According to a report from the Centers for Disease Control and Prevention, the number of babies born in the United States in 2020 fell 4% to about 3.6 million.

Answers

Answer 1

The decline in the number of babies born can be attributed to the Covid-19 pandemic but also to general demographic trends.

How can this change be explained?

The decline in the number of babies born in the United States in 2020 can be attributed to several factors:

COVID-19 Pandemic:  Due to uncertainty and changes in many atmospheres including job losses many people reconsider having a baby during this time.Demographic trend: In the last decades, fewer people have children due to more education, and changes in ideas about motherhood, among others.

Note: This question is incomplete; here is the missing information:

How can this decline be explained?

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Related Questions

n which generation, sporophyte(2N) or gametophyte(N) do the following belong.a)Spore: _________b)Calyptra:________c) Egg: ___________d)Protonema:______e)Aronium:____f) Paraphysis:______g)Zygote:_________h)Capsule:________i)Seta:

Answers

Answer and explanation:

a) Spore - N:  The adult diploid vegetable (2n) produces spores (n) by meiosis, which is why we call it sporophyte (spore producer).

b) Calyptra - 2N: Calyptra is an enlarged archegonian belly that protects the capsule containing the embryonic sporophyte. Calyptra are normally lost before the spores are released from the capsule.

c) Egg - N: Eggs are structures present in the ovary of plants, that implies that they are part of the gametophyte.

d) Protonema - 2N: The protonema is a cell body that gives rise to the gametophyte, in other words, the protonema is a young gametophyte, and like the gametophyte, it has 2N ploidy

e)  Arquegonium - 2N: Female sexual organ (gametangium), bottle-shaped, characteristic of bryophytes, pteridophytes and most gymnosperms, as part of the reproductive structure, its ploidy is 2N

f)  Paraphysis - N: Sterile hyphae of the fruiting body (fertile spore-bearing layer) of several ascomycete fungi. They are part of the gametophyte (surrounding the antheridia and archegonium).

g) Zygote - N:  From the fertilization of the gametes, the diploid zygote (2n) is formed, which will develop forming the adult individual. Meiosis in this cycle is known as final or gametic meiosis.

h) Capsule - 2N: It is in the capsule that the transition from the mother cell (2N) to the spore cell (N) occurs. The capsule is protected by calyptra (2N)

i) Seta - 2N: Setae are primarily part of the sporophyte, but can appear in some specific gametophyte phases (in parasitism). They support the capsule and assist in nutrient uptake.

The cells that form from the first few divisions of a fertilized egg cell can
develop into any cell in the human body or the placenta. What kind of stem
cells are these?
O A. Multipotent stem cells
B. Pluripotent stem cells
C. Totipotent stem cells
D. Unipotent stem cells

Answers

Answer:

The correct answer is D

Explanation:

The cells that form from the first few divisions of a fertilized egg cell can develop into any cell in the human body or the placenta is pluripotent cell. The correct option is B.

What is a stem cell?

Stem cells are the raw materials of the body, the cells that give rise to all other cells with specific responsibilities.

Under the right conditions, stem cells divide to form more cells known as daughter cells in the body or in a laboratory.

Stem cells spawn additional cells for the body as it grows and replace damaged or lost specialized cells.

They are able to do this due to two distinct properties: they can divide repeatedly to produce new cells. They can change into the other types of cells that make up the body as they divide.

Pluripotent cells are those that form from the first few divisions of a fertilized egg cell and can develop into any cell in the human body or the placenta.

Thus, the correct option is B.

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what forms between daughter plant cells near the end of the telophase and during cytokinesis​

Answers

Answer:

a cell plate forms along the metaphase plate, growing inward from the sides of the rectangular plant cell.

Explanation:

In Calvin cycle, 1 molecule of glucose is formed from :1 6CO2 + 18ATP + 3ONADPH2 6CO2 + 18ATP + 12NADP3 6CO2 + 30ATP + 12NADPH4 6CO2 + 12ATP

Answers

Solution:

For a total of 6 molecules of fixed carbon dioxide, the final stoichiometry of the Calvin cycle can be summarized in the following equation:

This would represent the formation of a 6-carbon phosphate sugar molecule.

