All drugs must interact specifically with a biological macromolecule to produce biological action؟
T /F​

Tribasic Potassium Phosphate + Calcium Nitrate = Tuite + Potassium Nitrate

2 moles of aqueous Tribasic Potassium Phosphate react with 3 moles of aqueous Calcium Nitrate to form 1 mole of solid Tuite and 6 moles of aqueous Potassium Nitrate

Reaction Type

Double Displacement (Metathesis)

Net Ionic Equation

2K3PO4 + 3Ca(NO3)2 = Ca3(PO4)2 + 6KNO3 might be an ionic equation. Calculate the net ionic equation for 2K3PO4(aq) + 3Ca(NO3)2(aq) = Ca3(PO4)2(s) + 6KNO3(aq).

Redox (Oxidation-Reduction) Reaction

K3PO4 + Ca(NO3)2 = Ca3(PO4)2 + KNO3 might be a redox reaction.

Reactants

Tribasic Potassium Phosphate - K3PO4

E340Iii E340(Iii) Potassium Phosphate Tripotassium Phosphate K3PO4 Molar Mass K3PO4 Oxidation Number

Calcium Nitrate - Ca(NO3)2

Saltpeter Lime Nitrate Lime Saltpeter Norge Saltpeter Norway Saltpeter Calcium Saltpeter Norwegian Saltpeter Anhydrous Calcium Nitrate Ca(NO3)2 Molar Mass Ca(NO3)2 Oxidation Number

Answer:

According to Coulomb’s law, the electric force between two identical negative charges is inversely proportional to the square of the distance between them. This means that as the distance between the two charges decreases, the electric force between them will increase. Since the charges are both negative, they will repel each other, so as they move closer together, the repulsive force between them will become stronger.

Explanation:

Answer:

0.617

Explanation:

The experimental value is the average of all the values recorded:

(2.65 + 2.73 + 2.77)/3 = 2.72

Then use the equation:

(2.72 - 2.7)/ 2.7 x 100 = 0.617

Answer:

A and D then I guess

Explanation:

sorry hope this helps!

The solution of 0.150 m ZnCl₂ can be prepared by the addition of 8.38 g of solid ZnCl₂ in 491.62 g of solvent.

Molality can be measured by the number of moles of solute in a solution corresponding to 1 kg of solvent. The unit for molality in chemistry is mol/kg. A solution of concentration 1 mol.kg⁻¹ is also referred to as 1 molal.

The mathematical equation of the calculation of molality is given by:

Molality = Moles of solute/ Volume of solvent (in Kg)

Given, the mass of solution = 500 g

The molality of the zinc chloride solution = 0.125 m

The molar mass of the ZnCl₂ = 136.286 g/mol

Consider that the mass of solid ZnCl₂ is 'x'.

The mass of the solvent = 500 - x

\(Molality=\frac{x/136.286}{500-x}\times 1000\)

0.125 × 136.286× (500- x) = 1000x

1017.035 x= 8517.87

x = 8.38 g

The solvent = 500 - 8.38 = 491.62 g.

Therefore, the mass of the solute solid ZnCl₂ is 8.38 g should be added in 491.62 g of solvent to prepare 0.125 molal.

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Answer:

Condensation

Explanation:

Zoe is quite keen to have noticed what we call condensation. Air contains many components, one of those being water vapor. Like how sugar is soluble in water, water can be said to be "soluble" in air. Water will evaporate into the air to a certain extent. The higher the temperature of the air, the more water the air can hold. If the air has more water that it can hold (potentially because of a temperature decrease), the extra water will come out of the air. Zoe's water bottle was cold, and because the air around Zoe's bottle had cooled down, the air can not hold as much water as it could when it was warm, so the air deposited the extra water in the form of liquid water onto the bottle, giving the illusion that her bottle was sweating.

Answer:

0. 070g

Mass of 1 Si atom =28.08/6.022*1023

So mass 1.5 *1021*4.6629*10-23

Answer:

\(\boxed {\boxed {\sf 0.070 \ g \ Si}}\)

Explanation:

We are given a value of atoms and asked to find the mass. We can complete this in 2 steps.

1. Convert Atoms to Moles

First, we have to convert atoms to moles. We use Avogadro's Number or 6.022 × 10²³. This is the number of particles (atoms, molecules, formula units, etc.) in 1 mole of a substance.

In this case, the particles are silicon atoms. We can set up a proportion.

\(\frac { 6.022 \times 10^{23} \ atom \ Si }{1 \ mol \ Si}\)

Multiply by the value of atoms given.

\(1.5 \times 10^{21} \ atom \ Si *\frac { 6.022 \times 10^{23} \ atom \ Si }{1 \ mol \ Si}\)

Flip the ratio. This allows the atoms of silicon units to cancel and leave the moles of silicon.

\(1.5 \times 10^{21} \ atom \ Si *\frac {1 \ mol \ Si } {6.022 \times 10^{23} \ atom \ Si}\)

\(1.5 \times 10^{21}*\frac {1 \ mol \ Si } {6.022 \times 10^{23} }\)

\(\frac {1.5 \times 10^{21} \ mol \ Si } {6.022 \times 10^{23} }\)

\(0.002490866822 \ mol \ Si\)

2. Convert Moles to Grams

Next, we convert the moles to grams. We use the molar mass, which is found on the Periodic Table. This value is the number of grams in 1 mole of a substance. Look for silicon (Si).

Use this value as a ratio.

\(\frac {28.085 \ g \ Si}{1 \ mol \ Si}\)

Multiply by the number of moles we calculated.

\(0.002490866822 \ mol \ Si *\frac {28.085 \ g \ Si}{1 \ mol \ Si}\)

The moles of silicon units cancel, so we are left with grams.

\(0.002490866822 *\frac {28.085 \ g \ Si}{1}\)

\(0.002490866822 *{28.085 \ g \ Si}\)

\(0.06995599469 \ g \ Si\)

3. Round

Finally we must round our answer. The original value has 2 significant figures, so our answer must have the same. For the number we calculated, that is the thousandth place.

\(0.069\underline95599469 \ g Si\)

The 9 tells us to round the other 9 to a 0, then the 6 to a 7.

\(0.070 \ g \ Si\)

The mass of 1.5 × 10²¹ silicon atoms is 0.070 grams of silicon.

For A it seems that the molecules are freely moving around and vibrating as well- indicates liquid. At B, the molecules are rigid with very less energy - indicating solid.

At equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

1: Write the balanced chemical equation:

\(C_O\)(g) + \(Cl_2\)(g) ⟶ \(C_OCl_2\)(g)

2: Set up an ICE table to track the changes in moles of the substances involved in the reaction.

Initial:

\(C_O\)(g) = 0.3500 mol

\(Cl_2\)(g) = 0.05500 mol

\(C_OCl_2\)(g) = 0 mol

Change:

\(C_O\)(g) = -x

\(Cl_2\)(g) = -x

\(C_OCl_2\)(g) = +x

Equilibrium:

\(C_O\)(g) = 0.3500 - x mol

\(Cl_2\)(g) = 0.05500 - x mol

\(C_OCl_2\)(g) = x mol

3: Write the expression for the equilibrium constant (Kc) using the concentrations of the species involved:

Kc = [\(C_OCl_2\)(g)] / [\(C_O\)(g)] * [\(Cl_2\)(g)]

4: Substitute the given equilibrium constant (Kc) value into the expression:

1.2 x \(10^3\) = x / (0.3500 - x) * (0.05500 - x)

5: Solve the equation for x. Rearrange the equation to obtain a quadratic equation:

1.2 x \(10^3\) * (0.3500 - x) * (0.05500 - x) = x

6: Simplify and solve the quadratic equation. This can be done by multiplying out the terms, rearranging the equation to standard quadratic form, and then using the quadratic formula.

7: After solving the quadratic equation, you will find two possible values for x. However, since the number of moles cannot be negative, we discard the negative solution.

8: The positive value of x represents the number of moles of \(Cl_2\)(g) at equilibrium. Substitute the value of x into the expression for \(Cl_2\)(g):

\(Cl_2\)(g) = 0.05500 - x

9: Calculate the value of \(Cl_2\)(g) at equilibrium:

\(Cl_2\)(g) = 0.05500 - x

\(Cl_2\)(g) = 0.05500 - (positive value of x)

10: Calculate the final value of \(Cl_2\) (g) at equilibrium to get the answer.

Therefore, at equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

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we can determine the enthalpy of reaction for the hypothetical reaction A2X4(l) + X2(g) → 2AX3(g) using the following steps:

Hess's Law of Constant Heat Summation  states that regardless of the multiple stages or steps of a reaction, the total enthalpy change for the reaction is the sum of all changes.

The law is  Hess's Law  of Constant Heat Summation  is described as a manifestation that enthalpy is a state function.

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Material from meteorites are not the elements used to make models of interstellar medium. The correct option is A.

The matter and radiation that prevail in the space between star systems in a galaxy are referred to as the interstellar medium in astronomy. This matter consists of gas including ionic, atomic, and molecular, dust, and cosmic rays.

