A turbine of a fossil fuel burning installation delivers 1,500 hp of mechanical energy to a generator. The generator then converts 80.0% of the mechanical energy into electrical energy. If the terminal potential difference of the generator is 1790 V, what current does it deliver (in A)

check photos (answer)

Comparing this to the actual power required for the two-stage compressor (242.6 kW), we can see that the actual power required is significantly higher.

Work done is the amount of energy transferred to or from a system as a result of a force acting on it over a distance.

To solve this problem, we can use the following steps:

Step 1: Determine the state points of the air at various stages of the compression process.

Stage 1: Inlet state = State 1

P1 = 100 kPa, T1 = 300 K, V1 = 10 m³/min

Stage 2: After the first stage of compression = State 2

P2 = 1200 kPa, T2 = ? (isentropic compression)

Stage 3: After intercooling = State 3

P3 = 350 kPa, T3 = 300 K, V3 = V2

Stage 4: After the second stage of compression = State 4

P4 = 1200 kPa, T4 = ? (isentropic compression)

Step 2: Calculate the temperature and specific volume at states 2 and 4 using the isentropic compression process.

For an isentropic compression process, we have:

(P2/P1)^((γ-1)/γ) = T2/T1

(P4/P3)^((γ-1)/γ) = T4/T3

where γ is the ratio of specific heats for air, which is approximately 1.4.

Solving for T2 and T4, we get:

T2 = T1*(P2/P1)^((γ-1)/γ) = 300*(1200/100)^((1.4-1)/1.4) = 742.6 K

T4 = T3*(P4/P3)^((γ-1)/γ) = 300*(1200/350)^((1.4-1)/1.4) = 892.5 K

Next, we can use the ideal gas law to calculate the specific volume of air at states 2 and 4:

V2 = V1*(P1/P2)(T2/T1) = 10(100/1200)(742.6/300) = 0.1867 m³/kg

V4 = V3(P3/P4)(T4/T3) = 10(350/1200)*(892.5/300) = 0.2604 m³/kg

Step 3: Calculate the work done in each stage of the compressor.

For an isentropic compression process, the work done can be calculated using the following equation:

W = (mCp)(T2-T1) = (mCp)(T4-T3)

where m is the mass flow rate of air, which can be calculated using the specific volume and inlet volumetric flow rate:

m = V1/(v160) = 10/(0.831460) = 0.2016 kg/s

Cp is the specific heat at constant pressure for air, which is approximately 1.005 kJ/kg-K.

Thus, the work done in each stage of the compressor is:

W1 = (0.20161.005)(742.6-300) = 77.2 kW

W2 = (0.20161.005)(892.5-300) = 116.9 kW

The total work done by the compressor is:

W_total = W1 + W2 = 77.2 + 116.9 = 194.1 kW

Step 4: Calculate the power required to run the compressor.

The power required to run the compressor can be calculated using the following equation:

Power = W_total/η

where η is the compressor efficiency.

We are not given the efficiency, but for a two-stage compressor, a reasonable estimate for η is reasonable estimate for the efficiency of a two-stage compressor is around 75-85%. Therefore, we can assume η = 0.8.

Using this efficiency value, the power required to run the compressor is:

Power = W_total/η = 194.1/0.8 = 242.6 kW

Step 5: Compare the result to the power required for isentropic compression from the same inlet state to the same final pressure.

For isentropic compression from the same inlet state to the same final pressure, the work done can be calculated using the following equation:

W = (mCp)(T2-T1) = (mCp)(T4-T3) = (m*Cp)*ΔT

where ΔT = T2-T1 = T4-T3 = 442.5 K

Thus, the work done for isentropic compression is: W_iso = (0.2016*1.005)*442.5 = 89.1 kW

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8 MB Physical memory needed to storing for page table.

Given

Virtual address = 33 bit.= 2³³ B

Page Number (P) Page Size (d)

21 12

Page Size = 4KB= 4*2¹⁰ B= 2²*2¹⁰ B (12 bit)

( 1K = 2¹⁰).

Total Number of Page (P) =

Virtual address Size/ Page Size

= 2³³B/ 2¹²B

= 2²¹ .

Page Table data structure used to mapping between Virtual Address and Physical Address.

page table contains all information about every page in PTE (Page Table Entry) .

