A uniform30 cmruler of mass50 gis attached to a friction-less vertical wall by a nail through one end. A horizontal force F=0.545 Nis applied to the end of the rod. If the rod is tilted at 40∘ from the vertical, what is the angular acceleration of the rod (around the nail) at this instant? Please enter a numerical answer below. Accepted formats are numbers or "e" based scientific notation e.g.0.23,−2,1e6, 5.23e-8

The bus with 12 passengers will have less kinetic energy.

option B.

The kinetic energy of an object is the energy possessed by an object due to its motion.

Mathematically, the formula for kinetic energy is given as;

K.E = ¹/₂mv²

where;

The bus with greater number of passengers will have more kinetic energy and vice versa.

Thus, the bus with 12 passengers will have less kinetic energy and the bus with 30 passengers will have more kinetic energy.

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Given data:

The mass of cockroch is m.

The mass of disk is 5m.

The initial speed of cockroch and disk is ω=0.26 rad/s.

Considering the radius of the disk is r, then the halfway radius of the disk will be r/2.

Part (a)

The final angular velocity can be calculated as,

Thus, the final speed is 1.04 rad/s.

Part (b)

The ratio of kinetic energy can be calculated as,

Thus, the ratio of kinetic energy is 7.42.

If Stas is pushing his car which has broken down and does 3 KJ of work against friction and moves it a distance of 12m, the friction force is 250 N

W = F d

W = Work done

F = Force

d = Distance

W = 3 KJ = 3 * 10³ J

d = 12 m

F = W / d

F = 3 * 10³ / 12

F = 0.25 * 10³

F = 250 N

Therefore, the friction force he has to push against is 250 N

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Answer:

a

Explanation:

ajjkiikkkkkhglutfgkitfgghiiij

Waves are an essential part of the physical world, and they play a crucial role in our daily lives. Waves can be broadly categorized into two types: mechanical waves and electromagnetic waves. Mechanical waves require a medium to travel, such as sound waves, while electromagnetic waves do not need a medium and can travel through space, such as light waves. Both types of waves exhibit unique properties, including amplitude, frequency, wavelength, and speed.

Sound waves are mechanical waves that require a medium to travel, such as air or water. These waves are longitudinal, meaning they move in the same direction as the wave. They have properties such as amplitude, which is the magnitude of the wave, and frequency, which is the number of waves that pass through a point in a given amount of time. Sound waves have a wide range of frequencies, from low-frequency waves, such as the sound of a bass guitar, to high-frequency waves, such as a dog whistle.

Electromagnetic waves, on the other hand, do not require a medium to travel and can travel through a vacuum, such as space. These waves are transverse, meaning they move perpendicular to the wave. They also have properties such as frequency and amplitude. Electromagnetic waves have a wide range of frequencies, from radio waves used to transmit music to gamma rays used to treat cancer.

In our daily lives, waves play a significant role. For example, we use radio waves to listen to the radio, watch television, and make phone calls. We use microwaves to heat food quickly, and we use infrared waves to sense heat and motion in security systems. We also use visible light waves to see the world around us, and ultraviolet waves to help our bodies produce vitamin D.

In conclusion, waves are a fundamental aspect of the physical world and play a significant role in our daily lives. Whether it's listening to the radio, using Bluetooth in our cars, or making phone calls, waves are involved in almost everything we do. Understanding the properties of waves, including frequency, amplitude, and wavelength, is crucial in understanding how waves function and how they affect our daily lives.

The equilibrium distance between the centers of the balls will be

x =\((2q1q2lmg)^{\frac{1}{3} }\).

To find the equilibrium distance between the two balls, we need to consider the forces acting on each ball. The main forces acting on each ball are the gravitational force and the electrostatic force between the two balls.

The gravitational force on each ball is given by:

Fg = mg (where g is the acceleration due to gravity)

The electrostatic force between the two balls is given by:

Fe = kq1q2/x² (where k is Coulomb's constant, and x is the distance between the centers of the two balls)

For equilibrium to occur, the net force on each ball must be zero. Therefore, we can set up the following equation:

Fg - Fe = 0

Substituting in the values for Fg and Fe, we get:

mg - (kq1q2/x²) = 0

Solving for x, we get:

x =\((2q1q2lmg)^{\frac{1}{3} }\).

where l is the length of the silk threads.

So, the equilibrium distance between the centers of the balls will be:

x =\((2q1q2lmg)^{\frac{1}{3} }\).

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Answer:

Explanation:

1. Place a cup of hot tea on a flat surface.

2. Place a thermometer in the tea and record the temperature.

3. Place a fan in front of the cup of tea and turn it on.

4. Place the thermometer in the tea again and record the temperature.

5. Compare the two temperatures and observe the difference.

6. The difference in temperature is an indication of the thermal energy that has been dissipated from the cup of hot tea.

The maximum potential difference that can be applied to a 1.0-nF vacuum capacitor with a separation of 1.0 mm is 30 kV and the maximum charge that can be stored on the capacitor without it discharging is 30 microcoulombs.

a. To find the maximum potential difference that can be applied to the vacuum capacitor, we need to calculate the breakdown voltage of air and then multiply it by 10. The breakdown voltage of air is about 3 million volts per meter (3 MV/m), or 3 kV/mm.

The separation of the plates is 1.0 mm, so the maximum potential difference that can be applied to the capacitor is:

V = Ed = (10 x 3 kV/mm) x 1.0 mm = 30 kV

Therefore, the maximum potential difference that can be applied to a 1.0-nF vacuum capacitor with a separation of 1.0 mm is 30 kV.

b. The maximum charge that can be stored on a capacitor is given by:

Q = CV

where Q is the charge, C is the capacitance, and V is the potential difference.

In this case, C = 1.0 nF and V = 30 kV. Converting the capacitance to farads and the potential difference to volts, we get:

C = 1.0 x 10^-9 F

V = 30 x 10^3 V

So, the maximum charge that can be stored on the capacitor is:

Q = CV = (1.0 x 10^-9 F) x (30 x 10^3 V) = 30 x 10^-6 C

Therefore, the maximum charge that can be stored on the capacitor without it discharging is 30 microcoulombs.

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Answer:

To establish this relationship we must examine the potentials that these forces create. The electrical potential is described by

        Ve = k q / r

The potential for strong nuclear force is

       Vn (r) = - gs / 4pir exp (-mrc / h)

Where gs is the stacking constant and r the distance between the nucleons,

We can compare these potentials where the force is derived from the relationship

       E = -dU / dr

       F = q E

Explanation:

Answer:

if the question is referring to what happens when ice freezes you could say that the water molecules have lass energy so they don't move around as much

Answer:

D. Weight

Explanation:

Hope that helps:)

The final momentum is 25 Kg m/s

In physics, momentum is a measure of an object's motion, calculated by multiplying the object's mass by its velocity. Mathematically, momentum is represented by the symbol "p" and can be expressed as:

p = mv

where "p" is momentum, "m" is mass, and "v" is velocity. Momentum is a vector quantity, meaning that it has both a magnitude (the amount of momentum) and a direction (the direction of the motion).

Given that;

Ft = mv - mu

It then follows that;

F = force

m = mass

v and u are the initial and the final velocities

Thus;

5 * 5 = 5v

v = 25/5

= 5 m/s

The final momentum is thus;

5 m/s * 5 Kg

= 25 Kg m/s

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Answer:

I know this isn't much help but its not B

Explanation:

Answer:

D

Explanation:

The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².

To calculate the average acceleration of the motorcycle, we can use the formula:

Average acceleration = (final velocity - initial velocity) / time

First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.

Converting the final velocity:

Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s

Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:

Average acceleration = (21.67 m/s - 0 m/s) / time

To find the time taken to reach this velocity, we need to use the formula for average speed:

Average speed = total distance/time

Rearranging the formula:

time = total distance / average speed

Plugging in the values:

time = 50 m / 21.67 m/s ≈ 2.31 seconds

Now we can calculate the average acceleration:

Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²

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According to the Keynesian view, manipulating foreign sector spending is not a reliable way to move the U.S. economy toward a more acceptable equilibrium because it does not address the fundamental causes of economic instability.

Keynesian economics focuses on the role of domestic demand in driving economic growth and stability. The government can use fiscal and monetary policy to stimulate aggregate demand and promote full employment. However, changes in foreign sector spending can be unpredictable and beyond the control of domestic policymakers. For instance, an increase in foreign demand for U.S. exports could boost economic growth and employment in the short run, but it may not be sustainable if the foreign demand later decreases. Similarly, a decrease in foreign demand for U.S. exports could have negative short-term effects on the economy, but it may not necessarily lead to a long-term decline. In short, Keynesian economics emphasizes the importance of domestic demand management and stabilizing the economy through government intervention. While changes in foreign sector spending can have some impact on the economy, they are generally seen as unreliable and unpredictable, and therefore not a reliable tool for achieving economic stability in the long run.

