a wire of length l is wrapped into a coil with n turns this coil is then placed in a magnetic field of strength b

Explanation:

speed = wavelength * frequency

         =   3 m  *  12 /s  = 36 m/s

Answer:

for the body to float, the density of the body must be less than or equal to the density of the liquid.

Explanation:

For a block to float in a liquid, the thrust of the liquid must be greater than or equal to the weight of the block.

Weight is

        W = mg

let's use the concept of density

        ρ_body = m / V

        m = ρ_body V

        W = ρ_body V g

The thrust of the body is given by Archimedes' law

        B = ρ_liquid g V_liquid

as the body floats the submerged volume of the liquid is less than or equal to the volume of the block

       ρ_body V g = ρ_liquid g V_liquid

       ρ_body = ρ liquid Vliquido / V_body

As we can see, for the body to float, the density of the body must be less than or equal to the density of the liquid.

Answer:

What are the best flowers? (My opinion)

Explanation:

You're welcome.

Answer:

Tulips,

Lilies,

Lotuses on my opinion...

Hello!

The answer is Gravity. Lets take a look at the options:

A. Nope, this would be if the shuttle was going horizontal.

B. Again, this would be if the shuttle was going horizontal.

C. Yes! This is the only force that is being overcome by using the rocket thrusts to move up.

D. No, the shuttle is using its thrust rocks to push against gravity.

I hope this helps! :)

If A box of mass 210 kg is pulled from rest with a string of tension 1300n inclined at 35° to the horizontal. if the box moved with a speed of 10m/s and the frictional force between the box and surface is 100 n, Then the distance covered by the box is 10.89 meters.

To calculate the distance covered by the box, we need to analyze the forces acting on it and apply the work-energy principle.

Given:

Mass of the box, m = 210 kg

Tension in the string, T = 1300 N

The angle of inclination, θ = 35°

Frictional force, f = 100 N

Initial speed, u = 0 m/s

Final speed, v = 10 m/s

First, let's resolve the tension force into components parallel and perpendicular to the incline. The parallel component of the tension force can be calculated as:

T_parallel = T * cos(θ)

Next, let's calculate the net force acting on the box along the incline. The net force is given by:

Net force = T_parallel - f

Now, using Newton's second law, we can calculate the acceleration (a) of the box:

Net force = m * a

From the given information, we have the final velocity (v), initial velocity (u), and acceleration (a). We can use the following kinematic equation to calculate the distance covered (s):

v^2 = u^2 + 2as

Rearranging the equation, we get:

s = (v^2 - u^2) / (2a)

Now, let's plug in the given values and calculate the distance covered:

T_parallel = 1300 N * cos(35°) ≈ 1067.35 N

Net force = 1067.35 N - 100 N = 967.35 N

a = (967.35 N) / (210 kg) ≈ 4.61 m/s^2

s = (10 m/s)^2 - (0 m/s)^2 / (2 * 4.61 m/s^2) ≈ 10.89 m

Therefore, the distance covered by the box is approximately 10.89 meters.

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Grouping data refers to the process of categorizing or organizing data based on specific criteria or attributes.

It involves grouping similar data points together to gain a better understanding of patterns, relationships, and trends within the dataset. By grouping data, you can simplify complex information and derive meaningful insights from large amounts of data. The purpose of grouping data is to create subsets or clusters that share common characteristics.

This enables easier analysis, summarization, and comparison of data within each group. Grouping can be performed on various types of data, such as numerical, categorical, or time-based data. Grouping data allows for the exploration of data at different levels of granularity.

For example, you can group sales data by region to analyze regional performance, or group customer data by demographics to identify specific customer segments. This process helps in identifying outliers, detecting patterns, and making data-driven decisions.

Common techniques for grouping data include using functions like GROUP BY in SQL or utilizing data visualization tools to create charts or graphs that illustrate the grouped data. Grouping can be applied in various fields, such as marketing, finance, healthcare, and research, to uncover insights and support decision-making processes.

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Answer:

The weight required to stretch a wire can be calculated using the formula:

W = (π/4) x d^2 x L x S

where:

d = diameter of the wire

L = length of the wire

S = stress applied to the wire

π = pi (3.14)

In this case, the wire has a diameter of 1.0 millimeters and a length of 1.0 meters. We want to stretch it by 3.0 millimeters, which means the stress applied to the wire is:

S = ΔL / L = 3.0 / 1000 = 0.003

Now we can plug in the values and calculate the weight required:

W = (π/4) x (1.0)^2 x 1.0 x 0.003

W = 0.0002355 kg or 0.2355 grams

Therefore, we need to add 0.2355 grams of weight to the free end of the wire to stretch it by 3.0 millimeters.

Answer:

a

e(k) =  \frac{2a}{c}  *  sin (\frac{k*a}{2} )

b

G_{v} =  \frac{d e(k ) }{dk }  =  \frac{a^2}{c}  *  cos (\frac{k* a}{2} )

Explanation:

From the question we are told that

    The  velocity  of transverse waves in a crystal of atomic separation is  

                  \(b_y  = c \frac{sin (\frac{k*a}{2} )}{\frac{k*a}{2} }\)

Generally the dispersion relation is mathematically represented as

            \(e(k) =  b_y  *  k\)

=>    \(e(k) = c  \frac{sin(\frac{k*a}{2} ) }{ \frac{k*a}{2} }  *  k\)

=>    \(e(k) =   c *  \frac{sin (\frac{k_a}{2} )}{ \frac{a}{2} }\)

=>    \(e(k) =  \frac{2a}{c}  *  sin (\frac{k*a}{2} )\)

Generally the group velocity is mathematically represented as

          \(G_{v} =  \frac{d e(k ) }{dk }  =  \frac{a^2}{c}  *  cos (\frac{k* a}{2} ) \)

0.002355 N-m torque must the motor deliver if the turntable is to reach its angular speed in 2.20 revolutions starting from rest

Torque is a measure of the twisting force that causes rotational motion. It is calculated by multiplying the force applied to an object by the distance from the axis of rotation at which the force is applied.

Given:

Angular speed, ω = 3.49 rad/s

Number of revolutions, N = 2.20 rev

Diameter of disk, D = 30.5 cm = 0.305 m

Mass of disk, m = 0.240 kg

The moment of inertia of a uniform disk about its center is (1/2) * m * r^2, where r is the radius of the disk. Here, r = D/2 = 0.1525 m.

Moment of inertia, I = (1/2) * m * r^2 = (1/2) * 0.240 kg * (0.1525 m)^2 = 0.002198 J-s^2/rad

The torque required to bring the disk to its angular speed can be found using the formula:

τ = I * α

where α is the angular acceleration of the disk. Since the disk starts from rest, we have:

α = ω^2 / (2 * π * N)

where π is the constant pi. Substituting the given values, we get:

α = (3.49 rad/s)^2 / (2 * π * 2.20 rev) = 1.071 rad/s^2

Therefore, the torque required is:

τ = I * α = 0.002198 J-s^2/rad * 1.071 rad/s^2 = 0.002355 N-m

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Answer:

AN ELASTIC COLLISION IS SAFER

Explanation:

IT'S BECAUSE THE MOVEMENT IS PRESERVED. YEN AN ELASTIC

COLLISION, THE ELASTIC BODY ABSORBS SOME OF THE MOVEMENT.

THIS CAUSES THE CAR TO SLOW DOWN MORE SLOWLY THAN IN AN

INELASTIC COLLISION WHERE IT DECELERATES FASTER.

ANYWAY I LEAVE YOU THE LINK

(THEY ALREADY DELETED THE ENGLISH SITE, BUT YOU CAN USE

TRANSLATOR):

https://gscourses.thinkific.com

Answer:

Light comes in different colors like radio, ultra violet, gamma-ray, etc, and they are invisible to the bare eye

Explanation:

The final velocity after 6.0 s is

1304.2 .

What is velocity?

velocityis the most fundamental quantity of physics . Work is said to be done when a force applied to an object cause a displacement of a object.

Solution -

As per the given-

Mass of runner m = 74kg

initial velocity of runner u=4.8 m/s

final velocity of runner v =0

Coefficient of friction ¥=0.7

Let's d be the distance moved by runner till the stop.

a- mechanical energy lost due to friction

As friction does negetive work causing the runner to stop.

As we know,

Mechanical energy lost= Kinetic energy of runner

Mechanical energy lost =

1/2 mv^2 = 1/2 ×74×4.8^2=852.2

Distance move by runner-

Work done by friction = mechanical energy lost

-¥×mg×d =852.2 j

-0.7×74×9.8×d = -491.2

Solving the equation we get

1304.2.

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Answer:

C) Momentum

Explanation:

Refers to an objects mass in motion.

The net force on particle q₂ is 1.05 x 10¹³ N, directed towards particle q1.

To find the net force on particle q₂, we need to calculate the force between q₁ and q₂, and the force between q₂ and q₃, and then add these two forces together.

The force between two point charges can be calculated using Coulomb's law, which states that

F = k × q₁× q₂ / r²

where F is the force, k is Coulomb's constant (9.0 x 10⁹ N m² / C²), q₁ and q₂ are the magnitudes of the charges, and r is the distance between the charges.

The force between q₁ and q₂ is

F₁ = k × q₁ × q₂ / r₁²

where r₁ = 0.10 m.

Substituting the values, we get

F₁ = 9.0 x 10⁹ N m² / C²  × 8.0 C  × 3.5 C / (0.10 m)² = 2.52 x 10¹³ N

The force between q₂ and q₃ is

F₂ = k  × q₂  × q₃ / r₂²

where r₂ = 0.15 m.

Substituting the values, we get

F₂ = 9.0 x 10⁹ N m² / C²  × 3.5 C  × (-3.5 C) / (0.15 m)² = -1.47 x 10¹³ N

Note that the negative sign indicates that the force is attractive, since q₂ and q₃ have opposite signs.

The net force on q₂ is the vector sum of F₁ and F₂

\(F_{net}\) = F₁ + F₂ = 2.52 x 10¹³ N - 1.47 x 10¹³ N = 1.05 x 10³ N

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The frequency of the wave is 0.33 Hz.

The celerity of the wave is wave is 4.95 m/s.

As the celerity of the wave increases, the wavelength increases.

The frequency of the wave is calculated by applying the following formula.

v = fλ

where;

f = 1 / T

f = 1 / 3 s

f = 0.33 Hz

The celerity of the wave is wave is calculated as follows;

v = fλ

v = ( 0.33 Hz ) x ( 15 m )

v = 4.95 m/s

λ = v / f

Thus, from the above equation as the celerity of the wave increases, the wavelength increases.

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The correct answer is Option B. The statement "they have the same A-number but different Z-number" is true .

Atoms of the same element only differ because one of the atoms has more electrons, making it an ion.

This difference does not affect the mass of the atom, which is determined by the sum of its protons and neutrons, represented by the atomic mass or A-number.

The number of protons in an atom is called the atomic number or Z-number.

The Z-number of an element is unique to it. All the atoms of a given element have the same number of protons.

Thus, for example, all carbon atoms have six protons, making the Z-number of carbon 6.

However, different isotopes of an element can have different numbers of neutrons.

This means that they have a different atomic mass or A-number.

Therefore, they have the same A-number but different Z-number.

Therefore the correct Option is B.

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Answer:

7.84 m/s

Explanation:

Height, h = 2 m

Initial velocity, u = 10 m/s

Angle, A = 80°

(a) Let the time taken to go to the net is t.

Use second equation of motion

\(h = u t + 0.5 at^2\\\\- 2 = - 10 sin 80 t - 4.9 t^2\\\\4.9 t^2 + 9.8 t - 2 = 0 \\\\t= \frac{- 9.8\pm\sqrt{9.8^2 + 4\times 4.9\times 2}}{9.8}\\\\t = \frac{- 9.8 \pm 11.6}{9.8}\\\\t = - 2.2 s , 0.2 s\)

Time cannot be negative.

So, t = 0.2 s

The vertical velocity at t = 0.2 s is

v = u + at

v = 10 sin 80 - 9.8 x0.2

v = 9.8 - 1.96 = 7.84 m/s

If a wave has an amplitude of 0.0800 m and is moving 7.33 m/s. The

wavelength of the wave is 1.69m.

The wavelength of a wave can be determined using the equation:

Wavelength = velocity / frequency

To determine the frequency we need to calculate the reciprocal of the time it takes for one complete oscillation.

frequency = 1 / time

frequency = 1 / 0.230

frequency ≈ 4.35 Hz

Substitute the values into the wavelength equation:

wavelength = velocity / frequency

wavelength = 7.33 / 4.35

wavelength ≈ 1.69m

Therefore the wavelength of the wave is approximately 1.69 meters.

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Answer:

100

w=f*s

20*5=100....

100 Joules of work is done on the cart.

Work done by a force is defined as the product of the displacement and the component of the applied force on the object in the direction of displacement. When we push a block with some force, the body moves with some acceleration, so it is called work done.

Work done is expressed as W=Fd and its unit is joules which can be defined as the amount of work done by a force in Newton is applied to an object, as a result of which it is displaced in meter.

For above given information,

Force= 20 N

Distance= 5 m

So, work done= 20*5= 100 Joules

Thus, 100 Joules of work is done on the cart.

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Answer:

6 gallons

Explanation:

At 30 mph, the fuel mileage is 25 mpg.

After 5 hours, the distance traveled is:

30 mi/hr × 5 hr = 150 mi

The amount of gas used is:

150 mi × (1 gal / 25 mi) = 6 gal

Answer:

Approximately \(-15.37m/s^2\)

Explanation:

The acceleration can be found using the formula:

\(x_{f} = x_{i} + v_{i} (t)+\frac{1}{2} (a)(t^{2} )\)

The work is as shown:

\(45m = 0 + 39 m/s (3.3s)+\frac{1}{2} a(3.3s)^2\)

\(45m=128.7m + 5.445s^2 a\)

\(-83.7m=5.445s^2a\)

\(a = -15.37190083m/s^2\)

a is about -15.37\(m/s^2\)

This question is incomplete, the complete question is;

The entropy of an ?-ideal gas changes in the following way as a function of temperature and volume:

ΔS = nRln(V\(_f\)/V\(_i\)) + ∝nRln(T\(_f\)/T\(_i\))

For an adiabatic process, the change in T is determined by the change in V. In this problem you will compute the contributions to S from the V and T terms separately, then add them up to find the total entropy change for an adiabatic process.

Argon gas, initially at pressure 100 kPa and temperature 300 K, is allowed to expand adiabatically from 0.01 m³ to 0.026 m³ while doing work on a piston.

1) What is the change in entropy due to the volume change alone, ignoring any effects of changing internal energy? ΔS = ? J/K

2) For this adiabatic expansion, what is the final temperature?  T\(_f\) =  ? K

Answer:

1) the change in entropy due to the volume change alone, ignoring any effects of changing internal energy is 3.185 J/K.

2) the final temperature is 158.66 K

Explanation:

Given the data in the question;

ΔS = nRln(V\(_f\)/V\(_i\)) + ∝nRln(T\(_f\)/T\(_i\))

P\(_i\) = 100 kPa = 100000 Pa

V\(_i\) = 0.01 m³

V\(_f\) = 0.026 m³

T\(_i\) = 300 K

1)  the change in entropy due to the volume change alone

from the question; ΔS = nRln(V\(_f\)/V\(_i\)) + ∝nRln(T\(_f\)/T\(_i\))

so change in entropy due to the volume change alone is;

ΔS = nRln(V\(_f\)/V\(_i\))

we know that, from ideal gas law; PV = nRT

so, nR = P\(_i\)V\(_i\)/T\(_i\)  ---- let this be equation 1

∴ ΔS = P\(_i\)V\(_i\)/T\(_i\) × ln(V\(_f\)/V\(_i\))

we substitute

ΔS = [( 100000 Pa ×  0.01 m³) / 300 K ] × ln(0.026m³ / 0.01m³ )

ΔS = 3.185 J/K  

Therefore, the change in entropy due to the volume change alone, ignoring any effects of changing internal energy is 3.185 J/K.

2)  Final temperature

we know that, in an adiabatic expansion;

\(PV^Y\) = K

where Y = 5/3

so

\(P_i\)\(V_i^{(5/3)\) = \(P_f\)\(V_f^{(5/3)\)

\(P_f\) = \(P_i\)\(( \frac{V_i}{V_f})^{(5/3)\)

we substitute

\(P_f\) = ( 100000 Pa) \(( \frac{0.01 m^3}{0.026 m^3})^{(5/3)\)

\(P_f\) = 20341.255 Pa

Also from ideal gas law;

PV = nRT

T = PV / nR

so

T\(_f\) = P\(_f\)V\(_f\) / nR

but from equation 1; nR = PV/T

so

T\(_f\) = (P\(_f\)V\(_f\)) / (P\(_i\)V\(_i\)/T\(_i\) )

T\(_f\) = ( P\(_f\)V\(_f\)T\(_i\) / P\(_i\)V\(_i\) )

we substitute

T\(_f\) = ( 20341.255 Pa × 0.026 m³ ×  300 K) / 100000 Pa × 0.01 m³ )

T\(_f\) = 158.66 K

Therefore, the final temperature is 158.66 K

The correct option is C, the velocity between 2s and 4s is 7 meters per second.

Here we have the graph of the velocity of a T-Rex as function of time in seconds.

Here we need to find the average value between 2 seconds and 4 seconds.

At 2 seconds, the graph says that the velocity is 7m/s

And we can see an horizontal line that ends at 4s, so the veloicty at 4 seconds is 7m/s

Then the average velocity in that interval is that one (because it is constant)

Then the correct option is C.

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The activation energy required to light a match is obtained by the chemical energy transferred into the thermal energy. When the match stick and head are rubbed together, the friction force is developed and hence, lightning occurs.

Activation energy is the minimum amount of energy available for the chemical reaction to occur. It involves the Breaking of adhesion between the match head and the striking surface causing the particle to vibrate.

The energy of vibration provides the activation energy required to light the match. The thermal energy of the vibrating particles on the head of the match is transferred from cool to hot regions.

As the head moves across the striking surface, its particles adhere to the surface for a short period of time and produce heat and light energy.

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Answer:

\(h_m=25.8\ m\)

Explanation:

Vertical Launch Upwards

In a vertical launch upwards, an object is launched vertically up without taking into consideration friction with the air.

If vo is the initial speed and g is the acceleration of gravity, the maximum height reached by the object is given by:

\(\displaystyle h_m=\frac{v_o^2}{2g}\)

The tennis ball was thrown straight up with a speed of v0=22.5 m/s. The acceleration of gravity is g=9.81\ m/s^2, thus:

\(\displaystyle h_m=\frac{22.5^2}{2\cdot 9.81}\)

\(\mathbf{h_m=25.8\ m}\)

Answer:

4.6 s

Explanation:

the period of a mass-spring system with the  characteristics can be calculated using the formula T = 2π√(m/k), where m is the mass of the object and k is the spring constant. the period of the mass-spring system with the given characteristics is approximately 3.14 seconds.

A mass-spring system has the following characteristics: A spring that is initially stretched or compressed has an oscillatory motion around its equilibrium position. This is referred to as a mass-spring system.The period of the mass-spring system is the time it takes for one complete cycle, including compression and extension. The period is given by the equation

`T = 2π * √(m/k)`,

where T is the period, m is the mass attached to the spring, and k is the spring constant. Let's consider an example to better understand this formula: Suppose a mass of 5 kg is attached to a spring with a spring constant of 20 N/m. What is the period of the system?

T = 2π * √(m/k) = 2π * √(5/20) = 2π * √(1/4) = 2π * (1/2) = π ≈ 3.14s

Therefore, the period of the mass-spring system with the given characteristics is approximately 3.14 seconds.

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The first law states that the internal energy change of that system is given by Q − W . Since added heat increases the internal energy of a system, Q is positive when added to the system and negative when removed from the system.

Answer:

Explanation:

Centripetal acceleration is expressed as shown:

a = v²/r

v is the velocity

r is the radius

If the length of the sling is 90cm, hence the circumference of the circular path is 90cm

Since C = 2πr

0.9 = 2πr

r = 0.9/2π

r = 0.9/2(3.14)

r = 0.9/6.28

r = 0.143m

Get the centripetal acceleration:

a = 90²/0.143

a = 56,643.36m/s²

Hence the the centripetal  acceleration of the stone is  56,643.36m/s²

Answer:

I had to put the blocks on the weigher, and write down how much they weigh. I had to put the blocks next to the ruler to measure the height.

Explanation:

u would change wright to write because wright can be a name and if u change it to write that would be correct because u are actually writing something down. so it would be right because u are writing something down