An air-conditioning system involves the mixing of cold air and warm outdoor before the mixture is routed to the conditional room in steady operation. Cold air enters the mixing chamber at 7 C and 105kpa at a rate of 0. 55 m3/s while warm air enters at 34 C and 105 kpa. The air leaves the room at 24 C.
The ratio of the mass flow rates of the hot to cold air steams is 1. 6
using variable specific heats, determine
a) the mixture temperture at the inlet of the room
b) the rate of heat gain of the room
Answers
a) To find the mixture temperature at the inlet of the room, we can use the equation:
(m_h * T_h + m_c * T_c) / (m_h + m_c) = T_m
where:
m_h = mass flow rate of hot air
T_h = temperature of hot air
m_c = mass flow rate of cold air
T_c = temperature of cold air
T_m = mixture temperature
Given that the ratio of the mass flow rates is 1.6, we can say m_h = 1.6 * m_c. Let's substitute the known values:
(1.6 * m_c * 34 + m_c * 7) / (1.6 * m_c + m_c) = T_m
Simplifying the equation:
(54.4 * m_c + 7 * m_c) / 2.6 * m_c = T_m
(61.4 * m_c) / (2.6 * m_c) = T_m
61.4 / 2.6 = T_m
T_m = 23.62°C
Therefore, the mixture temperature at the inlet of the room is approximately 23.62°C.
b) To calculate the rate of heat gain of the room, we can use the equation:
Q = m_c * c_c * (T_m - T_r)
where:
Q = rate of heat gain
m_c = mass flow rate of cold air
c_c = specific heat of cold air
T_m = mixture temperature
T_r = temperature of the room (leaving air temperature)
The specific heat of air can vary with temperature, but for simplicity, let's assume c_c is constant at room conditions.
Substituting the known values:
Q = 0.55 * c_c * (23.62 - 24)
Simplifying the equation:
Q = -0.55 * c_c
Therefore, the rate of heat gain of the room is -0.55 * c_c. Note that the negative sign indicates a heat loss from the room rather than a gain.
Please note that the specific heat values and units are not provided, so the result for the rate of heat gain is expressed relative to c_c. You would need to know the specific heat value and units to obtain an absolute value.
Related Questions
Characteristics of information assurance management work force
Answers
Integrity involves assurance that all information systems are protected and not tampered with. IA aims to maintain integrity through means such as anti-virus software on all computer system, and ensuring all staff with access to know how to appropriately use their systems to minimize malware, or viruses entering information systems.
IT Governance provides a variety of E-learning courses to improve staff awareness on topics such as phishing and ransomware, as a means to reduce the likelihood of system being breached, and data exposed.
2. Availability
Availability simply means those who need access to information, are allowed to access it. Information should be available to only those who are aware of the risks associated with information systems.
3. Authentication
Authentication involves ensuring those who have access to information, are who they say they are. Ways of improving authentication involve methods such as two-factor authentication, strong passwords, bio-metrics and other devices. Authentication may also be used to not only identify users, but also other devices.
4. Confidentiality
IA involves the confidentiality of information, meaning only those with authorization may view certain data. This step is closely mirrored by the six data processing principles of the General Data Protection Regulation (GDPR), where by personal data must be processed in a secure manner "using appropriate technical and oganizational measures" ("integrity and confidentiality").
5. Nonrepudiation
The final pillar simply means someone with access to your organizations information system cannot deny having completed an action within the system, as there should be methods in place to prove that they did make said action.
A ___________ is defined as a change in shape of the part between the damaged and undamaged area hat is smooth and continuous . When the part is straightened, it is returned to proper shape and state without any areas of permanent deformation.
Answers
A bend is defined as a change in the shape of the part between the damaged and undamaged area that is smooth and continuous.
What is a kink?
A kink can be defined as a sharp bend with a small radius over a short distance.
So when any part is kinked it must be replaced without any doubt. A part is kinked if it just doesn't work on the repair.
What is a bend?
Unlike a kink, a bend can be restored. That is after a bend also a part can be bought back to its original position.
When the part is straightened, it is returned to proper shape and state without any areas of permanent deformation.
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3. Of the following answers, which is NOT a way for employees to control exposure routes?
Answers
There are a lot of ways employees uses in controlling exposure routes. But when risk assessment is not be performed is not a part of the control methods.
