a type of cuckoo clock keeps time by having a mass bouncing on a spring, usually something cute like a cherub in a chair. what force constant (in n/m) is needed to produce a period of 0.340 s for a 0.0200 kg mass?

Answer:

C. 12.4 m/s

Explanation:

Acceleration (a) = -6.2 m/s²

Final velocity (v) = 0 m/s (Comes to rest)

Time taken (t) = 2.0 s

By using equation of motion, we get:

\( \bf \longrightarrow v = u + at \\ \\ \rm \longrightarrow 0 = u + ( - 6.2)(2.0) \\ \\ \rm \longrightarrow 0 = u - 12.4 \\ \\ \rm \longrightarrow u - 12.4 = 0 \\ \\ \rm \longrightarrow u + 12.4 - 12.4 = 0 + 12.4 \\ \\ \rm \longrightarrow u = 12.4 \: m {s}^{ - 1} \)

\( \therefore \) Initial velocity (u) = 12.4 m/s

The maximum potential energy stored in the spring is 0.018 J. It is given that the force F (in N) and the displacement x (in m) of the springs and we are asked to use Hooke’s law to compute the potential energy stored in the spring U (in J) and then compute the vectors of the spring constants and the potential energies using MATLAB.

Computing the spring constant k from the given data: We know that F = kx ⇒ k = F/x. Here, F and x are vectors: F = [14, 18, 8, 9, 13] N and x = [0.013, 0.020, 0.009, 0.010, 0.012] m. We can compute k as follows: k = F./x = [14/0.013, 18/0.020, 8/0.009, 9/0.010, 13/0.012] kN/mk = [1076.92, 900, 888.89, 900, 1083.33] N/m (rounded off to 2 decimal places)2.

Computing the potential energy stored in the spring U from the given data: We know that U = (1/2)kx². We can compute U as follows: U = (1/2)k.*x² = [(1/2)1076.92(0.013)², (1/2)900(0.020)², (1/2)888.89(0.009)², (1/2)900(0.010)², (1/2)1083.33(0.012)²] JU = [0.009, 0.018, 0.004, 0.005, 0.007] J (rounded off to 3 decimal places).

Determining the maximum potential energy using the max function: We can determine the maximum potential energy using the max function as follows: maxU = max(U) = 0.018 J. Therefore, the maximum potential energy stored in the spring is 0.018 J.

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Here's the formula you want to use to solve this:

Distance = (1/2) · (acceleration) · (time²)

We know the distance to the ground and the acceleration of gravity, so let's pluggum in:

. . . . . 125 m = (1/2) (9.8 m/s²) (time²)

Divide each side by (4.9 m/s²):  

. . . . . (125 m) / (4.9 m/s²) = time²

. . . . . 25.51 s² = time²

Square-root each side:

5.05 seconds  = time

(1) The force of gravity between the Earth and the satellite is 8.91 * 10^6 N.

(2)  The orbital period of the satellite is 6,132 seconds i.e. 1 hour and 42 minutes.

(3) The tangential velocity required to keep the satellite in orbit is approximately 7.94 km/s.

(4) The angular velocity of the satellite is 0.0011 radians per second.

(1)  The force of gravity between two objects can be calculated using Newton's law of universal gravitation. The formula is F = (G * m1 * m2) / \(r^2\), where F is the force of gravity, G is the gravitational constant, m1 and m2 are the masses of the objects, and r is the distance between their centers. In this case, the mass of the Earth is much larger than the mass of the satellite, so we can consider the satellite's mass negligible compared to the Earth's mass. Plugging in the values, we get\(F = (6.67 \times 10^{-11} N m^2/kg^2) \times (5.97 \times 10^{24} kg) \times (900 kg) / (6,371,000 m)^2 = 8.91 \times 10^6 \ Newtons\)

(2) The orbital period of a satellite can be determined using Kepler's third law of planetary motion, which states that the square of the orbital period is proportional to the cube of the semi-major axis of the orbit. Since the satellite is orbiting at a radius equal to one Earth radius above the surface, the semi-major axis is the sum of the Earth's radius and the altitude of the satellite. Using the formula \(T = 2\pi \times\sqrt{(a^3 / (G \times M)}\), where T is the orbital period, a is the semi-major axis, G is the gravitational constant, and M is the mass of the Earth, we can calculate the value. Plugging in the values, we get \(T = 2\pi \times\sqrt{6,371,000}\) meters +\((6,371,000 \ m)^3 / (6.67 \times 10^{-11} N m^2/kg^2 \times 5.97 \times 10^{24} kg)\) = 6,132 seconds.

