A5 pound object is moving horizontally with a speed of 15m/s. How much force is needed to keep the object
moving at 15m/s in the same direction? Explain WHY. You can give your answer as a relative estimate (ex: a small
amount...)

Explanation:

work done is equals to force into displacement in the direction of force

Ans: D

The orbital period of the exoplanet in Figure 9 is 3 days. To calculate the distance between the exoplanet and its star, we can use Equation 5: \(A = 3M \times P^{2}\). Here, A represents the distance in AU, \(M_{star}\) is the mass of the star in solar masses, and P is the orbital period of the exoplanet in years.

To use this equation, we first need to convert the orbital period from days to years. Dividing 3 days by 365.25 (the number of days in a year, accounting for leap years) gives us approximately 0.0082 years.

Using the mass of the star, which is 1.47 solar masses, we can now calculate the distance:

\(A = (3 \times 1.47) \times (0.0082)^{2}\)

Evaluating this expression yields a value of approximately 0.003 AU.

Therefore, the distance between the star and the exoplanet in Figure 9 is approximately 0.003 AU. This calculation provides an estimation of the separation between the exoplanet and its host star based on the given orbital period and the mass of the star.

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An acid-base indicator is a compound with a physical property that changes abruptly near the equivalence point.

An acid-base indicator is a chemical compound that is used to determine the endpoint of a chemical reaction. The endpoint of a chemical reaction is the point at which the reaction is complete or the point at which a chemical reaction is in equilibrium. The physical property of an indicator that changes abruptly near the endpoint is usually its color. In the case of an acid-base indicator, the color changes from one color to another as the pH of the solution changes.

This change in color occurs because the acidic or basic properties of the indicator change. The indicator can be used to determine the pH of a solution or to determine the concentration of an acid or base. The most commonly used acid-base indicator is litmus paper, which changes from blue to red in the presence of an acid. So therefore an acid-base indicator is a compound with a physical property that changes abruptly near the equivalence point.

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Answer:

0.5A

Explanation:

Using \(R = \frac{V}{I}\),

R is the resistance (in Ohms)

V is the voltage (in V)

I is the current (in A)

\(240=\frac{120}{I}\)

I = 0.5A

The ski will travel a distance of (2μL/3) + (2/3)h along the level at the foot of the incline.

Assuming that the ski starts from rest at the top of the incline and slides down the incline without any loss of energy due to friction or air resistance, the potential energy of the ski at the top of the incline is converted entirely into kinetic energy as it slides down the incline. When the ski reaches the bottom of the incline, all of the kinetic energy is transferred into potential energy and frictional work done by the coefficient of friction, bringing the ski to a stop.

Let's denote the height of the incline by h, the length of the incline by L, and the coefficient of friction between the ski and the snow by μ.

The potential energy of the ski at the top of the incline is given by:

PE = mgh

where m is the mass of the ski and g is the acceleration due to gravity. At the bottom of the incline, the potential energy is zero, and the kinetic energy of the ski is given by:

KE = (1/2)m\(v^2\)

where v is the speed of the ski at the bottom of the incline.

Since there is no net work done on the ski by external forces, the total energy of the ski is conserved, i.e.,

PE(top of incline) = KE(bottom of incline) + Work(friction)

mgh = (1/2)m\(v^2\) + μmgd

where d is the distance traveled by the ski along the level at the foot of the incline. Since the ski starts from rest at the top of the incline, we can also use the equation:

\(v^2\) = 2gh

To eliminate v from the above equation, giving:

d = (2μL/3) + (2/3)h

Therefore, the ski will travel a distance of (2μL/3) + (2/3)h along the level at the foot of the incline.

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Answer:

it is b on edge not d, well atleast for me it was b

Explanation:

Answer:

B) one battery, two switches, and three light bulbs

Explanation:

False

The Pressure Gradient Force (PGF) is the force that drives air from areas of high pressure to areas of low pressure. In both a trough and a ridge, the PGF is the same.

However, the winds will not be the same in both features.  