What are the three ways to control workplace hazards?The ways to control workplace hazards are known to be means taken to ensure safety in the workplace.
The examples are:
The use a hazard control plan to know, select and implement controls. Looking into the efficiency of existing controls, and creating plans with measures to protect workers in case of emergencies and nonroutine activities, etc.Learn more about exposure routes from
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determine the required diameter of a steel transmission shaft 10 m in length and of yield strength 350 mpa
Answers
The required diameter of a steel transmission shaft 10 m in length and of yield strength 350 mpa is 0.02795m
What is steel?
Steel is an iron alloy that contains a few tenths of a percent carbon to increase its strength and fracture resistance when compared to other types of iron. Many additional elements could exist or be added. Stainless steels that are corrosion- and oxidation-resistant often require an additional 11% chromium. Steel's high tensile strength and low cost make it useful in constructions, infrastructure, tools, ships, trains, automobiles, machinery, electrical appliances, armament, and rockets. The foundation metal of steel is iron.
Neglecting shaft weight Design the shaft using maximum shear stress theory and determine the required diameter
factor of safety = 1.5
length of shaft = 10 meters
material yield strength = 350 MPa
Torque = 500 N.m
The required shaft diameter = 0.02795 m
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Compute the corresponding angular measurements in the centesimal system for the
following angles which are in the Sexagesimal system
i. 125˚
ii. 12˚
Answers
The sexagesimal system angles for 125 is 2.18 and for 12 is 0.209
What is the sexagesimal system?
We know that 180 = π
Therefore,
(i) 125 = 125 * π / 180
= 125 * 22/ 7 * 180
= 2750 / 1260
= 2.18
(ii) 180 = π
12 = 12* π /180
= 12* 22/ 7 * 180
= 264/ 1260
= 0.209
Therefore, The sexagesimal system angle for 125 is 2.18 and for 12 is 0.209.
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Which statement describes the relay between minerals and rocks ?
Answers
Answer:
•○●□■hey hi!■□●○•Explanation:
Minerals and rocks are the same. Aggregates of minerals form rocks. Minerals determine the texture of a rock. Most rocks are made of a single mineral type.
☆♡hope this helps♡☆Faster air movement over an airfoil creates a _________ pressure field, which in turn allows lift.
a
Higher
b
Lower
Answers
Hai
Your answer will be A.
If you lower the Air Pressure your Object will Float Down ward. The Air Pressure allows it to Fly.
The pressure field created by faster air movement over an airfoil is; A: higher
What is pressure field?When the air hits the front of the wing, the air will flow in a steeper curve upward, than the bottom wing flow which will lead to the creation of a vacuum on top of the wing that pulls more air towards the top of the wing.
Finally, this air above does the same thing but it will move faster as a result of the vacuum pulling it in, and as such the vacuum now lifts the wing. Thus, Faster air movement over an airfoil creates a higher pressure field.
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A ciphertext has been generated with an affine cipher. The most frequent letter of the ciphertext is 'B', and the second most frequent letter of the ciphertext is 'U'. Break this code. Chapter 3, Problem 3P 6 Bookmarks Show all steps: қа ON The plaintext can be first encrypted by the multiplicative key and then by Caesar cipher key or first encrypted by Caesar cipher and then by multiplicative key is said to be affine ciphers. These two processes can give two different ciphers. The general form of the affine ciphers is as follows C = mp+b Given that the most frequent letter of the ciphertext is B and the second most frequent letter of the ciphertext is U. Let us consider the most frequent letter of the plaintext is 'e' and the second most frequent letter of the plaintext is 't'. Comment Submit Step 2 of 2 A • The numerical values of ciphertext B=1, U=20 and the numerical values of the plaintext e=4 and t=19. Then we can substitute the values in the equation as 1= (4a+b) mod 26 and 20=(19a+b) mod 26 • Therefore, 19=15a mod 26 . Let us consider a=1 by substituting 1 in place of a the above equation becomes 19=15(1) mod 26 • It will not satisfy the condition substitute 3 in place of a 19=15(3)mod 26=45 mod 26=19 • It satisfies the condition. Hence the value of a is 3. By substituting a value we can get the value of b as follows: 1=(4(3)+b) mod 26 = (12+b) mod 26=(12+15) mod 26=1 Hence, the value of a = 3 and b = 15.
