Ahmed is a mango seller on day 1 he sells3/10 mangoes and on day 2 he sells 2/5 manoges. how many mangoes he sells altogether

The type of dilation and scale factor in the figure shown is

Scale factors are used to increase or decrease image. The situation of increment is usually called magnifying or enlargement.

The given problem is enlargement since the preimage is smaller than the image. Also the scale factor will be greater than 1

Taking a point of reference say side 6 in the preimage and side 15 in the image and solve for the factor, assuming the factor is k

6k = 15

k = 15/6

k = 2.5

hence we say that the scale factor is 2.5

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Answer: Enlargement with scale factor of 2.5

Step-by-step explanation: I took the quiz so you don't have too!

The temperature has decreased by 4 degrees Celsius.

We have a temperature change from 3 degrees below zero at midnight to 7 degrees below zero at 2 a.m.

We have to determine how much did the temperature decrease.

A temperature of x degrees below zero means that the temperature of an area is equal to = - x degrees i.e., T = 0 - x = - x.

According to question -

Initial Temperature T(i) = 0 - 3 = - 3 degrees

Final temperature T(f) = 0 - 7 = - 7 degrees

Change in temperature ΔT = T(f) - T(i) = -7 - (-3) = -7 + 3 = - 4

Hence, the temperature has decreased by 4 degrees Celsius.

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To sum up, Edgar's behavior is an example of positive reinforcement as he has learned to associate finishing his work before going to bed with positive consequences.

Edgar's behavior is an example of a learning process known as operant conditioning. Operant conditioning is the concept that we learn to associate our behavior with its consequences, either positive or negative. We are motivated by rewards, such as praise, and punishments, such as criticism, that we experience as a result of our behavior.

In Edgar's case, his relief and ability to fall asleep after completing his research paper can be considered a reward. Thus, he has been conditioned to associate finishing his work before going to bed with positive consequences. This learning process is an example of positive reinforcement.

Positive reinforcement, in which a positive stimulus is used to encourage a desired behavior, is the most effective way to promote good behavior and discourage undesirable behavior. Positive reinforcement can take many forms, including praise, recognition, and tangible rewards.

By contrast, negative reinforcement, which involves removing an unpleasant stimulus, can also be used to encourage a desired behavior, but it is not as effective as positive reinforcement in the long term.

To sum up, Edgar's behavior is an example of positive reinforcement as he has learned to associate finishing his work before going to bed with positive consequences.

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Answer:

The solution of the system of equation is (3,8)

Step-by-step explanation:

We are given that

\(y=x+5\)...(1)

\(y=2x+2\)...(2)

We have to graph the system of linear equation.

For equation (1)

Substitute x=0

\(y=5\)

Substitute y=0

\(x=-5\)

Therefore, we obtained two points  (0,5) and (-5,0) for equation (1).

For equation (2)

Substitute x=0

\(y=2\)

Substitute y=0

\(2x=-2\)

\(x=-1\)

Therefore, we obtained two points  (0,2) and (-1,0) for equation (2).

Now, we find intersection point of two equation

Substract equation (2) from (1)

\(x=3\)

\(x=3\)

Substitute x=3 in equation (1)

\(y=3+5=8\)

The intersection point of two equation is at (3,8).

Hence, the solution of given system of equation is (3,8).

Answer:

(-4,-6)

Step-by-step explanation:

The intersection point is (-4,-6) when you both equations in the calculator. The person who answered this first is wrong.

If dr. Robinson rejects the null hypothesis after observing a test statistic that exceeds the critical value at the .05 level, there is a 5% chance that the null hypothesis is actually true.

This refers to the hypothesis that there is no significant difference between specified populations, where any observed difference is due to sampling or experimental error.

Hence, we can see that if dr. Robinson rejects the null hypothesis after observing a test statistic that exceeds the critical value at the .05 level, there is a 5% chance that the null hypothesis is actually true.

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Since the scale utilized in the draw is 1 inch : 9 feet and the diving board is 2 inches, we need to multiply the 2 inches by the scale:

The actual diving board is 18ft long

The correct option  a) 4 ft. , Service Cable that is attached to a building must be sustained at intervals no greater than 4 ft..

Service cables mounted in close proximity to a building must be supported at no more than four-foot intervals.

Thus,  service cable that is attached to a building must be sustained at intervals no greater than 4 ft.

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Answer:

  €0.78

Step-by-step explanation:

To find Euros per Dollar, divide euros by dollars:

  €175/$225 = 7/9 €/$ ≈ 0.78 €/$

Kareem received about €0.78 for each dollar exchanged.

Answer:

yes

Step-by-step explanation:

4<8*2+8

4<16+8

4<24

4 ≥2+1

4 ≥3

Answer:

i believe number 1 is 18 and number 2 is 9.

Step-by-step explanation:

if one full circle represents 6 CDs then on wednesday 18 Cds were sold because 6+6+6=18 and on thursday they sold 9 more Cds than on wednesday because they sold 6+6+6+6+3 which equals 9.

Answer:

2,300

Step-by-step explanation:

into hundredths.

that means each fish is cut into 100 pieces.

so, there would be

23 × 100 = 2,300

pieces of fish.

Answer:

A, 2,300.

Step-by-step explanation:

hope this helps lol

The first four terms of the Taylor series for the function (2x) about the point (a=1) are (2x + 2x - 2).

To find the first four terms of the Taylor series for the function (2x) about the point (a = 1), we can use the general formula for the Taylor series expansion:

\(\[f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \frac{f'''(a)}{3!}(x-a)^3 + \ldots\]\)

Let's calculate the first four terms:

Starting with the first term, we substitute

\(\(f(a) = f(1) = 2(1) = 2x\)\)

For the second term, we differentiate (2x) with respect to (x) to get (2), and multiply it by (x-1) to obtain (2(x-1)=2x-2).

\(\(f'(a) = \frac{d}{dx}(2x) = 2\)\)

\(\(f'(a)(x-a) = 2(x-1) = 2x - 2\)\)

Third term: \(\(f''(a) = \frac{d^2}{dx^2}(2x) = 0\)\)

Since the second derivative is zero, the third term is zero.

Fourth term:\(\(f'''(a) = \frac{d^3}{dx^3}(2x) = 0\)\)

Similarly, the fourth term is also zero.

Therefore, the first four terms of the Taylor series for the function (2x) about the point (a = 1) are:

(2x + 2x - 2)

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Step-by-step explanation:

first- b

swcond- a

third- c

Answer:

Step-by-step explanation:

interest was $160 for one year.

160/4000 = 0.04 = 4%

Answer:

x + y = 24

16x + 20y = 434

x = 11.5

y = 12.5

Step-by-step explanation:

Part A:

x + y = 24

16x + 20y = 434

Part B:

simplify the second equation to find a "kind of answer" to a variable,

so we could simplify it to either y = 21.7 - 0.8x or x = 27.125 - 1.25y

in this case we will use y = 21.7 - 0.8x

substitute your new value of y into the first equation:

x + (21.7 - 0.8x) = 24

now, we can solve this to find the actual value of x: x = 11.5

so plug in your real x value to the simplified second equation (y = 21.7 - 0.8x)

you get y = 12.5

this tells you how many hours the machine spent on making each type of item

Answer:

Cost price=100%

Step-by-step explanation:

Answer:

18 students have only 2 pencils

Step-by-step explanation:

There is 29 students. six + five is eleven. Subtract 29 - 11 which is 18

To classify a quadrilateral by its sides, we need to calculate the distance between each pair of its vertices.

The distance between Q and R is the square root of ((1-(-2))^2 + (5-(-1))^2) = square root of (3^2 + 6^2) = square root of (9+36) = square root of 45 = 6.7

The distance between R and T is the square root of ((-8-1)^2 + (-4-5)^2) = square root of (9+81) = square root of 90 = 9.5

The distance between Q and T is the square root of ((-8+2)^2 + (-4+1)^2) = square root of (10+5) = square root of 15 = 3.87

If the quadrilateral is a rectangle, two sides of it have to be equal, so in this case, AQRT is not a rectangle.

If the quadrilateral is a rhombus, all four sides have to be equal, so in this case, AQRT is not a rhombus.

If the quadrilateral is a square, all four sides have to be equal, so in this case, AQRT is not a square.

If the quadrilateral is a trapezoid, two adjacent sides are parallel, so in this case, AQRT is not a trapezoid.

If the quadrilateral is a parallelogram, two pairs of opposite sides are parallel, so in this case, AQRT is not a parallelogram.

If the quadrilateral is a kite, two pairs of sides have the same length, so in this case, AQRT is not a kite.

So the only possible classification is that AQRT is a general quadrilateral.

so we have:

QR = 6.7

RT = 9.5

QT = 3.87

Answer:

7.95$

Step-by-step explanation:

1.87 $ per 1 lb

1.87 * 4.25 = 7.95$

Answer:

$7.95 for 4.25 lbs. of grapes

Step-by-step explanation:

so your going to multiply $1.87 by 4.25 to get the total amount of money needing to be paid in or der to buy the 4.25 lbs. of grapes:

$1.87 * 4.25 = 7.9475

now turning it into money by rounding to the hundredths place:

7.9475 = $7.95

So you would have to pay $7.95 for 4.25 lbs. of grapes but logically you would bring 8 dollars to buy it, but down to the cents it would be $7.95.

The general solution to the given differential equation is\(y = (C_1)/(x(x-6y))\)where C_1 is the constant of integration.

The given differential equation is \(9x(x+y)y'=9y(x-6y)\)

Step 1: We can simplify this equation to get y' and dy/dx by dividing both sides by

9xy(x−6y) = (x−6y)dy/dx + y

=> dy/dx = y/[x(x−6y)] − 1/(x−6y)

Now, we can rewrite the differential equation as dy/dx = y/[x(x−6y)] − 1/(x−6y)

Step 2: This is a separable differential equation.

We can write it in the form

dy/dx + 1/(x−6y) = y/[x(x−6y)] Multiplying by the integrating factor μ(x) = e∫(1/(x−6y))dx gives us

\(\mu(x)dy/dx + [\mu(x)/(x-6y)] = \mu(x)y/[x(x-6y)]\)

We can simplify this as \(d/dx[\mu(x)y] = \mu(x)y/[x(x-6y)]\)

Integrating both sides, we get

ln|y| = ∫μ(x)/(x(x−6y)) dx + C where C is the constant of integration

Step 3: Now, we need to find the integrating factor μ(x). We can writeμ(x) = e∫1/(x−6y) dxSo, we substitute x−6y = t and get dx = dt + 6dy

So,

\(\mu(x) = e\int1/(x-6y) dx\)

= e∫1/t dt

= e^(ln|t|)

= |t|

= |x−6y|

Step 4: Substituting for μ(x) and simplifying the integral, we get

\(ln|y| = -(1/6)ln|x-6y| - (1/6)ln|x| + C'\)

=> \(ln|y| = ln((C_1)/(x(x-6y)))\)

=> \(y = (C_1)/(x(x-6y))\)

Where C_1 = e^C' is a new constant of integration \(y = (C_1)/(x(x-6y))\)

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Answer:

y = 126° + 29° = 155°

Step-by-step explanation:

I think this may be a solution:

126°+29°=155°

So, y=155°

Complex numbers can be represented in GeoGebra using the complex number constructors, specifically the complexnumber(real,imaginary) command.

This command creates a complex number with the given real and imaginary components. For example, a complex number with a real part of 3 and an imaginary part of 4 can be written as complexnumber(3,4). This will create a complex number with a real part of 3 and an imaginary part of 4, represented as 3+4i. GeoGebra also contains other commands for manipulating complex numbers, such as the conjugate(z) command, which produces the conjugate of the given complex number z, and the re(z) and im(z) commands, which extract the real and imaginary components of the given z, respectively. Together, these commands allow GeoGebra to effectively represent and manipulate complex numbers.

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The total weight of the two animals is 1.3 x 10^4 lbs.

The given parameters are

Animal 1 = 4.23 x 103 lbs.

Animal 2 = 8.7 x 103 lbs.

Rewrite the parameters properly

Animal 1 = 4.23 x 10^3 lbs.

Animal 2 = 8.7 x 10^3 lbs.

The total weight of the two animals is calculated as

Total weight = Animal 1 + Animal 2

This gives

Total weight = 4.23 x 10^3 lbs + 8.7 x 10^3 lbs.

Factor out 10^3 lbs

Total weight = (4.23 + 8.7) x 10^3 lbs.

Evaluate the sum

Total weight = 12.93 x 10^3 lbs.

Rewrite as

Total weight = 1.293 x 10^4 lbs.

Approximate

Total weight = 1.3 x 10^4 lbs.

Hence, the total weight of the two animals is 1.3 x 10^4 lbs.

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In this lab, the independent variable is the physical parameter being manipulated to determine its relationship with the dependent variable. The data from the lab shows that there is a linear relationship between the two variables, which can be seen in the graph provided.

However, there are several sources of error that could be present in the data. First, if the data was collected by hand, there is a possibility of human error due to misreading or recording incorrect values. To prevent this, it is important to double-check all data points before recording them. Additionally, factors such as the accuracy of the measuring device used and the precision of the data collected could lead to discrepancies in the results.

To minimize these errors, it is important to use a device that is accurate and precise, and record data to the correct level of precision. Finally, changes in the environment can also lead to inaccurate results, such as the temperature and humidity of the lab. To prevent this, it is important to keep the lab environment as consistent as possible and to record any variations in the environment that could affect the results.

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Answer:

A) 2

B)109

c) 4

d)71

I'm a hundred percent sure

Step-by-step explanation:

Draw the Venn diagram

First, we want to note two things:

We can describe this with an inequality:  x ≥ -10
Be sure you use ≥ and not >, since -10 is included.

We can describe this with interval notation: [ -10, infty )
Be sure you use [ and not ( on -10, since -10 is included.

You can also use set-builder notation: { x | x ≥ -10 }

Answer:

3 and 4

Step-by-step explanation:

given that the difference is 7, two numbers that add up to 7 are 3 and 4.

Answer:

Dara receives £120 and Jo receives £300

Step-by-step explanation:

D:J

2:5

5+2=7

£420÷7= £60

1 on the ratio= £60

Dara:

£60 × 2= £120

Jo:

£60× 5= £300

When throwing a pair of dice, there are a total of 6 sides on each die, which gives us 6 x 6 = 36 possible outcomes. The total number of spots (the sum of the numbers on the dice) can range from 2 to 12.

When a pair of dice are thrown, there are three possible outcomes for the total number of spots: 1) The sum of the spots on both dice is less than 7. This occurs when the first dice lands on a number between 1 and 6, and the second dice lands on a number that will make the total less than 7 (e.g. if the first dice lands on 3, then the second dice must land on a number less than or equal to 3).  2) The sum of the spots on both dice is exactly 7. This occurs when the first dice lands on a number between 1 and 6, and the second dice lands on the number that will make the total equal to 7 (e.g. if the first dice lands on 2, then the second dice must land on 5).  3) The sum of the spots on both dice is greater than 7. This occurs when the first dice lands on a number between 1 and 6, and the second dice lands on a number that will make the total greater than 7 (e.g. if the first dice lands on 4, then the second dice must land on a number greater than 3).

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