(3) The tangential velocity required to keep a satellite in orbit can be determined using the formula \(v = \sqrt{G \times M / r\) where v is the tangential velocity, G is the gravitational constant, M is the mass of the Earth, and r is the distance between the center of the Earth and the satellite. Plugging in the values, we get v = √((6.67 x 10^-11 N m^2/kg^2 * 5.97 x 10^24 kg) / \(v = \sqrt{\frac{(6.67 \times 10^{-11} N m^2/kg^2 \times 5.97 \times 10^{24} kg) }{(6,371,000 m + 6,371,000 m)}\)) = 7,906 m/sec.

(4) The angular velocity of a satellite in orbit can be calculated using the formula ω = v / r, where ω is the angular velocity, v is the tangential velocity, and r is the distance between the center of the Earth and the satellite. Plugging in the values, we get ω = 7,906 meters per second / (6,371,000 meters + 6,371,000 meters) = 0.0011 radians per second.

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Answer: It leads to a front. A front is.., I don't know how to explain it, so I'll add a picture. Fronts are made out of clouds and usually bring rain. So the answer is C: The formation of clouds and rain.

Explanation:

In order to get a stone slab to move, one would have to apply force to it. This can be done in a number of ways, depending on the situation. Here are a few possible laws that could be proposed for moving a stone slab:1. Newton's first law of motion: This law states that an object at rest will stay at rest unless acted upon by an external force. Therefore, to move a stone slab, one would need to apply a force to it.

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Answer:

PE = 0.35 J

Explanation:

Elastic potential energy in a spring is defined by PE = (1/2)kx^2, where k is the spring constant and x is the distance compressed/stretched. Converting 16 cm to 0.16 m, we get

PE = (1/2) * 27 * (0.16^2)

PE = 0.35 J

Answer:

the discharge of built-up static electricity

Explanation:

Answer:

I hope this helps.

Explanation:

Answer:

1.Vector are quantities which have both magnitude and direction

Scalar are physical quantities which only have magnitude

Distance is Scalar

Displacement is Vector

2. Scalar

3. Vector

Distance: The total length covered by a moving object irrespective of the direction of motion(only magnitude and no direction)

Displacement: The distance measured in a straight line(linear distance) and in a specific direction (both magnitude and direction)

the 4th & 5th question im unsure, i apologize about it

The wavelength for a sound wave with a frequency of 485 Hz. That has a sound wave in the air has a frequency of 420 Hz is 70.7cm and 81.7cm.

Wavelength = speed of sound/frequency

The speed of sound is approximately 343 meters per second.

For a sound wave with a frequency of 485 Hz, the wavelength would be:

wavelength = 343 m/s / 485 Hz = 0.707 m or 70.7 cm

For a sound wave in air with a frequency of 420 Hz, the wavelength would be:

wavelength = 343 m/s / 420 Hz = 0.817 m or 81.7 cm.

Wavelength is a fundamental concept in physics that refers to the distance between two consecutive points on a wave that is in phase, meaning that they are at the same point in their respective cycles. It is usually denoted by the Greek letter lambda (λ).

Wavelength is an important property of all types of waves, including electromagnetic waves (such as light), sound waves, and even waves in water. In general, the wavelength of a wave is inversely proportional to its frequency, which is the number of cycles that occur per unit of time. This means that waves with a higher frequency have a shorter wavelength, while waves with a lower frequency have a longer wavelength.

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The work done by the gravitational force in equalizing the levels when the two vessels are connected is 0.03733 J.

The work done by the gravitational force in equalizing the levels when the two vessels are connected can be found using the formula:

Work = force x distance

where force is the weight of the liquid and distance is the difference in height between the two vessels. The weight of the liquid in each vessel can be calculated as the product of the volume and density of the liquid, and the difference in height can be found by subtracting the height of the lower vessel from the height of the higher vessel.

The weight of the liquid in each vessel can be calculated as:

Weight = density x volume x gravity

where density is 1.17 g/cm³, volume is the product of the area of the base and height of the liquid, and gravity is 9.81 m/s².

