An airplane needs to head due north, but there is a wind blowing from the southeast at 50 km/hr. The plane flies at an airspeed of 500 km/hr... (check attachment)

Answer:

all for now is equivalent to 3:2 are: 9:6 27:18 and 81: 54

Step-by-step explanation:

hope that helps>3

Answer:

\(x=8, y=3\)

Step-by-step explanation:

Recall that if a matrix multiplication of two matrices is defined, then the number of columns of the first matrix is equivalent to the number of rows of the second matrix.

Since matrix M has (11-x) columns and matrix N has y rows, and MN is defined, so it follows:

\(y=11-x----(1)\)

Since matrix N has (y+5) columns and matrix M has x rows, and NM is defined, so it follows:

\(y+5=x----(2)\)

Substitute (1) into (2):

\(11-x+5=x\\2x=16\\\therefore x=8--(3)\)

Substitute (3) into (1):

\(y=11-8=3\)

Answer:

D) 500 square feet

Step-by-step explanation:

20x40=800

30x10=300

800-300=500

Answer:

500 square feet

Step-by-step explanation:

Walk way A=bh

A=40 times 20

A=800

garden

A=30 times 10

A=300

Now subtract walkway from the garden. 800 - 300= 500

Answer: CA= 13.5

Step-by-step explanation:

tan 64 = CA/6.6

2.05 = CA/6.6

CA = 13.5

Ta-Da!

In this example, process A completed its final quantum in q4, process B completed its final quantum in q4, and process C completed its final quantum in q4.

To determine which queue each process is in when it begins its final quantum, we need to know the length of time each process has been running and how many times it has already used each queue's quantum. Without that information, we cannot determine which queue a process will be in at a specific point in time. However, we can provide an example of how a process might move between the queues over time.

Let's consider the following three processes:

Process A - CPU burst time = 100s

Process B - CPU burst time = 30s

Process C - CPU burst time = 50s

Assume that all three processes arrive at the scheduler at the same time and are added to q1, the highest priority queue.

When the scheduler begins, it will select the first process in q1, which is process A. Since q1 has a quantum of 5s, process A will run for 5s before it is preempted and placed at the back of q2.

The next process in q1 is B. B will also run for 5s before being preempted and placed at the back of q2.

Next, the scheduler will select process C from q1. C will run for 5s before being preempted and placed at the back of q2.

Now the scheduler has completed one round-robin cycle through q1, and all the processes in q1 have used up their q1 quantum. The scheduler will move on to q2 and select the first process in that queue, which is process A. Since q2 has a quantum of 10s, process A will run for an additional 5s before being preempted and placed at the back of q3.

The next process in q2 is B. B will run for 10s before being preempted and placed at the back of q3.

Next, the scheduler will select process C from q2. C will run for 10s before being preempted and placed at the back of q3.

Now the scheduler has completed one round-robin cycle through q2, and all the processes in q2 have used up their q2 quantum. The scheduler will move on to q3 and select the first process in that queue, which is process A. Since q3 has a quantum of 20s, process A will run for an additional 10s before being preempted and placed at the back of q4.

The next process in q3 is B. B will run for 20s before being preempted and placed at the back of q4.

Next, the scheduler will select process C from q3. C will run for 20s before being preempted and placed at the back of q4.

Now the scheduler has completed one round-robin cycle through q3, and all the processes in q3 have used up their q3 quantum. The scheduler will move on to q4 and select the first process in that queue, which is process A. Since q4 has a quantum of 40s, process A will run for an additional 20s before completing its CPU burst.

The next process in q4 is B. B will run for 30s before completing its CPU burst.

Finally, the scheduler will select process C from q4. C will run for 40s before completing its CPU burst.

However, it's important to note that the exact behavior of the scheduler will depend on the length of time each process has been running and how many times it has already used each queue's.

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Answer:

t=10.9

Step-by-step explanation:

8t-13t+10(t-2)=34

8t-13t+10t-20=34

5t-20=34

5t=54

t=10.9

The probability of spinning an even number, flipping tails, then spinning an odd number is:

1/9   (as fraction) or 11.11% (as percent)

To find the probability of spinning an even number, flipping tails, then spinning an odd number. We need to consider the individual probabilities. That is:

We have only one even number in the spinner, and that is 2. Thus,

P(even number) = 1/3

For a coin, the probability of head or tail is 1/2. Thus,

P(tail) = 1/2

We have two odd number in the spinner, and that is 1 and 3. Thus,

P(odd number) = 2/3

Therefore, the probability of spinning an even number, flipping tails, then spinning an odd number will be:

P(even, tail, odd) = 1/3 * 1/2 * 2/3

                            = 2/18

                            = 1/9   (as fraction)

In percent:

P(even, tail, odd) =  1/9 * 100

                            = 11.11%

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Answer: Please mark brainliest if right

113/100

Step-by-step explanation:

Convert to a mixed number by placing the numbers to the right of the decimal over 100. Reduce the fraction. Then, convert the mixed number to an improper fraction by multiplying the denominator by the whole number and adding the numerator to get the new numerator. Place this new numerator over the original denominator.

the fraction equivalent of the repeating decimal 1.13 (3 repeated) in simplest form is 17/15.

