After Newton came up with the three Laws of Motion and the Universal Law of Gravitation, he revised Kepler's 3rd Law. In doing so he gave us a tool for determining what property of orbiting bodies? O The combined masses of both objects. O The velocity of the objects as they orbit each other. O The mass of the smaller object. The acceleration of the objects.
Answers
After Newton revised Kepler's 3rd Law, he gave us a tool for determining the combined masses of both objects in an orbiting system. Newton's laws of motion and his universal law of gravitation revolutionized our understanding of celestial mechanics .
Kepler's 3rd Law, also known as the harmonic law, states that the square of the orbital period (T) of a planet is proportional to the cube of its average distance (r) from the Sun. Mathematically, it can be expressed as:
T² = (4π² * r³) / (G * M)
Where T is the orbital period, r is the distance between the center of the planet and the center of the Sun, G is the gravitational constant, and M is the mass of the Sun.
However, Newton's revision of Kepler's 3rd Law, known as Newton's version of Kepler's 3rd Law, provides a more general form. It states that the square of the orbital period (T) of a planet or any other two orbiting objects is proportional to the cube of the semi-major axis (a) of the elliptical orbit. Mathematically, it can be expressed as:
T² = (4π² * a³) / (G * (M₁ + M₂))
Where M₁ and M₂ are the masses of the two objects in the system.
By rearranging this equation, we can solve for the combined masses of both objects (M₁ + M₂):
M₁ + M₂ = (4π² * a³) / (G * T²)
Therefore, after Newton revised Kepler's 3rd Law, we have a tool for determining the combined masses of both objects in an orbiting system.
After revising Kepler's 3rd Law, Newton provided us with a tool for determining the combined masses of both objects in an orbiting system. By using his version of Kepler's 3rd Law, which relates the square of the orbital period to the cube of the semi-major axis of the orbit, we can calculate the combined masses of the objects. This revision expanded our understanding of celestial motion and allowed for the determination of important properties of orbiting bodies beyond their distances and periods. Newton's laws of motion and his universal law of gravitation revolutionized our understanding of celestial mechanics and provided a foundation for further developments in the field of astronomy and physics.
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Related Questions
What are the advantages of radial symmetry in a polyp that stays in one place? receive food from any direction 360 degree defense O prevents overheating easier to reproduce
Answers
Radial symmetry provides various advantages to a stationary polyp, such as effective food capture, defense, temperature regulation, and reproduction.
The advantages of radial symmetry in a polyp that stays in one place include the ability to receive food from any direction, 360-degree defense, prevention of overheating, and easier reproduction.
1. Receive food from any direction: Since the polyp has a symmetrical body structure, it can efficiently capture and process food coming from all directions without needing to reorient itself.
2. 360-degree defense: Radial symmetry enables the polyp to detect and respond to threats from any direction, providing an effective defense mechanism.
3. Prevents overheating: A symmetrical body structure allows for better heat distribution, reducing the risk of overheating in a stationary polyp.
4. Easier reproduction: Radial symmetry simplifies the reproduction process, as identical body parts can divide or produce offspring without complex body planning.
In summary, radial symmetry provides various advantages to a stationary polyp, such as effective food capture, defense, temperature regulation, and reproduction.
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why is a polarized filter helpful to a photographer? A. it transmits all light
Answers
Answer:
It blocks some light, but not all.
Explanation:
The point of polarization is to get the light to travel in a single plane. The light waves occur in a single plane. The direction of the vibration of the waves is the same. With two polarized filters, it is possible to block out nearly all the light.
What is the estimated effective nuclear charge, zeff, experienced by an electron in a 3p orbital of a chlorine atom?.
Answers
estimated effective nuclear charge experienced by a 3 p electron of chlorine is 6.1.
What is nuclear charge ?
In atomic physics, the net nuclear charge is the actual amount of positive (nuclear) charge experienced by electrons in a multi-electron atom. The term "effective" is used because the shielding effect of negatively charged electrons prevents higher energy electrons from experiencing the full nuclear charge of the nucleus due to inner layer repulsive effects. The net nuclear charge experienced by an electron is also called the nuclear charge. The strength of the nuclear charge can be determined by the oxidation number of the atom. Most of the physical and chemical properties of elements can be described in terms of their electronic configurations. . It is known that the magnitude of the ionization potential depends on the following factors:
atomic size;
nuclear charge;
Inner shell shielding effect u
The extent to which the outermost electrons penetrate the charge cloud created by the inner electrons.
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two objects, with masses m1 and m2, attract each other with force f. if the mass of m1 increased by a factor of two then the new gravitational force would be:
Answers
The new gravitational force between them would be twice the initial gravitational force.
What is Newton's law of universal gravitation?Newton's law of universal gravitation states that the force of attraction between two object in the universe is directly proportional to the product of their masses and inversely proportional to the square of the distance between the two objects.
Mathematically, the formula for Newton's law of universal gravitation is given as;
F = ( Gm₁m₂ ) / ( R² )
where;
m₁ is the mass of the first objectm₂ is the mass of the second objectR is the distance between the two objectsG is universal gravitation constantWhen mass m1 of the two objects doubles, the new gravitational force will be calculated as;
F' = ( G x 2m₁ x m₂ ) / ( R² )
F' = 2( Gm₁m₂ ) / ( R² )
F' = 2F
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Types of Forces Lab Report
Instructions: In the Types of Forces lab, you will experiment with the contact force friction. Use the following lab report to record your hypothesis, materials, procedures, observations, and conclusion. You will submit your completed report.
Name and Title
Name of Lab:
Student Name:
Instructor:
Date:
Objective
The purpose is to test whether the surface texture of the ground affects the distance an object can roll.
Hypothesis
If an object rolls over _______________ (type of material), then it will _____________ (describe the prediction of distance it will travel).
Materials
For this lab, I used the following items:
Procedure
Short summary of what I did:
I experienced the following errors while doing my experiment:
Test (independent) variable (What was different about my test groups?):
Outcome (dependent) variable (What was I measuring?):
Data
Record the distance traveled for each of the trials for the three floor surfaces in the table below.
Distance Object Traveled
Floor Surface Trial 1 Trial 2 Trial 3
Data Analysis
Calculate the average distance traveled for each floor surface. Use the following guidelines for calculating averages, and show your work.
Floor Covering Calculation of the Average Average Distance Traveled
Example (trial 1 measurement + trial 2 measurement + trial 3 measurement) / 3 (number of trials) Your answer from the calculation, showing the average distance the ball rolled for that floor covering.
Answers
Frictional force is reduced in smooth surfaces but is large in rough surfaces.
What is Force?Force is defined as an agent which causes a change in the motion or state of an object.
Forces are of two types:
Contact forces and Non-contact forcesContact forces include frictional force.
Frictional forces refers to the force which acts between two surfaces in contact by opposing the relative motion of one over the other
Frictional force depends on the nature of surfaces in contact where rough surfaces produce greater frictional force than smooth surfaces.
Therefore, frictional force is reduced in smooth surfaces but is large in rough surfaces.
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The celestial sphere turns once around each day because.
Answers
Answer:
The celestial sphere turns once around each day because...
the planet on which we live is rotating
Explanation:
Earth is constantly rotating which causes the celestial sphere to rotate as well.
5. The speed of a car is 15m/s. Its speed in km/h is *
Answers
Answer:
54 Km per hour..
Explanation:
Multiply the speed value by 3.6
15m/s=15*3.6
=54km/hr
A 985 car is moving in a circular track with tangential speed of 25 m/s . The radius of the track is 2.75km 985 kg,calculate the centripetal acceleration on the car
Answers
F = mv²/r = m.a
a = v²/r
a = 25²/(2.75 x 10³)
a = 0.227 m/s²
you charge a parallel-plate capacitor, remove it from the battery, and prevent the wires connected to the plates from touching each other. when you increase the plate separation, do the following quantities increase, decrease, or stay the same?
Answers
The capacitance characteristics allow to find that the response to increase the separation of the plates are:
Capacitance increases The potential difference decreases The charge remains constant
A capacitor is a system formed by two parallel plates charged with opposite charge that stores energy, the capacitance is
C = \(\frac{Q}{\Delta V} = \epsilon_o \frac{A}{d}\)
Where C is the capacitance, Q the stored charge, ΔV the voltage difference, A the area of the plates, d the separation between them and ε₀ the dielectric permittivity (ε₀ = 8.85 10⁻¹² \(\frac{C^2}{N \ m^2 }\))
In this case the capacitor is charged and then the separation of the plates increases, the different amounts are affected:
From the expression it is observed that the capacitance increases The area of the plates remains constant, The charge remains constant, since it is not connected to the battery The potential difference decreases.
In conclusion of the characteristics of capacitance, let us find that the response for increased separation of the plates are:
Capacitance increases The potential difference decreases The charge remains constant
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When the displacement in SHM is one-half the amplitude xm, what fraction of total energy is (a) kinetic energy and (b) potential energy (c) At what displacement, in terms of the amplitude, is the energy of the system half kinetic energy and half potential energy
Answers
Answer:
b
Explanation:
In an element's square on the periodic table, the number with the greatest numerical value represents the
number of neutrons.
number of electrons.
atomic number.
atomic mass.
Answers
Answer: Atomic mass
Explanation:
I took the test!
your welcome
Answer:
Atomic Mass on edge2020
Explanation:
Just did it. And got it correct.
A hockey puck with a mass of 0.16 kg travels at a velocity of 40m / s toward a goalkeeper. The goalkeeper has a mass of 120 kg and is at rest. Assuming a closed system, find the total momentum of the goalkeeper and puck after the puck is caught by the goalkeeper. In 3-4 sentences, identify the object with the greater momentum after the puck is caught and explain your reasoning. (4 points)
Answers
(a) The total momentum of the goalkeeper and puck after the puck is caught by the goalkeeper is 6.4 kgm/s.
(b) The goalkeeper has greater momentum after the puck is caught because of the conservation of linear momentum. The initial momentum of the hockey puck of 6.4 kgm/s was transferred to the goalkeeper which increased his initial zero momentum to approximately final momentum of 6.4 kgm/s.
What is the total moment of the goalkeeper and puck?
The total momentum of the goalkeeper and puck after the puck is caught by the goalkeeper is calculated by applying the principle of conservation of linear momentum.
m₁u₁ + m₂u₂ = v (m₁ + m₂)
where;
m₁ is the mass of the hockey puckm₂ is the mass of the goalkeeperu₁ is the initial velocity pucku₂ is the initial velocity of the goalkeeperv is the final velocity of the goalkeeper and puck after the collision0.16(40) + 120(0) = v (0.16 + 120)
6.4 = 120.16v
v = (6.4) / (120.16)
v = 0.053 m/s
The final momentum of the hocky puck after the collision is calculated as;
Pf₁ = 0.16 kg x 0.053 m/s
Pf₁ = 0.0085 kgm/s
The final momentum of the goalkeeper after the collision is calculated as;
Pf₂ = 120 kg x 0.053 m/s
Pf₂ = 6.36 kgm/s
The total momentum = 0.0085 kgm/s + 6.36 kgm/s = 6.4 kgm/s
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The current is measured with the ammeter at the bottom of the circuit. When the switch is opened, does the reading on the ammeter (a) increase (b) decrease (c) not change
(18.3)
Answers
When the switch is opened in a circuit, the flow of current is interrupted. This means that there is no longer a complete circuit, and the current will stop flowing. Therefore, the reading on the ammeter will decrease or become zero. The right option will be B) decrease.
The current is measured with the ammeter at the bottom of the circuit, which means that it is measuring the flow of current in the entire circuit.
When the switch is opened, it creates an open circuit, and the ammeter will no longer measure any current flowing through it.
In conclusion, the reading on the ammeter will drop or become zero when the switch is opened in a circuit.
It is important to note that the reading on the ammeter will only change if the circuit is interrupted by opening a switch or if there is a change in the resistance or voltage in the circuit. Hence, the correct answer is B) decrease.
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Please help!! I'll name you brainliest!!
Answers
Answer:
11
Explanation:
the O at the end stands for oxygen and after that theres the number 11. that tells u how many oxygen atoms there are PLEASE AMRK BRAINLIEST ;C
a) Calculate force FL upwards (the hand on the right)
b) Calculate Fr downwards
Answers
Answer:
did you find the answer yet??
Explanation:
Two identically-sized metal spheres on insulating
stands are positioned as shown below. The
charge on sphere A is −4.0 × 10−6 coulomb and
the charge on sphere B is −8.0 × 10−6 coulomb.
The two spheres are touched together and then
separated. The total number of excess electrons
on sphere A after the separation is
Answers
Answer:
-6 x 10^-6 C
Explanation:
The two spheres will equilibrate to the same charge on each
-6 x 10^-6 C
The two spheres are touched together and then separated. The total number of excess electrons on sphere A is 3.75×10¹³ electrons after the separation.
What is electric charge ?Electric charge is the physical property of matter that experiences force when it is placed in electric field. F = qE where q is amount of charge, E = electric field and F = is force experienced by the charge. there are two types of charges, positive charge and negative charge which are generally carried by proton and electron resp. like charges repel each other and unlike charges attract each other. the flow charges is called as current. Elementary charge is amount of charge a electron is having, whose value is 1.602 x 10⁻¹⁹ C.
When the spheres touch together, they obtain equal charges. Since the spheres are same in dimension, they obtain equal charges.
Given,
q₁ = −4.0 × 10⁻⁶ C
q₂ = −8.0 × 10⁻⁶ C
q₁ + q₂ = −4.0 × 10⁻⁶ C + −8.0 × 10⁻⁶ C = -12.0 × 10⁻⁶ C
When two charged spheres touch together, they will have equal amount of charge. Means there attain equilibrium of charge.
Hence each charged sphere will have -6.0 × 10⁻⁶ C of charge.
The number of excess electrons on both the spheres will be,
(6.0 × 10⁻⁶ C) ÷ (1.6 × 10⁻¹⁹C) = 3.75 × 10¹³
The number 1.6 × 10⁻¹⁹C is called as Elementary charge.
Hence the number of excess electrons on Sphere A is 3.75 × 10¹³.
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observationally, how can we decide which of the four general expansion models best describes the present-day universe? observationally, how can we decide which of the four general expansion models best describes the present-day universe? the best way of observing is the accurate measurements of distances between the galaxies. the most fitting standard candles for such measurements at such distances are white dwarf supernovae. the best way of observing is the accurate measurements of the masses of galactic central supermassive black holes. the most fitting approach for such measurements at such distances are the maps of the relative speeds of the stellar clusters. the best way of observing is the accurate measurements of the masses of galactic central supermassive black holes. the most fitting approach for such measurements at such distances are the relative amounts of gas and stars in the galaxies. the best way of observing is the accurate measurements of distances between the galaxies. the most fitting standard candles for such measurements at such distances are the active galactic nuclei x-ray and gamma-ray bursts.
Answers
To determine which of the four general expansion models best describes the present-day universe, we must rely on observational evidence. Accurate measurements of distances between galaxies and the masses of galactic central supermassive black holes are essential for making these determinations.
One effective method for measuring distances involves using standard candles, such as white dwarf supernovae, which allow us to gauge distances accurately. Another approach involves observing active galactic nuclei X-ray and gamma-ray bursts, which also serve as reliable distance indicators.
Additionally, measuring the masses of galactic central supermassive black holes can provide insight into the expansion model. Mapping the relative speeds of stellar clusters and examining the relative amounts of gas and stars in galaxies are suitable techniques for obtaining such measurements.
In summary, a combination of accurate distance measurements using standard candles like white dwarf supernovae and active galactic nuclei bursts, along with mass measurements of galactic central supermassive black holes, can help us identify the most appropriate expansion model for the present-day universe.
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According to Bohr's model of the hydrogen atom, the atomic orbit with a quantum number of n = 1 has
an orbit radius of 0.0529 nanometers.
The orbit with a quantum number n = 2 has a radius of 0.212 nanometers.
Which number would be closest to the radius of the orbit with the quantum number n = 5?
A. 0.846 nm
B. 1.32 nm
C. 1.9 nm
D. 0.476 nm
Answers
The practice of science can answer only scientific questions. And scientific questions guide the design of investigations. What must be true of the possible answers to a scientific question? A. They are popular with a majority of scientists. B. They agree with all prior experiments. C. They lead to increased funding of scientific research. D. They can be supported by evidence.
Answers
The scientific question can be supported by evidence that must be true of the possible answers to a scientific question. Option D is correct,
What is a Scientific hypothesis?A scientific hypothesis must meet two criteria, A scientific hypothesis must be testable, and a scientific hypothesis must be falsifiable The basic idea of a hypothesis is that there is no predetermined outcome.
For a solution to be termed a scientific hypothesis, it has to be an idea that can be supported or refuted through carefully crafted experimentation or observation.
Only scientific questions may be answered by scientific activity. The design of the research is also influenced by scientific issues.
The scientific question can be supported by evidence that must be true of the possible answers to a scientific question.
They are accurate regarding the scientific question and can be substantiated by proof.
Hence option D is correct.
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rigid rod of negligible mass lying along the y axis connects three particles as shown: should the total rotational kinetic energy from (c) be the same as the total kinetic energy of the system you calculated from (e)? why or why not?
Answers
Total rotational kinetic energy & the total kinetic energy (KE_tot) are not necessarily same as one is associated with rotational motion and other with total energy.
The total rotational kinetic energy (KE_rot) and the total kinetic energy (KE_tot) of a system are not necessarily the same, as they represent different types of energy. KE_rot represents the energy associated with rotational motion, while KE_tot represents the total energy of the system, including both translational motion and rotational motion.
In the case of the rigid rod connecting three particles, if the system is in rotational motion, the particles will have both translational and rotational motion. The translational motion of the particles contributes to the total kinetic energy of the system, while the rotational motion contributes to the rotational kinetic energy of the system.
In general, it can be said that KE_rot and KE_tot are related, but their values will depend on the specific details of the system, such as the masses of the particles, their distances from the axis of rotation, and the speed and direction of their motion.
It is not necessarily the case that the total rotational kinetic energy from (c) should be the same as the total kinetic energy of the system you calculated from (e), as the two represent different aspects of the energy of the system. However, in some specific cases, if the system is in pure rotational motion, the total rotational kinetic energy and the total kinetic energy of the system will be the same.
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Identify the nature and point of action of the third force acting on the wheelbarrow.Write down an equation showing the relationship between the three forces
Answers
Wheelbarrow is a small cart which has a wheel in the front, and two supporting legs and two handles in the back. It is used for carrying loads.
Wheelbarrow is a second class lever. The three forces acting on a wheelbarrow are input force (applied force to move), output force (due to load) and the force due to fulcrum (or wheel) on one end.
The applied force and force due to wheel are in opposite directions, one acting upward and the other acting downward. The load force will be in between the applied force and the force due to wheel.
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a ball is swung in a vertical circle such that at one point along its circular path the forces exerted on the ball can be represented by the free body diagram. the magnitude of the tension force exerted on the ball, t, is twice that of the force due to gravity exerted on the ball from earth, fg. what is the location of the ball, and what is the magnitude of the centripetal acceleration of the ball?
Answers
Location of the ball is top of the circle and acceleration is 3g.
Since tension force is more, surely ball is having net force upward and hence, the location of the ball in this case is top of the circle.
Any object that moves in a circle has an acceleration vector towards the center of that circle. This is known as Centripetal acceleration.
total force/ net force when ball is top of the circle is sum of tension force and gravity force.
\(F_{net\) = T + mg
Because of this net force, there is centripetal acceleration towards the center.
so, T + mg = ma
2mg + mg = ma
3mg = ma
a = 3 × force of gravity
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what evidence is there that fields exist between objects even if those objects are not in contact?
Answers
Gravitational force -an attractive force that exists between all objects with mass
What is a force of attraction between two objects even if they are not touching?Gravity has traditionally been defined as a force of attraction between things that have mass. According to this conception of gravity, anything that has mass, no matter how small, exerts gravity on other matter. Gravity can act between objects that are not even touching.An apple falling down from a tree is one of the best examples of non-contact force.Iron pins attracted in the presence of a magnet bar without any physical contact.Falling raindrops on earth is also an example of a non-contact force.Magnetic forces are non contact forces; they pull or push on objects without touching them. Magnets are only attracted to a few 'magnetic' metals and not all matter. Magnets are attracted to and repel other magnets.Gravity is a force of attraction that exists between any two masses, any two bodies, any two particles. Gravity is not just the attraction between objects and the Earth. It is an attraction that exists between all objects, everywhere in the universe.
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Fields exist between objects even if objects don't have any contact because gravity pulls them toward each other.
What is gravity?gravity, also called gravitation, in mechanics, the universal force of attraction acting between all matter. It is by far the weakest known force in nature and thus plays no role in determining the internal properties of everyday matter. On the other hand, through its long reach and universal action, it controls the trajectories of bodies in the solar system and elsewhere in the universe and the structures and evolution of stars, galaxies, and the whole cosmos. On Earth all bodies have a weight, or downward force of gravity.In physics, gravity (from Latin gravitas 'weight') is a fundamental interaction which causes mutual attraction between all things with mass or energy.To learn more about gravity refer to:
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Waves spread when passing through openings of various sizes. More spreading occurs for openings that are _________.
Answers
Through various-sized apertures, waves propagate. When the apertures match the size of the wave amplitude, more spreading takes place.
If waves travel through one medium and then into another, does diffraction happen?When waves move from one medium to another, the direction they travel in changes, which is known as refraction. A shift in wavelength and speed always occurs with refraction. Waves bend over gaps and obstructions in a process known as diffraction. As the wavelength gets longer, more diffraction occurs.
How does diffracted light affect waves?The spreading of waves as they go through an aperture or around objects is known as diffraction. When the aperture's or obstacle's size is on the same scale as the wavelength of the light.
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according to Newton's 1st law , an object without a net force ? What
Answers
Answer:
an object in motion stays in motion an object at rest stays in rest
Explanation:
two sirens are attached to a vertical metal plate. they both have the same frequency and they are in phase. the sirens are separated by a distance of 4.00 m. they generate sound with a frequency of 514 hz. a fire fighter is standing away from the sirens, in front of one of the sirens. what is the closest distance from the metal plate the fire fighter can stand and hear destructive interference?
Answers
Answer:
When two sound waves with the same frequency and amplitude interfere, they can either add up constructively, resulting in a louder sound, or cancel each other out destructively, resulting in no sound at all. Destructive interference occurs when the waves are out of phase by half a wavelength, which means that the distance between the two sources is equal to an odd multiple of half the wavelength.
In this case, the distance between the two sirens is 4.00 m, which is equal to one wavelength (λ) plus half a wavelength (λ/2) of the sound waves they emit. Therefore, the wavelength of the sound waves is λ = 4.00 m / 1.5 = 2.67 m.
To find the distance from the metal plate where the fire fighter can stand and hear destructive interference, we need to calculate the distance from the plate to the fire fighter that is equal to an odd multiple of half the wavelength. Let's call this distance "x".
If the fire fighter is standing in front of one siren, the distance from the plate to the fire fighter is:
d1 = x
If the fire fighter moves towards the plate by a distance of half the wavelength, the distance from the plate to the fire fighter becomes:
d2 = x - λ/2
The difference between these two distances must be an odd multiple of half the wavelength for destructive interference to occur:
d2 - d1 = -λ/2 = -(2.67 m / 2) = -1.335 m
Therefore, the fire fighter can stand at a distance of x = 1.335 m away from the metal plate and hear destructive interference.
A gyroscope flywheel of radius 2.12 cm is accelerated from rest at 16.2 rad/s2 until its angular speed is 1820 rev/min. (a) what is the tangential acceleration of a point on the rim of the flywheel during this spin-up process
Answers
The tangental acceleration of the flywheel of radius 2.12 cm with a final angular velocity of 1820 rev/min and an angular acceleration of 16.2 rad/s is 0.34 m/s².
What is tangental acceleration?This is the rate of change of tangental velocity of an object in circular motion.
To calculate the tangental acceleration, we use the formula below.
Formula:
a = αr............. Equation 1Where:
a = Tangental accelerationr = radius of the flywheelα = Angular acceleration of the flywheel.From the question,
Given:
r = 2.12 cm = 0.0212 mα = 16.2 rad/s²Subsitute these values into equation 1
a = (0.0212×16.2)a = 0.34 m/s²Hence, The tangental acceleration of the flywheel of radius 2.12 cm with a final angular velocity of 1820 rev/min and an angular acceleration of 16.2 rad/s is 0.34 m/s².
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Use the information in Question 1 to answer the following question. Determine the voltage across the capacitor after t = 2.94LaTeX: \tau
Use the information in Question 1 to answer the following question. Determine the time it takes the capacitor to reach 2.2 V.
( question 1:
4.90(1-exp(-2.00t)) + 0.10
determined the time constant as 0.5 )
Answers
The voltage across the capacitor after t = 2.94τ is approximately 4.74 V, the time it takes the capacitor to reach 2.2 V is approximately 0.407 seconds.
Using the given time constant of 0.5 ,
voltage equation 4.90(1- exp (-2.00t)) + 0.10, we can solve for the voltage across the capacitor after t = 2.94τ:
t = 2.94τ = 2.94 x 0.5 = 1.47 seconds
V(t=2.94τ) = 4.90( 1 - exp (-2.00 x 1.47)) + 0.10
≈ 4.74 V
To determine the time it takes the capacitor to reach 2.2 V, we can rearrange the voltage equation:
4.90(1-exp(-2.00t)) + 0.10 = 2.2
Solving for t:
t ≈ 0.407 seconds
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What is the average speed of a race car that moved 20 kilometers in 10 minutes?
Answers
Answer:21
Explanation:every body said
7. A particle carrying a charge of 10s C starts from rest in a uniform electric field whose intensity is 50 V/m. What
is the force on the particle? How much kinetic energy will the particle have after it has moved 5 m?
Ans:
5 x 10+ N, 2.5 x 10³ J
Answers
The force on the particle is equal to 5 ×10⁻⁴ N. The kinetic energy of the particle is 2.5 ×10⁻³ J.
What is an electric field?An electric field can be described as the field that surrounds electrically charged particles and acts as a force on all other charged particles in the field.
The Coulomb force on a charge q at any point is equal to the product of the charge and the electric field at that point
\({\displaystyle \mathbf {F} =q\mathbf {E} }\)
The SI unit of the electric field is a volt per meter (V/m).
Given, the magnitude of charge, q = 10⁻⁵ C
The electric field, E = 50 V/m
The force on the particle, F = 50 × 10⁻⁵ = 5 ×10⁻⁴ N.
Work, W = K.E. = F.S = 5 ×10⁻⁴ × 5 = 25 × 10⁻⁴ = 2.5 ×10⁻³ J
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