An arrow is shot vertically upward and then 1.87 s later passes the top of a tree 39.9 m high. How much longer will the arrow travel upward, how high will it go?

Time :
Height:

Answer:

• For horizontal motion, the projectile is not under a free fall. So, it is not experienced by gravitational force hence acceleration due to gravity is negligible.

\({ \tt{s _{x} = u _{x} t}} \\ \)

The weight of the fourth casting is 48 kg.

Given - The weight of three castings -

45.302kg

44.982kg

45.716kg

To find - The average weight if the 4th casting is taken the average weight becomes 46kg what is the weight of the 4th casting​

Solution -

Let's calculate the average weight of the first three castings using the given weights:

Average weight = (Weight of first casting + Weight of second casting + Weight of third casting) / 3

Average weight = (45.302 kg + 44.982 kg + 45.716 kg) / 3

Average weight = 136.000 kg / 3

Average weight = 45.3333... kg (rounded to four decimal places)

Now, let's calculate the weight of the fourth casting by using the average weight and the desired overall average weight:

Total weight of all four castings = Average weight * 4

Total weight of all four castings = 46 kg * 4

Total weight of all four castings = 184 kg

To find the weight of the fourth casting, we subtract the total weight of the first three castings from the total weight of all four castings:

Weight of the fourth casting = Total weight of all four castings - Total weight of first three castings

Weight of the fourth casting = 184 kg - 136 kg

Weight of the fourth casting = 48 kg

Therefore, the weight of the fourth casting is 48 kg

Given,

The distance between the cannon and the wall, x=13.5 m

The height of the wall, h₀=7.9 m

The angle of projection, θ=51.9°

The time duration in which the ball passes the point that is directly above the wall, t=1.15 s

A)

The x-component of the initial velocity is given by,

Where u is the initial velocity of the cannon ball.

On substituting the known values,

Thus the speed with which the cannon ball was fired is 19.03 m/s

B)

The height of the cannonball at the point that is directly above the wall is given by,

Where g is the acceleration due to gravity.

On substituting the known values.

Thus, the vertical distance by which the cannon ball clears the top of the wall is,

Thus the cannon ball clears the top of the wall by a distance of 2.84 m

Answer:

For people to reduce the inclined nature of a mountain, they make the roads longer by putting curved in the way. Riding a bicycle up a hill can be a very challenging task but riding it on a zig-zagged road makes it easier to go up and down. Making it curved ensures that it's flatter even though it becomes longer.

The kinematics of the uniform motion and the addition of vectors allow finding the results are:

Vectors are quantities that have modulus and direction, so they must be added using vector algebra.

A simple method to perform this addition in the algebraic method which has several parts:

 Indicate that Barry's velocity is constant, let's find using the uniform motion thatthe distance traveled in ad case

              v = \(\frac{\Delta d}{t}\)

              Δd = v t

Where  v is the average velocity, Δd the displacement and t the time

We look for the first distance traveled at speed v₁ = 600 m / s for a time

          t₁ = 2 min = 120 s

          Δd₁ = v₁ t₁

          Δd₁ = 600 120

          Δd₁ = 72 10³ m

Now we look for the second distance traveled for the velocity v₂ = 400 m/s    

  time t₂ = 1 min = 60 s

          Δd₂ = v₂ t₂

          Δd₂ = 400 60

          Δd₂ = 24 103 m

In the attached we can see a diagram of the different Barry trajectories and the coordinate system for the decomposition,

We must be careful all the angles must be measured counterclockwise from the positive side of the axis ax (East)