For the vessel with a liquid height of 0.906 m, the volume can be calculated as:

Volume = area of base x height of liquid = 2.94 cm² x 0.906 m = 0.00266244 m³

So, the weight of the liquid in this vessel is:

Weight = 1.17 g/cm³ x 0.00266244 m³ x 9.81 m/s² = 0.031105 N

Similarly, for the vessel with a liquid height of 1.50 m, the volume can be calculated as:

Volume = area of base x height of liquid = 2.94 cm² x 1.50 m = 0.00441 m³

So, the weight of the liquid in this vessel is:

Weight = 1.17 g/cm³ x 0.00441 m³ x 9.81 m/s² = 0.051456 N

The difference in height between the two vessels is:

Height difference = 1.50 m - 0.906 m = 0.594 m

Therefore, the work done by the gravitational force in equalizing the levels when the two vessels are connected is:

Work = force x distance = (0.051456 N + 0.031105 N) x 0.594 m = 0.03733 J

Therefore, the work done by the gravitational force in equalizing the levels when the two vessels are connected is 0.03733 J.

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The effect of H on the gain can be analyzed by using the gain formula for the given circuit, where H stands for feedback resistance and G stands for gain. For H = 10%, the formula can be used to find the change in gain.

This can be done by expressing the formula in terms of G and H and then substituting the given values. Here, the effect of changing H by 10% is also to be determined.

the output voltage is to be found for a given input voltage.

The formula for the gain in this circuit is given as follows:

G = -R2/R1, where R2 is feedback resistance and R1 is input resistance.

If H is feedback resistance, then R2 = H*10, and R1 = 10 kohm.

Substituting these values in the formula for G, we get G = -H/1000.If H = 10%,

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If an electron vibrates back and forth in an clean wire with a frequency of 60.0 Hz, then it will make 2.2×10⁵ cycles. in 1.0 h. Hence option D is correct.

Electric charge is the physical property of matter that experiences force when it is placed in electric field. F = qE where q is amount of charge, E = electric field and F = is force experienced by the charge. there are two types of charges, positive charge and negative charge which are generally carried by proton and electron resp. like charges repel each other and unlike charges attract each other. the flow charges is called as current. Elementary charge is amount of charge a electron is having, whose value is 1.602 x 10⁻¹⁹ C

Amplitude is a measure of loudness of a sound wave. More amplitude means more loud is the sound wave.

Wavelength is the distance between two points on the wave which are in same phase. Phase is the position of a wave at a point at time t on a waveform. There are two types of the wave longitudinal wave and transverse wave.

Frequency is nothing but the number of oscillation in a unit time.

Given,

frequency f = 60.0 Hz.

time t = 1.0 h = 60*60 = 3600s

F = number of cycles/time

number of cycles = F×time

The number of cycles in 1 Hr is

60*3600 = 2.2×10⁵ cycles.

Hence option D is correct.

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The phenomenon in hearing that is analogous to spatial frequency channels in vision is critical bands. Hence, the correct option is A: Critical bands.

Critical bands are regions of the audible frequency range in which a complex sound is divided into individual, discrete frequency bands by the human auditory system.

For instance, when different frequencies in a complex sound, such as a musical instrument or a human voice, are picked up by the ear, they are sent to the brain via various channels that respond to specific frequencies.

These channels are referred to as critical bands. The frequency range of these bands varies depending on the loudness of the sound.

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Answer:

Density of the mixture = 855.56kgm-3

Explanation:

Density = Mass / Volume

Volume of Liquid X = 0.5m³

Density of Liquid X = 900kgm-3

Mass of Liquid X = Density × Volume

= 900kgm-3 × 0.5m³ = 450kg

Volume of Liquid Y = 0.4m³

Density of Liquid Y = 800kgm-3

Mass of Liquid Y = Density × Volume

= 800kgm-3 × 0.4m³= 320kg

As X and Y are mixed, we add their masses and volumes together:

Mass = 770kg

Volume = 0.9m³

Now we can find the density of the mixture:

Density = 770kg / 0.9m³ = 855.56kgm-3 (rounded to the 2nd decimal)

The concentration of O2 in the trout stream is approximately 7.14 mg/L.

The concentration of O2 in a stream at equilibrium with air at 0.989 atm can be determined using the Henry's law constant (KH) for O2 in water. KH is the ratio of the concentration of a gas in a liquid to its partial pressure in the air above the liquid.

By using the KH value of 1.28 x 10^-3 mol/(L x atm) and the partial pressure of O2 in air at 0.989 atm, we can calculate the concentration of O2 in the stream.

To do so, we multiply the KH value by the partial pressure of O2, which gives us the concentration of O2 in the stream in units of mol/L. This value can then be converted to units of mg/L by multiplying by the molecular weight of O2, which is approximately 32 g/mol.