In a trough, the winds tend to move towards the center of the trough, where the air is rising, and this causes convergence and lifting. This upward motion causes a decrease in pressure, leading to a steeper pressure gradient, which means stronger winds. On the other hand, in a ridge, the winds move away from the center of the ridge, where the air is sinking, and this causes divergence and sinking. This sinking motion causes an increase in pressure, leading to a weaker pressure gradient and lighter winds.  

Therefore, assuming the same PGF, the trough will have the faster winds compared to the ridge.

(1) The initial velocity of the ball is 7.8 m/s.

(2a) The time of motion of the baseball is 6.5 seconds.

(2b) The horizontal distance traveled by the baseball is 206.8 m.

(3) The height of fall of the bullet  before hitting the target is 0.078 m.

The given parameters include;

h = Vyt + ¹/₂gt²

where;

h = 0 +  ¹/₂gt²

t = √(2h/g)

t = √(2 x 8)/9.8

t = 1.28 s

x = Vxt

Vx = x/t

Vx = 10/1.28

Vx = 7.8 m/s

The given parameters include;

\(T = \frac{2u \times sin(\theta)}{g} \\\\T = \frac{2 (45) \times sin(45)}{9.8} \\\\T = 6.5 \ s\)

x = Vxt

x = (ucosθ)t

x = (45 cos(45)) x (6.5)

x = 206.8 m

The given parameters include;

x = Vxt

t = x/Vx

t = 100/800

t = 0.125 s

h = ¹/₂gt²

h =  ¹/₂(9.8)(0.125)²

h = 0.078 m

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Answer:

If the driver is wearing a seat belt, the seat belt rather than the windshield applies the unbalanced force that stops the driver's forward motion. The force from the seat belt is applied over a longer time, so the force causes less damage.

Explanation:

The three polarizers are linearly polarized with their axes forming an angle of 60° with each other. When no polarizer is placed in the path of the light beam, maximum light intensity is observed. But when two polarizers are placed with their axis parallel to each other, minimum light intensity is observed. This is because the polarizers only allow the transmission of light waves that vibrate in a direction parallel to their axes.When the third polarizer is inserted between the first two, the intensity of light transmitted through the third polarizer depends on the angle between the transmission axes of the first two polarizers and the transmission axis of the third polarizer.

If the axis of the third polarizer is at 30° to the axis of the first polarizer, maximum light intensity is observed on the screen. This is because the third polarizer axis is oriented at 30° to the axis of the second polarizer, allowing more light to be transmitted through the third polarizer. Hence, the third polarizer acts as an analyzer of the polarized light after the first two polarizers, by selectively transmitting light waves of a particular polarization direction.Answer:In the previous set of measurements, adding the third polarizer in some cases increased the light intensity incident on the screen. The three polarizers are linearly polarized with their axes forming an angle of 60° with each other. When no polarizer is placed in the path of the light beam, maximum light intensity is observed. But when two polarizers are placed with their axis parallel to each other, minimum light intensity is observed.

This is because the polarizers only allow the transmission of light waves that vibrate in a direction parallel to their axes. When the third polarizer is inserted between the first two, the intensity of light transmitted through the third polarizer depends on the angle between the transmission axes of the first two polarizers and the transmission axis of the third polarizer. If the axis of the third polarizer is at 30° to the axis of the first polarizer, maximum light intensity is observed on the screen. This is because the third polarizer axis is oriented at 30° to the axis of the second polarizer, allowing more light to be transmitted through the third polarizer. Hence, the third polarizer acts as an analyzer of the polarized light after the first two polarizers, by selectively transmitting light waves of a particular polarization direction.

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The weight density of water is 62.4 pounds per cubic foot. This value is used to determine the weight of water based on its volume.

The weight density of a substance is a measure of how much weight it has per unit volume. In the case of water, its weight density is 62.4 pounds per cubic foot. This means that for every cubic foot of water, it will weigh 62.4 pounds.

Weight density is an important concept in various fields, such as engineering, construction, and fluid mechanics. It allows us to calculate the weight of water in different scenarios. For example, if we have a tank with a known volume of water, we can use the weight density to determine the total weight of the water in the tank. Similarly, if we know the weight of water in a container, we can calculate its volume by dividing the weight by the weight density.

Understanding the weight density of water is crucial for various practical applications. It helps in designing structures that involve water, such as dams, reservoirs, and pipes, as it provides insights into the forces exerted by the water. Additionally, it is also relevant in fields like hydrology and environmental science, where accurate measurements of water weight are necessary for calculations and analysis.

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Answer:

Tuberculosis

Explanation:

Tuberculosis is a disease of lower respiratory system because it's affect the lungs and the voice box . It is a bacteria disease that affect the lungs and it is very contagious. It can spread rapidly to the brain and spine. Most times people with tuberculosis did not show symptoms but when there is symptoms,the symptoms include cough with blood, night sweats, fever e t.c.

Answer:A

Explanation:

All we need to do in order to find out the direction is to take into account the sign of the charge. As they are both positive, the particles will repel each other, which can be seen on the following drawing:

Thus, particle q2 will try to push particle q1 to the left

The answer is: -

Answer:

Approximately \(3.43\; {\rm m\cdot s^{-2}}\), assuming that air resistance is negligible in both occasions, and that \(g_{\text{earth}} = 9.81\; {\rm m\cdot s^{-2}}\) near the surface of the Earth.

Explanation:

Let \(x\) denote the displacement of the marker. Let \(a\) denote the acceleration of the marker. Let \(t\) denote the time it takes for the marker to reach the ground.

Under the assumptions, acceleration of the marker would be constant, and the SUVAT equations would apply. Rearrange the SUVAT equation \(x = (1/2)\, a\, t^{2}\) to find acceleration \(a\):

\(\begin{aligned}a &= \frac{2\, x}{t^{2}}\end{aligned}\).

Let \(a_{\text{Mars}}\) and \(t_{\text{Mars}}\) denote the acceleration and time taken on Mars. Similarly, let \(a_{\text{Earth}}\) and \(t_{\text{Earth}}\) denote the acceleration and time taken on Earth. It is implied that the Marker travelled the same distance (same displacement, \(x\)) both on Earth and on Mars.

Using the SUVAT equation from above:

\(\begin{aligned}a_{\text{Mars}} &= \frac{2\, x}{{t_{\text{Mars}}}^{2}}\end{aligned}\).

\(\begin{aligned}a_{\text{Earth}} &= \frac{2\, x}{{t_{\text{Earth}}}^{2}}\end{aligned}\).

\(\begin{aligned}\frac{a_{\text{Mars}}}{a_{\text{Earth}}} &= \frac{\displaystyle \frac{2\, x}{{{t_{\text{Mars}}}^{2}}}}{\displaystyle \frac{2\, x}{{{t_{\text{Earth}}}^{2}}}} \end{aligned}\).

\(\begin{aligned}\frac{a_{\text{Mars}}}{a_{\text{Earth}}} &= \left(\frac{{t_{\text{Earth}}}}{{t_{\text{Mars}}}}\right)^{2}\end{aligned}\).

\(\begin{aligned}a_{\text{Mars}} &= \left(\frac{{t_{\text{Earth}}}}{{t_{\text{Mars}}}}\right)^{2}\, a_{\text{Earth}} \\ &= \left(\frac{1.3\; {\rm s}}{2.2\; {\rm s}}\right)^{2}\, (9.81\; {\rm m\cdot s^{-2}}) \\ &\approx 3.43\; {\rm m\cdot s^{-2}}\end{aligned}\).

Answer:   biogeochemical process

Explanation:

If the sun's temperature drops a little, what will happen is a decrease in oxygen in the atmosphere, resulting in damage to the earth's atmosphere.

The sun is the center of the solar system. The sun is a star that is closest to the earth. Like other stars, the Sun is a hot object composed of various high-pressure gasses. Oxygen is produced by marine plants in the form of phytoplankton and algae. 28% is produced by rainforests, and the remaining 2% is produced by other sources.

If plants die, while humans continue to use oxygen, the oxygen in the atmosphere will decrease. What's more, machines emit carbon dioxide. Without being able to convert it into oxygen in photosynthesis, carbon dioxide would accumulate in the atmosphere.