Answers
The affine cipher key is a=3, b=15.
What are the values of a and b in the affine cipher?The given problem involves breaking an affine cipher, where the most frequent letter in the ciphertext is 'B', and the second most frequent letter is 'U'. Affine ciphers involve two processes: encryption by a multiplicative key followed by encryption by a Caesar cipher key or vice versa.
To solve this problem, we need to find the values of the multiplicative key (a) and the Caesar cipher key (b). Let's assume that the most frequent letter in the plaintext is 'e', which corresponds to the numerical value 4, and the second most frequent letter is 't', which corresponds to the numerical value 19.
By substituting the numerical values, we can set up the following equations:
1 = (4a + b) mod 26
20 = (19a + b) mod 26
From the second equation, we can deduce that 19 = 15a mod 26.
Let's consider the value a = 1. Substituting this into the equation, we get:
19 = 15(1) mod 26
However, this equation does not satisfy the condition. So, let's try a different value for a.
By substituting a = 3 into the equation, we get:
19 = 15(3) mod 26
19 = 45 mod 26
19 = 19
This equation satisfies the condition. Therefore, we have found that the value of a is 3.
Now, let's substitute the value of a into the first equation to find the value of b:
1 = (4(3) + b) mod 26
1 = (12 + b) mod 26
1 = (12 + 15) mod 26
1 = 27 mod 26
1 = 1
Hence, we have determined that the value of a is 3 and the value of b is 15.
Therefore, the affine cipher key for breaking this code is a = 3 and b = 15.
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Determine the required diameter of a steel transmission shaft 10 meters in length and material yield strength 350 MPa in order to resist a torque of up to 500 N.m. The shaft is supported by frictionless bearings at its ends. Design the shaft using the maximum shear stress theory, and selecting a factor of safety of 1.5. Neglect shaft weight.
Answers
Answer:
0.02795 m
Explanation:
Neglecting shaft weight Design the shaft using maximum shear stress theory and determine the required diameter
factor of safety = 1.5
length of shaft = 10 meters
material yield strength = 350 MPa
Torque = 500 N.m
The required shaft diameter = 0.02795 m
attached below is a detailed solution of the problem
determine the area occupied by one molecule of red 40 dye on the surface. assume the surface area of each wool piece to be 40 cm2. show your work.
Answers
The area occupied by one molecule of Red 40 dye on a 40 cm² wool piece can be found by dividing 0.004 m² by the number of dye molecules adsorbed on the surface.
To determine the area occupied by one molecule of Red 40 dye on the surface, we need to know the number of dye molecules that are present on the wool surface.
Let's assume that we have N molecules of Red 40 dye adsorbed on the surface of each 40 cm² wool piece.
The surface area of one wool piece is 40 cm² = 0.004 m².
The molecular weight of Red 40 dye is approximately 496 g/mol.
Assuming that the density of Red 40 dye is similar to that of water (1 g/cm³),
the volume occupied by one molecule of Red 40 dye is approximately 5.0 × 10⁻²³ m³ (496 g/mol divided by 6.02 × 10²³ molecules/mol).
To determine the area occupied by one molecule of Red 40 dye on the surface, we need to divide the surface area by the number of dye molecules, which gives:
Area occupied by one molecule = (0.004 m² / N)
Therefore, the area occupied by one molecule of Red 40 dye on the wool surface is (0.004 m² / N),
where N is the number of Red 40 dye molecules adsorbed on the surface of each 40 cm² wool piece.
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Identify the careers that match the descriptions. Operates machines that cut through rocks underground so natural resources can be harvested: Studies and manages natural resources to protect the environment: Manages forests for conservation, human enjoyment, and harvesting: Inspects, measures, and classifies logs based on quality: Operates machinery to cut down trees and move logs:
Answers
Answer:
1. Operates machines that cut through rocks underground so natural resources can be harvested: Mine-cutting and channeling operator
2. Studies and manages natural resources to protect the environment: Conservation Scientist
3. Manages forests for conservation, human enjoyment, and harvesting: Forster
4. Inspects, measures, and classifies logs based on quality: Log grader or scaler
5. Operates machinery to cut down trees and move logs: Logging equipment Operator
Explanation:
Conservation Scientist – studies and manages natural resources to protect the environment and support human uses of natural resources
Forester – manages forests for conservation, human enjoyment, and tree harvesting
Mine Cutting and Channeling Machine Operator – operates machinery in underground mines that bring natural resources up to the surface for human use
Logging Equipment Operator – operates logging machinery, such as tractors or bulldozers
Log Grader or Scaler – inspects, measures, and classifies logs based on their quality
The careers that match the given descriptions are; Conservation Scientist, Forester , Mine Cutting and Channeling Machine Operator ,and Logging Equipment Operator.
What are the careers that match the given descriptions?Conservation Scientist deals with the studies and manages natural resources to protect the environment and support human uses of natural resources
Forester deals with forests for conservation, human enjoyment, and tree harvesting
Mine Cutting and Channeling Machine Operator are the operates machinery in underground mines that bring natural resources up to the surface for human use
Logging Equipment Operator are the operates logging machinery, such as tractors or bulldozers
Log Grader or Scaler deals with the inspects, measures, and classifies logs based on their quality.
The careers that match the given descriptions are; Conservation Scientist, Forester , Mine Cutting and Channeling Machine Operator ,and Logging Equipment Operator.
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Technician A says automotive gasoline engines run on the 2 stroke principal. Technician B says Diesel engine hace less compression than a gasoline engine. Who is correct?
Answers
Answer:
both are incorect
Explanation:
2 stroke principal is a mix of gasoline and engine oil a normal gasoline engine does not run on 2 stroke fuel
technician B is also wrong Diesel engines generally generate much higher compersion than gasoline engines
Tech A says that one approved way to clean dust off brakes is with compressed air. Tech B says that some auto parts may contain asbestos. Who is correct
Answers
Tech B is correct it's a verified fact that some auto parts may contain asbestos.
Do auto parts contain asbestos?
Asbestos has been used in a wide range of automotive products, including brakes, clutches, hood liners, gaskets, heat shields, and many others.
Drum and disc brakes were traditionally made with 35% to 60% asbestos. It is still legal in the United States to sell asbestos-containing auto parts, and many brake and clutch parts contain up to 35% asbestos.
Contaminated parts have been found in vehicles of all types, including cars, trucks, motorcycles, buses, trains, and military vehicles. Elevators and other types of transportation machinery also used asbestos brakes.
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i. choose the best answer (3 points each) (c)1. which of the following is true regarding the n flag of the status register sreg? (a) n is set when operation has a carry out (b) n is set when the operation result is 0 (c) n is set when the operation result is negative (d) n is set when the operation causes overflow
Answers
In these lectures, the Status Register has been mentioned multiple times, first in relation to carry bits for instructions like adc and rol and subsequently with the branch instruction brne.
It's finally time to examine the specifics of this vital register. The status register is an 8-bit register located in the I/O memory region of the microcontroller. It has eight flags that are updated in accordance with the outcomes of the preceding instruction.
An additional piece of logic called the Sign Flag can be utilised to identify whether the outcome of a preceding operation was positive or negative. It is simply the Two's Complement Overflow and Negative flags combined in an exclusive OR. If one or the other is set, it will be set.
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Please solve this asap
Answers
a) The speed of the link's rotation is therefore: \(v_O_Q = 33.54 m/s k\)
b) The acceleration of the slotted link at point P is therefore:
\(a_O_Q = a_P + \alpha_OQ x r_PQ - \omega_OQ\)
How to solvea. To find the velocity of the peg with respect to the slotted link, we need to subtract the velocity of the slotted link at point P from the velocity of the peg at point P.
The velocity of the slotted link at point P can be found by using the velocity relationship for a slotted link:
v_OQ = v_P + omega_OQ x r_PQ
where:
\(v_O_Q\) is the velocity of point Q on the slotted link, \(\omega_OQ\) is the angular velocity of the slotted link,\(r_P_Q\) is the distance from point P to point Q on the slotted linkx represents the vector cross product.At the instant shown in the diagram, the slotted link is rotating counterclockwise with an angular velocity of:
\(\omega_OQ = d\theta/dt = (15 deg)/(1 s) = 15 rad/s\)
The distance from point P to point Q on the slotted link is:
\(r_P_Q = \sqrt{[(0.9 m)^2 + (0.6 m)^2]} = 1.08 m\)
The velocity of the slotted link at point P is therefore:
\(v_O_Q = v_P + omega_O_Q * r_P_Q\)
= 10 m/s + (15 rad/s) x (1.08 m) x k
= (10 + 16.2) m/s k
= 26.2 m/s k
The relative velocity of the peg with respect to the slotted link is then:
\(v_r_e_l = v_P - v_OQ\)
= 10 m/s - 26.2 m/s k
= -26.2 m/s k + 10 m/s b1
Step 2/3
To find the speed of the link's rotation, we can use the relationship between angular velocity and linear velocity for a rotating object:
\(v_O_Q = omega_O_Q x r_O_Q\)
where r_OQ is the distance from point O to point Q on the slotted link.
The distance from point O to point Q on the slotted link is:
\(r_O_Q = \sqrt{[(2 m)^2 + (1 m)^2]} = 2.236 m\)
The speed of the link's rotation is therefore:
\(v_O_Q = omega_O_Q x r_O_Q\)
= (15 rad/s) x (2.236 m) x k
= 33.54 m/s k
Step 3/3
b. To find the peg's acceleration relative to the slotted link, we need to subtract the acceleration of the slotted link at point P from the acceleration of the peg at point P. The acceleration of the slotted link at point P can be found using the acceleration relationship for a slotted link:
\(a_O_Q = a_P + \alpha_O_Q * r_P_Q - \omega_OQ^2 * r_PQ\)
where a_OQ is the acceleration of point Q on the slotted link, alpha_OQ is the angular acceleration of the slotted link, and all other terms are as previously defined.
At the instant shown in the diagram, the slotted link is rotating counterclockwise with an angular acceleration of:
\(\alpha_O_Q = d^2(\theta)/dt^2 = 0\)
Since the angular acceleration is zero, the third term in the acceleration equation for the slotted link is also zero.
The distance from point P to point Q on the slotted link is as previously calculated:
\(r_P_Q = \sqrt{ [(0.9 m)^2 + (0.6 m)^2]} = 1.08 m\)
The acceleration of the slotted link at point P is therefore:
\(a_O_Q = a_P + \alpha_O_Q x r_P_Q - \omega_O_Q^\)
Therefore,
a)The speed of the link's rotation is therefore:v_OQ = 33.54 m/s k
b)The acceleration of the slotted link at point P is therefore:
a_OQ = a_P + alpha_OQ x r_PQ - omega_OQ
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For RTK to work, what do we need besides two or more receivers collecting data from a sufficient number of satellites simultaneously?
Answers
Answer:
phase measurement and the information content
Explanation:
The full form of RTK is Real Time Kinematic. It is used for satellite navigation technique to increase the precision of the position data that is derived from the positioning systems based on satellites like the NavIC, GPS, Galileo, BeiDou and GLONASS. It takes help of the measurements of phase of signal's carrier wave and also the information content of these signals and it also relies on the single interpolated virtual station in order to provide the real time corrections and provide correct and accurate information.
If the owner decides to increase the living room dimensions by 20%, what is the new length and width of the living room floor?.
Answers
The original length and width of the living room floor were 10 ft x 12 ft.
The new length and width of the living room floor would be 12 ft x 14.4 ft.
If the owner decides to increase the living room dimensions by 20%, the new length and width of the living room floor would be 12 ft x 14.4 ft. This is because the 20% increase would be 2 ft for the length and 2.4 ft for the width. Therefore, the new length would be 10 ft + 2 ft = 12 ft, and the new width would be 12 ft + 2.4 ft = 14.4 ft. This would increase the area of the living room from 120 ft2 to 168 ft2, a 40% increase from the original area.
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genetic algorithms: do not work for most problems. develop solutions to particular problems using inheritance, crossover, and mutation. represent knowledge as groups of characteristics. are based on logic. seek to emulate a human expert's way of solving problems.
Answers
Genetic algorithms B: develop solutions to particular problems using inheritance, crossover, and mutation, as well as C: represent knowledge as groups of characteristics, also they E: seek to emulate a human expert's way of solving problems.
Genetic algorithms are a problem-solving approach inspired by the process of natural selection in evolution. They work by generating a population of potential solutions represented as chromosomes with characteristics. These characteristics are combined through techniques like inheritance, crossover, and mutation to create new generations of solutions. T
he algorithm aims to improve the solutions over time through fitness evaluation and selection. Genetic algorithms are designed to simulate the process of evolution and mimic the problem-solving capabilities of human experts rather than being based on strict logic. Therefore, the correct answer is that genetic algorithms develop solutions to particular problems using inheritance, crossover, and mutation (Option B, C nad E).
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Which of these processes uses a die and a press to form parts?
A) Stamping
B) Tailor-rolling
C) Hydroforming
D) Tailor-welding
Answers
The process of die forming that uses a die and a press to form parts from the given processes is called; C: Hydroforming
What are some of the steps in the die forming operations?
There are different types of die forming in sheet metal operations. Now, Hydroforming is a specialized type of die forming that uses a high pressure hydraulic fluid to press room temperature working material into a die.
Tailor Welding is a process of making welded blanks made from individual sheets of steel of different thickness, strength and even coating that are joined together by the use of laser welding.
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Portable electronic machines known as AEDs are used to analyze and treat life-threatening cardiac arrhythmias. They are an automated and external type of a device known as what?
Answers
Note that it is correct to state that Portable electronic machines known as AEDs are used to analyze and treat life-threatening cardiac arrhythmias. They are a type of defibrillator.
What is the explanation for the above response?Note that AED's are a kind of defibrillator that are created and designed to be used by laypeople or people of low medical skills instead of medical professionals.
This device can analyze the heart's rhythm and indicated if the patient will need to be shocked with electricity to restore balance to their hearts Rythm.
Thus, it is correct to state that AEDs are an automated and external type of a device known as defibrillator.
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mechanical properties of organic materials
Answers
The mechanical properties of organic solids most relevant to deformable devices include the elastic modulus (usually obtained as the tensile or Young's modulus),(109) elastic range and yield point,(110) toughness,(111) and strain to fracture(31
A circuit diagram for a lighting circuit is shown in Figure 6.
Figure 6
230 V AC
A
RL1
+
B T 12 V
04
4
Explain the function of the relay RL1 in the lighting circuit shown in Figure 6.
[2 marks)
Answers
Answer:
is there a picture of the figure?
Determine the real roots of f (x) = −0.6x2 + 2.4x + 5.5:(a) Graphically.(b) Using the quadratic formula.(c) Using three iterations of the bisection method to determinethe highest root. Employ initial guesses of xl = 5 and xu = 10.Compute the estimated error εa and the true error εt after eachiteration.
Answers
The three methods used to find the real roots of the function are,
graphically, the quadratic formula, and by iteration.
The correct vales are;
(a) Graphically, the roots obtained are; x ≈ -1.629, and 5.629
(b) Using the quadratic formula, the real roots of the given function are; x ≈ -1.62589, x ≈ 5.62859
(c) Using three iterations, we have; the bracket is \(x_l\) = 5.625, and \(x_u\) = 6.25
Reasons:
The given function is presented as follows;
f(x) = -0.6·x² + 2.4·x + 5.5
(a) The graph of the function is plotted on MS Excel, with increments in the
x-values of 0.01, to obtain the approximation of the x-intercepts which are
the real roots as follows;
\(\begin{array}{|c|cc|}x&&f(x)\\-1.63&&-0.00614\\-1.62&&0.03736\\5.62&&0.03736 \\5.63&&-0.00614\end{array}\right]\)
Checking for the approximation of x-value of the intercept, we have;
\(x = -1.63 + \dfrac{0 - (-0.00614)}{0.0376 - (-0.00614)} \times (-1.62-(-1.63)) \approx -1.629\)
Therefore, based on the similarity of the values at the intercepts, the x-
values (real roots of the function) at the x-intercepts (y = 0) are;
x ≈ -1.629, and 5.629
(b) The real roots of the quadratic equation are found using the quadratic
formula as follows;
The quadratic formula for finding the roots of the quadratic equation
presented in the form f(x) = a·x² + b·x + c, is given as follows;
\(x = \mathbf{ \dfrac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}}\)
Comparison to the given function, f(x) = -0.6·x² + 2.4·x + 5.5, gives;
a = -0.6, b = 2.4, and c = 5.5
Therefore, we get;
\(x = \dfrac{-2.4\pm \sqrt{2.4^{2}-4\times (-0.6)\times 5.5}}{2\times (-0.6)} = \dfrac{-2.4\pm\sqrt{18.96} }{-1.2} = \dfrac{12 \pm\sqrt{474} }{6}\)
Which gives
The real roots are; x ≈ -1.62859, and x ≈ 5.62859
(c) The initial guesses are;
\(x_l\) = 5, and \(x_u\) = 10
The first iteration is therefore;
\(x_r = \dfrac{5 + 10}{2} = 7.5\)
\(Estimated \ error , \ \epsilon _a = \left|\dfrac{10- 5}{10 + 5} \right | \times 100\% = 33.33\%\)
\(True \ error, \ \epsilon _t = \left|\dfrac{5.62859 - 7.5}{5.62859} \right | \times 100\% = 33.25\%\)
f(5) × f(7.5) = 2.5 × (-10.25) = -25.625
The bracket is therefore; \(x_l\) = 5, and \(x_u\) = 7.5
Second iteration:
\(x_r = \dfrac{5 + 7.5}{2} = 6.25\)
\(Estimated \ error , \ \epsilon _a = \left|\dfrac{7.5- 5}{7.5+ 5} \right | \times 100\% = 20\%\)
\(True \ error, \ \epsilon _t = \mathbf{\left|\dfrac{5.62859 - 6.25}{5.62859} \right | \times 100\%} \approx 11.04\%\)
f(5) × f(6.25) = 2.5 × (-2.9375) = -7.34375
The bracket is therefore; \(x_l\) = 5, and \(x_u\) = 6.25
Third iteration
\(x_r = \dfrac{5 + 6.25}{2} = 5.625\)
\(Estimated \ error , \ \epsilon _a = \left|\dfrac{5.625- 5}{5.625+ 5} \right | \times 100\% = 5.88\%\)
\(True \ error, \ \epsilon _t = \mathbf{\left|\dfrac{5.62859 - 5.625}{5.62859} \right | \times 100\%} \approx 6.378 \times 10^{-2}\%\)
f(5) × f(5.625) = 2.5 × (0.015625) = 0.015625
Therefore, the bracket is \(x_l\) = 5.625, and \(x_u\) = 6.25
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This is a classification of back pain based on duration. A) AcuteB) RecurrentC) ChronicD) All of the above
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Answer:
D) All of the above.
Match the following with the type of memory they are describing:
A. RAM
B. ROM
C. PROM
D. EPROM
E. EEPROM
F. FLASH
1. This memory can be programmed by the user instead of at the factory, and is read-only.
2. This memory is not only nonvolatile, but also can be erased by an electrical signal 1 byte at a time.
3. The contents of this memory are programmed one time when manufactured and are nonvolatile
4. This memory can be read from and written to, and is used by microcontrollers for variable data storage.
5. This memory is quite similar to the one described in 2. But allows for faster data access in blocks.
6. The contents of this memory will persist when the power is removed, but only UV can erase them.
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Explanation:
1. This memory can be programmed by the user instead of at the factory and is read-only. - A. PROM. (PROGRAMMABLE MEMORY)
2. This memory is not only nonvolatile but also can be erased by an electrical signal 1 byte at a time. - E. EEPROM (ELECTRICALLY ERASABLE PROGRAMMABLE MEMORY)
3. The contents of this memory are programmed one time when manufactured and are nonvolatile. A. RAM
4. This memory can be read from and written to and is used by microcontrollers for variable data storage. B. ROM (RANDOM ACCESS MEMORY)
5. This memory is quite similar to the one described in 2. But allows for faster data access in blocks. F. FLASH
6. The contents of this memory will persist when the power is removed, but only UV can erase them. D. EPROM (ERASABLE PROGRAMMABLE MEMORY)
Why is inches of water column" used to measure gas pressure instead of psig? A) gas pressures must be accurately set for correct operation B) All of these options C) gas marifold pressures are too smail for accurate measurenterit in pSi D) it is a more precise measurement
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The use of inches of water column as a unit of measurement for gas pressure is mainly due to the fact that gas pressures must be accurately set for correct operation.
Unlike psig (pounds per square inch gauge), which measures pressure relative to atmospheric pressure, inches of water column measures the pressure differential between two points, making it a more precise measurement for low-pressure systems.Furthermore, gas manifold pressures are often too small for accurate measurement in psig, which is typically used for higher-pressure systems. Inches of water column is a more suitable unit for measuring the small pressure differentials found in gas manifold systems.In summary, the use of inches of water column as a measurement for gas pressure is a more precise and suitable option for accurately setting gas pressures in low-pressure systems, where psig may not be a practical unit of measurement.The reason "inches of water column" is used to measure gas pressure instead of psig is because of the following factors:
A) Gas pressures must be accurately set for correct operation: Ensuring the correct pressure for gas systems is essential for safety and efficiency.
C) Gas manifold pressures are too small for accurate measurement in PSI: Inches of water column provides a more sensitive and precise measurement for low gas pressures typically found in these applications.
D) It is a more precise measurement: Using inches of water column allows for more accurate and consistent pressure readings, which is vital for proper functioning and safety in gas systems.
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A chain fall locks it’s elevated load is place using
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A chain fall locks it’s elevated load is place using an automatic brake.
A chain fall locks it’s elevated load is place using an automatic brake.
What is automatic brake?Automatic emergency braking (AEB) is a safety feature that may detect when a collision is likely to happen and automatically apply the brakes to either slow down the vehicle before impact or stop it altogether to prevent a collision.
Additionally, it found that injuries from these incidents decreased by 56%. Reverse automated braking systems have been associated with a 78% reduction in crashes when compared to vehicles that merely have a reverse camera.
In general, automatic emergency braking is intended to engage at highway speeds, provided the front collision warning sensors can identify the car in front of them. In towns, newer systems operate at slower rates.
Thus, an automatic brake.
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Wegener thought that ________. there was once one big continent that was later separated by the Atlantic Ocean there were once several continents that recombined to form the continents we have today there were once two big continents that were separated later by the Atlantic Ocean there was once one big continent that later broke into several pieces
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Wegener thought that there was once one big continent that later broke into several pieces. This idea is known as the theory of continental drift, which proposed that
the continents were once joined together in a supercontinent called Pangaea and over time, they gradually moved apart to form the continents we have today.Wegener thought that there was once one big continent that later broke into several pieces. He proposed the theory of continental drift, suggesting that the continents were once connected in a supercontinent called Pangaea. Over time, Pangaea split apart, and the fragments drifted to their current positions, forming the continents we have today. Wegener supported his hypothesis with evidence such as the matching shapes of the continents' coastlines, similar rock formations across different continents, and fossil distribution. Although his theory faced significant skepticism during his time, it laid the foundation for the modern understanding of plate tectonics and the movement of Earth's continents.
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Differentiate (i) € € between the following terms in satellite communications Azimuth and Elevation Angle (1 mark) L mark) Centripetal force and Centrifugal force (1 mark) Preamble and guard time (1 mark) Apogee and Perigee (1 mark) FDMA and FDM (1 mark) communication have solved the limitati
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Azimuth and Elevation AngleAzimuth refers to the angular position of a spacecraft or a satellite from the North in the horizontal plane.Elevation angle is the angle between the local horizontal plane and the satellite.
In other words, the altitude of the satellite over the horizon. Centripetal force and Centrifugal forceIn circular motion, centripetal force is the force acting towards the center of the circle that keeps an object moving on a circular path.
Centrifugal force is a fictitious force that seems to act outwards from the center of rotation. In reality, the object moves straight, but the frame of reference is rotating, giving rise to an apparent force.Preamble and guard timeThe preamble is used to establish and synchronize the data being sent to the receiver. On the other hand, the guard time is a fixed time interval that separates consecutive symbols or frames to avoid overlap.
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name one simple machine in our home and explain how it can be made to be more efficient.
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Levers are a type of basic machine that are useful for altering the span of the shaft or the height of the fulcrum.
What is an example of a machine?A machine seems to be a physical system that use power to exert forces, regulate movement, and carry out an activity. The phrase is frequently used to refer to both naturally occurring biological macromolecules and manmade devices that use engines or motors.
How come it's called a machine?The Greek word "makhana," which means "device," is where the term "machine" originates. In 1540, the name was first used to designate any form of construction in English. About 1670, its contemporary meaning as a term for a machine with several moving components started to take shape.
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