Let's use trigonometry for each distance

Route 1

          cos (180 -35) = \(\frac{x_1}{\Delta d_1}\)

          sin 145 = \(\frac{y_1}{\Delta d1}\)

          x₁ = Δd₁ cos 125

          y₁ = Δd₁ sin 125

          x₁ = 72 103 are 145 = -58.98 103 m

          y₁ = 72 103 sin 155 = 41.30 10³ m

Route 2

          cos (90+ 30) = \(\frac{x_2}{\Delta d_2}\)

          sin (120) = \(\frac{y_2}{\Delta d_2}\)

          x₂ = Δd₂ cos 120

          y₂ = Δd₂ sin 120

          x₂ = 24 103 cos 120 = -12 10³ m

           y₂ = 24 103 sin 120 = 20,78 10³ m

The component of the resultant vector are

              Rₓ = x₁ + x₂

              R_y = y₁ + y₂

              Rx = - (58.98 + 12) 10³ = -70.98 10³ m

              Ry = (41.30 + 20.78) 10³ m = 62.08 10³ m

We construct the resulting vector

Let's use the Pythagoras' Theorem for the module

             R = \(\sqrt{R_x^2 +R_y^2}\)

             R = \(\sqrt{70.98^2 + 62.08^2}\)   10³

             R = 94.30 10³ m

We use trigonometry for the angle

             tan θ ’= \(\frac{R_y}{R_x}\)

             θ '= tan⁻¹ \(\frac{R_y}{R_x}\)

             θ '= tan⁻¹ \(\frac{62.08}{70.98}\)

             θ ’= 41.2º

Since the offset in the x axis is negative and the displacement in the y axis is positive, this vector is in the second quadrant, to be written with respect to the positive side of the x axis in a counterclockwise direction

            θ = 180 - θ'

            θ = 180 -41.2

            θ = 138.8º

Finally, let's calculate the speed for the way back, since the total of the trajectory must be 5 min and on the outward trip I spend 3 min, for the return there is a time of t₃ = 2 min = 120 s.

The average speed of the trip should be

             v = \(\frac{\Delta R}{t_3}\)  

             v = \(\frac{94.30}{120} \ 10^3\)

              v = 785.9 m / s

in the opposite direction, that is, the angle must be

               41.2º to the South of the East

In conclusion, using the kinematics of the uniform motion and the addition of vectors, results are:

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Thermodynamics is a macroscopic science. Thermodynamics is the study of the relations between heat, work, temperature, and energy.

Thermodynamics  is a branch that deals with heat, work and temperature, and their relation to energy, radiation and physical properties of matter. Thermodynamics is a macroscopic science which means dealing with substances in bulk or with large amount.

Thermodynamics is classified into the following four branches:

1- Classical Thermodynamics

2- Statistical Thermodynamics

3- Chemical Thermodynamics

4- Equilibrium Thermodynamics

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The ball exerts a force on the wall, and the wall exerts an equal and opposite force on the ball. So, the correct answer is A.

Newton's 3rd law of motion states that for every action, there is an equal and opposite reaction. The action is the force that the ball exerts on the wall, and the reaction is the force that the wall exerts back on the ball. When the ball hits the wall, it exerts a force on the wall. This force is equal in magnitude but opposite in direction to the force that the wall exerts back on the ball. This is why the ball reverses course. Therefore, option A is correct.

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--The complete Question is, Which of the following statements is true according to Newton's 3rd law when a ball hits a wall and reverses course?

A) The ball exerts a force on the wall, and the wall exerts an equal and opposite force on the ball.

B) The ball exerts a force on the wall, but the wall does not exert a force on the ball.

C) The wall exerts a force on the ball, but the ball does not exert a force on the wall.

D) The ball and the wall do not exert any forces on each other. --

Answer:

C. 20 cm x 80 cm

Explanation:

The dimensions of the scale model have the same ratio of the original dimensions. The ratio of the original dimenstions is

240/60 = 4

Then, the ratio for each option is

A. 360/90 = 4

B. 3/1 = 3

C. 80/20 = 4

D. 480/120 = 4

Therefore, B is not a correct option.

Additionally, we don't use A because the units for length and width are different

And we don't use D because the measures are too long for a model.

Therefore, the answer is

C. 20 cm x 80 cm

Answer:

A. Brain patterns

Explanation:

Got it right on the quiz.

Answer:

Brain Patterns

Explanation:

This was correct

Average force acting on Purley is -1749m/\(s^{2}\).