In one PTE contain information of one page.

Size of Page Table

= Number of Page * Size of PTE

= 2²¹ * 4 B

= 2²¹ * 2² B

= 2²³ B

= 2³ MB. ( 1M = 2²⁰)

= 8MB.

8 MB Physical memory needed to storing for page table.

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Answer:

The outer diameter of the ball is 6.2138 cm

Explanation:

The formula to apply is ;

Heat loss ,

\(Q/t=kA*\frac{( T_1-T_2)}{d}\)

where ;

Q/t=total heat loss from the ball = 1600 w

k=coefficient of heat transmission through the ball= 2.75 W/m.˚C

A=area in m² of the ball with the coefficient of heat transmission

T₁=Hot temperature

T₂=Cold temperatures

d=thickness of the ball

Area of spherical ball using internal diameter, 3cm= 0.03 m will be

Radius = half the diameter = 0.03/2 = 0.015

Area = 4 *π*r²

Area = 4*π*0.015² = 0.002827 m²

Apply the formula for heat loss to get the thickness as:

1600 = {2.75 * 0.002827 *(250-30 ) }/d

1600 =1.711/d

1600d = 1.711

d=1.711/1600 = 0.001069 m

d= 0.1069

Using internal radius and the thickness to get outer radius as;

3 + 0.1069 = 3.1069 cm

Outer diameter will be twice the outer radius

2*3.1069 = 6.2138 cm

Address Byte Address (hexadecimal) Sections in address space

Last Flash Address FFFF Flash Memory

First Flash Address C000 Flash Memory

Last RAM address 03FF RAM Memory

First RAM address 0200 RAM Memory

Last I/O address (16-bit per.) 01FF I/O address space

First I/O address (16-bit per.) 0100 I/O address space

Last I/O address (8-bit per.) 00FF I/O address space

First I/O address (8-bit per.) 0000 I/O address space

Maximum stack size is 1792 bytes.

Initial value of SP should be 0x025E.

PUSH R9: SP is decremented by 2, and the value in R9 is stored at the new SP address.

POP R9: The value at the current SP address is loaded into R9, and SP is incremented by 2.

The MSP430F20x microcontroller has 2,048 Bytes of RAM memory available, starting at the address 0x0200 in the address space. This RAM memory can be used for storing program variables, data, and stack operations. The RAM memory is divided into multiple segments, including general-purpose registers, stack memory, and system registers. The starting address of the RAM memory is important to know when programming the microcontroller and accessing its memory.

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The probability 2/5 of the applications require at most three forms, and 3/5 of the applications require between two and four forms, inclusive.

We know that the sum of probabilities of all possible outcomes must be equal to 1. Therefore, we have:

p(1) + p(2) + p(3) + p(4) + p(5) = c(1 + 2 + 3 + 4 + 5) = 15c

Since this sum must be equal to 1, we have:

15c = 1

c = 1/15

Now, we can find the probabilities for the events:

Probability of requiring at most three forms:

P(y ≤ 3) = p(1) + p(2) + p(3) = (1/15)(1 + 2 + 3) = 6/15 = 2/5

Probability of requiring between two and four forms, inclusive:

P(2 ≤ y ≤ 4) = p(2) + p(3) + p(4) = (1/15)(2 + 3 + 4) = 9/15 = 3/5

Therefore, in the long run, 2/5 of the applications require at most three forms, and 3/5 of the applications require between two and four forms, inclusive.

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Answer:

D. Measure the voltage on the conductor with a known good meter

Explanation:

In a safe approach to electrical work,the thing that you should always do immediately before touching any electrical conductor is  C. Measure the voltage on the conductor with a known good meter.

One should never touch any wires or conductors until you are certain that their electrical supply has been turned off. Circuits must be locked out and marked with a tag to prevent re-energizing them. A conductor is always risky. Before working on a circuit, always test to make sure it is deenergized.

The action you should always do right away before touching any electrical conductor is  the safest approach to electrical work. Use a reputable meter to measure the voltage across the conductor.

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A driver should have at least a 10 mph speed advantage when overtaking (passing) another vehicle.

A speed limit refers to the maximum amount of speed that is legally permitted or allowed in a specific area for safety. Thus, this limit must be abided and strictly adhered to by all road users such as drivers of a vehicle.

According to the highway traffic code and regulations, a driver should have at least a 10 mph speed advantage when overtaking (passing) another vehicle.

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Answer:

B

Explanation:

Anxiety is very common especially nowadays but it's especially common in psychological disorders

Here is a Java program that accomplishes the given tasks:

import java.awt.*;

import java.awt.geom.AffineTransform;

public class ShapeReflection {

   public static void main(String[] args) {

       // Reflecting the shape with the points

       int[] xPoints = {160, 220, 220, 190, 160};

       int[] yPoints = {130, 130, 160, 180, 160};

       int numPoints = xPoints.length;

       // Reflecting the shape about the line Y = -X + 500

       for (int i = 0; i < numPoints; i++) {

           int x = xPoints[i];

           int y = yPoints[i];

           // Calculate the reflected points

           int newX = 500 - y;

           int newY = 500 - x;

           // Update the original points with the reflected points

           xPoints[i] = newX;

           yPoints[i] = newY;

       }

       // Drawing the shape using loop and methods

       DrawingPanel panel = new DrawingPanel(600, 600);

       Graphics2D g2 = panel.getGraphics();

       g2.setColor(Color.BLACK);

       g2.drawPolygon(xPoints, yPoints, numPoints);

   }

}

This program uses the `java.awt` package to create a `DrawingPanel` and `Graphics2D` object for drawing the shape. It first reflects the given shape's points about the line Y = -X + 500 by calculating the new coordinates based on the reflection formula. Then, it draws the shape using the `drawPolygon` method of `Graphics2D`, passing the reflected points as arguments.

Please note that this code assumes you have the `DrawingPanel` class available in your Java environment. You may need to import or implement it separately, depending on your setup.

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here's your answer..

Oxygen combines with nitrogen in the air to form NO at about 2500 celsius.

The enormous energy of lightning breaks nitrogen molecules and enables their atoms to combine with oxygen in the air forming nitrogen oxides. These dissolve in rain, forming nitrates, that are carried to the earth.

At these high temperatures, nitrogen and oxygen from the air combine to produce nitrogen monoxide. One nitrogen molecule (N2) reacts with one oxygen molecule (O2) to make two nitrogen monoxide molecules (NO).

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Answer:

7 available

Explanation:

Since 3 colors are available r = 3

Total combination = 35

nCr = 35 ---1

nCr = n!/(n-r)!r!---2

We put equation 1 and 2 together

n-1)(n-2)(n-3)!/n-3)! = 35x 3!

We cancel out (n-3)!

(n-1)(n-2) = 210

7x6x5 = 210

nC3 = 35

7C3 = 35

So If there are 35 combinations, 7 colors are available.

Thank you!

The available colors are illustrations of combination, and there are 7 colors available.

The given parameters are:

\(Total = 35\) --- the number of combinations

\(r = 3\) -- the number of colors in one combination.

The number of combinations is calculated using:

\(Total = ^nC_r\)

Where n represents the number of colors available.

So, we have:

\(35= ^nC_3\)

Apply combination formula

\(35= \frac{n!}{(n - 3)!3!}\)

Expand the numerator

\(35= \frac{n(n - 1)(n - 2)(n - 3)!}{(n - 3)!3!}\)

Cancel out the common factors

\(35= \frac{n(n - 1)(n - 2)}{3!}\)

Expand

\(35= \frac{n(n - 1)(n - 2)}{3 \times 2 \times 1}\)

\(35= \frac{n(n - 1)(n - 2)}{6}\)

Multiply both sides by 6

\(210= n(n - 1)(n - 2)\)

Rewrite the equation as

\(n(n - 1)(n - 2) = 210\)

Using a graphing calculator, we have:

\(n = 7\)

Hence, the number of colors available is 7

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ok zcxnlegdjbfxbkqlu

jksdczruiorth

Answer:

mechanical engineer

Explanation:

Thomas is checking an electrical wire in a washroom with a wet floor. Ground-fault circuit interrupters in the electrical wire will help prevent electrical shock.

The ground-fault circuit interrupter, or GFCI, is a quick-response circuit breaker that may cut off electricity in as little as 1/40 of a second in the event of a ground fault.

It compares the current flowing into and out of the machinery along the conductors of the circuit.

Therefore, electrical shock can be avoided with the aid of ground-fault circuit interrupters in the electrical line.

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Answer:

Explanation:

A scenario is an actual sequence of interactions (i.e., an instance) describing one specific situation; a use case is a general sequence of interactions (i.e., a class) describing all possible scenarios associated with a situation. Scenarios are used as examples and for clarifying details with the client. Use cases are used as complete descriptions to specify a user task or a set of related system features.

The emitter, collector, and base—or, in more recent switching applications, the source, drain, and gate—are the three electrical leads that commonly make up a transistor.

transistor: a semiconductor signal-generating, regulating, and amplifying device. Integrated circuits, or "microchips," which frequently have billions of these tiny components etched onto their glossy surfaces, use transistors as their active parts.

Transistors, which are present in practically every electronic component, have evolved into the brain cells of the information age. The ability of the semiconductor material to conduct electrical current, which in most applications moves between the emitter (or source) and collector (or drain), is influenced by an electrical signal supplied to the base (or gate). Similar to how a faucet valve is used to control the flow of water through a garden hose, a voltage source, such as a battery, drives the current, but the rate of current flow through the transistor at any one time is controlled by an input signal at the gate.

Nowadays, transistors are used in millions of components per integrated circuit in microprocessors and computer memory microchips, which include solid-state multimedia storage systems for electronic games, cameras, and MP3 players. Here, whether current may flow from the transistor's source to its drain is determined by the voltage applied to the gate electrode, which is typically a few volts or less.

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Answer:

Milk Production, Health, and Age.

Explanation:

You want a younger cow when buying cattle so you can have gather more milk from it over it's lifetime. You also want to make sure that it can actually produce milk. Then you want a cow in good health.

Proper operation of electric deicing boots on individual propeller blades may best be determined by feeling the sequence of boot heating and have an assistant observe the loadmeter indications.

The electrical meters that utility companies install frequently contain a load meter, a gadget. This gauge's main purpose is to show the maximum amount of electricity used since the monitor was last read, typically to see whether there have been any recent power surges that would invalidate the other readings.

The technology can be used by homeowners to figure out how to save energy and when they use electricity the most.

It is simpler to track levels of energy conservation when load meters additionally feature a separate indication that measures the current voltage (amperes) being pulled from the utility company in real time.

Therefore, Proper operation of electric deicing boots on individual propeller blades may best be determined by feeling the sequence of boot heating and have an assistant observe the loadmeter indications.

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The angle of attack of a wing directly controls the C) distribution of pressures acting on the wing.

When the angle of attack of a wing is increased, the air moving over the curved upper surface of the wing must travel a greater distance and faster than the air moving beneath the wing's flat lower surface. This creates an area of lower air pressure above the wing and an area of higher air pressure beneath the wing, resulting in lift. The greater the angle of attack, the greater the lift produced.

However, if the angle of attack is too great, the airflow over the wing may separate, causing a loss of lift and potentially leading to a stall. Therefore, proper control of the angle of attack is crucial for safe and efficient flight.

Option C is answer.

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Answer:  0.765 m kg / s

Explanation:

Momentum = (mass) x (speed)

Answer:

All machines have three fundamental hazards: moving parts, point of operation, and the power transmission.

Explanation:

The unit that supplies power to the machine is a critical hazard due to high energy sources being potential fatal if proper protocols are not followed. This is why lockout tagout (LOTO) measures are put in place in order to protect people while they work on equipment.

The family should accept a minimum of Kshs.42,250,000.00 to avoid incurring a loss.

To obtain the total cost, the expenses for the land, trees and upkeep are summed up and subsequently reduced by 6. 5% using a discount rate.

Hence, it can be seen that a forced acquisition appraisal primarily focuses on three key factors: the land's market value, the expenses involved in replacing the property, and the potential harm caused to the owner's belongings.

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(linear) searches a C-string --s-- for a certain character --f-- returning (via w) the offset it found or -1 if not and the address (via p) if found or nullptr if not. Option B.

The code starts by declaring a function called "mysterious" which takes in a C-string (s), a character (f), and a long variable (w) by reference. The function also returns a pointer to a character.

Inside the function, a new pointer variable "p" is created and assigned the value of "s". A while loop is then started which continues until either the character pointed to by "p" is equal to "f" or it reaches the end of the string ('\0').