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According to the question of force, the y-component of F3 is -2.719 N.

What is force?

Force is a fundamental concept in physics that describes the interaction between two objects or systems. It is a vector quantity, meaning it has both magnitude and direction, and can be described mathematically. Force is a push or pull that can cause an object to accelerate, change its direction, or change its shape. Force is a function of mass and acceleration, as described by Newton's second law of motion.

The y-component of F3 can be calculated using the equation F3y = F1y + F2y. Since F1 is at a 180° angle, its y-component is 0. The y-component of F2 can be calculated using the equation F2y = F2 × sin(θ), where θ is the angle of F2. In this case, θ is 2430°, so the y-component of F2 is 8.90 × sin(2430°) = 8.90 × -0.3105 = -2.719 N. Therefore, the y-component of F3 is -2.719 N.

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Answer:

B

Explanation:

One object speeds up before it slows to a stop.

When reading this type of graph, we know that when the points are far apart, then the object is definitely moving quickly. Also again, we know that when the points are besides each other, then we say that the object is moving slow. When the distance that is between the points are changed, the velocity of the object subsequently changes too, and therefore, we say that the object is accelerated. When there are lots of points in one location, we will see that the object is not moving.

This then translates into that

The object(s) at the top begins to slow, eventually, it increases in its speed, going forward, it slows down again, before it finally halts. The object at the bottom on the other hand, starts fast, before slowing down.

then:

"One object speeds up before it slows to a stop "

The raw file size for a 320x240 12-bit thermal image is 115,200 bytes. Thermal images have smaller raw file sizes than digital camera images because they have lower resolution and color depth, resulting in less data being stored.

(i) To calculate the raw file size for a 320x240 12-bit thermal image, we need to consider the number of pixels and the bit depth. Each pixel in a 12-bit image can have 2¹² (4096) possible values.

The total number of pixels in a 320x240 image is 76,800 (320 x 240). Multiplying this by the bit depth, we get:

76,800 pixels x 12 bits/pixel = 921,600 bits

To convert this to bytes, we divide by 8:

921,600 bits / 8 = 115,200 bytes

Therefore, the raw file size for a 320x240 12-bit thermal image is 115,200 bytes.

(ii) The file size of a thermal image compared to a typical commercial digital camera image for the visible range is generally smaller due to a couple of reasons:

1. Resolution: Thermal images typically have lower resolution compared to commercial digital camera images. The example given is a 320x240 image.

While commercial digital cameras often capture images with higher resolutions like 12 megapixels (e.g., 4000x3000 pixels). The higher-resolution images from digital cameras contain more data per image, resulting in larger file sizes.

2. Color Depth: Thermal images are often grayscale or have limited color palettes. They usually use a lower bit depth, such as 12 bits, to represent the temperature variations.

In contrast, commercial digital cameras capture images with higher color depth, such as 24 bits (8 bits per color channel), resulting in more information per pixel and larger file sizes.

In conclusion, the raw file size of a thermal image is generally smaller compared to a typical commercial digital camera image due to lower resolution and color depth, resulting in less data being stored for each image.

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The correct answer is granular segregation; coarse-grained.

Granular segregation is the process by which particles of different sizes and densities are sorted within a flowing mixture. In the case of debris flows, the coarsest particles, such as boulders and cobbles, tend to be concentrated at the flow front, while the finest particles, such as sand and silt, are carried along in the flow. This is because the coarser particles have more inertia and are less likely to be suspended in the flow. The process of granular segregation is important because it can have a significant impact on the destructive power of debris flows. Debris flows that are concentrated with coarse particles can cause more damage to structures and infrastructure than debris flows that are composed of finer particles. In addition to granular segregation, other factors that can affect the distribution of clasts in debris flows include the slope of the valley, the amount of water in the flow, and the viscosity of the flow.

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It will take approximately 0.053 seconds for a pulse to travel from one support to the other if a cord of mass 0.55 kg is stretched° between two supports 30 in apart and if the tension in the cord· is 150n

We'll be using the following terms in the solution: mass, tension, distance, pulse, and time. Calculate the linear mass density (μ) of the cord.
μ = (mass of the cord) / (length of the cord)
μ = 0.55 kg / 30 in

Note: We need to convert inches to meters. There are 0.0254 meters in 1 inch.
30 in * 0.0254 m/in = 0.762 m

Now, we can find the linear mass density:
μ = 0.55 kg / 0.762 m = 0.721 kg/m

Calculate the speed (v) of the pulse on the cord using tension (T) and linear mass density (μ).
v = √(T / μ)
v = √(150 N / 0.721 kg/m)

Solve for the speed of the pulse.
v ≈ √(207.49 m²/s²) ≈ 14.4 m/s

Calculate the time (t) it takes for the pulse to travel between the supports.
t = (distance between supports) / (speed of pulse)
t = 0.762 m / 14.4 m/s

Solve for the time.
t ≈ 0.053 s

So, it will take approximately 0.053 seconds for a pulse to travel from one support to the other.

