an analyst working in tableau uses color to show the range where a data point is from and intensity to show its magnitude. what is this called?

The terminal speed of the marble is 0.588 m/s.

The term "force" has a specific meaning in science. At this level, calling a force a push or a pull is quite appropriate. A force is not something an item "has in it" or that it "contains." One thing experiences a force from another. There are both living things and non-living objects in the concept of a force.

We know that,

F = mg                          ......(1)

where,

F = force

m = mass

g = acceleration due to gravity

Also,

v = F/k                            ......(2)

where,

v = terminal speed

k = proportionality constant

Substituting the value of F from equation (1) in equation (2)

v = mg/k                             .......(3)

Given,

m = 30 g = 0.030 kg

k = 0.500 kg/s

g = 9.8 m/s²

To find,

v =?

Put the values in equation (3)

v = mg/k        

v = 0.03(9.8)/ 0.500

= 0.294/0.500

= 0.588 m/s

​

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Answer:

Capacitance is the ratio of the charge to the potential difference. How is the charge stored on a capacitor related to the capacitance of the capacitor and the potential difference across the capacitor? The charge equals the product of the capacitance and the potential difference.

Explanation:

Hope this helps

Answer:

The red car would experience the greatest acceleration.

Explanation:

Newton says that Force equals mass times acceleration or F = ma

We get a = F/m

If we want the greatest acceleration or a, mass or m must be the lowest.

The work done in stretching the spring from its natural length to 10 inches beyond its natural length is 112 lb·in.

The work done in stretching a spring is given by the formula:

\(\[ W = \frac{1}{2} k (x_f^2 - x_i^2) \]\)

In this case, the spring is stretched 4 inches beyond its natural length, so the initial displacement is 4 inches. The force required to hold the spring at this displacement is 16 lb. We can use Hooke's Law to find the spring constant:

\(\[ k = \frac{F}{x_i} = \frac{16 \, \text{lb}}{4 \, \text{in}} = 4 \, \text{lb/in} \]\)

Now, we can calculate the work done in stretching the spring to 10 inches beyond its natural length:

\(\[ W = \frac{1}{2} (4 \, \text{lb/in}) \left( (10 \, \text{in})^2 - (4 \, \text{in})^2 \right) = 112 \, \text{lb·in} \]\)

Therefore, the work done in stretching the spring is 112 lb·in.

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Answer:

The percent uncertainty of the volume=\(\frac{15.70}{523.59} \times 100=2.99\%\)

The volume of sphere with absolute uncertainty=\(523.59 \pm 15.7 cm^3\)

Explanation:

Radius of sphere = 5 cm

Radius with uncertainty r'= \(5 \pm 0.05\)

Volume of sphere = \(\frac{4}{3} \pi r^3=\frac{4}{3} \pi (r')^3\)

\(V=\frac{4}{3} \pi (r')^3\\\frac{dV}{dr'}=4\pi (r')^2\)

Where dV is the uncertainty in volume

dr' is the uncertainty in radius

\(dV=4\pi (r')^2 dr'\\dV=4 \pi (5)^2(0.05)\\dV=15.70\\V=\frac{4}{3} \pi (r')^3=\frac{4}{3} \pi (5)^3=523.59\)

The percent uncertainty of the volume=\(\frac{15.70}{523.59} \times 100=2.99\%\)

The volume of sphere with absolute uncertainty=\(523.59 \pm 15.7 cm^3\)

a. During the upward acceleration, the net force acting on the man is the force due to gravity (weight) plus the force exerted by the elevator (normal force), which can be expressed as:

Fnet = ma

Fnet = (72 kg)(1.30 m/s^2) = 93.6 N

The normal force exerted by the scale is equal in magnitude to the force due to gravity, so:

Fnormal = mg

Fnormal = (72 kg)(9.81 m/s^2) = 706.32 N

The scale reading is the magnitude of the normal force, which is:

scale reading = Fnormal = 706.32 N

b. During the constant velocity motion, the elevator is not accelerating, so the net force acting on the man is zero. Therefore, the normal force exerted by the scale is equal in magnitude to the force due to gravity:

Fnormal = mg

Fnormal = (72 kg)(9.81 m/s^2) = 706.32 N

The scale reading is the magnitude of the normal force, which is:

scale reading = Fnormal = 706.32 N

c. During the upward deceleration, the net force acting on the man is the force due to gravity (weight) minus the force exerted by the elevator (normal force), which can be expressed as:

Fnet = ma

Fnet = (72 kg)(-0.500 m/s^2) = -36 N

The normal force exerted by the scale is now less than the force due to gravity, so:

Fnormal = mg - Fnet

Fnormal = (72 kg)(9.81 m/s^2) - (-36 N)

Fnormal = 760.32 N

The scale reading is the magnitude of the normal force, which is:

scale reading = Fnormal = 760.32 N

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Digital signals more reliable than analog signals because of the many following reasons:

Analog Signal is a Continuous type signal which has one time varying quantities such as Voltage, Pressure, etc. As in the analog audio signal the instantaneous voltage continuously varies with the sound wave's pressure.

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Answer:

800N

Explanation:

as we know that

weight = mass × acceleration due to gravity

= 80kg × 10 m/s^2

= 800N.

Answer:

V1 = 15m/s[45o E of N.] = 45o N. of E.

V2 = 18m/s[5o N. of E.].

Vr = 15m/s[45o] + 18m/s[5o].

Vr = 15*Cos45+15*sin45 + 18*Cos5+18*sin5.

Vr = (10.61+10.61i) + (17.93+1.57i) = 28.54 + 12.18i.

Magnitude = sqrt(28.54^2 + 12.18^2) =

Tan A = Y/X = 12.18/28.54 = 0.42887. A =

0  2

posted by Henry

Apr 8, 2017

31 m/s

23 ° north of east

Explanation:

I think least electricity is used between probably 7-8a.m. and 4-5p.m.

This is because, around those times, the suns already out. Depending on how sunny it is, it may not be as cold as all the other times of the day. And by then, buildings are typically already warmed all up. Everybody's body heat also may play a factor in buildings. ( if there is a ton of people )

Ray could use Metal bar 1 to find out if Metal bar 2 is a magnet by bringing them close to each other. If Metal bar 2 is a magnet, it will be attracted to Metal bar 1.

Ray can also try to move Metal bar 1 along the length of Metal bar 2. If Metal bar 2 is a magnet, it will induce a magnetic field in Metal bar 1, causing it to experience a force as it moves. Alternatively, when Ray moves Metal bar 1 along the length of Metal bar 2, he would observe a force acting on Metal bar 1 as it moves. This is because the magnetic field produced by Metal bar 2.

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Answer:

hydrochlorine +12÷B to the power of 4 -× y reapeated zminus 2 to the power of 9

Answer:

Shiny objects don't absorb heat as well as dull objects. Shiny objects reflect heat or they reflect more heat then absorb it. So the heat thats being hit on a shiny object is being reflected instead of being absorbed. Dull objects are better at aborbing heat. So that makes dull objects heat up faster than shiny objects, since shiny reflects more and dull doesn't as much.

Explanation:

I hope it helps! Have a great day!

pan~

Answer:

The velocity vBW of the boat relative to the water is 4.0 m/s, directed perpendicular to the current, as in Figure 3.18.

Explanation:

The boat is perpendicular to the shore. Then the net velocity of the boat with respect to river is 5 m/s. The observer feels like the boat is moving slower than they appear actually.

Relative velocity is velocity of an object measured with respect to other object which can be of stationary or moving with a speed. Thus speed relative to another object is called the relative velocity.

The relative velocity is what's the speed for an observer but it differs from actual velocity. Sometimes it may slower or faster depending on the object with which a we are relating the speed.

Given that the speed of the boat = 4 m/s

speed of river = 3 m/s.

Both are perpendicular and the net velocity of the boat is :

r = √(3² + 4²) = 5 m/s.

Hence, the velocity of the boat relative to the shore will be 5 m/s.

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Answer:

I really think it's Chinese

Explanation:

hope this helps

Answer: It has the skill to nest

sorry if I'm wrong

Answer:

B: A colorful beak

Explanation:

i hope this helped!

This can be expressed as,T2 = (M + m)aT1 = Mg/2where,T2−T1= (M + m)a − Mg/2 Solving the above equations will give the value of α and then we can find out the final velocity of the platform.

Here's the solution to the given problem: Let the origin of our coordinate system be located at the center of the platform. We can assume that there is no friction between the platform and the ground. If v  Rw, the woman will collide with the center of the platform after the platform stops moving because it is not able to move with the required speed to reach the center of the platform before it stops. The net torque about the origin, assuming that the angular momentum is conserved, is Iα = τ, or, assuming that the angular momentum is conserved,T2−T1=IwoR2wR2+mr2αT2 = Mg/2 + Mv/RT1 = (M + m)g/2Let a be the speed of the platform just after the woman reaches the center, which is given by a = v + αr. This can be expressed as,T2 = (M + m)aT1 = Mg/2where,T2−T1= (M + m)a − Mg/2Solving the above equations will give the value of α and then we can find out the final velocity of the platform.

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Answer:

Change in velocity

−2−10=−12

Time required is 4 seconds

a=Δv/t

=−12/4

=−3m/s²

Hence,

option C is correct answer.

Explanation:

Because liquids are basically incompressible......gases will compress and the machine will fail to do what you want it to do .

As the vehicle turns, the tires on one side will leave marks on the ground while the tires on the other side do not. Therefore, only the tire marks from the turning side are visible.

When a vehicle travels in a curved path, typically only two tire marks are visible. This is because most vehicles have four tires, with two tires on each side. As the vehicle turns, the tires on one side will leave marks on the ground while the tires on the other side do not. Therefore, only the tire marks from the turning side are visible. therefore when a vehicle travels in a curved path, typically only two tire marks are visible.

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Three forces are at work on the skateboard when a skater is motionless on it. The board is first drawn towards Earth by gravity. Second, the skater's weight presses down on the board. Third, the skateboard is raised by the ground.

According to Newton's first law of motion, an object at rest will stay at rest and an object in motion will stay in motion unless it is acted upon by an unbalanced force. A moving object will continue to move without the presence of an unbalanced force, and it will do so at the same speed and in the same direction. Because inertia is an object's propensity to resist a change in motion, Newton's first law of motion is frequently referred to as the law of inertia.

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The current through a wire change if the wires resistance is increased in the following ways;

The relationship between resistance and the area of the cross section of a wire is inversely proportional. Resistance also depends on the material of the conductor.

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Ankle mobility. Good ankle mobility contributes to better balance, fewer falls, and better performance during activities like squats and deadlifts.

Range of motion (ROM) exercises are done to preserve flexibility and mobility of the joints on which they are performed.

What is meant by Ankle mobility ?

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Answer:

10g to kg=0.01

20×0.01=0.2

Force of 0.2N

Answer:

I think the answer is D-they require onky one electron to fill their outer energy level.

Time taken by the car to travel 300 miles is 4.615 hours.

The speed of any moving object is the ratio of the distance traveled and the time taken to cover that distance.

Given is the distance d = 300 miles and the speed s = 65 miles/hour, then the time taken t will be

s=d/t

65 = 300/t

t= 4.615 hours

Thus, time taken by the car to travel 300 miles is 4.615 hours.

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The coefficient of kinetic friction between the tires and the road is approximately 0.383.

To determine the coefficient of kinetic friction, we can use the equation relating the deceleration (a) of the van to the coefficient of kinetic friction (μ) and the acceleration due to gravity (g). The equation is given by a = μ * g.

First, we need to calculate the deceleration of the van. The initial speed (vi) is 100 km/h, and the final speed (vf) is 40 km/h. We convert these speeds to meters per second by dividing by 3.6 (since 1 km/h = 1000 m/3600 s). Thus, vi = 100 km/h ÷ 3.6 = 27.8 m/s and vf = 40 km/h ÷ 3.6 = 11.1 m/s.

Next, we can calculate the deceleration using the formula a = (vf - vi) / t, where t is the time interval of 5 seconds. Therefore, a = (11.1 m/s - 27.8 m/s) / 5 s = -3.34 m/s^2 (negative sign indicates deceleration).

Finally, we can calculate the coefficient of kinetic friction using the equation a = μ * g. Rearranging the equation, we have μ = a / g. Assuming the acceleration due to gravity is 9.8 m/s^2, we find μ = -3.34 m/s^2 / 9.8 m/s^2 = -0.34.

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