Activity 3:
Direction: Read the sample weather bulletin.
Weather Bulletin: Tropical Cyclone Typhoon Rolly (GONI)
Sunday, 1 November, 2020 at 4:00 PM (DOST PAG-ASA 2020)
Location of Center
50 km South Southwest of Tayabas, Quezon
Coordinates
13. 6°N, 121. 40 E
Strength of the Winds
Maximum sustained winds of 165 km/h near
the center and gustiness of up to 230 km/h.
Movernent
Moving westward at 25 km/h
Forecast positions
(24 hours) Afternoon of November 2: 300 km
West of Iba, Zambales
15. 1° N, 117. 20 E
(48 hours) Afternoon of November 3: 665 km
West of Iba, Zambales
Outside PAR (15° N, 113. 8°E)
(72 hours) Afternoon of November 4: 935 km
West of Central Luzon
Outside PAR (14. 79 N, 111. 6° E)
Questions:
3.
What is the speed of the typhoon winds?
What is the velocity of the typhoon?
How does speed differ from velocity?
How important is knowing the velocity in determining the weather
forecast for the next hours?
4
Let Us Reflect​

Answer:

me to I have the same question

Explanation:

She can put an ice cube on each cup to see which cube melts faster.

First, we know two things:

We can also assume, because of the second thing, that all ice cubes have the same temperature.

Then, one way to know which cup has more temperature is to put one ice cube on each cup, then measure the time it takes for the cube to melt completely.

When you put the ice cube on the cup, it will start to "drain" the heat energy from the liquid. If the liquid has more temperature, more energy can the cube drain, thus faster it will change to the liquid phase.

Then with a single cube on each cup you will have enough evidence to determine which cup has more temperature.

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Answer:

98

Explanation:

A. ME = PE + KE

ME = mechanical energy

PE = potential energy

KE = kinetic energy

B. ME = 800 + 250

C. 1050 J

Answer:

Explanation:

The density of a substance can be found by using the formula

\(density = \frac{mass}{volume} \\\)

From the question

mass = 30 g

volume = 30 mL

We have

\(density = \frac{30}{30} = 1 \\ \)

We have the final answer as

Hope this helps you

Answer:

the matter is made into paper

Explanation:

Answer:

No. 1 is the correct answer.

Explanation:

The natural resources which deplets after long and continious use and are unable to be recreated/ takes a lot of time to renew are non renewable resources

Answer:

25.021 sec

Explanation:

v=d/t

-2.33= - 58.3/t

t= - 58.3/-2.33

t=25.021 sec

The displacement of the 2-kg mass as a function of time can be determined using the equation of motion for simple harmonic motion ,where the displacement x would be x0.

Using the equation of motion for simple harmonic motion :
x(t) = A * cos(ωt + φ)
Where:
x(t) is the displacement of the mass at time t
A is the amplitude of the motion
ω is the angular frequency
φ is the phase angle
Without additional information such as the spring constant or any initial conditions, we cannot determine the specific values of A, ω, and φ.
At time t = 30 sec, we can calculate the displacement x if we know the initial conditions. If the mass is released from rest at a distance x0 to the right of the equilibrium position, we can assume that the initial displacement is x0.
Therefore, at t = 30 sec, the displacement x would be x0 since the mass would still be at the same distance from the equilibrium position as it was initially.

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Answer:

7.5 × 10^-11 m

Explanation:

Hope this helps !

Answer: C (Irradiance)

Explanation:

It is a fact

The term for sunlight intensity is called "irradiance." (C)

Sunlight intensity, or irradiance, is a measure of the amount of solar energy falling on a surface per unit of time, typically expressed in watts per square meter (W/m²). It is an important factor to consider in various fields, such as solar energy production, agriculture, and climate studies.

Irradiance can vary depending on factors such as time of day, geographic location, and atmospheric conditions.

Unlike glow, which refers to a gentle light, or luminosity, which describes the amount of light emitted by an object, irradiance specifically focuses on the power of sunlight reaching a given surface.

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In conclusion, the acceleration due to gravity is a crucial aspect of physics that enables us to experience weight on Earth. It has a value of approximately 9.81 m/s² near sea level. One of the ways to estimate it is by using a pendulum.