Meteorite material is not used to create models of the interstellar medium.

Thus, the correct option is A.

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Answer:

an atom is the smallest particle of matter

a compound is a substance that has two or more atoms and element is the opposite of compound.

molecule is........,...............hope this helps

The correct answer is  a sphybridisation in z coordinate.So to form sphybridisation we need a s orbital and a p orbital  .

In genomics, hybridization is the process by which two complementary single-stranded DNA or RNA molecules bond together to form a double-stranded molecule.The bonding is determined by the correct base pairing between the two single-stranded molecules. When one s and one p orbital in the same main shell of an atom combine to form two new equivalent orbitals, this is referred to as sphybridization.

The newly formed orbitals are known as sphybridized orbitals. It forms linear molecules with a 180° angle. Atomic orbitals include both s and p orbitals. These orbitals represent the most likely region in which we can find an electron of that atom. The primary distinction between s and p orbitals is that s orbitals are spherical in shape, whereas p orbitals are dumvell-shaped.So to form  sp hybridisation we need a s orbital and a  p orbital .

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The balanced form of the chemical equations given in the image are as follows:

A balanced chemical equation is an equation that obeys the law of conservation of mass i.e. the number of atoms of each element on both sides of the equation are the same.

A chemical equation is balanced with the aid of coefficients, which are numbers placed in front of each compound or element as a multiplying factor.

According to this question, some chemical equations were given in the image attached. The balanced form of these equations are in the main answer part.

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Answer:

Explanations:

Taking into account the reaction stoichiometry, 2.778 moles of oxygen are needed to react with 100 grams of aluminum.

In first place, the balanced reaction is:

4 Al + 3 O₂  → 2 Al₂O₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The following rule of three can be applied: If by reaction stoichiometry 108 grams of Al react with 3 moles of O₂, 100 grams of Al react with how many moles of O₂?

moles of O₂= (100 grams of Al× 3 moles of O₂)÷ 108 grams of Al

moles of O₂= 2.778 moles

Finally, 2.778 moles of oxygen are needed.

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Answer:

See explanation

Explanation:

Vinegar and oil have different densities, as such we expect the two substances to separate when mixed. However, oil constitutes the organic phase(water insoluble) while vinegar constituents the aqueous phase since it is water soluble.  Therefore, the two substances separate into layers when left to stand for a while.

The structure of lecithin makes it a good emulsifier. Hence, it can be able to cause oil and vinegar to mix, constituting a single phase when lecithin is stirred in.

Vinegar molecules and oil molecules are not attracted to one another. Lecithin is attracted to both vinegar molecules and oil molecules. Due to this attraction, lecithin can cause vinegar and oil to mix evenly.

Due to their immiscibility, oil and vinegar separate into layers when they are mixed together. Oil is non-polar, but vinegar (which is acetic acid that has been diluted) is polar. Because of their different polarity, these compounds are said to be "immiscible," which means they do not mix well or create a stable solution when combined. When you stir oil and vinegar together, the agitation causes them to mix to some extent at first, but the various interactions between their molecules cause them to quickly separate into distinct layers.

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Answer:

india you got lot of rubbish scholar

Answer:

Canada is a country in North America. Its ten provinces and three territories extend from the Atlantic to the Pacific and northward into the Arctic Ocean, covering 9.98 million square kilometres (3.85 million square miles), making it the world's second-largest country by total area. Its southern and western border with the United States, stretching 8,891 kilometres (5,525 mi), is the world's longest bi-national land border. Canada's capital is Ottawa, and its three largest metropolitan areas are Toronto, Montreal, and Vancouver.

Explanation:

Answer:

d 1 1/2 oz.. of 80-proof liquor

1 1/2 oz. of 80-proof liquor is not equivalent to one drink. Hence, option D is correct.

Oz is an abbreviation for ounce. An ounce is equal to 1/16 pound (437 1/2 grains) and equal to 480 grains, or 1/12 pound.

1 1/2 oz. of 80-proof liquor is not equivalent to one drink.

Hence, option D is correct.

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Explanation:

Adding logs of same base is equivalent to multiplying the arguments. You get:

\( log_{3}(35x) = 4\)

Use the definition of the log to turn this into an exponential function:

\( {3}^{4} = 35x\)

\(81 = 35x\)

\(x = \frac{81}{35} \)

Answer: 1.3 L

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

To calculate the volume for given molarity, we use the equation:

\(\text{Molarity of the solution}=\frac{\text{moles of solute}}{\text{Volume of solution in L}}\)

\(6.8M=\frac{8.6mol}{\text{Volume of solution in L}}\)

\(\text{Volume of solution in L}=1.3\)

Thus the volume in Liters is 1.3

C13 and H1 different signals (c and h), and splitting and integration and approximate chemical shift.

An approximate chemical shift range for different nuclei (carbon, hydrogen) based on common observations in NMR spectroscopy.

Carbon (13C):

Chemical shift range: around 0-200 ppm

Hydrogen (1H):

Chemical shift range: around 0-12 ppm

Nuclear magnetic resonance (NMR) spectroscopy is a powerful analytical tool that is used to study the structure and composition of molecules. It is based on the concept that certain nuclei in a molecule, such as hydrogen, can absorb and emit electromagnetic radiation in the radio frequency range when exposed to a magnetic field. By analyzing the patterns of absorption and emission, NMR spectroscopy can provide information about the chemical environment and connectivity of atoms within a molecule.

This information can be used to determine the molecular structure, identify the different types of atoms within a molecule, and quantify the amounts of different chemical species present in a sample. NMR spectroscopy has a wide range of applications in fields such as biochemistry, medicinal chemistry, materials science, and environmental chemistry, and is essential for the study of many complex chemical systems.

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Answer:

Below

Explanation:

2 K2  CuNa2 ===>  2 K2 Na  + Cu      <====K, Na and Cu are the same # on each side (though I have never seen ' K2' except in mountaineering) and drug lore)

it is push i think to move the car

Answer:

Either A. Push or B.Pull because the truck is either pushing or pulling the car to move it. So it depends on if it's pushing or pulling the car.

Explanation:

Approximately 194.0 grams of glucose (C6H12O6) would be required to prepare a 5000 mL solution with a concentration of 0.215 M.

To determine the mass of glucose (C6H12O6) required to prepare a 0.215 M solution in 5000 mL, we need to use the formula:

Molarity (M) = moles of solute / volume of solution (in liters)

First, let's convert the volume of the solution from milliliters (mL) to liters (L):

5000 mL = 5000/1000 = 5 L

Now, we can rearrange the formula to solve for moles of solute:

moles of solute = Molarity (M) x volume of solution (L)

moles of solute = 0.215 M x 5 Lmoles of solute = 1.075 mol

Since glucose (C6H12O6) has a molar mass of approximately 180.16 g/mol, we can calculate the mass of glucose using the equation:

mass of solute = moles of solute x molar mass of solute

mass of glucose = 1.075 mol x 180.16 g/mol

mass of glucose = 194.0 g (rounded to three significant figures)

Therefore, approximately 194.0 grams of glucose (C6H12O6) would be required to prepare a 5000 mL solution with a concentration of 0.215 M. It's important to note that the molar mass of glucose used in this calculation may vary slightly depending on the level of precision required.

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The volume of the gas at STP would be 23.93 liters.

The volume of gas at STP (Standard Temperature and Pressure), we need to use the Ideal Gas Law, which states that PV = nRT, where P is pressure, V is volume, n is the number of moles of gas, R is the gas constant, and T is temperature. First, we need to calculate the number of moles of gas in the initial sample. We can use the formula n = PV/RT, where P is the initial pressure, V is the initial volume, R is the gas constant, and T is the initial temperature.
n = (2.31 atm) x (25.15 L) / [(0.0821 L atm/mol K) x (201 + 273.15 K)]
n = 1.067 moles

Now, we can use the molar volume of gas at STP, which is 22.4 L/mol, to calculate the volume of gas at STP.
V = n x 22.4 L/mol
V = 1.067 moles x 22.4 L/mol
V = 23.93 L
Therefore, the volume of the gas at STP would be 23.93 liters.

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Answer:

The coloring and possibly testing it

Potassium chloride is a medication that is used to treat or prevent low potassium levels in the body.Potassium can be removed from the body by certain diseases, illnesses, and drugs.

The addition of NaCl to a KCl mixture reduces the unpleasant side tastes associated with KCl, such as bitter, chemical, and metallic.

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Step 1 - Understanding the reaction

This reaction is a precipitation reaction: one of the products formed by the reaction is water-insoluble. This is also called, for simplicity sake, a douple-replacement reaction.

In such reactions, the cations will exchange their places, i.e., they will combine with the other cation's anion:

Step 2 - Solving the equation

Note Ba(2+) ion is ionic-bonded to Cl(-) anion, whereas K(+) ion is bonded to CO3(2-) anion. They will exchange places:

Note BaCO3 is a solid compound, because it is not soluble in water.

Step 3 - Balancing the reaction

To properly balance this reaction we have to multiply KCl by two: