a white pool ball (mass 0.17 kg) moving 13.2 m/s hits a red pool ball that is initially stationary and has a mass of 0.15 kg. the red ball gains a speed of 9 m/s to the right. what is the final velocity of the white ball, to the nearest 0.01 m/s?

c                                                            

Explanation: c because you said it lol

Answer:

c

Explanation:

Answer:

not sure just need points

Explanation:

a+b+c

The acceleration rate of a car that weighs 1189 kg and takes 11.3 seconds to reach 60 mph is 5.3 m/s2. Acceleration is a term used to describe how quickly an object's velocity changes over time.

There are accelerations in vector quantities (in that they have magnitude and direction). The acceleration of an object depends on the direction of the net force acting on it. how much quicker than usual a thing is going. The velocity of an item in motion is a function of time and quantifies how quickly its position modifies with respect to a frame of reference. A moving object's velocity indicates both its direction and speed of motion.

A=(v-U)/t, where A=(0-60)/11.3, and A=(60-11.3 = 5.3 m/s2).

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For a car that weighs 1189 kg and accelerates from 0 to 60 in 11.3 seconds. The vehicle will accelerate at 5.3 m/s2. This is the correct answer.

An object has positive acceleration if it is accelerating and travelling in the right direction. Positive acceleration can be demonstrated by an example of a speeding vehicle. The acceleration in this case occurs in the same direction as the vehicle's motion, which is forward and speeding up.

In terms of running, the body accelerates whenever it begins, picks up pace, or changes course. Given how frequently the rate of velocity must change and how frequently there are direction changes in most sports, it is obvious that acceleration is important for athletic speed performance.

Acceleration, a = v-u/t where v = final velocity, u = initial velocity and t = time taken

a = 60 - 0/11.3

a = 5.3 s²

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The differential equation which describes the temperature of the object over time is;

dH/dt = -k (H-S), where k = 0.97. The solution to this differential equation is given by H(t) = S + 65e^(-0.97t).

Newton’s law of heating and cooling is an application of the first law of thermodynamics. The law suggests that the rate of change of temperature of an object is proportional to the difference between its temperature and the temperature of the surroundings.

A warm object is placed in a refrigerator where the surrounding temperature is cooler, and the temperature of the object decreases. This phenomenon can be explained using differential equations. Given that H(t) is the temperature of the object being cooled and S is the surrounding temperature, the differential equation which describes the temperature of the object over time is given by;dH/dt = -k (H-S)

where k is the constant of proportionality.To solve this differential equation, we can use separation of variables, such that;

dH/dt = -k (H-S)dH/(H-S) = -k dt

Integrating both sides, we get;ln|H-S| = -kt + Cwhere C is the constant of integration.Rearranging, we have;

|H-S| = e^(-kt+C)

At time, t = 0, H = 100 and after 30 minutes the object is 75 degrees; t = 0.5 hours, H = 75. We can use these values to solve for C and k as follows;

|100-35| = e^(C) => 65 = e^(C)     …(1)

and|75-35| = e^(-0.5k+C) => 40 = e^(C) e^(-0.5k) => e^(-0.5k) = 40/65 => e^(-0.5k) = 8/13 => -0.5k = ln(8/13) => k = -2ln(8/13) => k = 0.97    …(2)

Substituting equation (1) into (2), we get;H-S = 65e^(-0.97t)  =>  H(t) = S + 65e^(-0.97t)

Therefore, the differential equation which describes the temperature of the object over time is;dH/dt = -k (H-S), where k = 0.97.

The solution to this differential equation is given by H(t) = S + 65e^(-0.97t).

The differential equation which describes the temperature of the object over time is;

dH/dt = -k (H-S), where k = 0.97. The solution to this differential equation is given by H(t) = S + 65e^(-0.97t).

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Your motorbike breaks down five Km from your home. You use 400 N force for the entire 60 minutes that it takes you to push this motorbike home. The total power is 555.55 Watts.

