 0.85 m)

vy = initial vertical velocity (0 m/s, only horizontal)
a = acceleration (due to gravity in this situation, 9.8 m/s²)

t = time (? sec)
Simplify and rearrange the variables for 't'.

\(d_y = 0(t) + \frac{1}{2}at^2\\\\d_y = \frac{1}{2}at^2\\\\t^2 = \frac{2d_y}{a}\\\\t = \sqrt{\frac{2d_y}{a}}}\)

Plug in the given values.

\(t = \sqrt{\frac{2(0.85)}{9.8}} = \boxed{0.4165 s}\)

B)

Now, remember that the ball's acceleration in the vertical direction due to gravity does NOT impact its horizontal velocity. Its vertical and horizontal velocities are COMPLETELY independent. Thus, we can simply use the time solved for above and each ball's respective velocities in the following kinematic equation:
\(d_x = v_xt\)

dₓ= horizontal displacement (? m)

vₓ = horizontal component of velocity (3.5 and 5.3 m/s for A and B respectively)

t = time (0.4165 s)

Solve for the distance traveled by each ball:
Ball A:
\(d_x = 3.5 * 0.4165 = \boxed{1.458 m}\)

Ball B:
\(d_x = 5.3* 0.4165 = \boxed{2.207 m}\)

First option is correct.Larry the Rock is going through Static Equilibrium.

In this situation, Larry is at rest and remains stationary despite the forces acting on him. While David and Pancho are exerting equal forces from opposite sides, their forces cancel each other out, resulting in a net force of zero. As a result, Larry does not move or experience any acceleration.

Static equilibrium occurs when an object's forces and torques balance each other, leading to a stable, balanced state. In this case, the forces exerted by David and Pancho are equal in magnitude and opposite in direction, creating a condition where the resultant force is zero. As a result, Larry remains in a state of rest, unable to experience any movement or acceleration.Therefore, the type of equilibrium that Larry the Rock is going through is Static Equilibrium.

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According to Chargaff's rule, the amounts of adenine (A), thymine (T), and guanine (G) in the DNA molecule are equal to each other. The amounts of cytosine (C) and guanine (G) are also equal.

Erwin Chargaff was a biochemist, author, Bucovinian Jew who immigrated to America during the Nazi era, and professor of biochemistry at Columbia University's medical school.

Chargaff found patterns among the four bases, or chemical building blocks, of DNA, which are directly related to DNA's function as the genetic material of living things.

He was born in Austria-Hungary. Heraclitean Fire: Sketches from a Life Before Nature, an autobiography he penned, received positive reviews.

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Answer:

The different types of fluid flow are: Steady and Unsteady Flow. Uniform and Non-Uniform Flow. ... Compressible and Incompressible Flow. Rotational and Irrotational Flow.

Answer:

A boat can travel 2.30 m/s in still water. (a) If the boat points its prow directly across a stream whose current is. ... (a) What is the velocity (magnitude and direction) of the boat relative to the shore? ... The boat's velocity with respect to the shore, , is the sum of its velocity with respect to the water

Explanation:

The potential difference (voltage) between the plates is approximately 1.45 kV.

The kinetic energy of an electron can be related to the potential difference between the plates of an electric field using the equation:

KE = qV,

where KE is the kinetic energy of the electron, q is its charge, and V is the potential difference between the plates.

We know that the electron is accelerated from rest to a final velocity of 8 x 10^7 m/s, so its change in kinetic energy is given by:

ΔKE = 1/2 mv^2 - 1/2 m(0)^2 = 1/2 mv^2

where m is the mass of the electron.

The potential difference between the plates can be found by rearranging the equation to solve for V:

V = ΔKE / q

Substituting the values we have:

V = (1/2) mv^2 / q

The mass of an electron is approximately 9.11 x 10^-31 kg, and its charge is -1.6 x 10^-19 C. Substituting these values and the final velocity of 8 x 10^7 m/s, we get:

V = (1/2) (9.11 x 10^-31 kg) (8 x 10^7 m/s)^2 / (-1.6 x 10^-19 C)

V = -1.45 kV

Therefore, the potential difference (voltage) between the plates is approximately 1.45 kV.

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Answer:

The magnitude of displacement vector 2D-E is approximately 14.49 units. The calculation is done using the Pythagorean theorem after finding 2D-E by multiplying vector D by 2 and subtracting vector E.

Explanation:

The value of 2D-E must first be calculated in order to ascertain the displacement 2D-E's magnitude. Vector D may be multiplied by two to accomplish this, and the result can be obtained by deducting vector E:

2D-E = 2(6i + 3j - k) 4i + 5j + 3k = 8i + 11j - 5k - (4i - 5j + 3k) = 12i + 6j - 2k

We can use the Pythagorean theorem to determine the magnitude of the displacement vector now that we know it:

|2D-E| = √(8² + 11² + (-5)²) = √(64 + 121 + 25) = √210 ≈ 14.49

The displacement 2D-E magnitude is therefore 14.49 units or such. From the object's beginning location to its ultimate position, the displacement's entire length is shown by this. Being a scalar variable, the displacement's magnitude does not reveal the displacement's direction.

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Based on the information, it should be noted that the resistance R is 0.5 Ω.

When S1 and S2 are open, i leads e by 30°. In this case, the circuit consists of only the inductor (L) and the capacitor (C) in series. Therefore, the impedance of the circuit can be written as:

Z = jωL - 1/(jωC)

Since i leads e by 30°, we can express the phasor relationship as:

I = k * e^(j(ωt + θ))

Z = jωL - 1/(jωC) = j(120π)L - 1/(j(120π)C)

Re(Z) = 0

By equating the real parts, we get:

0 = 0 - 1/(120πC)

Let's assume that there is a resistance (R) in series with the inductor and capacitor. The impedance equation becomes:

Z = R + jωL - 1/(jωC)

Z = R + jωL

Im(Z) = ωL > 0

Substituting the angular frequency and rearranging the inequality, we have:

120πL > 0

L > 0

This condition implies that the inductance L must be greater than zero.

When S1 and S2 are closed, i has an amplitude of 0.5 A. In this case, the impedance is:

Z = R + jωL - 1/(jωC)

Since the amplitude of i is given as 0.5 A, we can express the phasor relationship as:

I = 0.5 * e^(j(ωt + θ))

By substituting this phasor relationship into the impedance equation, we can determine the value of R. The real part of the impedance must be equal to R:

Re(Z) = R

Since the amplitude of i is 0.5 A, the real part of the impedance must be equal to 0.5 A: 0.5 = R

Therefore, the resistance R is 0.5 Ω.

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Answer:

gravity wave

Explanation:

ANSWER:

STEP-BY-STEP EXPLANATION:

We have the following:

Answer:

Plz mark brainliest

Explanation:

As with kinetic energy, potential energy can change. When two objects interact, each one exerts a force on the other that can cause energy to be transferred to or from the other object.

Answer:

I = 0.25 [amp]

Explanation:

To solve this problem we must use ohm's law which tells us that the voltage is equal to the product of the current by the resistance.

V = I*R

where:

V = voltage [Volt]

I = amperage or current [amp]

R = resistance [ohm]

Since all resistors are connected in series, the total resistance will be equal to the arithmetic sum of all resistors.

Rt = 2 + 8 + 14

Rt = 24 [ohm]

Now clearing I for amperage

I = V/Rt

I = 6/24

I = 0.25 [amp].

Answer:

Changes of state. The kinetic theory of matter can be used to explain how solids, liquids and gases are interchangeable as a result of increase or decrease in heat energy. ... If it is cooled the motion of the particles decreases as they lose energy.13 Nov 2000

Explanation:

The second reflection is created as the light frvl as it passes through the block. Multiple pictures are created via surface diffraction.

The act of light spreading out after passing through a narrow area or bending around an object is known as diffraction. The dispersion of light waves is a topic covered in physics classes. Sound, television, and water waves are all susceptible to diffraction.

Diffraction is the small bending of light that occurs when it travels around an object's edge. The degree of bending is influenced by the wavelength of light's size in relation to the opening's size. When the opening exceeds the wavelength of the light, the

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Answer:

when u learn something new it goes to ur short term memory

Answer:

density is defined as the amount of mass contained in unit volume of a body .its si unit is kg/m*3

Answer:

Density is the amount of mass per unit volume of a substance.

Archimedes principle states that"When a body is totally or partially immersed in a liquid,it experience an upthrust which is equal to the weight of the liquid displaced"

Answer:

The acceleration due to gravity on the planet Fergie is 0.0123 m/s^2.

Explanation:

We want to find the acceleration due to gravity on the planet Fregie. Let it be g m/s^2.

Now, the acceleration due to gravity is defined through the following equation:

\(mg = GMm/R^2\)

where m is the mass of an object on the surface of the planet, M is the mass of the planet, R is the radius of the planet, and G is the universal Gravitational constant.

Subsituting values for M = 6.23*10^23, R = 5.79*10^7, G = 6.67*10^(-11), we get

g = 0.0123 m/s^2.

Thus the acceleration due to gravity on the planet Fergie is 0.0123 m/s^2.

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To calculate the net force on particle q2, we need to calculate the individual forces exerted by q1 and q3 on q2, considering their charges and separation distances.

Using Coulomb's Law, the force between two charged particles can be calculated as:

\(F = (k * |q1 * q2|) / r^2\)

where F is the force, k is Coulomb's constant (8.99 x 10^9 N m²/C²), q1 and q2 are the charges of the particles, and r is the separation distance between them.

For q1 and q2:

F1 = (8.99 x 10^9 N m²/C²) * (|-66.3 x 10^-6 C * 108 x 10^-6 C|) / (0.550 m)²

For q2 and q3:

F2 = (8.99 x 10^9 N m²/C²) * (|108 x 10^-6 C * -43.2 x 10^-6 C|) / (0.550 m)²

The net force on q2 is the vector sum of F1 and F2:

Net Force = F1 + F2

By calculating these values and performing the addition, we can determine the net force acting on particle q2.

Therefore, To calculate the net force on particle q2, we need to calculate the individual forces exerted by q1 and q3 on q2, considering their charges and separation distances.

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The energy efficiency of the car is approximately 16.7%.

The energy efficiency of a car is the ratio of the useful work output (in this case, the kinetic energy of the car) to the total energy input (in this case, the energy released by burning the gasoline). The equation for energy efficiency is:

The useful work output can be calculated as the kinetic energy of the car using the equation:

where m is the mass of the car and v is its velocity.

Substituting the given values:

The total energy input is the energy released by burning 0.1 L of gasoline, which is:

Substituting these values into the equation for efficiency:

Therefore, the energy efficiency of the car is approximately 16.7%.

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Answer:

The answer is D. displacement

Explanation:

The electrical force between the two balloons having charges of 2.2×10⁻⁶ C and 1.8×10⁻⁷ C and held 0.65 meters apart is 8.44×10⁻³ N

From Coulomb's law, we understood that the electrical force between two points charges is given by the following equation:

F = Kq₁q₂ / r²

Where

With the above equation, we can easily determine the electrical force between two balloons. Details below

We can obtain the force as follow:

F = Kq₁q₂ / d²

F = (9×10⁹ × 2.2×10⁻⁶ × 1.8×10⁻⁷) / (0.65)²

F = 8.44×10⁻³ N

Thus, the electrical force between them is 8.44×10⁻³ N

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