A uniform (homogeneous) surface charge density Po [C/m'] is distributed over a cylindrical surface at rho-a, extending from-=-h / 2 to-= h /2. (There are no top or bottom surfaces for the cylindrical charge.) Find the electric field vector in free space at a point on the z axis at a height z above the origin, whereh/2

Answer:A cookie

Explanation:To track interests.

Answer:

120

Explanation:

Answer:

False

Explanation:

As seen in the diagram, electrons are rotating around the nucleus and are, therefore, not part of the nucleus.

To calculate the tensile stress in each plate using the given expressions, we'll consider the following:

a) Fhw.t:

Assuming F represents the force applied, h represents the height of the plate, w represents the width of the plate, and t represents the thickness of the plate, the expression Fhw.t represents the tensile stress in each plate.

The formula for tensile stress is stress = force / area, where the area is equal to the product of height, width, and thickness.

Therefore, the tensile stress in each plate can be calculated as F / (h * w * t).

b) Flow-d). t:

Assuming F represents the force applied, l represents the length of the plate, ow represents the outer width of the plate, d represents the inner width of the hole, and t represents the thickness of the plate, the expression Flow-d). t represents the tensile stress in each plate.

The formula for tensile stress is stress = force / area, where the area is equal to the product of the effective width and thickness. In this case, the effective width is (ow - d).

Therefore, the tensile stress in each plate can be calculated as F / ((ow - d) * t).

c) F.L:

Assuming F represents the force applied and L represents the length of the plate, the expression F.L represents the tensile stress in each plate.

The formula for tensile stress is stress = force / area, where the area is equal to the cross-sectional area of the plate.

Assuming the cross-section of the plate is rectangular, the area is equal to the product of length and thickness.

Therefore, the tensile stress in each plate can be calculated as F / (L * t).

d) F / (pi/4). d^2:

Assuming F represents the force applied and d represents the diameter of the hole in the plate, the expression F / (pi/4). d^2 represents the tensile stress in each plate.

The formula for tensile stress is stress = force / area, where the area is equal to the cross-sectional area of the plate. In this case, the cross-section is circular.

The cross-sectional area of a circle is given by pi/4 * d^2, where d is the diameter of the circle.

Therefore, the tensile stress in each plate can be calculated as F / (pi/4 * d^2).

Please note that the provided explanations assume linear elastic behavior and uniform stress distribution across the cross-section of the plates.

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Answer:

the answer is airfoil

Explanation:

hope the answer helps

Answer:

It is called the airfoil

Explanation:

The answer is D. ( airfoil) because an airport is a place. Air raid is a attack in the air and that only leaves airfoil, so airfoil is the correct answer.(Hoped that helped)

To build the given assembly in Solidworks, follow these steps:

Step 1: Create a new assembly in Solidworks.

Step 2: In the assembly, select the Front plane and create a new sketch.

Step 3: Draw the first bracket by selecting the Rectangle tool from the Sketch tab and then selecting the Smart Dimension tool to add dimensions to the sketch.

The first bracket will be 100mm x 50mm, with holes of 5mm diameter located 10mm from each edge. The thickness of the bracket will be 2mm.

Step 4: Extrude the first bracket sketch by selecting the Extruded Boss/Base tool. Enter 2mm as the extrude depth.

Step 5: Create a new sketch on the top plane of the first bracket.

Step 6: Draw a circle of 2.5mm diameter in the center of the new sketch and extrude it by 2mm.

Step 7: Now, select the bottom face of the first bracket and create a new sketch.

Step 8: Draw the second bracket sketch in the new sketch. The second bracket will be identical to the first bracket.

Step 9: Extrude the second bracket sketch by 2mm.

Step 10: Now, select the right face of the first bracket and create a new sketch.

Step 11: Draw the third bracket sketch in the new sketch. The third bracket will be identical to the first and second brackets.

Step 12: Extrude the third bracket sketch by 2mm.Step 13: Now, select the top face of the second bracket and create a new sketch.

Step 14: Draw a circle of 2.5mm diameter in the center of the new sketch and extrude it by 10mm.Step 15: Now, select the bottom face of the third bracket and create a new sketch.

Step 16: Draw a circle of 2.5mm diameter in the center of the new sketch and extrude it by 10mm.

Step 17: Now, insert two pins with 5mm diameter and 20mm length in the holes of the brackets.

Step 18: Finally, save the assembly.The assembly contains 3 machined brackets and 2 pins. The brackets have a thickness of 2mm and equal size holes through all material. The material used is 6061 alloy with a density of 0.0027g/mm3. The top edge of the notch is located 20mm from the top.

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a. use the one prime factor(N) routine to find a prime factor p of N. b .the algorithm will call the one prime factor(N) routine approximately n/2 times. c. this has a worst-case time complexity of O(n log n). time complexity of O(2^(n/2)), d. this algorithm is definitely an improvement.

Binary numbers are a number system that only uses two digits, 0 and 1, to represent numbers. In the binary system, each digit represents a power of two, with the rightmost digit representing 2^0 (1), the next digit representing 2^1 (2), the next digit representing 2^2 (4), and so on.

For example, the binary number 1010 represents the decimal number (1 x 2^3) + (0 x 2^2) + (1 x 2^1) + (0 x 2^0), or 8 + 0 + 2 + 0, which is equal to 10 in decimal.

(a) We can use the one prime factor(N) routine repeatedly to factor the given n-digit binary number into prime factors. We can repeatedly call the one prime factor(N) routine until we get all the prime factors of the number. After each call, we divide the input number by the prime factor obtained from the routine, and repeat the process until we have obtained all the prime factors.

Here is the pseudocode for the algorithm:

Input: n-digit binary number N

while N > 1:

  factor = one_prime_factor(N)

  print(factor)

  N = N / factor

(b) In the worst case, the input number may be a large prime number. In this case, the one prime factor(N) routine will return the input number itself as the prime factor. Therefore, we will need to call the one prime factor(N) routine n times to factor the input number into primes.

(c) Each call to the one prime factor(N) routine takes O(n^3) time (assuming it takes linear time to perform arithmetic operations on two n-digit binary numbers). Therefore, the worst-case time complexity of the algorithm is O(n^4).

(d) The time complexity of the algorithm is quite high, which means it may not be fast enough for large input sizes. In practice, there are faster algorithms for factoring integers, such as the general number field sieve (GNFS) or the quadratic sieve (QS), which have much lower time complexities. However, the one prime factor(N) routine may still be useful in certain situations where we only need to find one prime factor of a number.

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Answer:

Phuong works on a research project and creates a report for her boss.

Answer:

B. Bart types information into a computer database.

C. Phuong works on a research project and creates a report for her boss.

D. Anton answers phone calls and greets guests who visit a company.

Answer:

Explanation:

write each force in terms of magnitude and directions  

Fx = F sin Ф

Fy = F cos Ф

where Ф is to be measured from x axis.

∑F at y = o

FAy + FBy + FCy + FDy + FEy + FGy = 0

∑F at x = o

FAx + FBx + FCx + FDx + FEx + FGx = 0

Let  

FA = FA sin (110)   +   FA cos (110)

FB = 20 sin (270)  +  20 cos (270)

FC = 16 sin (140)    +  16 cos (140)

FD = 9 sin (40)       +  9 cos (40)

FE = 20 sin (270)    +  20 cos (270)

FG = FG sin (50)     +  FG cos (50)

add x and y forces:

FAx + FBx + FCx + FDx + FEx + FGx = 0

FAy + FBy + FCy + FDy + FEy + FGy = 0

FA sin (110)  + 0  + 16 sin (140)  + 9 sin (40)  + 0   + FG sin (50) = 0

FA cos (110) - 20 + 16 cos (140) + 9 cos (40) - 20 + FG cos (50 = 0

FA sin (110)  + 0  + 10.285  + 5.785  + 0   + FG sin (50) = 0

FA cos (110) - 20 - 12.257 + 6.894 - 20 + FG cos (50) = 0

FA sin (110)  + 16.070 + FG sin (50) = 0        

FA cos (110) - 45.363 + FG cos (50) = 0

solving for FA, and FG

FA = 13 kN

FG = 15.3 kN

From the given information, we can say that the sum of the upward forces is equivalent to the sum of the downward forces.

From the diagram, equating the component of the upward forces and the downward forces, we have:

\(\mathbf{-F_a sin 70 +F_c sin 40+F_d sin 40 + F_g sin50= F_b+F_e}\) --- (1)

Also, the sum of the horizontal positive x-axis as well as the horizontal negative x-axis can be computed as:

\(\mathbf{F_g cos 50 +F_d cos 40 = F_c cos 40 +F_a cos 70 --- (2)}\)

If:

\(F_B = F_E = 20 \ kN \\ \\ F_c = 16 \ kN \\ \\ F_D= 9\ kN\)

Then, from equation (1), we can have the following:

\(\mathbf{F_a sin 70 + 16 sin 40 + 9 sin40 + F_gsin 50 = (20 + 20 )kN}\)

collecting like terms;

\(\mathbf{F_a sin 70 + F_gsin 50 = 40 - 16 sin 40 - 9 sin40 }\)

\(\mathbf{F_a sin 70 + F_gsin 50 =23.93}\) --- (3)

From equation (2);

\(\mathbf{F_g cos 50 + 9cos 40 = 16 cos 40 + F_a cos 70}\)

collecting like terms:

\(\mathbf{F_g cos 50 -F_a cos 70 =16cos 40 -9cos 40}\)

\(\mathbf{-F_a cos 70 +F_g cos 50 =5.36 ----- (let \ this \ be \ equation (4))}\)

Suppose we equate (3) and (4) together using the elimination method;

\(\mathbf{F_a sin 70 + F_gsin 50 =23.93}\) --- (3)

\(\mathbf{-F_a cos 70 +F_g cos 50 =5.36 --- (4)}\)

Let's multiply (3) with ( cos 70 ) and (4) with (sin 70);

Then, we have:

\(\mathbf{F_a sin 70 cos 70 + F_gsin 50 cos 70 =23.93 cos 70}\)

\(\mathbf{-F_a cos 70 sin 70 +F_g cos 50 sin 70 =5.36 sin 70}\)

Adding both previous equations together, we have:

\(\mathbf{F_a sin 70 cos 70 + F_gsin 50 cos 70 =23.93 cos 70}\)

\(\mathbf{-F_a cos 70 sin 70 +F_g cos 50 sin 70 =5.36 sin 70}\)

\(\mathbf{(0 + F_g(sin 50 cos 70 + sin70 cos50) = 23.93 cos 70 + 5.36 sin 70)}\)

\(\mathbf{( F_g(0.262 + 0.604)) =(8.19 + 5.04)}\)

\(\mathbf{( F_g(0.866)) =(13.23)}\)

\(\mathbf{ F_g =\dfrac{(13.23)}{(0.866)}}\)

\(\mathbf{ F_g =15.28 \ N}\)

Replacing the value of \(\mathbf{F_g}\) into equation (3), to solve for \(\mathbf{F_a}\), we have:

\(\mathbf{F_a sin 70 + F_gsin 50 =23.93}\)

\(\mathbf{F_a sin 70 + 15.28sin 50 =23.93} \\ \\ \mathbf{F_a sin 70 +11.71 =23.93} \\ \\ \mathbf{F_a sin 70 =23.93-11.71 } \\ \\ \mathbf{F_a sin 70 =12.22 } \\ \\ \mathbf{F_a =\dfrac{12.22 }{sin 70}} \\ \\\)

\(\mathbf{F_a =13.01 \ N}\)

Therefore, we can conclude that the magnitudes of \(\mathbf{F_a}\) and \(\mathbf{F_g}\) are 13.0 N and 15.28 N respectively.

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To determine the type of the system, we need to find the number of poles at the origin (i.e., the number of integrators) in the open-loop transfer function.

The open-loop transfer function, G(s), has three poles at the origin (s² term in the denominator). Hence, the system is a Type 3 system.

