A submarine diving to a depth of 500 m would experience a pressure of 5,068,625 Pa on its hull, which is approximately 50 times greater than the atmospheric pressure at sea level.
a) When a submarine dives to a depth of 500 m, the pressure on its hull increases due to the weight of the water above it.
The pressure at this depth can be calculated using the formula \(P = \rho gh\), where ρ is the density of seawater, g is the acceleration due to gravity, and h is the depth.
Plugging in the values, we get P = (1025 kg/m³)(9.81 m/s²)(500 m) = 5,068,625 Pa.
b) To determine how many times greater the pressure is at a depth of 500 m compared to the surface, we can divide the pressure at 500 m by the atmospheric pressure at sea level.
Converting 14.7 psi to Pa, we get 101,325 Pa. Dividing 5,068,625 by 101,325 gives us approximately 50 times greater.
In summary, a submarine diving to a depth of 500 m would experience a pressure of 5,068,625 Pa on its hull, which is approximately 50 times greater than the atmospheric pressure at sea level.
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16. Determine the gravitational force of attraction between the Earth and Jupiter given the mass of the earth is 6 x 10^24 kg, the mass of Jupiter is 1898.6 x 10^24 kg and the closest distance is abou
The gravitational force of attraction between the Earth and Jupiter is approximately 1.32 x 10²⁸ N.
The gravitational force of attraction between two objects can be calculated using Newton's law of universal gravitation, which states that the force (F) is proportional to the product of their masses (m₁ and m₂) and inversely proportional to the square of the distance (r) between their centers. Mathematically, the formula is expressed as:
F = (G * m₁ * m₂) / r²
where G is the gravitational constant.
m₁ = 6 x 10²⁴ kg (mass of Earth)
m₂ = 1898.6 x 10²⁴ kg (mass of Jupiter)
r = 5.88 x 10¹¹ m (distance between Earth and Jupiter)
Plugging in the values into the formula, we have:
F = (6.67 x 10⁻¹¹ N m²/kg²) * (6 x 10²⁴ kg) * (1898.6 x 10²⁴ kg) / (5.88 x 10¹¹ m)²
Calculating the expression, we find:
F ≈ 1.32 x 10²⁸ N
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THE COMPLETE QUESTION IS:
Determine the gravitational force of attraction between the Earth and Jupiter given the mass of the earth is 6 x 10²⁴ kg the mass of Jupiter is 1898.6 x 10²⁴ kg and the closest distance is about 5.88 x 10¹¹
heat engine accepts heat at a rate of 200 kw, and it produces a net power output of 50 kw. determine the thermal efficiency of this engine.
The thermal efficiency of this engine is calculated by taking the net power output of 50 kW and dividing it by the amount of heat input of 200 kW. Thus, the thermal efficiency of this engine is 25%.
The thermal efficiency of a heat engine is defined as the ratio of the net power output of the engine to the heat input. In this case, the heat engine is accepting heat at a rate of 200 kW and producing a net power output of 50 kW.
To calculate the thermal efficiency, we use the following equation: Thermal Efficiency = Net Power Output/Heat Input In this case, the net power output is 50 kW and the heat input is 200 kW. Therefore, the thermal efficiency of this engine is equal to 0.25 or 25%. It is important to note that the thermal efficiency of a heat engine is affected by several factors, such as the efficiency of the engine itself, the temperature of the heat source, the temperature of the heat sink, and the type of energy conversion being performed. Therefore, the thermal efficiency of any engine may vary from one situation to another.
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A materiel that allows electricity to flow easily is called an
A materiel that allows electricity to flow easily is called an conductor
Why the axis of the Earth is tilted?
The axis of the Earth is tilted because of the way it was formed and the forces acting upon it.
The most widely accepted theory is that the Earth was formed about 4.5 billion years ago from the solar nebula, a rotating disk of gas and dust that surrounded the young Sun. As the disk began to cool and contract, it flattened into a disk, and the Earth formed within it. The gravitational forces of the Sun and Moon acting on the Earth caused it to become slightly flattened at the poles and bulging at the equator, and this resulted in a tilting of the Earth's axis. The tilt of the Earth's axis has remained relatively constant over time, leading to the seasons we experience as the Earth orbits the Sun.
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An oil drop (m = 1.6 x 10-16 kg) is suspended between plates separated by 1.8 cm. The voltage
across the plates is 125 V. Is this possible?
Answer:
E = V / d 125 V / .018 m = 6940 V/m electric field
F = E Q force on Q due to E
F = E n e where n is the number of electrons in Q
m g = E n e
n = m g / E e where n is the number of electrons e needed to support drop
n = 1.6 * 10E-16 * 9.8 / (6940 * 1.6 * 10E-19)
n = 1.41
Since n needs to be an integral number of charges, the drop would
not be suspended (motionless under these conditions).
A projectile has an initial horizontal velocity of 34.0 M/s at the edge of a roof top. Find the horizontal and vertical components of its velocity after 5.5s
I need shown work !
Answer:
\(v_x=34 m/s\)
\(v_y=53.9\ m/s\)
Explanation:
Horizontal Launch
When an object is thrown horizontally with a speed v from a height h, it describes a curved path ruled by gravity until it eventually hits the ground.
The horizontal component of the velocity is always constant because no acceleration acts in that direction, thus:
vx=v
The vertical component of the velocity changes in time because gravity makes the object fall at increasing speed given by:
\(v_y=g.t\)
The horizontal component of the velocity is always the same:
\(v_x=34 m/s\)
The vertical component at t=5.5 s is:
\(v_y=9.8*5.5=53.9\)
\(v_y=53.9\ m/s\)
What is the approximate time of death if the body temperature was 10°C (50°F)?
If the body temperature was 10°C, the approximate time of death would be between 12 and 36 hours, depending on the surroundings and other variables.
What time does death occur?However, it's crucial to note that the time of death can be influenced by several factors like the environment, clothing, and the person's physical state. The time of death can also be estimated by measuring the body temperature, also known as algor mortis.
After death, the body temperature decreases at a rate of roughly 1.5°C per hour, though this might change depending on the surroundings and other variables. It is impossible to pinpoint the exact time of death if the body temperature was 10°C, although it may indicate that death happened several hours earlier because the body temperature will continue to drop after death.
However, other techniques, like lividity, rigor mortis, and inspection of the stomach contents, are more accurate, hence it is not advised to utilize this method alone to establish the time of death. For a more precise estimation of the time of death, a forensic specialist should be consulted.
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a car travel the first 20km with a speed of 40km/h and the next 40km with a speed of 80km/h . find the average speed
Answer:
average speed is 60km/h
Explanation:
you sum up the speed attained in each distance covered and divide it by 2 to get your answer
There are three main types of rocks identified by how they are formed.Which of the following is true concerning the formation of rocks on Earth
Answer:
Igneous Rock
Sedimentary Rock
Metamorphic Rock
Explanation:
Igneous Formed by lava
Sedimentary Form By other fragmented pieces of rock
Metamorphic rocks that have undergone physical changes exposed to extreme presure.
Please can someone help
Answer is b
Explanation:
one joule of energy used each second is equal to ? of work.
Exactly, 1 Joule of energy per second is what is used to define a Watt. Joules and seconds, respectively, are the SI units for time and work. A power of 1 Joule per second was used to define a Watt.
A one newton (N) force applied over a one meter distance does one joule's worth of work (or energy) (m).. To put it simply, it requires approximately 1 joule of energy to raise a 3/4 pound weight 1 foot off the ground or to drag something 1 foot using a parallel pulling force of 3/4 pound. According to this definition from physics, 1 volt is the same as 1 joule of electric potential energy divided by 1 coulomb of charge. The power unit is the watt. According to this, 1 joule of labor is completed in 1 second. It is, in essence, the ability of an appliance to use energy at a rate of 1 joule per second.
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Question:
A second set of data was obtained using thicker pieces of putty. Both sets of results are shown in graph 2. What is the relationship between the resistance and the thickness of the conducting putty?
The resistance of the thin wire is greater than the resistance of the thick wire because the thin wire has fewer electrons to carry the current. Therefore, for thinner pieces of conducting putty we have the larger resistance and for the thicker pieces of conducting putty we have the lower resistance.
Marty is confronted by a mugger with a knife who demands his wallet. In an instant, his heart races, his breath quickens and his temperature shoots up. When the mugger looks over his shoulder, Marty bolts down the street without thinking. This example illustrates which response?
a. Fight-or-flight
b. Behavioral disengagement
c. Tend and befriend
d. None of the above
Answer:
A. fight or flight
Explanation:
but uh tend and befriend could be an option to get out of this situation ;)
a. Fight-or-flight
what is a fight-or-flight response?The fight-or-flight or the fight-flight-or-freeze response is a physiological reaction that takes place in response to a perceived harmful event, attack, or danger to survival. It became first described by Walter Bradford Cannon.
“The fight or flight response, or stress response, is triggered by a release of hormones either prompting us to live and fight or run away and flee,” explains psychologist Carolyn Fisher, Ph.D. “during the response, all bodily systems are operating to maintain us alive in what we've perceived as a dangerous scenario
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a car is traveling at 30 metres per second it accelerates steadily for 5 seconds after which it is travelling at 50 metres per second calculate its acceleration
Answer:
its alot
Explanation:
calculate the range of wavelengths (in m) for x-rays given their frequency range is 30,000 to 3.0 ✕ 107 thz. Smaller Value ___________ mLarger Value ____________ m
The range of wavelengths (in meters) for x-rays with a frequency range of 30,000 THz to 3.0 × 10⁷ THz is approximately 1.0 × 10⁻¹¹ m to 1.0 × 10⁻⁸ m.
To calculate the range of wavelengths, we use the formula:
Wavelength (λ) = Speed of light (c) / Frequency (f)
The speed of light (c) is approximately 3.0 × 10⁸ m/s.
For the smaller value, use the higher frequency (3.0 × 10⁷ THz):
λ = (3.0 × 10⁸ m/s) / (3.0 × 10⁷ THz × 10¹² Hz/THz)
λ ≈ 1.0 × 10⁻¹¹ m
For the larger value, use the lower frequency (30,000 THz):
λ = (3.0 × 10⁸ m/s) / (30,000 THz × 10¹² Hz/THz)
λ ≈ 1.0 × 10⁻⁸ m
The range of wavelengths for x-rays is approximately 1.0 × 10⁻¹¹ m to 1.0 × 10⁻⁸ m.
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Elements with positive valences usually ______ electrons
A. Donate
B. Accept
C. Have no
D. Create
now assume that the crate is sliding along the floor with constant velocity. what is the magnitude fp of the force you need to exert on the crate to make it continue to slide along the floor with constant velocity?
The magnitude\(F_{P}\) of the force you need to exert on the crate to make it continue to slide along the floor with constant velocity is 437.5N.
How friction force can be calculated?The Normal Force (in a horizontal plane, it is comparable to the mass by gravity) and the Kinetic Coefficient of Friction must be multiplied in order to obtain the Friction Force, which must be used in order to solve this problem.
Given that the sentence does not specify the value of the coefficient of friction, I will ascribe a value of 0.5 between the crate and the ground. If a different value has been specified for this coefficient, the below equation will simply need to be changed to reflect it.
\(F_{P}\) = µK N
µK = Friction coefficient
Normal Force is N.
Replacing,
\(F_{P}\) = 0.5 × 875
\(F_{P}\) = 437.5N.
Consequently, the crate is subject to a friction force of 437.5N.
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Complete question is "Suppose you have to move a heavy crate of weight 875 {\rm N} by sliding it along a horizontal concrete floor. You push the crate to the right with a horizontal force of magnitude 300 {\rm N}, but friction prevents the crate from sliding. Now assume that the crate is sliding along the floor with constant velocity. What is the magnitude F_p of the force you need to exert on the crate to make it continue to slide along the floor with constant velocity?"
the precise value of the astronomical unit is group of answer choices 148,510,000 km 150,205,000 km 149,000,000 km 149,597,870.7 km 148.237.410 km
The precise value of the astronomical unit is 149,000,000 km and 148.237.410 km:
The astronomical unit is defined as the average distance between the Earth and the Sun.
This definition was first established in the 17th century by the German astronomer Johannes Kepler.
To determine the precise value of the astronomical unit, astronomers measure the distance between the Earth and the Sun using a variety of techniques, such as radar ranging, stellar parallax, and laser ranging.
One of the most accurate techniques for measuring the astronomical unit is radar ranging.
This method involves sending a radar signal from Earth to a planet or asteroid, and then measuring the time it takes for the signal to bounce back.
By knowing the speed of light and the time delay, astronomers can calculate the distance between the Earth and the object being studied.
Another technique for measuring the astronomical unit is laser ranging.
This method involves bouncing a laser beam off of reflectors placed on the Moon, and then measuring the time it takes for the light to travel back to Earth.
By knowing the speed of light and the time delay, astronomers can calculate the distance between the Earth and the Moon. This technique can also be used to measure the distance between the Earth and other planets and asteroids.
Using these and other methods, astronomers have determined the precise value of the astronomical unit to be 149,597,870.7 kilometers (or approximately 93 million miles).
This value is constantly being refined as new measurements are made, and may change slightly over time as more precise measurements are obtained.
The other answer choices provided are also distances in kilometers, but they are not the precise value of the astronomical unit.
For example, 148,510,000 km is the approximate distance between the Earth and the Sun at its closest approach, while 150,205,000 km is the approximate distance at its furthest distance.
149,000,000 km and 148.237.410 km are also not the precise values of the astronomical unit.
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How do particles move when a surface wave passes through a medium?
A.
Neither parallel nor perpendicular to the direction of wave motion
B.
Parallel to the direction of wave motion
C.
Perpendicular to the direction of wave motion
D.
Both parallel and perpendicular to the direction of wave motion
What would you need to do to find the number of neutrons in an atom?
Answer:
You subtract the atomic number from the atomic mass to find the number of neutrons alone
Explanation:
The atomic number is the number of protons OR electrons. They are both equal thus making the atom have a neutral charge. The relative atomic mass is the number of protons AND neutrons.
A boy runs in a 125-m race from rest. In the first 5 seconds, he increases his speed with a constant
acceleration of 2.0 m/s2. He then maintains this speed for the rest of the run. Calculate the total
time taken for the boy to finish the run.
Answer:
Assuming starting at zero velocity: at 4 seconds speed is 8 m/s (2m/s^2 * 4 seconds) and distance is 16 m (average speed is 4 m/s * 4 seconds). The remaining 84 meters (at 8 m/s) takes 10.5 seconds.
So total time to run 100 meters is 14.5 seconds.
Explanation:
Mutations in sections of DNA can be caused by all of the following EXCEPT
Question 2 options:
Viruses
Chemicals
Ultraviolet Radiation
Sexual Reproduction
Answer:
sexual reproduction
Explanation:
Two balls, ball A and ball B, are dropped from the same height onto the same surface. If ball A rebounds to a higher height than ball B then:(3) A. ball A is more elastic than ball B. B. ball B is more elastic than ball A. C. not enough information is given to determine which ball is more elastic.
Answer:
its b
Explanation:
A 1500 kg car travels 50 m north in 20 seconds. What is the magnitude of the average velocity of the car during the 20 second interval?
a. 2.5 m/s
b. 5.0 m/s
c. 6.5 m/s
d. 7.0 m/s
Answer:
a. 2.5 m/s
Explanation:
50 / 20 = 2.5 m/s
Drag force on a body increases with the increase in speed of the body . Justify with one example from everyday experience
Explanation:
One everyday example that justifies the increase in drag force with the increase in speed is riding a bicycle. When you ride a bicycle, you can feel the resistance against your body as you increase your speed.
At low speeds, the drag force is relatively low. However, as you start pedaling faster and gain speed, you will notice an increasing resistance against your body. This resistance is caused by the drag force acting on you as you move through the air.
As you accelerate on a bicycle, the air molecules in front of you get compressed, creating an area of high pressure. Simultaneously, the air molecules behind you expand, creating an area of low pressure. This pressure difference creates a force that opposes your forward motion, known as drag force or air resistance.
At higher speeds, the drag force becomes more significant and requires more effort to overcome. This is why you need to pedal harder or lean forward to reduce your frontal area and decrease the resistance as you ride faster.
The experience of feeling increased resistance while cycling at higher speeds demonstrates the effect of drag force increasing with speed. This principle applies not only to bicycles but also to various other objects moving through a fluid medium, such as cars, airplanes, or even a person running against the wind.
I hope I helped
A snap together cube has a protruding snap on one side and receptacle holes on the other 55 sides. What is the smallest number of these cubes that can be snapped together so that only receptacle holes are showing
The smallest number of cubes needed is 28. This forms a 3x3x3 cube with one central cube missing.
To minimize the number of protruding snaps while maximizing the number of receptacle holes, the cubes should be arranged in a 3x3x3 cube formation.
This structure would have 27 cubes, but one central cube must be removed to eliminate all protruding snaps.
Each of the remaining 26 cubes will have at least one side with receptacle holes facing outward.
The missing central cube ensures no protruding snaps are exposed.
Therefore, the smallest number of snap-together cubes needed to have only receptacle holes showing is 28.
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What component in a dry cell is like the hydro sulfuric acid in a wet cell? a) positive electrolyte b) primary contact c) positive electrode d) negative electrolyte
Answer:
d
Explanation:
Hydro sulphuric acid in a wet cell acts as an electrolyte. Similarly in a dry cell ammonium chloride paste acts as electrolyte along with zinc anode, carbon rod as cathode in a cylindrical pot. The dry-cell battery stores energy in an immobilized electrolyte paste, which is ammonium chloride in this case. This minimizes the need for water or a wet electrolyte as in wet batteries.
Rachel has an unknown sample of a radioisotope listed in the table. using a special technique, she is able to measure the mass of just the unknown isotope as 104.8 kg at 12:02:00 p.m. at 4:11:00 p.m. on the same day, the mass of the unknown radioisotope is 13.1 kg. which radioisotope is in the sample? potassium-42 nitrogen-13 barium-139 radon-220
The only possibility remaining is barium-139, which is a stable (non-radioactive) isotope and would not have undergone any radioactive decay during the time period between measurements. Hence, the unknown radioisotope in the sample is barium-139.
To determine which radioisotope is in the sample, we need to use the concept of radioactive decay and half-life. Radioactive decay is a process by which the nucleus of an unstable atom loses energy by emitting particles or radiation.
The rate of decay of a radioactive substance is described by its half-life, which is the time it takes for half of the substance to decay.
Let's calculate the half-life of each radioisotope listed in the table:
Potassium-42: Half-life of 12.4 hours
Nitrogen-13: Half-life of 10 minutes
Barium-139: Stable (non-radioactive)
Radon-220: Half-life of 55.6 seconds
From the given data, the sample of the unknown radioisotope had a mass of 104.8 kg at 12:02:00 p.m. and 13.1 kg at 4:11:00 p.m. on the same day, which is a time difference of 4 hours and 9 minutes.
Let's start by looking at the radioisotope with the longest half-life, which is potassium-42.
If the unknown radioisotope was potassium-42, its mass would have decreased by half during 12.4 hours, which is much longer than the 4 hours and 9 minutes between the measurements.
Therefore, we can eliminate potassium-42 as a possibility.
Next, let's consider nitrogen-13. If the unknown radioisotope was nitrogen-13, its mass would have decreased by half during 10 minutes. We can convert the time difference between measurements to minutes:
4 hours and 9 minutes = 249 minutes
Therefore, the number of half-lives during this time period would be:
249 / 10 = 24.9
This means that the mass of the sample would have decreased by a factor of \(2^{(24.9)\), which is approximately \(2.7 * 10^7\). Starting from the initial mass of 104.8 kg, the final mass would be:
104.8 kg / \((2.7 * 10^7)\) = \(3.9 * 10^{-6\) kg
This is much smaller than the measured final mass of 13.1 kg, so we can eliminate nitrogen-13 as a possibility.
Finally, let's consider radon-220. If the unknown radioisotope was radon-220, its mass would have decreased by half during 55.6 seconds. We can convert the time difference between measurements to seconds:
4 hours and 9 minutes = 14940 seconds
Therefore, the number of half-lives during this time period would be:
14940 / 55.6 = 269
This means that the mass of the sample would have decreased by a factor of \(2^{269\), which is approximately 6.8 x \(10^{80\). Starting from the initial mass of 104.8 kg, the final mass would be:
104.8 kg / (\(6.8 * 10^{80\)) = \(1.54 * 10^{-79\)kg
This is much smaller than the measured final mass of 13.1 kg, so we can eliminate radon-220 as a possibility.
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Answer: c
Explanation:
Give 3 differences between respiration and photosynthesis.
Respiration and photosynthesis are biological reactions in the environment each other. Both produce energy but in two different forms.
Differences between respiration and photosynthesis.During photosynthesis, Oxygen is released, and Carbon dioxide is consumed, but Carbon dioxide is liberated, and Oxygen is consumed during respiration.
Photosynthesis converts radiant or light energy into chemical or bond energy. Respiration delivers chemical or potential energy for several other functions in the body. Photosynthesis contains two stages light reaction and dark reaction. Respiration consists of two stages, they are inhalation and exhalation.
So we can conclude that The raw materials of photosynthesis are Carbon dioxide and water, but the raw materials of respiration are glucose and Oxygen.
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a gas cylinder holds 0.10 mol of o2 at 150 c and a pressure of 3.0 atm. the gas expands adiabatically until the volume is doubled. what are the final (a) pressure and (b) temperature?
(a) The final pressure is approximately 0.75 atm. (b) The final temperature is approximately 99.6°C. Adiabatic processes involve changes in pressure and temperature without heat exchange with the surroundings.
To determine the final pressure and temperature of the gas after adiabatic expansion, we can use the adiabatic process equation:
P₁V₁^γ = P₂V₂^γ,
where P₁ and V₁ are the initial pressure and volume, P₂ and V₂ are the final pressure and volume, and γ is the heat capacity ratio of the gas.
First, let's calculate the initial volume (V₁) of the gas. The ideal gas law can be used for this:
PV = nRT,
where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.
Rearranging the equation to solve for V₁:
V₁ = (nRT₁) / P₁,
where T₁ is the initial temperature.
Now, we know that the volume (V₂) is doubled, so V₂ = 2V₁.
Using the adiabatic process equation, we can rewrite it as:
P₁V₁^γ = P₂(2V₁)^γ.
Simplifying the equation, we find:
P₂ = P₁(2^(γ-1)).
Next, we need to determine the value of γ for oxygen gas. For a diatomic ideal gas, γ is approximately 1.4.
Now, we can calculate the final pressure (P₂):
P₂ = 3.0 atm * (2^(1.4-1))
≈ 0.75 atm.
To calculate the final temperature (T₂), we can use the relationship between initial and final pressure and temperature for an adiabatic process:
(T₂ / T₁) = (P₂ / P₁)^((γ-1)/γ).
Rearranging the equation, we find:
T₂ = T₁ * (P₂ / P₁)^((γ-1)/γ).
Substituting the known values:
T₂ = 150°C * (0.75 atm / 3.0 atm)^((1.4-1)/1.4)
≈ 99.6°C.
After adiabatic expansion, the final pressure of the gas cylinder is approximately 0.75 atm, and the final temperature is approximately 99.6°C. Adiabatic processes involve changes in pressure and temperature without heat exchange with the surroundings. By applying the adiabatic process equation and using the ideal gas law, we can determine the final state of the gas based on its initial conditions and the given expansion factor.
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