Inside the while loop, "p" is incremented to point to the next character in the string. Once the loop ends, the function checks if the character pointed to by "p" is the null character ('\0'). If it is, it means the character "f" was not found in the string, so the function sets "p" to a nullptr and returns it.

If the character pointed to by "p" is not the null character, it means "f" was found in the string. The function then calculates the offset of "f" in the string by subtracting the starting address of the string "s" from the address pointed to by "p". This value is stored in the long variable "w".

Finally, the character pointed to by "p" is set to the null character ('\0'), effectively truncating the string at the location of "f". The function then returns the pointer variable "p".

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Answer:

"cool"

Explanation:

We also need to apply the principles of rotational motion, such as conservation of angular momentum and torque.

A uniform bar and two ropes, but you haven't provided enough information for me to give you a specific answer.

In general, to determine the magnitude of the angular velocity of each rope, we need to know the geometry of the system and the forces acting on it. We also need to apply the principles of rotational motion, such as conservation of angular momentum and torque.

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Answer:

Conditions for equilibrium require that the sum of all external forces acting on the body is zero (first condition of equilibrium), and the sum of all external torques from external forces is zero (second condition of equilibrium). These two conditions must be simultaneously satisfied in equilibrium.

Hi there!

For a particle to be in static equilibrium:

\(\huge\boxed{\Sigma \tau = 0}}\)

The sum of torques acting on the particle must equal 0 Nm.

\(\huge\boxed{\Sigma F = 0}}\)

The sum of forces acting on the particle must equal 0 N.

Both of these conditions MUST be met in order for a particle to be in STATIC equilibrium.

A light weight vehicle traveling 50 mph can stop in approximately 200 feet.

The break system of a car is composed by several items that are always working together to slow down and bring a vehicle to a complete stop. It also has the function of keeping the car stationary when it is parked. In general, this system has two manual activation modes: the lever and the pedal, with the exception of vehicles adapted for people with disabilities.

Most vehicles today use the disc brake system. Disc brakes work by using pads, which are held inside a hydraulic caliper, receiving pressure to brake. Such pads generate friction on a disc, which makes the vehicle stop permanently.

The drum brake is another type, being older and dependent on the famous linings to cause friction in the wheel and stop the vehicle. A hydraulic cylinder makes the plies move inside the drum, which is a hollow part fastened with screws and attached to the wheels. This type of brake is on the rear wheels, for the most common models.

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The operational availability, considering the logistic time for support, is approximately 0.643 or 64.3%. We need to use the formulas related to availability and MTTR.

1. Maximum Value of MTTR:

The formula for availability is given as:

Availability = MTBF / (MTBF + MTTR)

Given that the inherent availability of the system is 0.92 and the MTBF is 220 hours, we can rearrange the formula to solve for MTTR:

0.92 = 220 / (220 + MTTR)

Solving for MTTR:

0.92 * (220 + MTTR) = 220

202.4 + 0.92 * MTTR = 220

0.92 * MTTR = 17.6

MTTR = 17.6 / 0.92

MTTR ≈ 19.13 hours

Therefore, the maximum value of MTTR is approximately 19.13 hours.

2. Operational Availability considering Logistic Time for Support:

The operational availability (Ao) can be calculated by considering both the inherent availability (Ai) and the logistic time for support (LTS) as follows:

Ao = Ai * (1 - LTS)

Given that the logistic time for support is stated as 30% of the total downtime, we can calculate it as follows:

LTS = 0.30 * (MTTR + LTS)

Simplifying the equation:

LTS = 0.30 * MTTR / (1 - 0.30)

Now, we can substitute the value of MTTR we obtained earlier:

LTS = 0.30 * 19.13 / (1 - 0.30)

LTS ≈ 0.30 * 19.13 / 0.70

LTS ≈ 8.25 hours

Finally, we can calculate the operational availability:

Ao = Ai * (1 - LTS)

Ao = 0.92 * (1 - 8.25 / (MTTR + LTS))

Ao = 0.92 * (1 - 8.25 / (19.13 + 8.25))

Ao ≈ 0.92 * (1 - 8.25 / 27.38)

Ao ≈ 0.92 * (1 - 0.301)

Ao ≈ 0.92 * 0.699

Ao ≈ 0.643

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