a
What does a hydraulic system do?
a decrease pressure
b. increase velocity
c. multiply force
d. reduce inertia
?
m

The energy of a photon in joule with a given frequency of 8.73 × 10⁸ Hz is *4.59 × 10⁻¹⁹ J*.

The energy of a photon can be calculated using the formula: E = h * f, where E represents energy, h is Planck's constant (6.626 × 10⁻³⁴ J • s), and f is the frequency of the photon. By substituting the given values into the formula, we can calculate the energy as follows: E = (6.626 × 10⁻³⁴ J • s) * (8.73 × 10⁸ Hz) E = 5.77 × 10⁻²⁵ J • Hz  E ≈ 4.59 × 10⁻¹⁹ J Therefore, the energy of the photon is approximately 4.59 × 10⁻¹⁹ J.

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When the switch is closed, the circuit is completed, connecting both light bulbs (resistors) in parallel. This causes the overall resistance of the circuit to decrease, leading to an increase in current from the battery. As a result, the brightness of bulb 1 decreases since the current is now shared between both bulbs.

First, let's look at what's happening with just bulb 1. When the circuit is closed and the switch is open, the current is flowing through bulb 1 and creating light. Bulb 1 has a certain resistance, which determines how much current can flow through it and how bright it will shine.

Now, when we close the switch, we're essentially adding another resistor (bulb 2) to the circuit. This changes the total resistance of the circuit, which affects the current flow through each bulb.

To determine what happens to bulb 1's brightness when the switch is closed, we need to think about the total resistance of the circuit. Let's say that each bulb has a resistance of 75 ohms (this is just an example). When the circuit is closed, the total resistance would be:

Rtotal = R1 + R2
Rtotal = 75 + 75
Rtotal = 150

So the total resistance of the circuit is 150 ohms.

Now, let's think about what this means for the current flow through each bulb. The current flowing through each bulb depends on the voltage of the battery and the resistance of each bulb. If we assume that the battery has a voltage of 9 volts (again, just an example), then we can use Ohm's Law to calculate the current flowing through each bulb:

I = V/R

For bulb 1:
I1 = 9/75
I1 = 0.12 amps

For bulb 2:
I2 = 9/75
I2 = 0.12 amps

So when the switch is closed, each bulb has a current of 0.12 amps flowing through it.
Well, the brightness of a bulb is directly related to the current flowing through it. So if the current through bulb 1 is the same as before (0.12 amps), then the brightness should be the same as before as well.

In other words, when the switch is closed, the brightness of bulb 1 should not change.

When the switch is closed, the total resistance of the circuit increases, but the current through each bulb stays the same. Therefore, the brightness of bulb 1 should not change.

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When the switch is closed, the brightness of the bulb1 will decrease.

Based on the circuit diagram, when the switch is open, the circuit is a parallel circuit, with bulb 1 and bulb 2 connected in parallel to the battery. The current from the battery splits into two branches, with some of the current flowing through bulb 1 and some of the current flowing through bulb 2. Since bulb 1 has a lower resistance than bulb 2, it will receive more current and will glow brighter than bulb 2.

When the switch is closed, the circuit becomes a series circuit, with bulb 1 and bulb 2 connected in series to the battery. In a series circuit, the same current flows through all components in the circuit. The total resistance of the circuit is the sum of the resistances of bulb 1 and bulb 2. If bulb 2 has a higher resistance than bulb 1, then the total resistance of the circuit will increase when the switch is closed, and the current through both bulbs will decrease. This means that the brightness of both bulbs will decrease when the switch is closed, including the brightness of bulb 1. Therefore, when the switch is closed, the brightness of bulb 1 will decrease.

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The amount of heat needed to raise the temperature of a 2kg object from 15°C to 25°C is 34000J.

HOW TO CALCULATE SPECIFIC HEAT CAPACITY:

Where;

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Answer:

well I done really know ask the others person

Answer:

wen I was in the car toing home from school after a bad day n si si I have crazzyyy

Answer:-

1. I feel  the most passionate and alive when I watch BTS, because they inspir me to do many things such as Loveing Myself and doning what I love in life and chase my dream. I also feel alive when playing soccer, dancing, playing piano, or singing/rapping, because these things are what I love to do and always loved to do.

2. Yes, I feel like I live everyday the same day, some little things change but the things I do every day are the same, never changes. Wake up, eat, homework, clean, eat, tv, eat, and sleep.

(a) Leak before break is a concept of designing the system or structure to minimize the risk of sudden catastrophic failure due to cracks.

The concept is to create a design that allows the development of cracks, and before the crack gets to a critical size, the system or structure should be able to detect the crack or leak. There are three stages in a leak-before-break condition:

First stage - Crack initiation: In this stage, cracks start to develop, but there is no effect on the system or structure's performance.

Second stage - Slow Crack Growth: In this stage, the crack's growth is slow, and the crack's effects on the system or structure are minimal.

Third stage - Rapid Crack Propagation: In this stage, the crack grows rapidly, and it could cause a catastrophic failure of the system or structure.  

(b) Longitudinal stress, σl = (pi x di^2)/4tσl = (28.75 x 10^6 x (0.08^2))/4 x 0.01σl = 58000000 Pa Hoop stress, σH = (pi x di x p)/2tσH = (28.75 x 10^6 x 0.08)/2 x 0.01σH = 11500000 Pa

(c) Critical crack size can be calculated as; ac = ((KIc^2 x Y)/(σpi))^(1/2)ac = ((23^2 x 0.7)/(28.75 x 10^6 x pi))^(1/2)ac = 1.6 x 10^-3 m

The crack is stable since the size of the crack is less than the critical crack size.

(d) Yes, the condition corresponds to a 'leak before break since the hemispherical crack's growth is slow, and the cylinder could detect it and initiate repairs before the cylinder fails catastrophically.

(e) No, the design will not be 'leak before break since the cheaper aluminum alloy's critical crack size is smaller than the crack's size. Therefore the cylinder will fail catastrophically.

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The Carolingian Empire began when Charlemagne was crowned by the Pope in 800.

This event marked the formal recognition of Charlemagne as the emperor of the Carolingian Empire, which encompassed a significant portion of Western Europe. Charlemagne's crowning by the Pope demonstrated the close relationship between the Carolingian rulers and the papacy, solidifying their authority and status as the dominant power in the region. The establishment of the Carolingian Empire under Charlemagne's rule marked a significant political and cultural development in Europe during the early Middle Ages.

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The car to the right has an unidentified mass of 0.779 kilograms.

Divide the object's weight by the acceleration of gravity to determine its mass. It is necessary to convert the weight units into Newtons. For instance, the mass of one kilogram on Earth can be calculated by dividing the weight in Newtons by the acceleration of gravity (in meters per second2)

Explain:

After the collision, the total momentum equals (1.3m)/(0). 92 0) According to the law of conservation of momentum, the unknown mass is equal to the total momentum before and after the collision: 1.9128 = (1.3 + m) (0.028) 1.3 + m = 2.079 m = 2.079 - 1.3 m = 0.779 kg.

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Answer:

Total contraction = 1.2277 mm

Explanation:

the solution is given in the picture below and it is more explanatory

Answer:

D. 1×10⁻⁸ M

Explanation:

[H⁺] [OH⁻] = 10⁻¹⁴

(1×10⁻⁶) [OH⁻] = 10⁻¹⁴

[OH⁻] = 1×10⁻⁸

The concentration of hydroxyl ion will be  \(10^{-8}\)M.

The amount of a chemical substance in a mixture is expressed by the substance's concentration.

Calculation of concentration.

Given data:

Concentration of H+ =  1 x \(10^{-6}\) M.

It is known that,

[\(H^{+}\)][\(OH^{-}\)] = \(10^{-14}\)M

Now, put the value of concentration of [\(H^{+}\)] in above equation.

[1× \(10^{-6}\)][\(OH^{-}\)] =  \(10^{-14}\)M

[\(OH^{-}\)]  =   \(10^{-14}\) / [1× \(10^{-6}\)]M

[\(OH^{-}\)]  = \(10^{-8}\)M

Therefore, the concentration of hydroxyl ion will be  \(10^{-8}\)M.

Hence, the correct answer will be an option (D).

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This is due to the fact that occluded fronts combine two cold air masses, which causes one of the cold air masses to go downward.

When a warm air mass is sandwiched between two cold air masses, an occluded front occurs. In an occlusion, the warm front passes over the cold front, which dives beneath it.

In a front is obscured, the warm front is fully supplanted by the cold front, in which the warm air masses have completely disappeared. Furthermore, there are frequent shifts in the various weather producing circumstances because of the cold front's relatively low temperature.

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The cost of energy consumption to operate the heater for 15 days is $2.25

Voltage (V) = 200 V

Current (I) = 25 A

Power (P) = VI = 200 * 25 = 5,000 W

Now, the calculation of the energy consumption for 15 days in KW/h

We will convert W to kW,

1000 W = 1kW

Therefore,

5,000 W = 5000 W × 1 KW / 1000 W = 5kW

The daily energy consumption will be calculated. This is attainable as follows,

P = 5kW

Time(t) = 10 h

Energy (E) = P/t = 5/10 = 0.5 kW/h per day.

Finally, we will calculate the energy usage for the next 30 days. This is attainable as follows:

1 day = 0.5 kW

Cost of one day = 0.5 * 0.30 = $ 0.15

Now, the cost to operate the heater for 15 days = $ 15 * 0.15 = $2.25

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Answer:

Well I think that 16 year olds should get a job because this could benefit them. They can learn to save and manage there own money. And I think that 16 yrs olds should get a job because this can help them in positive way.

Explanation:

Hope this made sense and help!!!

Answer:

b

Explanation:

Bears hibernate in the winter

Answer:

Velocity is the rate at which an object changes position

Answer:

Fossil fuels store energy from the sun as

Explanation:

Answer:

A. Strain

Explanation:

(no explanation)

Given data,

Mass of the bus is m = 9800 kg,

Speed of the bus is v = 40 mph,

Converting speed of the bus in m/s, {1 miles per hour = 0.447 meter per second}

v = 40*0.447

v = 17.88

Calculating momentum of the bus,

ATP and NADPH serve as the chemical fuel for the light independent processes, often referred to as the Calvin cycle.

Adenosine triphosphate, also known as ATP, is a highly energetic molecule that both stores and releases energy. It is created by the process of photophosphorylation during the light-dependent activities of photosynthesis. Another high-energy molecule formed during the light-dependent processes is NADPH, or nicotinamide adenine dinucleotide phosphate. This happens as a result of non-cyclic electron transport.

The light independent processes that transform carbon dioxide into glucose and other sugars are powered by both ATP and NADPH. An enzyme known as Rubisco uses the energy from these molecules to drive the fixation of carbon dioxide, turning it into a carbohydrate.

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Answer:

donde esta la bibliotekaaa

Explanation:

dfghj

Por definición de velocidad angular, periodo y frecuencia del M.C.U., la frecuencia, la velocidad angular y el periodo de la rueda son 8.833 Hz, 55.50 rad/s y 0.113 segundos respectivamente.

El movimiento circular uniforme (M.C.U.) es un movimiento de trayectoria circular en el que la velocidad angular es constante. Esto implica que describe ángulos iguales en tiempos iguales.  

En otras palabras, el M.C.U. describe el movimiento de un cuerpo con una rapidez constante y una trayectoria circular, cambiando en cada instante de dirección.

La frecuencia mide el número de revoluciones o vueltas completadas por unidad de tiempo. La frecuencia se expresa en s⁻¹ o Hertz (Hz).

Se define como:

f= ω÷ (2π) siendo ω la velocidad angular.

El periodo (T) es el tiempo que el cuerpo emplea en dar una vuelta completa; es decir que las características del movimiento son las mismas cada T segundos.

Se define como:

Una rueda gira con una frecuencia de 530 rpm. Expresada en las unidades correspondientes, la frecuencia de la rueda es:

f = 530rpm×\(\frac{1 min}{60 segundos}\)

f = 8.833 Hz

Siendo la frecuencia f= ω÷ (2π), entonces la velocidad angular es calculada como:

ω= f× (2π)

Entonces, la velocidad angular de la rueda es:

ω= 8.833 Hz× (2π)

ω= 55.50 rad/s

Finalmente, por definición de periodo, el periodo de la rueda es:

T= 1÷ 8.833 Hz

T=0.113 segundos

En resumen, la frecuencia, la velocidad angular y el periodo de la rueda son 8.833 Hz, 55.50 rad/s y 0.113 segundos respectivamente.

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Answer:

2: In a conductor, electric current can flow freely; in an insulator, it cannot flow freely.

Explanation:

trust

The negative plate is the one facing us because the electric field between the plates is zero, which can only happen if the two plates have the same magnitude and opposite sign of charge density.

Charge density is the amount of electric charge per unit area or per unit volume of a material or object. It is usually denoted by the symbol ρ and is measured in units of coulombs per square meter (C/m²) or coulombs per cubic meter (C/m³).

In the case of a charged plate, the charge density is the total charge on the plate divided by its surface area. For example, if a plate has a charge of 60 µC and an area of 2 m², then the charge density is:

Charge density = 60 µC / 2 m² = 30 µC/m²

Charge density is an important concept in electrostatics, as it is used to describe the distribution of electric charge over a surface or within a volume. It is also used in the calculation of electric fields and forces in electrostatics, as the electric field depends on the charge density of the objects producing the field.

Two large, charged plates with charge density ±30µC/m² facing each other with a separation of 5.0 mm.

One of the plates has a negative charge density.

We want to find out which plate is negative

1. Calculate the total charge on one of the plates using the charge density and the area of the plate:

Q = ±30 µC/m² * A

Here, A is the area of one of the plates.

2. Calculate the electric field due to each plate using Coulomb's law:

E = (1/4πε₀) * (Q / r²)

Here, r is the distance between the plates, which is 5.0 mm or 0.005 m.

ε₀ is the permittivity of free space, which is a constant and has a value of 8.85 x 10⁻¹² F/m.

Since there are two plates, calculate the electric field due to each plate and then take the difference between them to get the net electric field between the plates.

3. Substitute the values and calculate the electric field due to each plate:

E1 = (1/4πε₀) * (Q / r²)

E2 = (1/4πε₀) * (Q / r²)

Here, E1 is the electric field due to one plate, and E2 is the electric field due to the other plate. Since the plates have the same magnitude of charge density, their charges will have the same magnitude too, so we can drop the absolute value sign in Coulomb's law.

4. Subtract the electric field due to one plate from the electric field due to the other plate to get the net electric field:

E = E1 - E2

E = 0

Since, the net electric field is zero, this means that the electric field due to one plate is equal in magnitude and opposite in direction to the electric field due to the other plate. Therefore, the plates must have the same magnitude of charge and opposite signs of charge density.

5. Since, one of the plates has a negative charge density is known, this means that the negative plate is the one facing us. Therefore, the negative plate is the one that we were asked to identify.

Therefore, the negative plate is the one facing us.

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momentum= mass × velocity

p= 50×18

momentum= 900 kg m/s

a. The total electric flux density for point P1(4, -3, 2) is X units.

b. The magnitude of the vector from point A to point D is Y units.

a. The total electric flux density for point P1(4, -3, 2) can be calculated using Gauss's Law. Gauss's Law states that the electric flux passing through a closed surface is proportional to the charge enclosed by that surface. In this case, we have three point charges located at A(5, -1, 5), B(8, -1, 2), and C(3, 7, -2), each with their respective magnitudes of charge. To find the total electric flux density at point P1, we need to consider the electric fields generated by each of these charges and their distances from P1. By summing up the contributions of these electric fields, we can determine the total electric flux density at P1.

b. To find the magnitude of the vector from point A to point D, we need the coordinates of point D. However, the coordinates of point D have not been provided in the given question. Without the coordinates of point D, it is not possible to calculate the magnitude of the vector from point A to point D accurately.

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Answer:

the answers are "mass" and "distance"

Explanation:

hope this helps, plz mark brainiest :)

To reduce the effort required by a labourer in pushing a heavy trunk, several strategies can be employed:

1)Reduce the weight of the trunk

2)Use wheels or a trolley

3)Lubricate the surfaces

4)Provide leverage

5)By implementing these measures

To reduce the effort required by a labourer in pushing a heavy trunk, several strategies can be employed:

Reduce the weight of the trunk: If possible, remove or redistribute the contents of the trunk to make it lighter. This will decrease the force required to move it.

Use wheels or a trolley: Adding wheels to the trunk or placing it on a trolley can significantly reduce the effort needed to push it. By reducing friction with the ground, the labourer can easily roll the trunk instead of having to overcome static friction.

Lubricate the surfaces: Applying a lubricant, such as oil or grease, to the contact points between the trunk and the ground can reduce friction and make it easier to push.

Provide leverage: Attach handles or levers to the trunk to allow the labourer to exert force more efficiently, utilizing mechanical advantage to reduce effort.

By implementing these measures, the labourer's effort in pushing the heavy trunk can be reduced, making the task less physically demanding and more manageable.

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