To convert the repeating decimal 1.13 (3 repeated) into a fraction, we can use the concept of a geometric series.

Let's denote the repeating decimal as x:

x = 1.133333...

To eliminate the repeating part, we can multiply x by a power of 10 that will shift the repeating part to the left of the decimal point:

10x = 11.33333...

Now, subtracting the original equation from this equation, we can eliminate the repeating part:

10x - x = 11.33333... - 1.133333...

Simplifying:

9x = 10.2

Dividing both sides by 9, we find:

x = 10.2/9

Simplifying the fraction, we get:

x = 1.133333... = 10.2/9 = 17/15

Therefore, the fraction equivalent of the repeating decimal 1.13 (3 repeated) in simplest form is 17/15.

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Answer:

2x + 3

Step-by-step explanation:

Let's call the number x

twice a number is 2 times the number, or in this case 2x

3 more than 2x is 2x + 3

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

The equation that has infinitely many solutions in the options is 21 + 2.5w = 6 +5.7w - 3.2w + 15

An equation with infinitely many solutions essentially have same thing on both sides.

Generally, a linear equation has infinitely many solution when the equations are equivalent. Let take for example:

The equation above have infinitely many solution because there is no actual value of y.

Therefore,

2y + 2 = 2y + 2

2 = 2

We can see both sides are equal to each other. So, this is an infinitely many solution.

Therefore, 21 + 2.5w = 6 +5.7w - 3.2w + 15 has an infinitely many solution.

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AOM is under zero, as stated in the sequential equation

Answer:

3.9 kilograms

Step-by-step explanation:

If we take 40% of 6.5 kilograms, which is 2.6, and subtract it from the original mass, which is 6.5, we end up with the new mass of the pumpkin which is 3.9 kilograms.

(sorry if this is confusing, but I hope it helped)

Answer:

4:1

Step-by-step explanation:

4 trucks for 1 van

Answer:

Given:

Area of the sector (A) = 104π/9 square inches

Central angle (θ) = 65 degrees

The formula for the area of a sector of a circle is:

A = (θ/360) * π * r^2

We can rearrange this formula to solve for the radius (r):

r^2 = (A * 360) / (θ * π)

Plugging in the given values:

r^2 = (104π/9 * 360) / (65 * π)

r^2 = (104 * 40) / 9

r^2 = 4160 / 9

r^2 ≈ 462.22

Taking the square root of both sides:

r ≈ √462.22

r ≈ 21.49

Therefore, the radius of the circle is approximately 21.49 inches.

Answer: 8 inches

Step-by-step explanation:

Answer:

WN=37.8

Step-by-step explanation:

WN=18%*210

WN=0.18*210

WN=37.8

Answer:

Step-by-step explanation:

\(9\frac{1}{8} = 2\frac{1}{4} +x\)

\(\frac{9*8+1}{8} =\frac{4*2+1}{4} +x\)

\(\frac{73}{8} =\frac{9}{4} +x\)

\(\frac{73}{8} =\frac{9+4*x}{4}\)

do cross multiplication

\(8(4x+9)=4*73\\32x+72=292\\32x=292-72\\x=220/32\\x=6.875\)

a. Constant speed, C =  0. 19 miles/minutes

b. The fraction representing her constant speed is  1/x miles/minutes

c. The time it takes her to drive exactly 1 mile is 5. 38 minutes

The formula for calculating constant speed is expressed as;

Constant speed = total distance covered/ total time taken

From the information given, we have that;

Now, substitute the values into the formula

Constant speed = 1. 3 / 7

Divide the values

Constant speed = 0. 19 miles/minutes

When distance 1 mile, time taken = x minutes

Constant speed = 1/x miles/minutes

If 1. 3 miles = 7 minutes

Then, 1 mile = x

cross multiply

x = 7/1. 3

x = 5. 38 minutes

Hence, the constant speed is 0. 19 miles/minutes

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There are 152 red pens and 190 blue pens in Max's drawer, given that there are a total of 342 pens altogether.

Let's solve the problem step by step:

Identify the given information:

The ratio of red pens to blue pens is 4 to 5.

There are a total of 342 pens in the drawer.

Set up the ratio equation:

Let's assume the number of red pens is 4x, and the number of blue pens is 5x.

Here, 'x' is a scaling factor that allows us to find the actual number of pens.

We can write the equation as: 4x + 5x = 342.

Simplify and solve the equation:

Combining like terms, we have 9x = 342.

Divide both sides of the equation by 9 to solve for 'x':

x = 342 / 9 = 38.

Calculate the number of red pens and blue pens:

Now that we have the value of 'x', we can find the number of red and blue pens:

Number of red pens: 4x = 4 × 38 = 152.

Number of blue pens: 5x = 5 × 38 = 190.

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Step-by-step explanation:

Based on the information given, we have a diagram with two sides labeled as 13.3 mm and 5.5 mm, and another side labeled as X mm.

To find the length of X, we can use the fact that the sum of the lengths of the sides of a triangle is equal to the perimeter.

Perimeter = 13.3 mm + 5.5 mm + X mm

The perimeter is the total distance around the triangle. Since we have three sides, the perimeter is the sum of the lengths of those sides.

To find X, we can subtract the sum of the known sides from the perimeter:

X mm = Perimeter - (13.3 mm + 5.5 mm)

Since the value of X is not given, we cannot calculate it without the perimeter value. If you provide the perimeter value, I can help you find the length of X.

Right format of question:

Plot two points that are 7 units from Point D and also share the same x-coordinate as Point D.

Answer:

\(D' = (-4,-6)\) and \(D' = (-4,8)\)

Step-by-step explanation:

Given

\(D(x,y) = (-4,1)\)

Required

Determine a point 7 points from D and in the same x coordinate

Represent this point with D'.

From the requirement of the question, D' has two possible values and these values are:

\(D' = D(x,y-7)\) ----> 7 units down and

\(D' = D(x,y+7)\) ----> 7 units up

Substitute values for x and y in \(D' = D(x,y-7)\) and \(D' = D(x,y+7)\)

So, we have:

\(D' = D(x,y-7)\)

\(D' = (-4,1 - 7)\)

\(D' = (-4,-6)\)

\(D' = D(x,y+7)\)

\(D' = (-4,1+7)\)

\(D' = (-4,8)\)

Answer:

(x+2), (x-4), (x-3)

Step-by-step explanation:

Use the rational root theorem to get started, then factor the remaining quadratic to find:

x^3 − 5x^2 − 2x + 24 = (x + 2)(x − 4)(x − 3)

Explanation:

Let  f(x) =x^3 − 5x^2 − 2x + 24

By the rational root theorem, any rational zeros of  f(x)  must be expressible in the for p/q for integers p, q with p a divisor of the constant term 24 and q a divisor of the coefficient 1 of the leading term.

That means that the only possible rational zeros are the factors of 24, namely:

± 1, ± 2, ± 3, ± 4, ± 6, ± 12, ± 24

Try each in turn:

f(1) = 1 − 5 − 2 + 24 = 18

f(−1) = −1 − 5 + 2 + 24 = 20

f(2) = 8 − 20 − 4 + 24 = 8

f(−2) = −8 − 20 + 4 + 24 = 0

So  x = −2  is a zero and (x + 2) is a factor.

x^3 − 5x^2 − 2x + 24 = (x + 2)(x^2 − 7x + 12)

We can factor  

x^2 − 7x + 12 by noting that 4 × 3 = 12 and 4 + 3 = 7, so:

x^2 − 7x + 12 = (x − 4)(x − 3)

Putting it all together:

x^3 − 5x^2 − 2x + 24  =  (x + 2)(x − 4)(x − 3)

Answer: 37.68 inches

A frisbee is round so its a circle. And the formula of circumference of a circle is 2πr (r = 6 inches and π = 3.14)

So, 2πr = 2 * 3.14 * 6

2πr = 37.68 inches

The distance from Trinidad to Tobago via the ferry is approximately 158 kilometers, but when rounded to the nearest tens, it is approximately 160 kilometers.

The distance from Trinidad to Tobago via the ferry is approximately 158 kilometers. To determine the distance to the nearest tens, we need to round this value to the nearest multiple of 10.

To round a number to the nearest tens, we look at the digit in the ones place. If it is 0 to 4, we round down, and if it is 5 to 9, we round up.

In this case, the digit in the ones place is 8. Since 8 is closer to 10 than to 0, we round up to the nearest tens. Thus, the distance from Trinidad to Tobago can be rounded to 160 kilometers.

Rounding to the nearest tens gives us a value that is easier to work with and provides a rough estimate. It is important to note that this rounded value is not exact and may differ slightly from the actual distance. However, for practical purposes, rounding to the nearest tens is often sufficient.

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The amount cheaper is the car washes Malcolm orders than the car washes Martha's order is $13.

The correct answer choice is option B.

Malcolm's gift card = $50.

Cost Malcolm's car wash per visit = $7

Martha's gift card = $180

Cost Martha's car wash per visit = Difference between gift card balance of first and second visit

= $180 - $160

= $20

How cheap is the car washes Malcolm orders than the car washes Martha's order = $20 - $7

= $13

Therefore, Malcolm's car wash is cheaper than Martha's car wash by $13

The complete question is attached in the diagram.

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Answer:

We can start by finding how many pages Jordayn reads per hour:

Pages per hour = 72 ÷ (1 1/2) = 72 ÷ 3/2 = 48

So, Jordayn reads 48 pages per hour.

To find out how long it would take her to read a 168-page book, we can use the following formula:

Time = Pages ÷ Pages per hour

Time = 168 ÷ 48

Time = 3.5

Therefore, it would take Jordayn 3.5 hours to read a 168-page book, assuming her reading speed remains constant

Answer:

y=2x-6

Step-by-step explanation:

y+4=-2(x-1)

Since the slope intercept form is in the form of:

y=mx+c

Making above equation in this form.

y+4=-2(x-1)

opening bracket

y+4=2x-2

subtracting both side by 4.

y+4-4=2x-2-4

y=2x-6

This equation is the slope intercept form.

b = speed of the boat in still water

c = speed of the current

when going Upstream, the boat is not really going "b" fast, is really going slower, is going "b - c", because the current is subtracting speed from it, likewise, when going Downstream the boat is not going "b" fast, is really going faster, is going "b + c", because the current is adding its speed to it.

Now, the boat goes Upstream 48 miles, so Downstream must be travelling the same 48 miles back.

\({\Large \begin{array}{llll} \underset{distance}{d}=\underset{rate}{r} \stackrel{time}{t} \end{array}} \\\\[-0.35em] ~\dotfill\\\\ \begin{array}{lcccl} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\ \cline{2-4}&\\ Upstream&48&b-c&3\\ Downstream&48&b+c&2 \end{array}\hspace{5em} \begin{cases} 48=(b-c)(3)\\\\ 48=(b+c)(2) \end{cases} \\\\[-0.35em] ~\dotfill\)

\(\stackrel{\textit{using the 1st equation}}{48=(b-c)3}\implies \cfrac{48}{3}=b-c\implies 16=b-c\implies \boxed{16+c=b} \\\\\\ \stackrel{\textit{using the 2nd equation}}{48=(b+c)2}\implies \cfrac{48}{2}=b+c\implies 24=b+c\implies \stackrel{\textit{substituting}}{24=(16+c)+c} \\\\\\ 24=16+2c\implies 8=2c\implies \cfrac{8}{4}=c\implies \boxed{2=c}~\hfill~\stackrel{ 16~~ + ~~2 }{\boxed{b=18}}\)

For the given CDF of X, the pmf of X at 1,3,4,6 and 12 is written as :

P(X = k) = 0.30 for k = 1 , P(X = k) = 0.10 for k = 3,

P(X = k) = 0.05 for k = 4 , P(X = k) = 0.15 for k = 6,

P(X = k) = 0.40 for k = 12.

In order to find the probability mass function (PMF) of X, we need to calculate the probability that X takes on each possible value.

Since X can take on any positive integer value, we can start by calculating the probability that X equals each positive integer.

⇒ P(X = 1) = 0.30,

⇒ P(X = 3) = F(3) - F(1) = 0.40 - 0.30 = 0.10

⇒ P(X = 4) = F(4) - F(3) = 0.45 - 0.40 = 0.05

⇒ P(X = 6) = F(6) - F(4) = 0.60 - 0.45 = 0.15

⇒ P(X = 12) = F(12) - F(6) = 1 - 0.60 = 0.40

Therefore, the required PMF of X is: P(X = 1) = 0.30 , P(X = 3) = 0.10 , P(X = 4) = 0.05 , P(X = 6) = 0.15 and P(X = 12) = 0.40 .

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The given question is incomplete, the complete question is

An insurance company offers its policyholders a number of different premium payment options. For a randomly selected policyholder, let X = the number of months between successive payments.

The CDF of X is as follows:

F(x) = {0           x < 1

         {0.30 1 ≤ x < 3

         {0.40 3 ≤ x < 4

         {0.45 4 ≤ x < 6

         {0.60 6 ≤ x < 12

         {1        12 ≤ x

What is the pmf of X at 1,3,4,6 and 12?