Now let's calculate the steady-state error for each input using the steady-state error formula:

1. For the input 80u(t):

The steady-state error, E(s), is given by E(s) = 1 / (1 + G(s)). Since the input is a step function (u(t)), we can substitute s with 0 in the transfer function.

E(s) = 1 / (1 + G(0))

E(s) = 1 / (1 + 60(34)(4)(8) / (0)(6)(17))

Since there is an integrator in the system, the steady-state error for a step input is zero (E(s) = 0).

2. For the input 80tu(t):

The steady-state error, E(s), is given by E(s) = 1 / (1 + G(s)) * 1/s. We can substitute s with 0 in the transfer function.

E(s) = 1 / (1 + G(0)) * 1/0

E(s) = ∞

The steady-state error for a ramp input is infinity.

3. For the input 80t²u(t):

The steady-state error, E(s), is given by E(s) = 1 / (1 + G(s)) * 1/s². We can substitute s with 0 in the transfer function.

E(s) = 1 / (1 + G(0)) * 1/0²

E(s) = ∞

The steady-state error for an acceleration input is also infinity.

In summary:

The complete question should be:

\(80t^{2}u(t)\)

For a unity feedback system with feedforward transfer function as

\(G(s)\frac{60(s+34)(s+4)(s+8)}{s^{2}(s+6)(s+17)}\)

The type of system is:

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Answer:

1. Yes, they are all necessary.

2. Both written and verbal communication skills are of the utmost importance in business, especially in engineering. Communication skills boost you or your teams' performance because they provide clear information and expectations to help manage and deliver excellent work.

The location at which the joined forces of a pressure distribution on a wholly submerged plane surface counteracts is determined by its shape, orientation, and furthermore the pressure composition.

To exemplify, when a plane surface displays an evenly distributed pressure around its center of gravity, then the center of pressure will be found beneath the center of gravity when the surface inclines.

Yet, if the same plane surface remains horizontal, the pressure arrangement will remain homogenous and thus the two centers merge. Generally speaking, the center of pressure stands below, or at most level with, the center of gravity when the plane surface is straight.

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The expression that correctly gives the number of months it will take for the population of Heckleburg to increase by 1,000 people is (P people/mo.) X (1000 people) = (P x 1000) mo.

To find the number of months it will take for the population to increase by 1,000 people, we need to consider the rate of population growth, which is given as P people per month. Multiplying this rate by the number of people we want to increase, 1,000 people, gives us the expression (P people/mo.) X (1000 people). This expression represents the number of people that will be added to the population in a certain number of months.

The units cancel out, leaving us with the expression (P x 1000) mo., which represents the number of months it will take for the population to increase by 1,000 people based on the given growth rate.

It's important to note that the other options provided do not accurately represent the calculation needed to determine the number of months for a population increase of 1,000 people. They either do not consider the growth rate or incorrectly manipulate the given information.

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The 'marking menu' opened up ways for me to access the most commonly used commands and tools with a flick of the wrist. What's more impressive is that its dependent on workspace, so you can use it in all parts of the design!

HOPE IT HELPS:)

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The apparent resistance to AC by a capacitor is called capacitive reactance, and it is directly proportional to both the frequency and capacitance of the capacitor. It is measured in ohms and impedes the flow of current in circuits where the current is alternating.

The apparent resistance to AC by a capacitor is called capacitive reactance, and it is measured in ohms. Capacitive reactance (Xc) is a complex variable that is directly proportional to both the frequency (f) of the alternating current passing through the capacitor and the capacitance (C) of the capacitor. It is represented as:

Xc = 1 / (2πfC)

Where Xc is the capacitive reactance, f is the frequency of the AC, and C is the capacitance of the capacitor.

Capacitive reactance is similar to resistance in that it impedes the flow of current, but it only occurs in circuits where the current is alternating. The capacitive reactance of a capacitor is an opposition to the flow of alternating current due to the capacitor's ability to store energy in an electric field.

In conclusion, the apparent resistance to AC by a capacitor is called capacitive reactance, and it is directly proportional to both the frequency and capacitance of the capacitor. It is measured in ohms and impedes the flow of current in circuits where the current is alternating.

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The average daily flow of water in 10 years would be 21,249 m³/day.

To estimate the average daily flow of water in 10 years,

we have to use the current population and water consumption as a baseline.

We have to find the daily water consumption for the current population,

⇒ 6,083,270 m³ / 365 days = 16,676 m³/day

Now we have to calculate the expected water consumption for the future population,

= 16,676 m³/day x (73,728 / 58,000) = 21,249 m³/day

Therefore,

We can estimate that the average daily flow of water in 10 years would be 21,249 m³/day.

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Answer:

3

Explanation:

To determine if the rings are pure silver, we can calculate the density of the rings and compare it to the density of pure silver. The density of a material is the mass of the material per unit volume.

First, we need to find the volume of one of the rings. Since the rings are cylindrical, we can use the formula for the volume of a cylinder to find the volume of each ring:

V = π * r^2 * h

Where V is the volume of the ring, π is approximately equal to 3.14, r is the radius of the ring, and h is the height of the ring. In this case, the height of the ring is equal to the thickness of the ring, which is equal to the change in the water level (8.45 mm) divided by the number of rings (10). The radius of the ring is equal to half the diameter of the graduated cylinder (2.5 cm / 2 = 1.25 cm), since the rings are placed in the cylinder side by side.

Plugging these values into the formula, we find that the volume of each ring is:

V = 3.14 * (1.25 cm)^2 * (8.45 mm / 10) = 0.00367 cm^3

Next, we can use the mass and volume of each ring to calculate the density of the rings:

density = mass / volume

Since the mass of each ring is 0.738g and the volume of each ring is 0.00367 cm^3, the density of the rings is:

density = 0.738 g / 0.00367 cm^3 = 201.09 g/cm^3

Finally, we can compare the density of the rings to the density of pure silver, which is 10.49 g/cm^3. Since the density of the rings is much higher than the density of pure silver, it is likely that the rings are not pure silver.

It is important to note that this calculation is only an approximate estimation of the purity of the rings. There may be other factors that affect the density of the rings, such as impurities or variations in the thickness of the rings. Additionally, the value of the density of pure silver used in this calculation may not be entirely accurate, as the density of a material can vary depending on factors such as temperature and pressure. A more precise determination of the purity of the rings would require further testing and analysis.

The instrument used to measure middle ear function is a tympanometer.

A tympanometer is a medical device used to evaluate the functionality of the middle ear. It tests the function of the eardrum (tympanic membrane) and the conduction bones (ossicles) in the middle ear by adjusting pressure and measuring the movement of the eardrum in response.

The purpose of a tympanometer is to detect fluid accumulation in the middle ear, a ruptured eardrum, or a problem with the ossicles' conduction. It can also provide information on hearing loss and the effectiveness of medical treatment.

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The instrument used to measure middle ear function is a Tympanometer.Tympanometer is the medical device used for measuring middle ear function. It's a non-invasive tool that evaluates the functionality of the middle ear by measuring the movement of the eardrum (tympanic membrane).

The tympanometer is used to measure the compliance and mobility of the tympanic membrane and the ossicular chain. The procedure is painless and straightforward; a small probe is placed in the ear canal to deliver a brief pulse of air pressure, creating a change in the air pressure in the ear canal. The tympanometer then measures the amount of energy that is reflected back from the eardrum. The result is a graph that indicates the degree of mobility and compliance of the tympanic membraneIt can help the audiologist identify potential hearing problems, make recommendations for further diagnostic testing or treatment, and monitor the effectiveness of medical or surgical interventions.

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Answer: The maintenance factor of a lighting system reflects how much of the initial luminous flux is still available at the end of its useful life. The planned lighting engineer must compute the maintenance factor and multiply the new value of the light output by it.

Explanation:

Answer:

Explanation: A lighting system's maintenance factor indicates how much of the initial luminous flux remains available at the end of its service life. The maintenance factor must be determined by the planning lighting engineer and the new value of the luminous flux multiplied by it.