The acceleration due to gravity refers to the acceleration an object experiences as a result of the force of gravity. It is one of the most fundamental physical concepts in existence. The acceleration due to gravity is generally represented as “g,” and it varies depending on the planet or moon in question as well as the object’s distance from the object in question. When on Earth, the acceleration due to gravity is roughly 9.81 m/s² near sea level. This acceleration due to gravity is what enables us to stay on the planet and experience weight when we stand or sit on the ground. The value of the acceleration due to gravity may be determined by using a number of methods. One common approach is to use a pendulum. The formula for determining the acceleration due to gravity is g = (4π²L)/T², where L is the length of the pendulum and T is the time it takes for one full swing. Using this equation, it is possible to estimate the acceleration due to gravity for any planet or moon where there is a pendulum.

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Answer:

630 km.

Explanation:

To obtain the total distance travelled by David, we shall calculate the distance travelled in each, then sum them together.

Case 1:

Speed 1 (S₁) = 65 km / hour

Time 1 (t₁) = 6 hours

Distance 1 (d₁) =?

Speed = Distance /time

S₁ = d₁ / t₁

65 = d₁ / 6

Cross multiply

d₁ = 65 × 6

d₁ = 390 Km

Case 2:

Speed 2 (S₂) = 80 km / hour

Time 2 (t₂ ) = 3 hours

Distance 2 (d₂) =?

Speed = Distance /time

S₂ = d₂ / t₂

80 = d₂ / 3

Cross multiply

d₂ = 80 × 3

d₂ = 240 Km

Finally, we obtained the total distance travelled by David as follow

Distance 1 (d₁) = 390 Km

Distance 2 (d₂) = 240 Km

Total Distance travelled (dₜ) =?

Total distance = distance 1 + distance 2

dₜ = d₁ + d₂

dₜ = 390 + 240

dₜ = 630 km

Therefore, the total distance travelled by David is 630 km

After 0.30 moles of gas are released, the volume of the balloon will be 1.85 liters.

To determine the volume of the balloon after 0.30 moles of gas are released, we can use the ideal gas law equation in the form of (n1/V1) = (n2/V2), where n1 and V1 represent the initial moles and volume, and n2 and V2 represent the final moles and volume.

Initially, we have 4.00 moles of gas in a 2.00 L volume balloon. After releasing 0.30 moles, we have 4.00 - 0.30 = 3.70 moles remaining in the balloon. With pressure and temperature held constant, we can now find the final volume (V2):

(4.00 moles / 2.00 L) = (3.70 moles / V2)

To solve for V2, we can rearrange the equation:

V2 = (3.70 moles * 2.00 L) / 4.00 moles

V2 = 1.85 L

Therefore, after 0.30 moles of gas are released, the volume of the balloon will be 1.85 liters.

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The net force is the hypotenuse of the triangle and the value of the net force is 14.14 N.

The net force is the force that has the same effect in magnitude and direction as two  or more forces acting together. We know that force is a vector quantity thus it does have both magnitude and direction.

Since force is a vector, we need to look at the direction of the forces in order to find out what the direction of the net force would have to be. A close look at the image would show us that the net force is the hypotenuse of the triangle.

The value of the net force is;

R = √(10)^2 + (10)^2

R = 14.14 N

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The energy per photon associated with a frequency of 1260 kHz is 2.10×10^-25 J.

To calculate the energy per photon, we can use the equation: E = hf, where E represents the energy, h is the Planck's constant (6.62607015 × 10^-34 J·s), and f is the frequency of the photon. Given that the frequency is 1260 kHz, we need to convert it to hertz (Hz) by multiplying it by 10^3:

Frequency = 1260 kHz × 10^3 = 1.26 × 10^6 Hz

Now, we can substitute the values into the equation:

E = (6.62607015 × 10^-34 J·s) × (1.26 × 10^6 Hz)

E = 8.33929859 × 10^-28 J

The answer is given in scientific notation as 8.34 × 10^-28 J. However, the question specifically asks for the answer in the format of 0.00×10^0. To achieve this, we can multiply the result by 10^3 and adjust the exponent accordingly:

E = (8.33929859 × 10^-28 J) × (10^3)

E = 8.33929859 × 10^-25 J

Thus, the energy per photon associated with a frequency of 1260 kHz is 2.10×10^-25 J.

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All objects do have gravity, but the gravitational force between two objects depends on their masses and the distance between them. The force of gravity between two objects decreases rapidly as the distance between them increases.

It's also worth noting that objects need to be very massive and very close together for the gravitational force to become noticeable. For example, two people standing next to each other have a very small gravitational force between them, while two planets orbiting each other have a much stronger gravitational force.

In summary, while all objects have gravity, the gravitational force between objects depends on their masses and the distance between them, and the force of gravity between us and nearby objects is usually too small to have a noticeable effect. The force of gravity between us and the Earth is what keeps us in place and gives us weight.

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\(\boxed{\sf E_P=mgh}\)

\(\\ \sf\longmapsto E_P=25(10)(10)\)

\(\\ \sf\longmapsto E_P=25(100)\)

\(\\ \sf\longmapsto E_P=2500J\)

In 1912 Wertheimer discovered the phi phenomenon, an optical illusion in which stationary objects shown in rapid succession, transcending the threshold at which they can be perceived separately, appear to move.

When two neighbouring optical stimuli are presented in alternation with a relatively high frequency, an apparent motion is seen that is known as the phi phenomenon. At higher frequencies, beta movement is visible, but the stimuli themselves don't seem to move.

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The expression for the energy stored (E) in a stretched wire of original length (L), cross-sectional area (A), tension (T), and Young's modulus (Y) is given by E = Y * e * ln(L) * A

The work done to stretch the wire can be calculated by integrating the force applied over the displacement. In this case, the force applied is the tension (T) in the wire, and the displacement is the change in length (ΔL) from the original length (L) to the stretched length (L + ΔL).

The tension in the wire is given by Hooke's law, which states that the tension is proportional to the extension of the wire:

T = Y * (ΔL / L)

where Y is the Young's modulus of the material of the wire.

Now, let's calculate the work done to stretch the wire:

dW = T * dL

Integrating this expression from L to L + ΔL:

W = ∫ T * dL = ∫ Y * (ΔL / L) * dL

W = Y * ΔL * ∫ (dL / L)

W = Y * ΔL * ln(L) + C

Here, C is the constant of integration. Since the energy stored in the wire is zero when it is unstretched (ΔL = 0), we can set C = 0.

Finally, the expression for the energy stored in the wire (E) is:

E = W = Y * ΔL * ln(L)

or, if we substitute the cross-sectional area (A) and strain (e) of the wire, where e = ΔL / L:

E = Y * e * ln(L) * A

Thus, the expression for the energy stored (E) in a stretched wire of original length (L), cross-sectional area (A), tension (T), and Young's modulus (Y) is given by:

E = Y * e * ln(L) * A

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The gallons of water in the cloud is 405812 gallons and the water weight in tons is 542.433 tons.

Volume = length × width × height

length = 8 km

width = 8 km

height = 12 km

Volume (V) = l×b×h

                  = 12×8×8

                 = 768 km (1km = 1000 m)

                = 768000000 m³

The volume of the cloud = 768000 m³

Each cubic meter of the cloud has water droplets = 0.5 cm³

Total water content in the cloud = Volume / o.5

                                                     = 768000000/ 0.5

                                                     = 1,536,000,000 cm³

1 gallons = 3785 cm³

Total water content = 1,536,000,000

No of gallons = 1,536,000,000 / 3785

                       = 405,812

The total no of gallons is 405,812.

The total tons of water in the cloud is 542.4 tons.

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For a fixed sample size, the lower we set the significance level (usually denoted by alpha), the lower is the probability of committing a Type I error (rejecting a true null hypothesis). However, lowering alpha also increases the probability of committing a Type II error (failing to reject a false null hypothesis). This is because reducing alpha increases the threshold for rejecting the null hypothesis, making it harder to detect a significant difference.

Random error, on the other hand, is not affected by the significance level or sample size. It is the variability inherent in any measurement or observation due to factors such as measurement error, natural variability, or chance.

The p-value is a statistical measure that represents the probability of obtaining results as extreme or more extreme than the observed results, assuming that the null hypothesis is true. The p-value is directly related to the significance level (alpha), with smaller p-values indicating stronger evidence against the null hypothesis. Therefore, lowering alpha also decreases the p-value.

