(a) what is the magnitude of the average acceleration of a skier who, starting from rest, reaches a speed of 4.81 m/s when going down a slope for 1.94 s? (b) how far does the skier travel in this time?

The two experiments that Coulomb's to show the relationship between electrostatic force and that law carries Coulomb's name today to include this relationship as a fundamental component.

Torsion balance is used to study the repulsion and attraction forces of charged particles and found that the strength of the electric force between two point charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

A bar is suspended from the centre of the torsion balance by a thin fibre. The fibre functions as a flimsy torsion spring.

The torsion balance in Coulomb's experiment was a suspended metal-coated ball attached to one end of an insulating rod.

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According to the Ptolemaic system, all celestial bodies were put in motion  by a prime mover - a series of concentric spheres, with Earth at the center.

This geocentric model was developed by the ancient Greek astronomer Claudius Ptolemy and dominated the understanding of the cosmos for nearly 1,500 years. In this system, the planets, the Sun, and the stars were all embedded in their own transparent, crystalline spheres, which revolved around the Earth in perfect circles. These celestial bodies were believed to be attached to these spheres, and their motion was dictated by the rotation of these spheres.

The Ptolemaic model was based on the assumption that the universe was created as a perfect, harmonious system, with everything revolving around the Earth in a divinely ordered fashion. To account for observed irregularities in planetary motion, Ptolemy introduced the concept of epicycles, smaller circular paths within the larger circular orbits. The spheres were set in motion by a divine force or the so-called Prime Mover, a concept that had roots in Aristotle's philosophy. This force was thought to maintain the orderly motion of celestial bodies and preserve the perfect structure of the universe.

Thus, the Ptolemaic system relied on a complex arrangement of spheres and epicycles, driven by a divine force, to explain the motion of celestial bodies. Although this model was eventually replaced by the heliocentric model developed by Copernicus and Galileo, it played a significant role in shaping human understanding of the cosmos for centuries.

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(a) To make a free-body diagram of each box, we need to consider the forces acting on each box.

The box on the ramp will have the force of gravity acting downward, which can be resolved into components parallel and perpendicular to the ramp. The parallel component will act down the ramp, while the perpendicular component will act normal to the ramp. The box will also experience a force of friction acting up the ramp, which will be equal and opposite to the component of the force of gravity acting down the ramp. The box on the other side of the pulley will have only the force of gravity acting downward.

(b) The direction in which the 50.0 kg box moves will depend on the net force acting on it. If the force down the ramp due to the component of the force of gravity is greater than the force up the ramp due to friction, then the box will move down the ramp. If the force up the ramp due to friction is greater than the force down the ramp due to gravity, then the box will move up the ramp. If the forces are balanced, then the box will not move at all.

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Answer:

I would say tension force the last one because the gravitational force brinsg it down more.

Explanation:

Dont mind if its wrong im sorry

11.The time at 75° East longitude would be 1 hour and 20 minutes behind. 12.The time at 135° degrees East longitude would be 4 hours ahead. and 13. the time in Lima, Peru (15° South latitude, 75° West longitude) would also be 9:30 AM.

At 2:00 AM at 90° East longitude, the time at 75° East longitude would be 1 hour and 20 minutes behind. This is because for every 15 degrees of longitude, there is a time difference of approximately 1 hour. Since the two longitudes in question have a difference of 15 degrees, we can divide this by 15 to calculate the time difference.

If it is 8:00 PM at 15° East longitude, the time at 135° East longitude would be 4 hours ahead. Similarly, for every 15 degrees of longitude, there is an approximate time difference of 1 hour. Since the two longitudes in question have a difference of 120 degrees, we can divide this by 15 to calculate the time difference.

There is a 7-hour difference** between 105° West longitude and the Prime Meridian (0° longitude). The Prime Meridian, passing through Greenwich, England, serves as the reference point for determining time zones. As one moves westward from the Prime Meridian, each 15 degrees of longitude corresponds to a time difference of approximately 1 hour. Therefore, the time at 105° West longitude would be 7 hours behind the time at the Prime Meridian.

If it is 9:30 AM in New York (41° North latitude, 75° West longitude), the time in Lima, Peru (15° South latitude, 75° West longitude) would also be 9:30 AM. The latitude does not affect the time difference between the two locations. However, since both locations have the same longitude (75° West), they would experience the same local time. The time difference between different latitudes is primarily significant for determining time zones rather than the actual time within a specific time zone.

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Answer: C.

Explanation:  Abrasion is where two things rub together causing friction, which in turn wears the rock down.

Answer:

You can use a block and an inclined plane (just a tilted board)

Place the block on the plane and gradually increase the angle the plane makes with the horizontal.

Static friction will keep the block in place (no sliding) until the angle between the plane and the horizontal is large enough. The block will now slide but is still under the influence of kinetic friction. Thus static friction is greater than sliding friction.

Answer:

The amount of power will be increased.

Explanation:

If the work remains constant but the time is reduced the power increases. Since power is defined as the relationship between work overtime. By means of the following equation, we can see this relationship.

\(P=W/t\)

where:

P = power [Watts]

W = work [J] (units of joules)

t = time [s]

Let's assume with an example the above written.

If we have an electric motor that exerts a work of 950 [J], and the time used is 5 [s], the power is:

\(P = 950/5\\P = 190 [W]\)

Now if we want to accelerate the work done and use 2 seconds for the time, we will have:

\(P=950/2\\P=475 [W]\)

We want to see how maintaining the work constant but reducing the time in which it occurs affects the power. We will see that the power increases.

We define power as the amount of work done per unit of time.

So we can compute power as the quotient between the work done and the time in which it is done.

So, if we reduce the time in which the work is done, then the denominator is smaller, thus, the power will be larger.

This means that maintaining the work constant, and reducing the time in which it is done, increases the amount of power exerted.

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To calculate the volume of the balloon at a different temperature, we can use the combined gas law. The combined gas law states that the ratio of the initial pressure, volume, and temperature to the final pressure, volume, and temperature is constant, assuming the amount of gas remains constant. The formula can be written as:

(P1 * V1) / T1 = (P2 * V2) / T2

where:

P1 and P2 are the initial and final pressures, respectively,

V1 and V2 are the initial and final volumes, respectively, and

T1 and T2 are the initial and final temperatures, respectively.

Given:

Initial volume, V1 = 11.9 L

Initial temperature, T1 = 299 K

Final temperature, T2 = 267 K

Let's assume the pressure remains constant.

Using the combined gas law, we can solve for V2:

(P1 * V1) / T1 = (P2 * V2) / T2

Since the pressure is constant, we can simplify the equation to:

V2 = (V1 * T2) / T1

Substituting the given values:

V2 = (11.9 L * 267 K) / 299 K

Calculating this expression:

V2 ≈ 10.61 L

Therefore, at 267 K, the volume of the balloon filled with helium would be approximately 10.61 L.

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The accelaration is 0.

What is accelaration?

accelaration rate at which velocity change with time, in terms of both speed and direction.

Sol-The restoring  force in case of simple harmonic motion is an elastic force of the spring. It could be found by the use of Hooke's law  F = - kx. Here k - the spring constant and x - deformation of the spring (change of its length from equilibrium position).

We see that this is a variables force that is  depends on the given displacement of their mass-spring system of x. Minus sign tells us that the direction of this force is opposite to that of the  displacemnt; as a result of  this force brings the mass of the back to the equilibrium position (this is why we called it a restoring force).

As any force, restoring force could be found using Newtons second law F = ma, where m - mass of the body and a - acceleration of the body.

Now we can write:

When the body goes through equilibrium position its displacement x is zero. Hence, acceleration also 0.

BTW, the maximum value of the accelaration we will have when the amplitude of this  mass-spring system is the  maximum. At this points the direction of the mass-spring pendulum switches to the  opposite. Those points we are  call inflection points.

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Answer:

The shape of an orbit

Explanation:

Answer:

The geometry of an orbit

Explanation:

AYE PECKS

It will be very difficult to if you could travel back to the time when the Earth first formed as a planet. It has lots of volcano with no water or ocean.

Earth would have been a very hostile and unpleasant planet when it originally formed, and life would not have been viable. Without any water or ocean, it was merely molten volcanic soil. At that time, the atmosphere and life were not even established. First, there was a time when the Earth's atmosphere was highly hot and there were frequent collisions with celestial bodies. Hence, the heat generated in the atmosphere was in a molten volcanic state. lava and magma alone. Ocean formation and, by extension, life, were prohibited by high temperatures.

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The answer that best describes the surface of the Earth at this time is option B, "Earth has lots of volcanoes."

If you could travel back in time to when the Earth first formed as a planet, the surface of the Earth would likely be characterized by frequent volcanic activity and a lack of water. Therefore, the answer that best describes the surface of the Earth at this time is option B, "Earth has lots of volcanoes."

During the early stages of the Earth's formation, intense heat and pressure caused the surface to be covered in molten lava and ash. Over time, this activity led to the formation of the Earth's crust, and the continued volcanic activity helped shape the planet's surface and atmosphere.

It wasn't until later, through a process known as outgassing, that water vapor and other gases were released from the Earth's interior and began to accumulate in the atmosphere, eventually leading to the formation of oceans and the emergence of life.

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Credit: Larus (Full Credits to Larus I didn't make this answer)

The correct answer is that it is too high for the weather balloons.  

The mesosphere refers to the layer of the atmosphere of the Earth. It is present directly above the stratosphere and below the thermosphere. It elongates from about 50 to 85 kilometers above the Earth. The coldest temperatures in the atmosphere of the Earth, that is, around -90 degree C, is found close to the top of the layer.  

It is tough to study mesosphere, therefore, less is known about the layer of the atmosphere in comparison to the other layers. It is tough as weather balloons cannot fly high enough to reach the mesosphere. The satellites orbit above the mesosphere, and cannot directly determine the traits of the layer.  

Answer:    C. X-Rays

Explanation:

Answer:

C I am pretty sure

Explanation:

Image below

The magnetic field b at a point r>r is bR^4/2

What is a magnetic field?
Field of magnetism. Magnetic forces can be seen in a magnetic field, an electric current, a changing electric field, or a vector field around a magnet. Magnetic compass needles and other permanent magnets align in the direction of magnetic fields like the one found on Earth.

Used Ampere's law which says the integral of the "dot" (scalar) product of the magnetic field with a differential path element taken around a closed pat is proportional to the current flowing through the surface created by the closed path. More to the point:
integral[around closed contour C](B*dl) = u0*I where the "*" is the "dot" product between vector B and dl and u0 = permeability of free space.

Now for your wire, the closed path is a circle center on the central axis of the wire and the plane of the circle is perpendicular to the central axis. dl is the unit vector tangent to the circle at the circumference of the circle. So fix the radius of circle C to be R, then dl = \(Rdq q_U\) where q is the azimuthal angle in the plane of the circle and is the unit vector pointing in the q direction. SO the integral for B becomes

Integral[0 -> 2*pi]((1) where B-q is the component of B in the azimuthal direction.

Now for the righthand side. Suppose R > a (part B of your question). The wire has a total current of

It = integral[0-->a](J 2*pi*r*r) = integral(br^2*2*pi*r*r) = ba^4/2
And equating to eq(1) above 2*pi*R*B-q = ba^4/2

B-q = ba^4/(4*pi*R)
Now look at the case where R<=a

The current is then
I(R) = integral[0-->R](J 2*pi*r*dr) = bR^4/2

And equating to equation 1

2*pi*R*B-q = bR^4/2
B-q = bR^3/(4*pi)

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The density of the planet is \(2249.17 \frac{kg}{m^3}\)

Solution:

Given

Time period T = 1.57 hours = \(1.57 \times 60 \times 60 sec\)

using formula

T = \(\frac{2 \times \pi}{ \omega}\)

\(\omega = \frac{2 \pi} T\\\omega = \frac{2 \pi} {1.57 \times 60 \times 60 sec}\)

also, force \(F = \frac{GMm}{R^2}\)

meanwhile Force \(F = \frac{mv}{R^2}\\\)

equating both the above equations we get

we get \(v = \sqrt{\frac{GM}{R} }\)

also \(M = \frac {4\pi R^3 \rho} 3\)

also, \(\omega = \frac vR\)

then \(\frac{2 \pi} {1.57 \times 60 \times 60 sec} = \sqrt{\frac{G \frac {4\pi R^3 \rho} 3}{R} }\)

solving the equation we get

\(\rho = 2249.17 \frac{kg}{m^3}\)

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13.02 meters

Explanation

the work done by the brakes makes the car stops, so the change in energy equals the work done

hence

also, the work done by a force is given by

then, let

replace

therefore, the answer is

13.02 meters

I hope this helps you

Answer: 1.480 mm/s

Explanation:

Given

Cross-sectional area \(A=0.80\times 10^{-6}\ m^2\)

Number density(no of charges per unit volume) \(n=9.5\times 10^{28}\ m^{-3}\)

Current \(I=18\ A\)

We know, drift velocity is given by

\(\Rightarrow v_d=\dfrac{I}{neA}\\\Rightarrow v_d=\dfrac{18}{9.5\times 10^{28}\times 1.6\times 10^{-19}\times 0.8\times 10^{-6}}\\\Rightarrow v_d=\dfrac{18\times 10^{-3}}{12.16}=1.480\ mm/s\)

Answer:

Approximately \(14\; {\rm m\cdot s^{-1}}\).

Explanation:

The gravitational potential energy \(\text{GPE}\) of this roller coaster is proportional to the height \(h\) of the roller coaster.

The kinetic energy \(\text{KE}\) of this roller coaster is proportional to the square of speed \(v\).

The question states that the track is frictionless. Thus, during the descent, the \(\text{GPE}\) of this roller coaster is turned into \(\text{KE}\) without any energy loss.

When the roller coaster was at \((1/2)\) of the the initial height, only\(1 - (1/2) = (1/2)\) of the original \(\text{GPE}\) was turned into \(\text{KE}\). The \(\text{KE}\!\) of this roller coaster at that height would be \(1 - (1/2) = (1/2)\!\) of the \(\text{KE}\!\!\) when the roller coaster is at the ground level.

The \(\text{KE}\) of the roller coaster is proportional to \(v^{2}\) (the square of speed \(v\).) Thus, since the \(\text{KE}\!\) at \((1/2)\) the initial height is \(1 - (1/2) = (1/2)\!\) the \(\text{KE}\!\!\) at the ground level, the \(v^{2}\) at \((1/2)\!\) the initial height would also be \(1 - (1/2) = (1/2)\!\) the \(v^{2}\!\) at the ground level.

Since \(v = 20\; {\rm m\cdot s^{-1}}\) at the ground level, \(v^{2} = (20\; {\rm m\cdot s^{-1}})^{2}\) at the ground level. The \(v^{2}\) at \((1/2)\) the initial height would then be:

\((1 - (1/2))\times (20\; {\rm m\cdot s^{-1}})^{2}\).

Thus, the speed \(v\) at \((1/2)\) the initial height would be:

\(\begin{aligned}& \sqrt{(1 - (1/2))\times (20\; {\rm m\cdot s^{-1}})^{2}} \\ =\; & \sqrt{\frac{1}{2} \times (20\; {\rm m\cdot s^{-1}})^{2}} \\ =\; & \sqrt{200}\; {\rm m\cdot s^{-1}} \\ \approx\; & 14\; {\rm m\cdot s^{-1}}\end{aligned}\).

The size of the electric current is 155 Amperes.

Calculation:

I = Q / t

I = 93.0 C / 0.601 s

I = 155 C/s

I = 155 A

Electric current is the flow of charged particles such as electrons and ions, that travel through a conductor or space. It is measured as the net flux of charge to the surface or control volume. Electricity starts with atoms.

Atoms are made up of protons neutrons and electrons. Electricity is generated when electrons are moved from atom to atom by an external force. The flow of electrons is called current. Current refers to the flow of current in an electronic circuit and the amount of current that flows through the circuit.

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Answer:

"solve: given that F -12 N and time 4 seconds and let we have to find out the P.

F = 12 N

t = 4 s

p = ?

F = m×( v - u ) / t

12 = m×v / 4

m×v = 12× 4

p = 48 kg m/s

Linear momentum will be 48 kg m/s.

Explanation:

A force of at least 662.7 N is needed to start the table moving.

We need to use the formula for static friction:

F_static = friction coefficient * normal force

where the normal force is the force pressing the table down onto the ground, which is equal to the weight of the table.

Given that the mass of the table is 150 kg, we can find its weight:

weight = mass * gravity

where gravity is the acceleration due to gravity, which is approximately 9.81 m/s^2.

So the weight of the table is:

weight = 150 kg * 9.81 m/s^2 = 1471.5 N

The normal force is equal to the weight of the table, so:

normal force = 1471.5 N

Now we can calculate the force needed to start the table moving:

F_static = friction coefficient * normal force

F_static = 0.45 * 1471.5 N

F_static = 662.7 N

Therefore, a force of at least 662.7 N is needed to start the table moving.

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Based on the document attached, the  small bar magnet will be oriented when placed at position X is option d:

The orientation of the magnets   is known to be one that do affect its magnetic force. Atoms atoms, such as iron, are known to often gives a stronger magnetic force when compared to other atoms.

These atoms can be seen as tiny magnets, that has the north and south of each pole. If the poles is known to be oriented in all directions, the material will not bring about a net magnetic force.

Therefore, Based on the document attached, the  small bar magnet will be oriented when placed at position X is option d because the shapes of the magnetic field lines in regards to the bar magnet are said to be closed.

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The correct answer is b) never true. When capacitors are connected in series, the equivalent capacitance of the combination decreases. This is because the total charge on the combination is equal to the charge on each individual capacitor, but the voltage across the combination is the sum of the voltages across each capacitor.

The formula for capacitance is C = Q/V, so if the charge is the same but the voltage is higher, the capacitance will be lower.

Therefore, as more and more capacitors are connected in series, the equivalent capacitance of the combination decreases.

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Answer

v= 1/R mark me brainliest pls

When Two ideal inductors, L1 and L2, have zero internal resistance and are far apart, so their magnetic fields do not influence each other

(a) When two ideal inductors L1 and L2 with zero internal resistance are connected in series, their inductances add up. This is because the total magnetic flux linkage in the combined system is equal to the sum of the individual flux linkages. Mathematically, Leq = L1 + L2, so they are equivalent to a single ideal inductor with inductance Leq.

(b) When the same inductors are connected in parallel, their equivalent inductance can be found using the formula for parallel connected components: 1/Leq = 1/L1 + 1/L2. This formula shows that the reciprocal of the equivalent inductance is equal to the sum of the reciprocals of the individual inductances.

(c) For inductors L1 and L2 with nonzero internal resistances R1 and R2, when connected in series, their equivalent inductance remains Leq = L1 + L2, as mutual inductance is still zero. The equivalent resistance in series connection is the sum of individual resistances: Req = R1 + R2.

(d) When these inductors with internal resistances are connected in parallel, the formula for equivalent inductance remains the same: 1/Leq = 1/L1 + 1/L2. However, the equivalent resistance formula also follows the parallel connection rule: 1/Req = 1/R1 + 1/R2.

Therefore, it is true that these inductors are equivalent to a single inductor with 1/Leq = 1/L1 + 1/L2 and 1/Req = 1/R1 + 1/R2 when connected in parallel.

The magnetic field at the center of the square for this case is 0 T (tesla).

To calculate the magnetic field at the center of the square, we will use Ampère's Law, particularly the Biot-Savart Law. Each wire carries a 100-A current, and the distance between each wire and the center of the square is 10 cm (half the side length).

First, let's find the magnetic field due to one wire at the center of the square. The formula for the magnetic field at a perpendicular distance (R) from a long straight wire carrying current (I) is given by:

B = (μ₀ * I) / (2 * π * R)

Where B is the magnetic field, μ₀ is the permeability of free space (4π × 10⁻⁷ T·m/A), I is the current (100 A), and R is the distance (0.1 m).

Now, since there are 4 wires, we need to find the total magnetic field at the center of the square. Each wire contributes a magnetic field, but they are not in the same direction. Therefore, we need to find the vector sum of these magnetic fields.

The magnetic fields due to opposite wires have the same magnitude but are in opposite directions. Therefore, the total magnetic field at the center of the square is zero (since the magnetic fields cancel each other out).

So, the magnetic field at the center of the square for this case is 0 T (tesla).

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The initial velocity is 24.9 m/s

The parameters given in the question are as follows;

Final velocity= -4.5 m/s

Time= 3 seconds

acceleration= -9.8

initial velocity= ?

The formula that can be used to calculate the initial velocity is

v= u + at

-4.5= u + (-9.8)(3)

-4.5= u + (-29.4)

-4.5= u - 29.4

u= -4.5+29.4

u= 24.9

Hence the initial velocity is 24.9 m/s

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Answer:

initial velocity is 24.9 m/s

Explanation: