When fundamental frequency, length and tension is given then the wire's mass per unit length is 9.23 * 10 ^-3 g/m.
What is fundamental frequency?The fundamental frequency is defined as the lowest frequency of a periodic waveform. Fundamental frequency is defined as the average number of oscillations per second and is expressed in Hertz.
Given ; length , l= 0.54m Tension, T = 1373N
Frequency , f = 357 Hz
f= (1/2l)*(√T/m)
m = T/(4l² f²)
= 1373/(2*0.54² * 357²)
m= 9.23 * 10 ^-3 g/m
The wire's mass per unit length in grams/meter is 9.23 * 10 ^-3 g/m.
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An antitank weapon fires a 3.00-kg rocket which acquires a speed of 50.0 m/s after traveling 90.0 cm down a launching tube. Assuming the rocket was accelerated uniformly, what is the average force acted on it?
Answer:
~4166.67 N
Explanation:
We can find the acceleration that the rocket had by using one of the constant acceleration kinematics equations.
List out the motion variables we are given:
v_i = 0 m/sv_f = 50.0 m/sx = 90.0 cm → 0.9 m a = ?Using the equation:
v_f² = v_i² + 2aΔxWe can plug in the known variables and solve for acceleration.
(50.0)² = (0)² + 2a(0.9)Simplify this equation.
2500 = 1.8aDivide both sides by 1.8.
a = 1388.88889 m/s²Now we can use Newton's 2nd Law, F = ma, to determine the force acted on the rocket.
We know the mass of the rocket is 3.00-kg, and its acceleration is 1388.88889 m/s².
F = maF = (3.00)(1388.88889) F = 4166.66667 NThe average force acting on the rocket is about 4166.67 N.
que es el periodo de un pendulo
Answer:
what
Explanation:
Answer:
El periodo del péndulo simple, para oscilaciones de poca amplitud, viene determinado por la longitud del mismo y la gravedad.
Explanation:
No influye la masa del cuerpo que oscila ni la amplitud de la oscilación. Donde: T: Periodo del péndulo.
electrons oscillating with a frequency of 2.0 x 10^10 hertz produce electromamgteic waves. these waves would be classified as
Electromagnetic waves produced by electrons oscillating with a frequency of 2.0 x 10¹⁰ hertz would be classified as radio waves.
Electromagnetic waves are a form of energy that propagate through space in the form of oscillating electric and magnetic fields. These waves are generated by the acceleration or oscillation of charged particles, such as electrons.
The frequency of an electromagnetic wave refers to the number of oscillations or cycles it completes per unit of time. It is usually measured in hertz (Hz), which represents cycles per second. In the given scenario, the electrons are oscillating with a frequency of 2.0 x 10¹⁰ Hz.
Now, let's discuss the classification of electromagnetic waves based on their frequency and wavelength. The electromagnetic spectrum encompasses a wide range of waves, including radio waves, microwaves, infrared waves, visible light, ultraviolet waves, X-rays, and gamma rays.
Radio waves have the longest wavelengths and lowest frequencies among the electromagnetic waves. They typically range from a few centimeters to several kilometers in wavelength. These waves are commonly used for various forms of communication, such as radio and television broadcasting, as well as wireless communication technologies like Wi-Fi and cellular networks.
As the frequency of electromagnetic waves increases, we move through the spectrum, encountering microwaves, infrared waves, visible light, ultraviolet waves, X-rays, and gamma rays in that order. Each segment of the spectrum has distinct properties and applications.
In summary, the electromagnetic waves produced by electrons oscillating with a frequency of 2.0 x 10¹⁰ Hz would be classified as radio waves. These waves have longer wavelengths and lower frequencies compared to other regions of the electromagnetic spectrum and are widely used for communication purposes.
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Yashoda prepares some lemonade on a hot day. She adds 80g of ice at a temperature of zero degrees Celsius to 0.32kg of lemonade. The temperature of the lemonade decreases from 29 degrees Celsius to 8 degrees Celsius and all the ice melts. [Specific latent heat of fusion of ice = 340,000 J/kg, specific heat capacity of water = 4,200 J/kgK].
a)The energy required to melt the ice is
b) The formula used to calculate the energy gained by the melted ice (ice water) from the lemonade is
c)The energy gained by the melted ice (ice water) from the lemonade is
d)Assuming that there is no energy interactions between the lemonade and the surrounding, calculate the energy lost by the lime juice (to the ice and ice water).
e)Calculate the specific heat capacity of the lime juice.
Calculate the specific heat capacity of the lime juice.
The heat of fusion indicates the energy required to convert 1 g of solid to liquid at the same temperature. 250 x 332 Joules are required to melt 250 g of ice. For example, let's look at the energy required to melt 1 kg of ice at 0°C to produce 1 kg of water at 0°C.
For example, consider the energy required to melt 1 kg of ice at 0 °C to produce 1 kg of water at 0 °C. Using the temperature change equation and the water values in Table 1, we find that Q = mLf = 1.0 kg, 334 kJ/kg = 334 kJ is the energy to melt 1 kilogram of ice. The specific heat capacity of lemonade is about the same as that of water c = 4186 J/kg°C.
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(a) The energy needed to melt the ice is 27200 J.
(b) The formula to calculate the energy gained by the melted ice is Q = mCΔT.
(c) The energy gained by the melted ice from lemonade is 2688 J.
(d) The lost energy by the lime juice is 29888 J.
(e) The specific heat capacity of the lime juice is 4.447 J/ g °C.
The mass of ice is 80 grams.
The temperature of lemonade decreases from 29 °C to 8 °C.
The mass of lemonade, M = 0.32 kg = 320 g
The specific latent heat of fusion of ice = 3.4 × 10⁵ J/kg
Specific heat capacity of water = 4.2 × 10³ J/kg °C
a) The heat energy required to melt 1 kg of ice = 3.4 × 10⁵ J
So, the heat energy to melt 1 gram of ice = 340 J
Therefore, the energy required to melt 80 grams of ice = 340 × 80 = 27200 J
b) The formula for the energy gained by the melted ice from the lemonade is:
Q = mCΔT
Where m is the mass, C is the specific heat capacity, and ΔT is the change in temperature.
c) The energy gained by the melting of ice at 0 °C, Q = mCΔT
Q = 80 × 4.2 × ( 8 °C - 0 °C)
Q = 2688 J
d) The energy lost by the lime juice is energy gained by ice and water.
Lost energy by lime juice = 27200 J + 2688 J = 29888 J
e) Let's say C' is the specific heat capacity of the lime juice.
Then,
Q = MC'ΔT
Q = 320 g × C' × ( 29 - 8 )
Q = 6720C'
In equilibrium,
Heat lost = heat gained
6720C' = 29888 J
C' = 4.447 J/ g °C
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3. A current of 6.0 amperes flows through a light bulb when the voltage
difference between the ends of the filament are 110 volts. What is the
resistance?
Answer:
18.3Ω
Explanation:
Resistance can be found using the formula:
Resistance = \(\frac{Voltage}{Current }\)
Voltage = 110 volts
Current = 6.0 amperes
∴ Resistance = \(\frac{110}{6}\)
= 18.3 Ω ( to nearest 3 significant figures)
Rob is a high school student taking both algebra and geometry. Last night he had 27 homework problems combined from the two classes, and he took a total of 90 minutes to do them. If each algebra problem took him 2 minutes and each geometry problem took him 5 minutes, how many algebra problems did he have for homework?
Answer:
The answer is D
Explanation:
The number of algebra problems did he have for homework is 15.
The calculation is as follows:Here we assume x represent the number of algebra problems. So, the number of geometry problems was 27-x and the total working time was ...
2x +5(27 -x) = 90
-3x = 90 -135
-3x = -45
x = 15
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the boundary between a weld metal and an haz depends on the temperature at which metallurgical structure transformation begins for any specific metal and is dependent on welding temperature.
The given statement is true. The boundary between a weld metal and a heat-affected zone depends on the temperature at which metallurgical structure transformation begins for any specific metal and is dependent on welding temperature.
A heat-affected zone (HAZ) is a region in a metal that has been heated to the point where its microstructure and properties change due to welding, brazing, or thermal cutting. The HAZ usually lies between the unaffected base metal (UBM) and the weld metal (WM).
Welding temperature is defined as the temperature at which the welding process takes place, and it is a critical factor that affects the quality of the welded joints. The temperature range of the base metal and filler material is determined by the type of metal being welded and the welding process being used.The temperature at which metallurgical structure transformation occurs is important in welding.
As the temperature increases, the metal's microstructure is altered, and new metallurgical structures are formed. The boundary between the weld metal and the heat-affected zone is determined by the temperature at which metallurgical structure transformation starts, which is determined by the welding temperature. Thus, the given statement is true.
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you have three light bulbs; bulb a has a resistance of 240 q, bulb b has a resistance of 192 q, and bulb c has a resistance of 144 q. each of these bulbs is used for the same amount of time in a setup like that in the drawing. in each case the speed of the rod and the magnetic field strength are the same. rank the setups in descending order, according to how much work the hand in the drawing must do (largest amount of work first).
The correct sequence will be: A, B, C
Given,
Resistance A = 240 Ω
Resistance B = 192 Ω
Resistance C = 144 Ω
We know that the resistance has relations with Current (I) and Voltage (v)
But to find the work done by the hand,
We will apply the formula of the work,
W = VIt
Replacing V with R/I
Work = (R/I)*I*t
Work= R*t
The time given is same.
So here,
Work = Resistance,
By this derivation, the highest resistance will do the highest amount of work.
Therefore, the work done by Resistance A will be the most and then the work by resistance B and then the work by resistance C.
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the ocean contains many plants and protists that can make their own food through photosynthesis. Which need do these organisms get by living near the surface that they cannot get in deep water?
shelter
oxygen
sunlight
Answer:
sunlight
Explanation:
Photosynthesis is made possible by energy from the sun.
leftover ice rich planetesimals are called
what resistance would produce a current of 120 amps from a 6-volt battery?
suppose you are operating a fan and it is stalling. one thing that would not prevent stalling would be to slow down the fan. thicken the air. reduce the pitch of the fan. speed up the fan.
In such a scenario, slowing down the fan or thickening the air would not prevent stalling, as these actions do not address the underlying causes of the issue.
When a fan is stalling, it means that the airflow generated by the fan is disrupted, resulting in a decrease or complete halt in the movement of air.
Slowing down the fan would actually exacerbate the problem since reducing the fan's speed decreases the airflow it can generate. The reduced speed might make it easier for obstructions or other factors to disrupt the airflow, leading to further stalling.
Similarly, thickening the air, such as by increasing the humidity or adding particles to the air, would not prevent stalling. In fact, denser air could potentially increase resistance and hinder the fan's ability to move air effectively, making stalling more likely.
Reducing the pitch of the fan blades, on the other hand, may help alleviate stalling. The pitch of the blades affects how much air the fan can move per rotation. By reducing the pitch, the fan can create less resistance and potentially overcome any obstacles or disruptions in the airflow.
Speeding up the fan can also be an effective way to prevent stalling. Increasing the fan's speed provides more energy to overcome any obstructions and maintain a consistent airflow.
In summary, when a fan is stalling, slowing down the fan or thickening the air would not prevent stalling. However, reducing the pitch of the fan blades or speeding up the fan can help address the underlying issues and maintain proper airflow.
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An alpha particle is moving at a speed of 5.45×10 ^5 m s ^−1 through a velocity selector and mass spectrometer in a direction perpendicular to the shared uniform magnetic field. The electric field strength of the velocity selector is 12.0×10 ^6 N/C. The charge of an alpha particle is 3.22×10 ^−19 C and its mass is 6.64×10 ^−27 kg.
The magnetic field strength required in the mass spectrometer is approximately 22.0 Tesla.
To solve this problem, we can use the principles of the velocity selector and mass spectrometer to determine the conditions necessary for the alpha particle to pass through both devices.
The velocity selector works by applying an electric field perpendicular to the direction of motion of the charged particle, while the mass spectrometer uses a magnetic field to deflect the charged particle in a circular path.
Step 1: Determine the magnetic field strength required in the mass spectrometer.
The velocity selector and the mass spectrometer work together to ensure that only particles with a specific speed and charge pass through. For the alpha particle to pass through, the electric force must balance the magnetic force.
Electric force, Fe = q * E
Magnetic force, Fm = q * v * B
Setting these forces equal to each other: q * E = q * v * B
Simplifying and solving for B: B = E / v
Substituting the given values:
B = (12.0×10^6 N/C) / (5.45×10^5 m/s)
B ≈ 22.0 T
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how many teeth shows signs of decay?
Answer:
what do you mean
Explanation:
Question 15
Experiments performed with light indicate that light exhibits
particle properties, only
wave properties, only
both particle and wave properties
o neither particle nor wave properties
Question 16
Answer:
Both particle and wave properties
Explanation:
Light is defined as a particle and a wave, and even as a combination of a particle and a wave. A unit of light is the photon. Higher energy photons behave like particles and low energy photons behave like waves.
Experiments performed with light indicate that light exhibits both particle and wave properties.
50 kg box rests on a frictionless horizontal surface. Force acts on it and changes its speed to 25 m/s in 5 s, then find the value of force.
Force acts on it and changes its speed to 25 m/s in 5 s, then the value of force will be 250N.
Force: What is it?
The interaction between two objects, which can accelerate an object's motion, is described by the physical quantity force. In the International System of Units (SI), the Newton (N) is its standard unit of measurement.
We can use Newton's second law of motion, which states that the force acting on an object is equal to the object's mass divided by its acceleration, to determine the force's value. In this instance, the box has a starting speed of 0 m/s and a final speed of 25 m/s, which it reaches in 5 seconds. As a result, the box accelerates to:
a = (v_f - v_i) /t
= (25 m/s - 0 m/s) / 5 s
= 5 m/s²
There is no force produced by friction because the box is on a smooth surface. As a result, the only force exerted on the box is the force applied (F). The value of F can now be determined using Newton's second law of motion:
F = m × a
= 50 kg × 5 m/s²
= 250 N
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What is a force that opposes motion between two surfaces that are in contact?
Answer:
Friction is a force that opposes motion.
A kettle does 1 J of work in 1 second. What is the power of the kettle?
Answer:
The power of the kettle is P = 1 watt.
Explanation:
The definition of power is:
Power equals the quotient between work and time, or:
P = w/t.
In this case, we know that the work is:
w = 1J
And the time is:
t = 1 s
Then the power will be:
P = 1J/1s = 1 J/s
Also knowing that:
1 J/s = 1 W
(w is the unit for Watt)
We can conclude that the power of the kettle is:
P = 1 W
A state of being conscious, or aware, of something is called ________________.
Group of answer choices
A. activation
B. mindfulness
C. persistence
D. motivation
Answer:
B or D
Explanation:
A force F~ = Fx ˆı + Fy ˆ acts on a particle that
undergoes a displacement of ~s = sx ˆı + sy ˆ
where Fx = 10 N, Fy = −1 N, sx = 4 m, and
sy = 1 m.
Find the work done by the force on the
particle.
Answer in units of J.
Find the angle between F~ and ~s.
Answer in units of ◦
.
The work done by the force on the particle is 39J and the angle between F and s is 19.7 degree.
What is Force ?An item with mass is pulled or pushed which alters its velocity. A material that has the ability to change a body's rest or motion state is referred to as an external force. It possesses a magnitude and a direction.
Briefing:Force F = (Fx, Fy)
Displacement S = (Sx,Sy)
Fx=10N
Fy=-1N
Sx=4m
Sy=1m
F=(10,-1)N and S=(4,1)m
Work done is calculated by taking dot product of force and displacement vector:
W=F·S
W=10×4 + (-1)×1
W=40+(-1)=39J
W = 39 J
To find angle between F and s:
\(|F|=\sqrt{10^2+(-1)^2}\)
|F| = √101
|S| = √(4² + 1²)
|S| = √17
W = |F| |S| cosθ
39 = √101 √17 cosθ
θ = 19.7.
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whoever hears this I want u to know that I am here for I will always be be and so will God. Things well get better I promise!! YOU have to go through the storm to get to the rainbow. TURN TO GOD he will always help u and he loves you and I do to and so does Jesus u got this. DONT GIVE UP and keep on pushing at the end it will all be worth it I promise AND GIVE YOUR LIFE TO JESUS he will help you
Answer:
Awe you too. God is gonna bless you more than anyone. You bring so much courage to the world and some people need to hear this because they are going through it but people like you are amazing and a blessing. Im thankful for this message and i hope you have the best life the Lord could ever give love. You keep on pushing and you will suceed.Explanation:
Answer:
You too :)
Explanation:
In a uniform electric field, which statement is correct? A All charged particles experience the same force. B All charged particles move with the same velocity. C All electric field lines are directed towards positive charges. D All electric field lines are parallel.
Answer:
D. All electric field lines are parallel in a uniform electric field
If you are holding a stack of books at your waist and then you walk across the room your hands did?
1) efficiency
2) power
3) work
4) no work
Answer:
3. Work
Explanation:
Number 1 isn't correct because you are not using efficiency to hold books and walk across the room.
Number 2 could be correct but isn't in this situation because you use power only to hold the books but not to walk across the room.
Number 4 is not correct because you need to do work to do something.
Explain two scenarios where a large truck can have the same momentum as a small car.
The momentum, p, of any object having mass m and the velocity v is
\(p=mv\cdots(i)\)
Let \(M_L\) and \(M_S\) be the masses of the large truck and the car respectively, and \(V_L\) and V_S be the velocities of the large truck and the car respectively.
So, by using equation (i),
the momentum of the large truck \(= M_LV_L\)
and the momentum of the small car \(= M_SV_S\).
If the large truck has the same momentum as a small car, then the condition is
\(M_LV_L=M_SV_S\cdots(ii)\)
The equation (ii) can be rearranged as
\(\frac {M_L}{M_S}=\frac {V_S}{V_L} \; or \; \frac{M_L}{V_S}=\frac{M_S}{V_L}\)
So, the first scenario:
\(\frac {M_L}{M_S}=\frac {V_S}{V_L}\)
\(\Rhghtarrow M_L:M_S=V_S:V_L\)
So, to have the same momentum, the ratio of mass of truck to the mass of the car must be equal to the ratio of velocity of the car to the velocity of the truck.
The other scenario:
\(\frac{M_L}{V_S}=\frac{M_S}{V_L}\)
\(\Rhghtarrow M_L:V_S= M_S:V_L\)
So, to have the same momentum, the ratio of mass of truck to the velocity of the car must be equal to the ratio of mass of the car to the velocity of the truck.
Acceleration is the change of velocity over some
time. Is it true or false
An experiment is performed in which a current carrying wire is wrapped around an iron rod,
The north pole of a bar magnet is placed near the top of the rod. The magnet moves away
from the rod. Which conclusion can be drawn from this experiment?
Answer:
The sides move away because the rod itslef is magnitized so north and north , south and south don´t attract vice versa.
Explanation:
If a radio wave carries information by changing the amplitude of the transmitted wave, what kind of broadcast might it possibly be?
A) AM radio and analog TV video
B) AM radio only
C) FM radio only
D) FM radio and analog TV sound
HELLLLPPP MMEEEEEE
Which particle moves around the nucleus? (5 points) Electron Molecule Neutron Proton
Answer:
Electrons move around the nueclues and the proton and neutron is found inside the nucleus
Answer:
Electron
Electron is one of the sub-atomic particle that revolves around the nucleus.
They are present in orbits which are just like the orbits of planets in the solar system which are the paths of revolution.
Aesthetics is Multiple Choice an area of psychology that deals with truth. a measurement used in the Middle East, similar to a hectare. the area of medicine concerned with hygiene. an area of philosophy that deals with beauty.
Aesthetics is an area of philosophy that deals with beauty.
Aesthetics is a branch of philosophy that explores the nature of beauty, art, and the principles underlying aesthetic judgments. It investigates questions related to the perception, interpretation, and appreciation of beauty in various forms, including visual arts, literature, music, and other creative expressions. Aesthetics also explores the concepts of taste, artistic value, and the role of emotions and perception in the aesthetic experience. It delves into philosophical inquiries such as the nature of art, the criteria for evaluating artworks, and the relationship between beauty and truth.
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When an electric current passes through a wire a magnetic field is formed, this is called______________.
A) Atomic force
B) Intermolecular force
C) Electromagnetism
D) Nuclear spin