A turtle accelerates from a stop at 3m/s/s to the South for 8s. What is the turtle’s final velocity? Show your work and include the correct units.

Answer:

The force that must be applied to the chain in order for the chain to have the given acceleration is approximately 694.2 N

Explanation:

The given restive force, \(F_f\) = 130 N

The mass of the wheel, m = 1.70 kg

The diameter of the wheel, D = 50.0 cm

∴ The radius of the wheel, R = 50.0 cm/2 = 25.0 cm = 0.25 m

The diameter of the sprocket over which the chain passes, d = 8.75 cm

The radius of the sprocket over which the chain passes, r = 8.75 cm/2 = 4.375 cm = 0.04375 m

The angular acceleration, α = 3.50 rad/s²

Torque, τ = I·α

Where;

I = The moment of inertia = m·R²·α

The net torque = The applied torque - The friction torque

Therefore, we get;

I × α = m × R² × α = F × r - \(F_f\) × R

1.70 kg × (0.25 m)² × 3.50 rad/s² = F × 0.04375 m - 120 N × 0.25 m

F = (1.70 kg × (0.25 m)² × 3.50 rad/s² +  120 N × 0.25 m)/(0.04375 m) = 694.214286 N

The force that must be applied to the chain in order for the chain to have the given acceleration, F ≈ 694.2 N

Explanation:

a.displacement is vector quantity there fore

we combine the two direction

\( {c}^{2} = \sqrt{ {a}^{2} + {b}^{2} } \)

\( {c}^{2 } = \sqrt{ {12}^{2} + {16}^{2} } \)

\( {c}^{2} = \sqrt{400 } \)

\(c = 20\)

displacement is 20km to wards north

b:average speed

\(v = s \div t\)

20/3=6.67

c: please type correctly

The ratio of a substance's weight, especially a mineral, to an equal volume of water at 4°C is called it's specific gravity or relative density.

Specific gravity is the ratio of the density of a substance to the density of a reference substance, usually water. In simple terms, specific gravity is the density of a substance compared to the density of water. It's a dimensionless amount since it's a ratio. It is frequently used in geology to compare the densities of minerals to those of water.

Specific gravity is calculated by dividing the density of a substance by the density of water. The specific gravity formula is given by:

Specific gravity = (density of substance)

(density of water)The specific gravity of a substance can be calculated by comparing its weight to the weight of an equal volume of water at a particular temperature, such as 4°C.

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To determine the amount of work done to move the Chevrolet Tahoe, we can use the equation: Work = Force × Distance

Since the car is initially at rest, we need to calculate the force required to accelerate it to a speed of 35.2 m/s.

To find the force, we can use Newton's second law of motion:

Force = mass × acceleration

Given the mass of the Chevrolet Tahoe is 1.80 x 10³ kg, and it starts from rest, we know that the initial velocity is 0 m/s.

The final velocity is given as 35.2 m/s, and the acceleration is the change in velocity divided by the time taken. However, we don't have the time mentioned in the question, so we cannot directly calculate the acceleration.

To find the acceleration, we can use the kinematic equation:

v²  = u²  + 2as

Where: - v is the final velocity (35.2 m/s) - u is the initial velocity (0 m/s) - a is the acceleration - s is the distance (unknown)

Since the car starts from rest, the initial velocity (u) is 0 m/s.

Rearranging the equation, we have: a = (v² - u² ) / (2s)

Substituting the given values, we have:

a = (35.2²  - 0² ) / (2s)

Simplifying this equation, we get:

a = 620.48 / (2s)

To solve for s, we need to know the value of the acceleration. Since it is not provided in the question, we cannot directly determine the work done.

In conclusion, to determine the amount of work done to move the Chevrolet Tahoe, we need additional information such as the acceleration or the time taken to reach the final velocity.

Without this information, we cannot provide a direct answer to the question.

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(i) The magnitudes of the electric fields they separately create at a radial distance of 6 cm is \(E_{a}\)=\(E_b}\). and (ii) The magnitudes of the electric fields they separately create at radius 4 cm is \(E_{a} =E_{b}\), so the correct option is option b.

A conductor refers to a material that allows an electric current to flow through it with ease. In other words, it has a low electrical resistance. Conductors are materials that have a high number of free electrons that are able to move freely through the material. Examples of conductors include copper, aluminum, gold, and silver. These materials are commonly used in the electrical industry to make wires and other electrical components that need to conduct electricity. In addition to materials, a conductor can also refer to a person or an organization that is responsible for directing or leading an orchestra or a choir. In this context, a conductor is in charge of maintaining the ensemble's rhythm and intonation, and interpreting the score in a way that brings out the music's emotional content and intended meaning.

(i) The magnitude of the electric field created by a charged conductor is given by the formula E = \(\frac{kq}{r}\), where k is the Coulomb constant, q is the charge, and r is the distance from the center of the sphere.

For a good conductor, like sphere A, the charge will be distributed evenly on the surface of the sphere. So, the electric field at a radial distance of 6cm will be Eₐ = \(\frac{kq}{r^{2} }\) = \(k\frac{210^{-6} }{(619^{-2} )}^{2} =\frac{k}{72}\)

For an insulator, like sphere B, the charge is distributed uniformly throughout its volume. The electric field at a radial distance of 6cm will be \(E_{b}\)=  \(\frac{kq}{r^{2} }=k\frac{210^{-6} }{(619^{-2} )}^{2} =\frac{k}{72}\)

As we can see, the magnitudes of the electric fields created by both spheres are equal, so the answer is (b) \(E_{a} =E_{b}\)

(ii) For the radius of 4cm, the electric field created by sphere A and sphere B will

\(E_{a} =\frac{kq}{r^{2} }=k\frac{210^{-6} }{(410^{-2} )^{2} } =\frac{k}{16}\\E_{b} =\frac{kq}{r^{2} }=k\frac{210^{-6} }{(410^{-2} )^{2} } =\frac{k}{16}\\\)

As we can see, the magnitudes of the electric fields created by both spheres are equal at a radius of 4cm, so the answer is (b) \(E_{a} =E_{b}\)

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The maximum speed of electrons is 5.28 × 10⁵ m/s and the Work function is 3.34 × 10⁻¹⁹ J.

We have,

The wavelength of incident light = 420 nm

Stopping potential = 0.660 V

Here, we have to calculate the maximum speed of emitted electrons, the work function, and the metal. 

The stopping potential is given by the equation,

eV₀ = (E)Kinetic(max) + work function

v₀= √{2(E)kinetic(max)/m}

v₀= √2e(V₀)/m

work function= hν - eV₀

Where 'e' is the charge on an electron, 'm' is the mass of an electron, V₀ is the stopping potential, and 'ν' is the frequency of the light source.

Here we have,

λ= 420 nm

ν= (c)/λ

= (3.0 × 10⁸ m/s)/(420 × 10⁻⁹ m)

ν= 7.14 × 10¹⁴ Hz

h = 6.63 × 10⁻³⁴ Js

e = 1.60 × 10⁻¹⁹ C

m = 9.11 × 10⁻³¹ kg

V₀= 0.660 V

v₀= √(2 × e × V₀)/m

v₀ = √[(2 × 1.60 × 10⁻¹⁹ C × 0.660 V)/(9.11 × 10⁻³¹ kg)]

v₀ = 5.28 × 10⁵ m/s

Work function= hν - eV₀

Work function= (6.63 × 10⁻³⁴ Js × 7.14 × 10¹⁴ Hz) - (1.60 × 10⁻¹⁹ C × 0.660 V)

Work function= 3.34 × 10⁻¹⁹ J

For metal identification, we need to compare the work function with the known work functions of metals. For Sodium (Na), the work function is 2.75 eV = 4.4 × 10⁻¹⁹ J, which is less than the calculated work function, indicating that the metal is not Sodium.

Hence, we cannot identify the metal with the given data. The maximum speed of emitted electrons is 5.28 × 10⁵ m/s and the work function is 3.34 × 10⁻¹⁹ J.

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If we know the semimajor axis and eccentricity of an object's orbit, then we can determine the object's closest and farthest points from the mass it is orbiting. The semimajor axis is the distance from the center of mass of the object and the mass it is orbiting, and the eccentricity describes the shape of the orbit. If the eccentricity is zero, the orbit is a perfect circle, and the closest and farthest points are the same distance from the mass.

If the eccentricity is greater than zero, the orbit is elliptical, and the closest point is called the perihelion (or periapsis), while the farthest point is called the aphelion (or apoapsis). Knowing these points can help us understand the behavior of objects in orbit and make predictions about their movements.
If we know the semimajor axis and eccentricity of an object's orbit, then we can determine the object's closest and farthest points from the mass it is orbiting.

Step 1: Identify the semimajor axis (a) and eccentricity (e) values.
Step 2: Calculate the closest point (perihelion) using the formula: Perihelion = a * (1 - e)
Step 3: Calculate the farthest point (aphelion) using the formula: Aphelion = a * (1 + e)

By following these steps, you can find the perihelion and aphelion distances of an object in its orbit around the mass it is orbiting, using the semimajor axis and eccentricity.

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Answer:

einy obv

Explanation:

he did lsd

The strong nuclear force overcomes the repulsive electric force of protons in the atomic nucleus because it is a much stronger force. It is able to act over very short distances and is mediated by particles that are much heavier than electrons and photons.

The repulsive electric force of protons in the atomic nucleus does not cause the protons to fly apart because of the strong nuclear force. The strong nuclear force is an attractive force between nucleons that overcomes the repulsion between protons due to the electromagnetic force. This force is responsible for holding the nucleus of an atom together.

We will explain the physics behind why the strong nuclear force overcomes the repulsive electric force. The protons in the nucleus are positively charged and would normally repel each other due to the electrostatic force. The reason why they do not is because they are held together by a stronger force, the strong nuclear force. This force acts between nucleons, which are particles found in the nucleus of an atom. The strong nuclear force is a short-range force that acts over distances of less than a femtometer. It is much stronger than the electrostatic force, which is why it is able to hold the nucleus together. The reason for this is that the strong nuclear force is mediated by particles called mesons, which are much heavier than electrons and photons. The strong force is able to overcome the repulsion between protons because it is much stronger than the electromagnetic force, which is what causes the repulsion in the first place.

The strong nuclear force overcomes the repulsive electric force of protons in the atomic nucleus because it is a much stronger force. It is able to act over very short distances and is mediated by particles that are much heavier than electrons and photons. This force is responsible for holding the nucleus of an atom together and is what allows for the existence of matter as we know it.

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Answer:

2.76 eV

Explanation:

The Quanta of Light For example, a photon of blue light of wavelength 450 nm will always have 2.76 eV of energy.

Answer:

Bacteria

Fungi

Viruses

Parasites

Answer:

So, Mercury is the closest planet to the Sun.

Explanation:

Answer:

The wavelength is approximately 611 nm

Explanation:

We can use the formula for the condition of maximum of interference given by:

\(d\,sin(\theta)=m\,\lambda\\(0.000250\,\,m)\,\,sin(1.12^o)=8\,\lambda\\\lambda=\frac{1}{8} \,(0.000250\,\,m)\,\,sin(1.12^o)\\\lambda \approx 610.8\,\,nm\)

We can also use the formula for the distance from the central maximum to the 5th minimum by first finding the tangent of the angle to that fifth minimum:

\(tan(\theta)=\frac{y}{D}\\ tan(\theta)=\frac{0.0333}{3.02} =0.011026\)

and now using it in the general formula for minimum:

\(d\,sin(\theta)\approx d\,tan(\theta)=(m-\frac{1}{2} )\,\lambda\\\lambda\approx 0.00025\,(0.011026)/(4.5)\,\,m\\\lambda\approx 612.55\,\,nm\)

Answer:

The correct answer is  \(6.1\times10^{-7}\:m\)

Explanation:

The distance from the central maxima to 5th minimum is:

\(x_{5n}-x_{0} =3.33\:cm=0.033\:m\)

The distance between the slits and the screen:

\(L = 302\:cm = 3.02\:m\)

Distance between 2 slits: \(d = 0.00025\:m\)

\((n-\frac{1}{2})\lambda=\frac{d(x_n)}{L}\)

For fifth minima, n = 5... so we have:

\(x_{5n}=\frac{9\lambda L}{2d}\)

For central maxima, n = 0... so we have:

\(x_{0}=\frac{n\lambda L}{d}=0\)

So the distance from central maxima to 5th minimum is:

\(\frac{9\lambda \:L}{2d}-0=0.033\)   (Putting the values, we get):

\(\Rightarrow \lambda = 6.1\times 10^{-7}\:m\)

Best Regards!

The position of the mass at t = 13 s, based on given information, is -0.044m or -4.3 cm.

To find the position of the mass at t=13s, we can use the equation for simple harmonic motion:

x(t) = A * cos(ωt + φ)

where x(t) is the position of the mass at time t, A is the amplitude (maximum displacement), ω is the angular frequency, and φ is the phase angle.