What is Newton's second law of motion?

According to this, a body's momentum changes at a rate that is equal to the force acting on it over time in both magnitude and direction. A body's momentum is determined by multiplying its mass by its speed.

Given,

According to newton's second law of motion:

F =ma

Purley's initial speed = 173km/h

Final speed = 0

Distance traveled = 0.66 m

So, \(v_{i}\) = 172 km/h × 1 hr/3600 s × 1000m/1km

\(v_{i}\) = 48.1 m/s

By using kinematics

\(v^{2} f\) = \(v^{2} i\) + 2ad

\(0^{2}\) = 48.\(1^{2}\) + 2a(0.66)

-1.32a = 2309

a= -1749 m/\(s^{2}\)

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Answer:

  λ = 0.64 10⁻⁶ m = 640 nm

Explanation:

The two reflected rays experience constructive interference, if we can see them, so we can one condition for interference, but let's see two phenomena that occur

* A ray when it is reflected by a surface of major spare part index has a phase change of 180º, these passes at the air-plastic interface

* A ray when passing a material with a refractive index changes its wavelength

       λ= λ₀ / n

taking into account these facts the condition in constructive interference is

             2 n t = (m + ½) λ

             λ= 2 n t / (m + ½)

if we suppose that we have the first inference m = 0

            λ = 2 1.6 0.5 10⁻⁶ (0 + ½)

            λ = 3.2 10⁻⁶ m

this wavelength is in the infrared

suppose an interference of m = 1

          λ = 1.6 10⁻⁶ / (1 + 1/2)

          λ = 1.06 10-6 m

m = 2

         λ = 1.6 10⁻⁶ / (2 + 1.5)

         λ = 0.64 10⁻⁶ m

this wavelength corresponds to the visible range (640 nm) orange

Explanation:

potential energy= mgh

30 × 10 × 30 = 9000J or 9KJ

Answer:

c. Both kinetic and potential energy

Explanation:

When the starting gun is fired at the beginning of a cross country foot race, the runners will begin to move from a stationary position at the bottom of a hill. This movement will result in a change in both their kinetic energy and potential energy.

Kinetic energy is the energy of motion, and it will increase as the runners accelerate from a stationary position and begin moving at a faster speed.

Potential energy is energy stored in an object due to its position or shape. The runners at the starting line have potential energy due to their position at the bottom of a hill. As they begin to move upward, their potential energy will decrease as they move further away from the ground.

Therefore, both kinetic and potential energy will change when the starting gun is fired at the beginning of a cross country foot race.

Answer:

(b) a real refrigerator

The quantity of heat energy that must be transferred to 2.25 kg of brass to raise its temperature from 20 °C to 240 °C is 195030 J

First, we shall list out the given parameters from the question. This is shown below:

The quantity of heat energy that must be transferred can be obtained as follow:

Q = MCΔT

= 2.25 × 394 × 220

= 195030 J

Thus, we can conclude quantity of heat energy that must be transferred is 195030 J

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Answer:

speed=0.3*100=30m/s

speed=0.1*50=5m/s

frequency=20/0,5=40HZ

frequency=80/0.2=400HZ

frequency=120/0.4=300HZ

wavelength=340/440=0.77m

wavelength=340/880=0.39m

wavelength=250/400=0.63m

speed=2*50=100m/s

speed=0.5*100=50m/s

Explanation:

Answer:

Explanation:

f = 1550((1522 + 8)/(1522 - 12))

f = 1,570.529... 1571 Hz

Answer:

jjjjj

Explanation:

dkcdzjc

A program that could do an instantaneous analysis of video motion will be useful it in a sportscast to analyze events as they occur.

A motion video is defined as the display of video images at a rate (such as thirty frames per second) that causes objects to appear to move smoothly and continuously.

Sports inherently involve fast and accurate motion, which can be difficult for competitors to master but also for coaches and trainers to analyze and audiences to follow. Because of the nature of most sports, monitoring with sensors or other devices attached to players or equipment is generally not possible. This opens up a plethora of opportunities for the use of computer vision techniques to assist competitors, coaches, and the audience

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a. the landing ramp should be placed at 276.298 ft horizontally from the launch point.

(b) the angle of the landing ramp is 30°.

(a)

Launch speed = 55.0 mph * (1.467 ft/s)

= 80.685 ft/s

Horizontal distance = Launch speed * Time of flight

Vertical velocity = Launch speed * sin(30.0°)

Time to reach maximum height = Vertical velocity / g

Vertical distance = (1/2) *g * t²

and Time = √(2 * Vertical distance / g)

Total time of flight = 2 * Time to reach maximum height + Time for descent

Horizontal distance = Launch speed * Total time of flight

The Vertical velocity = 80.685 ft/s * sin(30.0°)

= 40.3425 ft/s

Time to reach maximum height = 40.3425 ft/s / 32.2 ft/s²

Time to reach maximum height  = 1.253 s

Time of descent = √(2 * 25.0 ft / 32.2 ft/s²)

Time of descent  = 0.913 s

Total time of flight = 2 * 1.253 s + 0.913 s

Total time of flight = 3.419 s

In conclusion, the horizontal distance = 80.685 ft/s * 3.419 s

horizontal distance = 276.298 ft

b.

the angle of the landing ramp is  30.0 be the same as the launch angle.

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The insect's velocity is 0.2 meter/second along east.

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

Given parameters:

An insect crawls 4 m east along a hiking path.

Time taken by it: t = 20 seconds.

We have to fine: the insect's velocity, v =?

So, the magnitude of velocity: v= 4/20 meter/second = 0.2 meter/second.

And the direction velocity is along east.

Hence,  the insect's velocity is 0.2 meter/second along east.

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Answer:

option B is the correct answer

Explanation:

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Answer:

A

Explanation:

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Answer:

the period of the pendulum will be twice as long.

Explanation:

because i looked it up

The speed that the pea strikes the ceiling 2.20 m above the table is 4.64 m/s.

A projectile is an object that is launched into the air and then moves only in response to the acceleration of gravity. The trajectory of the object is referred to as the projectile's trajectory.

Speed is given by,

v²-u² sin²Θ =2(-g)h

v = √u² sin2Θ - 2gh

v = √(7.67) sin² (73) - 2(9.8) (1.90)

v = 4.06935

The resultant speed is given by,

v = √ v² + (u cos Θ)² =

v = √(4.06935)²+(7.67 cos 73)²

v = 4.64 m/s

Therefore, the speed is 4.64 m/s.

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Answer:

\(\huge\underline\color{green}{Answer \: ☘}\)

In the case of a water wave in the ocean, the medium through which the wave travels is the ocean water. In the case of a sound wave moving from the church choir to the pews, the medium through which the sound wave travels is the air in the room.

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There are 90 phones of volume, 10-7 W/m2 of sound intensity, and 0.0314 watts of source power.

A straightforward frequency analysis compares the values of the fields you provide and generates a report listing each value for those fields along with the frequency at which each value occurs.

The rate at which a sound power wave repeats itself, also known as frequency or pitch, is measured in cycles per second. Bullfrog calls and cricket chirps have lower frequencies than drum beats and whistles, respectively.

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Answer:

Yes

Explanation:

Yes. The momentum is the same when the speed of the tennis ball is 18 times greater than the speed of the basketball and the velocities of both objects are in the same direction.

Answer:

The acceleration of the crate is \(0.3356\,\frac{m}{s^2}\)

Explanation:

Recall the formula that relates force,mass and acceleration from newton's second law;

\(F=m\,a\)

Then in our case, we know the force applied and we know the mass of the crate, so we can solve for the acceleration as shown below:

\(F=m\,a\\75.5\,N=225\,\,kg\,\,a\\a=\frac{75.5}{225} \,\frac{m}{s^2} \\a=0.3356\,\,\frac{m}{s^2}\)

We can use Newton's second law to calculate the net force:

Answer:

b. 4N west