Answer:
The acceleration due to gravity of the planet is approximately 15.083 m/s²
Explanation:
The given information are;
The mass of the golf ball = 45.93 gram
The time it takes the golf ball to hit the ground 0.44 seconds
The height, s, from which the golf ball is dropped = 146 cm = 1.46 m
The equation of motion for the golf ball can be expressed as follows;
s = u·t + 1/2·a·t²
Where;
s = 1.46 m
u = The initial velocity of the golf ball = 0 m/s
a = The acceleration due to gravity of the planet
t = The time it takes the golf ball to hit the ground = 0.44 seconds
By substituting, we have;
1.46 = 0 × 0.44 + 1/2 × a × 0.44²
a = 1.46/(1/2 × 0.44²) ≈ 15.083 m/s²
The acceleration due to gravity of the planet = a ≈ 15.083 m/s².
I need help guysss , how can I get a Tutor on here
Answer:
it would say ask and see the tutor
Answer:
You type out your question and it should ask you where you want to post it. You choices are tutor or community. Choose community.
Explanation:
I just did it and it worked. Good luck
Describe your observations about the mid-ocean ridge. What did it look like? How do you think it got there?
(subject science)
Giving Brainliest
what is the number of significant digits in the measurement 10.005m?
Show that if the total linear momentum of a system of particles is zero, the angular momentum of the system is the same about all origins.
The angular momentum of a system is constant if the total linear momentum of the system is zero.
Is the angular momentum constant when the total linear momentum is zero?The main answer is that if the total linear momentum of a system of particles is zero, the angular momentum of the system remains constant regardless of the choice of origin. Angular momentum is a measure of rotational motion and depends on the distribution of mass and velocity within the system
When the total linear momentum is zero, it implies that the system's center of mass is stationary or moving at a constant velocity. In such cases, the system's angular momentum is independent of the origin chosen for calculations.
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One end of a string is fixed. An object attached to the other end moves on a horizontal plane with uniform circular motion of radius R and frequency f. The tension in the string is Fs . If both the radius and frequency are doubled, the tension is what
Answer:
If both the radius and frequency are doubled, then the tension is increased 8 times.
Explanation:
The radial acceleration (\(a_{r}\)), measured in meters per square second, experimented by the moving end of the string is determined by the following kinematic formula:
\(a_{r} = 4\pi^{2}\cdot f^{2}\cdot R\) (1)
Where:
\(f\) - Frequency, measured in hertz.
\(R\) - Radius of rotation, measured in meters.
From Second Newton's Law, the centripetal acceleration is due to the existence of tension (\(T\)), measured in newtons, through the string, then we derive the following model:
\(\Sigma F = T = m\cdot a_{r}\) (2)
Where \(m\) is the mass of the object, measured in kilograms.
By applying (1) in (2), we have the following formula:
\(T = 4\pi^{2}\cdot m\cdot f^{2}\cdot R\) (3)
From where we conclude that tension is directly proportional to the radius and the square of frequency. Then, if radius and frequency are doubled, then the ratio between tensions is:
\(\frac{T_{2}}{T_{1}} = \left(\frac{f_{2}}{f_{1}} \right)^{2}\cdot \left(\frac{R_{2}}{R_{1}} \right)\) (4)
\(\frac{T_{2}}{T_{1}} = 4\cdot 2\)
\(\frac{T_{2}}{T_{1}} = 8\)
If both the radius and frequency are doubled, then the tension is increased 8 times.
If both the radius and frequency are doubled, then the tension will be increased 8 times.
From kinematic formula:
\(\bold {a_r = 4\pi r^2 \times f^2 \times R^2}\) .............................. (1)
Where:
f - Frequency,
R - Radius of rotation,
From Second Newton's Law,
\(\bold {\sum F = T = m\times a_r }\) ......................... (2)
Where
m is the mass of the object,
From equation 1 and 2,
\(\bold {T = m\times 4\pi r^2 \times f^2 \times R^2}\\\) .................... (3)
From equation, tension is directly proportional to the radius and the square of frequency.
Then, if radius and frequency are doubled, then the ratio between tensions is:
\(\bold {\dfrac {T_2}{T_1} = (\dfrac {F_2}{F_1})^2 \times \dfrac {R_2}{R_1} = 4 \times 2 = 8 }\)
Therefore, If both the radius and frequency are doubled, then the tension will be increased 8 times.
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which was an idea use to distribute the theory of plate tectonics
Answer:
continental drift
Explanation:
Wegener proposed that the continents plowed through crust of ocean basins, which would explain why the outlines of many coastlines look like they fit together like a puzzle
please help me guys please please please please please please please please please please please please please
Answer:
1.F = 256 N
2.a = 8 m/s/s
By looking at the given information, you know force, and an acceleration. Therefore you have enough information to use the first formula.
F = ma
256 N = m * 8 m/s/s
m = 256 N/8 m/s/s
m = 32 Kg
if a car engine has a thermal efficiency of 50% and it does 500 j of work in one cycle, how much energy input does it require each cycle?
A automobile engine that performs 500 j of effort in one cycle and has a thermal performance of 50% needs 1000 j of energy for input each cycle.
Energy in Example: What is it?Energy can take on a variety of shapes. Energy can take many different forms, such as light, heat, mechanical, electrical, acoustic, chemical, nuclear, or atomic energy.
Can you break energy?Energy can only be converted or moved through one form to another; it cannot be created or destroyed. For instance, kinetic energy is produced from chemical energy.
Briefing:Efficiency = (E out / E in) × 100%
E in = (E out / 50) × 100
E in = (500 / 50) × 100
E in = 1000j
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Which is true about forensic testing? Forensic scientists must accurately interpret test results Evidence testing is no longer reliable All tests are fully automated Forensic scientists never make mistakes
Answer:
Forensic scientists must accurately interpret test results
Explanation:
Misinterpreting test results could mean someone being falsely accused of a crime which you would want to avoid.
People under going physical therapy after an injury often find it helpful to perform exercise in water? Why?
(No links please)
To a stationary observer, a man jogs east at 6 m/s and a woman jogs west at 2 m/s. from the man's frame of reference, what is the woman's velocity?
Answer: 8m/s west I think
To a stationary observer, a man jogs east at 6 m/s and a woman jogs west at 2 m/s. From the man's frame of reference, the woman's velocity is 4 m/s.
What is Velocity?
Velocity is a term that defines that how much a particle covered the distance in a particular time. Velocity is a vector quantity. It can be measured in m/s or cm/s.
How can we calculate the velocity?To calculate the velocity we are using the formula, Δv= v₁-v₂
Here we are given,
v₁= According to a stationary observer, velocity of a man=6 m/s East.
v₂=According to a stationary observer, velocity of a woman= 2 m/s West.
We have to calculate the woman's velocity, from the man's frame of reference= Δv
Now we put the values in the above equation, we get
Δv= v₁-v₂
Or, Δv= 6-2
Or, Δv=4m/s.
According to the calculation we can say that, From the man's frame of reference, the woman's velocity is 4 m/s.
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Suppose an 18-wheel truck and trailer has a mass of 30,000 kg and is traveling with a speed of 24.5 m/s . If the driver slams on his brakes and begins to skid, what would the stopping distance be if the coefficient of kinetic friction between the truck's tires and the pavement is 0.50 ?
Answer:
it's A
Explanation:
HELP THIS IS TIMED PLEASE OMG
Answer:
d) 40000 kgm/s
Explanation:
The formula for momentum is p = m*v
so p = 100*400
p = 40000 kgm/s
UVA and UVB rays can cause skin damage and skin cancer. True False
Answer:
true
Explanation:
they can cause skin damage
The following figure is from a student’s experiment to find the centre of mass of an irregular shape.
a. Explain how the student used the following equipment to find the centre of mass:
• String
• A small mass (e.g. adhesive putty)
• A stand
• A pencil
• A straight-edge (e.g. ruler).
Include a diagram of the experimental set-up as part of your explanation.
To find the center of mass of an irregular shape using
String- for hanging at the center
• A small mass - hung from the string
• A stand-holding up the string
• A pencil pinpointing the center
• A straight-edge- Identify the middle
What is the center of mass?Generally, a point indicates the mean location of the matter in a body or system.
In conclusion, the center of mass also indicates a point at which the body is most balanced under gravity.
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1 A grandfather clock uses energy stored in raised weights. The weights transfer energy to the clock mechanism as they fall. One clock has a 4.5 kg weight that supplies energy to the chimes (which play a few notes every 15 minutes), and two 3.5 kg weights that power the clock and the mechanism that strikes the hours.