Given a spring constant k = 24.5 N/m and a mass m = 465 g (0.465 kg), we can calculate the angular frequency (ω) using the formula:

ω = √(k/m) = √(24.5/0.465) ≈ 7.30 rad/s

The amplitude (A) is the initial stretch of the spring, which is 4.8 cm (0.048 m).

Since the mass is released at t=0, the phase angle (φ) is 0.

Now, we can plug these values into the equation:

x(13) = 0.048 * cos(7.30 * 13)

x(13) ≈ -0.043 m

The position of the mass at t=13s is approximately -0.043 m, which means it is 4.3 cm to the left of the equilibrium position.

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Option (b) is the correct answer: the pressure of a gas increases due to an increase in temperature because the molecules strike the walls of the container more often.

Gay-Lussac's law, also known as the pressure law, states that the pressure of a gas is directly proportional to its temperature, assuming the volume and amount of gas remain constant. Therefore, an increase in temperature leads to an increase in pressure. The explanation for this phenomenon lies in the kinetic theory of gases.

According to the kinetic theory, the temperature of a gas is related to the average kinetic energy of its molecules. When the temperature increases, the average kinetic energy of the gas molecules also increases. As a result, the gas molecules move with higher velocities and collide more frequently with the walls of the container.

The frequency of molecular collisions with the container walls is directly related to the pressure exerted by the gas. When the gas molecules strike the walls more often due to increased kinetic energy, the pressure exerted by the gas increases.

Therefore, option (b) is the correct answer: the pressure of a gas increases due to an increase in temperature because the molecules strike the walls of the container more often.

An increase in temperature causes the pressure of a gas to increase because the gas molecules collide more frequently with the walls of the container, as explained by Gay-Lussac's law and the kinetic theory of gases.

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Answer:

Replication Crisis

Explanation:

Replication crisis in psychology- It refers to the concerns about credibility of finding the results in psychological science.

The process by which dissolved minerals crystallize and glue particles of sediment together is called "cementation."

Cementation occurs when minerals dissolved in water, such as calcite, silica, or iron oxide, precipitate and fill the spaces between sediment grains. Over time, these minerals crystallize, forming a natural cement that binds the sediment particles together, solidifying them into a cohesive sedimentary rock. Cementation is a vital process in the formation of sedimentary rocks, contributing to their strength and durability.

During the process of sedimentation, various types of sediment, such as sand, silt, and clay, settle and accumulate. These sediment particles are often loose and unconsolidated. However, cementation plays a crucial role in transforming these loose sediments into solid sedimentary rocks.

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No. this is not true for a spherical capacitor.

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(a Vector r represents the sum of the two vectors x and y.

(b) The algebraic equation for the vector addition shown is r² = x² + y²

(a) The resultant of the vectors is the sum of the two vectors x and y which is given by vector r.

So vector r represents the sum of the two vectors x and y.

(b) The algebraic equation for the vector addition shown is determined by applying Pythagorean theorem as follows;

r² = x² + y²

where;

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Answer:

it is difficult

my best answer would be a. 6

hope its right!!

===========================================

Explanation:

The half-life formula is

y = A*(1/2)^(x/H)

where A is the starting amount, H is the half-life, x is the time value and y is the amount after x units of time have passed.

I'll express the x and H values in terms of millions of years. So for example, when we say H = 500, then that really refers to 500 million years.

----------

In this case, we know that,

Let's use those values to solve for x. We'll need logs to cut the exponents down from the trees.

y = A*(1/2)^(x/H)

3 = 192*(1/2)^(x/500)

3/192 = (0.5)^(x/500)

0.015625 = (0.5)^(x/500)

log(0.015625) = log( (0.5)^(x/500) )

log(0.015625) = (x/500)*log(0.5)

(x/500)*log(0.5) = log(0.015625)

x = 500*log(0.015625)/log(0.5)

x = 3,000

Keep in mind that x is in millions of years. So saying x = 3,000 means 3,000 million years. This translates to 3,000*10^6 = 3,000,000,000 = 3 billion years.

It will take about 3 billion years for the 192 atoms to decay to only 3 atoms.

The amount of half-lives this occurs is x/H = (3,000)/500 = 6

So the time span of 3 billion years is the same as 6 half-lives when each half-life is 500 million years long.

Answer:

The lifeguard should run approximately 17.752 meters along the shore, before, jumping in the water

Explanation:

The given parameters are;

The rate at which the lifeguard runs = 5 m/s

The rate at which the lifeguard swims = 1 m/s

The horizontal distance of the child from the lifeguard = 30 meters along the shore

The vertical distance of the child from the lifeguard = 60 meters along the shore

Let x represent the distance the lifeguard runs

We have;

The distance the lifeguard swims = √((30 - x)² + 60²)

Time = Distance/Speed  

The time the lifeguard runs = x/5

The time the lifeguard swims = √((30 - x)² + 60²)/1

The total time = √((30 - x)² + 60²) + x/5

The minimum time is given by finding the derivative and equating the result to zero, as follows;

Using an online application, we have;

d(√((30 - x)² + 60²) + x/5)/dx = 1/5 - (30 - x)/(√((30 - x)² + 60²)) = 0

Which gives;

1/5 - (30 - x)/(√(x² - 60·x + 4500) = 0

(30 - x)/(√(x² - 60·x + 4500)) = 1/5

5×(30 - x) = √(x² - 60·x + 4500)

We square both sides to get;

(5×(30 - x))² = (x² - 60·x + 4500)

(5×(30 - x))² - (x² - 60·x + 4500) = 0

25·x² - 1500·x + 22500 - x² + 60·x - 4500 = 0

24·x² - 1440·x + 18000 = 0

Dividing n=by 24 gives;

24/24·x² - 1440/24·x + 18000/24 = 0

x² - 60·x + 750 = 0

By the quadratic formula, we have;

x = (60 ± √((-60)² - 4×1×750))/(2 × 1) =

Using an online application, we have;

x = (60 ± 10·√6)/(2)

x = 30 + 5·√6 or x = 30 - 5·√6

x ≈ 42.25 m and x ≈ 17.752 m

At x = 42.25

Time = √((30 - 42.247)² + 60²) + 42.247/5 ≈ 69.69 seconds

At x = 17.75

Time = √((30 - 17.752)² + 60²) + 17.752/5 ≈ 64.79 seconds

Therefore, the route with the shortest time is when the lifeguard runs approximately 17.752 meters (rounded to three decimal places) along the shore, before, diving in the water

Answer: The force of gravity

The stagnation point is the point where the fluid flow comes to a complete stop momentarily. In the stagnation point, the correct answer is (a) airflow speed is at its maximum.

It occurs when a fluid, such as air, is forced to change its direction suddenly, causing the velocity to drop to zero.

At the stagnation point, the fluid is brought to rest and then redirected. As a result, the airflow speed is at its maximum just before reaching the stagnation point, and it decreases to zero at that specific location.

Beyond the stagnation point, the airflow starts to accelerate again in the new direction. Therefore, the stagnation point represents the maximum airflow speed along the flow path. The correct option is A.

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Answer:

The percentage error in quantity P is 19%.

Explanation:

It is given that,

A physical quantity P is related to four observables a, b and c as follows:

\(P=\dfrac{a^3b^2}{c^4}\)

The percentage errors of measurements in a, b and c are 1%, 4% and 2% respectively.

We need to find the percentage error in quantity P. It is given by :

\(\dfrac{\Delta P}{P}\times 100=(3\times \dfrac{\Delta a}{a}+2\times \dfrac{\Delta b}{b}+4\times \dfrac{\Delta c}{c})\\\\=3\times 1+2\times 4+4\times 2\\\\\dfrac{\Delta P}{P}\times 100=19\%\)

So, the percentage error in quantity P is 19%.

Answer:

a) 50 rad/s

b) 39.8 rev

Explanation:

Given:

r = 0.36 m

v₀ = 0 m/s

a = 1.8 m/s

t = 10 s

a) Find: ω

v = at + v₀

v = (1.8 m/s) (10 s) + (0 m/s)

v = 18 m/s

ω = (18 m/s) / (0.36 m)

ω = 50 rad/s

b) Find: Δθ

Δx = v₀ t + ½ at²

Δx = (0 m/s) (10 s) + ½ (1.8 m/s) (10 s)²

Δx = 90 m

Δθ = (90 m) / (2π × 0.36 m)

Δθ = 39.8 rev

Answer: The thickness of the vertical flow lines indicates the relative quantity.

The thickness of the vertical flow lines indicates the relative quantity.

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