Allison and her classmates planted bean seeds at the same time as Yuki and her classmates in Tokyo did. Allison is video-chatting with Yuki about their class seedlings. Who should expect to have the taller plant at the end of the school year?

PLZ HELP NOW

Allison's Plant: 2.5 inches in 5 days


Yuki's Plant: 5.5 centimeters in 4 days



(HINT: How can we change the rates to compare the growth rate of the seedlings)


Your answer:

The equation that best describes the relation is y = -x+1 ( optionD)

A linear equation is an algebraic equation of the form y=mx+b. involving only a constant and a first-order (linear) term, where m is the slope and b is the y-intercept.

Taking x(0,1) and y ( 1,0)

therefore the slope of the line

= 0-1/1-0

= -1/1 = -1

the equation a line is given as

y-y1 = m(x-x1)

= y-1 = -1( x - 0)

= y-1 = -x

y = -x +1

therefore the equation that describe relation is y = 1-x or y = -x+1

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Amplitude and period of y = 1 + cos 0 are amplitude: = 1 and period:  2π respectively.

The cosine function cosx is one of the basic functions encountered in trigonometry

y = 1 + cos 0

Rewrite the expression as

−cos(x)+1.

Use the form

acos(bx−c)+d

To find the variables used to find the amplitude, period, phase shift, and vertical shift.

a =-1

b =1 = d

c=0

Find the amplitude

Let

Amplitude: = 1

Phase Shift:  = 0

List the properties of the trigonometric function.

Amplitude: 1

Period:  2π

Phase Shift: None

Vertical Shift: 1

So the amplitude and period of the equation y = 1 + cos 0 are 1 and 2 correspondingly.

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The amplitude and period of the equation y = 1 + cos 0 are 1 and 2 correspondingly.

The cosine formula One of the fundamental trigonometry functions is cosx.

y = 1 + cos 0

Change the wording to

−cos(x)+1.

Apply the form

acos(bx−c)+d

to identify the parameters used to calculate the vertical shift, phase shift, amplitude, and period.

a =-1

b =1 = d

c=0

Measure the amplitude.

Let

Amplification: 1

0 for phase shift

Describe the trigonometric function's characteristics.

1 amplitude

Duration: 2

No phase shift

Shift Vertically: 1

As a result, y = 1 + cos 0 has an amplitude and period of 1 and 2, respectively.

Answer: 0.4337

Step-by-step explanation:

Let X represents the test results for a class that follow a normal distribution .

Given: Mean \(\mu=78\), Standard deviation  \(\sigma=36\)

Then, the probability that it is greater than 84 will be

\(P(X>84)=P(\dfrac{X-\mu}{\sigma}>\dfrac{84-78}{36})\\\\=P(Z>0.167)\ \ \ [Z=\dfrac{X-\mu}{\sigma}]\\\\=1-P(Z<0.167)\\\\=1-0.5663=0.4337\ [\text{By p-value table}]\)

Hence, the required probability = 0.4337

Answer:

A. The probability that a randomly selected sports car from this manufacturer will be white with gray upholstery is P=0.12.

B. Assuming that we know the car has tan upholstery, the probability that the car is either silver or white is P=0.50.

Step-by-step explanation:

We first start by stating that the events "exterior color" and "leather color" are independent, so the probability of the outcomes of each event is not affected by the outcomes of the other event.

A. The probability of having a car that is white (W) with gray upholstery (G) is equal to the probability of having a car that is white multiplied by the probability of having a car with gray leather upholstery. Mathematically, this is:

\(P(\text{W\&G})=P(W)\cdot P(G)=0.3\cdot 0.4=0.12\)

B. As the events are independent, the probability of having a silver or white car, given that the car has tan upholstery, is the same as the probabiltiy of having a silver or white car:

\(P(S\,or\,W | T)=P(S\,or\,W)=P(S)+P(W)=0.20+0.30=0.50\)

a. Expenses: Books and supplies, Housing and food, Tuition and fees, Transportation and Personal expenses. Funding: Savings,

Scholarships, Grants and Student loans.

b. Total estimated expenses are $29,400

(a) Below is an estimate of all her expenses and sources of funding for her 2-year college education.

Expense:

Books and supplies: $1700

Housing and food: $14,020

Tuition and fees: $11,660

Transportation: $2040

Personal expenses: $2980

Funding:

Savings: $7800

Scholarships: $10,240

Grants: $11,600

Student loans: $6200

(b) What is the total of her estimated expenses?

To find the total estimated expenses, we need to add up all the expenses mentioned:

$1700 + $14,020 + $11,660 + $2040 + $2980 = $29,400

Therefore, the total estimated expenses for Nicole's 2-year college education is $29,400.

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Answer: x>6

Step-by-step explanation:

The density of an irregularly shaped object with a mass of 6.05 g is 5.50 g/mL.

We have to determine the density of an irregularly shaped object with a mass of 6.05 g.

The volume of the strangely formed object is the volume it displaces.

The volume displaced is the difference between the starting volume of water and the final volume of water when the object is submerged.

The value can be taken as 3.15 mL because the final volume of water in the diagram is between 3.10 and 3.20 mL.

Volume of object = volume displaced

Volume of object = final volume - initial volume

Volume of object = 3.15 mL - 2.05 mL

Volume of object = 1.10 mL

The following formula can then be used to calculate the object's density:

Density = mass / volume

Density = (6.05 g) / (1.10 mL)

Density = 5.50 g/mL

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The complete question is:

A student needs to determine the density of an irregularly shaped object with a mass of 6.05 g.

Part A: The student fills a 10 mL graduated cylinder with deionized water. Use the image below to determine the volume of water in the graduated cylinder.

Report the answer to the correct number of significant figures. Initial volume of water = 2.05 mL

Answer:

16

Step-by-step explanation:

Step 1: Write down the function \(f(x)=7x^2+2x+3.\)

Step 2: Write down the limit definition of the derivative:
\(f'(x)= lim_{h0} \frac{f(x+h)=f(x)}{h} .\)

Step 3: Substitute the function \(f(x)\) into the limit definition:
\(f'(x)=lim_{h0} \frac{(7(x+h)^2+2(x+h)+3)-(7x^2+2x+3)}{h}.\)

Step 4: Simplify the expression inside the limit:
\(f'(x)=lim_{h0}\frac{7x^2+14xh+7h^2+2x+2h+3-7x^2-2x-3}{h} .\)

Step 5: Combine like terms:
\(f'(x)=lim_{h0} \frac{14xh+7h^2+2h}{h} .\)

Step 6: Factor out an \(h\) from the numerator:
\(f'(x)=lim_{h0} \frac{h(14x+7h+2h}{h} .\)

Step 7: Cancel out the \(h\) in the numerator and denominator:
\(f'(x)=lim_{h0}(14x+7h+2).\)

Step 8: Evaluate the limit as \(h\) approaches 0:
\(f'(x)=14x+2.\)

Step 9: Substitute \(x=1\) into the derivative:
\(f'(1)=14(1)+2=14+2=16.\)

The Slope of the tangent line to the curve \(f(x)=7x^2+2x+3\) at \(x=1\) would be \(16.\)

Answer:

C and D

Step-by-step explanation:

Let's solve for x to see what range the answer has to be in:

-2x - 3 ≤ -1

-2x ≤ 2

x ≥ -1

So the value of x must be larger than or equal to -1. So the answers would be 1 and 0

The simple ratio of 13 km to 3 km as required to be determined in the task content is; 13 : 3.

It follows from the task content that the simple ratio of 13 km to 3 km is to be determined as required.

On this note, we have that;

13 km to 3 km.

which results to;

13 : 3

However, since 13 and 3 have no common factors except 1; it follows that the result as a simple ratio is; 13 : 3.

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Answer:

The first box : -4  the second one : 6

Step-by-step explanation:

subtract 7 from 3 for the first box, then add 10 to -4 for the second one.

Answer:

350

Step-by-step explanation:

Let,

 x = bench

 x + 35 = garden table

EQUATION:

   (x) + (x + 35) = 735

   2x = 735 - 35

   2x = 700

   x = 350

SUBSTITUTE:

  bench costs 350 and garden table costs 385

Hello!

Based on the info we have we can form 2 equations :

(Keep in mind x is the cost of the garden table and y is that of the bench)

Now substitute x in the first equation.

⇒ y + 35 + y = 735

⇒ 2y = 700

⇒ y = 350

∴ The cost of the bench is \(\fbox {350}\)

Slope = -7/2

The slope-Intercept form of the equation of a line is given as:

y = mx + c

where m represents the slope and

c represents the intercept

The given equation is:

Comparing the equation above to y = mx + c

m = 2/7

The slope of the line perpendicular to y = mx + c is:

Slope = -1/m

Since m = 2/7

Answer:

1.

Step-by-step explanation:

sec x cos x

= 1/cos x  * cos x

= cos x / cos x

= 1.

Answer:

54

Step-by-step explanation:

2×27=54 hope this helps

Answer:

60

Step-by-step explanation:

I think that is the best choice sorry if i got it wrong.

Answer:

60 degrees

Step-by-step explanation:

Angle 1 is already 55 degrees, if you move the y line 5 degrees clockwise then it equals 60 degrees. Angle 1 and 3 are vertical angles so they are equal, if angle 1 is 60 degrees after we move the line then angle 3 is also 60 degrees

Answer: 1 = 90 2=58 3=90 6=58 7=8

Step-by-step explanation:

I don’t know what 4 and 5 are

According to the properties of the standard normal distribution, approximately 99.7% of the values lie within three standard deviations of the mean. Therefore, the answer is 99.7%.