The quantity of energy transferred or transformed per unit of time is known as power. The watt, or one joule per second, is the unit of power in the International System of Units. A scalar quantity is power.

Power is related to other factors; for instance, the power required to move a ground vehicle is equal to the product of the vehicle's velocity, traction force on its wheels, and aerodynamic drag. A motor's output power is calculated by multiplying its torque output by the angular velocity of its output shaft. The power lost by an electrical component in a circuit is also a function of the voltage across the component and the current that flows through it.

P =\(\frac{W}{t}\)

where W is work done and t is time.

t= 60min= 60 × 60= 3600 sec

W = F × S

where

F is force and S is displacement

Substituting the values,

P = 555.55 W

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Therefore, the refractive index of gasoline is 1.43.

The refractive index of gasoline can be calculated using the formula Refractive index (n) = Speed of light in vacuum (c) / Speed of light in the medium (v).


To find the refractive index of gasoline, we'll use the formula:
refractive index = speed of light in vacuum / speed of light in gasoline
Here, c = 3.00E+08 m/s and v = 2.10E+08 m/s.

n = (3.00E+08 m/s) / (2.10E+08 m/s) = 1.43

Substituting the given values:

refractive index = 3.00E+08 m/s / 2.10E+08 m/s

refractive index = 1.43
So, the refractive index of gasoline is 1.43.

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Answer:

1)  ΔE = -800 J, 2) ΔE = 200 J, 3)  ΔE = -200 J, 4) ΔE = 800 J

Explanation:

For this exercise let's use the first law of thermodynamics

          ΔE = Q + W

Where we will apply this expression to several cases

1) output Q = 500 J and does work of W = 300 J.

The two processes involve an energy output

         ΔE = - 500 - 300

         ΔE = -800 J

Therefore, the internal energy of the gas decreases by this amount,

2) enter Q = 500J and do work of W = 300 J

         Positive heat is added and does negative work

         ΔE = 500 - 300

         ΔE = 200 J

3) they leave Q = 500 J and do (work on the gas) W = 300J

negative heat and positive work come out

          ΔE = -500 + 300

          ΔE = -200 J

4) heat enters Q = 500 J, work on gas W = 300 J

both positive

         ΔE = 500 + 300

         ΔE = 800 J

Answer:

4 target heart rate. is the answer

Explanation:

hope its right

The magnetism of a piece of magnetized iron can be weakened by demagnetization.

Magnetization refers to the magnetic moment of a material that is magnetized. Magnetic materials are made up of tiny magnetic dipoles, which are arranged randomly in a typical magnetic substance. However, these dipoles' directions can be aligned with one another by applying a strong magnetic field. In a magnetic substance, this causes the magnetic moment to increase. The degree of magnetization that a substance can achieve when placed in a magnetic field is referred to as magnetization.

Demagnetization is the process by which a magnet loses its magnetism. Demagnetization of a magnet can be accomplished by exposing it to a sufficiently strong magnetic field in the opposite direction to the one that magnetized it. As a result, the magnet's magnetic domains are rearranged and randomized. This effect causes the magnet's magnetic moment to diminish until it reaches zero, rendering it non-magnetic.

The direction of the magnetic field is important because it determines whether or not a material is magnetized. A magnetic field applied to a magnetic material in one direction is responsible for magnetizing the material in that direction, whereas a magnetic field in the opposite direction is responsible for demagnetizing it.

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The resolution of the same telescope at 600 nm is 3 arcseconds

The resolving power of a telescope is directly proportional to the wavelength of light. The resolution is inversely proportional to the wavelength squared. The Rayleigh criterion states that two objects are resolvable if the distance between them is greater than the radius of the diffraction pattern of one object, given by D = 1.22λ/D, where D is the aperture of the telescope (diameter), λ is the wavelength of the light, and θ is the angular separation between the objects.

According to Rayleigh's criterion,

θ = 1.22 λ/D

In the first case:

θ₁ = 1.22 (300nm) / D

θ₁ = 1.46/D

In the second case:

θ₂ = 1.22 (600nm) / D

θ₂ = 2.92/D

We know that the ratio of the resolutions is given as:

R₂ / R₁ = λ₁ / λ₂

Where,

R₁ = 1.5 arcseconds

R₂ = resolution at 600nm wavelength = λ₁ / λ₂

R₂ = λ₁ / λ₂ * R₁ = (300nm) / (600nm) * (1.5 arcseconds) = 0.75 * 1.5 arcseconds = 1.125 arcseconds

Therefore, the resolution of the telescope at 600nm is 3 arcseconds (rounded to one decimal place).

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(a)

i. the voltage between a and b is zero.

ii.  Voltage between points b and c is \(2.25 * 10^6 V\)

iii.  Voltage between points c and infinity \(2.25 * 10^6 V\)

b.)  (i) Point a is at a higher potential than point b.

(ii) Point c is at a higher potential than point b.

(iii) Point a is at a higher potential than point c.

c.  If the charge on the shell were -150.0 μC, the magnitudes of the voltages would remain the same, but the signs would change

(a)

(i) Voltage between points a and b:

We know that  point b is inside the spherical shell and  the voltage between a and b is zero.

(ii) Voltage between points b and c:

V = k * (Q / r),

Q = 150.0 μC and r = 60.0 cm = 0.6 m:

V = \((9 * 10^9 Nm^2/C^2) * (150.0 * 10^-^6 C) / 0.6 m\)

V = \(2.25 * 10^6 V\)

(iii) Voltage between point c and infinity:

The voltage at point c is the same as the voltage between points b and c = \(2.25 * 10^6 V.\)

(iv) Voltage between points a and c:

V = k * (Q / r), where Q = 150.0 μC and r = 60.0 cm = 0.6 m:

V = (\(9 * 10^9 Nm^2/C^2) * (150.0 * 10^-^6 C) / 0.25 m\)

V =\(6.75 * 10^6 V\)

(b)

(i) Point a is at a higher potential than point b.

(ii) Point c is at a higher potential than point b.

(iii) Point a is at a higher potential than point c.

(c) If the charge on the shell were -150.0 μC, the magnitudes of the voltages would remain the same, but the signs would change.

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To calculate the surface tension of the liquid with a density of 1,040 kg/m3 that rises to a height of 1.8 cm in a 1.0-mm diameter capillary tube, we can use the Jurin's Law formula:
Surface tension (γ) = (density × gravity × height × radius) / (2 × cos(contact angle))
First, we need to convert the given units to meters:
Height: 1.8 cm = 0.018 m
Diameter: 1.0 mm = 0.001 m
Radius = Diameter / 2 = 0.0005 m
Assuming a contact angle of zero, cos(0) = 1. Using the standard gravitational constant g = 9.81 m/s², we can now calculate the surface tension:
γ = (1,040 kg/m3 × 9.81 m/s² × 0.018 m × 0.0005 m) / (2 × 1)
γ = 0.091665 kg m/s² or N/m
Therefore, the surface tension of the liquid is approximately 0.0917 N/m.

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The persuasion strategy that takes advantage of the speaker’s credibility is ethos. Ethos refers to the credibility and trustworthiness of the speaker or writer.

Ethos is used to convince and persuade the audience to accept the author’s claims as being valid or accurate. It is also a means of convincing the audience to take the author’s stance on a given issue seriously.

Ethos is one of the three pillars of persuasion, along with pathos and logos. Ethos, which stands for ethical or moral appeal, is a persuasion technique that relies on the credibility and trustworthiness of the speaker. A speaker or writer may use ethos to persuade an audience to accept his or her arguments by showing that he or she is knowledgeable, honest, and trustworthy.

Ethos appeals are commonly used in persuasive writing, especially in academic and professional writing, to establish the author's credibility and gain the reader's trust. Examples of ethos include using expert opinions, citing research studies, using personal anecdotes, or sharing experiences.

Using ethos helps to establish the speaker's authority and expertise, which can lead the audience to be more receptive to the main answer or argument presented.

Ethos is a powerful tool in persuasive writing, as it helps to establish the writer's credibility and encourages the reader to accept his or her argument.

In conclusion, the persuasion strategy that takes advantage of the speaker’s credibility is ethos.

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When light is emitted from an atom, it is the result of an electron in the atom moving from a higher energy level to a lower energy level.

This process is called "atomic emission" and it results in the release of energy in the form of a photon, or a particle of light.

Here is a step-by-step explanation of how atomic emission occurs:

1. An electron in an atom absorbs energy, causing it to move from a lower energy level to a higher energy level. This is called "atomic excitation."
2. The electron is now in an excited state, which is unstable.
3. The electron eventually returns to a lower energy level, releasing the excess energy it had absorbed.
4. This release of energy is in the form of a photon, or a particle of light.
5. The photon is emitted from the atom, resulting in atomic emission.

So, in summary, when light is emitted from an atom, it is the result of an electron moving from a higher energy level to a lower energy level and releasing energy in the form of a photon.

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Based on Newton's first law of motion, when the space X falcon 9 was launched into the space, it will continue moving at that speed unless an external force acts on it.

The rate of change of momentum of the space X falcon 9 is directly proportional to the applied force of the engine, this is based on Newton's second law of motion.

Finally, according to Newton's third law of motion, the applied force on the space X falcon 9 is equal and opposite to reaction of the space X falcon.

Newton's first law states that if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force.

Newton's second law describes the affect of net force and mass upon the acceleration of an object.

Newton's third law states that when two bodies interact, they apply forces to one another that are equal in magnitude and opposite in direction.

Thus, based on Newton's first law of motion, when the space X falcon 9 was launched into the space, it will continue moving at that speed unless an external force acts on it.

The rate of change of momentum of the space X falcon 9 is directly proportional to the applied force of the engine, this is based on Newton's second law of motion.

Finally, according to Newton's third law of motion, the applied force on the space X falcon 9 is equal and opposite to reaction of the space X falcon.

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The force responsible for the acceleration of the crate is the frictional force between the crate and the bed of the truck.

When the truck accelerates, the crate tends to remain at rest due to inertia. However, the frictional force between the crate and the bed of the truck acts in the forward direction, allowing the crate to accelerate along with the truck.

This frictional force is a result of the interaction between the surfaces of the crate and the truck bed. Without this frictional force, the crate would slide or move independently from the truck's acceleration.

The frictional force arises due to the microscopically rough surfaces of the crate and the truck bed. As the two surfaces are pressed against each other, intermolecular forces come into play, resulting in the generation of the frictional force

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Answer:

1. A: acceleration

2. D: torsion

3.  C: gravitational force or possibly B: frictional force

4. B: noncontact force

5. B: distance: displacement

6. C: speed

The time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.

The cooling law is given by:

$$\frac{dQ}{dt}=-k(T-T_0)$$

where Q is the heat in the object, t is the time taken, T is the temperature of the object at time t, T0 is the temperature of the environment and k is a constant known as the cooling constant.

We need to find the time it takes for the coffee to reach a drinking temperature of 73°C given that its initial temperature is 93°C.

Therefore, we need to find the time it takes for the coffee to cool down from 93°C to 73°C when placed in a room temperature of 18°C.

Let’s assume that the heat energy that is lost by the coffee is equal to the heat energy gained by the environment. We can express this as:

dQ = - dQ where dQ is the heat energy gained by the environment.

We can substitute dQ with C(T-T0) where C is the specific heat capacity of the object.

We can rearrange the equation as follows:

$$-\frac{dQ}{dt}=k(T-T_0)$$

$$-\frac{d}{dt}C(T-T_0)=k(T-T_0)$$

$$\frac{d}{dt}T=-k(T-T_0)$$

The differential equation above can be solved using separation of variables as follows:

$$\frac{d}{dt}\ln(T-T_0)=-k$$

$$\ln(T-T_0)=-kt+c_1$$

$$T-T_0=e^{-kt+c_1}$$

$$T=T_0+Ce^{-kt}$$

where C = e^(c1).

We can now use the values given to find the specific value of C which is the temperature difference when t=0, that is, the temperature difference between the initial temperature of the coffee and the room temperature.

$$T=T_0+Ce^{-kt}$$

$$73=18+C\cdot e^{-0.09t}$$

$$55=C\cdot e^{-0.09t}$$

$$C=55e^{0.09t}$$

$$T=18+55e^{0.09t}$$

We can now solve for the value of t when T=93 as follows:

$$93=18+55e^{0.09t}$$

$$e^{0.09t}=\frac{93-18}{55}$$

$$e^{0.09t}=1.3636$$

$$t=\frac{\ln(1.3636)}{0.09}$$

Using a calculator, we can find that the time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.

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Answer:

Fault lines

Explanation:

Answer:

Time, t = 3.2 ms

Explanation:

It is given that,

Mass of basketball, m = 0.622 kg

Initial velocity, u = 4.23 m/s

Final velocity, v = 3.85 m/s

Average force acting on the ball, F = 72.9 N

We need to find the time of contact of the ball with the floor. Let t is the time of contact. So,

\(F=ma\\\\F=\dfrac{m(v-u)}{t}\\\\t=\dfrac{m(v-u)}{F}\\\\t=\dfrac{0.622\times (3.85-4.23)}{72.9}\\\\t=0.0032\ s\\\\\text{or}\\\\t=3.2\ ms\)

So, the ball is in contact with the floor for 3.2 ms.

The pressure transmitted in the hydraulic system is approximately 195.33 atm. The pressure transmitted in the hydraulic system can be calculated by dividing the force applied by the area of the pedal cylinder.

The given force is 315 N and the diameter of the pedal cylinder is 0.450 cm. To calculate the area, we need to convert the diameter to meters by dividing it by 100. Thus, the radius of the pedal cylinder is 0.450 cm / 2 / 100 = 0.00225 m.The area of the pedal cylinder is then calculated using the formula for the area of a circle: A = π * r^2. Substituting the values, we have A = π * (0.00225)^2 ≈ 0.0000159 m^2.Now, we can calculate the pressure by dividing the force (315 N) by the area (0.0000159 m^2). The pressure transmitted in the hydraulic system is approximately 19,811,320.75 Pa.To express the pressure in atmospheres, we can convert Pa to atm by dividing by the standard atmospheric pressure, which is approximately 101,325 Pa. Therefore, the pressure transmitted in the hydraulic system is approximately 195.33 atm.

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The energy density inside a coil can be calculated using the formula:

Energy density (u) = (1/2) * (μ₀ * B^2)

Where u is the energy density, μ₀ is the permeability of free space, and B is the magnetic field strength.

The magnetic field strength (B) inside a solenoid (coil) is given by:

B = μ₀ * n * I

Where μ₀ is the permeability of free space, n is the number of turns per unit length, and I is the current flowing through the coil.

Given:

Length of the coil (l) = 1 m

Number of turns (n) = 2000

Current (I) = 25 A

First, we need to calculate the magnetic field strength (B) inside the coil:

B = μ₀ * n * I

Next, we can calculate the energy density (u) using the magnetic field strength:

u = (1/2) * (μ₀ * \(B^2\))

Let's substitute the given values into the formulas:

B = μ₀ * n * I

B = (4π × \(10^{-7}\)) T·m/A) * (2000 turns/m) * 25 A

Calculate the value of B.

Once we have the value of B, we can calculate the energy density (u):

u = (1/2) * (μ₀ * \(B^2\))

Substitute the value of B and evaluate the expression to find the energy density inside the coil.

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A laser beam of wavelength 505.6 nm is incident on two slits 0.239 mm apart. The bright interference fringes are spaced approximately 0.17 mm apart

The spacing between bright interference fringes in a double-slit interference pattern can be calculated using the formula:

Δy = (λL) / d

Where: Δy is the spacing between bright fringes, λ is the wavelength of the laser beam, L is the distance from the slits to the screen, and d is the separation between the two slits.

Given:

λ = 505.6 nm = 505.6 x 10^(-9) m (convert wavelength to meters)

d = 0.239 mm = 0.239 x 10^(-3) m (convert slit separation to meters) L = 4.18 m

Plugging these values into the formula, we get:

Δy = (505.6 x 10^(-9) m * 4.18 m) / (0.239 x 10^(-3) m)

= 0.017 m

To convert this value to millimeters, we multiply by 1000:

Δy = 0.017 m * 1000

= 17 mm

Therefore, the bright interference fringes are spaced approximately 0.17 mm apart.

The bright interference fringes on the screen, when a laser beam of wavelength 505.6 nm is incident on two slits 0.239 mm apart, are approximately 0.17 mm apart.

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Answer:

The chemical equation for photosynthesis is 6CO2+6H2O→C6H12O6+6O2.

Explanation:

The solution to the calculation, rounded to the proper number of significant figures, is approximately 1654 J.

To find the solution to the calculation, we need to follow the rules of significant figures and perform the arithmetic operations step by step.

Subtract the given masses: (165.43 g - 78.15 g) = 87.28 g.

Calculate the temperature difference: (297.6 K - 292.8 K) = 4.8 K.

Multiply the mass difference by the specific heat capacity and the temperature difference:

(87.28 g) × (4.184 Jg^(-1) K^(-1)) × (4.8 K) = 1653.71776 J.

Round the result to the proper number of significant figures based on the given values.

The given values have the following significant figures:

165.43 g has 5 significant figures.

78.15 g has 4 significant figures.

4.184 Jg^(-1) K^(-1) has 4 significant figures.

297.6 K has 4 significant figures.

292.8 K has 4 significant figures.

Since we are multiplying and dividing, the result should have the same number of significant figures as the value with the fewest significant figures, which is 4.

Round the result to 4 significant figures: 1653.71776 J ≈ 1654 J.

Therefore, the solution to the calculation, rounded to the proper number of significant figures, is approximately 1654 J.

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Answer: False

Explanation: The size of the observable cosmos has changed during the past few billion years. Since the Big Bang, which is thought to have happened approximately 13.8 billion years ago, the observable universe has been expanding. This indicates that the observable universe has been expanding together with the distance between galaxies. The cosmos has seen phases of acceleration and slowdown in its expansion, however the rate of expansion has not always been constant. The observable universe is therefore bigger than it was a few billion years ago.

Answer:

A simple cell can be made by connecting two different metals in contact with an electrolyte

Mars is believed to have significantly less metal in its core than Earth due to its smaller size and differences in planetary formation processes.

Mars and Earth formed around the same time, approximately 4.6 billion years ago, through the process of accretion. However, their formation processes differed in some aspects, resulting in variations in their compositions. Mars is smaller than Earth, with a diameter of about 6,779 kilometers, compared to Earth's 12,742 kilometers. Due to its smaller size, Mars has a lower mass and gravity, which could have led to a lower concentration of heavy metals sinking into its core during formation.

Additionally, the abundance of metal-rich meteorites and other materials available during the formation of the two planets may have been different. Earth may have received more metal-rich materials due to its larger size and stronger gravitational pull, whereas Mars, being farther from the Sun, may have had less access to these building blocks.

Another factor is the differentiation process that both planets underwent. Earth's core is believed to have separated more efficiently from its mantle, leading to a higher concentration of heavy metals in its core. Mars, on the other hand, may have experienced a less efficient differentiation process, resulting in a less metal-rich core.

In summary, Mars's smaller size, differences in planetary formation, and less efficient differentiation process contribute to its core containing significantly less metal than Earth's core.

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