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Answer:

the answer for this is Letter B

As heat is continuously supplied to a system, the temperature remaining constant for some time at one point could be due to a phase change occurring within the system.

During a phase change, such as solid to liquid or liquid to gas, the added heat is used to overcome the intermolecular forces holding the particles together, rather than increasing the temperature.

As a result, the temperature remains constant until the phase transition is complete. This phenomenon is known as latent heat. For example, during the melting of ice, the temperature remains at 0 degrees Celsius until all the ice has melted.

Similarly, during boiling, the temperature of the boiling liquid remains constant until all the liquid has turned into vapor.

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According to the given statement The value of T1 is 63.58 Newtons.

There is gravitational contact between things with mass. As an item interacts with the Earth, this force is referred to as the weight. The weight measuring unit is the Newton (same as for any other force).

According to the question,

On the X-axis,

T1cos30⁰ - T2cos60⁰ = 0

or,

T1cos30⁰ = T2cos60⁰

On substituting the values, we get

T1 *  \(\sqrt{3}\)/ 2 =  T2 * 1/2

T1 * \(\sqrt{3}\) = T2 .........(Eq. 1)

On the Y axis

T1sin30⁰ - T2sin60⁰ = 139.3 N

T1 / 2 + \(\sqrt{3}\)/ 2 = 139.3 N

T1 + \(\sqrt{3}\)T2 = 139.3 N * 2

From equation 1 we get,

T1 + \(\sqrt{3}\) * \(\sqrt{3}\)T1 = 278.4 N

T1 + 3T1 = 278.4 N

4T1 =  278.4 N

T1 =  278.4 N / 4

T1 = 69.58 N

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Answer:

Water, carbon dioxide, and oxygen are among the few simple molecules that can cross the cell membrane by diffusion

Explanation:

The strength of the magnetic field required, applied perpendicular to the direction of the beam, that will deflect the beam of electrons into a circular arc with radius of 3.23 mm is 0.157 x 10^-3 T.

Explain the motion of electrons in a uniform magnetic field.

​Because magnetic force is always perpendicular to velocity, the charged particle is not affected by it. The kinetic energy and speed of the particle stay unchanged as a result. Motion's speed is unaffected, only its direction. Uniform circular motion frequently looks like this. The most straightforward scenario is when a charged particle moves perpendicular to a constant B-field. (If this happens in a vacuum, the magnetic field is what mostly controls the motion.) Here, the centripetal force is provided by the magnetic force (Lorentz force).

Cyclotron resonance is the word used to describe a particle moving in a circular pattern as a result of a constant magnetic field.

Equating the centripetal force and magnetic force we get,

r= mv/qB

we find

B= mv/er

where m is the mass of electrons

           e is the charge of electrons

B = (9.11×10 ^−31 kg)(89200 m/s)/ (1.60×10 ^−19  C)( 3.23 x 10^-3 m)

  = 157239.164 x 10^-9

  = 0.157 x 10^-3 T

Hence, the strength of the magnetic field required to deflect the beam of electrons is 0.157 x 10^-3 T

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The combination of cloudy skies, quiet winds, and humid air would encourage the greatest temperature shift from sunrise to mid-afternoon.

The location of a place in relation to the sea is the primary factor that affects temperature. Compared to land, the sea both gains and loses heat gradually. Rapid warming and cooling occur on land.

Latitude, height, distance from the sea, and ocean currents are the four unavoidable factors that affect temperature.

Compared to land, oceans warm up and cool down considerably more gradually. This indicates that, for the same latitude and elevation, coastal areas tend to be warmer in the winter and cooler in the summer.

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The greatest temperature change from sunrise to mid-afternoon would be caused by a mix of gloomy skies, calm winds, and humid air.

The main factor affecting temperature is where a place is in proximity to the sea. The sea progressively warms and cools compared to land. On land, there is a sudden warming and cooling.

The four unavoidable factors that affect temperature are latitude, height, distance from the sea, and ocean currents. Oceans warm up and cool down much more gradually than land does. This shows that coastal places typically experience warmer winters and cooler summers for the same latitude and elevation.

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Answer:

\(F=\frac{mgh-\frac{1}{2} mv^2}{d}\)

Explanation:

Step 1: Write out equation

\(\frac{1}{2} mv^2+Fd=mgh\)

Step 2: Subtract FD on both sides

\(\frac{1}{2} mv^2=mgh-Fd\)

Step 3: Subtract mgh on both sides

\(\frac{1}{2} mv^2-mgh=-Fd\)

Step 4: Divide both sides by -d

\(\frac{\frac{1}{2} mv^2-mgh}{-d} =F\)

Step 5: Rewrite

\(F=\frac{mgh-\frac{1}{2} mv^2}{d}\)

The amount of lateral strain in a tension member can be calculated using Poisson's ratio.

To calculate the lateral strain, we can use the equation: ε_lateral = -ν * ε_longitudinal

Where:

ε_lateral = Lateral strain

ν = Poisson's ratio

ε_longitudinal = Longitudinal strain

Poisson's ratio (ν) is a material property that describes the ratio of lateral strain to longitudinal strain when a material is subjected to an axial load. It is defined as the negative ratio of the transverse strain to the longitudinal strain.

Calculating the lateral strain involves determining the longitudinal strain, which can be calculated using the equation:ε_longitudinal = ΔL / L

Where:

ε_longitudinal = Longitudinal strain

ΔL = Change in length of the tension member

L = Original length of the tension member

Once the longitudinal strain is calculated, we can use Poisson's ratio to determine the lateral strain by multiplying the longitudinal strain by the negative value of Poisson's ratio.

It is important to note that the lateral strain is typically very small compared to the longitudinal strain in a tension member, especially for materials with a low Poisson's ratio.

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Answer: When a funnel is dipped into a liquid soap solution, soap molecules from the solution stick to the surface of the funnel and form a thin film. As the film becomes thinner, it reaches a point where it can no longer support its own weight, and gravity causes it to detach from the funnel and form a soap bubble.

When the funnel is removed, the soap bubble remains intact due to the surface tension of the soap film. Soap molecules have hydrophilic (water-attracting) and hydrophobic (water-repelling) ends, which enable them to form a stable film at the surface of the liquid. The surface tension of the soap film creates a force that tries to minimize the surface area of the bubble, which is why soap bubbles tend to form spherical shapes.

However, the soap bubble is not stable and will eventually burst due to a number of factors, such as evaporation of the liquid, changes in temperature or humidity, or contact with other objects. When the soap bubble bursts, the soap film breaks apart and the soap molecules mix with the surrounding air or liquid.

Explanation:

When a funnel is dipped into a soap solution and removed, a soap bubble forms due to the surface tension of the soap solution. As air is blown into it, the bubble expands until it pops when the soap film can't withstand the pressure difference anymore.

When a funnel is dipped into a liquid soap solution and then removed, a soap bubble forms at the end of the funnel. This phenomenon occurs due to a property of liquids known as surface tension. Surface tension is the force that causes the liquid surface to contract, thus forming a shape with the minimum possible area, a sphere.

After the funnel is dipped into the soap solution, a thin film of soap solution forms inside it. When the horn is removed and the air is blown from the other end, the air trapped inside the thin soap film expands to include a bubble.

Eventually, gravity causes the liquid soap to flow downwards, thinning the top of the bubble, and the bubble will pop when the film is too thin to sustain the pressure difference between the inside and outside. So, stating and explaining what happens to the bubble when the funnel is removed can also take into consideration the effect of gravity in this process.

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In order to prevent overloading of any circuit, dual rail electrical supply includes independent tracks and P C B traces that are used to offset voltage sags between various circuits.

Using conductive paths, tracks, or signal traces etched from copper sheets laminated onto a non-conductive substrate, a printed circuit board, or PCB, is used to mechanically support and electrically link electronic components.

Semiconductors are used by practically all inverters to generate a controlled power output. An input voltage is rectified if the source has an ac input.

It is, therefore, the proper response.

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Answer:

B

Explanation: