a vechile ravels at a constant speed of 6.0 meters per second round a horrizontal circular curve with a radius of 24 meters. the mass of the vechile is 4.4 x 10^3 kolgranms, an icy patch is location at p on the curve

Answers

Answer 1

17) The magnitude of the frictional force that keeps the vehicle on its circular path is  C) 6.6 x 103 N

The magnitude of the frictional force that keeps the vehicle on its circular path can be found by using the equation For = mv2/r, where m is the mass of the vehicle, v is the velocity of the vehicle, and r is the radius of the curve. Plugging in the given values, we get Ffr = (4.4 x 103 kg)(6.0 m/s)2/24 m = 6.6 x 103 N.

18) The amount of work done on the object is D) 30 J.

Work is equal to the amount of force multiplied by the distance the object has moved. In this case, the force is 5 N and the distance moved is 3 m, so the work done on the object is 5 N x 3 m = 15 Nm = 15 J.

19) The crane does work at the rate of C) 5 x 104 watts

The rate at which work is done is equal to the total amount of work done divided by the total time it took to do the work. In this case, the total amount of work done is 200 N x 50 m = 10,000 Nm = 10,000 J, and the total time taken is 5 s. So the rate of work done is 10,000 J/5 s = 2,000 J/s = 2 kW = 5 x 104 watts.

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Complete question:

A vehicle travels at a constant speed of 6.0 meters per second around a horizontal circular curve with a radius of 24 meters. The mass of the vehicle is 4.4 × 103 kilograms. An icy patch is located at P on the curve.

17) What is the magnitude of the frictional force that keeps the vehicle on its circular path?

A) 6.5 × 104 N B) 1.1 × 103 N C) 6.6 × 103 N D) 4.3 × 104 N

18) A net force of 5.0 newtons moves an object a distance of 3.0 meters in. How much work is done on the object?

A) 10. J B) 15 J C) 1.0 J D) 30. J

19) A crane raises a 200‐newton weight to a height of 50 meters in 5 seconds. The crane does work at the rate of

A) 2 × 103 watts B) 8 × 10−1 watt C) 5 × 104 watts D) 2 × 101 watts


Related Questions

PLEASE HELP!!!!! which statements correctly conpare the masses of protons,neutrons,and electrons​

PLEASE HELP!!!!! which statements correctly conpare the masses of protons,neutrons,and electrons

Answers

Protons and neutrons have similar mass
Electrons are smaller then a proton or a neutron

If the car has a mass of 0.2 kg, the ratio of height to width of the ramp is 12/75, the initial displacement is 2.25 m, and the change in momentum is 0.58 kg*m/s, how far will it coast back up the ramp before changing directions

Answers

Answer:

     l = 0.548 m

Explanation:

For this exercise we compensate by finding the speed of the car

         p = m v

         v = p / m

         v = 0.58 / 0.2

         v = 2.9 m / s

this is how fast you get to the ramp, let's use conservation of energy

starting point. Lowest point

         Em₀ = K = ½ m v²

final point. Point where it stops on the ramp

         \(Em_{f}\) = U = m g h

  mechanical energy is conserved

          Em₀ = Em_{f}

          ½ m v² = m g h

           h = \(\frac{m v^2}{2 g}\)

let's calculate

          h = \(\frac{0.2 \ 2.9^2}{2 \ 9.8}\)

          h = 0.0858 m

to find the distance that e travels on the ramp let's use trigonometry, we look for the angle

          tan θ = y / x

          tan θ = 12/75 = 0.16

          θ = tan⁻¹ 0.16

          θ = 9º

therefore

           sin 9 = h / l

           l = h / sin 9

           l = 0.0858 / sin 9

           l = 0.548 m

A 1 000 kg car is pulling a 300 kg trailer. Together, the car and trailer move forward with an acceleration of 2. 15 m/s². Ignore any force of air drag on the car and all friction forces on the trailer. Determine (a) the net force on the car​

Answers

(a) A 1 000 kg car is pulling a 300 kg trailer, together the car and trailer move forward with an acceleration of 2. 15 m/s² the net force acting on the car (and trailer) is approximately 2,795 Newtons (N).