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Answer:

a. 50 m/s b. 0 m/s c. 50 m/s d. 4.04 s e. -39.6 m/s f. 63.78 m/s g. 202 m

Explanation:

a. What is the initial horizontal velocity?

Since the object is launched horizontally, it initial horizontal velocity is 50 m/s

b. What is the initial vertical velocity?

Since the object is launched horizontally, it has no initial vertical component. So, its initial vertical velocity is 0 m/s

c. What is the final horizontal velocity?

Its final horizontal velocity is 50 m/s since no force acts on it in the horizontal direction to change its value.

d. How much time did it take for the object to hit the ground?

We use the equation s = ut - 1/gt² since the object is falling under gravity where u = initial vertical velocity = 0 m/s, s = height of cliff = 80 m, g = acceleration due to gravity = -9.8 m/s² and t = time it takes the object to hit the ground.

s = ut - 1/2gt²

80 m = 0 × t - 1/2 × -9.8 m/s² × t²

80 m = 4.9 m/s² × t²

t² = 80 m ÷ 4.9 m/s²

t² = 16.33 s²

t = √(16.33 s²)

t = 4.04 s

e. What is the final vertical velocity?

Using v = u + at where u = initial vertical velocity = 0 m/s, v = final vertical velocity, a = acceleration = -g =  -9.8 m/s²and t = time it takes object to reach the ground = 4.04 s.

Substituting these values into the equation, we have

v = u + at

v = 0 m/s + (-9.8 m/s²) × 4.04 s

v = -39.6 m/s

f. What is the final resultant speed?

The final resultant speed v' is the resultant of the final horizontal velocity and the final vertical velocity. Let u' = final vertical velocity = 50 m/s.

v' = √(u'² + v²)

v' = √((50 m/s)² + (-39.6 m/s)²)

v' = √(2500 m²/s² + 1568.16 m²/s²)

v' = √(4068.16 m²/s²)

v' = 63.78 m/s

g. How far from the base of the cliff will the projectile land?

The distance from the base of the cliff, d where the projectile lands is

d = u't where u' = horizontal velocity = 50 m/s and t = time it takes object to land = 4.04 s

d = 50 m/s × 4.04 s

d = 202 m

Answer:

9v

Explanation:

Given that the water flows at speed v in a pipe of radius r.

Let \(v_2\) is the speed of water flow where the radius of the pipe is r/3.

By using the continuity equation, the mass flow rate of water is the same at all the cross-sections of the pipe, wh have

\(\rho_1A_1_v_1 =\rho_2A_2_v_2\)

Where \(\rho_1, A_1\) and \(v_1\) are the density, area of the cross-section and speed at cross-section 1 and  \(\rho_2, A_2\) and \(v_2\) are the density, area of the cross-section and speed at cross-section 2.

As the density of the water remains constant. so \(\rho_1=\rho_2\).

\(\Rightarrow A_1_v_1 =A_2_v_2 \\\\\Rightarrow (\pi r^2)v=(\pi (r/3)^2v_2 \\\\\Rightarrow r^2v=\frac {r^2}{9}\times v_2 \\\\\Rightarrow v= \frac {v_2}{9} \\\\\Rightarrow v_2=9v.\)

Hence, the speed of the water flow where the radius is r/3 is \(9v\).

Answer:

goalindia

goalindiaGiven:

goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kg

goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 W

goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:

goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.

goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.Calculation:

goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.Calculation:- The Power can be given by the formula:

goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.Calculation:- The Power can be given by the formula:P = F × v

goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.Calculation:- The Power can be given by the formula:P = F × v⇒ v = P/F

goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.Calculation:- The Power can be given by the formula:P = F × v⇒ v = P/F⇒ v = P/mg

goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.Calculation:- The Power can be given by the formula:P = F × v⇒ v = P/F⇒ v = P/mg⇒ v = 1357.72/(226.8 × 9.8)

goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.Calculation:- The Power can be given by the formula:P = F × v⇒ v = P/F⇒ v = P/mg⇒ v = 1357.72/(226.8 × 9.8)⇒ v = 1357.72/2222.64

goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.Calculation:- The Power can be given by the formula:P = F × v⇒ v = P/F⇒ v = P/mg⇒ v = 1357.72/(226.8 × 9.8)⇒ v = 1357.72/2222.64⇒ v = 0.61 m/s

goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.Calculation:- The Power can be given by the formula:P = F × v⇒ v = P/F⇒ v = P/mg⇒ v = 1357.72/(226.8 × 9.8)⇒ v = 1357.72/2222.64⇒ v = 0.61 m/s- So, the velocity of the car will be 0.61❤

Answer:GAS

Explanation:

Answer:

The answer will be A. Wedge

Explanation:

Creating an effective system to solve problems is beneficial in various ways as it enables an individual to come up with a clear and concise solution to any problem or situation that may arise.