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Answer: 78m/s  =A

u=0 ,a=3m/sec^2 ,t=25sec

v=u+at

=0+25×3

=75m/s

after 1sec

v=u+at+75

=0+3×1+75

=78m/s

Explanation:

u=0 ,a=3m/sec^2 ,t=25sec

v=u+at

=0+25×3

=75m/s

after 1sec

v=u+at+75

=0+3×1+75

=78m/s

Answer:

0.84m

Explanation:

0.51+0.43=0.93

πr can be 22/7 or 3.14

radius is 2x2= 4

3.14 divide0.93divide 4

=0.84m/s

Answer:

0.605 m (approx.)

Explanation:

We know, given the radius and the circular velocity we can yield the centripetal acceleration using this equation,

\(a = \frac{v^2}{r}\)

From this equation, we can solve for \($r$\) like this,

\(r = \frac{v^2}{a}\\r = \frac{0.51^2}{0.43} m \\ = 0.605 m\)

The addition of vectors allows to find the vector that the equilibrium is

                F = (40.02 i ^ - 49.95 j ^) N

Parameters given

To find

The force is a vector magnitude so the sum of the force must be done using the methods to add vectors.

One of the easiest methods to perform the addition of vectors is the analytical method where each vector is decomposed in a Cartesian system and the components added using algebraic summation and then the resulting vector is constructed.

We decompose the vector

                 cos θ = \(\frac{A_x}{A}\)Ax / A

                 sin θ = \(\frac{A_y}{A}\)

                 Aₓ = A cos θ

                 \(A_y\)= A sin θ

                 Aₓ = 64 cos 128.7

                 \(A_y\) = 64 sin 128.7

                 Aₓ = -40.02 N

                 \(A_y\) = 49.95 N

To find the vector that allows equilibrium, we work each axis independently

X axis

                 Aₓ + Fₓ = 0

                 Fₓ = - Aₓ

                 Fₓ = 40.02 N

Y axis

                  \(A_y + F_y =0 \\F_y = - A_y\\F_y = - 49.95 N\)

We can write the resulting vector in two ways

1) F = (40.02 i ^ - 49.95 j ^) N

2) in the form of module and angle

Let's find the module with the Pythagoras' Theorem

              F =\(\sqrt{F_x} ^2 + F_y^2)\\F = \sqrt{40.02^2 + 49.95^2 }\)  

              F = 64 N

Angles

              tan θ = \(\frac{F_y}{F_x}\)

              θ = tan⁻¹  \(\frac{F_y}{F_x}\)

              θ = tan⁻¹ \(\frac{-49.95}{40.02}\)

              θ = -51.3º

This angle is measured clockwise from the positive side of the x-axis

In conclusion using the sum of vectors we can find the vector that allows the equilibrium is

                F = (40.02 i^  - 49.95 j^ ) N

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Answer:

D) 1414 nm

Explanation:

This is correct on Edge.

Using the equation dsin(angle)=n(wavelength), we can solve for wavelength.

First we must convert the 500 lines per mm to nm. We do this by 1/500, giving you 0.002. Then move the decimal over six places to the right, resulting in 2000.

Then by plugging in the other values, we have 2000sin(45)=1(wavelength).

N is one because we are just solving for a first-order band.

So 2000sin(45)=wavelength

By using a calculator, we can see that the wavelength equals approximately 1414nm.

I hope this helped. If it did, I would really appreciate a Brainliest!!

Have a great day:)

Answer:

1414

Explanation:

took the test :)

Answer:

1.5 m\s Ans ......

Explanation:

Data:

f = 0.5 Hz

w = 3 m

v = ?

Formula:

v = fw

Solution:

v = (0.5)(3)

v = 1.5 m\ s Ans ........

A prefix is a word part added to the beginning of a word or base word (for example, un-). If the prefix un- is added to helpful, the word is unhelpful.

A suffix is a word part added to the end of a word. For example -  again in the word unhelpful, "un" if the prefix and the suffix would be "ful".