A vehicle approaches a set of traffic lights with a speed of 15m/s. When 50m from the lights the driver brakes and comes to a rest at the lights. Calculate the deceleration of the vehicle

The earth conducts seismic waves-- when an earthquake occurs, stations farther and farther away from the quake see the S and P waves propagated through deeper and deeper layers. By measuring the arrival time of the waves, the velocity of the waves can be found as a function of depth. There is clear evidence for several layers in the earth which both refract the waves and below which the velocities are different. This is a bit like holding a book under your desk while a friend (gently) taps the other end of the desk. If you listen closely to the sound (i.e. with your ear on the top of the desk) the sound changes noticeably if a large book is pressed up against the bottom of the desktop. You might also try to figure out how to tell if a golf ball is wound, liquid filled, or solid-- without looking at it. (You can tell if you hit one!)

Scientists can tell by observing the seismic waves that are recorded all over the surface of the earth from distant earthquakes. The seismic waves are reflected (bounced off) layers of different densities, and they are refracted (bent) when they enter layers of different densities. Some of them don't go through liquid at all (the S waves). Scientists have been monitoring earthquakes and studying the phases of seismic waves that arrive at different stations for - hmm, well I don't exactly know - but certainly at least the last 75 years, with more and more sophisticated equipment. Seismologists look at the little wiggles that are made by pens on paper, connected to seismometers, every time a wave from an earthquake anywhere in the world passes under their station. It is by studying many of these seismic records, for many years, and pooling all our knowledge, that we have been able to come up with a working model of what the inside of the earth is made of, where the boundaries between layers of different density and composition lie, and why we have earthquakes where we do.

to Something you can do to model how seismologists "listen" to earthquakes is densitieshave a friend tap on a big table while you put your ear on the table at the other end. We put sensitive instruments in the ground that act like ears so we can detect seismic waves from distant earthquakes.

Answer:

Explanation:

length = 4.7 m

extension x = (0.11 /100) m + 4.7 m

= 4.7011 m

force = 360 N

spring constant k = ?

formula : F = kx

k = F/ x

k = 360 ÷ 4.7011

k= 76.578 Nm^-1

The spring constant of the wire of a steel wire 4.7 m long stretches 0.11 cm when it is subjected to a tension of 360 N is 76.57 N/m.

Simple, symmetrical motion i.e., SHM is a genuinely fascinating kind of agitation. It is continuously used in the objects' oscillatory motion. Most springs have SHM. The "spring constants" that are intrinsic to springs determine how stiff they are. A well-known law, Hooke's law, describes the SHM and provides a formula for the applied force using the spring constant.

Simple harmonic motions and Hooke's law are related to the definition of the spring constant. Therefore, we must first examine Hooke's rule before attempting to define the spring constant and comprehend how it operates.

Given:

The tension force, T = 360 N,

The length of the wire, L = 4.7 meters,

The elongation, l = 0.11 cm,

Calculate the spring constant by the following formula,

k = T / l

( l = x(0.11 /100) m + 4.7 m= 4.7011 m)

Here, k is the spring constant.

Substitute the values,

k = 360 / 4.7011

k = 76.57 N / m

Therefore, the spring constant of the wire of a steel wire 4.7 m long stretches 0.11 cm when it is subjected to a tension of 360 N is 76.57 N/m.

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Since the velocity roll off the table with a horizontal velocity this means that the vertical initial velocity is zero. Now, while the ball is falling, the vertical motion is a free fall motion, which means that we can use the following equation:

In this case we know that:

• The final height, y, is zero (the ground).

• The initial velocity is zero.

• The time it takes to hit the ground is 0.5 s.

• The acceleration of gravity is 10.

Plugging these and solving for the initial height, y0, we have:

Therefore, the initial height is 1.25 m

Answer:

\(\huge\boxed{25.5mi}\)

Explanation:

Simply multiply the rate by the time

17 * 1.5 = 25.5 mi

Hope it helps :) and let me know if you want me to elaborate.

Explanation: A projectile motion is characterized by a motion whose path is alike to that of an arc. It already has its derived equations. For the maximum height H and the maximum range R, the equations are:

H = v₀²sin²θ/2g       ;       R = v₀²sin(2θ)/g

As you can observe, they are almost alike. Since they both contain v₀²/g, let's isolate this term for both equations:

v₀²/g = 2H/sin²θ

v₀²/g = R/sin (2θ)

Equating both equations:

2H/sin²θ = R/sin (2θ)

H = Rsin²θ/2sin(2θ)

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Explanation:

vi = 5 and vf = 8 are the initial and final velocities respectively. The change in time is t = 20 seconds.

So,

x = 0.5*(vi + vf)*t

x = 0.5*(5+8)*20

x = 130 meters

represents the distance traveled. The first equation shown above is one of the four kinematics equations.

Answer:    E: 6.0

Explanation:

If the switch is closed, and the circuit is allowed to reach steady state. The resulting steady-state current supplied by the battery is 6 A, hence option E is correct.

When the voltage across the resistor is equal to the battery voltage, we can use Ohm's Law to determine the steady state current. Where I is the current in amps and V is the voltage in volts.

At steady state, the equivalent circuit will look like there is no current flowing across the resistor because the inductor has zero resistance and behaves like a piece of wire that is short-circuited.

Due to the same potential difference across, the battery's steady-state current supply is,

i =  e ÷ R

= 30 ÷ 5

= 6 A

Therefore, the resulting steady-state current supplied by the battery is 6 A.

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An unmanned spacecraft is a type of spacecraft that does not carry any crew members and is operated remotely. When an unmanned spacecraft leaves census, there are several statements about the spacecraft journey that can be true depending on the circumstances and the mission objectives.

Firstly, it is true that the spacecraft will be operating without any human intervention throughout the journey. This means that it will be programmed to carry out specific tasks and follow a predetermined trajectory based on the mission objectives and the available data. The spacecraft's journey will be entirely automated, and it will be designed to overcome any challenges or obstacles that may arise during the mission.

Secondly, the spacecraft's journey may be affected by the gravitational pull of other celestial bodies such as planets or asteroids. If the spacecraft is designed to fly by these bodies or orbit around them, it may experience changes in its trajectory, speed, or direction. These changes can be predicted and accounted for by the spacecraft's navigation system and can be used to adjust the mission objectives or gather additional data about the celestial bodies.

Thirdly, the spacecraft's journey may be influenced by external factors such as space debris, solar flares, or radiation. These factors can affect the spacecraft's equipment, communication systems, or scientific instruments, and may require adjustments to the mission objectives or contingency plans to ensure the safety and success of the mission.

Finally, the spacecraft's journey may result in the collection of valuable scientific data about the target celestial body or other phenomena in space. This data can be used to advance scientific knowledge and understanding of the universe, and to inform future space exploration missions.

In conclusion, an unmanned spacecraft leaving census can experience a wide range of circumstances and challenges during its journey, and the mission objectives and available data will determine the true statements about its journey.

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Answer: Economists measure the gross domestic product to see how much economic activity there is in a particular country.

Explanation:

Answer:

Answer is explained in the explanation section below.

Explanation:

Note: This question is incomplete and lacks the necessary diagram of the circuits to solve for this question. However, I have found similar question on the internet and dragged the diagrams out of it. I have attached the diagrams of the circuits for your ease. It has two circuits to be solved. Attachment 1 refers to first circuit and Attachment 2 refers to second circuit.

Solution:

We are asked to find the potential difference and current through each resistor.

So,

Calculations for Circuit 1: Please refer to Attachment 1

First we need to find the Resistance:

Req = \(\frac{9 . 6}{9+6} +3\)

R = 6.6 Ohm

Now, we know that:

V = IR

So,

I = V/R

V = 12 V

I = 12 V/ 6.6 ohm

I = 1.82 Amperes.

Now,

The Potential Difference through 3 ohm resistor:

P.D = \(V_{3}\) = 1.82 x 3

\(V_{3}\) = 5.45 V

Now,

The Potential Difference through 6 ohm and 9 ohm resistor:

\(V_{6/9}\) =  12V - 5.45V

\(V_{6/9}\) =  6.545V

Now,

The current through 6 ohm is:

\(I_{6}\) = \(\frac{6.545}{6}\)

\(I_{6}\) = 1.09 A

Now,

The Current through 9 ohm is:

\(I_{9}\)  = \(\frac{6.545}{9}\)

\(I_{9}\)  = 0.72 A

Similarly,

Calculations for Circuit 2: Please refer to attachment 2:

Req = \(\frac{(30+50).90}{90+(30+50)} +20\)

Req = 62.35 ohm

I = V/R

I = 12 V/ 62.35ohm

I = 0.192 Amperes.

Now,

The The Potential Difference through 20 ohm resistor:

\(V_{20}\) = 20 x 0.192

\(V_{20}\) = 3.849 V

Now,

The The Potential Difference through 90 ohm resistor:

\(V_{90/(30+50)}\) = 12 - 3.849

\(V_{90/(30+50)}\) = 8.150

Now,

The Current through 90 ohm is:

\(I_{90}\)  = 8.1509/90

\(I_{90}\) = 0.0905 Amperes

Now,

The Current through 30 and 50 ohm is:

\(I_{30/50}\) = 0.192 - 0.0905

\(I_{30/50}\)  = 0.101 A

Now,

The Potential Difference through 50 ohm resistor:

\(V_{50}\) = 50 x 0.101

\(V_{50}\)  = 5.094 V

The Potential Difference through 30 ohm resistor:    

\(V_{30}\) = 30 x  0.101

\(V_{30}\) = 3.0566 V

By supplying the fundamental knowledge required to create new instruments and techniques for medical use, physics enhances our quality of life

From can openers, light bulbs, and mobile phones to muscles, lungs, and brains; from paintings, piccolos, and pirouettes to cameras, vehicles, and cathedrals; from earthquakes, tsunamis, and storms to quarks, DNA, and black holes, physics aids us in understanding the workings of the world around us.

The science of physics is the most fundamental and has many applications in contemporary technology. Because it makes it possible for smartphones, computers, televisions, watches, and many other modern technologies to function automatically, physics is crucial to modern technology.

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Answer:

F=w=ma                                                                                                                                                       OR by using equations of motions                                                                               vf=vi-at                    : a=vf-vi/t                                                              eq 1                         s=vit+1/2at squre                                                                                 eq 2                     2as=vf squre - vi squre                                                                        eq 3                                                                                                                                                                                  

Explanation:

where m is the mass of falling body , f is the weight is the force acting down ward , vf is the final velocity, vi is the inetial velocity , t is the time and s is the distance covered by a body.

Answer:

I agree

Explanation:

I agree because most of the times girls pass more time with their mom since they hace more things in common, it’s the same with the boys.

Analysing the question:

We are given:

mass of object (m) = 0.03 kg

height of object (h) = 2.94 m

acceleration due to gravity (a) = 10 m/s²

initial velocity (u) = 0 m/s [the object fell, we are NOT given any initial velocity]

final velocity (v) = v m/s

Solving for Final velocity:

from the third equation of motion:

v² - u² = 2ah

replacing the variables

(v)² - (0)² = 2(10)(2.94)

v² = 58.8

v = 7.67 m/s

Answer:

[b] it id heated from 4o

Explanation:

Answer:

the magnitude of the ball's acceleration as it comes to rest on the foam is 817.5 m/s²

Explanation:

Given the data in the question;

initial velocity; u = 0 m/s

height; h = 2.5 m

we find the velocity of the ball just before it touches the foam.

using the equation of motion;

v² = u² + 2gh

we know that acceleration due gravity g = 9.81 m/s²

so we substitute

v² = ( 0 )² + ( 2 × 9.81 × 2.5 )

v² = 49.05

v = √49.05

v = 7.00357 m/s

Now as the ball touches the foam

final velocity v₀ = 0 m/s

compresses S = 3 cm = 0.03 m

so

v₀² = v² + 2as

we substitute

( 0 )² = 49.05 + 0.06a

0.06a = -49.05

a = -49.05 / 0.06

a = -817.5 m/s²

Therefore, the magnitude of the ball's acceleration as it comes to rest on the foam is 817.5 m/s²

Answer:

5 m/s

Explanation:

Total distance = 300 + 100 = 400m

Total time = 60 + 20 = 80s

Velocity = 400/80 = 5m/s

Average velocity of man is 5 meter per second.

To find the average speed of an object we divide the total distance travelled by the total time time taken by object.

Total distance travelled by man = 300 + 100 = 400 m

Total time taken by man = 60 + 20 = 80 seconds

Average velocity,\(=\frac{400}{80} =5m/s\)

Thus, Average velocity of man is 5 meter per second.

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The first harmonic of the standing wave on a string with a loose end represents half a wavelength.

The fraction of a wavelength represented by the first harmonic is 1/2.

The higher harmonics of a standing wave on a string with a loose end are odd-number multiples of the first harmonic.

1. The first harmonic of a standing wave on a string with a loose end occurs when there is a node near the driver end and an antinode at the loose end. To measure the frequency of the first harmonic, we need to determine the fraction of a wavelength represented by this standing wave.

The first harmonic of the standing wave on a string with a loose end represents half a wavelength.

The first harmonic of a standing wave on a string with a loose end consists of a node near the driver end and an antinode at the loose end. This configuration creates the simplest standing wave pattern.

In a standing wave, a node is a point where the amplitude of the wave is always zero, representing a point of minimum displacement. An antinode, on the other hand, is a point of maximum displacement, where the amplitude is at its highest.

Since the loose end does not invert the phase of the wave upon reflection, the reflected wave and the original wave constructively interfere at the loose end, resulting in an antinode.

In the first harmonic, there is exactly half a wavelength between the node near the driver end and the antinode at the loose end.

Therefore, the fraction of a wavelength represented by the first harmonic is 1/2.

2. To predict the frequencies of higher harmonics, we can use the relationship that the frequency of each harmonic is a multiple of the frequency of the first harmonic. The higher harmonics can be calculated as follows:

Second Harmonic: The second harmonic consists of two nodes and one additional antinode compared to the first harmonic. The fraction of a wavelength for the second harmonic is 1/2 * 2 = 1. Thus, the second harmonic has a frequency that is twice that of the first harmonic.

Third Harmonic: The third harmonic consists of three nodes and two additional antinodes compared to the first harmonic. The fraction of a wavelength for the third harmonic is 1/2 * 3 = 1.5. Thus, the third harmonic has a frequency that is three times that of the first harmonic.

Fourth Harmonic: The fourth harmonic consists of four nodes and three additional antinodes compared to the first harmonic. The fraction of a wavelength for the fourth harmonic is 1/2 * 4 = 2. Thus, the fourth harmonic has a frequency that is four times that of the first harmonic.

In general, the higher harmonics of a standing wave on a string with a loose end are odd-number multiples of the first harmonic.

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The finished compost can be used to enrich soil for planting and gardening. Mix the compost into the soil or use it as a top dressing around plants.

Substances Used to Fill It:

A mixture of "brown" and "green" organic materials such as leaves, grass clippings, fruit and vegetable scraps, coffee grounds, and shredded paper can be used to fill the bin.

Household Items That Can Go in It:

Most fruit and vegetable scraps, eggshells, tea bags, coffee grounds, yard waste such as grass clippings and leaves, and shredded paper can be added to the compost bin. Meat, dairy, and fatty foods should be avoided.

How Long It Takes Before It Is Ready:

The compost should be ready to use in approximately 6 to 12 months, depending on the environmental conditions and the frequency of turning and mixing the compost.

How You Use the Compost:

The finished compost can be used as a nutrient-rich soil amendment for planting and gardening.

Compost Bin Design:

To add household items to your compost bin, simply add any of the following organic materials to the bin: fruit and vegetable scraps, coffee grounds and filters, tea bags, eggshells, yard waste such as leaves and grass clippings, and shredded paper.

Compost is ready to use in this much time:

The compost should be ready to use in approximately 6 to 12 months, depending on the environmental conditions and the frequency of turning and mixing the compost.

Use your compost this way:

The finished compost can be used to enrich soil for planting and gardening. Mix the compost into the soil or use it as a top dressing around plants.

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To solve this problem, we need to determine the frictional force acting on the block with different magnitudes of the applied force.

First, we need to find the normal force on the block, which is equal to the weight of the block. The weight of the block is given by:

W = mg = 2.5 kg x 9.8 m/s^2 = 24.5 N

Next, we need to find the force of the applied vertical force, which is given in the problem as "is". We can use trigonometry to find the vertical component of the force:

Fv = is sinθ

where θ is the angle between the force and the horizontal surface. Since the problem does not give us the value of θ, we will assume it to be 0°, which means the force is purely horizontal.

(a) If the magnitude of the applied force is 8.0 N, then the frictional force can be calculated as:

Ff = μsFn = μs(mg - Fv) = 0.40(24.5 - 0) = 9.8 N

(b) If the magnitude of the applied force is 10 N, then the frictional force can be calculated as:

Ff = μsFn = μs(mg - Fv) = 0.40(24.5 - 10) = 5.8 N

(c) If the magnitude of the applied force is 12 N, then the frictional force can be calculated as:

Ff = μkFn = μk(mg - Fv) = 0.25(24.5 - 12) = 3.1 N

Therefore, the magnitude of the frictional force acting on the block is 9.8 N, 5.8 N, and 3.1 N, for applied forces of 8.0 N, 10 N, and 12 N, respectively.

(a) When the horizontal force is 8 N the frictional force is 11.8 N.

(b) when the applied force is 10 N; the frictional force is 13.8 N.

(c) when the applied force is 12 N; the frictional force is 15.8 N.

(a) The magnitude of the frictional force on the block when the horizontal force is 8 N is calculated as;

F - Ff = ma

where;

F - μmg = ma

6 - 0.4 x 2.5 x 9.8 = 2.5 a

2.5 a = -3.8

a = -3.8/2.5

a = -1.52 m/s²

when the applied force is 8 N;

8 N - Ff = -1.52 m/s² x 2.5 kg

Ff = 11.8 N

(b) when the applied force is 10 N;

10 N - Ff = -1.52 m/s² x 2.5 kg

Ff = 13.8 N

(c) when the applied force is 12 N;

12 N - Ff = -1.52 m/s² x 2.5 kg

Ff = 15.8 N

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The total work done by this force is 28.9-1457.86 N m.

Total work is the sum of all the energy expended in completing a job or task. It is the amount of effort and energy expended to accomplish a goal or complete a task. Total work can be calculated by adding up all of the individual components of the job or task, such as time, effort, and materials.

The total work done by this force can be calculated using the formula W = F * Δx, where F is the force vector, and Δx is the displacement vector. In this case, the total work done is:
W = (4.70-379, 2.09) * (4.25, 3.69-245) = (19.9-944.81, 8.00-513.05) N m
Therefore, the total work done is 28.9-1457.86 N m.

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a) The total surface area of tin G in terms of π is 170π cm².

b) The mass of tin H is 336 g.

To solve the given problem, we need to determine the total surface area of tin G in terms of π and the mass of tin H. Since the mass of an empty cylindrical tin is proportional to its surface area, we can use the given information to find the solutions.

a) Total surface area of tin G in terms of π:

The surface area of a cylinder consists of two circular bases and the lateral surface area. The formula for the lateral surface area of a cylinder is given by:

Lateral surface area = 2πrh

where r is the radius of the base and h is the height of the cylinder.

In the case of tin G, the given dimensions are a radius of 5 cm and a height of 12 cm. Substituting these values into the formula, we can calculate the lateral surface area:

Lateral surface area = 2π(5 cm)(12 cm)

Lateral surface area = 120π cm²

Since the total surface area of the cylinder includes the two circular bases as well, we need to add their areas. The area of a circle is given by:

Area of a circle = πr²

The radius of the circular base of tin G is 5 cm, so the area of each circular base is:

Area of each circular base = π(5 cm)²

Area of each circular base = 25π cm²

To find the total surface area of tin G, we sum the lateral surface area and the areas of the two circular bases:

Total surface area of tin G = Lateral surface area + 2 × Area of each circular base

Total surface area of tin G = 120π cm² + 2 × 25π cm²

Total surface area of tin G = 120π cm² + 50π cm²

Total surface area of tin G = 170π cm²

Therefore, the total surface area of tin G in terms of π is 170π cm².

b) Mass of tin H:

We are given that the surface area of tin H is 792π cm². We can assume that the same proportionality factor applies as in tin G, so we can set up the following proportion:

(surface area of tin G) / (mass of tin G) = (surface area of tin H) / (mass of tin H)

Using the given values, we have:

(170π cm²) / (72 g) = (792π cm²) / (mass of tin H)

Cross-multiplying and solving for the mass of tin H, we get:

(170π cm²) × (mass of tin H) = (72 g) × (792π cm²)

mass of tin H = (72 g) × (792π cm²) / (170π cm²)

mass of tin H = 336 g

Therefore, the mass of tin H is 336 g.

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Answer:

- colony: mass of single-type cells formed from single cell/small chain; pair or small cluster of cells; visible to naked eye

- colony forming unit: not visible to eye, original single cell or small chain/pair or small cluster of cells FROM WHICH colony forms

- Streaking plate: producing isolated colonies upon incubation using streak plate methods in agar

- Quadrant streak: used when sample is of high density

- Zigzag pattern: used when sample is of low density

a. The limit of resolution on this microscope is approximately 1254nm.

b. Two points that are 300nm apart will blur into one and cannot be distinguished as separate using this microscope.

The formula for the limit of resolution (d) is given by:

d = (0.61 × λ) / NA

where λ is the wavelength of light and NA is the numerical aperture.

a. To find the limit of resolution:

Given:

Wavelength of light (λ) = 520nm

Numerical aperture of the low-power objective lens (NA) = 0.25

Substituting these values into the formula, we have:

d = (0.61 × 520) / 0.25

d = 1254nm

Therefore, the limit of resolution on this microscope is approximately 1254nm.

b. To determine if two points 300nm apart can be distinguished:

Given:

Separation between the points (d) = 300nm

Since the separation between the points (300nm) is smaller than the limit of resolution (1254nm), the two points will blur into one and will not be distinguishable as separate entities.

In conclusion:

a. The limit of resolution on this microscope is approximately 1254nm.

b. Two points that are 300nm apart will blur into one and cannot be distinguished as separate using this microscope.

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Pathogens grow best at temperatures between 5°C and 60°C.

The ideal temperature range for food-poisoning bacteria to develop is between 5°C and 60°C. The temperature danger zone is the name given to this temperature zone.

The bacteria can't thrive if potentially dangerous items are kept heated (above 60°C) or cold (below 5°C). Bacteria can double in number in as little as 20 minutes at temperatures between 40 °F and 140 °F, where they proliferate the fastest.

FATTOM, an acronym for food, acidity, time, temperature, oxygen, and moisture, stands for the elements necessary for bacterial growth.

Due to their availability of nutrition, energy, and other elements that the bacteria require for growth, foods offer the ideal conditions for bacterial growth.

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The vehicle accelerates at 3 m/s² when velocity changes from 5 m/s to 2m/s.

Detailed explanations are provided below. Step 1: Determine the initial speed (v). The car's initial speed in this instance is 5 m/s.

Step 2: Determine the final speed (vf). The car's final speed is 2 m/s in this instance.

Step 3: Determine the variation in velocity (v).

In this instance, the change in velocity is 3 m/s (5 m/s – 2 m/s), which is the difference between the initial velocity and the final velocity.

Step 4: Determine the acceleration in a.

The acceleration in this instance is 3 m/s², which is calculated by dividing the change in velocity by the amount of time taken.

The rate at which velocity changes is acceleration. Acceleration typically indicates a change in speed, but not always. Because its velocity is changing in the opposite direction, even if an object moves in a circle at the same speed, it will still accelerate.

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The kinetic energy of the book after it is slids a distance of 2 meters will be 10 Joules.

The work-energy theorem states that "the work done on an object is the change in its kinetic energy".

Hence;

Kinetic energy = work done

Note that: work-done is expressed as:

Work done = f × d

Where f is force applied and d is distance traveled.

Given that:

Force applied f = 5 newton

Distance d = 2 meters

Work done = ?

Plug these values into the above formula and solve for the workdone.

Work done = f × d

Work done = 5N × 2m

Work done = 10Nm

Work done = 10 Joules

Therefore, the kinetic energy is 10 Joules.

Option B) 10 J is the correct answer.

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Answer:

The two main areas of physical science are chemistry and physics. Chemistry is the study of the composition, structure, proper- ties, and reactions of matter. Physics is the study of matter and energy and the interactions between the two through forces and motion.

Explanation:

1. The maximum height above its launch level is 1.45 m

2. The time of flight of the ball is 1.1 s

1. How do I determine the maximum height?

From the question given above, the following data were obtained:

The maximum height can be obatianed as follow:

H = u²Sine²θ / 2g

H = [5.5² × (Sine 76)²] / (2 × 9.8)

Maximum height = 1.45 m

How do I determine the time of flight?

The time of flight of the ball can be obtained as follow:

T = 2uSineθ / g

T = [2 × 5.5 × Sine 76] / 9.8

Time of flight = 1.1 s

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