Answer:

True

Explanation:

Spray gun plays an one of the most important roles in spray finishing as it directs air to atomize the fluid, gives the particles sufficient velocity to reach the product surface, and shapes the pattern/texture. Hope this helps you as much as intended.

Answer: True

Explanation:

The air cap on the spray gun plays an important role in spray finishing as it directs air to atomize the fluid, gives the particles sufficient velocity to reach the product surface, and shapes the pattern.

The drag per unit span on the model can be calculated using a control volume approach as follows:

Where ρ is the density of the fluid, V is the velocity of the fluid, and z is the distance from the top of the test section to the bottom. The integral can be calculated by summing up the velocity of the fluid at each point from the top to the bottom of the test section. This can be expressed as:

Where Vz is the velocity of the fluid at each point in the test section.

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Answer:

PEER establishes clear performance metrics, it serves consumer needs, and it covers all aspects of energy system performance.

Explanation:

on edg. just did it

If the airspeed is increased from 90 knots to 135 knots during a level 60 degree turn, the load factor will increase as well as the stall speed.

This is because the load factor is directly proportional to the square of the speed and the tangent of the bank angle. Therefore, increasing the speed and the bank angle will increase the load factor. Additionally, the stall speed will also increase due to the increased load factor. The radius of turn will remain the same, as it is determined by the speed and degree of bank, not the change in airspeed.

If the airspeed is increased from 90 knots to 135 knots during a level 60-degree turn, the load factor will increase as well as the stall speed.

Here's the step-by-step explanation:

1. Airspeed refers to the speed of an aircraft relative to the air around it. In this case, the airspeed increases from 90 knots to 135 knots.
2. The turn being discussed is a level 60-degree turn, meaning the aircraft is maintaining a constant altitude while turning at an angle of 60 degrees.
3. As the airspeed increases, the aircraft must generate more lift to maintain the level turn. This results in an increase in the load factor, which is the ratio of the lift produced to the aircraft's weight.
4. When the load factor increases, the stall speed also increases. Stall speed is the minimum airspeed at which an aircraft can maintain level flight without stalling (losing lift). A higher load factor requires a higher airspeed to prevent stalling.

So, when the airspeed increases from 90 knots to 135 knots during a level 60-degree turn, both the load factor and stall speed will increase.

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Answer:

Explanation:

Both a  and B

In these two statements by Technician A and Technician B, C. Both A and B are correct.

OEM means Original Equipment Manufacturer, while TCMC means Toyota Complete Maintenance Care. OEM brake pad kits come with new shims as TCMC brake pad kits.

Traditional part numbers bear 10-digits, but TCMC products bear 12-digit part numbers.

Thus, we can conclude from the statements by Technician A and Technician B that C. Both Technician A and Technician B are correct.

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MongoDB would probably be considered for a web app if a company had a significant commitment to JavaScript.

MongoDB stands as a NoSQL database solution that exhibits remarkable synergy with JavaScript, frequently employed alongside Node.js, a widely embraced runtime environment for server-side development utilizing JavaScript.

MongoDB offers a pliable data model centered around documents, harmonizing effortlessly with JavaScript's JSON-esque syntax. This database excels in managing unstructured or swiftly evolving data, showcasing its adeptness and adaptability.

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The options statements that explains why there are fewer limitations on solar energy use than there were in the past is  option C and B:

When it's cold outside and there are cloudy days, productivity is generally slow. Installation and initial costs are high. Large surface areas are needed for production at the consumer level.

While traditional energy sources can be dispatched whenever we need them, solar energy is intermittent and cannot provide electricity on demand without storage. However, it does produce a sizable amount of energy during the day.

Here are a few of the most significant drawbacks of solar energy that you should take into account before going solar.

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See full question below

a. efficiency is improving

b. countries that have the metals needed to produce solar panels will not sell these metals to other countries

c. solar panels are expensive to install, and sunlight is only available part of the day

d. climate change is increasing cloud production thereby reducing available sunlight