An apple is thrown across the cafeteria with a force of 10 N and at an acceleration of 6 m/s2. What is the mass of the apple? ... please answer asap

The mechanism that is responsible for the formation of snowflakes is the nucleation of ice crystals.

This is defined as a piece of snow which falls from the sky as a result of an extremely cold climate condition and is common in the arctic regions of the world.

Snow flakes are formed when ice crystals stick together to form the flakes which usually has a dust or pollen being formed around the area being talked about.

This is also regarded as a type of precipitation such as rain etc and is therefore the most appropriate choice.

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we can say that A ≤ 250N and B ≤ 250N.Based on the given information, we can calculate the force required to push the block up the slope using trigonometry.

First, we need to determine the angle of the slope. We know that the force of gravity acting on the block is 500N, so we can use this to find the angle using the formula:
sin θ = opposite/hypotenuse
where opposite is the weight of the block (500N) and hypotenuse is the force of gravity (also 500N).
sin θ = 500/500
sin θ = 1
θ = sin⁻¹(1)
θ = 90°
This tells us that the slope is vertical, so there is no way to push the block up the slope without friction. However, the problem states that there is no friction, so we can assume that the slope is not perfectly vertical.
Assuming that the slope is at some angle θ, we can use trigonometry again to find the force required to push the block up the slope.
sin θ = opposite/hypotenuse
sin θ = 250/F
F = 250/sin θ
where F is the force required to push the block up the slope.
We don't have enough information to calculate the angle θ, so we can't find the exact value of F. However, we can calculate the values of A and B using the formulae:
A = F cos θ
B = F sin θ
where A is the force acting perpendicular to the slope (i.e. the normal force) and B is the force acting parallel to the slope (i.e. the force pushing the block up the slope).
Using the expression for F above, we can simplify A and B as follows:
A = 250 cos θ
B = 250 sin θ
Again, we don't have enough information to calculate the exact values of A and B, but we can say that A will be less than or equal to 250N (since cos θ is always less than or equal to 1) and B will be less than or equal to 250N (since sin θ is always less than or equal to 1).

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Answer:

elaborate

Explanation:

you need to elaborate im just doing this for points but u need to elaborate

The variable that has the greatest effect on dynamic fluid forces is the relative velocity of the object with respect to the fluid.

This is because dynamic fluid forces are influenced by the movement of the fluid around the object, and the relative velocity determines how fast the fluid is moving in relation to the object.

The surface area of the object also plays a role in fluid forces, but it is a less significant factor compared to the relative velocity.

Fluid density is not directly related to dynamic fluid forces, but it can affect the overall behavior of the fluid.

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Answer:

X is ammeter and Y is voltmeter

Explanation:

The resistance of a wire is directly proportional to the length of the wire. That is the longer the length of the wire, the higher the resistance and the shorter the length of the wire, the smaller the resistance.

Ammeter is a measuring instrument used to measure the current in a circuit by connecting the meter in series with the circuit.

Ammeter is a measuring instrument used to measure the potential difference between two points by connecting the meter in parallel to the points.

Meter X is an ammeter since it is connected in series and meter Y is a voltmeter because it is connected in parallel.

a. The reduction half-reaction at the cathode (red lead) is Cd²⁺(aq) + 2e⁻ → Cd(s).

b. The oxidation half-reaction at the anode (black lead) is Cu(s) → Cu²⁺(aq) + 2e⁻.

c. The overall cell reaction is Cd²⁺(aq) + Cu(s) → Cd(s) + Cu²⁺(aq).

In the given electrochemical cell, the student connects a Cd²⁺(0.20 M)|Cd(s) half-cell to a Cu²⁺(1 M)|Cu(s) electrode. The cell potential, Ecell, is measured to be 0.77 V when the red lead is attached to the Cu electrode.

Based on the observed cell potential, we can determine the reduction and oxidation half-reactions at the cathode and anode, respectively.

a. Reduction half-reaction (cathode):

The cathode (red lead) experiences reduction, where Cd²⁺ ions from the Cd²⁺(0.20 M) solution gain electrons and get reduced to metallic Cd. The reduction half-reaction is Cd²⁺(aq) + 2e⁻ → Cd(s).

b. Oxidation half-reaction (anode):

The anode (black lead) undergoes oxidation, where metallic Cu loses electrons and forms Cu²⁺ ions in the Cu²⁺(1 M) solution. The oxidation half-reaction is Cu(s) → Cu²⁺(aq) + 2e⁻.

c. Overall cell reaction:

The overall cell reaction is the combination of the reduction and oxidation half-reactions. In this case, it can be written as Cd²⁺(aq) + Cu(s) → Cd(s) + Cu²⁺(aq).

By knowing the reduction and oxidation half-reactions, we can determine the overall redox reaction taking place in the electrochemical cell.

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Grandma dynamite's bus has an acceleration of 7.5 m/s².

acceleration = (final velocity - initial velocity) / time

where the final velocity is 90 m/s, the initial velocity is 0 m/s (since the bus starts from a stop), and the time taken is 12 seconds.

acceleration = (90 m/s - 0 m/s) / 12 s

acceleration = 7.5 m/s²

Acceleration is a fundamental concept in physics that describes the rate of change of an object's velocity over time. It is defined as the change in velocity divided by the change in time, and is expressed in units of meters per second squared (m/s²).

Acceleration can occur in different ways, such as speeding up or slowing down, changing direction, or a combination of both. A positive acceleration means an object is speeding up, while a negative acceleration means it is slowing down. Acceleration also depends on the mass of the object, with a larger mass requiring a greater force to achieve the same acceleration as a smaller mass.

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Answer:

x) KE and GPE

y) Only GPE

z) Only KE

Explanation:

From the diagram, we have;

1) At point X, the gall is at an elevation higher than the thrower, therefore, the ) ball has (gravitational) potential energy, GPE, because it can fall  to a lower level unassisted from the height it was thrown

And the ball is also in upward motion, with which it reaches the height 'Y', therefore, the ball has kinetic energy, KE, to move higher

2) At point 'Y' which is the maximum height, the ball no longer moves upwards and momentarily, the ball has no vertical motion, therefore, the ball has only energy due to height, which is the gravitational potential energy, GPE

3) At the point Z, at the instant just before the ball touches the ground, the elevation of the ball above the ground is small, while the velocity of the ball is close to maximum velocity, therefore, the ball has Only kinetic energy, KE

El calentamiento del instrumento viento antes de un concierto asegura que todos los instrumentos estén afinados y existan un mejor sonido, debido al cambio de frecuencia del instrumentos por los cambios de velocidad del aire debido al cambio de temperatura

Los instrumentos musicales trabajan por procesos de resonancia, ya sean de cuerda o viento; en los instrumentos de viento la frecuencia que emites esta dada por la relación  

                   fₙ = \(n \ \frac{v_s}{2L}\)    n = 1, 2, 3, ...

Donde f es la frecuencia emitida, L la longitud del tubo n es una constante entera y v_s es la velocidad del sonido

La velocidad del sonido en el aire depende de la temperatura del aire, según la relacion          

               vs = vo + 0,6 T  

Donde v₀ es la temperatura del aire a 0ºC, v₀ = 331 m/s y T la temperatura en grados centígrados.

De esta dos expresiones podemos ver que la frecuencia que emite el instrumento de viento depende  de la temperatura del aire, además en los instrumentos con boquilla la frecuencia de resonancia de la boquilla también depende de la temperatura de la boquilla que por ser liviana cambia fácilmente.

En conclusión el calentamiento del instrumento antes de un concierto asegura que todos los instrumentos estén afinados y existan un mejor sonido, debido al cambio de frecuencia del instrumentos por los cambios de velocidad del aire debido al cambio de temperatura

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The percent change in the drag force experienced by the ant as it increases its speed from 1 mm/s to 1.5 mm/s cannot be accurately determined without knowing more information about the ant, such as its size and shape, the viscosity of the fluid it is traveling through, and the properties of its surroundings. The drag force experienced by an object with a low Reynolds number is highly dependent on these factors. Therefore, without further information, it is impossible to provide a precise answer to this question.

To calculate the percent change in the drag force experienced by the ant, we can use the following formula:
Percent Change = [(Final Value - Initial Value) / Initial Value] * 100
In this case, the ant increases its speed from 1 mm/s to 1.5 mm/s. Since drag force is directly proportional to the speed in low Reynolds number scenarios (assuming constant fluid properties and object shape), we can calculate the percent change as follows:
Percent Change = [(1.5 mm/s - 1 mm/s) / 1 mm/s] * 100
Percent Change = [0.5 mm/s / 1 mm/s] * 100
Percent Change = 0.5 * 100
Percent Change = 50%
So, the percent change in the drag force experienced by the ant is 50% when it increases its speed from 1 mm/s to 1.5 mm/s.

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Answer:

20.96 m/s

Explanation:

Apply the kinematic equation:

Vf=Vi+at

Vi=8m/s

a=1.8m/s^2

t=7.2s

Putting this all in should give you your answer of 12.96m/s

The combination of a wire coil and a core would make the weakest electromagnet 20 coils of insulated wire around a hollow cardboard core. Thus, option B is correct.

Electromagnet is a type of magnet that produces its magnetic field when an electric field is applied across the material. The electromagnet is the temporary magnet as it acquires the magnetic properties when the electric current passes through it. When there is no electric current, its magnetic properties disappear.

Electromagnet consists of a wire wound on the coil and the current passes through the wire. The wire wound on the coil is mostly a ferromagnetic material like iron and the coil is a soft iron core. In an electromagnet, the magnetic field depends on the number of turns of the coil and the current flows through it.

From the given, steel core is wounded with wire it makes a strong electromagnet depending on the number of turns of the coil. The cardboard core is not a ferromagnetic material and hence, a small number of turns over the cardboard forms the weakest electromagnet.

Hence, the ideal solution is option B)20 coils of insulated wire around a hollow cardboard core.

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The final kinetic energy will it have just before hitting the ground is 5.8755 KJ.

Mass of the ball, M = 40 kg

Height of the ledge, S = 15 m

Initial velocity, u = 0 m/s (at rest)

Using equation of motion we get,

V² = u² + 2aS

V² = 0 + 2 × 9.8 × 15

V² = 294

v = 17.14m/s

kinetic enrgy is calculated as :

E = 1/2 × mass × v²

for initial velocity (u =0) kinetic energy is

E = 1/2 × 40 × 0²

E = 0J

for final velocity (v) kinetic energy is :

E = 1/2 × 40 × (17.14)²

E = 5,875.5 J

E = 5.8755 KJ

The final kinetic energy will it have just before hitting the ground is 5.8755 KJ.

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Answer:

In a 32-day period, a 512 mg sample of Iodine-131 will be reduced to 32 mg.
7
Since the half-life is 8 days, we can divide 32 days by the half-life to find the number of half-lives that have occurred: 32 days ÷ 8 days/half-life = 4 half-lives.

Now, for each half-life, the amount of Iodine-131 will decrease by half. After 1 half-life (8 days), 512 mg will become 256 mg. After 2 half-lives (16 days), it will be 128 mg. After 3 half-lives (24 days), it will be 64 mg. Finally, after 4 half-lives (32 days), the amount of Iodine-131 remaining in the sample will be 32 mg.

So, in a 32-day period, a 512 mg sample of Iodine-131 will be reduced to 32 mg.

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Answer:

Explanation:

Image result for write down an equation that relates the heat energy generated by one turn of the crank to the temperature increase of the cylinder in one turn

The quantitative relationship between heat transfer and temperature change contains all three factors: Q = mcΔT, where Q is the symbol for heat transfer, m is the mass of the substance, and ΔT is the change in temperature. The symbol c stands for specific heat and depends on the material and phase.

Answer:

the time it took Charilanda to get to the truck is 3s.

Explanation:

Given;

initial velocity of Charilanda, u = 2 m/s

final velocity of Charilanda, v = 5 m/s

acceleration of Charilanda , a = 1 m/s²

let her time of motion = t

\(a = \frac{v-u}{t} \\\\t = \frac{v-u}{a} \\\\t = \frac{5-2}{1} \\\\t = 3 \ s\)

Therefore, the time it took Charilanda to get to the truck is 3s.

Spongebob is pulling the wagon with a force of 57 N. It's important to note that this calculation assumes there is no friction or air resistance acting on the wagon

According to Newton's Second Law, force (F) is equal to the product of mass (m) and acceleration (a), or F=ma. In this problem, the mass of the wagon and snail combined is given as 60 kg, and the acceleration of the wagon is 0.95 m/\(s^2\). To find the force that Spongebob is pulling with, we can use the formula F=ma:

F = 60 kg x 0.95 m/\(s^2\)

F = 57 N

Therefore, Spongebob is pulling the wagon with a force of 57 N. It's important to note that this calculation assumes there is no friction or air resistance acting on the wagon, as those forces would make the acceleration different from 0.95 m/\(s^2\) and would need to be taken into account in the calculation.

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Answer:

1530 m/s

Explanation:

Given that :

Speed = distance / time

Travel time take = 0.2 s

Distance covered = 306 metres

The speed of sound in the material :

Speed = distance / time = 306 m / 0.2

Speed = 1530 m/s

Answer:

If it is a True or False question then the answer would be TRUE

Explanation:

A hockey puck can transfer kinetic energy by

When a hockey player hits the puck with their stick, they transfer kinetic energy to the puck.

The puck then moves across the ice, and if it collides with another object (such as the boards or another player's stick), some of the kinetic energy from the puck is transferred to that object through touch.

This demonstrates that kinetic energy can move from one item to another and that energy transfers from materials through touch.

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Answer:

Magnitude of frictional force = 30 N

Explanation:

According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:

Fn=m.a

The net force is the vector addition of each individual force. If the sum of all the forces acting on an object is zero, then the acceleration is zero. That means the object moves at a constant speed or is at rest.

When an object is pushed across a horizontal rough surface, there are two forces acting in the direction of the motion: The applied force and the frictional force.

If the applied force is greater than the frictional force, then the object moves at a constant positive acceleration. If the frictional force is greater than the applied force, then the object won't move at all (if it was at rest) or will start a deaccelerated motion (braking).

Finally, if both forces are equal, the object will move at a constant speed or remains at rest. Since the box is moving at a constant speed, we can conclude the frictional force equals the applied force:

Magnitude of frictional force = 30 N

Explanation:

it requires energy

hope it helps

Answer:

Emperor penguins are near the top of the Southern Ocean’s food chain. They have a varied menu that changes with the season. Some prey items are more important than others. One of the most frequently eaten prey species is the Antarctic silverfish Pleuragramma antarcticum. They also eat other fish, Antarctic krill and some species of squid. Most prey items are small. Since they are very cold when ingested, their small size makes it easier to bring food up to body temperature to digest it.

The question that would allow a student to determine if a wave was an

electromagnetic wave are:

Option A and C are the correct options.

The question that would allow a student to determine if a wave was an

mechanical waves are:

Option B and D are the correct options.

This refers to a wave that has the ability to transmit its energy through a vacuum. Mechanical waves need a medium in order to send their energy from one location to another. An example of a mechanical wave is sound wave.

This refers to waves that are made as a result of vibrations between an electric field and a magnetic field.   Electromagnetic waves are made up of oscillating magnetic and electric fields.

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Because due to smaller size, the moon has less gravity than earth abd so it cannot hold gases like earth .