Some of the benefits that I would like to see in my own life as I begin to apply the 4-step problem-solving process are:Improved decision making skills- The 4-step problem-solving process will help me to make better decisions since it requires that I identify the problem, gather information, develop solutions, and implement the most suitable solution. This approach will help me to weigh my options carefully and make decisions based on logic rather than emotions.Improved communication skills- The process of problem-solving requires communication between team members. As I begin to apply the 4-step problem-solving process, I would like to develop better communication skills that will enable me to express my ideas clearly and succinctly.

This will be helpful not only in my personal life but also in my professional life where effective communication is a key to success.Improved critical thinking skills- The process of problem-solving requires critical thinking. By applying the 4-step problem-solving process, I would like to improve my critical thinking skills by learning how to analyze information, assess the problem, and develop solutions based on the available information.Improved productivity- The 4-step problem-solving process is a structured approach that helps to identify problems and develop solutions in a systematic manner. By applying this approach in my life, I would like to improve my productivity since I will be able to solve problems more efficiently and effectively.

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If we replace the incandescent bulb with a voltage meter and return the loop to its original configuration, then moving the bar magnet back and forth through the loop will induce an electrical current in the loop, as described by Faraday's law of electromagnetic induction.

A magnet is a material or object that produces a magnetic field, which is a force that can attract or repel certain other materials, such as iron or steel. The magnetic field is created by the motion of electric charges within the magnet, which align in such a way that they produce a net magnetic field. Magnets can be made from a variety of materials, including iron, cobalt, nickel, and certain alloys. They come in many different shapes and sizes, including bars, discs, horseshoes, and rings.

Here,

The type of current that is generated depends on the direction and rate of the magnet's motion. If the magnet is moved back and forth with a constant speed and in a straight line, the current induced in the loop will be an alternating current (AC), because the direction of the current will reverse every time the magnet changes direction. This can be observed by the voltage meter reading a voltage that periodically changes in direction.

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Answer:

0.705 kg less

Explanation:

Altitude at sea level = 0 ft

Altitude after climbing = 30,000 ft = 30,000 x 0.3048 = 9,144 m

Weight = W = mg

Change in weight = ΔW = (M-luggage) × (g-sea level - g-altitude)

g at sea level:

g1 = (Gravitational constant × Mass of the Earth) / (Radius of the Earth)²

g at altitude of 30,000 ft:

g2 = (Gravitational constant × Mass of the Earth) / (Radius of the Earth + Altitude)²

Gravitational constant = 6.674 × 10^-11 m^3 kg^-1 s^-2

g1 = (6.674 × 10^-11 × 5.98 × 10^24) / (6.37 × 10^6)^2

g1 ≈ 9.8358 m/s^2

g2 = (6.674 × 10^-11 × 5.98 × 10^24) / (6.37 × 10^6 + 9,144)^2

g2 ≈ 9.8076 m/s^2

ΔW = (M-luggage) × (g1 - g2)

= 25 kg × (9.8358 - 9.8076)

≈ 0.705 kg

Therefore, your luggage would weigh approximately 0.705 kg less when you climb to 30,000 ft compared to its weight at the airport.

Can't guarantee this is right, but I checked the numbers a few times and this is the best I can do!

Answer:

400 J

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 5 kg

Height (h) = 8 m

Workdone (Wd) =?

Workdone by gravitational force is given by the following equation:

Wd = mgh

Where:

Wd => is the Workdone.

m => is the mass of object

g => is the acceleration due to gravity

h => is the height to which the object is located.

With the above formula, we can obtain the workdone as follow:

Mass (m) = 5 kg

Height (h) = 8 m

Acceleration due to gravity (g) = 10 m/s²

Workdone (Wd) =?

Wd = mgh

Wd = 5 × 10 × 8

Wd = 400 J

Thus, the workdone by gravitational force is 400 J

Explanation:

To determine the force F of interaction between the half ring and the point charge, we can use the principle of superposition, which states that the total force on a point charge due to a collection of other charges is the vector sum of the individual forces that each of those charges would exert on the point charge if it were the only charge present.

First, we need to find the electric field at the center of curvature due to the charged half ring. The electric field at a point on the axis of a uniformly charged ring is given by:

E = kqz / (z^2 + R^2)^(3/2)

where k is Coulomb's constant, q is the linear charge density, z is the distance from the center of the ring to the point on the axis, and R is the radius of the ring.

At the center of curvature of the half ring, z = R, so the electric field is:

E = kq / (2R)

Next, we can use the electric field to find the force on the point charge q:

F = qE

Substituting the given values, we get:

F = (20 x 10^-9 C) x (9 x 10^9 N·m^2/C^2) x (1/20 cm)

F = 9 x 10^-3 N

Therefore, the force of interaction between the half ring and the point charge is 9 x 10^-3 N.

This force can also be interpreted as the force required to hold the point charge at the center of curvature against the electric field due to the charged half ring. It is an attractive force because the point charge is opposite in sign to the charged half ring.

Answer:

5.65N.

Explanation:

Solution Given:

radius of R = 10 cm=10/100=0.1 m

linear density λ = 1 Mikrokulon/m= 10^-6 Coulomb/m

force F=?

q1 = 20nC=20*10^-9 C

we have

Coulomb's law, which states that the force between two charges is proportional to the product of the charges and inversely proportional to the square of the distance between them. Mathematically, this can be expressed as:

F = k*(q1*q2)/r^2

since q1 is located at the center of curvature of the half ring , so the half ring is uniformly charged with a linear density of λ= 1 μC/m.

again

equation becomes.

F=k*(q1*λL)/r^2

Since the half ring is a semicircle,

we have L=πr

F=k*(q1*λ*πr)/r^2

substituting value

F=9 x 10^9 N*m^2/C^2 *(20*10^-9 C* 10^-6 m^3*π*0.1 m)/(0.1m^2)

F=5.65 N

Therefore, the force of interaction between the half ring and the point charge is 5.65N.

We are given two points on the distance-time graph: (1, 40) and (3,130)

This means that:

At time 1 hour, the distance traveled was 40 km

At time 3 hours, the distance traveled was 130 km

We want to find the average speed during this 2 hour interval (from 1 hour to 3 hours).

Average speed is defined as:

Average Speed = Change in Distance / Change in Time

The change in distance is the distance traveled from 1 hour to 3 hours, which is 130 km - 40 km = 90 km

The change in time is 3 hours - 1 hour = 2 hours

Average Speed = 90 km / 2 hours

= 45 km/hr

Therefore, the average speed during this interval of time is 45 km/hr.

Answer:

2.11 m/s

Explanation:

V=disp/time

V=(0.52m+3.7m)/(2)

V=4.22/2

V=2.11 m/s

Considering the Coulomb's Law, the magnitude of the charge on each particle is 4.2426 C.

Coulomb's law or law of electrostatics is the relationship between the interactions of electric charges, that is, it explains the force experienced by two electric charges at rest.

This law says that the electric force with which two point charges at rest attract or repel each other is directly proportional to the product of the magnitude of both charges and inversely proportional to the square of the distance that separates them, expressed mathematically as:

\(F=k\frac{Qq}{d^{2} }\)

where:

The force is attractive if the charges are of opposite sign and repulsive if they are of the same sign.

In this case, you know that:

Replacing in the Coulomb's Law:

\(1.8x10^{-8} N=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{Qq}{(0.3 m)^{2} }\)

Being Q=q:

\(1.8x10^{-8} N=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{q^{2} }{(0.3 m)^{2} }\)

Solving:

1.8×10⁻⁸ N÷ 9×10⁹ \(\frac{Nm^{2} }{C^{2} }\)= q²÷ (0.3 m)²

2×10⁻¹⁸ C²/m²= q²÷ (0.3 m)²

2×10⁻¹⁸ C²/m²= q²÷ 0.09 m²

2×10⁻¹⁸ C²/m² ×0.09 m²= q²

1.8×10⁻¹⁹ C²= q²

√1.8×10⁻¹⁹ C²= q

4.2426 C= q= Q

Finally, each charge has a value of 4.2426 C.

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Answer:

Contact forces are those types of forces that result when the two interacting objects are perceived to be physically contacting each other. Examples of contact forces include frictional forces, tensional forces, normal forces, air resistance forces, and applied forces.

Explanation:

The function is not continuous at x=1, so the answer is A.

At x=1, the two pieces of the function meet. The first piece ends with an open dot at (1,0), meaning that the function is not defined at $x=1$. The second piece starts with a closed dot at (1,-1), meaning that the function is defined at x=1 and takes the value -1 there.

Since the function is not defined at x=1, it cannot be continuous at that point. Therefore, the function is not continuous overall.