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Answer:

C

Explanation:towards Erin

The rope will move towards Erin because, the force between them is unbalanced and the more force is exerted by Erin. Hence, the displacement will occur on the greater force side.

Force is an external agent acting on a body to change its motion or to deform it. The net force acting on the body depends on the direction and magnitude of all  the force acting on it.

If two equal forces acts on the body from the same side they add up together and the net force is their sum. If the forces are acting from the opposite sides, they will cancel each other and is said to be balanced.

Here, two forces from the side is un balanced by a force from the opposite side. Hence, the greater force from Erin will make the rope displaced towards her side. Thus, option C is correct.

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Answer:

149 N

Explanation:

We can start by resolving the forces acting on the chair in the vertical direction:

N - mg = 0

where N is the normal force exerted by the floor on the chair, m is the mass of the chair, and g is the acceleration due to gravity.

Since the chair is not accelerating vertically, we know that the sum of the forces in the vertical direction is zero.

Now, let's resolve the forces acting on the chair in the horizontal direction. We'll use the force you applied and the force of friction between the chair and the floor:

F - f = ma

where a is the acceleration of the chair, and f is the force of friction.

The force of friction can be calculated as:

f = μN

where μ is the coefficient of friction between the chair and the floor.

We don't know the coefficient of friction or the acceleration of the chair, so we can't solve this equation directly. However, we can use the fact that the chair is sliding along the floor, which tells us that the force of friction is equal and opposite to the force you applied:

f = F sinθ = 39.0 N * sin(36.0°) ≈ 23.5 N

Therefore, we can substitute this value for f in the horizontal force equation:

F - f = ma

39.0 N * cos(36.0°) - 23.5 N = ma

Solving for a, we get:

a ≈ 0.34 m/s^2

Now we can go back to the vertical force equation and solve for the normal force:

N - mg = 0

N = mg = (110 N) + (m chair)(a)

We don't know the mass of the chair, but we can use the acceleration we just calculated to find it:

a = F/(m chair)

m chair = F/a ≈ 115 kg

Substituting this value for the mass of the chair, we get:

N = mg = (110 N) + (115 kg)(0.34 m/s^2)

N ≈ 149 N

Therefore, the normal force that the floor exerts on the chair is approximately 149 N.

Only old stars are found in the halo is true about the stellar populations in the Galaxy. Option C is the correct answer.

According to Baade, yellow stars predominated close to the galactic bulge and in globular star clusters, whereas bluer stars were closely linked to the spiral arms. Population I and population II were the two primary divisions, while population III, a more recent hypothetical divide, was introduced in 1978. Option C is the correct answer.

With regard to each population type's unique observed star spectra, considerable variations were discovered. These were subsequently revealed to be of great significance and may have been connected to stellar age, observed kinematics, star formation, and even galaxy development in both spiral and elliptical galaxies. These three basic population classifications distinguished stars according to their metallicity or chemical make-up.

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The stellar populations in the Galaxy can be categorized into three main groups: the disk, the bulge, and the halo. The disk population is where most of the star formation occurs, while the bulge and halo populations consist of stars of different ages and compositions.

The stellar populations in the Galaxy can be categorized into three main groups: the disk, the bulge, and the halo.

Overall, the disk population is where most of the star formation occurs, while the bulge and halo populations consist of stars of different ages and compositions.

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Answer:

Renewable Energy

Examples of Renewable energy are :

Solar

Tidal

Wind etc.

Explanation:

To determine the amount of work done by the tension in the ropes as the child swings from the initial position to the bottom, we would need more detailed information such as the weight of the child, the length of the ropes, and the angle at which the child swings. Without this information, it is impossible to provide a specific answer.

You need to follow these steps:

1. Identify the initial position and the bottom position of the child on the swing.
2. Calculate the displacement of the child during the swing (change in vertical height from the initial position to the bottom position).
3. Determine the tension force in the ropes. This force is equal to the weight of the child (mass × acceleration due to gravity) when the swing is at its lowest point.
4. Calculate the angle between the tension force and the displacement vector.
5. Calculate the work done by the tension in the ropes using the formula: Work = Force × Displacement × cos(angle)

Keep in mind that if the angle between the tension force and the displacement vector is 90 degrees, the work done by the tension in the ropes will be zero, as the tension force is acting perpendicular to the displacement of the child.

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Answer:

544

Explanation: