Air is expanded in a polytropic process with n = 1.2 from 1 MPa and 400∘C to 110 kPa in a piston?cylinder device. Determine the final temperature of the air.

Answer:

2+2H2O.We already learn it

Negative ions, designated by the notation (OH ), are always present in any acid or base. The concentration. [OH"] of these ions is related to H by the equation OH H = 10-14 moles per liter.

Find the concentrations of OH and Hl in moles per liter for the substances with the following pH value pH = 7.8

The pH of a solution is given by the expression:\(pH = -log[H+],\)

where [H+] is the hydrogen ion concentration in mol/L.

To find the concentration of [H], we use the equation:

pH = -log[H+]7.8

= -log[H+]H+

= 10^-7.8H+

= 1.58 x 10^-8 moles per liter

Now, let's find the concentration of [OH-] by using the formula:

OH- H+ = 10^-14[H+]

= 1.58 x 10^-8OH- (1.58 x 10^-8)

= 10^-14OH-

= (10^-14) + (1.58 x 10^-8)OH-

= 1.0000000000000158 x 10^-14 moles per liter

OH- = 1.00 x 10^-14 moles per liter (rounded to two decimal places)

Concentration of [H] is 1.58 × 10⁻⁸ moles per liter and the concentration of [OH] is 1.00 × 10⁻¹⁴ moles per liter.

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Answer:

the potential energy is stored energy so when your going up a roller coaster your storing energy and gaining charger for it to release when you go down which is kinetic energy

Explanation:

hope this is what you were looking for

Answer:

Its a mixture.

Anther

Filament

Pistil

Stalk

Answer:

Explanation:AntherFilamentPistilStalk

The following statements on HPLC modes are true is more polar compounds elute first in normal-phase HPLC (Option E).

The liquid chromatography (HPLC) is a technique in analytical chemistry employed for the separation, identification, and quantification of elements. It is considered a highly sensitive method, and it works by separating the components in a mixture with the assistance of a solvent under high pressure.

There are two modes of HPLC: Reversed-Phase HPLC (RP-HPLC) and Normal-Phase HPLC (NP-HPLC). In RP-HPLC, a nonpolar stationary phase, such as C18, is used, and polar solvents, such as water, are used as mobile phases. Polar stationary phases, such as silica gel, are used in NP-HPLC, while nonpolar solvents, such as hexane, are used as mobile phases.

More polar compounds have a greater affinity for the polar stationary phase than less polar compounds, which have a higher affinity for the nonpolar mobile phase in NP-HPLC. As a result, less polar compounds elute first in normal-phase HPLC.

Thus, the correct option is E.

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Answer:

OA. YESS

Explanation:

They will because they are all over America.

The vapor pressure of the solution is approximately 13.4 torr.

The vapor pressure of a solution can be calculated using Raoult's law, which states that the vapor pressure of a solution is directly proportional to the mole fraction of the solvent. In this case, water is the solvent and ethylene glycol is the solute.

Given that the vapor pressure of pure water at 20°C is 17.5 torr, we can calculate the mole fraction of water in the solution. Since the solution is 21.6% ethylene glycol, the mole fraction of water (solvent) is 1 - 0.216 = 0.784.

Using Raoult's law, the vapor pressure of the solution is:

vapor pressure of solution = mole fraction of solvent * vapor pressure of pure solvent

vapor pressure of solution = 0.784 * 17.5 torr

vapor pressure of solution ≈ 13.7 torr

Rounding to three significant figures, the vapor pressure of the solution is approximately 13.4 torr.

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Answer:

they help people realize their full potential

Explanation:

yes

Answer:

they seek to protect people and their property

Explanation:

The presence of grooved bedrock and glacial deposits called tillites in Africa found along the equator and in areas with a very warm climate, provides important clues about the position of this part of Africa in the past.

The existence of glacial deposits (tillites) indicates that the region experienced a significant cooling event in the past. Glaciers form in cold environments, suggesting that the climate of this part of Africa was considerably colder than it is today, despite its proximity to the equator.

The presence of grooved bedrock and tillites along the equator suggests that the region was located at higher latitudes in the past. The movement of tectonic plates over millions of years can result in the shifting of continents, and this evidence implies that the part of Africa in question was situated closer to the Earth's poles at the time the glacial deposits were formed

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Mothballs are made of naphtalene. The chemical structure of naphthalene is formed by two benzene rings, which gives this substance the classification of an aromatic compound.

The active principle of naphthalene is explained by a very interesting physical characteristic: sublimation, which is defined as the direct transition from a solid to a gaseous state. Once sublimated, naphthalene appears as a toxic vapor for undesirable microorganisms.

So, when a bag of mothballs is opened, they will sublime. So the molecules will not be able to come back to the bag, because they're in the gaseous state, which is too difficult for us to "pick up" the molecules of mothballs again and place them in their bag again.

It is like picking up water vapor, it is impossible.

Answer: Alternative "D"

Answer:

its A

Explanation:

The percent yield of Al₂S₃ is 83.3%.

The theoretical yield of Al₂S₃ can be calculated based on the balanced chemical equation and the amount of sulfur used:

4S + 3Al → 2Al₂S₃

molar mass of S = 32.06 g/mol

moles of S = 4.8 g / 32.06 g/mol = 0.1499 mol

According to the stoichiometry of the balanced equation, 0.1499 mol of sulfur should react with 0.1124 mol of aluminum to produce 0.2998 mol of Al₂S₃:

moles of Al = moles of S x (3/4)

moles of Al = 0.1499 mol x (3/4) = 0.1124 mol

moles of Al₂S₃ = moles of S / (4/2)

moles of Al₂S₃ = 0.1499 mol / (4/2) = 0.2998 mol

The theoretical yield of Al₂S₃ can be calculated based on its molar mass:

mass of Al₂S₃ = moles of Al₂S₃ x molar mass of Al₂S₃

mass of Al₂S₃ = 0.2998 mol x (150.16 g/mol) = 45.02 g

The percent yield of Al₂S₃ can be calculated by dividing the actual yield by the theoretical yield and multiplying by 100:

percent yield = (actual yield / theoretical yield) x 100%

percent yield = (4.5 g / 45.02 g) x 100% = 83.3%

As a result, the percent yield of  Al₂S₃ is 83.3%.

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Answer:

phosphorus

Explanation:

mark me brainliest pl

Answer:

C. Neither accurate nor precise

Explanation:

Thus the results are neither accurate nor precise.

Answer:

Mass = 917.4 g

Explanation:

Given data:

Number of molecules = 3.00 ×10²⁴ molecules

Mass in gram = ?

Solution:

1 mole contain 6.022 × 10²³ molecules

3.00 ×10²⁴ molecules × 1 mol /  6.022 × 10²³ molecules

0.5×10¹ mol

5 mol

Mass in gram:

Mass = number of moles  × molar mass

Mass = 5 mol  × 183.48 g/mol

Mass = 917.4 g

Answer:

A

Explanation:

it causes the genes of two different individuals to mix

Answer:

Explanation:

A. It causes the genes of two different individuals to mix.

Answer:

A

Explanation:

The golf ball has more inertia than the table-tennis ball, so it takes

more force to change the motion of the golf ball.

The visual indicator that enough of a drying agent , such as anhydrous MgSO4 or CaCl2 has been added to properly dry an organic solution is that the drying agent will move freely like a powder around the solution .

Because the anhydrous form is hygroscopic ( readily absorbs water from the air ).

What is the work of anhydrous magnesium sulphate ?

Magnesium sulphate is frequently used in the laboratory as an indicator, especially after aqueous work-up . aqueous work-up is a common technique in the lab to get rid of residual impurities after completion of a reaction . for this the organic reaction is cooled to room temperature and mixed with water .specific impurities will then diffuse into the aqueous phase and can be separated with a separatory funnel .

unfortunately some residual water will stay in the organic phase and this can have negative impact for characterization of compound . therefore Magnesium sulphate is added ,which is able to catch the residual water in its crystal lattice .after filtration of the solid magnesium sulfate ,the water is reduced to non-significant amount and the compound ready for further investigation.

Similarly , calcium chloride is strongly hygroscopic ( absorbs water from the environment ) , so it removes moisture from the air ,making it dryer . this results in water  in the substance to be dried to evaporate into the drier air and this cycle repeats until the system reaches an equilibrium.

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Answer:

By measuring friction along faults, scientists can tell where rocks are moving along easily and where they are locked. They hope to use this information to predict where major earthquakes might occur.

Explanation:

Answer:

By measuring friction along faults, scientists can tell where rocks are moving along easily and where they are locked. They hope to use this information to predict where major earthquakes might occur.

Explanation:

tOaTLLY DiDnT cOpY iT

E. Fe2O3 ; 3.3 g is correct, Fe2O3 is the reactant and 3.3 g is excess .

The equation shows that for every 1.8 g of Al, 8.6 g of Fe2O3 is needed. Fe2O3 is an oxide of iron and is also known as ferric oxide or hematite. It is a red-brown material that is insoluble in water and is used in a variety of industrial applications.In this reaction, 1.8 g Al is used, meaning 8.6 g of Fe2O3 is needed. Since only 8.6 g of Fe2O3 is used, there is an excess of 3.3 g of Fe2O3.

Equation: 8.6 g Fe2O3 + 1.8 g Al → Al2O3 + 2Fe

Therefore 3.3g of the reactant Fe2O3 is excesss

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complete question:The thermite reaction is performed using 8.6 g Fe 2O 3 and 1.8 g powdered Al metal. Which reactant is in excess and by how much?

Fe2O3 + 2 Al → Al2O3 + 2Fe

A. Al; 0.3 g

B. Fe2O3; 2.0 g

C. Al; 2.1 g

D. Al; 1.1 g

E. Fe2O3; 3.3 g

The moles of substances required to make scrambled eggs is given in the cooking recipe for scrambled eggs.

A mole of. a substance is the amount of that substance which contains the avogadro number (6.02 × 10^23) of particles in it.

A mole of a substance is usually given as a standard unit measurement of that substance.

The mass of 1 mole of is known as the molar mass if that substance.

From the recipe for preparing scramble eggs given, the moles of substances required are as follows:

Therefore, the moles of substances required to make scrambled eggs is given in the cooking recipe for scrambled eggs.

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Answer:

To determine the limiting reactant, you need to compare the amount of each reactant with the amount required to react completely with the other reactant. The reactant that runs out first is the limiting reactant.

In this case, the balanced equation for the reaction between MgSO4 and NH3 is:

MgSO4 + 2 NH3 → Mg(NH2)2SO4

From the balanced equation, we can see that 1 mole of MgSO4 reacts with 2 moles of NH3. Therefore, 3.7 moles of MgSO4 will react with (3.7 moles)(2 moles NH3/1 mole MgSO4) = 7.4 moles of NH3.

4.8 moles of NH3 is less than 7.4 moles, so NH3 is the limiting reactant.

Uday Tahlan

Temperature, cooling rate, supersaturation, composition, and presence of impurities, collectively influence the formation of nuclei and subsequent crystal growth during solidification.

They determine the stability of nuclei, the rate of crystal growth, and the quality of the resulting crystal structure

When it comes to the solidification or crystallization process, the formation of nuclei and subsequent crystal growth are indeed two distinct mechanisms.

To understand how the parameters influence the kinetic and potential energy of atoms during solidification, we need to consider the factors that govern these processes.

Temperature:

Temperature plays a crucial role in solidification.

As the temperature decreases, the thermal energy of atoms decreases as well, leading to a decrease in their kinetic energy.

This reduction in kinetic energy promotes the formation of stable nuclei by allowing atoms to come closer together and form stable bonds.

Cooling Rate:

The rate at which the temperature decreases, or the cooling rate, affects the solidification process.

A slower cooling rate allows more time for atoms to diffuse and come together to form larger nuclei.

This slower cooling rate promotes the formation of well-defined crystal structures with fewer defects.

Supersaturation:

Supersaturation refers to a state where the concentration of solute atoms exceeds the equilibrium concentration.

In the context of solidification, supersaturation promotes nucleation by providing an excess of atoms available to form nuclei.

It increases the driving force for nucleation and subsequent crystal growth.

Composition:

The composition of the material being solidified influences the solidification process.

Different atomic compositions can result in varying interatomic forces and bonding energies.

These factors affect the stability of nuclei and the subsequent crystal growth.

For example, a material with a high atomic diffusion rate may exhibit faster crystal growth.

Presence of Impurities:

Impurities or foreign particles can have a significant influence on solidification.

They can act as nucleation sites, promoting the formation of nuclei and affecting crystal growth.

Impurities can also lead to the formation of different crystal structures or defects within the crystal lattice.

Regarding the kinetic and potential energy of atoms, the solidification process involves a decrease in both forms of energy:

Kinetic Energy:

As the temperature decreases, atoms lose thermal energy, resulting in a decrease in their kinetic energy.

This decrease in kinetic energy allows atoms to come closer together and form stable bonds.

Potential Energy:

During solidification, atoms rearrange themselves into a more ordered and stable arrangement, reducing their potential energy.

As atoms bond together to form a crystal lattice, their potential energy decreases due to the more favorable arrangement of atoms in the solid state compared to the liquid state.

Overall, the parameters mentioned above, such as temperature, cooling rate, supersaturation, composition, and presence of impurities, collectively influence the formation of nuclei and subsequent crystal growth during solidification.

They determine the stability of nuclei, the rate of crystal growth, and the quality of the resulting crystal structure.

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This problem is providing the ionic radius of an anion, A²⁻ as 0.290 nm and asks for that of the cation A²⁺ in comparison to the former.

Firstly, we need to recall the concept of ionic radius, as the distance between the nucleus and the outermost electron shell of an ion. In such a way, we can have two scenarios:

1. Anions result from the gain of electrons exhibited by a nonmetal, which means they turn out bigger than the neutral atom.

2. Cations result from the loss of electrons exhibited by a metal, which means they turn out smaller than the neutral atom.

With the aforementioned, we infer that the cation A²⁺, will me smaller than the anion A²⁻, which means it will have an ionic radius smaller than 0.290 nm.

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1107 Joule is the amount of energy which is needed to change 88.0 g of solid benzene at 5.53°C into liquid benzene, also at 5.53°C.

In order to perform work and to produce heat and light, energy must be delivered to a body or to an external physical system. Energy is a quantitative property. Energy is a preserved resource; according to the rule of conservation of energy, energy can only be transformed from one form to another and cannot be created or destroyed. 

A moving object's kinetic energy, an object's potential energy, an object's elastic energy, chemical energy linked to chemical reactions, electromagnetic radiation's radiant energy, and the internal energy of a thermodynamic system are examples of common kinds of energy.

mole of benzene = 85.2/78.11 =1.09mol

1 mole of benzene requires  10.19 kJ/mol energy

1.09 mole of benzene requires 1.09× 10.19 kJ/mol = 11.107kJ/mol energy

                                                                                  = 1107 Joule energy

Therefore,  1107 Joule is the amount of energy which is needed to change 88.0 g of solid benzene at 5.53°C into liquid benzene, also at 5.53°C.

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1. To determine the number of moles of NaClO₃ required to produce 61 moles of O₂, we can use the stoichiometric ratio between NaClO₃ and O₂.

From the balanced chemical equation, we see that 2 moles of NaClO₃ produce 3 moles of O₂. Therefore, we can set up the following proportion:

2 moles NaClO₃ / 3 moles O₂ = x moles NaClO₃ / 61 moles O₂

Solving for x, we get:

x = (2/3) × (61 moles O₂) / (1 mole NaClO₃) ≈ 41 moles NaClO₃

Therefore, approximately 41 moles of NaClO₃ are needed to produce 61 moles of O₂.

2. From the balanced chemical equation, we see that 3 moles of Cu react with 8 moles of HNO₃ to produce 2 moles of NO. Therefore, we can set up the following proportion:

3 moles Cu / 8 moles HNO₃ = 2 moles NO / x moles HNO₃

Solving for x, we get:

x = (8/3) × (2 moles NO) / (1 mole Cu) ≈ 5.3 moles HNO₃

Therefore, 5.3 moles of HNO₃ are needed to produce 2 moles of NO. If 26 moles of HNO₃ are consumed, we can calculate the moles of NO produced using a proportion:

3. 5.3 moles HNO₃ / 2 moles NO = 26 moles HNO₃ / y moles NO

Solving for y, we get:

y = (2/5.3) × (26 moles HNO₃) / (1 mole NO) ≈ 9.8 moles NO

Therefore, approximately 9.8 moles of NO can be produced when 26 moles of HNO₃ are consumed.

4. From the balanced chemical equation, we see that 8 moles of HNO₃ react with 4 moles of H₂O. Therefore, we can set up the following proportion:

8 moles HNO₃ / 4 moles H₂O = 75 moles HNO₃ / x moles H₂O

Solving for x, we get:

x = (4/8) × (75 moles HNO₃) / (1 mole H2O) = 37.5 moles H₂O

Therefore, 37.5 moles of H₂O can be produced when 75 moles of HNO₃ are consumed.

5. From the balanced chemical equation, we see that 2 moles of NaClO₃ produce 3 moles of O₂. Therefore, we can set up the following proportion:

2 moles NaClO₃ / 3 moles O₂ = 9 moles NaClO₃ / x moles O₂

Solving for x, we get:

x = (3/2) × (9 moles NaClO₃) / (1 mole O₂) = 13.5 moles O₂

Therefore, approximately 14 moles of O₂ are produced when 9 moles of NaClO₃ are used.

6. The stoichiometric ratio between C and CH₄ from the balanced chemical equation is 1:1. This means that 1 mole of carbon is required to produce 1 mole of methane.

Therefore, we can use the following proportion:

1 mole C / 1 mole CH₄

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(a) The reaction is endothermic.

(b) The heat is coming from the surroundings.

(c) The heat is absorbed by the reaction.

(a) The reaction is endothermic because the beaker feels cool in your hand. In an endothermic reaction, heat is absorbed from the surroundings, resulting in a decrease in the temperature of the immediate environment.

(b) The heat is coming from the surroundings. As the reaction proceeds, it requires energy in the form of heat, which it absorbs from the surrounding environment.

(c) The heat is going into the reaction. In an endothermic reaction, heat energy is absorbed by the reactants, causing their temperature to increase. This absorption of heat allows the reactants to undergo the chemical reaction and proceed toward the formation of products.

Overall, in an endothermic reaction, the heat is absorbed from the surroundings, causing the beaker to feel cool in your hand. The heat energy is utilized by the reaction to drive the chemical transformation of the reactants into products.

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Approximately 4 L of C₂H₂ are required to produce 8 L of CO₂ assuming the reaction is at STP.

To solve for the amount of C₂H₂ needed, we can use the stoichiometry of the balanced equation, combustion of hydrocarbons and the ideal gas law. According to the balanced equation, 2 moles of C₂H₂ react to produce 4 moles of CO₂. Therefore, we can set up the following ratio by assumimg x moles of C₂H₂ and then solving for x,

x = (2/4) * (8 L CO₂)

= 4 L C₂H₂

Since the problem states that the reaction is at STP (standard temperature and pressure), we can assume that the volume of gas is directly proportional to the number of moles of gas.

V = nRT/P

Solving for n at STP,

n = PV/RT = (4 L) x (1 atm) / (0.0821 L·atm/mol·K x 273.15 K) ≈ 0.167 mol

Therefore, approximately 0.167 mol (or 4 L) of C₂H₂ is required to produce 8 L of CO₂ assuming the reaction is at STP.

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