For all questions on this sheet,
use g = 10 N/kg
a Calculate how much energy is stored when all three of these weights are raised by 70 cm. b How far does the 4.5 kg weight have to be lifted to store 45 J of energy?
2 The water tank in a house can hold 200 litres of water. The mass of 1 litre of water is 1 kg. The tank is 2 m above the bathroom taps and 5 m above the kitchen taps. The kitchen taps are 1 m above the floor.
a
Calculate the gravitational potential energy (GPE stored in the water in the tank when it is full. State any assumptions made in your answer.
b Calculate the speed at which the water would come out of the bathroom taps and kitchen taps. You
may assume that no energy is transferred due to friction in the pipes.
3 The Victoria Falls in Africa is one of the world's largest waterfalls. Just over 1000 m° of water pass over the falls every second and fall approximately 100 m. 1 m3 of water has a mass of 1000 kg. a What mass of water goes over the falls every second? Give your answer in standard form.
b
Calculate the GPE of 1 kg of water at the top of the falls.
c If all the GPE stored in 1 kg of water is transferred to kinetic energy, calculate the speed of the water as
it reaches the bottom.
d Suggest why the water will not be falling as fast as your answer to part c suggests. e What is the total energy transferred per second as the GP stored in the water falling in one second is
transferred to other energy stores.
f Suggest the ways in which this energy is finally stored.
4 A post driver is used to drive fence posts into the ground. It is a hollow tube with a closed top, and handles on the side. A person fits the driver over a fence post, then lifts it up and lets it drop.
post driver
50 cm
a A post driver has a mass of 10 kg. Calculate the change in GPE stored when the post driver is lifted by 50 cm above the post, as shown in the diagram.
b
Calculate the speed of the driver when the end hits the post.
C
Explain how much extra energy is stored if the post driver is
fence post
lifted by 1 metre instead of only 50 cm.
d Calculate the speed of the post driver after it falls for 1 m. e A new design of post driver has a mass of 15 kg. Suggest one advantage and one disadvantage of this new design.
Extra challenge
5 F The post driver in question 4a stops in
0.5 seconds when it hits the fence post.
a Calculate the force needed to bring the post driver to a stop. (Hint: use your answer to 4b.)
The momentum of a moving object is the product of its mass and its velocity. The force needed to stop a moving object depends on how fast its momentum changes.
force = change in momentum
=
mv - mu
time
t
b What provides this force?
c Explain how your answer might be different it the post were being sunk into very soft ground,
F = force (N)
u = initial velocity (m/s)
te time (s)
m = mass (kg)
v = final velocity (m/s)
1a) The total energy stored when all three weights are raised by 70 cm is 80.5 J.
1b) The height of the tank is 2 m.
2b) The potential energy is converted into kinetic energy when the water flows out of the taps 6.32 m/s.
3a) The mass of water that goes over the falls every second is 1 x 10⁶ kg.
3b) The gravitational potential energy of 1 kg of water at the top of the falls 1000 J.
3c) The speed of the water as it reaches the bottom if all the GPE stored in 1 kg of water is transferred to kinetic energy is 44.72 m/s.
3d) The water will not be falling as fast as the speed calculated in part c suggests because of the presence of air resistance and the fact that the water falls through a medium (air) which offers resistance to its motion.
3e) The energy transferred when the GPE stored in the water falling in one second is transferred to other energy stores is finally stored in thermal energy stores due to the heat generated by the water as it hits the bottom.
1a) To calculate the amount of energy stored in the three weights, we use the formula given below:
E = mgh
Where,E = Energy (Joules)
m = Mass (kg)
g = Gravity (10 N/kg)
h = Height (m)
For the 4.5 kg weight:
E = 4.5 x 10 x 0.7 = 31.5 J
For each of the 3.5 kg weight:
E = 3.5 x 10 x 0.7 = 24.5 J
Thus, the total energy stored when all three weights are raised by 70 cm is:
31.5 J + 24.5 J + 24.5 J = 80.5 J
1b) To calculate how far the 4.5 kg weight must be lifted to store 45 J of energy, we use the formula:
E = mghh = E/mg = 45 / (4.5 x 10) = 1 m2a)
To calculate the gravitational potential energy stored in the water in the tank when it is full, we use the formula given below:
E = mgh
Where,E = Energy (Joules)
m = Mass (kg)
g = Gravity (10 N/kg)
h = Height (m)
The mass of 1 litre of water is 1 kg and the tank can hold 200 litres of water. Therefore, the total mass of water in the tank is:
Mass = 200 kg
The height of the tank is 2 m.
Therefore, the gravitational potential energy stored in the water in the tank is:
E = mgh = 200 x 10 x 2 = 4000 J
Assumptions made in the answer:
We have assumed that the tank is full.
2b) To calculate the speed at which the water would come out of the bathroom and kitchen taps, we use the formula given below:
PE = KEPE = mghKE = 1/2mv²
Where,PE = Potential Energy (Joules)
KE = Kinetic Energy (Joules)
m = Mass (kg)
g = Gravity (10 N/kg)
h = Height (m)
v = Velocity (m/s)
Assuming that the potential energy of the water in the tank is converted into kinetic energy when the water flows out of the taps, the potential energy stored in the water in the tank is given by:
PE = mgh = 200 x 10 x 2 = 4000 J
The potential energy is converted into kinetic energy when the water flows out of the taps.
Therefore, KE = 1/2mv²v² = 2KE/mv² = 2(4000)/200 = 40 m²/s²v = √(40) = 6.32 m/s (speed of the water coming out of the taps)
3a) To calculate the mass of water that goes over the falls every second, we use the formula given below:
Mass = Volume x Density
Where,Volume = 1000 m³/s, Density = 1000 kg/m³, Mass = 1000 x 1000 = 1000000 kg = 1 x 10⁶ kg
3b) To calculate the gravitational potential energy of 1 kg of water at the top of the falls, we use the formula:
E = mgh
Where,m = 1 kg, g = 10 N/kg, h = 100 m, E = 1 x 10 x 100 = 1000 J
3c) To calculate the speed of the water as it reaches the bottom if all the GPE stored in 1 kg of water is transferred to kinetic energy, we use the formula given below:
PE = KEP
E = mgh
KE = 1/2mv²
Where,PE = Potential Energy (Joules)
KE = Kinetic Energy (Joules)
m = Mass (kg)
g = Gravity (10 N/kg)
h = Height (m)
v = Velocity (m/s)
Assuming that all the potential energy is converted into kinetic energy when the water reaches the bottom,
PE = KEKE = mghv² = 2mghv² = 2(1)(10)(100)v² = 2000v = √(2000) = 44.72 m/s
3d) The water will not be falling as fast as the speed calculated in part c suggests because of the presence of air resistance and the fact that the water falls through a medium (air) which offers resistance to its motion.
3e) To calculate the total energy transferred per second as the GPE stored in the water falling in one second is transferred to other energy stores, we use the formula given below:
Power = Energy / Time
Where,Power = 1 x 10⁶ x 10 x 100 = 1 x 10⁹ W = 1 GW (assuming that 1 m³ of water falls every second)3f)
The energy transferred when the GPE stored in the water falling in one second is transferred to other energy stores is finally stored in thermal energy stores due to the heat generated by the water as it hits the bottom.
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New attempt is in progress. Some of the new entries may impact the last attempt grading. Incorrect. The hammer throw is a track-and-field event in which a 7.30-kg ball (the hammer) is whirled around in a circle several times and released. It then moves upward on the familiar curved path of projectile motion and eventually returns to the ground some distance away. The world record for the horizontal distance is 86.75 m, achieved in 1986 by Yuriy Sedykh. Ignore air resistance and the fact that the ball was released above the ground rather than at ground level. Furthermore, assume that the ball is whirled around a circle that has a radius of 2.22 m and that its velocity at the instant of release is directed 47.9° above the horizontal. Find the magnitude of the centripetal force acting on the ball just prior to the moment of release.
This question involves the concepts of centripetal force, range of projectile and projectile motion.
The magnitude of centripetal force is "2812.8 N".
First, we will find the velocity of the ball by using the formula of the range of the projectile.
\(R = \frac{v^2Sin2\theta}{g}\)
where,
R = range of projectile = 86.75 m
v = speed = ?
θ = launch angle = 47.9°
g = acceleration due to gravity = 9.81 m/s²
Therefore,
\(86.75\ m = \frac{(v)^2Sin(2)(47.9^o)}{9.81\ m/s^2}\\\\v = \sqrt{\frac{(86.75\ m)(9.81\ m/s^2)}{Sin95.8^o}}\)
v = 29.25 m/s
Now, we will use the formula to find out the centripetal force:
\(F_c = \frac{mv^2}{r}\)
where,
\(F_c\) = Centripetal Force = ?
m = mass of the ball = 7.3 kg
v = speed = 29.25 m/s
r = radius = 2.22 m
Therefore,
\(F_c = \frac{(7.3\ kg)(29.25\ m/s)^2}{2.22\ m}\)
Fc = 2812.8 N = 2.812 KN
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If a 5 kg cart is pulled with a net force of 20 Newtons. What is the magnitude, in m/s2, of the acceleration?
Answer:
F=ma
a=F/m=20/5=4 m/s^2
the first successful attempt to establish the size of earth is credited to
The first successful attempt to establish the size of Earth is credited to the ancient Greek mathematician and astronomer Eratosthenes.
Eratosthenes noticed that at noon on the summer solstice, the sun was directly overhead in Syene, a city in southern Egypt, casting no shadow. However, in Alexandria, which was located about 500 miles north of Syene, the sun cast a shadow of approximately 7.2 degrees. Eratosthenes realized that the difference in the shadow length was caused by the curvature of the Earth's surface, and he used his knowledge of geometry to calculate the circumference of the Earth.
Eratosthenes' estimate was remarkably accurate, coming within about 2% of the Earth's actual circumference. His achievement laid the groundwork for future studies of Earth's size and shape and cemented his legacy as one of the greatest scientists of antiquity.
So,the first successful attempt to establish the size of Earth is credited to the ancient Greek mathematician and astronomer Eratosthenes. He was born in Cyrene, a Greek colony in present-day Libya, in 276 BCE and was the chief librarian at the Library of Alexandria in Egypt.
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microwave transmission systems are used for _____ volume, _____ distance, _____ communications.
"Microwave transmission systems are used for high volume, long distance, line-of-sight communications."
Microwave is a line-of-sight wireless communication technology that uses high frequency beams of radio waves to provide high speed wireless connections that can send and receive voice, video, and data information.
Due to their small wavelength and ability to be focused into narrow beams that may be targeted directly at the receiving antenna, microwave links are frequently employed for point-to-point communications. As opposed to lower frequency radio waves, which interfere with one other, this enables neighbouring microwave equipment to operate on the same frequencies.
Another benefit is that the microwave band has a very high information-carrying capacity due to its high frequency; its bandwidth is 30 times greater than that of the radio spectrum below it.
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Chich expression correctly describes force using Sl units
O A. 1 N = 1 kg-m/s2
B. 1 N = 1 kg.m/s
C. 1 J = 1 kg-m/s?
D. 1 J = 1 kg m/s
Answer:1 N = 1 kg·m/s2
Explanation:
A wave has a wavelength of 2 meters and a frequency of 1.5 hz. What is its speed
Answer:
3m/s is the answer.
Explanation:
f = c/λ
f = frequency
c = speed (m/s)
λ = wavelength
f = c/λ
1.5 = c/2
c = 3m/s
Consider the pseudo code below. Which is the output when input is "NCUCSIE"? (A) NCUCSIENCUCSIE (B) EISCUCN (C) NCUCSIE (D) EISCUCNEISCUCN
Consider the pseudo code below, the output when input is "NCUCSIE" is (A) NCUCSIENCUCSIE.
The given pseudo code has a loop that iterates through each character of the given input and constructs a new string by adding each character twice. The output will therefore be a string that has each character repeated twice. For the given input "NCUCSIE", the output will be "NCUCSIENCUCSIE". Here is a step-by-step explanation of how the code works: Take input from the user. In this case, the input is "NCUCSIE".
Initialize an empty string called "result", literate over each character of the input string one by one. For each character, append it to the result string twice using the concatenation operator "+=". When all characters have been processed, the result string will contain each character repeated twice, output the result string. The correct answer for the given question is option (A) NCUCSIENCUCSIE.
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A block slides along a rough table and is brought to rest after travelling a distance of 2.7m. The frictional force is assumed constant at 3.8 N. Find the work done by the frictional force.
Answer:
The workdone by the Frictional force is 10. 26 Joules.
Explanation:
Parameters: Frictional force = 3.8 N
Distance = 2.7m
Workdone = ? Joules
Workdone = Frictional force × Distance travelled
= 3. 8 × 2. 7
= 10.26 Joules.
The workdone by the frictional force when brought to rest after travelling a distance of 2. 7m is 10. 26 Joules.
true/false. The gravitational force between the two objects is weak because they are 1 m apart. No gravitational force exists between the two objects because their masses are small.
The given statement "The gravitational force between the two objects is weak because they are 1 m apart. No gravitational force exists between the two objects because their masses are small." is False.
The gravitational force between the two objects is not weak because they are 1 m apart. The strength of the gravitational force depends on the masses of the objects and the distance between them.
Additionally, it is not true that no gravitational force exists between the two objects because their masses are small. Every object in the universe exerts a gravitational force on every other object, regardless of their masses. However, the strength of the gravitational force will be weaker if the masses are smaller.
So. The gravitational force between the two objects is weak because they are 1 m apart. No gravitational force exists between the two objects because their masses are small is False.
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Which body system is responsible for bringing the oxygen an organism will need to conduct cellular respiration?
Answer:
The respiratory system is responsible for bringing the oxygen an organism will need to conduct cellular respiration. The respiratory system includes the lungs and other organs involved in breathing, such as:
the trachea,bronchi,and alveoli.When we inhale, oxygen from the air enters the lungs and diffuses into the bloodstream, where it is transported to the body's cells. Inside the cells, oxygen is used in the process of cellular respiration to produce energy in the form of ATP.
Hope that helps! Good luck! :)
9) What is the temperature of 5 moles of nitrogen at 1 atm in a 2 liter container?*
- 4.88 K
- 0.0328 K
- 0.41 K.
- 0.0164 K
Answer:
4.88 K.
Explanation:
From the question given above, the following data were obtained:
Number of mole (n) = 5 moles
Pressure (P) = 1 atm
Volume (V) = 2 L
Gas constant (R) = 0.082 atm.L/Kmol
Temperature (T) =?
The temperature of the gas can be obtained by using the ideal gas equation as illustrated below:
PV = nRT
1 × 2 = 5 × 0.082 × T
2 = 0.41 × T
Divide both side by 0.41
T = 2 / 0.41
T = 4.88 K
Therefore, the temperature of the gas is 4.88 K.
Describe the relationship between speed and thinking distance. Physics Paper 2
While there is no direct relationship between speed and thinking distance, higher speeds can result in longer thinking distances due to the increased reaction time needed by the driver.
The relationship between speed and thinking distance is not a direct one, as thinking distance is primarily influenced by the driver's reaction time rather than the actual speed of the vehicle. Thinking distance refers to the distance traveled by a vehicle during the driver's reaction time after perceiving a hazard.
However, there is an indirect relationship between speed and thinking distance in the sense that higher speeds generally result in longer thinking distances. When a vehicle is traveling at a higher speed, the driver needs more time to process information, make decisions, and react to potential hazards. Therefore, a higher speed can lead to a longer thinking distance.
It is important to note that thinking distance is just one component of the total stopping distance, which also includes braking distance. Braking distance is directly influenced by the speed of the vehicle. Higher speeds require longer braking distances to bring the vehicle to a stop.
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While in a hot air balloon, your altimeter breaks and you cannot easily determine your height. You measure your angle of depression to the nearby lake to be 54
∘
. After flying 100 feet towards the landmark, you measure again and the new angle of depression is 61
∘
. Find the height of the balloon.
To find the height of the balloon, we can use trigonometry and the concept of similar triangles. Let's denote the height of the balloon as "h" and the horizontal distance from the balloon to the landmark as "x".
We have two right triangles: one before flying 100 feet and another after flying 100 feet. In both triangles, the angle of depression to the lake is given as 54 degrees and 61 degrees, respectively.
Using the tangent function, we can set up the following equations:
Before flying:
tan(54°) = h / x
After flying:
tan(61°) = h / (x + 100)
Now we can solve these equations to find the value of "h". Let's solve for "x" in the first equation:
x = h / tan(54°)
Substituting this value into the second equation, we have:
tan(61°) = h / ((h / tan(54°)) + 100)
Now we can solve this equation to find the value of "h".
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how is an object's motion related to speed, velocity, and acceleration?
Answer:
Speed describes only how fast an object is moving, whereas velocity gives both the speed and direction of the object’s motion being a vector quantity. The standard unit to measure velocity is meter per second (m/s or ms-1). For example, “10 meters per second” is scalar and “10 meters per second West” is vector. Acceleration