Now, the Calvin cycle uses chemical energy from ATP to combine six carbon atoms from six CO2 molecules with 12 hydrogens from NADPH to produce one molecule of glucose. So that, we can conclude that the correct answer is:

In Calvin cycle, 1 molecule of glucose is formed from :1 6CO2 + 18ATP + 3ONADPH2 6CO2 + 18ATP + 12NADP3
In Calvin cycle, 1 molecule of glucose is formed from :1 6CO2 + 18ATP + 3ONADPH2 6CO2 + 18ATP + 12NADP3

The table shown below represents the number of species growing in an area that was logged using clear-cutting 45 years ago in Temagami, Ontario. Data was collected periodically over 45 years.
Describe the changes occurring in vegetation type and species diversity over the 45 years.
What does the pattern of change tell you about what is happening in this area?
Explain how the data supports your conclusion.

The table shown below represents the number of species growing in an area that was logged using clear-cutting

Answers

According to the information we can infer that in general the number of species has increased.

What conclusion can we draw from the graph?

Based on the information in the graph, we can conclude that over the years the number of species has increased. In the case of grasses, it went from having 32 species to having 35. In the case of trees, it went from having 0 to having 24, and in the case of shrubs, it went from having 0 to having 18.

In the row that shows the total number of species, it went from having 32 to having 77, which means that it doubled the number of species in this period of time.

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Identify the most appropriate control the researchers should use when determining whether the mutation affects the growth rate of the E. Coli-M bacteria

Answers

When determining whether a mutation affects the growth rate of a bacterial strain such as E.

coli-M, the most appropriate control for the researchers to use would be a wild-type or "normal" strain of E. coli-M that has not been subjected to any genetic manipulation. This control would allow the researchers to compare the growth rate of the mutant strain to that of a known baseline and determine whether any observed differences in growth rate are due to the mutation or some other factor.

In addition to the wild-type control, the researchers should also consider using other controls that account for potential confounding factors such as differences in environmental conditions or experimental procedures. For example, they might use a negative control in which the bacteria are not exposed to any growth medium, or a positive control in which the bacteria strain  are exposed to a growth medium that is known to support rapid growth.

Using appropriate controls is an essential component of scientific experimentation, as it allows researchers to ensure that any observed effects are due to the variable being tested rather than some other factor.

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which one protein makes ?

a) Ribosomes
b) mitochondria
c) nucleus
d) chloroplasts ​

Answers

Answer:

a. ribosomes

Explanation:

The principal source of air pollution from volcanoes is

Answers

Answer:

locally sulfur dioxide gas

Explanation:

these gases can come from Lava flows as well as a volcano that erupts violently

Answer: Ash

Explanation:

took on ed

12. Why is our sense of hearing important?

Answers

Answer:

As one of our most vital senses, the capacity to hear allows us to connect to the world for numerous very critical reasons. Most notably, hearing joins us to people enabling us to communicate in a manner that none of our different senses can accomplish.

Explanation:

Hearing allows us to connect with the world around us, it's beneficial to communicate with others, be able to listen for dangers, etc. Our ears can detect all sorts of noises, and all of these sounds have some sort of importance to us. Some noises can indicate danger, which is vital for survival. Hearing is also crucial for socialization; on average, a person will hear up to 70,000 words a day!

I hope this helped!! :)

Answer:

Hearing is essential for maintaining relationships and connections with friends and family, fully participating in team and community activities, and experiencing life events. Hearing makes it possible to engage, listen, laugh, and enjoy many of the things that help shape your quality of life

why would measuring just root mass not be a totally accurate way of measuring the effect of fertilizer on root growth

Answers

Answer:

Fertilizers affect the root growth in several ways such as:

Provide muti-nutritionsProvide more mineral nutritionSlow release of nutrients in soilRapid growth of plant root

Root mass of root is the measurement of growth in length and weight of the roots.

So, the effect of fertilizer is not limited to the growth in length and weight, there are several nutritional changes in roots which are also important for the measurement of effect of fertlisers on root growth.

Answer:

The correct answer is - there are several other factors that affect the growth of the roots other than fertilizers.

Explanation:

Measuring the root mass only is not a correct or accurate way of measuring of the effect of the fertilizers on root growth as it is not the only factor that affect growth of the roots.

The factors that have significant effect on growth of roots of the plant are environmental conditions that are present in the root zone such as gas exchange, Water, Space, Carbohydrates, Non-limiting Temperature, Minerals, Microbial Associations and Low Soil Density.

Thus, the correct answer is -  there are several other factors that affect the growth of the roots other than fertilizers.

What is photosynthesis the conversion of?

Answers

Photosynthesis is the process of conversion of light energy into chemical energy in the form of Glucose.

The conversion of light energy into chemical energy in the form of sugars is known as photosynthesis. Oxygen is released as a byproduct as glucose molecules (or other sugars) are Synthesized from water and carbon dioxide in a process driven by light energy. Two essential resources are provided by the glucose molecules to organisms: energy and organic, fixed carbon.

This group includes the brilliant creatures of nature, green plants. By taking in carbon dioxide and transforming it into carbohydrates—a molecule that stores energy—they perform a photosynthesis cycle.

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Select a field of study within environmental science. Describe how a professional in that field would contribute to the environmental study of a lake.
(Think about the specific expertise that a professional in your field of choice would have.)

Answers

One field of study within environmental science is limnology, which is the study of freshwater ecosystems, including lakes.

What is the contribution of limnologist?

A professional in this field would contribute to the environmental study of a lake in several ways. For example:

Physical and chemical analysis: A limnologist would measure various physical and chemical parameters of the lake, such as temperature, pH, dissolved oxygen, and nutrient levels.

Biodiversity assessment: The limnologist would study the lake's biotic community, including algae, phytoplankton, zooplankton, and fish populations. This information would help determine the overall health of the lake.

Water quality monitoring: The limnologist would monitor the lake's water quality and identify potential pollutants, such as excess nutrients, heavy metals, and other toxic substances.

Ecosystem dynamics: The limnologist would study the lake's ecosystem dynamics, including food webs, trophic relationships, and nutrient cycling. This information would be used to understand how the lake functions and respond to environmental changes.

Overall, a limnologist would use a combination of field and laboratory methods to gather data and conduct analysis to contribute to the understanding and management of the lake's health and ecosystem.

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Which condition can cause transpiration to stop in a plant?
O A. Open stomata
O B. Dry soil
C. Heavy rainfall
O D. Stiff guard cells

Answers

Answer:

The answer is B. Dry soil

Explanation:

Plants can't continue to transpire without wilting if the soil is very dry because the water in the xylem that moves out through the leaves is not being replaced by the soil water. This condition causes the leaf to lose turgor or firmness, and the stomata to close

What are the process of the digestive system​

Answers



Check all that are true of the following scenario.
An archer strings an arrow on a bow and draws the string back. Aiming the bow
upwards at a 45 degree angle, the archer pauses with arms locked into position and
then releases the string. The arrow flies upwards making an arc and then sticks into
the trunk of a tree with an audible thud.
At least four different types of energy are illustrated in this example.
The first energy transformation in the scenario is chemical energy to kinetic.
From the time the archer draws the bow until the thud us heard, entropy increases in
the universe.
The energy of the arrow at the end of the scenario is equal to the energy exerted by the
muscles of the archer.
When the arrow sticks into the tree the original energy has all been used up.

Answers

Statements 1 and 3 are true, while statements 2 and 4 are false.The first energy transformation in the scenario is chemical energy to kinetic. - True.

The archer converts chemical energy stored in their muscles into kinetic energy when they release the string and propel the arrow forward.From the time the archer draws the bow until the thud is heard, entropy increases in the universe. - False. Entropy is a measure of disorder or randomness in a system. In this scenario, the archer's actions do not necessarily lead to an increase in entropy.

The energy of the arrow at the end of the scenario is equal to the energy exerted by the muscles of the archer. - False. Energy is conserved in a closed system, but some energy is lost as heat and sound during the process. Therefore, the energy of the arrow at the end may be less than the energy exerted by the archer's muscles.

When the arrow sticks into the tree, the original energy has all been used up. - False. Energy is not created or destroyed but rather transformed from one form to another. Some of the initial energy from the archer's muscles is transferred to the arrow's kinetic energy, but it is not entirely used up.In summary, statements 1 and 3 are true, while statements 2 and 4 are false.

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What. Is black i will mark as brinelist ​

Answers

Just black?
Well it’s a colour which results from the absence of visible light. In technical sense black and white aren’t colour, but shades however, many people disagree since you combine other pigments to get black. Black is also associated with darkness, evil, despair and night (if it’s Literature related). It’s the darkest shade and it’s an achromatic colour.

simple. black. Is a color and it is dark

In the image is the blood hypertonic, isotonic, or hypotonic compared
to the matrix of the brain?

Answers

Answer:

Hypotonic

Explanation:

there is less concentration in the blood compared to the brain

Answer:


Hypotonic

Explanation:

the blood is hypotonic compared to the matrix of the brain because it has less solutes than the matrix

what are oysters used for​

Answers

Answer:

Well most people (like myself) eat oysters in a seafood boil. But you can also find a pear in an oyster and use it for a necklace or bracelet.

Explanation:

Answer:

Eating

Explanation:

What makes an illness reportable? Give an example of a mandatory reportable disease and a reason
why it might have made the reportable list. HELP PLEASE

Answers

Answer:

Explanation

Reportable diseases are divided into several groups: Mandatory written reporting: A report of the disease must be made in writing. Examples are gonorrhea and salmonellosis. Mandatory reporting by telephone: The provider must make a report by phone.

Just like Mendel, you have grown a pea plant that has two phenotypic traits you are interested in. Round (Dominant) or Wrinkled (Recessive), Yellow (Dominant) or Green (Recessive) After crossing two plants heterozygous in both traits (RrYy x RrYy), you have 556 progenies classified as follows. Calculate their expected progeny phenotypic distributions as if these traits are independently assorted rather than linked. (4 pts)

Observed Values
315 Round, Yellow Seed
108 Round, Green Seed
101 Wrinkles, Yellow Seed
32 Wrinkled, Green Seed
556 Total Seeds
What are the Expected Values for RrYy x RrYy?

Use Chi-Square Analysis and the p-value chart (refer to Lab 4 handout for formula and chart) to determine whether these traits do indeed display independent assortment. Show your work. (4 pts)

What is your null hypothesis? Are the data consistent with your null hypothesis or can you reject the null hypothesis? Provide the p-value evidence to support your case. (4 pts)

List three properties of DNA that would be the same between DNA isolated from strawberries and any other living organism. (3 pts)

List three properties that would be different between DNA isolated from strawberries and the DNA of any other living organism. (3 pts)

If a chromosome is 2 μm long during mitosis and contains about 1.5 cm of supercoiled DNA, how many times must the DNA condense itself during mitosis? Show your work. (1 pt)

If this measurement were the same for all of your chromosomes, how long would your DNA be in the uncondensed form if you joined all of it from end to end? Show your work. (1 pt)

Answers

The probability of both traits appearing in the same offspring is (3/4) x (3/4) = 9/16 and the probability of both traits appearing in the same offspring is (1/4) x (1/4) = 1/16.

What are traits?

Traits are defined as specific characteristics or attributes of an individual.

1. To calculate the expected values, we need to multiply the total number of progeny by the probabilities of each phenotype. The expected values are:

315 Round, Yellow Seed = (556) x (9/16) = 311.5

108 Round, Green Seed = (556) x (3/16) = 104.5

101 Wrinkles, Yellow Seed = (556) x (3/16) = 104.5

32 Wrinkled, Green Seed = (556) x (1/16) = 34.5

2. Chi-Square Analysis:

The chi-square test is used to determine whether the observed data fits the expected data. The formula for the chi-square test is:

χ² = Σ [(O-E)²/E]

Where:

χ² = chi-square value

O = observed frequency

E = expected frequency

We can calculate the chi-square value for this data as follows:

χ² = [(315-311.5)2/311.5] + [(108-104.5)2/104.5] + [(101-104.5)2/104.5] + [(32-34.5)2/34.5]

χ² = 1.01 + 1.69 + 0.84 + 0.39

χ² = 3.93

3. Degrees of freedom (df) = (number of phenotypes - 1) = 3

Using the chi-square distribution table with 3 degrees of freedom and a significance level of 0.05, the critical value is 7.815. Since our calculated chi-square value (3.93) is less than the critical value (7.815), we fail to reject the null hypothesis.

4. Null Hypothesis:

The null hypothesis is that the observed data fits the expected data, meaning that the traits are independently assorted.

5. Properties of DNA that are the same between strawberries and any other living organism:

DNA is composed of four nitrogenous bases: adenine, guanine, cytosine, and thymine.DNA is organized into double helix structures.DNA is responsible for carrying genetic information.

6. Properties of DNA that are different between strawberries and any other living organism:

The sequence of the nitrogenous bases is unique to each organism.The amount of DNA in each organism can vary widely.The number of chromosomes can vary widely between organisms.

7. Calculating the number of times DNA must condense itself during mitosis:

If the chromosome is 2 μm long and contains about 1.5 cm of supercoiled DNA, then the DNA must condense itself by a factor of 1.5 cm / 2 μm = 7500 times during mitosis.

8. Calculating the length of DNA in the uncondensed form:

If the chromosome is 2 μm long and contains 1.5 cm of DNA, then the length of DNA in the uncondensed form is 1.5 cm / 2 μm = 750,000 μm or 750.

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The smooth ER differs from the rough ER in that:

Answers

Answer:

What is the difference between the rough and smooth ER? Rough ER's have ribosomes on the surface and produce large amounts of proteins for export. Smooth ER's contain a collection of specialized enzymes and does not have ribosomes on its surface.

Explanation:

what is the analogy between the vacuole and a school?

Answers

Answer:

The vacuoles is like the cabinets in the school used to store items. where we release all of our energy. Cytoplasm is like the hallways of the school.

For a female to have a X-Linked Recessive Disorder, what must be true? Select all that apply.

For a female to have a X-Linked Recessive Disorder, what must be true? Select all that apply.

Answers

The best options would be:

1. The father has to be a carrier fr the disorder

2. The mother has to be a carrier for the disorder

If the father who is a carrier of the disease marries a normal female could also produce an x-linked recessive female offspring.

If the mother who is a carrie osf the disorder marries a normal male, could also produce an x-linked recessive female offspring.

Select from the drop-down menu the best answer for each question. Which specialized organelle is shown? Which process occurs in the above organelle?​

Select from the drop-down menu the best answer for each question. Which specialized organelle is shown?

Answers

Answer: the person who asked this question attached the answer at the bottom of thier question I Just wanted to put an answer so people won‘t miss it.

Explanation:

Select from the drop-down menu the best answer for each question. Which specialized organelle is shown?

Answer:

the person so submitted this question also had the answers attached, but it's Mitochondrion and Cellular Respiration

Explanation:

Select from the drop-down menu the best answer for each question. Which specialized organelle is shown?

6. Lakes are composed of different zones, based on the amount of sun and the
forms of life that live in them. (9 points)
A. Draw a lake, and label the four zones. (5 points)
B. What type of food is eaten in each zone? (4 points)

Answers

The food eaten in the zones in the lake include;

Littoral Zone - Sea weed

Limnetic Zone - Plants

Euphotic Zone - Shrimps

Benthic Zone - Calms of shrimps

What are the zones in the lake?

Littoral Zone: This zone is the lake or pond's shoreline. It is made up of the area between dry land and open water that can be very narrow or very wide.

Limnetic Zone: The open water area of a lake or pond is generally classified as the Limnetic Zone. In oligotrophic ponds and lakes, this is a much larger section of water than in eutrophic bodies of water.

Euphotic Zone: The upper portion of the Limnetic Zone near the water's surface is known as the Euphotic Zone or Epilimnion (warm water region). This is the part of the water that gets sunlight. The zone ends when sunlight cannot penetrate the water.

Benthic Zone: The Benthic Zone consists of organic sediments and soil at the bottom of a pond or lake. This zone will expand as the body of water ages. It is regarded as the digestive system of a pond or lake.

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6. Lakes are composed of different zones, based on the amount of sun and theforms of life that live in

What is MKS,CGS and FPS system?​

Answers

Answer:

In the CGS system, fundamental units are Centimeter, Gram and second. MKS system – Meter kilogram second system. In the MKS system, fundamental units are Meter, kilogram and second. FPS system – Foot Pound second system. In the FPS system, fundamental units are Foot, Pound and second.

Explanation:

have a nice day

Answer:

Explanation:

CGS system : Centimeter, Gram and second.

MKS system : Meter, kilogram and second.

FPS system :  Foot, Pound and second.

Which two factors have the greatest influence on creating increased genetic variation within a species?
A)Crossing-over, which takes place during prophase 1 of meiosis 1.
b)When the chromatids separate in metaphase 2 in meiosis 2.
c)Independent assortment of chromosomes that occurs during anaphase 2 of meiosis 2.
d)When the chromosomes separate in metaphase 1 of meiosis 1.

Answers

Answer:

A and C.

The two factors that have the greatest influence on creating increased genetic variation within a species are:

A) Crossing-over, which takes place during prophase 1 of meiosis 1. This is the process by which homologous chromosomes exchange genetic material, resulting in new combinations of alleles on the chromosomes.

C) Independent assortment of chromosomes that occurs during anaphase 1 of meiosis 1. This is the process by which homologous chromosomes randomly line up and separate from each other, resulting in different combinations of maternal and paternal chromosomes in the resulting haploid cells.

Therefore, options A and C are the correct answers. Option B refers to the separation of sister chromatids during meiosis 2, which does not create new combinations of alleles. Option D refers to the separation of homologous chromosomes during meiosis 1, which does contribute to genetic variation but not to the same extent as crossing-over and independent assortment.

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which of the following is the ultimate electron acceptor in oxidative phosphorylation? cytochrome c coenzyme q oxygen atp adp

Answers

the correct answer is oxygen.

What is the definition of over crowding?

Answers

Overpopulation refers to a population which exceeds its sustainable size within a particular environment or habitat. Overpopulation results from an increased birth rate, decreased death rate, the immigration to a new ecological niche with fewer predators, or the sudden decline in available resources.

11. A person who has rickets might need
more foods from which two groups?

Answers

A person who has rickets might need more foods from the milk and green leafy vegetables groups. Rickets is a disease that is caused by a lack of vitamin D. Vitamin D is essential for the absorption of calcium and phosphorus, which are needed for the formation of strong bones. Milk and green leafy vegetables are good sources of vitamin D. Other foods that are good sources of vitamin D include fatty fish, egg yolks, and fortified foods.

In addition to getting enough vitamin D, people with rickets may also need to take calcium and phosphorus supplements. These supplements can help to improve bone health and prevent further bone loss.

Here are some specific foods that people with rickets may want to include in their diet:

Milk
Yogurt
Cheese
Salmon
Tuna
Sardines
Eggs
Fortified orange juice
Fortified cereal
Tofu
Green leafy vegetables
Fortified bread
Fortified pasta
It is important to talk to a doctor or registered dietitian about the best way to manage rickets. They can help to create a personalized diet and supplement plan that will meet the individual's needs.
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