Air at 508C, 1 atm and a volumetric flow rate of 60 m3 / min enters an insulated control volume operating at steady state and mixes with helium entering as a separate stream at 1208C, 1 atm and a volumetric flow rate of 25 m3 /min. A single mixed stream exits at 1 atm. Ignoring kinetic and potential energy effects, determine for the control volume (a) the temperature of the exiting mixture, in 8C. (b) the rate of entropy production, in kW/K. (c) the rate of exergy destruction, in kW, for T0 5 295 K
Answers
(a) The temperature of the exiting mixture is 300.8 8C.
(b) The rate of entropy production is 0.767 kW/K.
(c) The rate of exergy destruction is 177.5 kW.
Air at 50 8C, 1 atm and a volumetric flow rate of 60 m3/min mixes with helium entering as a separate stream at 120 8C, 1 atm and a volumetric flow rate of 25 m3/min. A single mixed stream exits at 1 atm. Ignoring kinetic and potential energy effects, determine for the control volume.
(a) the temperature of the exiting mixture, in 8C. (b) the rate of entropy production, in kW/K. (c) the rate of exergy destruction, in kW, for T0 5 295 K.The given problem can be solved by the application of the energy and mass balance equations as well as the second law of thermodynamics.
The rate of mass flow (m) of air (ṁ_air) and helium (ṁ_he) can be calculated using the given volumetric flow rate and the density of air and helium.The mass flow rate of air (mṁ_air) = Volumetric flow rate of air (V_air) × Density of air (ρ_air) = 60 m3/min × 1.2 kg/m3= 72 kg/min
The mass flow rate of helium (mṁ_He) = Volumetric flow rate of helium (V_He) × Density of helium (ρ_He) = 25 m3/min × 0.166 kg/m3 = 4.15 kg/min.The mass flow rate of the mixture is the sum of the mass flow rates of the air and helium.
Therefore, the mass flow rate of the mixture (mṁ_mixture) = mṁ_air + mṁ_He = 72 + 4.15 = 76.15 kg/min(a) Calculation of the temperature of the exiting mixture:By applying the energy balance equation for steady-state processes, the energy input equals the energy output. That is,Q_in = Q_outor, mṁ_air Cpa T1 + mṁ_He Cp_He T2 = mṁ_mixture Cp T3
where, Cpa and Cp_He are the specific heat capacities of air and helium at constant pressure respectively.Cp is the specific heat capacity of the mixture at constant pressure.T1 and T2 are the temperatures of air and helium before mixing.T3 is the temperature of the mixture after mixing.
Substituting the given values into the above equation and solving for T3, we get;72 × 1.005 × (508 − T3) + 4.15 × 5.193 × (1208 − T3) = 76.15 × 1.128 × (T3 − 298)T3 = 573.8 K = 300.8 8C
Therefore, the temperature of the exiting mixture is 300.8 8C.
(b) Calculation of the rate of entropy production:The rate of entropy production can be calculated using the second law of thermodynamics. The entropy generation (S_gen) is given by the equation:S_gen = ṁ_mixture × s_mixture − ṁ_air × s_air − ṁ_He × s_He
where, s_air and s_He are the specific entropies of air and helium respectively.s_mixture is the specific entropy of the mixture.Taking the reference temperature (T0) to be 295 K, the rate of entropy production can be calculated as:
S_gen = ṁ_mixture × [s_mixture − s_0(T0)] − ṁ_air × [s_air − s_0(T0)] − ṁ_He × [s_He − s_0(T0)]where, s_0(T0) is the entropy at reference temperature (T0).
s_mixture = 1.128 × ln [(0.21 × P_1)/(0.21 × P_1 + 0.79 × P_2)] + 0.881 × ln [(0.79 × P_2)/(0.21 × P_1 + 0.79 × P_2)] = 1.128 × ln [(0.21 × 1)/(0.21 × 1 + 0.79 × 1)] + 0.881 × ln [(0.79 × 1)/(0.21 × 1 + 0.79 × 1)] = 0.375 kJ/kg.K
where, P_1 and P_2 are the partial pressures of air and helium respectively at the exit temperature.Taking the specific entropies of air and helium from steam tables, we get;
s_air = 72 × 1.005 × [ln T3/T0] − 72 × R_air × [ln P1/P0] = 72 × 1.005 × [ln(573.8/295)] − 72 × 0.287 × [ln 1/1] = 349.1 J/kg.ks_He = 4.15 × 5.193 × [ln T3/T0] − 4.15 × R_He × [ln P2/P0] = 4.15 × 5.193 × [ln(573.8/295)] − 4.15 × 2.076 × [ln 1/1] = 602.1 J/kg.k
Where, R_air and R_He are the specific gas constants of air and helium respectively.The rate of entropy production (S_gen) = 76.15 × [0.375 − 0.365] − 72 × [0.349 − 0.300] − 4.15 × [0.602 − 0.176] = 0.767 kW/K
Therefore, the rate of entropy production is 0.767 kW/K.
(c) Calculation of the rate of energy destruction:
The rate of energy destruction is calculated using the equation:Energy destruction rate = S_gen × (T − T0)where, T is the temperature at which the entropy is generated.Substituting the given values, the rate of energy destruction is;Energy destruction rate = 0.767 kW/K × (573.8 K − 295 K) = 177.5 kW
Therefore, the rate of energy destruction is 177.5 kW.
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Related Questions
Using the formula XC=1/(2πfC) in your answer, how would a capacitor influence a simple DC series circuit?
Answers
The capacitive reactance of a DC series circuit increases when its capacitance decreases and vice-versa.
What is a DC series circuit?A DC series circuit can be defined as a type of circuit in which all of its resistive components are connected end to end, so as to form a single path for the flow of current.
This ultimately implies that, the same amount of current flows through a direct current (DC) series circuit.
The capacitive reactance of a DC series circuit.Mathematically, the capacitive reactance of a DC series circuit is given by this formula:
\(X_C = \frac{1}{2\pi fC}\)
Where:
is the capacitive reactance.f is the frequency.C is the capacitance.From the above formula, we can deduce that the capacitive reactance of a DC series circuit is inversely proportional to both frequency and capacitance. Thus, the capacitive reactance of a DC series circuit increases when its capacitance decreases and vice-versa.
In conclusion, a capacitor would influence a simple DC series circuit by blocking the flow of direct current (DC) through it.
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For heat transfer purposes, a standing man can be mod-eled as a 30-cm-diameter, 170-cm-long vertical cylinderwith both the top and bottom surfaces insulated and with theside surface at an average temperature of 34°C. For a con-vection heat transfer coefficient of 15 W/m2·K, determinethe rate of heat loss from this man by convection in still airat 20°C. What would your answer
Answers
Answer:
Rate of Heat Loss = 336 W
Explanation:
First, we will find the surface area of the cylinder that is modelled as the man:
\(Area = A = (2\pi r)(l)\)
where,
r = radius of cylinder = 30 cm/2 = 15 cm = 0.15 m
l = length of cylinder = 170 cm = 1.7 m
Therefore,
\(A = 2\pi(0.15\ m)(1.7\ m)\\A = 1.6\ m^2\)
Now, we will calculate the rate of heat loss:
\(Rate\ of\ Heat\ Loss = hA\Delta T\)
where,
h = convective heat tranfer coefficient = 15 W/m²K
ΔT = Temperature difference = 34°C - 20°C = 14°C
Therefore,
\(Rate\ of\ Heat\ Loss = (15\ W/m^2K)(1.6\ m^2)(14\ K)\\\)
Rate of Heat Loss = 336 W
Which of the following was an Enlightenment idea that influenced the Founding Fathers?
Answers
Answer:
revolt against what they perceived as unfair British taxation.
Explanation:
Answer: natural laws/ natural rights, liberty, justice, and equality
Explanation:
If you have a three-prong plug and a two-hole receptacle, it is acceptable to:
A. Break the third prong off the plug
B. Drill a third hole in the receptacle
C. Use an adapter with an adapter wire connected to a known ground
D. Ground an adapter wire to use with a well known connection
Answers
The correct option is C. Use an adapter with an adapter wire connected to a known ground.
When dealing with a three-prong plug and a two-hole receptacle, it is important to prioritize electrical safety. The appropriate solution is to use an adapter with an adapter wire connected to a known ground. The adapter wire is typically connected to a grounded object, such as a metal water pipe or a grounding rod. This allows the electrical device to be safely grounded without causing damage to the plug or receptacle. In such cases, it is not recommended to break off the third prong or drill a third hole in the receptacle.
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1. A transfer girder is to support one symmetrically located column having a factored load of P (5000+200N) KN and is supported on 600mmx600mm square columns. The clear span of the transfer girder is 6m. The overall depth of the beam is (h = 4000mm) and the width of the beam is (b=400mm). Using C25 concrete and S360 reinforcing steel, Design the beam by STM method. (Neglect self-weight of the beam). Note: N=3.
Answers
Answer:
15000 KN.m
Explanation:
To design the transfer girder using the STM (Simplified Theory of Moments) method, we need to follow the steps outlined below:
Step 1: Calculate the factored load (P):
Given: P = 5000 + 200N KN
Let's substitute N = 3 into the equation:
P = 5000 + 200(3) = 5000 + 600 = 5600 KN
Step 2: Calculate the factored moment (Mu):
Mu = P x L^2 / 8
= 5600 KN x (6m)^2 / 8
= 15000 KN.m
Step 3: Calculate the design moment (Md):
Md = Mu / γm
(where γm is the partial safety factor for moment)
The value of γm depends on the design code or standard being used. For example, in Eurocode 2, the value of γm for reinforced concrete beams is typically taken as 1.35. However, since the specific code or standard is not provided in the question, we cannot calculate the design moment without this information.
To proceed with the design, we need to know the value of γm as specified in the relevant design code. Once that value is known, we can calculate the design moment and continue with the design process.
It is advisable to consult a structural engineer or refer to the appropriate design code or standard to obtain the required values and ensure accurate calculations for the design of the transfer girder.
Q1) Determine the force in each member of the
truss and state if the members are in tension or
compression.
Set P1 = 10 kN, P2=15 KN
Answers
Answer:
CD = DE = DF = 0BC = CE = 15 N tensionFA = 15 N compressionCF = 15√2 N compressionBF = 25 N tensionBG = 55/2 N tensionAB = (25√5)/2 N compressionExplanation:
The only vertical force that can be applied at joint D is that of link CD. Since joint D is stationary, there must be no vertical force. Hence the force in link CD must be zero, as must the force in link DE.
At joint E, the only horizontal force is that applied by link EF, so it, too, must be zero.
Then link CE has 15 N tension.
The downward force in CE must be balanced by an upward force in CF. Of that force, only 1/√2 of it will be vertical, so the force in CF is a compression of 15√2 N.
In order for the horizontal forces at C to be balanced the 15 N horizontal compression in CF must be balanced by a 15 N tension in BC.
At joint F, the 15 N horizontal compression in CF must be balanced by a 15 N compression in FA. CF contributes a downward force of 15 N at joint F. Together with the external load of 10 N, the total downward force at F is 25 N. Then the tension in BF must be 25 N to balance that.
At joint B, the 25 N downward vertical force in BF must be balanced by the vertical component of the compressive force in AB. That component is 2/√5 of the total force in AB, which must be a compression of 25√5/2 N.
The horizontal forces at joint B include the 15 N tension in BC and the 25/2 N compression in AB. These are balanced by a (25/2+15) N = 55/2 N tension in BG.
In summary, the link forces are ...
(25√5)/2 N compression in AB15 N tension in BC25 N tension in BF0 N in CD, DE, and EF15 N tension in CE15√2 compression in CF15 N compression in FA_____
Note that the forces at the pins of G and A are in accordance with those that give a net torque about those point of 0, serving as a check on the above calculations.
The steel bracket is used to connect the ends of two cables. if the allowable normal stress for the steel is sallow = 30 ksi, determine the largest tensile force p that can be applied to the cables. assume the bracket is a rod having a diameter of 1.5 in.
Answers
The largest tensile force that can be applied to the cables given a rod with diameter 1.5 is 2013.15lb
The static equilibrium is given as:
F = P (Normal force)
Formula for moment at section
M = P(4 + 1.5/2)
= 4.75p
Solve for the cross sectional area
Area = \(\frac{\pi d^{2} }{4}\)
d = 1.5
\(\frac{\pi *1.5^{2} }{4}\)
= 1.767 inches²
Solve for inertia
\(\frac{\pi *0.75^4}{4}\)
= 0.2485inches⁴
Solve for the tensile force from here
\(\frac{F}{A} +\frac{Mc}{I}\)
30x10³ = \(\frac{P}{1.767} +\frac{4.75p*0.75}{0.2485} \\\\\)
30000 = 14.902 p
divide through by 14.902
2013.15 = P
The largest tensile force that can be applied to the cables given a rod with diameter 1.5 is 2013.15lb
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you can think of the ____ in a method declaration as a funnel into the method.
Answers
You can think of the parameters in a method declaration as a funnel into the method.
You can think of the parameters in a method declaration as a funnel into the method. Parameters are the inputs that a method takes in, and they define the type and name of the data that the method needs to execute its logic. When a method is called with arguments, the arguments are passed as values to the corresponding parameters in the method declaration. The parameters act as a funnel that channels the input data into the method's logic. The number and type of parameters in a method declaration determine how the method can be used and what data it can handle. By defining parameters with specific data types, a method can ensure that it receives the correct data and can operate on it correctly. The parameter names can also provide information about the purpose of the data being passed in, making the method more readable and understandable to other developers. When a method is called with arguments, the values of the arguments are copied into the corresponding parameters in the method declaration. The method then uses these parameter values to perform its logic and compute a result, which is returned to the caller. By defining parameters in a method declaration, developers can create modular and reusable code that can be used in different contexts and with different input data.
.
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Type your answer in the box. which implies that every In engineering, all equations must be dimensionally term must have the same unit. Read about this Do you know the answer? I know it Think so Unsure No idea
Answers
In engineering, it is important that all equations be dimensionally consistent, which means that every term must have the same unit.
This ensures that the equation is physically meaningful and that the results are accurate. Dimensional consistency is a key concept in engineering and is used to check the validity of equations and to derive new equations. It is also important for converting units and for making sure that all terms in an equation are in the correct units.
Without dimensional consistency, equations can lead to incorrect results and can cause problems in engineering design and analysis.
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An athlete is holding 24 lb of weights at a height of 6 inches above the stack as shown. To lower the weights, she applies a constant force of 5 lb to the handle. Determine the velocity of the weights immediately before they hit the stack.
Answers
The velocity of the weights immediately before they hit the stack is 3.4672 ft/s
How to solve for the velocity1 Lb = 0.453 kg
24 = 24 x 0.453
= 10.872kg
Therefore the m = 10.872
g = 9.87
m1 = 10.872/9.87
m1g = 1.112
T = 5 lb
= 5 x 0.453 = 2.265kg
m1g = T + 2T
1.112a = 10.872 - 3(2.265)
a = 3.66m/s²
initial velocity = 0
6x 2.54
= 15.24x10⁻²m
v² = 0+ 2as
v = √2as
v = √2x3.66x 15.24x10⁻²
= √1.1174
= 1.0571
a meter is equal to 3.28 ft
v*m = 1.0571 * 3.28
= 3.4672 ft/s
The velocity of the weights immediately before they hit the stack is 3.4672 ft/s.
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An organization sets its standards for quality according to the best product it can produce.
True
False
Answers
Answer:
True!! took the test
Explanation:
Select four elements to include when considering aesthetics.
Responses
direct costs
direct costs
variety
variety
form
form
emphasis
emphasis
exploded view
exploded view
asymmetry
asymmetry
Answers
Aesthetics is a subjective concept that encompasses various elements to create a visually pleasing and harmonious experience. When considering aesthetics, four important elements to include are variety, form, emphasis, and asymmetry.
1. Variety: Incorporating a range of different elements, such as colors, textures, shapes, and patterns, adds visual interest and prevents monotony. Variety can create a dynamic and engaging composition.
2. Form: The form refers to the shape, structure, and overall arrangement of elements. A well-defined and balanced form can evoke a sense of order and unity, contributing to the overall aesthetic appeal.
3. Emphasis: Emphasizing specific elements or focal points draws attention and creates a hierarchy within the composition. This can be achieved through contrasting colors, larger or unique shapes, or strategic placement, enhancing the visual impact.
4. Asymmetry: While symmetry can be visually pleasing, introducing deliberate imbalances or irregularities can add intrigue and uniqueness. Asymmetry creates a sense of movement and visual tension, making the design more captivating.
By considering these four elements, one can create a visually appealing aesthetic that is diverse, well-structured, visually engaging, and aesthetically intriguing.
Remember that these elements can be applied differently based on the context and desired outcome, allowing for endless possibilities and creative expressions.
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When you park on a hill,the direction your __are pointed determines which direction your car will roll if the breaks fail
Answers
Answer:
Tires or wheels? I think this is the answer. ^_^
Explanation:
What is the key objective of data analysis
Answers
Answer: The process of data analysis uses analytical and logical reasoning to gain information from the data. The main purpose of data analysis is to find meaning in data so that the derived knowledge can be used to make informed decisions.
Discuss the targeted design properties for resorbable polyurethanes for tissue repair and non-resorbable polyurethane permanent implants. How can the properties of the polyurethane be tailored to the application by modifying the structure?
Answers
The property is that polyurethanes have a good tear resistance as well as tensile strength.
What is polyurethanes?Polyurethane is an umbrella word for a group of polymers formed via the condensation of polyisocyanates and polyalcohols. Despite its xenobiotic origins, polyurethane has been discovered to be biodegradable by naturally occurring microbes.
Polyurethanes are synthesized by reacting a polyol (an alcohol having more than two reactive hydroxyl groups per molecule) with a diisocyanate or a polymeric isocyanate in the presence of appropriate catalysts and additives
To manage cell fate and tissue healing, biodegradable polyurethane platforms have been used. Cell bonding, spreading, multiplication, and separation are all influenced by framework features such as compound, mechanical, and primary. These are not fully fixed as the science of biodegradable polyurethanes, platform manufacturing technologies, and surface change approaches.
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The tow truck weighs 7.83 kN. The wheel base (distance between the front wheel and the back wheel) is 6.3 m and the center of gravity of the truck is 2.15 m behind the front wheel. The load hangs from the tow truck 0.9 m behind the back wheel.
Required:
How big can L be before the truck tips over?
Answers
In order to determine how big L can be before the truck tips over, we need to calculate the maximum overturning moment that the truck can withstand.
This can be done by comparing the overturning moment to the restoring moment.OVERTURNING MOMENT:The overturning moment can be calculated using the weight of the truck and the load as well as their respective distances from the pivot point (the front wheel).The weight of the truck is given as 7.83 kN, and the weight of the load is assumed to be L kN. Since the load is hanging 0.9 m behind the back wheel, its distance from the pivot point is 6.3 + 2.15 + 0.9 = 9.35 m. Therefore, the overturning moment is given by:Overtuning moment = (7.83 + L) * 9.35 kN.mRESTORING MOMENT:The restoring moment can be calculated using the weight of the truck and the load, as well as their respective distances from the pivot point (the front wheel), and the wheelbase of the truck.
The weight of the truck and the load act downwards, while the reaction force from the ground acts upwards at the front wheel. Since the truck is in equilibrium, the sum of the clockwise moments about the front wheel must equal the sum of the anticlockwise moments about the front wheel. Therefore, we can write:Clockwise moment about front wheel = Anticlockwise moment about front wheel(7.83 + L) * 2.15 = 7.83 * 6.3 + L * (6.3 + 0.9)Simplifying the above equation, we get:15.2815 + 2.15L = 50.409 + 6.3L4.15L = 35.127L = 8.47Therefore, the load can be a maximum of 8.47 kN before the truck tips over.
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Examine this statement:
SELECT 3 * 2 + 2 / 4 FROM DUAL; What is the result?
Answers
Answer:
it is 2
Explanation:
this is sql command that return one line (from dual ) with taht math solved
The result of this SQL statement would be 6.5
Here is the breakdown of the calculation:
3 * 2 = 6
2 / 4 = 0.5
6 + 0.5 = 6.5
Define the term SQL.
SQL stands for Structured Query Language. It is a programming language used to manage and manipulate relational databases. SQL is used to communicate with a database, allowing users to create, read, update, and delete data from a database. SQL is widely used by software developers, database administrators, data analysts, and other professionals who work with data.
SQL consists of a set of commands that are used to interact with a database. These commands include SELECT, INSERT, UPDATE, DELETE, and others. SQL commands are used to retrieve data from a database, add new data, modify existing data, and delete data. SQL is used to create and manage database schemas, which define the structure of a database and the relationships between different tables.
The SQL statement SELECT 3 * 2 + 2 / 4 FROM DUAL; will produce a result of 6.5.
The statement is performing a simple arithmetic calculation, which involves multiplication, division, and addition. Here is the calculation part:
3 * 2 is calculated first, which gives us 6.
2 / 4 is calculated next, which gives us 0.5.
Finally, the results of step 1 and step 2 are added together, giving us the final result of 6.5.
Therefore, The keyword "FROM DUAL" is often used in Oracle databases to select a constant value. In this case, it doesn't have any impact on the calculation itself, as we're only performing a simple arithmetic operation.
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Two stepped bar is supported at both ends.At the join point of two segments,the force F is applied(downwards).Calculate reactive forces R1 and R3 at the supports.What is value of absolute maximal stress?
Choose one answer nearest your result.
given= d1=10mm d2=20mm L1=20mm L2=10mm E=200GPa F=20kN
Answers
Answer:
F=200kN
Explanation:
The electrical contractor association is typical example of a
Answers
Answer:
Trade association.
Explanation:
I'm thinking it is as it represents contractors who design, install, inspect and maintain amongst other activities electrical and electronic equipments or service.
A refrigerator with a COP of 3.0 removes heat from the refrigerated space at a rate of 10 kW. Determine the rate of power input.
Answers
The rate of power input for this refrigerator is 3.33 kW.
A refrigerator with a COP (Coefficient of Performance) of 3.0 is designed to remove heat from the refrigerated space efficiently. The COP is the ratio of the amount of heat removed from the refrigerated space to the work (power input) done by the refrigerator.
In this case, the heat removal rate is given as 10 kW. To determine the rate of power input, we can use the following formula:
COP = (Heat removal rate) / (Power input)
Rearranging the formula to solve for the power input:
Power input = (Heat removal rate) / COP
By substituting the given values:
Power input = (10 kW) / (3.0)
Power input = 3.33 kW (approx.)
So, the rate of power input for this refrigerator is approximately 3.33 kW. This means that for every 3.33 kW of electrical power supplied to the refrigerator, it is able to remove 10 kW of heat from the refrigerated space. A higher COP indicates a more energy-efficient refrigerator.
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You do a simple experiment at home with the plastic body of a syringe, where you close the exit with one thumb, and push in the plunger with your other thumb. You are able to compress the air inside the syringe from 5ml to 1ml. Assume that you hold the plunger for long enough such that the temperature equalizes to ambient conditions.
Required:
a. Given that the circular plunger's diameter is 1.5cm, how much force is being exerted to hold the plunger in the compressed state?
b. Given that the opening of the syringe has a diameter of 2mm, how much force is exerted on the thumb used to trap the air from escaping?
Answers
Answer:
a. 89.5 N b. 1.59 N
Explanation:
a. Given that the circular plunger's diameter is 1.5cm, how much force is being exerted to hold the plunger in the compressed state?
Using Boyle's law, we find the final pressure at the compressed state given that the initial pressure is atmospheric pressure
So, P₁V₁ = P₂V₂ where P₁ = initial atmospheric pressure in syringe = 1 atm = 1.013 × 10⁵ N/m²,V₁ = initial volume of syringe = 5 ml, P₂ = final pressure in syringe at compression and V₂ = final volume of syringe = 1 ml
So, making P₂ subject of the formula, we have
P₂ = P₁V₁/V₂
Substituting the values of the variables into the equation, we have
P₂ = P₁V₁/V₂
P₂ = 1.013 × 10⁵ N/m² × 5 ml/1 ml
P₂ = 1.013 × 10⁵ N/m² × 5
P₂ = 5.065 × 10⁵ N/m²
Since pressure, P = F/A where F = force and A = cross-sectional area of syringe = πd²/4 where d = diameter of syringe = 1.5 cm = 1.5 × 10⁻² m.
So, F = PA
F = P₂πd²/4
substituting the values of the variables into the equation, we have
F = P₂πd²/4
F = 5.065 × 10⁵ N/m²π(1.5 × 10⁻² m)²/4
F = 5.065 × 10⁵ N/m²π(2.25 × 10⁻⁴ m²)/4
F = 35.8 × 10/4 N
F = 8.95 × 10
F = 89.5 N
b. Given that the opening of the syringe has a diameter of 2mm, how much force is exerted on the thumb used to trap the air from escaping?
Since the pressure in the syringe after compression is constant, we have
P₂ = F₁/A₁ where F₁ = force exerted on thumb and A₁ = cross-sectional area of opening of syringe = πd₁²/4 where d = diameter of opening of syringe = 2 mm = 2 × 10⁻³ m.
So, F₁ = P₂A₁
F = P₂πd₁²/4
substituting the values of the variables into the equation, we have
F = P₂πd²/4
F = 5.065 × 10⁵ N/m²π(2 × 10⁻³ m)²/4
F = 5.065 × 10⁵ N/m²π(4 × 10⁻⁶ m²)/4
F = 15.91 × 10⁻¹
F = 1.591 N
F ≅ 1.59 N
How many ase certifications are there for automotive technicians?
Answers
Answer:
There are 50 ASE certification tests, covering almost every imaginable aspect of the automotive repair and service industry.
Explanation:
yww <33
There are a total of 50 certifications for automotive technicians.
How to determine the number of certificationsin September 2021, the National Institute for Automotive Service Excellence (ASE) offers a total of 50 certifications for automotive technicians.
These certifications cover various areas of specialization, including engine repair, electrical systems, brakes, suspension and steering, heating and air conditioning, and more.
Each certification requires passing a written exam and meeting specific work experience requirements
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Need help please due today ill give brainliest for non-irrelevant answers
Describe the quality control measures engineers likely will use for a newly introduced line of cars that use solar power to recharge high-capacity batteries. Propose at least three tests or processes that will be important to any quality assessment for such a vehicle system.
Answers
Answer:
make sure its safe make sure it works as inteded
Explanation:
yes
Which tool would you use to grab and lift small objects? A. IC extractor. B. Multi-meter. C. 3-prong holder. D. Cable tester.
Answers
The tool that is specifically designed to grab and lift small objects is a 3-prong holder, also known as a tweezer or forceps.
A 3-prong holder is a handheld tool with two opposing arms that can be squeezed together to grip and hold small objects securely. It typically has a narrow and pointed tip that allows for precise handling of delicate or small items. The prongs of the holder are usually made of metal, such as stainless steel, which provides strength and durability.
The design of the 3-prong holder allows for easy manipulation and control when picking up small objects. The user can squeeze the arms of the holder to create a firm grip on the object, and release the grip by gently separating the arms. This tool is commonly used in various fields such as electronics, jewelry making, laboratory work, and medical procedures.
Unlike the other options provided:
- An IC (Integrated Circuit) extractor is a specialized tool used for safely removing IC chips from sockets or circuit boards. It is not intended for grabbing and lifting small objects in general.
- A multi-meter is an electrical testing tool used for measuring voltage, current, and resistance in circuits. It is not designed for grabbing or lifting objects.
- A cable tester is a tool used for checking the integrity and functionality of cables, such as Ethernet or audio cables. It is not suitable for grabbing or lifting small objects.
Thus, the correct option is "c".
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The tool that is specifically designed to grab and lift small objects is a 3-prong holder, also known as a tweezer or forceps.
A 3-prong holder is a handheld tool with two opposing arms that can be squeezed together to grip and hold small objects securely. It typically has a narrow and pointed tip that allows for precise handling of delicate or small items. The prongs of the holder are usually made of metal, such as stainless steel, which provides strength and durability.
The design of the 3-prong holder allows for easy manipulation and control when picking up small objects. The user can squeeze the arms of the holder to create a firm grip on the object, and release the grip by gently separating the arms. This tool is commonly used in various fields such as electronics, jewelry making, laboratory work, and medical procedures.
Unlike the other options provided:
- An IC (Integrated Circuit) extractor is a specialized tool used for safely removing IC chips from sockets or circuit boards. It is not intended for grabbing and lifting small objects in general.
- A multi-meter is an electrical testing tool used for measuring voltage, current, and resistance in circuits. It is not designed for grabbing or lifting objects.
- A cable tester is a tool used for checking the integrity and functionality of cables, such as Ethernet or audio cables. It is not suitable for grabbing or lifting small objects.
Thus, the correct option is "c".
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Transcribed image text: Suppose that you want to arrange a meeting with two other people at a secret location in Manhattan that is an intersection of two streets (let's say 110th street and 2nd avenue, for concreteness). You want to send each of them a message such that they can find the location if they work together, but neither one can find it on their own. What could you send to each of them? Explain your reasoning.
Answers
Answer:
You could send each person one half of the coordinates of the secret location, such as "110th street" to one person and "2nd avenue" to the other person. This way, they would need to work together to share their information and determine the exact location of the intersection.
This approach ensures that neither person can find the location on their own, as they only have half of the information needed to determine the intersection. Additionally, sharing the coordinates separately adds an extra layer of security to the meeting location as it would be difficult for anyone to determine the meeting location without both pieces of information.
However, it's important to ensure that each person understands the instructions clearly, so they know to work together to determine the secret location. It's also important to choose a location that is not well-known, so the possibility of someone stumbling upon the meeting location by chance is reduced.
Explanation:
Suggest how the following requirements might be rewritten in a
quantitative way:
a. The library system shall be easy-to-use.
b. The library system shall provide reliable service to all classes of
user.
c. The library system shall provide a rapid response to all user
requests for book information.
Answers
Answer:
answer letter c
Explanation:
yun anserr hhehehe
A car is driven over a curb twice—once very slowly and once quite rapidly. What would you need to know about the car in the second case that you did not need to know in the first case if you were required to find the tire force that resulted from going over the curb?
Answers
Answer:
You'd need to know things like the weight of the car, the spring constant of the suspension springs.
Explanation:
Driving over the curb slowly does not have much of an "impact" because of the small potential energy it has but to find the force that results from going over the curb at a much higher speed, you would need to know the weight of the car since it directly impact the force that it applies. You also would need to know about the car's suspension, the spring material, how stiff the springs are and their spring constant to calculate the force they absorb.
I hope this answer helps.
Answer ALL questions in this section. (a) Convert the hexadecimal number (FAFA.B) 16 into decimal number. (b) Solve the following subtraction in 2’s complement form and verify its decimal solution. 01100101 - 11101000 (c) Boolean expression is given as: A + B[AC + (B+C)D] (i) Simplify the expression into its simplest Sum-of-Product(SOP) form. (ii) Draw the logic diagram of the expression obtained in part (c)(i). (iii) Provide the Canonical Product-of-Sum(POS) form.
(iv) Draw the logic diagram of the expression obtained in part (c)(iii).
Answers
The hexadecimal number (FAFA.B) 16 into decimal number is 64250.6875 (decimal).
(a) To convert the hexadecimal number (FAFA.B)16 into a decimal number, we can break it down into its integer and fractional parts.
The integer part, FAFA16, can be converted to decimal by multiplying each digit by the corresponding power of 16 and summing them up:
FAFA16 = (15 × 16^3) + (10 × 16^2) + (15 × 16^1) + (10 × 16^0) = 64250
The fractional part, B16, represents the value 11/16 in decimal since B corresponds to the decimal value 11. Therefore, B16 = 11/16.
Combining the integer and fractional parts, we have:
FAFA.B16 = 64250 + 11/16 = 64250.6875 (decimal)
(b) To subtract the binary numbers 01100101 and 11101000 using 2's complement form, we first need to find the 2's complement of the second number (11101000).
Invert all the bits in 11101000 to get 00010111. Then add 1 to the result: 00010111 + 1 = 00011000.
Now, perform the subtraction by adding the first number (01100101) and the 2's complement of the second number (00011000):
01100101
+ 00011000 (2's complement of 11101000)
----------
01111101
The result is 01111101 in binary. To verify the decimal solution, convert it to decimal form:
01111101 = (0 × 2^7) + (1 × 2^6) + (1 × 2^5) + (1 × 2^4) + (1 × 2^3) + (1 × 2^2) + (0 × 2^1) + (1 × 2^0) = 125 (decimal)
Therefore, 01100101 - 11101000 = 125 in decimal.
(c) (i) To simplify the given boolean expression A + B[AC + (B + C)D] into its simplest Sum-of-Product (SOP) form, we can expand and simplify the expression:
A + B[AC + (B + C)D]
= A + B[AC + BD + CD]
= A + BAC + BBD + BCD
The simplified SOP form is: A + BAC + BBD + BCD.
(ii) To obtain the Canonical Product-of-Sum (POS) form, we'll first distribute the negation operation over the expression and apply De Morgan's laws:
A + BAC + BBD + BCD
= A + ABC + ABD + BCD
Next, we'll convert each term into its complement form:
A = A' + A
ABC = (A' + B' + C') + ABC
ABD = (A' + B' + D') + ABD
BCD = (B' + C' + D') + BCD
Finally, we'll combine these terms using the distributive property:
(A' + A) + (A' + B' + C') + ABC + (A' + B' + D') + ABD + (B' + C' + D') + BCD
This is the Canonical Product-of-Sum (POS) form of the given boolean expression.
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The Probable question may be:
(a) Convert the hexadecimal number (FAFA.B) 16 into decimal number.
(b) Solve the following subtraction in 2's complement form and verify its decimal solution.
01100101 - 11101000
(c) Boolean expression is given as: A + B[AC + (B+ C)D]
(i) Simplify the expression into its simplest Sum-of-Product(SOP) form.
(ii) Provide the Canonical Product-of-Sum(POS) form.
A 10 hp motor is used to raise a 1000 Newton weight at a vertical distance of 5 meters. What is the work the motor performs?
please explain the calculation
Answers
The work done by a 10 HP motor when it raises a 1000 Newton weight at a vertical distance of 5 meters is 5kJ.
Define work. Explain the rate of doing work.
Work is the energy that is moved to or from an item by applying force along a displacement in physics. For a constant force acting in the same direction as the motion, work is easiest expressed as the product of force magnitude and distance traveled.
Since the force transfers one unit of energy for every unit of work it performs, the rate at which work is done and energy is used are equal.
Solution Explained:
Given,
Weight = 1000N and distance = 5m
A/Q, the work here is done in lifting then
Work = (weight) × (distance moved)
= 1000 X 5
= 5000Nm or 5000J = 5kJ
Therefore, the work done in lifting a 1000 Newton weight at a vertical distance of 5 meters is 5kJ.
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The painting crew has 54 2/3 miles of center lines to paint on the highway. If they have completed 23 1/5 miles, how many miles do they have to go?
a. 31 7/15
b. 31 13/15
c. 24 4/15
cl. 31 1/2
Answers
Total miles of center lines = 54 2/3 miles
Miles already painted = 23 1/5 miles
54 2/3 - 23 1/5 = 31 7/15 miles
Therefore, the painting crew has 31 7/15 miles left to paint. Answer: (a) 31 7/15.
The correct option is B, 31 13/15 miles.
To find out how many miles the painting crew has left to paint, you need to subtract the completed miles (23 1/5) from the total miles (54 2/3). Find a common denominator for the fractions, which is 15. Convert the fractions to have the common denominator.
Total distance = 54 2/3 miles
Completed distance = 23 1/5 miles
We can subtract these two distances by finding a common denominator for the fractions:
54 2/3 miles = 54 10/15 miles
23 1/5 miles = 23 3/15 miles
Now we can subtract:
54 10/15 miles
- 23 3/15 miles
31 7/15 miles.
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