To determine the net force on the car, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration.

The total mass of the car and trailer combined is the sum of their individual masses: 1,000 kg + 300 kg = 1,300 kg.

The acceleration of the car and trailer system is given as 2.15 m/s².

Using Newton's second law:

Net force = mass × acceleration

Net force = 1,300 kg × 2.15 m/s²

Net force ≈ 2,795 N

Therefore, the net force acting on the car (and trailer) is approximately 2,795 Newtons (N).

This net force is responsible for accelerating the combined mass of the car and trailer in the forward direction. It represents the sum of all external forces acting on the system, such as the force exerted by the car's engine and the tension in the connection between the car and trailer.

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2. If an em' of Hg weighs 13.6 g, what is the mass of a cylinder of: Sem and height 20 Cm

Answers

Answer:

Let the mass of mercury  m= 13.6 gm and volume be V=1cm3.

Now change in volume when it is heated upto 50oC,

ΔV=VαΔT

ΔV=1×1.82×10−4×50

ΔV=91×10−4cm3 

New volume V1=V+ΔV=1.0091cm3

New density ρ=V1m=1.009113.6=13.48gcm−3

Explanation:

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The position of a particle as it moves along the x axis is given for t > 0 by x = (t 3 - 3t 2 + 6t) m, where t is in s. Where is the particle when it achieves its minimum speed (after t = 0)?

Answers

Given

t>0

\(x=t^3-3t^2+6t\)

Procedure

Speed would be:

\(v=3t^2-6t+6\)

This is the graph for the particle velocity. As you can see the graph corresponds to a parabola that has its minimum value when the time t is equal to 1.

The x-axis corresponds to the time and the y-axis corresponds to the velocity.

Now, with that minimum velocity-time, we can calculate the position using the initial equation that describes the particle position for each time.

\(\begin{gathered} t=1 \\ x=1^3-3\cdot1^2+6\cdot1 \\ x=1-3+6 \\ x=4 \end{gathered}\)

The particle will be in position 4

The position of a particle as it moves along the x axis is given for t > 0 by x = (t 3 - 3t 2 + 6t)

A 6 kg object is accelerated 13 m/s2. What is the net force?

Answers

Answer:

78 kg/s^2

Explanation:

Answer = 78 kg per second squared

Force = mass (acceleration)

F = (6)(13)

F = 78 kg / sec squared

Newton
10. Your mass on Earth is 50kg. Planet Xenon has half the gravitational force of Earth. What
are your weight and mass on Planet Xenon?

Answers

Given parameters:

Mass on earth  = 50kg

Unknown:

Mass on planet Xenon = ?

Weight on planet Xenon = ?

Mass is the amount of matter contained in a particular substance.

Weight is the force on a body and it is derived from the product of mass and acceleration due to gravity.

         Weight  = mass x acceleration due to gravity

Planet Xenon has half the gravitational force of Earth.

 This translated gives \(\frac{9.8}{2}\)   = 4.9m/s²

Now, mass is always the same every where if the amount of matter in a substance does not change.

In this problem, mass = 50kg on planet xenon.

Weight =  mass x acceleration due to gravity  = 50 x 4.9  = 245N

The weight on Xenon is 245N and the mass is 50kg

a toy is tossed from the edge of a table. its path is shown; air resisitance is ignored. use the picture below to answer the following questions

Answers

As there is only one force acting on the ball i.e. gravitational force, the acceleration will be constant and downward. Also because ball moves in the direction of the acceleration, the velocity increases.

Acceleration - constant; velocity - increasing.

What is Acceleration?

Acceleration is the rate of change of velocity of an object over time. It can be positive, negative, or zero. Positive acceleration is when an object speeds up, negative acceleration is when an object slows down, and zero acceleration is when an object's velocity remains constant.

What is velocity?

Velocity is a measure of the speed and direction of an object's motion. It is typically measured in meters per second (m/s) or kilometers per hour (km/h). Velocity can also be expressed in other units, such as miles per hour (mph) or feet per second (ft/s). Velocity is related to a object's acceleration, as an object's acceleration is the rate of change in its velocity over time.

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A jar of tea is placed in sunlight until it reaches an equilibrium temperature of 33.1 ◦C . In an attempt to cool the liquid, which has a mass of 185 g , 90.3 g of ice at 0.0 ◦C is added. At the time at which the temperature of the tea is 26.3 ◦C , find the mass of the remaining ice in the jar. The specific heat of water is 4186 J/kg · ◦ C . Assume the specific heat capacity of the tea to be that of pure liquid water. Answer in units of g.(2 significant digits pls) ​

Answers

90.1 g of ice are still present in the container. Calculating the heat received by the ice to melt and the heat lost by the tea is necessary until it reaches an equilibrium temperature of 33.1 ◦C .

How do you calculate the amount of heat needed to melt ice?

Consider how much energy is required to melt one kilogramme of ice at zero degrees to produce one kilogramme of water at zero degrees. The energy required to melt one kilogramme of ice is determined by Q = mLf = (1.0 kg)(334 kJ/kg) = 334 kJ using the equation for a change in temperature.

In order to calculate how much heat is gained by the ice melting, we must first calculate how much heat is lost by the tea as it cools from 33.1 °C to 0.0 °C.

Tea loses the following amount of heat: q1 = m1CT1 = 0.185 kg) (4186 J/kg C) (33.1 C - 0.0 C) = 26298.93 J.

Heat required for ice to melt is given by the formula: q2 = m2Hf = (0.0903 kg)(333.55 kJ/kg) = 30062.56 J

We may set q1 = q2 to get the mass of ice still present because the system is in thermal equilibrium:

m2 = q2/Hf = 333.55 kJ/kg / 30062.56 J = 0.0901 kg

Finally, we round the mass to two significant digits and convert it to grammes:

m2 = 90.1 g

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Two cars stuck in a traffic jam and each sounds its horn at a frequency of 625 Hz. A bicyclist between the two cars, 4.50 m from each horn, is find that she is at a point of constructive interference. How far backward must she move to reach the nearest point of destructive interference? As a speed of sound use the speed of 343 m/s.

Answers

The bicyclist needs to move backward by a distance of 0.2744 m to reach the nearest point of destructive interference.

What is the distance for the nearest point of destructive interference?

The wavelength of the sound wave produced by the horns can be calculated as;

λ = v/f

λ = 343/625

λ = 0.5488 m

let the integer multiple of the wavelength = d

d = mλ

d = 4.50 + x

where;

x is the distance that the bicyclist is from the point of constructive interference towards one of the horns

4.50 + x = mλ

4.50 + x = m(0.5488)

let the odd multiple of half the wavelength = d'

d' = (2n + 1)(λ/2)

d' = 4.50 - y

where;

y is the distance that the bicyclist is from the point of destructive interference towards one of the horns.

4.50 - y = (2n + 1)(λ/2)

4.50 - y = (2n + 1)(0.2744)

mλ = 2n(λ/2) + (λ/2) + 4.50 - y

x - y = (2n + 1)(λ/2) - 4.50

x - y = (2n + 1)(0.2744) - 4.50

Let n = 0

x - y = (0 + 1)(0.2744) - 4.50

y = 4.50 - 0.2744

y = 4.2256

The distance is cakculated as;

4.50 - y = 0.2744 m

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two particles with equal charge experiences a force of 12 nN where they are 30 cm apart. what is the magnitude of the charge on each particle

Answers

Considering the Coulomb's Law, the magnitude of the charge on each particle is 4.2426 C.

Definition of Coulomb's Law

Coulomb's law or law of electrostatics is the relationship between the interactions of electric charges, that is, it explains the force experienced by two electric charges at rest.

This law says that the electric force with which two point charges at rest attract or repel each other is directly proportional to the product of the magnitude of both charges and inversely proportional to the square of the distance that separates them, expressed mathematically as:

\(F=k\frac{Qq}{d^{2} }\)

where:

F is the electrical force of attraction or repulsion. It is measured in Newtons (N).Q and q are the values ​​of the two point charges. They are measured in Coulombs (C).d is the value of the distance that separates them. It is measured in meters (m).k is a constant of proportionality called the Coulomb's law constant. It depends on the medium in which the charges are located. Specifically for vacuum k is approximately 9×10⁹ \(\frac{Nm^{2} }{C^{2} }\).

The force is attractive if the charges are of opposite sign and repulsive if they are of the same sign.

Magnitude of the charge on each particle

In this case, you know that:

F= 12 nN= 1.8×10⁻⁸ N (being 1 nN= 1×10⁻⁹ N)k= 9×10⁹ \(\frac{Nm^{2} }{C^{2} }\)Q= qd= 30 cm= 0.3 m (being 100 cm= 1 m)

Replacing in the Coulomb's Law:

\(1.8x10^{-8} N=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{Qq}{(0.3 m)^{2} }\)

Being Q=q:

\(1.8x10^{-8} N=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{q^{2} }{(0.3 m)^{2} }\)

Solving:

1.8×10⁻⁸ N÷ 9×10⁹ \(\frac{Nm^{2} }{C^{2} }\)= q²÷ (0.3 m)²

2×10⁻¹⁸ C²/m²= q²÷ (0.3 m)²

2×10⁻¹⁸ C²/m²= q²÷ 0.09 m²

2×10⁻¹⁸ C²/m² ×0.09 m²= q²

1.8×10⁻¹⁹ C²= q²

√1.8×10⁻¹⁹ C²= q

4.2426 C= q= Q

Finally, each charge has a value of 4.2426 C.

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What product is formed by a reaction in which the hydrogen atoms of an acid are replaced by
the atoms of a metal?
A base
An oxide
A salt
An acid

Answers

The reaction of Acids with most metals and, when they do, a salt is produced without water.

A motorcycle travels at 55m / s, taking 5s to stop and relax Relax. Calculate the acceleration of that motor.

Answers

Answer:

The acceleration of the motorcycle = -11m/s²

Explanation:

The initial speed of the motorcycle, u = 55 m/s

The motorcycle takes 5 seconds to stop and relax

That is, the final speed, v = 0 m/s

Time, t = 5 seconds

Acceleration = (Change in speed)/Time

\(\begin{gathered} a=\frac{v-u}{t} \\ a=\frac{0-55}{5} \\ a=\frac{-55}{5} \\ a=-11m/s^2 \end{gathered}\)

The acceleration of the motorcycle = -11m/s²

A sidewalk has a length of 75.00m. How many inches is this? (Hint: you need to use two unit conversion fraction. 1 cm equals about 0.3937 inches)

Answers

Length = (75.00 m)

Length = (75 meter) x (3.28084 foot/meter) x (12 inch/foot)

Length = (75 x 3.28084 x 12) (meter-foot-inch / meter-foot)

Length = 2,952.76 inches

8. Combine the ice and the room-temperature water. Stir the mixture until the thermometer stays at the
same temperature for at least 1 minute. This means the thermometer is at the same temperature as the
mixture.
9. Record the temperature.
10. Stir the ice-water mixture occasionally for another 5 minutes. Then, record its temperature.
Table B: Part 2 Observations
Initial temperature (in "C) of the room-temperature water
Initial temperature (in "C) of the warm water
Temperature (in "C) of mixed warm water and room-temperature water
Temperature (in "C) of mixed warm water and room-temperature water after 5 min
Temperature (in "C) of mixed warm water and room-temperature water after 10 min
Initial temperature (in "C) of the ice
Temperature (in °C) of mixed ice and room-temperature water
Temperature (in "C) of mixed ice and room-temperature water after 5 min
Physical Science page

8. Combine the ice and the room-temperature water. Stir the mixture until the thermometer stays at thesame

Answers

The answer for the experiment is obtained by the principle of Newton's law of cooling. The initial temperature of the Room is taken as 32°C.

The ice cubes are mixed with room-temperature water, the ice starts to melt and the water becomes cold. This is because the ice and water have two different temperatures and when they are mixed there is an exchange of heat is taken place. When the ice cubes mixed with water the room temperature is decreases from 32°C. After stirring the mixture because of the heat released, the temperature increases.

When the ice-water mixture is stirred, the heat energy is evolved which melts the ice in the mixture, and therefore the temperature increases gradually. And stirring of water for every 5 minutes leads ice cubes to melt completely to form water and the level of water increases in the final stage. This was given by Newton's law of cooling.

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Which of the following helps prevent and cope with heat-related conditions?

Drinking water


Wear proper clothing


Rest frequently


all of the above

Answers

drinking water is ur answer.

An action which would help in preventing and coping with heat-related conditions is: A. Drinking water.

What is heat?

Heat can be defined as a form of energy that is transferred from a physical object (body) to another, as a result of a difference in temperature. Also, heat is a condition of weather that is generally characterized by a high degree of temperature.

This ultimately implies that, heat is most likely to cause dehydration and high body temperature.

In order to prevent and cope with heat-related conditions, you should ensure that you drink water at regular intervals for hydration.

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Given a 20.0 volt battery connected to two 40.0-ohm resistors connected in parallel. What current comes out of the battery in Amperes? 2.00 1.00 0.500 3.00 4.00

Answers

Given

The voltage of the battery, V=20.0 V

The resistance of the two resistors are 40 ohm each.

The two resistance are connected in parallel

To find

The current through the circuit.

Explanation

The resistors are connected in parallel

Thus the equivalent resistance is

\(R=\frac{40\times40}{40+40}=20\text{ ohm}\)

By Ohm's law,

\(V=RI\)

where I is the current through the battery

Putting the values

\(\begin{gathered} 20=20I \\ \Rightarrow I=1A \end{gathered}\)

Conclusion

The current through the battery is 1.00 A

Please help me in questions 4_5_6

Please help me in questions 4_5_6

Answers

Yes, the force of the engine does work on the car as it accelerates the car forward. Work is defined as the transfer of energy that occurs when a force is applied over a distance, and in this case, the force of the engine is causing the car to move, so it is doing work.

How to explain the force

As the car gains speed, its kinetic energy increases, which means it has more energy of motion. Kinetic energy is defined as one-half of the mass of an object times its velocity squared, so as the car's speed increases, so does its kinetic energy.

The gravitational potential energy of the car will remain constant as long as it stays on a horizontal road, assuming there is no change in elevation. Gravitational potential energy is the energy an object possesses due to its position in a gravitational field, and since the car's position relative to the ground is not changing, its gravitational potential energy will remain constant.

The tractive force of the engine may change depending on the speed of the car and the resistance to motion that the car is encountering. As the car speeds up, the air resistance acting on the car will increase, which will require more force from the engine to maintain the same acceleration. Additionally, if the road surface is rough or there are inclines, the tractive force required to maintain the same speed or acceleration will also increase.

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What is the Russell-Vogt theorem? Why is it important? How does it shed
light on the existence of the Main Sequence?

Answers

According to the Vogt-Russell theorem, the structure of a star in hydrostatic and thermal equilibrium with all energy produced from nuclear processes is uniquely defined by its mass and chemical element distribution throughout its interior.

Despite being called a theorem, the Vogt-Russell theorem has never been officially proven. The theorem is named for the astronomers Heinrich Vogt and Henry Norris Russell, who separately devised it.

What is the relevance of the Vogt-Russell theorem?

The Russell-Vogt Theorem, which states that the nature of a star is essentially entirely governed by its mass, age, and starting composition, explains why stars have such a well-defined brightness and temperature range while they are burning hydrogen in their interiors.

This trend is especially noticeable because the initial composition has little influence in comparison to the other two. The upper luminosity limit is caused by stars more massive than about 100 times the mass of the sun blowing themselves apart, while the lower luminosity limit is caused by objects less massive than about 0.08 times the mass of the sun failing to develop satisfactory pressure and temperature in their cores to burn hydrogen.

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I want for more information for these subject ,EXITONS AND BIEXITONS IN SEMICONDUCTOR QUANTUM DOLLS, I have to write a project about EXITONS AND BIEXITONS IN SEMICONDUCTOR QUANTUM DOLLS.

Answers

The study of excitons and biexcitons in semiconductor quantum dots is a fascinating and rapidly evolving field in semiconductor physics. Excitons are bound states of an electron and a hole created by the absorption of a photon in a semiconductor material. These quasi-particles exhibit unique optical and electronic properties, making them important for various applications such as optoelectronic devices and quantum information processing.

1. Introduction:

  - Provide an overview of excitons and biexcitons in semiconductor quantum dots.

  - Mention their significance in semiconductor physics and applications.

2. Excitons:

  - Define excitons as bound electron-hole pairs.

  - Explain how they form through photon absorption.

  - Discuss their properties, such as energy levels, binding energies, and radiative lifetimes.

  - Describe their behavior under external electric and magnetic fields.

3. Semiconductor Quantum Dots:

  - Introduce semiconductor quantum dots as nanoscale structures with unique quantum confinement effects.

  - Explain the synthesis methods for quantum dots, such as colloidal synthesis or epitaxial growth.

  - Discuss their size-dependent electronic and optical properties.

4. Biexcitons:

  - Define biexcitons as two excitons bound together.

  - Explain the conditions for biexciton formation.

  - Discuss their properties, including binding energies, lifetimes, and interaction with external fields.

5. Experimental Techniques:

  - Describe the experimental methods used to study excitons and biexcitons in semiconductor quantum dots, such as photoluminescence spectroscopy or ultrafast spectroscopy.

  - Highlight the importance of time-resolved techniques for understanding exciton dynamics.

6. Applications:

  - Discuss the applications of excitons and biexcitons in semiconductor quantum dots, such as in optoelectronic devices (e.g., solar cells, light-emitting diodes) and quantum information processing (e.g., quantum dots as qubits).

7. Current Research and Future Directions:

  - Provide an overview of recent advancements in the field.

  - Mention ongoing research efforts and emerging areas of interest.

  - Discuss potential future directions and challenges in the study of excitons and biexcitons in semiconductor quantum dots.

8. Conclusion:

  - Summarize the key points discussed in the project.

  - Emphasize the significance of excitons and biexcitons in semiconductor quantum dots for fundamental research and technological applications.

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if you pump air into a 100ml balloon, how far will that air spread?

Answers

if you pump air into a 100ml balloon, the distance is that the Gases will be ale to spread out very quickly to fill all the space that has been available to them in the balloon.

Does the volume grow when gas is added?

The capacity of a container increases as the gas content rises. A container's capacity reduces as the gas content is reduced. Of course, this assumes that the container's walls are expandable.

Therefore, Gases swiftly disperse to occupy all available area. Imagine blowing up a balloon. When you blow air into a balloon, the entire balloon is filled. A gas will take up all of the available space. This is due to the fact that a gas's particle structure is random.

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what is the velocity of the object 2.3 seconds after it is released from the top of the empire state building?

Answers

Explanation:

Object is under the effect of the acceleration of gravity

v = 1/2 a t^2       a = 9.81 m/s^2   t = 2.3

v = 25.9 m/s^2 = ~ 26 m/s   ( two significant digits)

Starting with the definition 1 in. = 2.54 cm, find the number of (a) kilometers in 1.20 mile and (b) feet in 1.80 km.

Answers

Explanation:

\(miles \: to \: km \\ = 1.2 \: miles \times \frac{1 \: km}{1.6093 \: miles} \\ = 0.7457 \\ \\ km \: to \: feet \\ = 1.8 \: km \times \frac{3280 \: ft}{1 \: km} \\ = 5904 \: ft\)

Help please i will mark brainlist!!

Help please i will mark brainlist!!

Answers

The answer is A.


p=m/v
p= 240/60
p= 4 g/cm^3

Answer:

A is correct a.p.e.x approved

Explanation:

have a nice day

If the mass = 1.50 kg, F1 = 1.50 N, 0, = 35.0°, 02 = 45.00 and the acceleration of the object in the + x direction is 1.0 m/s?, what must be the force F2? (Shown in image)

If the mass = 1.50 kg, F1 = 1.50 N, 0, = 35.0, 02 = 45.00 and the acceleration of the object in the +

Answers

The magnitude of force F₂ is determined as 0.38 N.

What is the magnitude of F₂?

The magnitude of force (F₂) is calculated by applying Newton's second law of motion as follows;

F = ma

where;

F is the resultant of the two forcem is the mass of the objecta is the acceleration of the object

The resultant forces in the x-direction is given as

F₁cosθ₁  +  F₂cosθ₂ = maₓ

(1.5 cos35) + F₂(cos45) = 1.5 x 1

1.23 + 0.71F₂ = 1.5

0.71F₂ = 1.5 - 1.23

0.71F₂ = 0.27

F₂ = 0.27/0.71

F₂ = 0.38 N

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What is the difference between dynamics and kinematics

Answers

Answer:

Kinematics is the study of how things move while dynamics is the study of forces and motion

A 2.0-kg block slides on a rough horizontal surface. A force (magnitude P = 4.0 N) acting parallel to the surface is applied to the block. The magnitude of the block's acceleration is 1.2 m/s2. If P is increased to 5.0 N, determine the magnitude of the block's

Answers

When the applied force increases to 5 N, the magnitude of the block's acceleration is 1.7 m/s².

Frictional force between the block and the horizontal surface

The frictional force between the block and the horizontal surface is determined by applying Newton's law;

∑F = ma

F - Ff = ma

Ff = F - ma

Ff = 4 - 2(1.2)

Ff = 4 - 2.4

Ff = 1.6 N

When the applied force increases to 5 N, the magnitude of the block's acceleration is calculated as follows;

F - Ff = ma

5 - 1.6 = 2a

3.4 = 2a

a = 3.4/2

a = 1.7 m/s²

Thus, when the applied force increases to 5 N, the magnitude of the block's acceleration is 1.7 m/s².

Learn more about frictional force here: https://brainly.com/question/4618599

Relative gravitational potential energy depends on gravity, mass, and height measured from the ____.

Answers

Answer:

We dont have a understandable Ansewer for this

Explanation:

What is the period of revolution of a satellite with mass m
that orbits the earth in a circular path of radius 9480 km
(about 3100 km
above the surface of the earth)?
Express your answer in seconds.

Answers

To find the period of revolution of a satellite orbiting the Earth in a circular path, we can use the formula:

T = 2π√(r³/GM)

Where:

T is the period of revolution,

r is the radius of the orbit,

G is the gravitational constant (approximately 6.67430 × 10^(-11) m³/(kg·s²)),

M is the mass of the Earth (approximately 5.972 × 10^24 kg).

Given:

Radius of the orbit, r = 9480 km = 9480 × 10^3 m

Radius of the Earth, R = 6371 km = 6371 × 10^3 m (approximately)

Height above the surface of the Earth = r - R = (9480 × 10^3) - (6371 × 10^3) m

We can calculate the total distance between the satellite and the center of the Earth as the sum of the radius of the Earth and the height above the surface:

Total distance = R + (9480 × 10^3 - 6371 × 10^3) m

Now, substituting the values into the formula for the period of revolution:

T = 2π√((R + (9480 × 10^3 - 6371 × 10^3))^3 / (G * M))

Calculating the period of revolution:

T = 2π√(((6371 × 10^3) + (9480 × 10^3 - 6371 × 10^3))^3 / (6.67430 × 10^(-11) * (5.972 × 10^24)))

Simplifying the expression:

T = 2π√((9480 × 10^3)^3 / (6.67430 × 10^(-11) * (5.972 × 10^24)))

Calculating the value:

T ≈ 2π√(8.982144 × 10^19 / (4.4649917 × 10^14))

Simplifying further:

T ≈ 2π√(2015.75 × 10^5)

Calculating the square root:

T ≈ 2π * 1422.374108

Calculating the value:

T ≈ 8952.778661 s

Therefore, the period of revolution of the satellite is approximately 8952.778661 seconds.

Can someone help me

Can someone help me

Answers

Answer:

Explanation:before the phase change the substance is a particle.

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