To determine the percentage of videos on the streaming site that are between 264 and 489 seconds, we need to calculate the area under the normal curve within that range. Since the distribution is approximately normal with a mean of 264 seconds and a standard deviation of 75 seconds, we can use the properties of the standard normal distribution to find the desired percentage.

First, we need to convert the values 264 and 489 to z-scores, which represent the number of standard deviations a particular value is away from the mean. The z-score formula is given by:

z = (x - μ) / σ

where x is the value, μ is the mean, and σ is the standard deviation. Plugging in the values, we get:

z1 = (264 - 264) / 75 = 0

z2 = (489 - 264) / 75 = 3

Next, we can use a standard normal distribution table or a calculator to find the area under the curve between z = 0 and z = 3. The area represents the percentage of videos falling within that range. The answer is 99.7% .

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Answer:

200

Step-by-step explanation:

Given that :

16% of coins are quarters from 1990

Number of quarters from 1990 = 32

Since 16% = 32 quarters

The number of the total coins can be obtained thus :

Let the total number of coins = x

16% = 32

100% = x

Cross multiply :

0.16x = 32 * 1

0.16x = 32

x = 32 / 0.16

x = 200

Hence, total number of coins in the collection = 200

Answer:

calculator gave me 6.5732

Step-by-step explanation:

Answer:

Exact Form:

1/22

Decimal Form:

0.045

Step-by-step explanation:

The correct expression is  \($(150 \cdot 1.15)^7$\) (Choice A).

The problem states that the painting's value increases by a factor of 1.15 each year. This means that the value at the end of each year is 1.15 times the value at the beginning of the year. Therefore, after one year, the value of the painting is\($150 \cdot 1.15 = 172.50$\).

To find the value after 7 years, we need to multiply the value of the painting each year by 1.15 a total of 7 times. This can be represented mathematically as \($(150 \cdot 1.15)^7$\). This expression is equal to the starting value of the painting, 150, multiplied by 1.15$ raised to the 7th power, which represents the 7 years of appreciation.

If we were to choose expression B, it would give an incorrect result because it uses a value of 1.1 instead of 1.15 to represent the yearly increase in value.

Expressions C and D are also incorrect because they are not taking into account the compounding effect of the yearly increase. Expression C adds the initial value and the total years together, and expression D adds the initial value to the yearly increase multiplied by 7, neither of which correctly reflects the exponential growth of the painting's value.

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The expression that will represent the volume of the identical rectangular base pyramid is: 2[One-third (5) (0.25) (2)] cubic units.

To calculate for the volume of a rectangular base pyramid, we use the formula:

volume = 1/3 × area of base rectangle × height

volume of one identical pyramid = (1/3 × 5 × 0.5 × 2)cubic units

volume of the two identical pyramid = 2(1/3 × 5 × 0.5 × 2)cubic units.

Therefore, the expression that will represent the volume of the identical rectangular base pyramid is: 2[One-third (5) (0.25) (2)] cubic units.

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Answer:

-90=\(x\)(\(x\)-18)

-90=\(x^{2}\)-18\(x\)

\(0=x^{2}-18x+90\)

\(x=9+3i or 9-3i\)

Step-by-step explanation:

you need to use quadratic formula and you will find square root a negative ( -9 ), which is an imaginary no.

square root (-9) = 3i

Therefore, the package with 40 hooks is the better buy in terms of cost efficiency.

To determine which package is the better buy, we need to compare the cost per hook for each package.

For the package of 25 hooks costing $9.95, we divide the total cost by the number of hooks:

Cost per hook = $9.95 / 25 = $0.398

Rounding to the nearest cent, the cost per hook is $0.40.

For the package of 40 hooks costing $13.99, we divide the total cost by the number of hooks:

Cost per hook = $13.99 / 40 = $0.3498

Rounding to the nearest cent, the cost per hook is $0.35.

Comparing the two costs per hook, we can see that the package with 40 hooks for $13.99 offers a better deal, as the cost per hook is lower at $0.35.

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- 8 + 2(- 5)

- 8 - 10

= - 18

The correct answer is the second option

The polynomial 11x⁵  + x⁴ - 4x³ - 5x² + 8 denotes the expression P - Q. The correct option is option A.

What is an expression?

A mathematical expression is a phrase that contains a minimum of two numbers or variables and at least one mathematical operation. It is possible to multiply, divide, add, or subtract in math. An expression has the following structure: Expression is (Math Operator, Number/Variable, Number/Variable)

Given polynomials are:

P = 11x⁵  + 9x⁴ - 4x³ - 7x² + 5

Q = (2x² + 1) (4x² - 3)

Simplify the polynomial Q = (2x² + 1) (4x² - 3):

Q = (2x² + 1) (4x² - 3)

Q = 2x²(4x² - 3) + 1(4x² - 3)

Q = 8x⁴ - 6x² + 4x² - 3

Add like terms:

Q = 8x⁴ - 2x² - 3

Now calculate P + Q

P + Q = 11x⁵  + 9x⁴ - 4x³ - 7x² + 5 + 8x⁴ - 2x² - 3

Combine like terms:

P + Q = 11x⁵ + (9x⁴ + 8x⁴) - 4x³  + (- 7x² - 2x²) + 5 - 3

P + Q = 11x⁵ + 17x⁴ - 4x³ - 9x² + 2

Now calculate P - Q

P - Q = 11x⁵  + 9x⁴ - 4x³ - 7x² + 5 - (8x⁴ - 2x² - 3)

P - Q = 11x⁵  + 9x⁴ - 4x³ - 7x² + 5 - 8x⁴ + 2x² + 3

P - Q = 11x⁵  + (9x⁴ - 8x⁴) - 4x³ + (-7x² + 2x² )+ (5 + 3)

P - Q = 11x⁵  + x⁴ - 4x³ - 5x² + 8

Now calculate Q - P

Q - P =  8x⁴ - 2x² - 3 - (11x⁵  + 9x⁴ - 4x³ - 7x² + 5)

Q - P =  8x⁴ - 2x² - 3 - 11x⁵  - 9x⁴ + 4x³ + 7x² - 5

Combine like terms:

Q - P = - 11x⁵ + (8x⁴ - 9x⁴) + 4x³ + (- 2x² + 7x²) - 3 - 5

Q - P = - 11x⁵- x⁴ + 4x³ + 5x² - 8

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The general solution of the partial differential equation is:

U(x, t) = Σ [Aₙ*sin((nπ/3)x)]*e^(-(nπ/3)²t)

The partial differential equation (PDE) is given as:

Uxx = (1/2)Ut with the boundary and initial conditions as 0< X <3 with U(0,t) = U(3, t)=0, U(0, t) = 5sin(4πx)

Assume that the solution can be written as a product of two functions:

U(x, t) = X(x)T(t)

Substituting this into the PDE, we have:

X''(x)T(t) = (1/2)X(x)T'(t)

Dividing both sides by X(x)T(t), we get:

(X''(x))/X(x) = (1/2)(T'(t))/T(t)

Since the left side only depends on x and the right side only depends on t, both sides must be equal to a constant, denoted as -λ²:

(X''(x))/X(x) = -λ²

(1/2)(T'(t))/T(t) = -λ²

Simplifying the second equation, we have:

T'(t)/T(t) = -2λ²

Solving the second equation, we find:

T(t) = Ce^(-2λ²t)

Applying the boundary condition U(0, t) = 0, we have:

U(0, t) = X(0)T(t) = 0

Since T(t) ≠ 0, we must have X(0) = 0.

Applying the boundary condition U(3, t) = 0, we have:

U(3, t) = X(3)T(t) = 0

Again, since T(t) ≠ 0, we must have X(3) = 0.

Therefore, we can conclude that X(x) must satisfy the following boundary value problem:

X''(x)/X(x) = -λ²

X(0) = 0

X(3) = 0

The general solution to this ordinary differential equation is given by:

X(x) = Asin(λx) + Bcos(λx)

Applying the initial condition U(x, 0) = 5*sin(4πx), we have:

U(x, 0) = X(x)T(0) = X(x)C

Comparing this with the given initial condition, we can conclude that T(0) = C = 5.

Therefore, the complete solution for U(x, t) is given by:

U(x, t) = Σ [Aₙsin(λₙx) + Bₙcos(λₙx)]*e^(-2(λₙ)²t)

where:

Σ represents the summation over all values of n

λₙ are the eigenvalues obtained from solving the boundary value problem for X(x).

To find the eigenvalues λₙ, we substitute the boundary conditions into the general solution for X(x):

X(0) = 0: Aₙsin(0) + Bₙcos(0) = 0

X(3) = 0: Aₙsin(3λₙ) + Bₙcos(3λₙ) = 0

From the first equation, we have Bₙ = 0.

From the second equation, we have Aₙ*sin(3λₙ) = 0. Since Aₙ ≠ 0, we must have sin(3λₙ) = 0.

This implies that 3λₙ = nπ, where n is an integer.

Therefore, λₙ = (nπ)/3.

Substituting the eigenvalues into the general solution, we have:

U(x, t) = Σ [Aₙ*sin((nπ/3)x)]*e^(-(nπ/3)²t)

where Aₙ are the coefficients that can be determined from the initial condition.

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Answer:

I have solved it and attached in the explanation.

Step-by-step explanation: